Monday

February 20, 2017
Total # Posts: 19

**9th grade Deductive Reasoning Math**

Yes

*October 11, 2010*

**math, really need some feedback asap.**

You are correct, 11/5 = 2.2. Do I need to round off for a single integer?

*September 30, 2010*

**math, really need some feedback asap.**

here's the next step: 11x-16x = 11 (collect like terms and solve for x.) -5x = 11 -x = 11 x = 11 Thank you TutorCat, the answer does match.

*September 30, 2010*

**math, really need some feedback asap.**

5/8 x+1/16 x=11/16+x 16*(5/8 x+1/16 x) = 16(11/16+x) 10x + x = 11 + 16x, so the next step is: 11x = 11 + 16x (get x-terms on the left.) -x = 11 (divide by -1.) x = 11 Is this correct?

*September 30, 2010*

**math, really need some feedback on this asap.**

After re-working the problem, I'm pretty confident this is the correct answer to the 2nd part of the problem. Can someone confirm my work.... Now this is the part that I get lost on. I know I am suppose to substitute 3 into one of the equations above, but how do I ...

*September 30, 2010*

**math, really need some feedback on this asap.**

7r-4s=-7 (7) 4r+7s=61 (4) 49r - 28s = -49 16r + 28s = 244 --------------- 65r = 195 195/65 = 3 (simplified) (3, is the first number of the ordered pair.) Now this is the part that I get lost on. I know I am suppose to substitute 3 into one of the equations above, but how do I ...

*September 30, 2010*

**math need asap**

7r-4s=-7 (7) 4r+7s=61 (4) 49r - 28s = -49 16r + 28s = 244 --------------- 65r = 195 195/65 = 3 (simplified) (3, is the first number of the ordered pair.) Now this is the part that I get lost on. I know I am suppose to substitute 3 into one of the equations above, but how do I ...

*September 30, 2010*

**math need asap**

10x + x = 11 + 16x, so the next step is: 11x = 11 + 16x (get x-terms on the left.) -x = 11 (divide by -1.) x = 11 Is this now correct?

*September 30, 2010*

**math need asap**

5/8 x+1/16 x=11/16+x 16*(5/8 x+1/16 x) = 16(11/16+x) 80 + x + 16 + x= 11 + 16x 80 + 2x + 16 = 11 + 16x -x = 18x (divide by 1) x = 18 Did I do this correctly?

*September 30, 2010*

**math need asap**

Ana, thank you, now I understand what I was doing wrong. I couldn't figure out how to rewrite the x=26-4y equation.

*September 30, 2010*

**math need asap**

Ok, so if I use the corrected number you gave, that would make y = 7. Returning to the 2nd equation x=26-4y and substituting x for 7. 4y = 7 - 26 still does not add up, what am I doing wrong?

*September 30, 2010*

**math need asap**

4x+5y=27 x=26-4y 4(26-4y) + 5y = 27 104 - 16y+ 5y = 27 -21y = - 77 21y = 77 y = 77/31 Now, I’m suppose to return to the 2nd equation x=26-4y and substitute 77/31 for x, I don’t understand if the is correct way or how to get the answer for the ordered pair.

*September 30, 2010*

**Math need by 9pm cst**

4x+5y=27 x=26-4y 4(26-4y) + 5y = 27 104 - 16y+ 5y = 27 -21y = - 77 21y = 77 y = 77/31 Now, I’m suppose to return to the 2nd equation x=26-4y and substitute 77/31 for x, I don’t understand if the is correct way or how to get the answer for the ordered pair.

*September 30, 2010*

**Math need by 9pm cst**

Solve by substitution method. Show step by step process. 4x+5y=27 x=26-4y

*September 30, 2010*

**Math need by 9pm cst**

5/8 x+1/16 x=11/16+x 16*(5/8 x+1/16 x) = 16(11/16+x) 80 + x + 16 + x= 11 + 16x 80 + 2x + 16 = 11 + 16x -x = 18x (divide by 1) x = 18 Did I do this correctly?

*September 30, 2010*

**Math need by 9pm cst**

Solve. Please show step by step process. 5/8 x+1/16 x=11/16+x

*September 30, 2010*

**Math need by 9pm cst**

7r-4s=-7 (7) 4r+7s=61 (4) 49r - 28s = -49 16r + 28s = 244 --------------- 65r = 195 195/65 = 3 (simplified) (3, is the first number of the ordered pair.) Now this is the part that I get lost on. I know I am suppose to substitute 3 into one of the equations above, but how do I ...

*September 30, 2010*

**Math need by 9pm cst**

Solve by elimination method. Please show step by step process. 7r-4s=-7 4r+7s=61

*September 30, 2010*

**Chemistry**

Water definitely lose (-ve or exothermic) energy. But NH4NO3 gain this heat (+ve). So NH4NO3 solution gained heat from water and water got it from the surrounding so overall gained heat +ve

*May 9, 2007*

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