http://rechneronline.de/function-graphs/ has excellent graphing help. You can plot up to 3 functions on the same axes, so it should work well for this problem.
(x-h)^2 + (y-k)^2 = r^2 describes a circle with center at (h,k) and radius r. Surely your text explains this. The fact that they ask such a question indicates that they expect you to recognize such a standard equation.
well, expand and equate coefficients: a = A 2ab = 16 2ac+b^2 = 28 2bc = 24 c^2 = C b=8/A c=√C 2A√C + 64/A^2 = 28 16/A√C = 24 so √C = 3A/2 2A(3A/2) + 64/A^2 = 28 A = ±2, ±4/√3 so, find C and thus a,b,c. Note that c = -√C provide...
Please help, have a couple left!
since 125 = 5^3, 1/3^-3 = 3^3 5^3 = x^3/(3^3) 5^3 = (x/3)^3 now take cube roots: 5 = x/3 x = 15
Trigonometric Functions! (Ferris Wheel)
well, since sin(x) has a max at x=90, and a min at x=270, that phase shift makes sense. You will have something along the lines of sin(x+270) The radius of the wheel is 9, and the whole wheel is lifted 2m, so we have 9sin(x+270)+11 see, at x=0, y=9(-1)+11 = 2 at x=90, y=9(0)+1...
1.50*21.0 sin 30.0° = 15.75m
The notation is kind of weird, but it appears that a2n = 2^n
Help In Math!
well, first off you know that since a<c<b, A<C<B (law of sines) That means (b)
Please help Math
360° is one complete rotation, so any multiple of that ends up in the same place. So, (b)
lots left unsaid here. (first, if she's paid annually, that means the pay period is one year.) I think you mean she has an annual salary. You need to divide that salary by the number of pay periods to get the pay per period.
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