Tuesday

February 21, 2017
Total # Posts: 37,725

**Maths**

I will assume that 41/4 is to mean 4 1/4 or 17/4 weight of box C ---- x weight of box B -----(17/4)x weight of box A ---- (5/2)(17/4)x or (75/8)x total weight : 19 5/4 kg or 195/4 kg ??? , the way you typed it. I was going to make the same assumption as above, but why would it...

*December 9, 2016*

**Algebra**

2b + s = 770 ---> s = 770-2b 3b + 2s = 1260 use substitution: 3b + 2(770-2b) = 1260 solve this for b to get burgers sub back into s = ... to get soda

*December 9, 2016*

**Area of a figure**

As you probably noticed, your figure did not come out as you intended. I read that as a rectangle 4 by 10 with an attached triangle of base 6 and height 4 so total area = rectangle + triangle = 4x10 + (1/2)(6x4) = 40 + 12 = 52 btw, "triangular point" makes no sense. ...

*December 9, 2016*

**Algebra**

You don't say what kind of a figure you have, but since you only mentioned three sides, I will assume you have a triangle. middle side ---- x shortest side ---- x-14 longest side ----- x+2 x + x-14 + x+2 = 60 solve for x, sub back into my definitions. Check if your answers...

*December 9, 2016*

**Math solving for x**

4x^2 + 7 is a second degree expression Had it been 4x^3, it would have been a third degree expression. The term with the highest degree determines the degree of the whole expression. If the equation had been 4x^2 + 7 = 0 4x^2 = -7 x^2 = -7/4 which is not a real number, so the ...

*December 9, 2016*

**Math Word Problem**

total number of students on the bus = 46 so what is the percentage equivalent of 20/46 ? You just want an approximation. If it had been 20/50 it would have been 40% you the denominator is a bit less than 50, so your percentage is a bit more than 40%, How about 43% or 44% ?

*December 9, 2016*

**Math Word Problem**

let the amount blueberry juice be x cups let the amount of raspberry cups be 3x cups (notice x : 3x = 1 : 3 , as needed) x + 3x = 48 4x = 48 x = 12 So she needs 12 cups of blueberry and 36 cups of raspberry notice 12 : 36 = 1 : 3 as required.

*December 9, 2016*

**math**

let the angles be 3x, 5x, and 7x you know they have to add up to 180° Solve 3x + 5x + 7x = 180 for x, the sub back into my definitions.

*December 9, 2016*

**Math**

My suggestion is to just learn the proper way to multiply. For relatively small numbers I might use the distributive property mentally. e.g. 14 x 6 ----> 10x6 + 4x6 = 60+24 = 84 or in cases like 18 x 6 , you could do 20x6 - 2x6 , .... (18 = 20-2) = 120 - 12 = 108 For larger...

*December 9, 2016*

**math**

Look at the question that Steve answered 3 years ago http://www.jiskha.com/display.cgi?id=1372679603 It is identical to yours except there were 7 children instead of your 10 BUT, in your question it seems that they changed the 7 to 10 but failed to change the associated ...

*December 9, 2016*

**algebra**

3x + 6y = 12 or even better ... x + 2y = 4

*December 8, 2016*

**Math**

h(x) = x^2 - 8x + 1 h(-1) = (-1)^2 - 8(-1) + 1 = 1 + 8 + 1 = 10

*December 8, 2016*

**Geometry**

that answer cannot possibly be correct let C(-2,-3) be the centre of rotation. then CA = <-5+2, -40+3> , where <...> is a vector = <-3,-37> using the rotation matrix cosØ -sinØ sinØ cosØ times <-3,-37> = 0 -1 1 0 times -3 -37...

*December 8, 2016*

**Math**

more than likely Lucy meant 4 x 10^5 and 4 x 10^7 as the two distances difference = 4(10^7) - 4(10^5) = 4(10^5) (10^2 - 1) = 4(99)(100,000) km farther = 39,600,000 km more or simply 40,000,000 - 400,000 = 39,600,000 km more

*December 8, 2016*

**Math**

1 slurp = (2/5)gulps 1 sip = (2/7) slurps 35 sips = 35(1/7)slurps = 5 slurps = 5(2/5) gulps = 2 gulps

*December 8, 2016*

**Math**

If your equation is x = -2 you have a vertical line where all points have the x-value of -2 e.g. (1,-2), (4,-2), (-2,-2), (0,-2) etc In general if you have an equation where the y term is missing you have a vertical line If you have an equation where the x term is missing , ...

*December 8, 2016*

**Math (optimization) really confused**

Make a sketch of a rectangle with a line parallel to the width dividing the rectangle into two equal parts. Let the length of the smaller rectangle be x and its width equal to y. (the whole rectangle would be 2x by y) given: 2xy = 225 y = 225/(2x) length of fence = L L = 4x + ...

*December 8, 2016*

**Probability**

your data is perfectly suited for this applet http://davidmlane.com/normal.html Just enter you data and enjoy

*December 8, 2016*

**Math (related rates) help?**

let the height of the ladder against the wall be y ft and let the base of the ladder be x ft from the wall we know x^2 + y^2= 13^ 2x dx/dt + 2y dy/dt = 0 when y = 12, x = 5 by above Pythagoras, and dy/dt = -2 ft/s 2(5)(dx/dt) + 2(12)(-2) = 0 dx/dt = 24/10 = 2.4 ft/s

*December 8, 2016*

**Math**

When dividing powers with the same base, keep the base and subtract the exponents, so 100^12 / 100^8 = 100^4 , which is C check the second one in the same way

*December 8, 2016*

**h.p.**

No response or indication that you even looked at the answers I gave you to your previous questions in this topic. What are your thoughts on this question?

*December 8, 2016*

**h.p.**

so term(6) = 1/(a+5d) = 1 a+5d = 1 ** term(10) = 1/(a+9d) = 5 5a + 45d = 1 *** ** times 5 ---> 5a + 25d = 5 subtract from *** 20d = -4 d = -1/5 in ** a - 1 = 1 a = 2 so the HP is 1/2 , 5/9 5/8, 27/20, ... term(15) = 1/(a+14d) = 1/(2 - 14/5) = -5/4

*December 8, 2016*

**ALGEBRA PLEASE HELP**

for a given point (p,q) and slope m the equation is y - q = m(x - p) Which of the choices matches this pattern for your given data

*December 8, 2016*

**harmonic progression**

Just like in your previous problem, the corresponding AS is 2/5 + 13/20 + 9/10 + 23/20 + ... = 8/20 + 13/20 + 18/20 + 23/20 + ... looks like a = 8/20, and d = 5/20 or a = 2/5 and d = 1/4 so term(n) of this AS = a + (n-1)d = 2/5 +(1/4)(n-1) = 2/5 + n/4 - 1/4 = n/4 + 3/20 = (5n...

*December 8, 2016*

**harmonic progression.**

If 1/3+8/23+4/11..... is a harmonic series, then the corresponding arithmetic series is 3 + 23/8 + 11/4 + ... = 24/8 + 23/8 + 22/8 so a = 3 and d = -1/8 term(7) = a + 6d = 3 -6/8 = 9/4 so the 7th term of the HS is 4/9

*December 8, 2016*

**Inequality test**

Wrong "guess", Jason why did you pick D ?

*December 8, 2016*

**Geometry**

#1, correct #2. you have a reflection in a horizontal line, so the x value does not change. P(4,11) was 8 units above y = 3, so the new point has to be 8 unites below y = 3 that is we want (4,-5) or D #3. reflection across the y-axis, leaves the y alone but switches the x to ...

*December 8, 2016*

**calculus**

if s(t) = (t+3)/(t-1)^3 v(t) = ( (t-1)^3 - (t+3)(3)(t-1)^2 )/(t-1)^6 , using the quotient rule v(t) = (t-1)^2 (t-1 - 3t - 9)/(t-1)^6 = (-2t - 10)/(t-1)^4 = -2(t+5)/(t-1)^4 I will leave it up to you to show that a(t) = 6(t+7)/(t-1)^5 so the velocity is decreasing for a(t) < ...

*December 8, 2016*

**g.p.**

Assuming g.m. stands for geometric mean the terms are 2, a, and 1/4 and a/2 = (1/4)/a a^2 = 1/2 a = ± 1/?2 or ± ?2/2

*December 8, 2016*

**g.p.**

the terms would be 8/27, (8/27)r, (8/27)r^2, (8/27)r^3, (8/27)r^4, (8/27)r^5, (8/27)r^6 , -81/6 (8/27)r / (8/27) = (-81/16) / ((8/27)r^5) r^7 = (-81/16)(27/8) r^7 = (-3)^7 / 2^7 r = -3/2 I will let you find the terms to be inserted

*December 8, 2016*

**calculus need help studying now**

a) I suggest expanding this rather than using the product rule y = (x^2 - 4x + 4)(x-7) = x^3 - 11x^2 +32x - 28 y ' = 3x^2 - 22x +32 y '' = 6x - 22 = 0 for a point of inflection x = 22/6 = 11/3 <------ there is your error y = (11/3-2)^2 (11/3-7) = (25/9)(-10/3...

*November 28, 2016*

**Math Question**

x^2+y^2-7x=12-4y x^2 - 7x + 49/4 + y^2 + 4y + 4 = 12 + 49/4 + 4 (x - 7/2)^2 + (y+2)^2 = 113/4 = ?113/2 you had that so the centre is (7/2 , -2) and the radius is ?113/2 which is appr 5.315 set you compass at appr 5.3 units, and with the above centre, draw your circle

*November 28, 2016*

**Math**

looks like you are just dividing your input by 10 y = x/10

*November 28, 2016*

**math**

Usually the "length" of a rectangle is greater than its "width", but anyway..... let the length be x yds then the width is x+15 yds x(x+15) = 100 x^2 + 15x - 100 = 0 (x - 5)(x + 20) = 0 x = 5 or x = -20, the latter is not possible the length is 5 and the ...

*November 28, 2016*

**Math (please check my answer)**

2 angles and the contained side of one triangle are the same as 2 angles and the same contained side of another, so ASA makes them congruent.

*November 28, 2016*

**MATH @Damon @ms. Sue**

The assumption we have to make is that the velocity is a linear function of the time .... So we have two ordered pairs (3,53) and (6,62) slope = (62-53)/(6-3) = 3 using the point (3,53) v-53 = 3(t-3) v-53 = 3t - 9 3t - v = - 44 or y = 3t + 44 should be easy to plot for 3 < ...

*November 28, 2016*

**Math**

younger brother --- x years Martha ----------- 2x years x + 2x = 36 carry on

*November 28, 2016*

**Math**

speed of current ---- x mph distance traveled each way ---- d miles time with the current = d/(6+x) time against the current = d/(6-x) d/(6-x) = 2d/(6+x) divide by d 1/(6-x) = 2(6+x) 6+x = 12 - 2x 3x = 6 x = 2 state your conclusion.

*November 28, 2016*

**Math**

salmon's rate of swimming --- x mph let rate of current be y mph 15/(x+y) = 3 3x+3y=15 ---> x+y=5 15/(x-y)=5 5x - 5y = 15 ----> x - y = 3 add those two equations: 2x = 8 x = 4 , then y = 1 state your conclusion

*November 28, 2016*

**algebra**

typo error in 90 c + 180 + 130 c = 4 c^2 + 80 c should be : 90 c + 1800 + 130 c = 4 c^2 + 80 c ---> c^2 - 35c - 450 = 0 (c - 45)(c + 10) = 0 c = 45 or a negative city speed was 45 mph

*November 27, 2016*

**YT host subscribe now!!**

Bro subscribe to the alex jones channel my man!

*November 27, 2016*

**Business Math**

i = .06/12 = .005 n = 20(12) = 240 PV = 50,000 paym = ?? paym( 1 - 1.005^-240)/.005 = 50,000 payment = $358.22 after 7 years: balance of mortgage = 50000(1.005)^84 - 358.22(1.005^84 - 1)/.005 = $38,737.12 Since the current value is 90,000 but they still owe 38,737.12 the ...

*November 27, 2016*

**Math**

"Determine the initial amount of the substance to the nearest 10th of an hour" HUH, since when is an amount of something measured in units of time?? (I will just ignore that part of the question) N = 8 e^(-6t) initial --- t=0 N = 8 e^0 = 8 mg <----- the initial ...

*November 27, 2016*

**Math**

let each of the equal sides be x cm A = (1/2)x^2 dA/dt = x dx/dt we know dA/dx = -5 cm^2 /s dx/dt = -5/x H^2 = x^2 + x^2 = 2x^2 H = ?2 x dH/dt = ?2 dx/dt = ?2(-5/x) so when x = 10 dH/dt = -5?2 /10 = -(1/2)?2 cm/s or appr -.707 cm/s

*November 27, 2016*

**Algebra**

number of dimes ---- x number of nickels ---- 2x + 1 value of coins: 10x + 5(2x+1) = 165 10x + 10x + 5 = 165 take over

*November 27, 2016*

**math**

http://www.jiskha.com/display.cgi?id=1480267024

*November 27, 2016*

**Math**

the way you typed it .... -5 + ?-50/10 = -5 + 5?2 i/10 = -5 + (?2/2) i what you probably meant: (-5 + ?-50)/10 = (-5 + 5?2 i)/10 = -1/2 + (?2/2) i

*November 27, 2016*

**Emma**

We solve equations, you don't have an equation if you meant: evaluate (?6+i)(?6-1) = 6 - ?6 + ?6i - i I have a strong feeling you meant: (?6+i)(?6-i) = 6 - i^2 , but i^2 = -1 = 6+1 = 7

*November 27, 2016*

**Algebra**

y = kx given: x=3, y=10 10 = k(3) k = 10/3 so y = (10/3)x when x = 6 y = (10/3)(6) = 20

*November 27, 2016*

**precalcalculus**

I assume you are familiar with the tradional way of identifying the information given about a triangle, such as ASA, SAS, SSS and SSA use "cosine law" for SAS and SSS use "sine law" for ASA and SSA #1 - a case of ASA --> a side contained between two ...

*November 27, 2016*

**precalculus**

There are several question of your type in the Related Questions section below

*November 27, 2016*

**precalculus**

Vague question. are you converting an equation or a point with rectangular coordinates?

*November 27, 2016*

**Maths**

For any number, there are 10 possible digits for the unit place, one of those is the 2. so prob(your event) = 1/10

*November 27, 2016*

**Algebra**

compare: http://www.jiskha.com/display.cgi?id=1480210517

*November 26, 2016*

**Algebra**

find the vertex of the parabola. The t of the vertex tells you when it reached the maximum height, the h tells you what that height is.

*November 26, 2016*

**Math**

equation: y = 100 (2)^(t/3.2) .. .. to get 450 bacteria 450 = 100 (2)^(x/3.2) 4.5 = 2^(x/3.2) take log of both sides and use log rules (x/3.2)log 2 = log 4.5 x/3.2 = log 4.5/log2 x = 6.944 hrs. or appr 7 hours

*November 26, 2016*

**precalculus**

How does this post differ from this one? http://www.jiskha.com/display.cgi?id=1480198638

*November 26, 2016*

**PreCalc**

let f(x) = 2x^3+x^2-8x+3 f(1) ? 0 f(-1) = -2+1+8+3 ? 0 f(3) ? 0 f(-3) ? 0 f(3/2) = 0 , yeahhhh, 2x-3 is a factor by long division, 2x^3+x^2-8x+3 = (2x-3)(x^2 + 2x -1) the quadratic has roots of x = -1 ± ?2 looking at the graph of y = 2x^3+x^2-8x+3 -1-?2 < x < -1+?...

*November 26, 2016*

**Algebra**

let the distance from Seattle to wilderness be x miles x/420 + x/300 = 6 times 2100 the LCM 5x + 7x = 12600 x = 1050 miles

*November 26, 2016*

**Trigonometry**

look at the cos^-1 (x/3) construct a triangle with base of x and hypotenuse of 3 by Pythagoras: r^2 = x^2 + y^2 3^2 = x^2 + y^2 y^2 = 9 - x^2 y = ?(9-x^2) so we want the tangent tan (cos^-1 x/3) = opposite/adjacent = ?(9-x^2)/3

*November 26, 2016*

**precalculus**

(3(cos(5pi/4)+i sin (5pi/4) ) )^8 = 3^8(cos 8(5?/4) + i sin 8(5?/4)) = 6561( cos 10? + i sin 10?) = 6561( 1 + i(0) ) = 6561 B (3-3i)^6 let z = 3-3i, so we want z^6 r = ?(9 + 9) = ?18 = 3?2 plot (3,-3) which is in IV, so Ø = 315° or 7?/4 z = 3?2(cos 7?/4 + i sin 7?/4...

*November 26, 2016*

**precalculus**

I checked the first 4, they were ok you seem to know what you are doing.

*November 26, 2016*

**Trigonometry**

a) isn't arcsin(sin(?)) the inverse of itself? so 13?/16 b) and c) same thing, except by definition arcsin( ..) will give you the smallest positive angle so arccos(cos(-?/18) = ?/18 d) arcsec(-?2) the angle Ø so that secØ = -?2 or cosØ = (-1/?2) &...

*November 26, 2016*

**precalculus**

a) ok b) (i-j)-(18i+27i) = -17i - 28j c) (5i-5j)-(30i+54j) --> you did 5u - 5v instead of 5u-v

*November 26, 2016*

**pre calculus**

250 pounds at 45° ---> (250cos45, 250sin45) 130 pounds at -60° ---> (130cos(-60), 130sin(-60) ) Resultant = (250cos45, 250sin45)+(130cos(-60), 130sin(-60) ) = (125?2, 125?2) + (65 , -65?3) = ( 125?2 + 65 , 125?2 - 65?3) = appr (241.7767 , 64.1934) maginitude...

*November 26, 2016*

**Discrete Math**

if you meant: x^1 + x^2 + x^3 + 2x^4 + x^5 = 68 there are none http://www.wolframalpha.com/input/?i=solve+x+%2B+x%5E2+%2B+x%5E3+%2B+2x%5E4+%2B+x%5E5+%3D+68

*November 26, 2016*

**pre calculus**

checking for right-angled triangle: is 100^2 = 55^2 + 85^2 ? NO so let's find the smallest angle by the cosine law: 55^2 = 100^2 + 85^2 - 2(100)(85)cosØ cosØ = 14200/17000 = .83529.. Ø = 33.35..° , (I stored it for accuracy on my calculator So area...

*November 26, 2016*

**pre calculus**

u=<0,-4>, v=<-2,-8> a) 2v+u = <-4,-16) + <0,-4) = <-4, -20> b) 5u - v = <0,-20> - <-2,-8) = <2, -12> c) do this one the same way

*November 26, 2016*

**Mathmatics help please**

clearly 25 and 15

*November 26, 2016*

**Maths help asap please**

3c-7 > 5c+4 3c - 5c > 4+7 -2c > 11 c < -11/2 or c < -5.5 so the smallest integer that is a solution is c = -6 check: if c = -6, -18 - 7 > -30+4 -25 > -36 , true! if c = -5 -15-7> -25+4 -22 > -21 , false

*November 26, 2016*

**Math**

subtract 2 from each part, and you are done -3<x+2<3 -3-2 < x+2-2 < 3-2 -5 < x < 1 ---> ( x lies between -5 and 1 )

*November 26, 2016*

**Math**

nothing wrong with that you could just use the trig-vector notation resultant = (10cos60,10sin60) + (20cos120,20sin120) + (30cos180,30sin180) + (40cos270,sin270) = (5, 5?3) + (-10, 10?3) + (-30, 0) + (0, -40) = ( -35, 5?3-40 )) your sketch will confirm that

*November 26, 2016*

**Trigonometry**

Both Steve and I both told you what was wrong with the wording of the question. http://www.jiskha.com/display.cgi?id=1480115359 Did you even look at the responses?

*November 25, 2016*

**Math**

(2 x 3)>2 - 5>2 is a false statement. you are basically saying: 6 > 2-5 > 2 6 > -3 > 2 the part 6 > -3 is true, but -3 > 2 is nonsense To ask "evaluate" the expression makes no sense Hey, wait a minute! Did you mean (2 x 3)^2 - 5^2 ?? then you...

*November 25, 2016*

**math**

You can't just drop the variable. 5(2x + 7) = 10x + 35 Now you can see that we can't add the 10 and 35 since they are "unlike" terms

*November 25, 2016*

**Math**

correct

*November 25, 2016*

**math**

The 14M, the 3M and the 1M are all expenses so what is 20 - (14+3+1) ?? I get 2 Million

*November 25, 2016*

**Calculus AB**

3y^3 + 2x^2 = 5 9y^2 dy/dx + 4x = 0 dy/dx = -4x/9y^2 when y = 1 , 3 + 2x^2 = 5 2x^2 = 2 x = ± 1 , but in quadrant 1, x = 1 dy/dx = -4(1)/9 = -4/9 equation of tangent: y-1 = (-4/9)(x-1) 9y-9 = -4x + 4 4x + 9y = 13 check: http://www.wolframalpha.com/input/?i=plot+3y%5E3+%...

*November 25, 2016*

**Trigonometry**

y = cos(3?/4 - x) already is a single function of x, namely the cosine function. I don't understand what else you want to do with it. We know: using cos(A-B) = cosAcosB + sinAsinB cos(3?/4 - x) = cos 3?/4 cosx + sin 3?/4 sin x = -?2/2 cosx + ?2/2sinx = ?2/2 (sinx - cosx...

*November 25, 2016*

**Math**

In the original number let the unit place by x then the tens place is 2x, (obviously x < 5) then the number in terms of its value is 10(2x) + x and the number reversed is 10x + 2x the difference between these two is 36, just translate this into Math. 10(2x) + x - (10x + 2x...

*November 25, 2016*

**Math**

clearly the 5 has to go in the unit position for the number to be odd At the front, what would be bigger, something 6 hundred or something 8 hundred?

*November 25, 2016*

**Mathematics**

let his sales be x .06x + 6000 = 10200 solve for x

*November 25, 2016*

**Maths**

330/x - 330/(x+5) = 1/2 That's ok, we end up with a quadratic. Multiply each term by 2x(x+5) 660(x+5) - 660x = x(x+5) 660x + 3300 - 660x = x^2 + 5x x^2 + 5x - 3300 = 0 (x-55)(x+60) = 0 x = 55 or x = -60, we would reject the -60 So your inward speed is 55 km/h, the return ...

*November 25, 2016*

**math**

90 = 2x3x3x5 since each pair of equal factors produces a perfect square, we have 3x3, a perfect square. So all we need is another 2 and another 5 How about 2x2x3x3x5x5 = 900 900 = 30^2 , so it is a perfect square, and it is divisible by 90

*November 24, 2016*

**math-factors and multiples**

both 40 and 32 divide by 8 both a^3 and a^2 divide by a^2 The GCF is 8a^2

*November 24, 2016*

**math**

It is 30a^2

*November 24, 2016*

**math**

5 ? m/-3 + 18 add m/3 to both sides 5 + m/3 ? 18 m/3 ? 13 m ? 39 or 5 ? m/-3 + 18 -13 ? m/-3 times -3 39 ? m m ? 39 , same as above

*November 24, 2016*

**math**

the slope of the 2nd is -2/16 = -1/8 which is the negative reciprocal of the slope of the first. Thus, the lines are perpendicular.

*November 24, 2016*

**math**

I assume we are factoring 25m^6-121m^4 = (5m^3 - 11m^2)(5m^3 + 11m^2)

*November 24, 2016*

**Calculus applications**

let the height be 100 cm^3 ?r^2 h = 100 h = 100/(?r^2) S = 2 circles + the sleeve = 2?r^2 + 2?rh = 2?r^2 + 2?r(100/(?r^2)) = 2?r^2 + 200/r you typed it wrong, it should have been 2?r^2 + 200 r^-1 dS/dr = 4?r - 200/r^2 = 0 for a min of S 4?r = 200/r^2 r^3 = 200/(4?) = 25/? r...

*November 24, 2016*

**Math**

Now: Marcus ---- x John ------ x+10 5 years from now: John's age = x+15 5 years ago: Marcus = x-5 3(x+15) = x-5 that would give you the silly answer of x = -25 checking now Marcus is -25 John is -15 5 years from now, John is -10 and 5 years ago Marcus was -30 sure enough 3...

*November 24, 2016*

**maths**

Without any restrictions, number of committees = C(10,4) = 210 include at least one woman ---> exclude cases of all 4 being men number of ways = 210 - C(5,4) = 205

*November 24, 2016*

**math**

now: daughter ---- x years Mary -------- 3x years 4 years ago: daughter : x-4 Mary : 3x-4 (x-4)(3x-4) = 40 3x^2 -16x + 16 = 40 3x^2 - 16x - 24 = 0 I was expecting it to factor, hoping for whole number solution, but .... x = (16 ± ?544)/6 = 6.55 or a negative check: if ...

*November 24, 2016*

**Math**

let the two numbers be 9x and 3x then 9x + 3x = 72 .. x = 6 sub into my definition to get the numbers.

*November 24, 2016*

**Math**

Find the midpoint of AB, then use your "distance between two points" formula to get CM .

*November 24, 2016*

**Maths**

let the numbers be x and x+1 solve: x + x+1 = 39

*November 24, 2016*

**math**

your first equation should have been 4x +5 = 37 instead of 4x(5) = 37 but then you miraculously switched it to the right one as you solved it. The answer is correct

*November 24, 2016*

**Further mathematics**

x^2 + y^2 = 5xy complet the square: x^2 + 2xy + y^2 = 7xy (x+y)^2 = 7xy take log of both sides 2log(x+y) = log 7 + logx + logy 2log(x+y) - log7 = logx + logy 2log(x+y) - 2log 7^(1/2) = logx + logy 2[ log(x+y) - log ?7] = logx + logy 2 log( (x+y)/?7 ) = logx + logx as required ...

*November 23, 2016*

**algebra~help me**

18^(4-4y)=54(?2)^(3y-2) take log of both sides (4-4y)log18 = lof54 + (1/2)(3y-2)log2 4log18 - 4ylog18 = log54 + (3y/2)log2 - log2 4log18 - log54 + log2 = y( (3/2)log2 + 4log18) 3.58972... = (5.4726...) y y = .655941

*November 23, 2016*

**Calculus**

so considering t = 0 to correspond with 2016 1000 = A 3^0 , but 3^0 = 1 A = 1000 b) y(5) = 1000 3^(4/3) = .... Use your calculator c) 100000 = 1000 3^(t/4) 1000 = 3^(t/4 take log of both sides log 1000 = log 3^(t/4) 3 = (t/4)log 3 t/4 = 3/log3 t = 12/log3 = appr 25.15 years iv...

*November 23, 2016*