#1. ok #2. I get 160 -- better check again #3. solve for t when h=0 #4. 180 + 20t - 16t^2
12 = mu * 24g
assuming a constant volume v, we have v = pi r^2 h so, h = v/(pi r^2) the surface area is a = 2pi r(r+h) = 2pi r(r + v/(pi r^2)) = 2 pi r^2 + 2v/r da/dr = 4pi r - 2v/r^2 = 2(2pi r^3 - v)/r^2 we want da/dr=0 for max/min area, so r = ∛(v/(2pi)) h = v/(pi r^2) = ∛(4v/...
There are 20 scores, so 74 is the one with 90% of the scores below it.
since ln(e) = 1 ln(e^5) = 5ln(e) = 5 so, you are correct. Though I didn't see the x creep in.
If you mean solve for x, then 8^x = √2 (2^3)^x = 2^(1/2) 2^(3x) = 2^(1/2) 3x = 1/2 x = 1/6 5^x = 1/√25 5^x = 1/5 5^x = 5^(-1) x = -1 don't know what the (3) means
visit wolframalpha.com and enter plot x=3cosθ,y=3sinθ note that x^2+y^2 = 9
you know the parallel line also has slope -2, so using the point-slope form, that is (y-0) = -2(x-2) ....................... the perpendicular line has slope -1/(-2) = 1/2 Figure the y-intercept and you again have a point and a slope.
(y-4)/(x-2) = (2-4)/(3-2) y-4 = -2(x-2) y = -2x+8 if x=0, y=8 if y=0, x=4 so, the intercepts are (0,8) and (4,0) I'm hoping you can figure out which is which