Tuesday
August 23, 2016

Posts by STEVE

Total # Posts: 42,728

SCIENCE
start: 0.1kg * 30m/s end: 0 doesn't matter how long it took.
August 1, 2016

mathematics
not sure just how sloppy you are being with the parentheses, You might mean √2+√(2+2cos4x) or √(2+√(2+2cos4x)) either way it's kinda sloppy first step is probably to see what cos4x reduces to
August 1, 2016

math
9+6=15 7/12 + 3/4 = 16/12 ...
August 1, 2016

math
well, 2/3 n = 12, so n = 18 now subtract
August 1, 2016

maths
10 = .20x
August 1, 2016

math
their combined rate of approach is 48 km/hr So, how long does it take to cover 10 km at that rate? Add that many minutes to 11:50 pm Why are they running at midnight???
August 1, 2016

math
If Ariel takes x hours, then it takes Teddy (x-5) hours. So, adding up all their work, you get 1/x + 1/(x-5) = 1/6 Now just find x
August 1, 2016

pre cal
np!
August 1, 2016

pre cal
24π/4 = 24/4 π = 6π that should help, since 2π is equivalent to 0.
August 1, 2016

pre calc
for two complex numbers to be equal, their real and imaginary parts must be equal. So, x = 1 y = -2
July 31, 2016

Nedd Help Please - PreCalc
the only thing you need to remember is that sin(kx) has period 2π/k So, divide that period into four parts, as shown in your example above, then evaluate y at each value of x. Where do you get stuck in that?
July 31, 2016

math
since ln2 < 1 1/ln2 > 1 so it diverges
July 31, 2016

Math
width:length = 600:800 = 6:8 = 3:4 study up on reducing fractions. You divide out the common factors, top and bottom.
July 31, 2016

Math
see previous post
July 31, 2016

math
of course not. List a few terms.
July 31, 2016

MATH
a simple convergent geometric series is r^n where r<1. (1/n - 1/n^2) = (n-1)/n^2 < 1 for all n>0 In fact, 1/n (1 - 1/n) < 1/n < 1/2 for n>2. So, An < 1/2^n for n>2
July 31, 2016

Need Help Please- Pre-Calc
the period of sin(x) is 2π. the period of sin(-π/3 x) is 2π/(π/3) = 6 You need to multiply by the amplitude. You need to reflect in the x-axis, since sin(-x) = -sin(x) so, the quarter points are (0,0), (3/2,-5), (3,0), (9/2,5), (6,0) see the graph at http...
July 31, 2016

Mathis
don't ask much, do you? n=0 sum=0 while n<100   n += 2   sum += n end while print sum
July 31, 2016

Maths
4logx+6logx-7logx=log27 log x^4 + log x^6 - log x^7 = log 27 log (x^4*x^6/x^7) = log 27 ... see what you can make of that
July 31, 2016

math (integral)
maybe not bogus, but not elementary either: https://en.wikipedia.org/wiki/Gaussian_integral
July 31, 2016

Math
0 and 9 -34 and -43 -34 and -25 1000001 and 1000010 I think you get the picture
July 31, 2016

algebra
the original fraction is x/(x+2) (x-1)/(x+2-1) = 1/2 now just solve for x.
July 31, 2016

Kalafaanschool
tends to slow down
July 31, 2016

Maths
24 * 1/2 * pi/6 * 6^3 cm^3
July 31, 2016

GENERAL MATHEMATICS
sec = 1/15 asst = 1/32 (32+x)/(2x+15) = 7/6 2(x + 1/x) = 33/16 and so on. See what you can do with the others here, as well as your two later posts. Do not expect someone here to do your whole assignment. You must be able to make some headway on at least some of them, no?
July 31, 2016

Geometry
follow the hint, and place P 3/7 of the way from A to B.
July 31, 2016

rawani
you can consider one of the forces along the x-axis. Let's use the 10N one. Then the two forces are <10,0> and <6.93,4.0> Add hem up to get <16.93,4.0> or 17.40N at an angle of 13.3° from the 10N force.
July 31, 2016

MATH
The terms of the sequence are (3/4)^n * n^10 or, n^10 / (4/3)^n I'm sure you've seen proofs that exponentials grow faster than polynomials, so this limit --> 0 a google search will turn up many proofs of this, such as http://math.stackexchange.com/questions/55468/...
July 31, 2016

MATH
Take a look at the first few terms in the series: 2/4 - 2/6 2/5 - 2/7 2/6 - 2/8 2/7 - 2/9 ... You can see that the terms start to cancel out. Taking the infinite sum, they all vanish except 1/4 + 2/5 = 9/10
July 31, 2016

MATH
Since (-1)^n / n converges, so does this one. n^3/(n^4+1) < 1/n
July 31, 2016

math
that will be an equilateral triangle of side 6.
July 30, 2016

Physics
The excellent article on wikipedia https://en.wikipedia.org/wiki/Trajectory discusses finding the maximum range on a slope. You can use that to solve for the problem's conditions.
July 30, 2016

Math
figure its fuel consumption rate, in gallons/hr * 4 multiply that by the weight per gallon.
July 30, 2016

Science
depends on the distance of the fulcrum.
July 30, 2016

Calculus
Using the ratio test, An+1/An = (n+1)!/(n+1)^(n+1) --------------------- x        n!/n^n = (n+1)!/n! n^n/(n+1)^(n+1) x = (n+1) (n/(n+1))^n * 1/(n+1) x = (n/(n+1))^n x Hmmm. what to do? = ((n+1)/n)^-n x = (1 + 1/n)^-n x This should look ...
July 30, 2016

matg
first step is usually to get rid of the nasty fractions. I see there's a typo in the first equation. I'll just assume 9/4 x. If wrong, fix it and follow the same steps to solution. 18x + 3y = -18 -4x + 45y = 4 or 6x + y = -6 -4x + 45y = 4 multiply to get rid of x: 12x...
July 30, 2016

AHOOGAAH! Homework Dump
no ideas on any of these?
July 30, 2016

Calculus AB
did you do the sketch? It should be clear that l/5.5 = (x+l)/12 no crank it out. Algebra I, babe.
July 30, 2016

Calculus AB
see similar previous problem. Just express r as a function of h and plug it in.
July 30, 2016

Geometri euclid
If the two circles have radii r and R, then the area between the circles is π(R^2-r^2) If a circle has AB as a diameter, then BC is its radius, since AB = AC + BC BC^2 + r^2 = R^2 so, BC^2 = R^2-r^2 That means the area of the circle with BC as its radius (AB as its ...
July 30, 2016

Calculus AB
v = 1/3 pi r^2 h But the dimension of the tank indicate that at any time, r/h = 4/10 So, use that to eliminate r.
July 30, 2016

Calculus AB
You know where the roots are. You know that if the root is of odd order, the graph crosses the x-axis there. And, if the root is of even order, the graph is just tangent there. So, knowing what you do about the general shape of polynomials, since this one is of even order, The...
July 30, 2016

Math
ratio test says no
July 30, 2016

Math
the two graphs are x^2 + y^2 = 1 (x-2)^2 + (y-3)^2 = 16 x^2-4x+4 + y^2-6y+9 = 16 but, x^2+y^2 = 1, so that means -4x+4 + 1 -6y+9 = 16 4x+6y = -2 so the slope of the line is -2/3 No need to actually find the points.
July 30, 2016

Math
Oops. Not all of those are on the graph. You may be right.
July 30, 2016

Math
well, let's see n   x   y 23 94 -98 22 90 -95 ... -22 -86 37 -23 -90 40 -24 -94 43 -25 -98 46 Looks like a lot more than 9 to me.
July 30, 2016

Math
eliminate t: (30-x)/40 = (50+y)/30 30(30-x) = 40(50+y) 900-30x = 2000+40y 30x+40y = -1100 3x+4y = -110 x = 4n+2 y = -(3n+29) Now just work out how many values of n produce x and y in the desired interval.
July 30, 2016

Physics
google is your friend. Use it.
July 30, 2016

math
See joejoe's post below. Same problem, different letters.
July 30, 2016

Trigonometry
Just factor out sinx: sinx(6sinx-1) = 0 so, sinx = 0 or sinx = 1/6 each will provide two solutions.
July 30, 2016

Trigonometry
The ship turned 90 degrees. So, the distance from port is just the hypotenuse of a right triangle with legs 7 and 24. Look familiar?
July 30, 2016

math
Assuming you mean the ratio of areas, If BC = 2x, then AD = 2x ABD has area 1/2 * 2x * 2x = 2x^2 ABEF has area (2x)*(2x) = 4x^2
July 30, 2016

Math
Sn = a(1-r^n)/(1-r) so, S5 = a(1-r^5)/(1-r)
July 30, 2016

Algebra
Col. Mustard, of course!
July 30, 2016

Math
In the interval -pi/4 <= t <= pi/4, the graph is traced once. But on 0 <= t <= pi/2, only half the curve is completed. Try changing the domain on this plot at http://www.wolframalpha.com/input/?i=plot+x%3Dcos(4t),y%3Dsin(6t),+-pi%2F4+%3C%3D+t+%3C%3D+pi%2F4
July 30, 2016

math
it's not that b is the middle value, but that if we want to build a set of ratios, a:b:c we need to have a common value for b in the two ratios a:b and b:c We could not have placed a or c in the center spot, because we only had one ratio for each of those. But to join the ...
July 29, 2016

math
a:b = 2:3 c:b = 3:2 we want b in the middle, so b:c = 2:3 lcm(2,3) = 6, so now we can write a:b = 4:6 b:c = 6:9 a:b:c = 4:6:9 a:c = 4:9
July 29, 2016

Calculus
try using the ratio test. You should be able to show that the series converges for |x| < e
July 29, 2016

Calculus AB
well, you want cos x = -0.4 so, x will be an angle in QII or QIII Your reference angle is arccos(0.4) = 66.4° so, x will be 180±66.4°
July 29, 2016

math
looks good to me Make sure you specify mm^3 for volume. That's a dang small prism, to be sure...
July 29, 2016

math
A(1+.12*5) = 160000
July 29, 2016

Calculus AB
it's an even multiple of 2pi, so the functions are the same as for 0.
July 29, 2016

Calculus AB
recall that log_a(b) = ln(a)/ln(b) So, converting everything to natural logs (or any set of logs with a common base), ln3/ln25 x + ln7/ln2 y = ln27/ln5 ln8/ln7 x + ln5/ln3 y = ln2/ln49 Now just solve the system as usual. It's messy, but it's just numbers. If you don&#...
July 29, 2016

statitics
just list the cases: P(WL) = 0.60*0.25 P(LW) = 0.40*0.55 Since they are mutually exclusive, P(WL)+P(LW) = 0.37
July 29, 2016

math
Divide 32 by the number of colors. Then count over in the list the remainder. For example, your list has 5 colors 32/5 = 6 R2 So, there are six complete cycles, with 2 left over. The 32nd stripe is thus blue. If you only wanted 4 colors, the do that division instead. A zero ...
July 29, 2016

luderitz
not following instructions, as in the subject of your post.
July 29, 2016

Math
.85x +.60*150 = .80(150+x)
July 29, 2016

math
x = (90-x)-8
July 29, 2016

Math
35 m/s * 1km/1000m * 3600s/hr = ? km/hr
July 29, 2016

science
If the distance is x meters, then since time = distance/speed, x/55 + x/330 = 7 x = 330m Now, the problem is that the bullet will drop 176m in the 6 seconds spent in the air. So, now we have to include the angle of the trajectory, which complicates matters some.
July 29, 2016

Maths
Review your sine rule. It is then clear that sinθ = √(15^2-6^2)/15 It might have been easier to calculate using cosθ = 6/15
July 29, 2016

Accounts
2000(1+.06/2)^(2*6)
July 29, 2016

Stats
Your Z table tells you that about 97% of the population lies below the mean + 1.88 std. so, ...
July 29, 2016

Physics
If I can get by the sloppy typing, it is clear that h^2 + 2^2 = 9^2
July 29, 2016

math
the number who passed either or both is .80+.85-.75 = 0.90 So, 10% of x students failed both: 45 = 0.10x . . .
July 29, 2016

PACE INter Science Colldege
100km/hr * 1L/10km * 1hr/3600s * 1000cm^3/L = 27.77 cm^3/s
July 29, 2016

Math
the linear ratio is √25:64 = 5:8 the volume ratio is thus 5^3:8^3 = 125:512 or, 250:1024
July 28, 2016

math
If the dimensions are x and y, then we have √(x^2+y^2) = x+8 xy = 60 You can grind out the solution, but I think you can recognize which factors of 60 form a convenient right triangle that works, no?
July 28, 2016

Calculus
dang those typos, yeah? 64 works much better.
July 28, 2016

Calculus
x+y=64 z = xy^3 = (64-y)y^3 = 64y^3 - y^4 dz/dy = 192y^2 - 4y^3 = 4y^2(48-y) I think the way is now clear, right?
July 28, 2016

jeez - get it right, willya?
and stop posting it!
July 28, 2016

algebra - eh?
how's that again? The product of two consecutive integer is 5 three times the larger integer
July 28, 2016

Math
just remember that revenue = price * no.tickets.sold You can use that to answer all these questions. Give it a try, and come back if you get stuck. also, recall that the vertex of a parabola ax^2+bx+c is at x = -b/2a. For R(x), that is where the maximum revenue occurs.
July 28, 2016

physics
v = √(2as) = √(2*9.8*20) = 19.80 m/s Now use that to answer the other question.
July 28, 2016

math
can't see hwy you don't just write the fractions, like 1/3, 2/√5, etc. Anyway, since volume is length * width * height then if one or more of those dimensions are scaled by a factor of r,s,t respectively, then the new volume is (length*r)*(width*s)*(height*t) = (...
July 28, 2016

Algebra 1
After n years, v = c(1-r)^n = 20000 * 0.79^n no need to subtract from anything, unless you want to see how much its value has declined. 6154.11 is the value after 5 years.
July 28, 2016

Maths
try using the sum-to-product formulas. If you get stuck, come on back and I'll see what we can do with what you have so far. I see google has some good discussions.
July 28, 2016

Maths
cos3x = cosx(2cos2x - 1) similarly, cos6x = cos2x(2cos4x - 1) I think you can see where this is going, right?
July 28, 2016

Maths
google is your friend many proofs online
July 28, 2016

pre cal
the asymptotes mean y = ??? / (x+2)(x-1) y(0)=0, so y = ax / (x+2)(x-1) y(2) = 12, so 12 = 2a/4 a = 24 y = 24x / (x+2)(x-1)
July 28, 2016

pre cal
vertical asymptote at x=6 and a horizontal asymptote means y = a(x-b)/(x-6) + c y(5) = 0, so b=5 y = a(x-5)/(x-6) + c y(0) = -5/6 and y(∞) = -1, so 5/6 a + c = -5/6 a + c = -1 1/6 a = -1/6 a = -1 c = 0 y = (5-x)/(x-6)
July 28, 2016

math
2 + 2 sinθ = 3 cos^2θ 2 + 2sinθ = 3 - 3sin^2θ 3sin^2θ + 2sinθ - 1 = 0 (3sinθ-1)(sinθ+1) = 0 sinθ = 1/3 sinθ = -1 so, there are two solutions for sinθ = 1/3 (QI and QII) and one solution for sinθ = -1
July 28, 2016

basic maths trignometry
secx - tanx = 1/cosx - sinx/cosx = (1-sinx)/cosx now use the double angle formulas to make that 1 - 2sin x/2 cos x/2 ------------------------- 2 cos^2 x/2 - 1 divide by cos^2 x/2 to get sec^2 x/2 - 2tan x/2 ----------------------------- 2 - sec^2 x/2 1+tan^2 x/2 - 2tan x/2...
July 28, 2016

math
5*4/5 = 4
July 28, 2016

Math
45/9 = x/12 x = 60
July 28, 2016

math
Oops. r=16% I calculated with r as the 6-month interest rate.
July 28, 2016

math
6250(1+r/2)^2 = 6760 r = 8%
July 28, 2016

Maths
For ease of reading, I'll just use s for sinx and c for cosx (1+s-c)/(1+s+c) = (1+s-c)^2/[(1+s)^2-c^2) = (1+s-c-sc)/(s+s^2) = (1-c)(1+s)/(s(1+s)) = (1-c)/s That means that [(1+s-c)/(1+s+c)]^2 = (1-c)^2/s^2 = (1-c)(1-c) / (1+c)(1-c) = (1-c)/(1+c)
July 27, 2016

Maths
I assume you mean arctan(x)+arcsin(x)=3/4 π well, you know that π/4 + π/2 = 3/4 π so, x=1 the hard way: sin(arctan(x)+arcsin(x)) = 1/√2 sin(arctan(x))cos(arcsin(x)) + cos(arctan(x))sin(arcsin(x)) = 1/√2 Now draw the right triangles for arctan(x...
July 27, 2016

pre cal
f(x) = a(x+5)(x-2)(x-4) f(-10) = a(-5)(-12)(-14) = -840a = -4 a = 1/210 f(x) = 1/210 (x+5)(x-2)(x-4)
July 27, 2016

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