Math
.30*679.95 = 203.99
Calculus
you don't want the minima and maxima of (x^2-4)/(1+cos(x)^2) That is not f(x). It is f'(x). So, the minima and maxima of f(x) occur when (x^2-4)/(1+cos(x)^2) = 0.
Chemistry
convert 600mg to moles. 2HCl + Mg(OH)2 = MgCl2 + 2H2O so, each mole of Mg(OH)2 needs 2 moles of HCl. So, now you know how many moles of HCl you need. For .5M HCl solution, you will need 2L (2000ml) of acid for each mole.
intergrations
using discs, v = ∫[0,4] πr^2 dy where r = x = √(24-6y) v = π∫[0,4] (24-6y) dy = π(24y-3y^2) [0,4] = 48π using shells, v = ∫[0,√24] 2πrh dx where r=x and h=y=4-x^2/6 v = 2π∫[0,√24] x(4-x^2/6) dx = 2x^2 - x^...
Calculus
(i) v(t) = ds/dt (ii) set v=0 and solve for t (iii) a(t) = dv/dt; find a(5)
Integrals
just expand the power and you have ∫(4x^4 - 12x^2 + 9) dx now it's easy - just powers
Math - PLEASE HELP
f(x) = ∫[4,x] 4t^10(2t+8lnt)^4 dt Don't know what the 0 is doing in there; if I got it wrong, fix it and modify the solution. Using Leibnitz's Rule for differentiation under the integral sign, f'(x) = 4x^10 (2x+8lnx)^4 so, f'(1) = 4(2+0)^4 = 64
Math
first, collect the stuff with d on one side, and the plain numbers on the other. Recall that a true equation remains true if you do the same thing to both sides. So, start by adding 3.4 to both sides: d/2.5 - 3.4+3.4 = 4.6+3.4 d/2.5 = 8.0 Now, multiply both sides by 2.5: d/2.5...
Mathematics
w(4w-7) = 15 Now, 15=3x5, so try w=3. In that case, the length is 5. Algebraically, 4w^2 - 7w - 15 = 0 (4w+5)(w-3) = 0 w = 3 or -5/4
math
aside from x=120, the other values are hard to find.
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