what will be the graph looks like for equation r = 4(1-cos(theta+pi/4))?
if there are x regular and y deluxe sandwiches, 3x+5y = 1100 2x+3y = 700 (x,y) = (200,100)
AB has slope -24/18 = -4/3 so, our line has slope 3/4 Since it passes through (0,0), its equation is y = 3/4 x Extra credit: 3/4 x intersects AB at (16,12), and that's the midpoint of the line we want. So, the 4th vertex of the kite is (32,24)
you have log 4/25 - log 27/125 + log 9 = log (4/25)(9)/(27/125) = log 20/3
I think the first is better, since it preserves the tense in both clauses.
If the tent ends have side s and the tent has length t, the area is a = 2(√3/4 s^2) + 3st since the volume of the tent is 2.2, √3/4 s^2 t = 2.2, and so t = 8.8/(√3 s^2) If the cost of the floor is 1, then the cost of the whole tent is c = 2(√3/4 s^2)(1....
8x-8-6x=20 that should help
Looks good to me.
(x,y) = (2cos 4π/11,2sin 4π/11) P = (√26,arctan(-1/-5)) v = 25cos32°i + 25cos32°j u+v = <(6-10),(2+1)> -3u = <-3(6),-3(2)>
yes, unless you want to round it up to 34.04