Wednesday

April 1, 2015

April 1, 2015

Total # Posts: 29,357

**math**

base will be 20-2x by 20-2x, and the height will be x Volume = x(20-2x)(20-2x) or x(20-2x)^2 clearly each of the dimensions must be positive, so 20-2x > 0 -2x > -20 x < 10 In my notation, 0 < x < 10, I will let you change it to yours.
*January 27, 2015*

**Calculus**

cost to produce 120 units = C(120) = 1000+5.7(120) + .7(120^2) = = 11764 cost to produce 100 units = C(100) = 8570 rate of change = (11764-8570)/(120-100) = 3194/20 = 159.70 dollars/unit repeat the process for 100 to 101
*January 27, 2015*

**algebra 2**

You have a typo and don't state how high above the water the diving board is. I will give it an arbitrary value of 6 ft. So the equation of height is h = -16t^2 + 10t + 6, where h is in ft and t is in seconds , where t ≥ 0 for a max height, we need the vertex of that...
*January 27, 2015*

**physics- vectors**

You must have meant, "What are (a) the magnitude and (b) the angle (relative to +x) of Vector C " A = (11.6cos36.5 + 11.6sin36.5) = (appr 9.32, 6.90) B = (14cos17.1 + 14sin17.1) = (appr13.38 , 4.12) vector C = (22.71 , 11.02) magnitude = √22.71^2 + 11.02^2) = ...
*January 27, 2015*

**algebra**

Algebaric expressions: algebraic expressions that are just plain barbaric.
*January 27, 2015*

**Kate**

I made a rough sketch of triangle JKR and filled in the angles. A basic property of triangles is that in any triangle, the smallest side is opposite the smallest angle, and the largest side is opposite the largest angle Since angle J of 75° is the largest, side RK must be ...
*January 27, 2015*

**math**

or, stated another way if x = 0 , y = -16 let's plug it in.... 0 + k(-16) + 15 = 0 k = 15/16
*January 26, 2015*

**math**

let's just look at the antifreeze, right now the volume of antifreeze is .7(4) L or 2.8 L Let the amount of the current fluid we are draining be x L Now 70% of that is antifreeze, so the amount of antifreeze we lose is .7x So the actual amount of antifreeze left in the rad...
*January 26, 2015*

**Math**

co-workers check -- x your check ------- .7x x + .7x = 695 1.7x = 695 x = 408.82 co-wks = $408.82 yours = .7(408.82) = $286.18 add them up to verify my answer
*January 26, 2015*

**Math**

Do you have a typo? You said, "What is P ?" but you said P = {1,2,3,4} , so we know it
*January 26, 2015*

**Math**

yes, the correct answer is 7/9 I was just objecting to the messy way that Kudum was writing the expression. Please read my answer to Kudum carefully
*January 26, 2015*

**@ Kudum - Math**

the expression 2/3/6/7 is in very bad form You MUST use brackets to establish the proper order of operations. the question was (2/3) ÷ (6/7) = (2/3)(7/6) = 7/9 but if you type in your expression 2/3/6/7 into any modern calculator, which are designed to follow the ...
*January 26, 2015*

**math**

Are you reading my replies to your posts? http://www.jiskha.com/display.cgi?id=1422288228
*January 26, 2015*

**math**

I will assume you are trying to type: A 6 cylinder car has cylinders with ..... volume of one cylinder = π(2.22^2)(3.25) = 50.3198..... so the engine is 6(50.3198..) = 301.9 cubic inches
*January 26, 2015*

**math**

same thing again, plug in the straight line equation, and solve
*January 26, 2015*

**math**

You could but you don't have to recall that x = (-b ± √(b^2 - 4ac)/(2a) Judging from the type of question you have been asking, I trust you have learned the properties of the "discriminant" b^2 - 4ac I gave them to you in one of the posts.
*January 26, 2015*

**math**

Same thing as your last post Just evaluate b^2 - 4ac and decide
*January 26, 2015*

**math**

intersect the line with the parabola kx^2 - 5x + 2 = -3x + 4 kx^2 - 2x - 2 = 0 Looks like you are studying the nature of the roots, remember that if b^2 - 4ac > 0 you will have two solutions b^2 - 4ac = 0 you will have 1 solution (2 equal ones) b^2 - 4ac < 0 , there is ...
*January 26, 2015*

**Maths**

Outer dimension of the picture : 44 by 34 area whole thing including the frame = 44x34 = ... area of picture = 40x30 so area of frame = ???
*January 26, 2015*

**Math**

Perhaps I am missing something, but if we fill each of the labeled bottles just once, the big bottle can contain as little as 18 L 1 x (4L + 6L + 8L) = 18L
*January 26, 2015*

**Math**

The is a quadratic equation: sin^2 x - sinx - 2 = 0 (sinx - 2)(sinx + 1) = 0 sinx = 2 , which is not possible or sinx = -1 x = 3π/2 or x = 270° location on unit circle --- (0,-1) period --- 2π general solution x = 3π/2 + 2kπ
*January 26, 2015*

**Add maths form 4**

using the properties dealing with the nature of the roots, if there are two equal roots, then b^2 - 4ac = 0 so in hx2 _ 4kx + 9h = 0 16k^2 -4(h)(9h) = 0 16k^2 = 36h^2 4k = 6h h/k = 4/6 So h : k = 4 : 6 = 2 : 3 They should have reduced their answer to 2:3
*January 26, 2015*

**algebra 1**

Yes, your question was answered. http://www.jiskha.com/display.cgi?id=1422242533 Always check back to avoid un-necessary duplication of answers such as this. Secondly it does not help if you switch names.
*January 26, 2015*

**Math**

let the angles in order of size be x , a , b, 2x "The difference between the smallest and second smallest angles" ---> a-x "the difference between the biggest and second biggest angles" ---> 2x-b 2x - b = a - x 3x = a+b also we know x + a + b + 2x = ...
*January 26, 2015*

**TO REINY**

check our previous post for the explanation
*January 25, 2015*

**ALGEBRA**

you showed this: x+0.05<632 x<632/0.05 x<??????? following my argument, you should have had x + .05x < 632 x is a common factor x(1 + .05) < 632 x(1.05) < 632 ahhh, now you see where that 1.05 comes from, right ?
*January 25, 2015*

**ALGEBRA**

When you pay for an item with sales tax of 5% you pay the price + the sales tax = 100% + 5% = 1 + .05 = 1.05 similary a sales tax of 7% ---> you pay 1.07 etc
*January 25, 2015*

**ALGEBRA**

1.05x = 632 x = 632/1.05 = 601.90 The machine should cost less than 601.90
*January 25, 2015*

**Calc**

I agree with SJ but I would look at the backend of this thing first. Consider 1/x As x --->0 , 1/x becomes infinitely large but we are taking cos(???) and the result of cos(anything) is a number between -1 and 1 so e^(cos(1/x)) lies between e^-1 and e^1 or between 1/e and e...
*January 25, 2015*

**algebra**

let the first odd integer be n then the next even integer is n+1 3n < 4(n+1) by 11 3n = 4(n+1) - 11 3n = 4n + 4 - 11 7 = n the first odd integer is 7, then next even one is 8 check: 3 times the first = 21 4 times the second = 32 Is 21 eleven less than 32 ??, YES
*January 25, 2015*

**calculus**

how about y = 7x^2/((x-7)(x-9))
*January 25, 2015*

**Calc 1**

1. lim ( √(x+4) - 2)/x , as x-->0 =lim ( √(x+4) - 2)/x * ( √(x+4) + 2)/( √(x+4) + 2) = lim (x+4 - 4)/(x(√(x+4) + 2) = lim 1/( √(x+4) + 2) , x --> 0 = 1/(2+2) = 1/4 #2. In any limit question, the first thing I do is to sub the approach ...
*January 25, 2015*

**Calculus**

1. y = x^3 , at x = 1, y=1, so we have the point(1,1) dy/dx = 3x^2 , which is 3, when x = 1 y-1 = 3(x-1) y-1 = 3x-3 3x - y = 2 or y = 3x - 2 2. Lim sinxcos 2x/(3x) = lim sinx/x * cos 2x/3, as x ---> 0 = (1)*(1/3) = 1/3
*January 25, 2015*

**Algebra**

original price = x sale price = .85x x - .85x = 180 .15x = 180 x = 180/.15 = 1200 $1200 for a cell phone ?? check: 15% of 1200 = 180
*January 25, 2015*

**ALGEBRA**

set the 2 equations equal to each other ... 16x + 150 = -x^2 + 60x - 10 x^2 - 44x + 160 = 0 (x-40)(x-4) = 0 x = 40 or x = 4 when x = 40, y = 16(40) + 150 = 790 when x = 4 , y = 16(4) + 150 = 214 Pick out the choice that matches my solution
*January 25, 2015*

**math**

2560 m/60 sec = 2.56 km/min = 60 km/h
*January 25, 2015*

**Quick Alegbra Help**

done http://www.jiskha.com/display.cgi?id=1422231991
*January 25, 2015*

**Math**

done http://www.jiskha.com/display.cgi?id=1422231991
*January 25, 2015*

**Math**

let total distance be x bus: x/4 jog : (1/2)(3x/4) = 3x/8 walk: 800 x/4 + 3x/8 + 800 = x times 8 2x + 3x + 6400 = 8x x = 6400 total distance = 6400 ft
*January 25, 2015*

**Algebra 2 Applications**

height = -4.9t^2 when t = 3 height = 4.9(9) m = appr 44.1 m
*January 25, 2015*

**Calculus**

You must have done it correctly, since I also got x = appr 389 m Since this does not appear to make any real sense, let's investigate the other 2 cases: 1. he runs all the 300 m on the trail then at right angles through the bush 2. he runs all the way through the bush ...
*January 25, 2015*

**Math( Attn: Reiny)**

in any parabola written in the form y = a(x-p)^2 + q, the vertex is (p,q) if a is positive, q will be a minimum when x = p if a is negative, q will be a maximum when x = p if the equation is written in the form y = ax^2 + bx + c, the x of the vertex can be simply found by -b/(...
*January 25, 2015*

**Math( Attn: Reiny)**

Yes Wendy, I made the error in copying it from paper to here , should have been 36-2x Look at Kudums solution, he did it correctly using the same variable setup as mine As for #2 (#3 in your earlier post), compare Kudum's with mine and see that we just interchanged our ...
*January 25, 2015*

**math**

Using only whole numbers for lengths and widths 1 by 7 2 by 6 3 by 5 4 by 4 ---> notice that the sum is always 8 if you allow sides with fractional measurement, then there would be an infinite number of cases e.g. 2.5 by 5.5 ..... 3.412 by 4.588 ..... etc --------> ...
*January 25, 2015*

**math**

start: 22° increase for 5 min: 5(12) = 60° temp after 5 min = 22+60 = 82° decrease for next 3.5 min = 3.5(4) = 14° so temp after 8.5 minutes = 82-14 = 68°
*January 25, 2015*

**algebric exponents**

(3^x + 3^x + 1)/8 = (2(3^x) + 1)/8 = 2(3^x)/8 + 1/8 = (3^x)/4 + 1/8
*January 25, 2015*

**Parabola Ques**

Woaahhh! , that looks like a major assignment question. I will tell you what I would do if I had to actually do this. let P be (s,t) , but we know that y^2 = 4ax so t^2 = 4as s = t^2/(4a) so we can let P be (t^2/(4a) , t) from y^2 = 4ax 2y dy/dx = 4a dy/dx = 2a/y So the slope ...
*January 25, 2015*

**law of exponents**

See my reply to your other post http://www.jiskha.com/display.cgi?id=1422164761
*January 25, 2015*

**algebra**

I asked for a possible improper fraction, so I would leave it as a = 20/3
*January 25, 2015*

**College Trigonometry**

from the first: t = x/(vcosØ) from the 2nd: y = vsinØ(x/(vcosØ) - (g/2)(x^2/(v^2 cos^2 Ø) y = xtanØ - (gx^2)/(2v^2cos^2 Ø)
*January 25, 2015*

**College Algebra and Trigonometry**

Wow, 20 sheets of paper ? Since you titled your post "College Algebra & Trig" I will assume you know that both cos(π/4) and sin(π/4) = √2/2 so x = (√2/2)u - (√2/2)v and y = (√2/2)u + (√2/2)v In 5x^2 - 6xy + 5y^2 we will need...
*January 25, 2015*

**maths**

please retype we use x^2 for x squared, x^3 for x cubed etc What does ..... mean ? If you mean division, then use / for the division sign and place brackets in the correct positions
*January 25, 2015*

**Math**

The way I read it .... y = (x-8)^2 - 6 is the result if the parabola y = (x-1)^2 + 14 has been moved 7 units to the right and 20 units down, so the point (-3,30) went along for the ride, so (-3,30) ---> (4,10) check: old vertex = (1,14) new vertex = (8,-6) ---> 7 to the ...
*January 25, 2015*

**math**

let's assume you mean 2x^2 + 8x +3 = 0 since it does not factor, let's use the formula x = (-8 ± √40)/4 = (-8 ± 2√10)/4 = (-4 ± √10)/2
*January 24, 2015*

**math**

Suppose I change the question to ... "If 15 pencils cost 3 dollars, how many pencils can be bought for 90 cents?" I am sure you could do that question. Now simply replace the numbers you used with the p, d, and c and use the same operations in the same order.
*January 24, 2015*

**Math**

I think we must assume that the tower is in relatively flat plane. I don't know how well you can sketch 3-D diagrams, but mine has two right-angled triangles. One showing the first fire, has a base angle of 8° and a height of 50, so the distance of the fire from is: 50...
*January 24, 2015*

**Math**

#1 "How tall was the tree originally if the piece they chopped down was 7feet tall" ??? 7 ft tall ? #2 , x^2 = 5^2 + 3^2 = 34 x = √34 = appr 5.83 ft or 6 ft to the nearest foot
*January 24, 2015*

**Math**

I would "solve" the equation this way: 3 cot^2 x -1 = 0 cot^2 x = 1/3 tan^2 x = 3 tan x = ±√3 so x is in any of the 4 quadrants, x = 60° , 180°-60° , 180°+60° , 360°-60° = 60° , 120° , 240° or 300° in radians...
*January 24, 2015*

**Math**

A triple of numbers such as 5, 12, 13 is called a Pythagorean triple, because the satisfy the Pythagorean equation. The simplest such triple is 3, 4, 5 (3^2 + 4^2 = 5^2) and 5, 12, 13 is the next simple one. Of course any multiple of that triple would also work, e.g. 3 x (3, 4...
*January 24, 2015*

**combination probability**

Ok Let's assume that all the marbles are distinguishable , that is, I can tell any red apart from the other reds, etc Now lets "choose" 2 reds and 2 whites = C(18,2)*C(16,2) = 18360 Remember in those the order does not matter, and we can tell reds apart and ...
*January 24, 2015*

**combination probability**

Are you looking for the probability of drawing 2 reds and 2 whites when drawing any 4 marbles ? you could have 4!/(2!2!) ways or 6 ways for it to happen: RRWW WWRR RWWR RWRW WRWR WRRW prob of (RWRW) = (6/18)*(7/17)*(5/16)*(6/15) = (6*7*5*6)/73440 prob(WRRW) = (7/18)*(6/17)(*(5...
*January 24, 2015*

**Geometry ques**

We will need the equation of the tangent. y = tanx y' = sec^2 x when x = π/4 , tan π/4 = 1 so at the point (π/4,1) the slope is sec^2 (π/4) = 2 so equation is y = 2x + b at (π/4,1) 1 = 2(π/4) + b b = 1 - π/2 = (2-π)/2 tangent ...
*January 24, 2015*

**Paarabola Ques**

It has to be perpendicular to the tangent.
*January 24, 2015*

**Probability Ques**

what is whist?
*January 24, 2015*

**Algebra**

prove: (1 + 2 + 4 + . . . + 2n) + 1 = 2n+1 testing: if n = 1 , LS = (1) + 1 = 2 RS = 2(1) + 1 = 3 FAIL if n=2 , LS = (1 + 2) + 1 = 4 RS = 2(2) + 1 = 5 , FAIL again Hard to prove something which is not true check your spelling or the wording of the question. I don't know ...
*January 24, 2015*

**Add maths form 4**

done: http://www.jiskha.com/display.cgi?id=1422068863
*January 23, 2015*

**math**

Much Ado About Nothing. two ordered pairs (1950 , 2555360972) and (2000 , 6079006982) slope = (6079006982 - 2555360972)/(2000-1950) = 70472920.2 ---> m for N(t)= mt+b using the first point: 2555360972 = 70472920.2(1950) + b b = -1.348668 x 10^11 so we have N(t) = 70472920....
*January 23, 2015*

**Add maths**

recall that for ax^2 + bx + c = 0 , the sum of the roots = -b/a product of the roots = c/a we are given that the roots are r and 3r so from your equation of x^2 - 2qx + 2q+4 = 0 a = 1, b = -2q, c = 2q+4 r+3r = 2q/1 4r = 2q q = 2r r(3r) = 2q+4 3r^2 = 2(2r) + 4 3r^2 - 4r - 4 = 0...
*January 23, 2015*

**Math (factors and products)**

integral values are integer numbers, so k cannot be a fraction possible factors that end in +12: (x+1)(x+12) (x-1)(x-12) (x+2)(x+6) (x-2)(x-6)--> x^2 - 8x + 12 , so k = -8 (x+3)(x+4) (x-3)(x-4) I expanded one of them, to show one value of k You do the others
*January 23, 2015*

**math**

So we are looking for the between 3181+53 and 3181-53 or between 3234 and 3128 . best webpage for this stuff: http://davidmlane.com/hyperstat/z_table.html enter 3181 for mean enter 526 for sd click on between: enter 3128 and 3234 to get .0803
*January 23, 2015*

**algebra**

f(x)+g(x) = -5x - 4 + 6x - 7 = .....
*January 23, 2015*

**Algebra**

take out a common factor, then use grouping ... 3x^3 + 9x^2 - 3x - 9 = 3(x^3 + 3x^2 - x - 3) = 3( x^2(x + 3) - (x + 3) = 3(x+3)(x^2 - 1) = 3(x+3)(x-1)(x+1)
*January 23, 2015*

**algebra**

testing for 3 terms, (n=3) 1²/1 + (1²+2²)/2 + (1²+2²+3²)/3 = 1 + 5/2 + 14/3 = 49/6 for n = 3 a) --> (3/36)(36+45+17) = 49/6 b) --> (3/6)((4)(2) = 4 , noway! c) --> (9+9+29) = 47 , noway! suspicious it could be a) test for n = 2 sum(2) = 1...
*January 23, 2015*

**algebra**

try it yourselves, using the method I showed in your two other posts of this type
*January 23, 2015*

**algebra**

let's see if we find a pattern sum(1) = 4 sum(2) = 4+6 = 10 sum(3) = 4 + 6 + 9 = 19 sum(4) = 19+13 = 32 using a) the corresponding answers would be 4 10 19 32 mmmmhhh , looking good using b) the terms are -11/3 .... noway using c) the terms are 24 ... forget it! could it ...
*January 23, 2015*

**Math**

agree
*January 23, 2015*

**Math**

clarify if you meant it the way you typed it, or if you meant 4(1^(x/2) )^x remember that 1^anything = 1 so the way you typed it, it would simply become y = 4(1/2)^x if you meant: y = 4(1^(x/2) )^x , then we have y = 4(1)^x or simply y = 4
*January 23, 2015*

**maths**

if collinear, then their slopes must be equal (d-1)/-k = (1-1)/(1-k) = (1-d)/(1) (1-d)/k = 0/(1-k) = (1-d)/1 from the middle ratio we know that the slope = 0 and thus all numerators are 0 so 1 - d = 0 d = 1 similarly if the first and the last are equal, (1-d)/k = (1-d)/1 , ...
*January 23, 2015*

**maths**

recall that for any quadrataic in general form the sum of the roots is -b/a and the product of the roots is c/a let the roots be r and 3r so -b/a = 4r ---- b = -4ar and c/a = 3r^2 ---- c = 3ar^2 I will assume your b2/ac is supposed to be b^2/(ac) then b^2/(ac) = (16 a^2 r^2)/(...
*January 23, 2015*

**algebra**

Now = time(0) = 2 = 2^1 time(1) = 4 = 2^2 time(2) = 8 = 2^3 ... time(n) = 2^(n+1) then 2^(n+1) = 10million log both sides and use rules of logs (n+1)log2 = log 10million n+1 = log 10million/lon2 = 7/log2 = 23.25.. n = 22.25 after 23 months there will be more than 30 million
*January 23, 2015*

**Math**

It asks for miles per gallons or miles / gallons So which numbers go where?
*January 22, 2015*

**ignore my babble - Antiderivatives**

Just go with Steve's reply, ignore mine I read that -3 as an extra term
*January 22, 2015*

**Antiderivatives**

If you differentiate your answers, you certainly don't get back the original f(x), so you are clearly wrong your problem is the middle term -4x^-3 for simple single terms like this, here is how I go about it to integrate I write down the given term: -4x^-3 I then raise the...
*January 22, 2015*

**Math**

Maybe some culinary experts could enlighten me, but ... if you "double" the recipe, wouldn't you just double all the ingredients ?? Anyway, taking the wording at face value, you would need 1.3(1.5) cups of water or 1.95 cups of water
*January 22, 2015*

**math: ratios**

a) Kieran has 9 parts and Simon has 2 parts, so together they have 11 parts, So the ratio of Kieran's parts to the whole = 9parts : 11parts = 9 : 11 b) Kieran/total = 9parts/11parts = 9/11 c) Simon/total = 2/11 (notice 2/11 + 9/11 = 11/11 or the whole total) d) 9x -2x = 28...
*January 22, 2015*

**Math please, please help**

All your numbers can be changed to nice decimals 3/4 = .75 , 2 3/4 = 2.75 3 7/8 = 3.875 map1: .75 inch ---> 30 miles 1 inch -----> 30/.75 = 40 2.75 inches--> 40(2.75) or 110 miles map2: .5 inches -----> 10 miles 1 inches ------> 10/.5 = 20 miles 3.875 --------&...
*January 22, 2015*

**math**

Looking at your other post, I will assume that we are again talking about "simple interest" (in reality simple interest would not be used for any length of time greater than one year. As a matter of fact the method used above would result in a rate much higher than 6...
*January 22, 2015*

**Quadratics**

ummmh, y = 3(x+2)^2 + 5
*January 22, 2015*

**Math-polynomials**

correct expand to show that your are correct.
*January 22, 2015*

**math**

suppose we just define n to be an even number (that way I don't have to worry about the 2n idea) then the 4 consecutive even number are n , n+2, n+4, and n+6 (n+2)^2 = n(n+6) n^2 + 4n + 4 = n^2 + 6n 4 = 2n n = 2 so the 4 numbers are 2 , 4, 6, and 8
*January 22, 2015*

**Math**

term(7) = a+6d term(4) = a+3d a+6d - (a+3d) = 15 a+6d-a-3d=15 3d=15 d = 5
*January 22, 2015*

**maths**

#1: a+6d=3 #2: a+11d=-3 subtract them -5d = 6 d = -6/5 back into a+6d=3 a + 6(-6/5) = 3 a = 3 + 36/5 = 51/5 first three terms are: 51/5 , 9 , 29/5
*January 22, 2015*

**7th grade math**

First one is correct For the second, yes, you could have just subtracted the two. They actually gave you more information than was needed. Obtaining the same answer confirms that your answer is correct. The second question would have been nice had it been worded this way: If ...
*January 22, 2015*

**algebra**

4000(1.04)^n = 4800 1.04^n = 1.2 take log of both sides and use log rules n log1.04 = log 1.2 n = log 1.2/log 1.04 = appr 4.65 years
*January 22, 2015*

**Math**

correct --- x wrong ---- y , both x and y must be whole numbers x+y+2 = 20 x+y = 18 , #! 5x - 3y - 2 = 72 5x - 3y = 74 , #2 #1 times 3 --> 3x+3y=54 #2 as is -----> 5x - 3y = 74 add them 8x = 128 x = 16 back in #1 16+y=18 y = 2 a) he got 16 right, and 2 wrong, skipping 2 ...
*January 22, 2015*

**Math**

side of base of cuboid ---- x x^2 = 44 let the height be h x^2 h = 378.4 h = 378.4/44 = 8.6
*January 22, 2015*

**math**

I would pick b)
*January 22, 2015*

**Math**

#1, the key terms in each answer is the power term pick any two increasing values of x e.g. x = 2, y = 7^2 - 2 = 47 x = 3 , y = 7^3 - 2 = 341 Is there any reason for this pattern NOT to continue, so the function is INCREASING You will see the same for c) and d) Now look at b) ...
*January 22, 2015*

**math**

A good way is to take two pieces of graph paper and cut both of them into 8by8 square pieces It is easy to see that there is 1 large 8x8 square on a chessboard Now use one of the 2 pieces and cut it down to a 7x7 square template. Try placing this template on the 8x8 sheet (...
*January 22, 2015*

**probability**

The three mustaches can be used in 4 different ways, that is we could use any of the 3 of them or we could none at all in the same way the eyebrows can be used in 3 ways, the noses in 5 ways, and the set of ears in 2 ways. so the number of different makeups is 4x3x5x2 = 120 ...
*January 22, 2015*

Pages: <<Prev | 1 | 2 | 3 | 4 | 5 | 6 | **7** | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | Next>>