Posts by Sandro!
Total # Posts: 10
(-2x^2y)^3 * (5xy^3)^2 What is ^ and * suppose to symbolize? ^=power *=times/multiply (-2x^2y)^3 * (5xy^3)^2 Sorry, I do not recall how to do this. I don't want to misguide you. First remove the parentheses by cubing the first term and squaring the second. (-8x^6y^3)*(25x^...
(-2x2y)3 * (5xy3)2 *I don't get this on at all!!! Are there any exponents in this one? If so, repost showing the caret to indicate the exponent. oh sorry I forget to do that.LOL!Here it is now: (-2x^2y)^3 * (5xy^3)^2 Are there any exponents in this one? If so, repost ...
(-mn8)3 would it be: -m^3n^3164 (-mn8)3 = -24mn Without carrots I have no idea where your exponents are. how?I don't get this one? Is this Sandro from Mrs.Pfeiffer's class?What grade are you in? Leo is saying you need to use carets to show an exponent. As you have ...
(5a^3b^4)2 would it be: 10a^6b^8 five squared is 25, and three squared is nine, not ten and six. Sorry!I always forget!LOL! (5a^3b^4)^2 = 5^2 (a^3)^2 (b^4)^2 = 25 a^6 b^8
(-3xy^3)^4 Would it be: -81x^4y^12 Almost, but not quite. Just watch your negative signs. So it would be positive? (-)*(-)*(-)*(-)= + right. Thanks
How do I do these powers? (2a5)3 So it is really: (2a^5)^3 Raise each inside the parentheses to the third. 23*(a5)3 = ?? I don't get it!Here is what I got: 2*2*2=8(a^8) *Also how do you do the powers for the numbers on here? almost but not quite. 2*2*2 = 8 which is correct...
BOBPURSLEY PLZ FINISH HELPIN ME W/MY OTHER PROBLEM
BASICALLY WHAT THE TITLE SAYS!
2.Two cars leave town going opposite directions. One car is traveling 55 mph, and the other is traveling 65 mph How long will it take before they are 180 miles apart? Hint: The time for both cars is the same and can be represented by "t." The total distance is 180 ...
1.Six pears and three apples cost $3.90. Two pears and five apples cost $3.30. How much does one pear cost? Hint: You have two unknowns (variables), so you need two equations. Write one equation for each situation and solve the system of equations. 6P + 3A=3.90 2P + 5A=3.30 ...
ALGEBRA 1!PLZ HELP!
Use the Substitution method to solve the system of equations. y - 2x = -5 3y - x = 5 Solve the first equation for y. y = 2x-5 Substitute that for y in the second equation and solve for x. Then use the value of x to substitute back into the first equation and solve for y. Post ...