sin(2π/3) = sin(π-π/3) = sinπ cosπ/3 - cosπ sinπ/3 = 0+sinπ/3 1/0 is undefined. cosx = ±√3/2 cosx > 0 in QI,QIV cosx < 0 in QII,QIII
the expression is undefined when the denominator is zero, because division by zero is undefined. 5m^2+m = m(5m+1), so it is zero for m = 0 or -1/5 even ignoring the typo in the numerator.
If there are x named Main, then x + x+2105 = 12485. Now just solve for x.
|T-346| <= 2 344 <= T <= 348 so, keep heating.
Physics I Newton's 2nd Law
excuse me? One of the most fundamental identities is F = ma
C: 2a+b=2d H: 6a+2c=6d O: 2b+c=d now, 6a+3b=6d 6a+2c=6d so, 3b=2c 6a+3b=6d 12b+9b=6d so, a=3b=2c So, if we choose a=6 because 6=LCM(2,3) a=6 b=2 c=3 d=7 and we have 6C2H6 + 2CO2 + 3H2O → 7C2H5OH
what is Jeopardy?
.00025km/hr * 1000m/km * 1hr/60min = .004m/min
what about it?