Saturday
May 25, 2013

Posts by Sarah H


Total # Posts: 32

Chem -plz check work
so i've worked on this some more, now I am asking if someone will plz check my work 2 half cells in a galvanic cell consist of one iron Fe(s) electorde in a solution of iron (II) sulphate FeSO4(aq)and a silver Ag(s) electrode in a silver nitrate solution, a)state the oxida...

grade 12 chemisstry
I have no idea what I'm doing here, please help. 2 half cells in a galvanic cell consist of one iron Fe(s) electorde in a solution of iron (II) sulphate FeSO4(aq)and a silver Ag(s) electrode in a silver nitrate solution, a)state the oxidation half reaction, the reduction h...

grade 12 chem - check my answer again please
Hi, please check my work: In an experiment, 23.4 g of FES are added to excess oxygen and 16.5 g of FE2O3 are produced. The balanced equation is: 4FeS + 7O2 --> 2Fe2O3 + 4SO2 Calculate the % yield. My Answer: nFeS=23.4g/87.92 g/mol =0.266 mol 4mol FeS / 0.266 mol = 7mol O2/ ...

chem - CHECK PLEASE BOB PURSLEY
I MEAN ETHYLENE GLYCOL, SORRY.

chem - CHECK PLEASE BOB PURSLEY
not ethelyne glycol?

chem
what is the common name for ethane and propene? I think propene is propylene but i don't know about ethane.

gr. 12 chemistry
Hi, please check my work: In an experiment, 23.4 g of FES are added to excess oxygen and 16.5 g of FE2O3 are produced. The balanced equation is: 4FeS = 7O2 --> 2Fe2O3 + 2SO2 Calculate the % yield. My Answer: nFeS=23.4g/87.92 g/mol =0.266 mol 4mol FeS / 0.266 mol = 7mol O2/ ...

Chemistry - Bob Pursley
Posted by Sarah H on Friday, May 23, 2008 at 8:10pm. Hi, please check my work: In an experiment, 23.4 g of FES are added to excess oxygen and 16.5 g of FE2O3 are produced. The balanced equation is: 4FeS = 7O2 --> 2Fe2O3 + 2SO2 Calculate the % yield. My Answer: nFeS=23.4g/87...

Chemistry - please help
Hi, please check my work: In an experiment, 23.4 g of FES are added to excess oxygen and 16.5 g of FE2O3 are produced. The balanced equation is: 4FeS = 7O2 --> 2Fe2O3 + 2SO2 Calculate the % yield. My Answer: nFeS=23.4g/87.92 g/mol =0.266 mol 4mol FeS / 0.266 mol = 7mol O2/ ...

Chemistry - please help
Hi, please check my work: In an experiment, 23.4 g of FES are added to excess oxygen and 16.5 g of FE2O3 are produced. The balanced equation is: 4FeS = 7O2 --> 2Fe2O3 + 2SO2 Calculate the % yield. My Answer: nFeS=23.4g/87.92 g/mol =0.266 mol 4mol FeS / 0.266 mol = 7mol O2/ ...

Pages: 1 | 2 | 3 | 4 | Next>>

For Further Reading

Search
Members
Community