Friday

March 27, 2015

March 27, 2015

Total # Posts: 30,097

**geometry**

The median from A goes to the midpoint of BC at (6,3) Its slope is 3/8, so its equation is y = 3/8 (x+2) The bisector of BC also goes through (6,3) with slope -2/5, so its equation is y-3 = -2/5 (x-6)
*March 12, 2015*

**Math**

5-2=3 2+3=5 so, which is greater, 3*3 or 2*5?
*March 12, 2015*

**algebra--1 question**

Neither. It is (x+3)(x+4) (x-3)(x-4) = x^2-7x+12 (x-3)(x+4) = x^2+x-12
*March 12, 2015*

**Math**

1 large bag is 2/(5/6) = 12/5 small bags So, 5 large bags = 12 small bags
*March 12, 2015*

**Math**

draw the road, and label the houses DM=4 MC=1 So, DC = DM+MC = 5 Randy does not matter in this calculation.
*March 12, 2015*

**7th grade geometry**

if the prism has dimensions x,y,z, then if each dimension is increased by 2.5, we have 2(xy+xz+yz) = 2((3.5+2.5)(1.5+2.5) + (3.5+2.5)(2+2.5) + (1.5+2.5)(2+2.5)) = 138 ft^2 But, I doubt that is what happens. The question now is, how wide is the paper, and which dimension(s) get...
*March 12, 2015*

**algebra**

Just use your distance formula: d^2 = (7+9)^2 + (-6-5)^2
*March 12, 2015*

**periodic functions(math)**

(a) see http://www.wolframalpha.com/input/?i=plot+2.5sin%280.523t%29%2B2.9+for+t%3D0+to+24 (b) since sin(kt) has period 2π/k, sin(.523t) has period 2π/.523 = 12.01 That is, the tide cycles every 12 hours. (c) look at the graph and see where d(t) >= 1.3 You want ...
*March 12, 2015*

**Math**

6b+3o = 10 3b+5o = 12 12b+6o = 20 9b+15o = 36 21b+21o = 56 b+o = 56/21 = 2.67
*March 12, 2015*

**math**

If she saves for n days, she will need n(n+1)/2 >= 7000
*March 12, 2015*

**math**

3C1 * 7C3 * 3C1 = 3*35*3
*March 12, 2015*

**physics**

.35 ton * 2000lb/ton * 1N/.2248lb = 3113.88 N
*March 12, 2015*

**algebra**

I find it helps to have the highest powers first: -2x^2+7x-6 -(2x^2-7x+6) -(2x-3)(x-2)
*March 12, 2015*

**alg. Compounding periods.**

#1) how many months in 5 years? #2) 11000(1+.035/365)^90 = 11095.34
*March 12, 2015*

**math**

the wheel has a diameter of 30 ft So, its circumference is 30π ft That means that 4 trips around = 4*30π = 120π ft
*March 12, 2015*

**Math**

Assuming the three angles are listed in order, you have to remember that consecutive angles are supplementary opposite angles are equal. So, 5x-2 + 8y+2 = 180 5x-2 = 3x+22 So, x = 12, making y=15
*March 12, 2015*

**calc**

Been there, done that. 1st related question below: http://www.jiskha.com/display.cgi?id=1425923355 Always check the related questions when you have posted one. Yes, it's not often easy to find the ones you want before.
*March 12, 2015*

**linear equation and one variable**

If the pencil costs x, then the pen costs 7x The rest of the posting makes no sense. I think you left out an amount somewhere.
*March 12, 2015*

**Physics**

v = √(1.8^2 + (9.8*3)^2) = 29.45 If θ is the angle from the vertical, tanθ = 1.8/(3*9.8) h = 4.9*3^2 = 44.1 m distance from base = 3*1.8 = 5.4 m
*March 12, 2015*

**Math**

there are initially 2 yellows out of a total of 10 marbles. chance of yellow on 1st draw: 2/10 with that yellow gone, there is now only 1 yellow out of 9 total, so the chance of a yellow on the 2nd draw is 1/9 So, the total probability is 2/10 * 1/9
*March 12, 2015*

**chemistry**

3g C = 1/4 mole 8g O2 = 1/2 mole So, you have CO2
*March 12, 2015*

**factorise fully**

Do you mean (p^2)(x) or p^(2x) 2q^y or 2q^2 y The mixture of exponents and multiplication seems unlikely. I will assume you meant p^2 x - 2q^2 y - 2 pqx + pqy = (p-2q)px + (p-2q)qy = (p-2q)(px+py)
*March 12, 2015*

**maths**

the area of the tank is 220m^2 So, you want to have a volume of 220*.21 = 46.2 m^3 15 km/hr = 4.167 m/s The area of the pipe is pi*.07^2 = 0.01539m^2 So, the water is flowing in at 4.167*0.01539 = 0.06414 m^3/s 46.2 m^3 / (.06414 m^3/s) = 720 s = 12 min = 0.2 hr
*March 12, 2015*

**Integration**

It occurs to me that a simpler way to go is x = sinθ, θ = arcsin(x) dx = cosθ dθ ∫x arcsin(x) dx = ∫ θ sinθ cosθ dθ = 1/2 ∫ θ sin2θ dθ Now use integration by parts to get u = θ, du = dθ dv = ...
*March 12, 2015*

**Integration**

now let x = sinθ dx = cosθ dθ ∫x^2 / 2√(1-x^2) dx = ∫ sin^2θ / 2cosθ * cosθ dθ = 1/2 ∫sin^2θ dθ = 1/4 ∫1-cos2θ dθ = 1/4 (θ - 1/2 sin 2θ) = 1/4 (θ - sinθ cosθ) = 1/4 (...
*March 12, 2015*

**Integration**

do these the same way, using integration by parts ∫x arcsin(x) dx Let arcsin x, du = 1/√(1-x^2) dx dv = x dx, v = 1/2 x^2 ∫ u dv = uv - ∫ v du ∫ x arcsin(x) dx = 1/2 x^2 arcsin(x) - ∫x^2 / 2√(1-x^2) dx Now you should be able to proceed.
*March 12, 2015*

**Combining Like Terms**

get rid of the parentheses, and you have -4-8-x-9x Surely now you can combine like terms, right?
*March 12, 2015*

**Calculus 1**

y = (√x)^3x lny = 3x ln√x = 3/2 x lnx 1/y y' = 3/2 (lnx + x/x) = 3/2 (lnx + 1) y' = 3/2 y (1+lnx) = 3/2 (√x)^3x (1+lnx) = 3/2 x^(3x/2) (1+lnx)
*March 12, 2015*

**Calculus 1**

y = x^(8cosx) lny = 8cosx lnx 1/y y' = 8(-sinx lnx + 8/x cosx) y' = 8 x^(8cosx) (8/x cosx - sinx lnx)
*March 12, 2015*

**algebra**

(10+8)/(10+8+42)
*March 12, 2015*

**trig**

the circumference of the frisbee is 12π in So, a point on the rim is traveling with a speed of 360*12π in/min Now just convert that to mi/hr
*March 12, 2015*

**calculus**

eh? did you not write down your calculations? How can you possibly not know how you arrived at an answer. I think you mean you are not sure whether your answer is right. At the moment in question, we have a 5-12-13 right triangle. x^2 + y^2 = 13^2 2x dx/dt + 2y dy/dt = 0 2(5)(...
*March 12, 2015*

**math (answer check)**

just make DE the hypotenuse, and consider horizontal and vertical legs. (-5,5),(9,5),(9,8) or (-5,5),(-5,8),(9,8) Trying to make DE one of the legs makes things a lot harder.
*March 12, 2015*

**utd**

The distance z is z^2 = (x-1)^2 + (y-1)^2 2z dz/dt = 2(x-1) dx/dt + 2(y-1) dy/dt At t=π/6, z=√((4(√3/2)-1)^2+(2(1/2)-1)^2) = 2√3-1 Note that at t=π/6, the point on the curve is (2√3,1) So, now we just have dx/dt = -4sint = -2 dy/dt = 2cost...
*March 12, 2015*

**FACTORISE FULLY**

a^3+b^3) = (a+b)(a^2-ab+b^2) so, (3x+y)^3 + (3x-y)^3 = ((3x+y)+(3x-y))((3x+y)^2-(3x+y)(3x-y)+(3x-y)^2) = (6x)(9x^2+6xy+y^2-9x^2+y^2+9x^2-6xy+y^2) = (6x)(9x^2+3y^2) = 18x(3x^2+y^2)
*March 11, 2015*

**Pre-Calculus**

You have his earnings as 100+5+10+15+... Since he gets $100 just for entering, all he needs to do is walk enough miles to get another $50 5+10+15+... is an arithmetic series of n terms, where Sn = n/2 (2*5+(n-1)5) >= 50 n >= 4 Check: 5+10+15+20 = 50
*March 11, 2015*

**Vectors**

Looks good to me.
*March 11, 2015*

**Geometry**

just find θ where sinθ = 25/32
*March 11, 2015*

**Chemistry( HELP PLEASE, IM DESPERATE!!!)**

These are all basically the same. For the first one, it takes 3 moles of O2 for every 2 moles of CH3OH. 13.97g CH3OH = 0.436 moles 5.45g O2 = 0.170 moles 3/2 * 0.436 > 0.170, so the O2 limits the reaction. Each 3 moles of O2 produces 2 moles of CO2, so we will get 2/3 * 0....
*March 11, 2015*

**Calculus 1**

f(x)=3 sin x+ln(5x) f'(x) = 3 cosx + 1/x Note that ln(5x) = ln5 + lnx So, the ln5 is just a constant, with zero derivative Of course, you could use the chain rule, so d/dx ln(5x) = (1/5x)*5 = 5/5x = 1/x
*March 11, 2015*

**Math**

(1+0.013)^n = 2 n = log2/log1.013 ...
*March 11, 2015*

**Pre Algebra**

zero
*March 11, 2015*

**Calc**

Use <= for less than or equal. a(t) = cos(t)-sin(t) v(t) = sin(t)+cos(t) + c v(0)=1, so c=0 v=0 when sin(t)+cos(t)=0. That is, sin(t) = -cos(t) sin(t)=cos(t) when t=π/4, so using that as a reference angle, that makes t = 3π/4 or 11π/4 Only 11π/4 is ...
*March 11, 2015*

**Math**

First, I doubt that 960t-5t is correct. If you meant v=960-5t, then clearly 960 is its maximum speed, whence it slowed down. If you meant v=960t-5t^2, that's a bit more interesting. Then the maximum speed is at t=96, and v(96) = 46080 But, if we stop counting at t=10, then...
*March 11, 2015*

**Ap calc**

a = 12t-6 v = 6t^2-6t+c v(0)=3, so c=3, and v = 6t^2-6t+3 s = 2t^3-3t^2+3t+c Since we assume zero distance at t=0, c=0. s(2) = 2*8 - 3*4 + 3*2 = 10
*March 11, 2015*

**math**

If the interior angle is x, then the sum of the other two interior angles is also x. Since they add up to 180, x=90. Also, since the sum of an interior angle and its adjacent exterior angle is a straight line, they sum to 180. So, the largest interior angle has the smallest ...
*March 11, 2015*

**math**

see the 1st related question below
*March 11, 2015*

**Algebra**

a = 49/10 b = 14/9 The reciprocal of b/a is a/b (49/10)/(14/9) = 49/10 * 9/14 = 441/140 = 63/20
*March 11, 2015*

**math**

4x + 5x = 90 x=10 The angles are 40 and 50 The smaller is increased by 10% from 40 to 44 So, the larger is decreased by 4 to 46. 4 is 8% of 50
*March 11, 2015*

**math**

If you meant that Logan is twice as old as Lindsay, then you are correct in setting it up as you did. Your solution, however, is bogus. x-5 + 2x-5 = 30 3x - 10 = 30 3x = 40 x = 40/3 No joy there. If it should have read Logan is 2 years older than Lindsay, then the equation is...
*March 11, 2015*

**math**

h/800 = sin 15°
*March 11, 2015*

**physics**

just see when the distances are equal: 120km/hr = 100/3 m/s, so 100/3 t = 2.5/2 t^2 t = 80/3 Now I expect you can handle the rest . . .
*March 11, 2015*

**Algebra please explain**

each year the boat is worth .85 as much as it was 92000*.85^10 = 18112.45 You are correct. I assume you were guessing between A and C, since the other two are clearly unreasonable.
*March 11, 2015*

**important maths ques**

As usual, draw a diagram. If you draw a line through the center, perpendicular to the chords, you cut them in half. The radius is the hypotenuse of two right triangles. One has a leg of 5, and the other has a leg of 12. So, 5^2 + 12^2 = r^2 12^2 + (17-x)^2 = r^2 5^2 + x^2 = 12...
*March 11, 2015*

**maths please help and explain**

2logx + 1 = log900 since 1 = log10, 2logx + log10 = log900 log x^2 + log10 = log900 log(10x^2) = log 900 10x^2 = 900 x^2 = 90 x = √90 3log(x-2) = 4.714 log(x-2)^3 = 4.714 (x-2)^3 = 51760.68 x-2 = 37.268 x = 39.268 16^(x-3) = 8^(2x+1) since 16 = 2^4 and 8 = 2^3, 2^(4(x-3...
*March 11, 2015*

**MATHS**

this is just like your last problem with the fruits. Try writing down in algebra what they told you. Come back if you get stuck, but show how far you got.
*March 11, 2015*

**maths**

What info did they give? d+p+a = 1134 .75d = a+252 p-96 = a+252 Now you can solve for the amounts.
*March 11, 2015*

**Maths**

Quite an interesting result, new to me. I see you have a typo. This problem is discussed here: http://math.stackexchange.com/questions/364002/prove-that-tan-1-fracyzxr-tan-1-fraczxyr-tan-1-fracxy
*March 11, 2015*

**math**

without trying to go into any existential discussion, let's just say that it is usually written as 1/4 I suspect there is more than that to your question . . .
*March 11, 2015*

**math**

or, if the slope is vertical, there's no derivative there. y = ∛x
*March 11, 2015*

**math**

not so. consider y = |x| Any time there's a cusp, or pointy place, on the graph, f is continuous, but since the slope changes instantly from one value to another, it is not differentiable there.
*March 11, 2015*

**math**

we all know that near x=0, sin(x) = x (or nearly) Since sin(pi-x) = sin(x), sin(pi-x) = pi-x
*March 11, 2015*

**Trigonometry**

just plug the numbers into the sum/difference formulas. Surely you can do that... Since both x and y are less than π/4 (why?), x+y is in QI. Since y > x, x-y is in QIV.
*March 11, 2015*

**MATH**

slope = tan 45°
*March 11, 2015*

**math**

As usual, 42
*March 11, 2015*

**math**

v = 4^3 = 64 ft^3 Now you can easily do (b), yeah?
*March 10, 2015*

**math**

x^2 + (x+7)^2 = 13^2 Looks like a 5-12-13 triangle to me.
*March 10, 2015*

**Pre-Calculus(Trignometry)**

Looks good to me.
*March 10, 2015*

**Calculus**

never come here expecting help "in a couple of minutes." you can't count on anyone's watching every post as it comes up. The first related question below is this exact problem, just with different numbers. Always be sure to check the related questions when ...
*March 10, 2015*

**algebra**

you have two points: (200,6) and (300,15) So, just use the two-point form of the line: y-6 = (9/100)(x-200)
*March 10, 2015*

**Pre-Calculus**

Because of symmetry, the vertex is midway between the roots: x = -13
*March 10, 2015*

**Pre-Calculus**

Looks good to me
*March 10, 2015*

**Calculus**

when the elevator is at height x, tanθ = (x-23)/15 so, sec^2θ dθ/dt = 1/15 dx/dt (1+tan^2θ) dθ/dt = 1/15 dx/dt (1 + ((x-23)/15)^2) dθ/dt = 1/15 dx/dt Now just plug and chug. You have x, and dx/dt=4 ...
*March 10, 2015*

**calculus**

3x^2+y^2 = 7 6x + 2yy' = 0 y' = -3x/y using implicit differentiation again, 6x + 2yy' = 0 6 + 2y'^2 + 2yy" = 0 y" = -(6+2y'^2)/2y = -(6+2(9x^2/y^2))/(2y) = -3(3x^2+y^2)/y^3 = -21/y^3 or, using the quotient rule, y' = -3x/y y" = ((-3)y...
*March 10, 2015*

**Math**

If you add up 22+18, that's 40. But, you counted the 6 who have both twice, so that leaves only 34. So, of the 50 students, 34 have shoes or boards, or both. So, 16 students have neither.
*March 10, 2015*

**math**

room: 8*6 = 48 carpet: 6*4 = 24
*March 10, 2015*

**Math**

(10+7)/(2+10+16+7)
*March 10, 2015*

**Math**

The letter C is not a closed shape. Is it not real?
*March 10, 2015*

**Math**

probably, but I'm not sure what you mean by "wider." All the graphs stretch out both directions infinitely far. However, (B) does so more slowly, so I guess you could say it's wider. See http://www.wolframalpha.com/input/?i=plot+y%3D3x^2%2B2%2C+y%3D3x^2%2B3%...
*March 10, 2015*

**Math questions**

3/4 = 18/24 5/6 = 20/24 8 3/4 = 8 18/24 = 7 42/24 7 42/24 - 5 20/24 = 2 22/24 = 2 11/12
*March 10, 2015*

**math**

4 1/2 yards is 4*36 + 18 = 162 inches She was left with 3 ft 8 in = 36+8 = 44 inches. I think now you can handle the rest, yeah?
*March 10, 2015*

**Geometry**

since volume scales as the cube of the linear scale, the new cone is scaled in every dimension to 3/4 the original cone. So, its volume is (3/4)^3 * 1920 = 810 Note that you don't need the height, just the relative scale factor. 1/3 pi r^2 h = 1920 1/3 pi (3/4 r)^2 (3/4 h...
*March 10, 2015*

**Math**

sorry, no Venn diagrams here.
*March 10, 2015*

**algebra**

If the digits are a and b, then we have a+b = 8 10b+a = 10a+b - 18
*March 10, 2015*

**Arithmetic Progressions**

a+d = 4a a = 10 10+d = 40 d = 30 S12 = 12/2 (2*10 + 11*30)
*March 10, 2015*

**math**

Trick question. At its highest point, the ball changes direction. It has to stop to do that. v = 0
*March 10, 2015*

**Math**

I'll do one, and you can do the other. You can check your work at wolframalpha.com x^3-x = x(x-1)(x+1) so we want A/x + B/(x-1) + C/(x+1) = (3x^2-7x-2)/(x^3-x) So, using the common denominator, we have A(x^2-1) + Bx(x+1) + Cx(x-1) = 3x^2-7x-2 (A+B+C)x^2 + (B-C)x - A = 3x^2...
*March 10, 2015*

**Mathematics**

well, just subtract 6√2 - 6 = 6(√2-1) On the other hand, if you're just asking about the nature of the difference, 6√2 is 6 times √2 6 is just 6 what is the difference between 6*3 and 6? same question, different numbers. Not sure just what is ...
*March 10, 2015*

**maths**

avg speed is total distance/total time time = distance/speed, so (100+200)/(100/40 + 200/60) = 360/7 km/hr
*March 10, 2015*

**math**

2*3*6 sinx*sinx cosx*cosx 36 sin^2(x) cos^2(x) or 9(2 sinx cosx)^2 9 sin^2(2x) 9/2 (1-cos(4x))
*March 10, 2015*

**math**

8 cubes of side 2 have surface 8(6*2^2) one cube of side 4 has surface 6*4^2
*March 10, 2015*

**math**

it appears you want 2^2010 + 2^2012 + 10 --------------------------- 2^2009 + 1 (2^2009*2 + 2^2009*8 + 10)/(2^2009+1) (2^2009*10 + 10)/(2^2009+1) 10(2^2009+1)/(2^2009+1) 10
*March 10, 2015*

**trapezoidal method**

there are many trapezoid rule calculators online, which explain the method and do the math.
*March 10, 2015*

**College Algebra**

if there is x at 10%, the remainder (12000-x) is at 3%. So, add up the interest: .10x + .03(12000-x) = .06(12000)
*March 10, 2015*

**math**

2 min = 8*15sec so, it will double 8 times. 10 * 2^8 = ?
*March 10, 2015*

**Algebra 2**

If you mean the nth term is -4 (1/3)^(n-1) then clearly you have a GP where a = -4 r = 1/3 The terms are -4, -4/3, -4/9, ... The sum is thus a/(1-r) = -4/(2/3) = -6
*March 10, 2015*

**Geometry**

75 at W20°S = <-70.48,-25.65> 125 at N10°W = <-21.71,123.10> Add them up to get the resultant: <-92.19,97.45> Now just convert that back to distance and heading.
*March 10, 2015*

**Elective mathematics**

since there is a common ratio, (2k-4)/(k-3) = (4k-3)/(2k-4) (2k-4)^2 = (4k-3)(k-3) 4k^2 - 16k + 16 = 4k^2 - 15k + 9 k = 7 Now just plug and chug.
*March 10, 2015*

**Analytic geometry**

I don't know what you mean by necessary, but the hyperbola is 9x^2+18x - 4y^2+8y = -41 9(x^2+2x+1) - 4(y^2-2y+1) = -41 + 9*1 - 4*1 9(x+1)^2 - 4(y-1)^2 = -36 or, 4(y-1)^2 - 9(x+1)^2 = 36 (y-1)^2/9 - (x+1)^2/4 = 1 That should tell you what you need to know.
*March 10, 2015*

**Calculus**

exponentials grow faster than any power. So, x^5/e^x -> 0 consider using l'Hospital's Rule. After 5 times, the limit is 120/e^x -> 0
*March 10, 2015*

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