Thursday

September 29, 2016
Total # Posts: 36,061

**statistics**

prob = (3/20)(2/19) = 3/190 same question as: I have 20 marbles of which 3 are red I choose 2 without replacement, what is the probability that they are both red

*July 29, 2016*

**math**

So we need a triangle with area of 30 cm^2 let the length of each of the equal sides of the isosceles triangle be x, and the height be h h^2 + 6^2 = x^2 ** but we also know that the area of the triangle is (1/2)(12)h = 30 6h = 30 h = 5 then in ** 25 + 36 = x^2 x^2 = 61 x = &#...

*July 29, 2016*

**math**

By the definition of a rhombus , all sides are equal, so if one side is 10, then all sides are equal to 10. Also, the diagonals bisect each other at right angles creating 4 congruent right-angled triangles. Looking at one of these triangles, we have sides 3x, 4x, and ...

*July 29, 2016*

**oops - Calculus**

dont' know where the 65 came from simply change it to 64 and complete the solution, you should get 48 and 16

*July 28, 2016*

**Calculus**

A product is the result of a multiplication. "product of one of them plus the cube of the other" is mathematically confusing, since "plus" implies addition. I will assume you meant: "product of one of them with the cube of the other" let the one ...

*July 28, 2016*

**maths**

(3-√-16) = 3 - 2i recall: √-1 = i √-16 = √4 x √-1 = 2i

*July 27, 2016*

**Math**

let the two numbers be x and x+1 x + x+1 = S 2x = S - 1 x = (S-1)/2 The square of the larger number minus the square of the smaller number = (x+1)^2 - x^2 = x^2 + 2x + 1 - x^2 = 2x + 1 = (S-1) + 1 = S check: let's take 37, and 38 sum = 75 square of larger =1444 square of ...

*July 27, 2016*

**Math**

15/4 = 3.75 or = 3 3/4 as a mixed fraction or how about (1/2)(7.5) or (1/4)(15 or .....

*July 27, 2016*

**GP**

so the GP terms are: a+d, a+3d, and a+6d (a+3d)/(a+d) = (a+6d)/(a+3d) (a+6d)(a+d) = (a+3d)^2 a^2 + 7ad + 6d^2 = a^2 + 6ad + 9d^2 ad = 3d^2 divide by d a = 3d common ratio : r = (a+3d)/(a+d) = 6d/(4d) = 3/2

*July 27, 2016*

**Maths**

Did you look at http://www.jiskha.com/display.cgi?id=1469612090

*July 27, 2016*

**Maths**

after 1 day, the two clocks will show a difference of 5 minutes after 2 days, the two clocks will show a difference of 10 minutes ... after n days the clocks will show a difference of 5n minutes. One day consists of 1440 minutes. number of days needed to make up this time = ...

*July 27, 2016*

**maths**

Since you gave the dimension of only one wall, let's assume that the room is square. As Steve showed in his calculation, one wall has an area of 5x3 or 15 m^2 So 4 walls have an area of 60 m^2 if 6 litres cover 10 m^2 1 L will cover 10/6 or 5/3 m^2 number of litres of ...

*July 27, 2016*

**Algebra**

time of Bell's sprinklers --- x hrs time of Patterson's ------- 65-x hrs solve for x: 15x + 25(65-x) = 1225

*July 26, 2016*

**geometry**

well, it could either be 8, 8, 10 or 8, 10, 10 so which fits?

*July 26, 2016*

**MAth Trig**

72° = (π/180)(72) radians = 2π/5 radians arc = rØ 32 = 2π/5 r r = 80/π so the diameter is 160/π cm or appr 50.9 cm or 72/360 = 32/(2πr) 144πx = 32(360) x = 80/π , as above

*July 26, 2016*

**Maths**

The two scales where they coincide are -40 degrees in both units There are many places in the world where such temperatures exist. In my Canada these are the top 10 lowest temperatures recorded. http://www.durhamregion.com/whatson-story/5153897-top-10-coldest-temperatures-...

*July 26, 2016*

**Math**

Abegail --- x years Alger ---- x-7 years x(x-7) = 144 x^2 - 7x - 144 = 0 (x - 16)(x + 9) = 0 x = 16 or x = -9, the last does not make sense. sub back in my definitions

*July 26, 2016*

**Army school math**

let each of the equal sides be x 2x + 6 = 26 x = 10 make a sketch of the triangle, draw in its height h h^2 + 3^2 = 10^2 h = √91 area = (1/2)(6)√91 = 3√91 cm^2 which is the same as DrBob's answer

*July 26, 2016*

**Trigo**

I made a sketch, showing two right-angled triangles. One is : base angle 28°, height = 30 tan28 = 30/base base = 30/tan28 other triangle: let the distance between ships be x tan23° = 30/(base + x) base + x = 30/tan23 x = 30/tan23 - base = 30/tan23 - 30/tan28 = 14.25 m

*July 26, 2016*

**physics**

first leg: a = 1 v = t + c when t = 0 , v = 0 , thus c = 0 v = t s = (1/2)t^2 so after 20 seconds, s = (1/2)(400) = 200 m v = 20 m/s (or 72 km/h ) second leg: at constant speed, no acceleration v = 20 m/s s = rate x time = 20(1800) = 36000 m last leg: a = ? v = at + 20 when t...

*July 26, 2016*

**Math**

size of side of square to be cut out --- x cm volume = (25-2x)(32-2x)(x) = 1575 expanding we get: 4x^3-114x^2 + 800x = 1575 4x^3 - 114x^2 + 800x - 1575 = 0 messy to solve, gave up trying to factor, and used Wolfram: http://www.wolframalpha.com/input/?i=solve+4x%5E3+-+114x%5E2...

*July 25, 2016*

**CHECK MY ALGEBRA 2**

Scott was right, the denominator causing the vertical asymptote at x = -2 is x+2 final answer: f(x) = (x-4)/( (x-4)(x+2) )

*July 25, 2016*

**pre cal**

You should know that we can only take logs of positive numbers, so x-1 > 0 x > 1 so the vertical asymptote is x = 1

*July 25, 2016*

**Math**

the the circle be x^2 + y^2 = r^2 then y = √(r^2 - x^2) or (r^2 - x^2)^(1/2) let the length of the rectangle be 2x, and the height be 2y then the vertex in quadrant I is (x, (r^2 - x^2)^(1/2) ) area = 2x(2y) = 4xy = 4x((r^2 - x^2)^(1/2)), remember r is a constant d(area...

*July 25, 2016*

**Please help me solve this - PreCalc**

let x = π/6 for easier typying so your 1/cos2 * π/16 - 1/cot2 * π/16 = 1/cos^2 x - 1/cot^2 x = sec^2 x - tan^2 x since sec^2 x = 1 + tan^2 x , = 1 + tan^2 x - tan^2 x = 1

*July 25, 2016*

**pre cal**

plug in your values, assuming you meant f(x) =a (2)^(bx) and not what you typed. for (0,3) , 3 = a(2)^0 --> 3 = a for (1,4) , 4 = 3(2)^b 2^b = 4/3 take logs of both sides, and use log rules b log2 = log4 - log3 b = (log4 - log3)/log2 = appr .415037

*July 25, 2016*

**math**

smaller number --- x larger number ---- x+5 "the sum of two numbers is 25" translate into an equation and solve.

*July 23, 2016*

**Maths**

Use your definitions: a + ar^2 = 7/3 a( 1 + r^2) = 7/3 ** ar + ar^3 = 7/4 a(r + r^3) = 7/4 *** divide *** by ** (r + r^3)/(1 + r^2) = (7/4) / (7/3) = 3/4 4r + 4r^3 = 3 + 3r^2 4r^3 - 3r^2 + 4r - 3 = 0 r^2(4r - 3) + 1(4r-3) = 0 (4r-3)(r^2 + 1) = 0 4r = 3 or r^2 = -1 , the last ...

*July 23, 2016*

**Math - Trig**

All you have to do is follow the same steps I used to get the answer of 4.51 http://www.jiskha.com/display.cgi?id=1469238292

*July 22, 2016*

**Math**

Stacey/ba, please don't switch names 7.8 + sin3.5 (pi/6(t-3)) = 10.29 sin3.5 (pi/6(t-3)) = 2.49 not possible, sin(?) cannot be > 1 when you first posted this, you had 3.5sin (pi/6(t-3)) I will change it to 7.8 + 3.5sin (pi/6(t-3)) = 10.29 3.5sin (pi/6(t-3)) = 2.49 sin (...

*July 22, 2016*

**correction - Math**

forget the first part of my solution, I read it as 3x^3−x^2+bx−24 we know : f(x) = ax^3−x^2+bx−24 since x-2 is a factor, f(2) = 0 f(2) = 8a - 4 + 2b - 24 = 0 8a + 2b = 28 4a + b = 14 ** f(-4) = 0 -64a - 16 - 4b - 24 = 0 -64a - 4b = 40 16a+ b = -10 *** ...

*July 22, 2016*

**Math**

ax^3−x^2+bx−24 = (x-2)(x+4)(ax + c) the ax^3 can only come from the multiplication of the first terms of each of the binomials, (x)(x)(ax) = 3x^3 ----> a = 3 the -24 can only come from the multiplication of the last terms of each of the binomials, (-2)(4)(c) = -...

*July 22, 2016*

**Futher maths**

tanØ + 2secØ = 2cotØ + 3cscØ sinØ/cosØ + 2/cosØ = 2cosØ/sinØ + 3/sinØ multiply each term by sinØcosØ sin^2 Ø + 2sinØ = 2cos^2 Ø + 3cosØ sinØ(sinØ + 2...

*July 22, 2016*

**math**

John's rate = 1/4 Michael's rate = 1/x combined rate = 1/4 + 1/x = (x+4)/(4x) given: 1/( (x+4)/(4x) ) = 3 4x/(x+4) = 3 4x = 3x + 12 x = 12 Michael alone would take 12 hours check: combined rate = 1/4 + 1/12 = 1/3 time at combined rate = 1/(1/3) = 3

*July 21, 2016*

**math**

Think about the method and the pattern if you had 80% ----> 80/100 = 4/5 if you had 8% -----> 8/100 = 2/25 if you had .8% ----> .8/100 = 8/1000 = 1/125 your .8/100 * 10/10 = 8/1000 , not 8/100

*July 21, 2016*

**Math**

"Which statement best describes the sum 7/8? " - first of all 7/8 is not the "sum" - secondly, there is no mathematical reason for Jack to come up with 7/8 - thirdly , this is a silly question.

*July 21, 2016*

**Math**

" ...all the possible values for angle Ø, given that Ø =-3/8and 0<theta<3pi " this makes no sense, did you skip the trig function in front of Ø, such as sinØ = -3/8 ??

*July 21, 2016*

**Math**

one question at a time. period of your cosine is 4 s so 2π/k = 4 4k = 2π k = π/2 so let's start with A = cos (πt/2) the min is .08, and the max is .82, thus a = (.82-.08)/2 = .37 so far: A = .37 cos (πt/2) the min of that is .37, but we want the ...

*July 21, 2016*

**Math**

Are you assuming the relation follows a trig function, either a sine or cosine ?

*July 21, 2016*

**Math**

area to be covered = 4(90) or 360 square feet, assuming your room is square. number of gallons = 360/120 = 3 gallons

*July 21, 2016*

**Arithmetic/Geometric Sequence**

A quick check shows it is neither arithmetic nor geometric, so mess around with it a bit how about (1/18)( 12, 6, 4, 3, ....) , 18 is the LCD notice : 12/1 = 12 12/2 = 6 12/3 = 4 12/4 = 3 so it looks like term(n) = (1/18)(12/n) = 2/(3n)

*July 21, 2016*

**Math**

Chandra ---- x years Ben's age ---- x+6 yrs Ali's age ---- x+6 + 3 = x+9 yrs (x + x+6 + x+9)/3 = 10 solve for x, then back-sustitute.

*July 21, 2016*

**Calc**

P = 5cos (pie/2 (t)) +5 the period of this function is 2π/(π/2) = 4 for the lowest productivity, we need the minimum of the function. we know that cos (pie/2 (t)) has a minimum of -1 then 5cos (pie/2 (t))has a minimum of -5 and 5cos (pie/2 (t)) +5 has a minimum of 0 ...

*July 20, 2016*

**math**

cotx = 6/5 ---> tanx = 5/6 secy = 3/2 ---> cosy = 2/3 sketch your triangles in quad I using Pythagoras, if tanx = 5/6 r^2 = 25 + 36 = 61 r = √61 if cosy = 2/3 by Pythagoras: 2^2 + Y^2 = 3^2 Y = √5 tany = √5/3 tan(x+y) = (tanx + tany)/(1 - tanxtany) = (5...

*July 20, 2016*

**Math - Trig**

the period of your function is 2π/(π/6) or 12. So it represents 1 year of temperature change. first look at the graph: http://www.wolframalpha.com/input/?i=plot+y++%3D+12.5+%2B+15.8sin+(%CF%80%2F6+x+%E2%88%922%CF%80%2F3)+,+y+%3D+12.5+from+0+to+12 notice the sine ...

*July 20, 2016*

**Math - Trig**

period = 2π/k in our case k = 2π/3 period = 2π/(2π/3) = 3 so one rotation takes 3 seconds, thus 4 rotations would take 12 seconds The radius of the wheel would be the amplitude of your cosine curve which is 17.5 cm Here is a graph of your courve: http://www...

*July 20, 2016*

**Math**

So the zero can only come from the numerator, thus r^2 + 5r + 6 = 0 (r+2)(r+3) = 0 r = -2 or r = -3 BUT, as noted in your other replies, r cannot be -2 so r = -3 which is C

*July 20, 2016*

**Math**

let's graph the original function http://www.wolframalpha.com/input/?i=plot+y++%3D+%E2%88%92+sin+(3x+%2B+%CF%80%2F3+)+%E2%88%92+2 Notice that the curve does not cross or touch the x-axis, that is , it can never be zero. Therefore the reciprocal can never be undefined and ...

*July 20, 2016*

**Math**

We all know that 4 quarters make up 1 dollar. so how many quarters do we need to make up $50.50 ?

*July 20, 2016*

**math**

let the three numbers be x-1, x, and x+1 , where x is the middle number x-1 + x + x+1 = 18 3x=18 x=6 so the middle number is 6, and the three numbers are 5,6, and 7 btw, You could define the numbers any way you want. I could say, let the first number be (5x+7), then the next ...

*July 20, 2016*

**Math**

1/4 -1/x+6= 1/x ? I have this feeling you meant 1/4 - 1/(x+6) = 1/x multiply by 4x(x+6) , the LCD x(x+6) - 4x = 4(x+6) x^2 + 6x - 4x = 4x + 24 x^2 - 2x - 24 = 0 (x-6)(x+4) = 0 x = 6 or x = -4

*July 20, 2016*

**maths**

total trip = 2(27) + (11/2)(20) km = 164 km total time = 2+11/2 or 7.5 hours average speed = 164/7.5 or appr 21.87 km/h

*July 20, 2016*

**trigonometry**

2sin(t)cos(t)-cos(t)+2sin(t)-1=0 cost(2sint - 1) + (2sint - 1) = 0 (2sint - 1)(cost + 1) = 0 sint = 1/2 or cost = -1 if sint = 1/2 t = π/6 or t = 5π/6 if cost = -1, look at your cosine curve, t = π

*July 19, 2016*

**Math**

make a sketch of the first few bounces and you will see: 1 bounce --- 56 m 2nd bounce = 2(28) = 56 3rd bounce = 2(14) = 28 4th bounc = 2(7) = 14 5th bounce = 2(3.5) = 7 6th bounce = 2(1.75) = 3.5 add them up to get ..... 164.5 or: from the 2nd on , we have a geometric sequence...

*July 19, 2016*

**mathes**

The room is 800 cm by 600 cm, and the tile is 8 cm by 10 cm, so the tiles will fit exactly along either side. (ignoring any grouting gaps) area of floor = 480,000 cm^2 area of one tile = 80 cm^2 number of tiles = 480,000/80 or 6000 tiles or tiles along the length = 800/8 = 100...

*July 19, 2016*

**math**

cosine law: x^2 = 2.4^2 + 2.4^2 - 2(2.4)(2.4)cos 30° ....

*July 19, 2016*

**Math**

This one is a bit different. In the first one, the "16" was the value of one of the terms of the ratio. In this one, the "240" is the sum of the terms of the ratio. Let Anton's number of stamps be 4x let Maria's number be 2x 4x + 2x = 240 x = 40 ...

*July 19, 2016*

**Find the probability**

following your "steps" prob(both red) = C(4,2)/C(9,2) = 6/36 = 1/6 or , straightforward way .... prob = (4/9)(3/8) = 1/6

*July 19, 2016*

**Calculus**

let y = 1/sinx = (sinx)^-1 dy/dx = -1(sinx)^-2 (cosx) = cosx (1/sin^2 x) = cosx/sinx * 1/sinx = cotx cscx

*July 18, 2016*

**Calculus the derivative**

Did you not look at my solution to the same question ? http://www.jiskha.com/display.cgi?id=1468890453 All I can see wrong with it, I labeled part D as B for B all you have to do it sub t = 1 and t = 3 into your velocity equation: v = -32t.

*July 18, 2016*

**Calculus the derivative**

A . correct B. for the average velocity no Calculus is needed P(1) = -16(1) + 1454 = 1438 P(3) = -16(9) + 1454 = 1310 average velocity = (1310 - 1438)/(3-1) = -64 ft/s C. now you want to set -32t = -64 t = 2 E. correct F. I disagree. you want P(t) = 0 -16t^2 + 1454 = 0 t^2 = ...

*July 18, 2016*

**Math**

i = .0275/12 = .002291666... what is 5700(1.00229166..)^144 ?

*July 18, 2016*

**MATH**

just use your definitions: the terms would be a, ar, and ar^2 so a(ar)(ar^2) = 343 a^3 r^3 = 343 (ar)^3 = 343 ar = 7 or a = 7/r a + ar + ar^2 = 49/2 a(1 + r + r^2) = 49/2 (7/r)(1 + r + r^2) = 49/2 7/r + 7 + 7r = 49/2 times 2r 14 + 14r + 14r^2 = 49r 14r^2 - 35r + 14 = 0 2r^2 - ...

*July 18, 2016*

**MAth**

Let's consider how I got the values of x we started with sinx = -1/2 We know from our basic trig functions or by the CAST rule, that x must be in quadrants III or IV (you must know that!) We then find the angle in standard position, that is the corresponding angle if it ...

*July 18, 2016*

**MAth**

normally our domain is 0 ≤ x ≤ 2π perhaps if you think in degrees it might be easier to see. -π/6 radians is -30° now where is -30° ? doesn't it coincide with 330°, and isn't 330° = 11π/6 radians ?

*July 18, 2016*

**MAth**

It factors (2sin x + 1)(3sin x + 1) = 0 sinx = -1/2 or sinx = -1/3 If sinx = -1/2, I know x must be in III or IV x = 210° or 330° x = 7π/6 or 11π/6 if sinx = -1/3, x must be in III or IV angle in standard position is appr 19.47° x = 199.47° or 340.53&...

*July 18, 2016*

**Math - Trig**

To "solve" we need an equation. I will assume you meant: 4cos^2 x - 3 = 0 cos^2 x = 3/4 cosx = ± √3/2 , ----> all 4 quadrants you should recognize that cos π/6 = √3/2 x = π/6 or x = π - π/6 = 5π/6 or x = π + π/...

*July 18, 2016*

**oops - Calculus rate of change**

thanks Steve

*July 18, 2016*

**Calculus rate of change**

Since the height is twice the diameter, the height is equal to the radius of the circular base. Let the radius be r V = (1/3)π r^2 h, but h = r V = (1/3) π r^3 dV/dt = π r^2 dr/dt dr/dt = 20/(πr^2) ** when t = 5 min, V = 5(20) = 100 m^3 100 = (1/3)πr^3...

*July 18, 2016*

**Math**

re-writing your equation: (1/x)/((1/3)x^(-2/3)) = 3/x^(1/3) (3/x) x^(2/3) = 3/ x^(1/3) divide by 3 (1/x) x^(2/3) = 1/x^(1/3) multiply both sides by x^(1/3) (1/x)(x)^1 = 1 1 = 1 so the equation is true for all x, except of course x = 0, or else we would be dividing by zero

*July 18, 2016*

**Maths**

length : breadth : perimeter = 100 : 80 : 360 = .... reduce to lowest term ratio

*July 18, 2016*

**math**

prob(star) = 1/8

*July 18, 2016*

**math**

percentage = (12 + 10)/(25 + 10) = 22/35 = .6285.. or appr 62.9 %

*July 18, 2016*

**math**

smaller ----- x larger ------ x+6 Just translate the English into Math: 2(6+x) + 10 = 3x - 2 solve for x

*July 17, 2016*

**Maths**

look at the second question below in Related Questions answered by Mathmate in 2011 http://www.jiskha.com/display.cgi?id=1304625732

*July 17, 2016*

**Maths**

Are you taking Calculus? Hint: Newton's Law of Cooling

*July 17, 2016*

**math**

Isn't that just 7 choose 3 ??

*July 17, 2016*

**math**

So in 1 day, the earth rotates 24,000 miles (according to your data) after 4 hours it rotated 4000 miles 4000/24000 = 1/6 1/6 of a rotation after 4 hours do the others in the same way

*July 17, 2016*

**Math**

the sum of my numbers is .... ? incomplete

*July 17, 2016*

**@ Asfand**

For most of your replies you have just blurted out the answer. Supplying the answer is not what the purpose of this webpage is. A student has to understand how the question is done, the answer to me is just an afterthought. A reply should contain solutions, part of solutions, ...

*July 17, 2016*

**Math**

first equation: 4h + 6j = 71 second equation: ???????

*July 17, 2016*

**math**

Continue from where you left off when you were "dany" http://www.jiskha.com/display.cgi?id=1468749031

*July 17, 2016*

**math**

let the sales be s solve for s: .12s + 4000 = .02s + 10000

*July 17, 2016*

**math**

You are probably just as good as googling and counting as I am Goggle a list of primes. count how many primes you see from 23 to 97

*July 17, 2016*

**algebra**

mmmhhh, how many sides does a hexagon have?

*July 17, 2016*

**math**

distance at 20 mph = 5(20) = 100 miles distance at 25 mph = 2(25) = 50 miles percent of longer distance more than shorter distance = 100%

*July 17, 2016*

**math**

I assume you are trying to solve this system. 9x+3y-4z=35 ** x+y-z=4 *** 2x-5y-4z = -48 **** subtract **** from ** 7x + 8y = 83 ## 4 times *** ----> 4x + 4y - 4z = 16 subtract **** from the above 2x + 9y = 64 ### 7 times ### ---> 14x + 63y = 448 2 times ## ----> 14x...

*July 17, 2016*

**MATHS**

I assume you made a sketch On mine, I labeled the centre of the smaller circle P and the centre of the larger circle Q There is a common chord, I called that AB Adding the areas of the two circles would count the overlap twice, so we have to subtract the overlap. The overlap ...

*July 17, 2016*

**math**

let w represent the work done A's rate ---- w/24 B's rate ---- w/9 C' rate ----- w/12 B and C's combined rate = w/9 + w/12 = 7w/36 work done by B and C in 3 days = 21w/36 amount left to be done by A = w - 21w/36 = 15w/36 time for A to finish the job = (15w/36...

*July 17, 2016*

**algebra**

looks like you expect somebody to do an assignment or homework for you, and you have not shown any work or indication where your problems lie. What don' t you understand about these questions. They all seem to deal with "geometric mean" btw, you will have more ...

*July 16, 2016*

**pre cal**

1.05( u dot v)

*July 16, 2016*

**small oops - math**

just noticed the - sign in front of √3 so our z = -√3 + i no big deal: the magnitude stays the same, however, the angle would now be in quad II so Ø = 150° or 5π/6 making our √z = √2(cos 75° + i sin75°) OR √2( cos 5π/...

*July 16, 2016*

**math**

let z = √3 + i magnitude = √(√3^2 + 1) = 2 angle Ø: tanØ = 1/√3 Ø = π/6 or 30° so z = 2(cos30° + i sin30°) or 2cis 30° or 2 cis π/6 √z = z^(1/2) = √2( cos 15° + i sin15°) or √2(cos...

*July 16, 2016*

**math**

-12-12√3 i magnitude = √( 144 + 432) = √576 = 24 tan Ø = -12√3/-12) = √3 Ø = 60° or π/3 but from my sketch I see that we are in quadrant III so Ø = π/3 + π = 4π/3 -12-12√3 i = 24(cos 4π/3 + i...

*July 16, 2016*

**math**

just evaluate, even if you don't have a calculator, you should be able to find cos 11π/6 or cos 330° = cos30° = √3/2 sin 11π/6 = -1/2 9(cos 11pi/6 + i sin 11pi/6) = 9(√3/2 - 1/2) = 9√3/2 - 9/2 i

*July 16, 2016*

**Math**

I agree with Steve's answer, but I don't understand why he initially used a plus sign in his cosine equation. I did a similar question to yours about 5 years ago http://www.jiskha.com/display.cgi?id=1303931140 Back to yours, if the resultant of two forces is less than ...

*July 16, 2016*

**MATHS**

What's with all the + signs in the first post? smaller ---- x larger ----- 30-x 2x - 6 = 30-x 3x = 36 x=12 smaller is 12, larger is 30-x or 18 2nd: I will assume you meant to type: "The denominator of a fraction exceeds the numerator by 3" so the original ...

*July 15, 2016*

**Math**

Contains a typo How many own birds ? anyway .... suppose 4 own birds ratio of bird owners : cat owners = 4 : 9 Make the appropriate changes to my solution once you know how many bird owners.

*July 15, 2016*

**Math**

done, look back

*July 14, 2016*