Saturday

April 30, 2016
Total # Posts: 10

**social studies (check answers)**

U in connexus school biii? I am. I'm struggling on that question too, but I can't risk turning it in cause it's important for me
*April 21, 2014*

**Science**

She only had 3 questions... What was number 3 when it ask what happened to the moon if gravity didn't affect it?
*January 24, 2014*

**business math**

what are the amount and present value of an annuity of $100 paable at the beginning of each quarter fro 15 years if the interest rate is 12% compounded quarterly? Present Value=PMT[(1-(1+i)^-n)/i] Amount = ?????
*March 12, 2007*

**calc limit**

lim (2^x - 3^-x)/2^x + 3^-x x-> infinity Thanks. Do you mean (2^x - 3^-x)/(2^x + 3^-x) or [(2^x - 3^-x)/2^x] + 3^-x ? in other words, is the second 3^-x in the denominator? In any case, the limit of 3^-x as x-> infnity is zero. That should help you figure out the answer...
*March 12, 2007*

**Linear Algebra**

a)Let v be a fixed vector in R^3. Show that the transformation defined by T(u)=vxu is a linear transformation. b)Find the range of this linear transformation. Thanx
*March 11, 2007*

**eigenvalues/eigenvectors**

The matrix; [ 1 -2 0] [-2 -1 1] [ 0 0 -1] I have found the eigenvalues to be -1 and +/- 5^1/2 but am having problems putting the root 5 values a eigenvectors. I know I sub it back into the matrix { x-1 -2 0 } { -2 x+1 1 } { 0 0 x+1} but then it gets messy. Can someone finish ...
*March 10, 2007*

**Algebra**

for the matrix: { 1 -2 0} {-2 -1 1} { 0 0 -1} I found the eigenvalue to be -1 and +/- 5^1/2 Is this correct and can someone show me how to put the root 5 values as eigenvectors? Please and Thanks
*March 8, 2007*

**precalc sequence**

5-5^2 = 5-25 =-20 The fifth term is just when n=5 I believe. What is the fifth term of the sequence a sub n=5-n^2? a)-11 b)-20 c)-7 d)-5 I believe that the answer that fits the best is d, but I could be wrong
*March 8, 2007*

**discrete math**

If a and b are positive integers, prove that: ab = gcd(a,b)*lcm(a,b). Can visualize this being true and easily create examples just dont know how to prove algebraically. well the gcd of any two number can be found by multiplying the two numbers together and the lcm of all ...
*March 8, 2007*

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