Friday

May 6, 2016
Total # Posts: 40,219

**Algebra**

clearly you have skipped the definitions. arithmetic has terms which differ by the same amount geometric has terms with a common ratio, one to the next. a) has a ratio which changes: A(n) = A(n-1)*n A(n)/A(n-1) = n, which is not constant not GP or AP b)That +8 is a dead ...
*May 3, 2016*

**math**

do you have some kind of calculation to buttress your gut feeling? play with some numbers, at least.
*May 3, 2016*

**math**

original: n/d new: .5n/.75d = (2/3)(n/d) so, it is decreased by 33.3%
*May 3, 2016*

**Math -Trig**

for any x, cot(x) = 1/tan(x) 3pi/4 is in Quadrant II, so draw the triangle. x = -1 y = 1 cot(3pi/4) = x/y = -1/1 = -1 or, consider that cot(pi-x) = -cot(x) since cos(pi-x) = -cos(x) and sin(pi-x) = sin(x) so, cot(3pi/4) = cot(pi - pi/4) = -cot(pi/4)
*May 3, 2016*

**Math - Trig**

12 revolutions per minute 3.5*pi meters per revolution ...
*May 3, 2016*

**math**

Apparently greedy Ashley already had 1/4 of a pizza! anyway, 1 3/4 = 7/4 divide that by 11, as we're just talking about the friends.
*May 3, 2016*

**half-life**

.5mg is 1/8 of 4 mg 1/8 = (1/2)^3 so, that's 3 half-lives
*May 3, 2016*

**math**

60/36 ft * 12in/ft
*May 3, 2016*

**maths**

200 sin40
*May 3, 2016*

**Math**

1/6 of the time for each number.
*May 3, 2016*

**math**

11!/(2!2!2!2!) = 2,494,800
*May 3, 2016*

**Calculus**

see a nice calculator here to check your work: http://www.emathhelp.net/calculators/calculus-2/simpsons-rule-calculator/
*May 3, 2016*

**math**

(60 * 0.80 - 10) * 1.55 = $58.90
*May 3, 2016*

**math**

a = b + 0.50b = 1.5 b b = a/1.5 = 2/3 a so, b is 1/3 less than a, or 33.3% less
*May 3, 2016*

**math**

increasing by N% means the new value is 1+N/100 as much as the old value. So, we have new = old*(1+1)(1+1.5) = 5.00 * old so, old = new/5 or 20%
*May 3, 2016*

**math**

x * 1.25 = 2 x = 1.6 so, the first increase was 60%
*May 3, 2016*

**urgent math**

#1. 7^(9-3) = 7^6 NOT 7^(9/3) = 7^3 subtract exponents when dividing numbers. What you have is 7*7*7*7*7*7*7*7*7 ------------------------ 7*7*7 only three of the 7's cancel #2 z^8/z^12 = 1/z^4 = z^-4 So, D, not C #3 ok #4 not sure what ...
*May 3, 2016*

**Math**

two adjoining trapezoids produce a figure with six sides. You only give four lengths. You will need to use the sides and the Pythagorean Theorem to determine the heights of the trapezoids. Then it's easy, since you know the formula for the area of a trapezoid, given its ...
*May 3, 2016*

**Algebra**

#10. since 1=√1, you must have -2v-3 = 1 #11. √(n+5)= √(5n-11) n+5 = 5n-11 n = 4 check: √9 = √9 #12. well, geez, just check them! √(12-(-4)) = √(12+4) = √16 = 4 Since this is not equal to -4, that value is extraneous. √(12-...
*May 3, 2016*

**math**

independent means they can both happen, and do not affect each other. Like two consecutive rolls of a die. Rolling a 3 and then a 6 are independent, and can both happen. Mutually exclusive events cannot both happen, such as flipping a coin and getting both a head and a tail. ...
*May 3, 2016*

**Science**

well, time = distance/speed, so just crank it out.
*May 3, 2016*

**Math**

(2 – 9c)(–8) 2(-8)+(-9c)(-8) -16 + 72c
*May 3, 2016*

**Geometry/Trig**

since the acute angles are 45°, the two legs are both 16 (a fact you left out) so, the hypotenuse is √(16^2 + 16^2) = 16√2
*May 3, 2016*

**chemistry**

moles KOH = .0175 * .553 = .00968 so, you need that many moles of HBr, making the molarity M = .00968/.025 = 0.387
*May 3, 2016*

**Math**

x - x/3 + 25 = 115
*May 3, 2016*

**math 1324**

x+y+z = 2000000 .07x + .085y + .095z = 169750 y = 4z see the matrix solution at http://www.wolframalpha.com/input/?i={{1,1,1},{.07,.085,.095},{0,1,-4}}*{{x},{y},{z}}+%3D+{{2000000},{169750},{0}} {{1,1,1},{.07,.085,.095},{0,1,-4}}*{{x},{y},{z}} = {{2000000},{169750},{0}}
*May 3, 2016*

**Analytic Geometry**

cot2θ = 0 so θ=45° Then just do the rotation matrix stuff to find the equation in the new coordinates.
*May 3, 2016*

**math**

won = 15+3*lost won + lost = 123 lost = 27 won = 96
*May 3, 2016*

**math**

3/200 = 1.5/100 = 1.5%
*May 3, 2016*

**Math**

tanx/sinx = 1/cosx cosx=0 at odd multiples of pi/2. So, that is where you have asymptotes. cosx changes sign at those points, so also does your graph.
*May 3, 2016*

**math**

depends on the area of the base. Divide the volume by the area to get the height.
*May 3, 2016*

**math - eh?**

huh?
*May 3, 2016*

**math - Correction.**

that is an obtuse angle. I'd say 0° < d < 90°
*May 2, 2016*

**Maths**

The three numbers will therefore be close to 21.98. So, I'd say they'd be 21,22,23 whose product is 10626
*May 2, 2016*

**math**

480ft/30s * 60s/min = 960 ft/min
*May 2, 2016*

**math**

not so. you have found d/dt (dy/dx), but you want d/dx (dy/dx) = d/dt(dy/dx) / dx/dt = -1/(1+t)^2 / e^t = -1/((1+t)^2 e^t)
*May 2, 2016*

**TRIGONOMETRY2**

can't use google? 1st hit led to http://www.cut-the-knot.org/proofs/2Colors2Points.shtml#solution
*May 2, 2016*

**TRIGONOMETRY**

√(x+b)-√(x-a) >= √(x+a)-√(x-b) since x>=a>=b, we have x+b >= 2b x-a >= 0 x+a >= 2a >= 2b x-b >= x-a see what you can do with that
*May 2, 2016*

**Math**

the ratios are: length: 11/33 = 1/3 width: 7/28 = 1/4 so, not similar
*May 2, 2016*

**math**

not quite. log(x^2) = 2logx 150 = 3*100/2, so log 150 = log3 + 2log10 - log2 75 = 3*(10/2)^2, so log75 = log3 + 2log10 - 2log2 or, since 75 = 150/2 log75 = log150-log2 as above
*May 2, 2016*

**Probability**

1/15000 (1000 + 2*300 + 20*10) = 3/25
*May 2, 2016*

**Math**

there is no limit. There must be some other considerations.
*May 2, 2016*

**Geometry**

well, just check. a sphere with diameter d has volume π/6 d^3 3*(π/6)(5^3) = 375π/6 (π/6)*8^3 = 512π/6 π/12 * 10^3 = 500π/6
*May 2, 2016*

**calculus**

94 ∑ k k=3 assuming you meant ... 144, 12 ∑ k^2 k=3
*May 2, 2016*

**Algebra**

y=5x
*May 2, 2016*

**pre-cal**

as they said, the total area is xy as for the print area, that is (x-2)(y-3) = 26
*May 2, 2016*

**calculus**

maximize p=x(30-x)-100-6x subject to x >= 10 x <= 20 the profit is revenue-cost, so p(x) = x(30-(x-10)) - 100 - 6x = -x^2+34x-100 dp/dx = 34-2x dp/dx=0 at x=17
*May 2, 2016*

**calculus**

this is just the chain rule in reverse. G'(x) = cos(x^2) (2x)
*May 2, 2016*

**calculus**

change all the t's to x^2, then multiply by (x^2)' G(x) = cos(x^2)(2x)
*May 2, 2016*

**math**

it is a function whose graph is s straight line.
*May 2, 2016*

**calculus**

Sketch the region. It has vertices at (0,0), (2,0), (4,2) You can get the area by using vertical or horizontal strips. Using vertical strips, they all lie below the curve √x, but the lower boundary changes from y=0 to y=x-2 at x=2. So, the area is ∫[0,2] √x ...
*May 2, 2016*

**math**

as usual, v = Bh = 20*10 = 200 cm^3 note that the area of the base must be in cm^2, not just cm.
*May 2, 2016*

**Math**

You have only listed 4 side lengths, so I'm not clear. But, to get the area, divide it up into triangles, and maybe rectangles, if there are any. Then just add up the areas of the pieces.
*May 2, 2016*

**math**

the base is 139.2/9.6 = 14.5 since all sides are the same, the perimeter is 4*14.5 = 58
*May 2, 2016*

**algebra**

(17-1)/(2-(-2)) = 16/4 = 4
*May 2, 2016*

**calculus too hard help**

Let's pick up at lny = x ln(y) 1/y y' = ln(y) + x/y y' y' (1/y - x/y) = ln(y) y' = y*ln(y)/(1-x) I'd suggest not looking too hard for a pattern. Pop over to wolframalpha.com and try entering x^x, then x^x^x, then x^x^x^x, and so on. The derivatives ...
*May 2, 2016*

**Math**

Thank you Reiny. That makes perfect sense to me. Next time I post a question I will think a little harder to possible ways of working questions like this. 😀😀
*May 2, 2016*

**Math**

When a telephone exchange is established, there are 10,000 new phone numbersto use(i.e. 722-0000 to 722-9999). Of these 10,000 phone numbers, how many do not contain the digit "9"? I know I can do it this long way, but how do I do it in a shorter more reliable way. ...
*May 2, 2016*

**Calculus - urgent**

Consider the mass as a bunch of horizontal strips, each with area (x2 - x1) dy and thus mass (x2-x1)y dy = y(√(1+2y/3) - (2y^2-y)) dy Now just integrate from 0 to 1.0989
*May 2, 2016*

**trigonomentry...Very hard**

theta, not tita. let x = 3tanθ x^2 = 9tan^2θ 9+x^2 = 9+9tan^2θ = 9sec^2θ √(9+x^2) = 3secθ so, draw a right triangle. Since tanθ = x/3, those are the two legs, and the hypotenuse is √(9+x^2) Now you can write down sinθ and cosθ
*May 2, 2016*

**Geometry (answer please)**

#1. well, each wire is the hypotenuse of a right triangle, with legs 16 and 10√2 back later for #2.
*May 2, 2016*

**Math**

surely, 3+3+3 feet, no? assuming the ribbon is to go once around the edges of the blanket...
*May 1, 2016*

**Math**

since u.v = |u||v|cosθ we must have cosθ = -1. In other words, v = -u
*May 1, 2016*

**Algebra 1**

B is good.
*May 1, 2016*

**math**

If you're using logs base 10, recall that log(32) = log(10*3.2) = log(10)+log(3.2) = 1+log(3.2) So, just look up log of 3.2 and add 1. Whoa - who uses tables these days?
*May 1, 2016*

**Plane trigonometry**

I don't know what "the five points" are, but here's the graph: http://www.wolframalpha.com/input/?i=2sin%28pi*%28x%2B1%2F2%29%29%2B1
*May 1, 2016*

**trig**

I'll use x for ease of typing tan(x)/(tan(2x)-tan(x)) tan(x)/((2tanx)/(1-tan^2(x))-tan(x)) tan(x)/((tanx(2/(1-tan^2(x)) - 1) 1/(2/(1-tan^2(x)) - 1) (1-tan^2(x))/(2 - (1-tan^2(x)) (1-tan^2(x))/(1+tan^2(x)) (1-tan^2(x))/sec^2(x) (1-tan^2(x))cos^2(x) cos^2(x)-sin^2(x) cos(2x)
*May 1, 2016*

**Algebra**

you are correct.
*May 1, 2016*

**MEASUREMENTS**

15m^2 * (3.28ft/1m)^2 * 1bag/20ft^2 * $2.00/bag = $16.14 you said M^2, then used YD^2. I used meters, but you can fix it. Your units do not work out right, and you lost the 15
*May 1, 2016*

**Exponential Modeling**

on the other hand, given the topic of the posting, 0.10(1+r)^40 = 1.25 (1+r)^40 = 12.5 1+r = 1.065 r = 6.5% per year
*May 1, 2016*

**MATH**

The scores are x x x x x x x x The median is 5, so they are x x x 5 5 x x x or x x x 4 6 x x x or 3 3 3 3 7 7 7 7 In the first case, 5 goals are scored. Otherwise, we need not have any scores of 5.
*May 1, 2016*

**math**

this is discussed at http://mathforum.org/sum95/suzanne/whattess.html google is your friend. Use it.
*May 1, 2016*

**MATH- HELP PLEASE. IM LOST**

the other side is either 3.7Ø or 3.7/Ø
*May 1, 2016*

**Geometry ( helllppp pleaaassse )**

#1. How can working with a single point on the ceiling tell anything about the length of the ceiling? #2. Drop the ladder to the floor, and mark where it hits. The use the ladder to construct a hexagon. Two of the main diagonals intersect at the center of the hexagon, just ...
*May 1, 2016*

**Exponential Modeling**

100 * (1/2)^7
*May 1, 2016*

**Exponential Modeling**

2000 * (1/2)^x
*May 1, 2016*

**Exponential Modeling**

p = 1013 * .88^x check for typos
*May 1, 2016*

**Math**

subtract 32 and multiply by 5/9 C = 5/9 (F-32)
*May 1, 2016*

**Algebra**

try this useful site: http://www.zweigmedia.com/RealWorld/LPGrapher/lpg.html
*May 1, 2016*

**Math**

5/6 * 1/2 = 5/12 you might as well ask, what is 1/2 of 5/6?
*May 1, 2016*

**Math**

a + a+d + a+2d = 24 a+3d + a+4d + a+5d = 51 now simplify the equations and solve for a and d.
*May 1, 2016*

**Geometry**

If the foot of the ladder started out at x ft away from the wall, then we know that the length of the ladder is 2x ft. With a 45° angle, then the two legs are x+8 ft, and the length of the ladder is (x+8)√2. So, now we have 2x = (x+8)√2 x(2-√2) = 8√...
*May 1, 2016*

**Solid Mensuration**

circles can be packed in many ways. If they are in a rectangular lattice then they may be in a 2x3 array, in which case, each circle's diameter is 1 foot. Surely by now you have made some attempt to solve the problem...
*May 1, 2016*

**Matthhh**

the straight-line distance is √(60^2+6^2) = 60.3 ft, so ...
*April 30, 2016*

**Algebra**

since there is a walkway on both sides, each dimension is increased by 2x. A(x) = (20+2x)(15+2x)
*April 30, 2016*

**Algebra**

since time = distance/speed, 6/(90-x) + 6/x = 4.5 x ≈ 1.35 km/hr
*April 30, 2016*

**math**

1 2 3 5 6 6 6 so, it can be 1. or even 1 5 5 5 5 5 6
*April 30, 2016*

**Discrete Mathematics**

26!/(8!12!6!) wow - who'd have thought that the entire set of books would contain only three different titles?
*April 30, 2016*

**CES**

1*22 + 9x = 8(x+22)
*April 30, 2016*

**MATH**

volume = 50*10*20 cm^3 1 liter = 1000 cm^3
*April 30, 2016*

**algebra**

I suspect the subtraction problem is 2x^2+5x-10 3x^2-x+9 ----------------- -x^2+6x-19
*April 30, 2016*

**math**

42 is the answer to the Ultimate Question of Life, the Universe and Everything -- surely it answers your feeble inquiry! Actually, I have no idea what you're talking about. which columns are you talking about? The only thing I can think of is that the line of cars looks ...
*April 30, 2016*

**Math**

well, 1 meter is 100 cm. So, how much is still needed?
*April 30, 2016*

**rio claro west secondar**

0.4^2 * 3.7 = 0.16 * 3.7 = ?
*April 30, 2016*

**math**

bzzt. The new value is 120% of the old one, so it increased by 20%.
*April 30, 2016*

**math**

3 of 8 = 3/8 = .375 = 37.5% t2o killed leaves 6 to share, so adjust the fraction. then subtract to find the change.
*April 30, 2016*

**math**

well, what are the nearby multiples of 500? ... 29,000 29,500 30,000 ... which is closest?
*April 30, 2016*

**maths**

you kidding me? You can't count by twos?
*April 30, 2016*

**Maths**

LCM(30,60,x) = 1500 30 = 2*3*5 60 = 2^2*3*5 1500 = 2^2*3*5^3 x could be 5^3 = 125 or any multiple of 25 consisting only of 2,3,5 as factors GCF(30,60,x) = 10 so, 125 is out, but 250 is in LCM(30,60,250) = 1500 GCF(30,60,250) = 10
*April 30, 2016*