# Posts by SAP

Total # Posts: 19

math, really need some feedback asap.
You are correct, 11/5 = 2.2. Do I need to round off for a single integer?

math, really need some feedback asap.
here's the next step: 11x-16x = 11 (collect like terms and solve for x.) -5x = 11 -x = 11 x = 11 Thank you TutorCat, the answer does match.

math, really need some feedback asap.
5/8 x+1/16 x=11/16+x 16*(5/8 x+1/16 x) = 16(11/16+x) 10x + x = 11 + 16x, so the next step is: 11x = 11 + 16x (get x-terms on the left.) -x = 11 (divide by -1.) x = 11 Is this correct?

math, really need some feedback on this asap.
After re-working the problem, I'm pretty confident this is the correct answer to the 2nd part of the problem. Can someone confirm my work.... Now this is the part that I get lost on. I know I am suppose to substitute 3 into one of the equations above, but how do I ...

math, really need some feedback on this asap.
7r-4s=-7 (7) 4r+7s=61 (4) 49r - 28s = -49 16r + 28s = 244 --------------- 65r = 195 195/65 = 3 (simplified) (3, is the first number of the ordered pair.) Now this is the part that I get lost on. I know I am suppose to substitute 3 into one of the equations above, but how do I ...

math need asap
7r-4s=-7 (7) 4r+7s=61 (4) 49r - 28s = -49 16r + 28s = 244 --------------- 65r = 195 195/65 = 3 (simplified) (3, is the first number of the ordered pair.) Now this is the part that I get lost on. I know I am suppose to substitute 3 into one of the equations above, but how do I ...

math need asap
10x + x = 11 + 16x, so the next step is: 11x = 11 + 16x (get x-terms on the left.) -x = 11 (divide by -1.) x = 11 Is this now correct?

math need asap
5/8 x+1/16 x=11/16+x 16*(5/8 x+1/16 x) = 16(11/16+x) 80 + x + 16 + x= 11 + 16x 80 + 2x + 16 = 11 + 16x -x = 18x (divide by 1) x = 18 Did I do this correctly?

math need asap
Ana, thank you, now I understand what I was doing wrong. I couldn't figure out how to rewrite the x=26-4y equation.

math need asap
Ok, so if I use the corrected number you gave, that would make y = 7. Returning to the 2nd equation x=26-4y and substituting x for 7. 4y = 7 - 26 still does not add up, what am I doing wrong?

math need asap
4x+5y=27 x=26-4y 4(26-4y) + 5y = 27 104 - 16y+ 5y = 27 -21y = - 77 21y = 77 y = 77/31 Now, I’m suppose to return to the 2nd equation x=26-4y and substitute 77/31 for x, I don’t understand if the is correct way or how to get the answer for the ordered pair.

Math need by 9pm cst
4x+5y=27 x=26-4y 4(26-4y) + 5y = 27 104 - 16y+ 5y = 27 -21y = - 77 21y = 77 y = 77/31 Now, I’m suppose to return to the 2nd equation x=26-4y and substitute 77/31 for x, I don’t understand if the is correct way or how to get the answer for the ordered pair.

Math need by 9pm cst
Solve by substitution method. Show step by step process. 4x+5y=27 x=26-4y

Math need by 9pm cst
5/8 x+1/16 x=11/16+x 16*(5/8 x+1/16 x) = 16(11/16+x) 80 + x + 16 + x= 11 + 16x 80 + 2x + 16 = 11 + 16x -x = 18x (divide by 1) x = 18 Did I do this correctly?

Math need by 9pm cst
Solve. Please show step by step process. 5/8 x+1/16 x=11/16+x

Math need by 9pm cst
7r-4s=-7 (7) 4r+7s=61 (4) 49r - 28s = -49 16r + 28s = 244 --------------- 65r = 195 195/65 = 3 (simplified) (3, is the first number of the ordered pair.) Now this is the part that I get lost on. I know I am suppose to substitute 3 into one of the equations above, but how do I ...

Math need by 9pm cst
Solve by elimination method. Please show step by step process. 7r-4s=-7 4r+7s=61

Chemistry
Water definitely lose (-ve or exothermic) energy. But NH4NO3 gain this heat (+ve). So NH4NO3 solution gained heat from water and water got it from the surrounding so overall gained heat +ve

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