Thursday

October 8, 2015
Total # Posts: 34,415

**English**

thank you
*September 8, 2015*

**English**

Read the following sentences from "The Youngest Doll."The aunt thought he was listening for the breathing of the prawn to see if it was still alive, and shefondly lifted his hand and placed it on the spot where he could feel the constant movement of thecreature's...
*September 8, 2015*

**Math**

w/(7 1/4) = 15/(8 1/2) w = 435/34 = 12 27/34 Strange measurements.
*September 8, 2015*

**Algebra**

see related questions below.
*September 8, 2015*

**physics**

a = ∆v/∆t = (6.90-25.6)m/s / (8.38-0)s = (-18.7 m/s)/8.38s = -2.23 m/s^2
*September 8, 2015*

**Science**

and did you do an experiment and collect data?
*September 8, 2015*

**Coding**

just double-click on cmd.exe
*September 8, 2015*

**calculus - My Bad**

I misread the 2nd problem - go with Reiny.
*September 8, 2015*

**calculus**

D(x) = x^2+2x D(C) = C^2+2C = (4x-5)^2 + 2(4x-5) = 16x^2 - 32x + 15 f(x) = 1+√(x+2) f(f) = 1+√(f+2) = 1+√(1+√(x+2)+2) = 1+√(3+√(x+2))
*September 8, 2015*

**Precalc**

C(x) = 4x-5 C(D) = 4D-5 = 4(x^2+2x)-5 = 4x^2 + 8x - 5
*September 8, 2015*

**Algebra**

M >= 10 O >= 3 3M+12O <= 84
*September 8, 2015*

**math**

2*5*3 = 30
*September 8, 2015*

**math**

1&1/2 ≈ 2 2&6/7 ≈ 3 7*2*3 = 42
*September 8, 2015*

**Algebra**

Anyway, if you suspect a geometric series, just divide any term by the preceding term to get the common ratio (1/5) / 1 = 1/5 (1/25) / (1/5) = 1/5 . . .
*September 8, 2015*

**Algebra**

you can't see the common ratio between 1, 5, 25? Hmmm. a = 1 r = 1/5 S = a/(1-r) = 1/(1 - 1/5) = 1/(4/5) = 5/4
*September 8, 2015*

**Algebra**

It is indeed the commutative property of multiplication.
*September 8, 2015*

**Math**

13 hours is 6 hrs less than 19 hours. So, add 6(0.6) to the height.
*September 8, 2015*

**Math**

The nth term is the sum of the first n positive integers. Or, starting with 1, add 1. Then increase the amount added by 1 for each term. That is, the next amounts added are 2,3,4,5,...
*September 8, 2015*

**math**

24 = 2^3 * 3 36 = 2^2 * 3^2 GCF = 2^2 * 3 = 12 21 = 3 * 7 56 = 2^3 * 7 GCF = 7 For the GCF, find the prime factors and their powers. Then multiply the smallest power of each prime that is common to both numbers.
*September 8, 2015*

**Math**

Assuming that leading zeros are not used, there are 34 and 43 The 3-digit ones are 304 340 403 430 So, add them up
*September 8, 2015*

**PreCalc**

the slope is, naturally, tan(7π/6)
*September 8, 2015*

**PreCalc**

that would be y = tan(1.2) x
*September 8, 2015*

**Math**

72 = 8*9 504 = 7*8*9 Does that help?
*September 8, 2015*

**Math**

LCM(16,24,30) = 240 10000/240 = 41.6 So, 42*240 will be the next multiple of 240.
*September 8, 2015*

**Math**

18 = 2 3^2 25 = 5^2 35 = 5 7 So, the LCM is 2 * 3^2 * 5^2 * 7 = 3150 3150*2 = 6300 3150*3 = 9450 I expect that is the largest 4-digit multiple.
*September 8, 2015*

**Mathematics**

ever hear of a 5-12-13 right triangle? No? Ever hear of the Pythagorean Theorem?
*September 8, 2015*

**Math**

(x-84)/(x-156) = 7/4 x = 252 Note that 252 is not the answer to the question.
*September 8, 2015*

**Math**

12000 * 1.023^5
*September 8, 2015*

**Math**

(a+b)^2 = a^2 + 2ab + b^2 So, 5^2 = 2*4 + a^2+b^2 a^2+b^2 = 17 Now do the next, knowing that (a^2+b^2)^2 = a^4 + 2a^2b^2 + b^4
*September 8, 2015*

**Maths**

google is your friend. https://in.answers.yahoo.com/question/index?qid=20130802032429AAbedMl
*September 8, 2015*

**calculus**

dy/dx=3x^2(e^-y) e^y dy = 3x^2 dx e^y = x^3 + c y = ln(x^3+c) Can't provide a particular solution unless you can tell me something else about y or c.
*September 8, 2015*

**calculus**

dy/dx = 9x^2 y dy/y = 9x^2 dx ln y = 3x^3 + c y = c e^(3x^3)
*September 8, 2015*

**Algbra 2**

You have (1.8 x 10^-3)(9.32 x 10^2) ------------------------------ (4.5 x 10^3)(2.0 x 10^-6) 16.776 x 10^-1 ------------------- 9.000 x 10^-3 1.864 x 10^2
*September 8, 2015*

**physics**

s(t) = 1/2 at^2 You have a, so plug it in. The mass does not matter.
*September 8, 2015*

**MATH HELP**

If the rectangular part has width x and height y, then we have a perimeter x+2y+πx/2 = 50.700 8.8+2y+8.8π/2 = 50.7 y = 14.039 So, the area is A = xy + π/2 (x/2)^2 = 8.8*14.039 + π/2 * 4.4^2 = 153.954
*September 7, 2015*

**geometry**

the midpoint of AE is (A+E)/2 = 1
*September 7, 2015*

**Algebra**

Assuming you mean absolute value, there is no solution. Absolute values are always positive, so multiplying by -3 can never give a positive value as the answer.
*September 7, 2015*

**Algebra**

no solution. -3n is always negative if n is positive. And |n| is always positive
*September 7, 2015*

**Algebra**

if t=0 when the second plane leaves, then you want t when 350(t + 1/6) = 400t t = 7/6 or 1:10 hours Or, consider that in 10 minutes, the 1st plane flies 58.333 miles. The 2nd plane, going 50 mph faster, then must take 58.333/50 = 7/6 hours to make up the difference
*September 7, 2015*

**Physics**

280-175 = ?
*September 7, 2015*

**Math**

I agree
*September 7, 2015*

**math**

just plug in 48 for h0, and solve for t when h(t) = 0. Just the usual quadratic stuff.
*September 7, 2015*

**math**

I hope you got w=35. Then the dimensions are 140x210 Check: 140*210 = 29400, half of the lot's area.
*September 7, 2015*

**math**

something tells me you did not draw a diagram or do much of anything else. The area of the lot is 58800. So, if the lawn has width w, the factory has dimensions (210-2w)(280-2w) and we know that its area is half of the lot. So, (210-2w)(280-2w) = 58800/2 Now just solve that ...
*September 7, 2015*

**math**

so, draw a diagram, label the dimensions and answer whatever question you have (not shown).
*September 7, 2015*

**math**

x+y = 12 x^2+y^2 = 74 (x+y)^2 = x^2+y^2 + 2xy = 144 74+2xy=144 2xy=70 xy=35 35 = 7*5 So, the rectangle is 7x5
*September 7, 2015*

**computer programming**

You can start by doing the planning. What ideas do you have?
*September 7, 2015*

**Pre Cal @HighFive**

We agree, Reiny, so it must be right!
*September 7, 2015*

**Pre Cal**

(2x^-4y^-1) = 2/(x^4 y) (2y^4z^-1) = 2y^4/z so, the numerator is (2/(x^4 y) * 2y^4/z)^-2 = (4y^3 / x^4 z)^-2 = (x^8 z^2)/(16y^6) Put all that over (2x^3 y) and you have (x^5 z^2) / (32y^7)
*September 7, 2015*

**algebra**

a function is a set of ordered pairs where no two 2nd elements are related to the same 1st element. So, it is not a function if more than one pair have the same 1st element. Look at the numbers and you can get the answer.
*September 7, 2015*

**Math**

f/m = 13/5 I assume you meant if there are 48 more female teachers than the male teachers (otherwise, that would mean there were 48 females, and 13 does not divide 48) f = m+48 13/5 m = m+48 8/5 m = 48 m = 30 So, there are 30+78 teachers in all.
*September 7, 2015*

**math**

That would be 5000 * 1.15^4 It's just a GP, with a = 5000 r = 1.15
*September 7, 2015*

**Math**

Assuming the usual carelessness with parentheses, I'll interpret your expression as (2x^2)^(3/2)/((2^(1/2))*x^4) (2x^2)^(3/2) = 2^(3/2) * x^3 So, you have 2^(3/2) x^3 ---------------- = 2/x 2^(1/2) x^4
*September 7, 2015*

**algebra help me please**

A = 9/2 (b+35) 2A/9 = b+35 2A/9 - 35 = b
*September 7, 2015*

**algebra**

yes, it is, though I would have written it -(x-2) = 4 (why might that be?) Extra credit. What is a different correct step (not shown)?
*September 7, 2015*

**Precalculus**

Uese De Moivre's formula. (1-i)^10 = (√2 cis -π/4)^10 = 2^5 cis -10π/4 = 32 cis -π/2 = -32i (1+i)^20 = (√2 cis π/4)^20 = 2^10 cis 5π = -1024
*September 7, 2015*

**Math Trig**

if you set J at (0,0), then W is at (-500,200). Check your formulas, and you will find that the plane's heading (not bearing!) is 360-arctan(200/500)
*September 7, 2015*

**Math Trig**

First step. Draw the picture. Do you know the Pythagorean Theorem? Can you convert from x-y to headings?
*September 7, 2015*

**Math**

the circumference of the tire is the distance it moves in one revolution. So, what are the circumferences of the two tires? You want the difference, times 2 (for two revolutions)
*September 7, 2015*

**math**

clearly, p(LF) = 5/59 So, does that sound like it's where he usually hits? What does "usually" mean in terms of probability?
*September 7, 2015*

**Math**

well, how many days in 300000 minutes?
*September 7, 2015*

**numbers**

clearly the smaller digit is 1, since the larger digit cannot be greater than 9. The number must be 15 Check: 51 = 6+3*15
*September 7, 2015*

**Geometry**

the side length including the walkway is 6+20+8 = 32 Now you can find the perimeter. That's how much fence is needed!
*September 7, 2015*

**programmimg**

years+months = (years*12+m) months
*September 7, 2015*

**IMT**

.05 what?
*September 7, 2015*

**math**

I'll start. 9/(10*18)
*September 7, 2015*

**math**

5/8 + 7/10 25/40 + 28/40 53/40
*September 7, 2015*

**Maths**

might speedy, I must say! Oh -- was there a question in there somewhere?
*September 7, 2015*

**Algebra**

well, let's see. parallel lines have the same slope. I guess that leaves only perpendicular as the correct response. Surely a topic as basic as this is highlighted in a shaded box in your text! It can't possibly be as fast to post here and await a response as to simply...
*September 6, 2015*

**algebra**

Just work things normally: 21k – 3n + 9p > 3p + 12 21k - 3n > -6p + 12 7k - n > -2p + 4 -n > -2p - 7k + 4 n < 2p + 7k - 4
*September 6, 2015*

**math**

|x-32| <= 8 The cost must be within $8 of $32. So, what numbers are 8 below and 8 above 32?
*September 6, 2015*

**physics**

Your knowledge of projectile motion tells you that the range R and max height H are R = (v^2 sin2θ)/g H = (v sinθ)^2/2g You know θ,g,R,H so you should be able to come up with v.
*September 6, 2015*

**Math @Lee**

Here's a thought, Lee. Why not show us your calculations? Then we can (a) see what you meant to start with (b) see where you went wrong
*September 6, 2015*

**Math**

Must be a typo in either the question or the answers. I just note that 6*3/9+1 = 3
*September 6, 2015*

**Geometry**

Seems correct to me.
*September 6, 2015*

**@Damon**

It always seems like cheating to use a Taylor Series to prove a derivative... But nice of you to step in and help. It's clear that google is of no use to someone who cannot spell...
*September 6, 2015*

**Calculus using the first derivative**

do you mean the limit of the difference quotient? There are several good discussion of the topic online. Google is your friend.
*September 6, 2015*

**Physics**

90km/hr = 25m/s 128km/hr = 35.56m/s Let t=0 be the moment the speeder passes the cop. Then we want t when 35.56t = 25(t-1) + 1.40(t-1)^2 t = 11
*September 6, 2015*

**Pre-Calculus HELP!**

There's a nice discussion of this topic at http://laurashears.info/math122/unit4/polarAndParamFormsOfParabola/
*September 6, 2015*

**maths**

clearly it will take ten times as long for a single man to do the job.
*September 6, 2015*

**Caculus**

with a hint like that, what troubles you? The only wrinkle is that (x-1) > 0 for x > 1 (x-1) < 0 for x < 1 to check your work, enter your function at wolframalpha.com, and it will show the graph.
*September 6, 2015*

**math**

As always, draw a diagram. If the height is h, and the distance is d, you have h/d = tan 60° h/(d+100) = tan 30° Now just solve for d and h.
*September 6, 2015*

**algebra**

Hmmm. Looks like a typical govt school... Recall that complementary angles add to 90°, so you want x where x + 72°40' = 90°0'
*September 6, 2015*

**Algebra**

recall your differences of squares factoring: a^2-b^2 - (a+b)(a-b) So, here you just have (9p)^2 - (7q)^2
*September 6, 2015*

**Algebra**

well, (x+5)^2 = x^1+10x+25, so ...
*September 6, 2015*

**Algebra**

You have u^2+v^2, where u = 2ab v = 5cd As you know, (u+v)^2 = u^2+2uv+v^2 Now just plugin your substitutions.
*September 6, 2015*

**Subj: Physics school: omar samatar secondary school**

v0 + 4a = 16 v0 + 10a = 28 a=2, v0=8 s(t) = s0+ 8t + t^2 Now you can figure the distance traveled during any interval.
*September 5, 2015*

**Math**

you have two 5-12-13 triangles. Since the two sides of 12 are joined as a single line, add up all the sides and subtract 12 twice for the interior sides. If that seems hard, just draw the figure, label the exposed sides, and do the math.
*September 5, 2015*

**Algebra I**

time = distance/speed You have the speed. Look up the distance and do the math.
*September 5, 2015*

**Algebra I**

no solutions, since that would mean that 4-b = 2-b 4 = 2
*September 5, 2015*

**UNAM**

it would be (.25*.015 + .125*.050)/(.015+.050) = 0.1538M
*September 5, 2015*

**physics**

since the ball went straight up, its has zero velocity at maximum height. So, what does that say about its momentum?
*September 5, 2015*

**numerical analysis**

well, you know that f(0) = -2 f(pi/2) = pi/2 So, start with those two values a1 = 0, b1=pi/2 so, c1 = pi/2-(pi/2)(pi/2-0)/(pi/2-(-2)) = 0.88 f(c1)=f(0.88) = 0.421 Since f(c1) > 0, a2 = a1, b2 = c1 = 0.421 I assume you can follow the method, as explained at https://en....
*September 5, 2015*

**Algebra**

Only true if a > 0. If a<0, then you have x < b/a or x<c.
*September 5, 2015*

**PRE CALCULUS**

In 8 years, the share price rose by 3.86, making the rate of change (slope) 3.86/8 = 0.4825 per year. So, since we started measuring at the $0.18 price, at t=5, the price p(t) is p-0.18 = 0.4825(t-5) Now you can find p(t) for other values of t. The other problem is worked in ...
*September 4, 2015*

**math**

If a line (-9,7) is marked by e which is a ratio of 1/4 then where is e on the line? My answer is -7
*September 4, 2015*

**Math - My Bad**

ignore my question. Ms Sue read it right
*September 4, 2015*

**math**

does each 4.5ft fence section have an and piece, or does the entire fence have two end pieces (one on each end)?
*September 4, 2015*

**math**

does 3x - 4x = x?
*September 4, 2015*