since it's a right triangle, the 3rd side is just the hypotenuse, so c^2 = 6^2+6^2 only one 4" panel would fit in a 6" wall.
forget the "to" x+7 >= 3x 7 >= 2x 7/2 >= x 3x+4 <= 5x 4 <= 2x 2 <= x
standard trig substitution Just as ∫[dy/(1+y^2)] = arctan(y), ∫[dy/(1-y^2)] = arctanh(y)
advanced pre algebra
forget the "to" -6 >= g+4 -10 >= g or, if you like, g <= -10
how many times you gonna post this question, which has been answered already? click on the "alex" link above to see.
xy' + 1 = y^2 xy' = y^2-1 y' = (y^2-1)/x dy/(y^2-1) = dx/x arctanh(y) = log(x) or, log (1-y)/(1+y) = 2log(x)+c and you can massage that into exponentials and wind up with y = 1-e^(2cx^2) / 1+e^(2cx^2)
A = .00385B A = .00385(3.5) = .013 ml Something tells me there's a typo somewhere here. No beaker is so small as to make that amount of liquid measurable.
100 x 7.5 = ?
J = work N = force work = force * distance