Tuesday

January 17, 2017
Total # Posts: 47,908

**MATH MS. SUE**

I did the math silly

*December 8, 2016*

**MATH MS. SUE**

Are those correct?

*December 8, 2016*

**MATH MS. SUE**

1. B 2. C 3. A 4. A

*December 8, 2016*

**MATH MS. SUE**

Alright I don't have any answers in mind but I'd like your help hand me some equations to solve for this

*December 8, 2016*

**MATH MS. SUE**

Spare me a second please, Ms. Sue

*December 8, 2016*

**MATH MS. SUE**

1. The length of a piece of paper is 8.5 inches. Using scissors, you reduce the length of the paper to 4.25 inches. What is the scale factor of the dilation? A. 1/4 B. 1/2 C. 2 D. 4 2. On a given blueprint, 1 inch = 30 feet. If the dimensions of a meeting room on the blueprint...

*December 8, 2016*

**Diagram**

Racist: Please stop bill

*December 8, 2016*

**Diagram**

This is a repost from a few weeks ago from someone esle but need help. The ramp shown below is used to move crates of oranges to loading docks at different heights. When the horizontal distance AB is 15ft, the height of the loading dock, BC, is 3ft. What is the height of the ...

*December 8, 2016*

**MATH**

2. 3^2 = 9 9*13 = 117 Am I right?

*December 8, 2016*

**MATH**

1. = 10*6 = 60

*December 8, 2016*

**MS. SUE HIIII**

Equation

*December 8, 2016*

**MATH**

1. The sides of a square are increased by a scale factor of 6. The perimeter of the smaller square is 10 ft. What is the perimeter of the larger square? A.10 ft B. 40 ft C. 60 ft D. 120 ft 2. A right triangle has an area of 13 m^2. The dimensions of the triangle are increased ...

*December 8, 2016*

**MATH MS. SUE**

Yes you were very much help and I thank you for that

*December 8, 2016*

**MATH MS. SUE**

B. $144.04

*December 8, 2016*

**MATH MS. SUE**

OK thank you but you didn't help it is divide 157/1.09 = 144.0366...

*December 8, 2016*

**MATH MS. SUE**

1. On a recent day, one U.S. dollar was worth 1.09 euros. If you were to exchange 157 euros on that day, how many U.S. dollars would you have received? A. $110.09 B. $144.04 C. $155.91 D. $171.13

*December 8, 2016*

**Math**

all real numbers except where t^2+6t+9 = 0

*December 8, 2016*

**MATH MS. SUE**

x = 49/10 Thanks Ms.Sue

*December 8, 2016*

**MATH MS. SUE**

Hand me over an equation please.

*December 8, 2016*

**MATH MS. SUE**

1. Sarah’s mother has a miniature village modeled after her home town. The model is 10 feet long and 7 feet wide. The actual village is 7 miles long. What is the village’s actual width? If necessary, round to the nearest tenth of a mile. A. 4.9 miles B. 10 miles C. 1...

*December 8, 2016*

**Math**

it would help if you actually provided a sequence... As long as no x value maps to two or more y values, it is a function.

*December 8, 2016*

**Math**

a depth of 4 feet means you need ? [-10,-6]

*December 8, 2016*

**math**

Just add up the revenue from each kind of ticket. The total must be 779: 3s+5t = 779

*December 8, 2016*

**Math**

8×5+8×1 -2×6+6-2 = 22 hint: 48-26 = 22

*December 8, 2016*

**Math**

122.5 sips * 2slurps/7sips * 2gulps/5slurps = ? gulps The units cancel as desired, so just work with the numbers.

*December 8, 2016*

**Algebra**

at time t hours, since distance = time * speed, when they have covered the 26 miles, solve for t. 6t + 8(t-1.3) = 26

*December 8, 2016*

**Math**

This web site shows how to find the area of the cross-section. Using that, the volume is 40*area. The weight is density * volume. Then you can either integrate to find the work, or just see how high the center of mass has to be lifted, and work = weight * distance. http://...

*December 8, 2016*

**math**

when 625-300t = 400-150t

*December 8, 2016*

**Math - Calculus**

okay. You seem to be using shells, so you need to be integrating along y, since the shells have a thickness of dy. v = ?[0,6] 2?rh dy where r = y and h = 4-x = 4-y^2/9 v = ?[0,6] 2?y(4-y^2/9) dy = 72? If you want to integrate along x, you need to use discs of thickness dx: v...

*December 8, 2016*

**Trig identities**

well, that does make a difference. You just need to think about what happens in the various quadrants. Recall that sin? = y/r cos? = x/r r is always positive, so if sinx is positive, and cosy is negative, that means you are in QII. Now you know that sinx = 3/5 cosx = -4/5 siny...

*December 8, 2016*

**Math (optimization) really confused**

As always, in similar problems, the fence is evenly divided into lengths and widths. So, you know right off that 2y=3x. y(2y/3) = 225 y^2 = 675/2 y = 18.37 x = 12.23

*December 8, 2016*

**Math**

64 oz = $2.00 divide by 64 to get 1oz = $2/64

*December 8, 2016*

**Math**

clearly not D. Using that, p(15) = 60+16 = 75, when the projection states it will be 450 We have a slope (4) and a point (15,450). So, using the point-slope form, we get p-450 = 4(x-15)

*December 8, 2016*

**Trigonometric identities**

well, you know that sinx = 3/5 cosx = 4/5 siny = 12/13 cosy = 5/13 Now just use the identity sin(x-y) = sinx cosy - cosx siny

*December 8, 2016*

**MATH**

a = 75x b = 50x for x <= 12 50*12+125(x-12) for x > 12

*December 8, 2016*

**h.p.**

Tn = (2n-1)(2n+1) = 4n^2-1 so n ?Tk = ?4k^2-1 = 4?k^2 - 4?1 k=1 Now you know what ?k^2 is and ?1 = n

*December 8, 2016*

**science**

it lost 20m/s in 25 seconds. So, each second it lost 20/25=0.8 m/s a = -0.8 m/s^2

*December 8, 2016*

**g.p. - homework dump**

geez - you ever going to show some of your own work? These slow-mo homework dumps are annoying.

*December 8, 2016*

**Math (related rates) help?**

yes - so, try it sin? = y/13 cos? d?/dt = 1/13 dy/dt Now just plug in your numbers. Use the Pythagorean Theorem to figure cos? when y=12.

*December 8, 2016*

**math**

1.10(568+102-57) = ?

*December 8, 2016*

**math**

B the two lines have different slopes, so they must intersect.

*December 8, 2016*

**h.p.**

so, if you have the answer, what are your thoughts on how to get it?

*December 8, 2016*

**Maths**

Remember your basic 3-4-5 right triangle. Scale it up by 3 and you have 9-12-15. Now draw your diagram, and all should be clear.

*December 8, 2016*

**Math**

you don't say at what point the wheel starts. Let's say that at t=0 the point of interest at the bottom of the rotation. Since cos(t) starts at the top, we know right away that the function will look like y = -cos(kt) The diameter is 18, so the radius is 9, and we now ...

*December 8, 2016*

**MATH**

The three vectors form a triangle. So, recall the law of cosines. c^2 = a^2 + b^2 - 2ab cos?

*December 8, 2016*

**Solving inequality Test 29 questions**

You don't offer many choices...

*December 8, 2016*

**Maths**

After 10 days, there was enough food for 20 days for x students. So, if the number of students grew from x to x+60, it will only last 20x/(x+60) = 20 - 1200/x+60 more days. So, it depends on how many students there were to start with. If there were x at first, then the 20-day ...

*December 8, 2016*

**calculus**

Check the graph. Is f'(x)=0 anywhere on the interval? Clearly not, so now you have to figure out why. Is f(-1) = f(1)? Is df/dx defined everywhere on the interval? (check out x=0)

*December 8, 2016*

**Electrical Circuits**

well, what is copper's thermal resistance coefficient?

*December 8, 2016*

**maths**

check out the angles and distances.

*December 8, 2016*

**Math**

well, it took 1/2 hour, so ...

*December 8, 2016*

**Algebra II**

If the square has side s, then 4s = 2(x+4 + x) s^2 + x(x+4) = 94 ...

*December 8, 2016*

**geometry**

no idea. How are the angles related? What is the diagram being discussed?

*December 8, 2016*

**G.p.**

a = 1 r = 1/2 S12 = (1 - 1/2^12)/(1 - 1/2)

*December 8, 2016*

**G.p.**

b-a = c-b 1/a^2 - 1/b^2 = 1/b^2 - 1/c^2

*December 8, 2016*

**Math**

well, add 'em up: 2 4/8 3 3/8 1 2/8 ------- 6 9/8 = 7 1/8

*December 7, 2016*

**math**

(450-45)/450 = ? Or, you can reason that 45 is 10% of 450 that were used, so ...

*December 7, 2016*

**Trigonometry**

24.91 @ S36°W

*December 7, 2016*

**MATH, please help**

they are in proportion because 8*9 = 6*12 In a proportion a/b = c/d ad = bc

*December 7, 2016*

**Math**

12% is about 1/8 so, you need about 8 times the amount.

*December 7, 2016*

**Math**

There must be a typo. It is 2x^3+5x^2+x-7 So, (C) could be right, if it has the typo.

*December 7, 2016*

**Math**

the slope is -A/B So, of course, B cannot be zero. That gives the equation Ax=C which is a vertical line, so the slope is undefined.

*December 7, 2016*

**Math**

right.

*December 7, 2016*

**Check Answer!!**

That is right.

*December 7, 2016*

**Math**

linear: constant difference quadratic: constant 2nd differences exponential: constant ratio over equal intervals

*December 7, 2016*

**Check Answer!!**

4600(1+.025/4)^(4*8) = 5614.96 what formula did you use?

*December 7, 2016*

**precalculus**

well, you know it will be in QIV, so 270 < ? < 360 arctan(7/3) = 66.8014° But you want arctan(-7/3) = -66.8014°, in QIV. So, add 360 to that to get 293.19° Hmmm. Not one of the choices. However, arctan(-3/7) = 337° Looks like there was a typo in the problem.

*December 7, 2016*

**precalculus**

tan?/sec? = sin? Now do you have an idea?

*December 7, 2016*

**Algebra**

the 2nd is just the first, shifted down 9 That is, subtracting 9 from the y-values moves the graph downwards. Try it.

*December 7, 2016*

**Geometry**

yes.

*December 7, 2016*

**Geometry**

D is the biggest angle, so the opposite side (EF) is the longest side. Now do the others similarly.

*December 7, 2016*

**Math**

I can find no solutions.

*December 7, 2016*

**Geometry**

Draw a diagram. Note that AE is divided into two pairs of equal lengths. BD contains one of each pair. So, BD is half the length of AE. 2(3x+5) = 4x+20 x = 5

*December 7, 2016*

**algebra 1**

since the lines have different slopes, they intersect. Now just use the value of y from eq #2 and substitute it into eq #1 to get the value of x. Then you can get y.

*December 7, 2016*

**Math**

look for SSS in the lengths of the sides of the triangles formed.

*December 7, 2016*

**precalculus**

I doubt I can explain it any more clearly than (a) your text (b) the many discussions provided using google.

*December 7, 2016*

**math**

7(a+6d) = 11(a+10d) 7a+42d = 11a+110d 4a+68d = 0 a+17d = 0 T18 = a+17d = 0

*December 7, 2016*

**analytic geometry**

x and y have increased by 2. Extending the line 3 times more will increase each by 6. So, the desired point is (9,9)

*December 7, 2016*

**duet**

the terms are a, a+d, a+2d, a+3d so you want to show that a^2 - (a+3d)^2 = 3((a+d)^2 - (a+2d)^2) Now just verify that by expanding both sides.

*December 7, 2016*

**math(A.P)**

The sum of the 1st n odd numbers is n^2. So, n^2 > 5000

*December 7, 2016*

**Maths**

(25-2x)(30-2x) = 300

*December 7, 2016*

**maths**

Let AB=AC = x, and the base BC = 2y Then you have 2x+2y = 64 y^2 + 24^2 = x^2 (32-x)^2 + 24^2 = x^2 x = 25 You might have guessed this right off, since one of the basic right triangles with integer sides is 7-24-25 Of course, a 3-4-5 triangle scaled up by 6 would be 18-24-40 ...

*December 7, 2016*

**math**

just use the formulas you know, and write down the facts as given: S25 = 25/2 (2a+24d) = 200 S3 = 3/2 (2a+2d) = 4.2 Solve those two equations, and you get a = 4/5 d = 3/5 "larger" indicates only two items. I assume you mean the "largest" term, which is T25...

*December 7, 2016*

**Geometric progression**

1+2^1+2^2+...+2^n = 2^(n+1)-1 So, the sequence becomes 2^1-1 + 2^2-1 + 2^3-1 + ... + 2^n-1 = 2^1 + 2^2 + ... + 2^n - n = 2^(n+1)-1 - n-1 = 2^(n+1) - (n+2) check (n=5): 1+3+7+15+31 = 2^6-7 = 57

*December 7, 2016*

**G.p.**

same old same old, with a = 1 r = -1/2

*December 7, 2016*

**G.p.**

Sn = a(1-r^n)/(1-r) Just use your formula.

*December 7, 2016*

**math**

just plug and chug: a+8d = 0 25/2 (2a+24d) = 50 8d = -a, so 25/2 (2a-3a) = 50 a = -4

*December 7, 2016*

**math**

of course not. multiplying miles by miles gives you area: miles^2 Keep track of the units and all becomes clear: 1 km = 0.62 mi that means that 1km/0.62mi = 1 Now, you can always multiply by 1 and not change things. So, since you want to convert miles to km, 26mi * 1km/0.62mi...

*December 7, 2016*

**G.p.**

when x/(x-2) = (x+3)/x

*December 7, 2016*

**math**

the one rising from 270 with a slope of 80

*December 6, 2016*

**physics**

correct.

*December 6, 2016*

**Math**

so you want the left limit (as x->2 from below) Now, recall the definition of |u| |u| = u if u >= 0 |u| = -u if u < 0 When x < 2, x-2 < 0, so |x-2| = 2-x So, the limit is (2-x)/(x-2) -> -1 You can see this on the graph at http://www.wolframalpha.com/input/?i...

*December 6, 2016*

**Math**

(?(2x+3)-?(3x))/(x^2-3x) If you have l'Hospital's Rule as a tool, then you know that the limit is the same as (1/?(2x+3) - 3/(2?(3x)) / (2x-3) = (1/3 - 3/6)/3 = -1/18

*December 6, 2016*

**Math**

g(k) = -k^2 + 4k + 1 I suspect there is more to this question...

*December 6, 2016*

**maths**

both numbers are multiples of 7. 77 = 7*11, so you want two numbers which sum to 11, and have no factors in common. That would be 1,10: 7+70 = 77 2,9: 14+63 = 77 ...

*December 6, 2016*

**Math liberal arts 2**

yes! m is the slope. That's why y=mx+b is called the "slope"-intercept form of the line.

*December 6, 2016*

**Algebra**

what's the trouble? Each term, starting with the 3rd, is the sum of the two previous terms. Since the first two terms are 9,9 the sequence continues with 9+9 = 18 9+18 = 27 18+27 = 45 ... You might try writing the sequence as a_(n+1) = a_n + a_(n-1) saves using all those ...

*December 6, 2016*

**Algebra**

parent: y = ?x shift left 7.3 gives y = ?(x+7.3) stretch by 9 gives y = 9?(x+7.3) reflection changes the sign of the y-values, so y = -9?(x+7.3) square root is a particular function. cube root is not "^3 squareroot" Try saying cube root 4th root 5th root etc. instead...

*December 6, 2016*

**Algebra**

vertical asymptotes: 1/((x+2)(x-7)) root at x = -5: (x+5)/((x+2)(x-7)) horizontal asymptote. we need the degree to be equal, so try 7x(x+5) -------------- 2(x+2)(x-7) The problem here is that now we have another x-intercept at (0,0) So, let's work with 7(x+5)^2...

*December 6, 2016*