Monday

October 24, 2016
Total # Posts: 45,210

**Math, Precalc**

you have cosB. Use that to get cosA. Now you cab find angle A using the law of sines: sinA/a = sinB/b Now, use the law of cosines to get side a: a^2 = b^2+c^2 - 2bc cosA

*September 29, 2016*

**percentage**

it's unfortunate that the 50K break points are included in the step function. Note that [x/50k] = 0 for x<50K, but 1 for x=50K So, assuming whole dollars, we have adjust our floor function to be [(x-1)/50000]+1 The first plan pays 3700 for 0 <= x <= 50000 3700 + ....

*September 29, 2016*

**math**

either convert all to decimal, or give them a common denominator Then it will be easy to tell

*September 28, 2016*

**Math**

(4y^5)^5 = 4^5 y^(5*5) = 1024y^25 because that is just 4y^5 * 4y^5 * 4y^5 * 4y^5 * 4y^5

*September 28, 2016*

**Pre-Calculus**

cot^2 = csc^2 - 1

*September 28, 2016*

**Math**

entire area - pool area - walkway area (8+2*.8)(5+2*.8) - 8*5 = ?

*September 28, 2016*

**Math**

no idea. what are you doing?

*September 28, 2016*

**Compound Interest**

Don't you have a formula for the future value of an annuity? If not, google can provide it -- or maybe your class textbook!

*September 28, 2016*

**Auburn Hugh School**

remember the 5-12-13 right triangle. Of course, there are many other non-integer solutions.

*September 28, 2016*

**math!! @bob**

a^2=b^2+c^2-2bc*cosA and we don't know A yet

*September 28, 2016*

**math!!**

sinB = 1/√10 b/sinB = c/sinC, so √3/(1/√10) = √10/sinC sinC = 1/√3 A = 180 - (B+C) sinA = (180 - (B+C)) = sin(B+C) = sinBcosC+cosBsinC = (1/√10)(√2/√3)+(3/√10)(1/√3) = (2+3√2)/(2√15) Now get a/sinA = b/...

*September 28, 2016*

**Algebra**

me, too

*September 28, 2016*

**Math**

(8-2)(4+6) = 60

*September 28, 2016*

**pre-calculus**

tan = sin/cos = 1/2

*September 28, 2016*

**pre-calculus**

sin(-x) = -sin(x)

*September 28, 2016*

**Pre-Calculus**

same bogus question. csc(theta) cannot be less than 1.

*September 28, 2016*

**geometry**

yes. As you could have verified by plugging in 2 to your function.

*September 28, 2016*

**Math**

(20)((-2 + 2) * 2^2 +6) = 120 what do you get for the other one?

*September 28, 2016*

**Math**

(3*5)+4-(14/2)=12

*September 28, 2016*

**Trig**

θ is in QIV, so x>0 and y<0 cosθ = x/r = 8/17 so, x = 8 y = -15 r = 17 Now recall the other trig functions: sinθ = y/r tanθ = y/x

*September 28, 2016*

**Algebra**

sure: y = -2x+3

*September 28, 2016*

**math**

substitute 7 for y division property (divide by 8)

*September 28, 2016*

**Math (calculus 3) - correction**

correct. good catch

*September 28, 2016*

**Math (calculus 3)**

recall that the height y = 1 + 40*sin(pi/6) t - 8t^2 (a) solve for t when y=1 (b) as with all parabolas, the vertex is at t = -b/2a

*September 28, 2016*

**Math**

This is called the power set.Any set of n elements has 2^n subsets. Just sum all the powers of 2 from 0 to n-1

*September 28, 2016*

**math plzz help**

330/(50+60)

*September 28, 2016*

**computer science**

Sorry about the formatting. I meant to say `Twas brillig, and the slithy toves Did gyre and gimble in the wabe: All mimsy were the borogoves, And the mome raths outgrabe. "Beware the Jabberwock, my son! The jaws that bite, the claws that catch! Beware the Jubjub bird, and...

*September 28, 2016*

**computer science**

`Twas brillig, and the slithy toves Did gyre and gimble in the wabe: All mimsy were the borogoves, And the mome raths outgrabe. "Beware the Jabberwock, my son! The jaws that bite, the claws that catch! Beware the Jubjub bird, and shun The frumious Bandersnatch!" He ...

*September 28, 2016*

**Geometry**

m<3 means the measure of angle 3 But, since we have no diagram, there's no way to tell anything about <1

*September 28, 2016*

**Calculus**

y = 4x + [5/sin x] = 4x + 5cscx y' = 4 - 5 cscx cotx y" = 5/2 csc^3(x) (cos(2x)+3) cos(2x)+3 is always positive. on (0,π) csc^3 > 0, so, y is concave up. similarly, y is concave down on (-π,0)

*September 28, 2016*

**physics**

since F = GMm/r^2 replacing r by 2r means the F is divided by 2^2

*September 28, 2016*

**science**

since g is inversely proportional to r^2, multiplying r by 2 means dividing g by 2^2

*September 28, 2016*

**math**

not sure what the special characters are. Copy/paste from word processor documents often mangle the fonts in a browser.

*September 28, 2016*

**Parabola**

2x^2-3x+4y+5=0 2x^2-3x+5 = -4y x^2 - 3/2 x + 5/2 = -2y x^2 - 3/2 x + (3/4)^2 = -2y + (3/4)^2 - 5/2 (x - 3/4)^2 = -2y - 31/16 (x - 3/4)^2 = -2(y + 31/32) So, the vertex is at (3/4, -31/32) You know that for the parabola x^2 = 4py here, 4p = -2, so p = -1/2 the focus is at a ...

*September 28, 2016*

**math**

the exterior angles of a decagon are all 360/10 = 36° So, 3x+6 = 36 x = 10 For the interior angles (each 144°), 3x+6 = 144 x = 46

*September 28, 2016*

**maths need help**

you will not solve this algebraically. Use a numeric approximation or read it from a graph, such as http://www.wolframalpha.com/input/?i=150sinx%3Dx%2B69.98

*September 28, 2016*

**algebra 1, solving polynomials**

there are no zeros. All you have is 8*12

*September 28, 2016*

**algebra**

1st step: multiply both sides by 17

*September 28, 2016*

**Urgent Math**

discs of thickness dx: v = ∫[0,1] πr^2 dx where r=y = 1-x^2 v = ∫[0,1] π(1-x^2)^2 dx shells of thickness dy: v = ∫[0,1] 2πrh dy where r=y and h=x=√(1-y) ∫[0,1] 2πy√(1-y) dy To integrate, use u^2 = 1-y dy = -2u du

*September 28, 2016*

**calculus help me**

y = cot(x+y) y' = -csc^2(x+y) (1+y') y' = -csc^2(x+y) - csc^2(x+y) y' y' (1+csc^2(x+y)) = -csc^2(x+y) y' = -csc^2(x+y)/(1+csc^2(x+y)) But, csc^2 = 1+cot^2, so y' = -(1+y^2)/(1+1+y^2) = -(1+y^2)/(2+y^2) or, you can say 1/y = tan(x+y) arctan(1/y) = x+...

*September 28, 2016*

**algebra**

good answer, but it does not address the question.

*September 28, 2016*

**math**

since distance = speed * time, 90(t-1) = 80(t+1)

*September 28, 2016*

**Maths**

sin^-1 (4x^4+x^2) = 1/6 pi 4x^4+x^2 = sin(pi/6) = 1/2 8x^4+2x^2-1 = 0 x^2 = [-2±√(4+32)]/16 = [-2±6]/16 = -1/2 or 1/4 x^2 = -1/2 x = ±i/√2 x^2 = 1/4 means x = ±1/2

*September 28, 2016*

**science**

F=ma, so 5 = 18M = 24m M = 5/18 kg m = 5/24 kg For both masses, 5 = (5/18 + 5/24)a a = 72/7 m/s^2

*September 28, 2016*

**Aptitude**

how many times around does each hand go? Each time around has circumference 2πr for the hand's radius.

*September 28, 2016*

**math trig**

see related questions below. Just use your numbers to follow the logic.

*September 28, 2016*

**Maths**

in English you don't lend from. You either borrow from or lend to fix that and all the other typos and try again.

*September 28, 2016*

**Calculus**

#1 You know that as x->0 sinx/x -> 1 tanx/x -> 1 You have θ/tan7θ = (1/7) (7θ/tan7θ) -> (1/7)(1) = 1/7 As the graph will show http://www.wolframalpha.com/input/?i=plot+y%3Dx%2F(tan7x),+-0.3+%3C%3D+x+%3C%3D+0.3 #2 some parentheses would help f(x...

*September 28, 2016*

**Math**

at r%, 8000(r/100) = 12000((r-1)/100) - 200

*September 28, 2016*

**Math**

8000(r/100) = 12000((r-1)/100) - 200

*September 28, 2016*

**Math**

A plug in t=0 B as with any parabola, the vertex is at t = -b/2a C see B D plug in t=2

*September 28, 2016*

**Math**

(a) and (b) look ok distance = speed * time, so since the time is the same (3.5 hrs), just add up all the speeds and multiply by 210 minutes: 210(8/80 + 6/42 + 15/75) = 93 miles

*September 27, 2016*

**calc**

#1: h(x) = k cos x 0 ≤ x ≤ 3π #2: h(x)= 10 − x 3π < x #2: limit as x->3π = 10-3π #1: h(3π) = k cos3π = -k So, you need -k = 10-3π k = 3π-10 #1: h(x) = (3π-10)cosx

*September 27, 2016*

**math**

what are path numbers?

*September 27, 2016*

**math**

slope: (-4-5)/(-2-1) = -9/-3 = 3 Now, using the point-slope form, y-5 = 3(x-1) at x=0, y=2 2*3+2 = 8 2(3+2) = 10 You took twice the sum of the slope and the intercept, but that was not the question.

*September 27, 2016*

**Calculus**

who needs a limit? f = x + 4/x f' = 1 - 4/x^2 So, f'(4) = 1 - 4/16 = 3/4 The tangent line at (4,5) is thus y-5 = 3/4 (x-4) using the limit f(4+h)-f(4) = (4+h)+4/(4+h) - (4 + 4/4) = ((4+h)^2+4)/(4+h) - 5 = ((4+h)^2+4-5(4+h))/(4+h) = (h^2+3h)/(4+h) = h(h+3)/(h+4) Now ...

*September 27, 2016*

**algebra**

well, it traveled 90 miles in 1 1/2 hours. So, it is still 1 1/2 hours away at 2:15

*September 27, 2016*

**mathematics**

see related questions below

*September 27, 2016*

**Math**

87 - 6 - x >= 32 81 - x >= 32 49 >= x so, at most $49 for shirts.

*September 27, 2016*

**math**

Plot the points. It will be clear that the line contains (0,-50). Or, now that you know the slope, use the point-slope form of the line with any of the points. How about (5,80) y-80 = 26(x-5) Now plug in x=0 and you will get y = -50.

*September 27, 2016*

**math**

no idea what you did wrong, since you didn't bother to show your work.

*September 27, 2016*

**math**

first, check to be sure there is a constant slope: (80+310)/(5+10) = 26 (262-80)/(12-5) = 26 (444-262)/(19-12) = 26 So, the slope is 26 For the y-intercept, since x=0 is 1/3 of the way from 5 to -10, the y-intercept is 1/3 of the way from 80 to -310: -50 26 + -50 = -24 Just to...

*September 27, 2016*

**Algebra**

you cannot tell by looking at that table?? Really??? Look again.

*September 27, 2016*

**Math**

Let the amounts of notes be u,v,w,x respectively. Now just start writing down the facts: 100u+50v+20w+10x = 14400 x = 3w w = 5v v = 5u Now just solve for u. Or, consider if there is a single $100 note. That means there are 5 $50's, 25 $20's, 75 $10's 100+5*50+25*20...

*September 27, 2016*

**Science**

work is in Joules, J J = F*d = ma*d= kg-m^s/2 * m = kg-m/s Note I have used kg instead of grams, since MKS uses m,kg,s CGS uses cm,g,s You can use g,m,s if you want, but then the work will not be measured in Joules or ergs.

*September 27, 2016*

**Math**

3m wide, but how long? Anyway, if it is x meters long, then you need 3x - (3-2w)(x-2w) = 3x/2 because the area of the whole thing minus the area inside the pathway is the area of the pathway. So, plug in your length for x, and then solve for w.

*September 27, 2016*

**Math**

the width+length must be 12. So, start listing pairs of integers which add to 12: 1,11 2,10 ... 6,6

*September 27, 2016*

**Math**

twenty tens means a 2 in the hundreds place now work from that, one item at a time.

*September 27, 2016*

**math**

26 = 5+(3^2-6)*7 play around with the others a while. There aren't that many places to put the parens.

*September 27, 2016*

**Algebra**

see http://www.jiskha.com/display.cgi?id=1474984965

*September 27, 2016*

**math**

the length + width must be 12, so the following dimensions will work: 1x11 2x10 ... 6x6

*September 27, 2016*

**Algebra**

correct But note that x is a variable name × is the multiplication symbol

*September 27, 2016*

**Maths grade 8**

If there are n sides, then each exterior angle is 360/n degrees. each interior angle is thus 180 - 360/n = 180(n-2)/n degrees.

*September 27, 2016*

**de~movire**

note that x^4-x^3+x^2-x+1 = (x^5+1)/(x+1) see what you can do with that...

*September 27, 2016*

**math**

since distance = speed * time, 3x = 2.5(x+2)

*September 27, 2016*

**stationary point**

You need both partials to be zero. That is, #1: 3y^3 + 2xy = 0 #2: 3(3x+1)y^2 + x^2 = 0 From #1, we get x = -3y^2/2 Plug that into #2 and you get y^2 = 4/15 So, z has stationary points at (-2/5, ±2/√15)

*September 27, 2016*

**Math**

2x^2 - 128 = 0 x^2 = 64 x = ±√64 = ±8

*September 27, 2016*

**Math**

56/(77-56)

*September 27, 2016*

**mathematics need help**

There are lots of proofs of the chain rule on line. You can find one here, if you scroll down some http://tutorial.math.lamar.edu/Classes/CalcI/DerivativeProofs.aspx So, now you know that if y = f(g) and g is a function of x, then dy/dx = df/dg * dg/dx You can see that treated...

*September 27, 2016*

**mathematics need help**

this is just the chain rule. I assume you have seen the proof of that. That said, just substitute x for f(x).

*September 27, 2016*

**Physics .. hard problem**

oops. After falling for 5.88 seconds, the student is caught, then 3.81 seconds later they land gently on the ground.

*September 27, 2016*

**Physics .. hard problem**

At time t=x, the Rocketeer catches up with the student. At that point (the Rocketeer having arrived with some unknown velocity v), their height and speed are student: 427 - 4.9x^2 9.8x Rocketeer: 427 - v(x-5) - 4.9(x-5)^2 v + 9.8(x-5) So, we match their heights and we get 427...

*September 27, 2016*

**Math**

v^2 = 2as 35^2 = 2a*18 a = 34 m/s^2 You have no idea how long it took to accelerate. The units in your calculation are all jumbled up.

*September 27, 2016*

**math**

8/x + 3/4 < 2 8/x < 5/4 now you can easily find x.

*September 27, 2016*

**math**

set x=0: 0 + 4y = 15

*September 27, 2016*

**Math**

first, find the common denominator for each problem. Then you can work with the fractions more easily.

*September 27, 2016*

**Engineering Math**

well, apparently P(a-bP) = bP(300 − P) aP - bP^2 = 300bP - bP^2 so, a = 300b dP/dt = P(300b-bP) = bP(300-P) Try plugging that in. You already know what the logistic growth function looks like, so that should guide your efforts some.

*September 27, 2016*

**maths need help**

If there are n terms, we have a + ar = x ar^(n-2) + ar^(n-1) = y a(1+r) = x ar^(n-2)(1+r) = y now divide r^(n-2) = y/x r = (y/x)^(n-2)

*September 27, 2016*

**maths trig need help**

clearly not true at x = pi/4. The LS is undefined while the RS = √2.

*September 27, 2016*

**math**

3x - 1(19-x) >= 32

*September 27, 2016*

**physics**

h = (v sinθ)^2 / 2g

*September 27, 2016*

**Algebra**

there are lots of linear regression calculators online, such as http://ncalculators.com/statistics/linear-regression-calculator.htm

*September 27, 2016*

**further maths**

you can start by dividing by 5 everywhere 5x-30x+25=0

*September 27, 2016*

**Math**

7^{-10}

*September 27, 2016*

**physics**

°C = 5/9 (°F-32) now just plug in F=1800

*September 27, 2016*

**physics**

no "fever" 37°C = 98.6°F

*September 27, 2016*

**maths**

if the last digit is 4, then there are 6! ways If the last digit is 2 or 8, then there are only 6!/2! ways because of the duplicate 4s. So, there are only 2*6! total ways

*September 27, 2016*

**Urgent Math**

First, do a long division x^3/(x^2+1) = x - x/(x^2+1) for the 2nd term, let u=x^2+1

*September 27, 2016*

**Math**

either 2x+50 = 180 or 2*50+x = 180

*September 27, 2016*

**Math**

Let u=18x-x^2-77 log_3(u) exists if u>0 log_5(log_3)u)) exists if log_3(u)>0, or u > 1 log_4(log_5(log_3(u))) exists if log_5(log_3(u)) > 0, or log_3(u) > 1, or u > 3 So, we need 18x-x^2-77 > 3 18x-x^2-80 > 0 (10-x)(x-8) > 0 8 < x < 10

*September 27, 2016*