sketch a dotted line y = x-2 shade in the region above this line
I assumed you were on the x-y plane If you are just on a number line, put an open circle at x=3, then draw in the line to the left of that with an arrow at its end point.
draw a dotted vertical line at x = 3 Shade in the region to the left of that boundary line.
Steve, only 2 points were actually given. (3/2, 17/6) (3, 13/3) The others were (0, ??) (11/4, ??) So I could form a unique linear, but an infinite number of quadratics, cubics, etc that pass through those two points. Once I have an equation, the missing y values of the other ...
Your relation could be linear: using (3/2 , 17,6) and (3, 13/3) slope = (17/6 - 13/3)/(3/2 - 3) = (-3/2) / (-3/2) = 1 y - 13/3 = 1(x-3) 3y - 13 = 3x-9 3x - 3y = -4 now plug in the given input as x or the given output as y e.g input = x = 11/4 3(11/4) - 3y = -4 times 4 33 - 12y...
If you look on the can, it will probably give you either litres or gallons as its content, so clearly volume enters the picture. 44. none of the the choices suit the survey they are conducting. Something like this would make more sense: Check one or more of the following sport...
Math, please help
tanx cosx cscx = sinx/cosx * cosx * 1/sinx = 1 so the first one is an identity For questions like this, I use this trick pick a weird angle, e.g x = 13.79° If that weird angle satisfies your equation, it is "highly likely" that it is an identify. ( I know that it...
I will assume that your * means exponent In most typing notations we use the ^ to show exponents so your first would be (2z^3 - 3y^2)^5 you will have to know the expansion for (a+b)^n = a^n + C(n,1) (a)^(n-1) b + C(n,2) a^(n-2) b^2 + ... I will do the 2nd and last, you do the ...
Math: Differential Equations
if y'' = sinx then y' = -cosx + c given : 2= -cos0 + c 2 = -1 + c c = 3 y' = -cosx + 3 y = -sinx + 3x + k given: 0 = =sin0 + 0 + k 0 = 0 + 0 + k --> k = 0 y = -sinx + 3x you had that, you are done! you have it expressed in terms of x
TRIG help quickly please
2 cos (2x) - 1 = 0 cos (2x) = 1/2 2x = π/3 or 2x = 2π-π/3 or 5π/3 x = π/6 or x = 5π/6 none of the given answers apply I will assume you meant 2 cos^2 x - 1 = 0 by definition: 2cos^2 x -1 = cos (2x) so cos(2x) = 0 2x = π/2 or 2x = 3π/2 x ...
Math Check 2 ?s quick
first question is correct #2 should be true. sin^-1 (x) means find the angle Ø so that sinØ = x since the result of taking the sine is always a number between -1 and +1 then for sin^-2 (x) , your choice of x has to be -1 ≤ x ≤ 1 e.g try taking sin^-1 ...
from the first data: it has to be a multiple of 5 + 12, could be 17 22 27 32 37 42 47 ... from the 2nd data: it has to be a multiple of 6 + 1 , could be 7 13 19 25 31 37 43 .. ahhh, 37 is found in both , which is also Lila's answer. There were 37 choir members
Algebra 1 (Reiny)
I don't know if your name is Victoria, but here is her post with the same question as yours. I think my answer applies well here http://www.jiskha.com/display.cgi?id=1389322523
Math help me quicckly
arclength = rØ, where r is the radius, and Ø is the central angle in radians 30 = 15Ø Ø = 30/15 or 2 radians π radians = 180° so 2 radians = 2(180/π)° = appr 114.59°
yes, it has two equal sides and all angles are less than 90°
actually a rhombus, forgot about the 4 equal sides
sounds like the definition of a parallelogram.
a) --- up to you let the length of the side which is parallel to the highway be x , x < 640 let the length of the other two equal sides by y each x + 2y = 640 ---> y = (640-x)/2 = 320 - x/2 area = xy = x(320-x/2) = 320x - (1/2)x^2 so we need the vertex of this downwards ...
According to my diagram, h/445 = 10/45 h = 10(445)/45 = ...
length left over after 25% is cut off = .75(84) length of each of the 6 pieces = .75(84)/6 = 10.5 cm Are you not concerned about the loss due to all those cuts?
lotto next number 1/90
I have devised a method of picking the winning number, but it doesn't always work. The key thing is to pick the set of numbers that will win.
A line segment is formed by choosing any two points and joining them So it comes to C(10,2) = 10!/(8!,2) = 45
You have mismatched sets of brackets, that is, the number of right-sided brackets is not the same as left-sided brackets. I will assume there is one final at the end. -(2x-(5x+2)-2+(2x+7) ) = -(2x-5x-2-2+2x+7 ) = -(-x + 3) = x-3
remember we can only take logs of positive numbers, so x^2 + x + 2 > 0 If we consider the graph of y = -x^2 + x + 2, we have a parabola which opens downwards. So the domain of the original g(x) would be all those values of x for which the parabola is positive, that is, all ...
To be continuous, the two graph must be "linked" at x = 3 that is, x^2 - 1 = 2ax for x = 3 9-1 = 6a a = 8/6 = 4/3 so the two functions are f(x) = x^2 - 1 for x < 3 and f(x) = (8/3)x for x≥ 3 (note that (3,8) would be on both graphs, ignoring the restrictions)
f(g(x) = f(x+2) = (x+2)^2 or x^2 + 4x + 4 2. if g(x) = √x , domain of g(x) is all x ≥ 0 g(f(x)) = g(5x+7) = √(5x+7) whose domain is : 5x+7 ≥ 0 5x ≥ -7 x ≥ -7/5 3. by definition f^-1 (f(x)) = x so if x = a f^-1 (f(a)) = a let's illustrate...
interest earned = 1 million(1.02)^4 - 1 million
math for busness and finance
Paym(1.06^8 - 1)/.06 =40000 payment = 4000(.06)/(1.06^8 - 1) = $ 4041.44
for this GS a = 23 t(3) = ar^2 92 = 23r^2 r^2 = 4 r = ± 2 sum(n) = 62813 sum(n) = a(r^n - 1)/(r-1) 23(2^n -1)/1 = 62813 2^n - 1 = 2731 2^n = 2732 n log2 = log2732 n = 11.4 something wrong here, n has to be a whole number. check: for 11 terms, sum(11) = 23(2^11 - 1)/1 = ...
Original number of students = x original number playing = x/4 this year: number of students = x+6 number playing = x/4 + 4 x/4 + 4 = (1/3)(x+6) times 12 3x + 48 = 4x + 24 -x = -24 x = 24 So now there are x+6 or 30 students in the class
number = 298(1.08)^n , where n is the number of years so when n = 3 population = 298(1.08)^3 = appr 375
I will interpret (g f)(-3) as f(g(-3)) now g(-3) = -3 + 5/-3 = -14/3 then f(g(-3)) = f(-14/3) = 196/9 + 5 = 241/9 , none of your choices match If you meant g(x) = (x+5)/x repeating the above, I get 49/9 but that is not what you typed, but probably meant.
in general the x of the vertex is given by -b/(2a) = -7/-10 = 7/10
correct If your x's drop out and you end up with a false statement, such as our 6 = 7, then there is NO solution if, however, the x's drop out and you end up with a true statement, there would have been an infinite number of solutions.
The values that we need from Pascal's triangle are 1 5 10 10 5 1 (s+2v)^5 = s^5 + 5(s^4)(2v) + 10(s^3)(2v)^2 + 10(s^2)(2v)^3 + 5(s)(2v)^4 + (2v)^5 = .. I will leave the algebraic simplification up to you
I know that sin (π/6) or sin 30° = .5 so (π/4)(x-6) = π/6 or (π/4)(x-6) = π - π/6 = 5π/6 (in II) case 1 times 12 and divide by π 3(x-6) = 2 3x - 18 = 2 3x=20 x = 20/3 case 2 times 12 , and divide by π 3(x-6) = 10 3x - 18=10 3x =...
y= -4x - 2 Now, why could you not do this? All you had to do was to subtract the 4x and the +2 form both sides.
sort of hard to line numbers up nicely in this format, the .... represents spaces 1 | 1 -2 +2 ......... 1 ..-1 ..... 1 -1 1 so (r^2 - 2r + 2) ÷ (r-1) = r-1 + 1/(r-1) or r-1 with a remainder of 1
tickets sold by Minh --- x tickets sold by Jake --- 3x (notice x : 3x = 1 : 3) So number of tickets sold by Zoe = 4x 4x - 36 = x 3x = 36 x = 12 total tickets = x+3x + 4x = 8x or 96 money collected = 96($2) = $192
at each drainage even we are taking out 1/4 of the current mixture and replacing it with 5 L of pure antifreeze, leaving 3/4 of the previous mixture after 1st drainage: amount of antifreeze =5 L after 2nd drainage: amount of antifreeze = (3/4)(5) + 5 = 8.75 L after 3rd drainag...
In my diagram , I arbitrarily let the radius of the cylinder be 1 unit let the radius of the cylinder be r , and let the height of the cylinder be 2h That way I can say: r^2 + h^2 = 1 r^2 = 1 - h^2 or r = (1- h^2)^(1/2) Surface area (SA) = 2πr^2 + 2πrh = 2π(1-h^...
I did not get this sinx = 2/3, then cosx = √5/3 if secy = 5/3, then cosy = 3/5, and siny = 4/5 sin(x+y) = sinxcosy + cosxsiny = (2/3)(3/5) + (√5/3)(4/5) = (6 + 4√5)/15 Your individual trig values are correct, you must have made a substitution error.
Anyone want to help me?
did you mean s=6r^(5t) or s=6r^5t , the way you typed it. I will take it the way you typed it. t = s/(6r^5)
yes, you are correct
Algebra 2 help...
amount = 487 (1/2)^(t/36) where t is the number of days. if t = 5 amount = 487(.5)^(5/36) = 442.302 kg
d/20+1=d/24+ 1 1/4 d/20+1=d/24+ 5/4 times 120 , the LCD 6d + 120 = 5d + 150 d = 150-120 = 30
your error is in the 3rd last line from : 10 - 5b = 20 -5b = 10 b = -2 btw, why didn't you sub back into 2a + b = 3, it would have been easier. Also , it is not a good idea to sub into an equation that you have altered, try going back into the easiest-looking of the origin...
3x - 9y = 3 6x - 3y = -24 from the first, divide by 3 x - 3y = 1 x = 3y+1 sub into the 2nd 6(3y+1) - 3y = -24 18y + 6 - 3y = -24 15y = -30 y = -2 then x = -6+1 = -5 for the 2nd system, multiply the 1st by -4 2x -4y = -24 2x + 6y = 19 subtract them 10y = 43 y = 43/10 = 4.3 into...
Calc and Vectors
looks like for each $5 decrease in the price, the attendance rises by 2000 let the number of $5 decreases be n the price of a ticket = 60-5n attendance = 18000 + 2000n revenue = (60-5n)((18000+2000n) factoring .... = 5(12-n)(1000)(18 + 2n) = 5000(12-n)(18+2n) = 5000(216 + 6n -...
Calc and Vectors
It could have yielded a minimum value, and there is no maximum value. setting the derivative equal to zero and solving for x, gives you the x where either a maximum or a minimum occurs.
" When he multiplies this number by 6 and then subtracts 15 from the answer, he ends up with his original number." -----> 6x - 15 = x easy to solve for x
oops - math
Steve, looks like you should have had that early morning coffee. from p + 12 > 9 p+12 - 12 > 9 - 12 p > -3
2nd one: x/4- 8 = 16 - (3/4)x multiply each term by 4 , the LCD x - 32 = 64 - 3x 4x = 96 x = 96/4 = 24 1st one is even easier, give it a try.
What's with the >.< are these supposed to be in-equations? Tell me before I do them
let f(x) = x^4+3x^3+3x^2-3x-4 f(1) = 1 + 3 + 3 - 3 - 4 = 0 f(-1) = 1 - 3 + 3 + 3 - 4 = 0 f(0) = -4 ≠ 0 f(2) = ..... ≠ 0 so what do you think?
as two equal parts 9/8 + 9/8 = 18/8 = 9/4 as three equal parts, 3/4 + 3/4 + 3/4 = 9/4 9/8 + 9/8 = 2(9/8) = 9/4 3/4 + 3/4 + 3/4 = 3(3/4) = 9/4
Dont get this question..
zeros of a function are those values of x which make y = 0 that is, where does the graph cross or touch the x-axis The ideal expression has the function in factored form, we have that already, so it is easy Just set each of the factors equal to zero and solve e.g. x-3 = 0 x = ...
Algebra 2 help!
which pair works in both equations ? (all pairs work in the 2nd equation, but not in the 1st)
Of course you have to know that i^2 = -1 so (-5i)(-3i) = 15i^2 = 15(-1) = -15
try making a sketch make the 70's opposite each other, and the 110' opposite each other. What do you notice? Is it possible to have the two 70's adjacent to each other?
Algebra help please!
same thing as x^2 - 5x + 3 = 0 x = (5 ± √13)/2 which is the same as a)
let the amount of the more expensive mix be x pounds then the amount of the cheaper mix has to be 60-x pounds .80x + .65(60-x) = .70(60) times 100 , (I don't like decimals) 80x + 65(60-x) = 70(60) 80x + 3900 - 65x = 4200 15x = 300 x = 20 Use 20 pounds of the expensive kind...
Algebra 1 (Reiny)
in general if you have y > mx + b, you would shade in the region above the line y = mx + b y < mx + b , you would shade in the region below the line y = mx + b if the inequality contains ≥ or ≤ , the would include the boundary line itself and make it solid if...
Algebra 2 help!
then, as I said before, x = (5 ± √-19)/2 none of the choices match, that's all there is to say.
Algebra 2 help!
first make the equation more presentable .... x^2 - 5x + 11 = 0 x = (5 ± √-19)/2 none of the answers match this, so there has to be a typo. since all answers contain √13 your equation could have been x^2 - 5x + 3 = 0 that would give you x = (5 ± ͩ...
for x^2 + bx + .... take 1/2 of the coefficient of the x term, in your case 1/2 of 16 is 8 now square that , in your case 8^2 = 64 so you would add 16 to make it into a perfect square test: x^2 - 16x + 64 = (x-8)^2 yup, it works.
let the tens digit be x then the unit digit is x-4 the number itself is 10x + (x-4) sum of the digits is x + x-4 = 2x - 4 10x + x-4 = 9(2x-4) -3 11x-4 = 18x - 36 - 3 -7x = -35 x = 5 tens digit is 5, unit digit is 1 the number id 51
I did this for you before guessing what you might have meant. Tell me what b , c, and Ø are before I attempt it again.
Actually none of them do the constants were completely ignored in all the choices. You would want what is called the "augmented" matrix -10 -9 13 12 8 -7 -5 15 5 4 -6 -12 btw, the elements of a matrix are not separated by commas
let the tens digit of our number be x let the unit digit be y so the number is 10x + y sum of its digit = x+y 10x + y = 7(x+y) - 3 3x - 6y = -3 , #1 the number reversed is 10y+x 10y+x = 10x+y - 18 9y - 9x = -18 y - x = -2 y = x-2 sub this into #1 3x - 6(x-2) = -3 -3x = -3-12 x...
make a sketch, notice the 2 given points form a horizontal line, and has length 14 So the other side must be a vertical line let the point below (4,5) be (4,y) then (5-y) + 14 = 22 y = -3 So the point below (4,5) is (4,-3) and the point below (-10,5) is (-10, -3) the point cou...
I will do the last one, you do the others the same way point is (6,-2) line is y = -3x - 6 slopes of perpendicular lines are negative reciprocals of each other. So the new line is y =(1/3)x + b sub in the given point -2 = (1/3)(6) + b -2 = 2 + b -4 = b new equation: y = (1/3)x...
we could write n*0 as n(5-5) which is 5n - 5n = 0 for all values of n
Try this on your calculator 5/.01 = .. 5/.00001 = 5/.0000001 = notice I am making my divisor smaller and smaller, almost zero and what is happening to your answer? The closer my divisor gets to zero, the larger the answer. So when I could actually divide by zero, then the answ...
since tangent is negative in II and IV and the sine is negative in III and IV , our angle Ø must be in quadrant IV so using our given tanØ = -8/5 y = -8, x = 5 and r^2 = 64+25 = 89 r = √89 sinØ = y/r = -8/√89 cosØ = x/r = 5/√89 csc...
for h2, the height from the base to the top of the flag: h2/34 = tan 48.6° h2 = 34tan48.6° = .. for h1, the height to the bottom of the flag h1/34 = tan 44.6° h1 = 34tan44.6° h2-h1 = 5.1 (this information is not needed when I calculate h2 - h1, I get 5.04 , not...
4! means 1x2x3x4 = ....
rational and irrational
no, .3π is not rational since π is irrational, any multiple of π such as .3π is also irrational. (I don't understand what the 67/79 , 75 pi,0.3 pi,13 pi is supposed to be )
let the rise be 2x , and the run be 5x, then the hypotenuse is 1320 (2x)^2 + (5x)^2 = 1320 29x^2 = 1320 x^2 = 1320/29 x = √(1320./29) = appr 6.74665 rise = 2x = appr 13.5 ft run = 5x = appr 33.7 ft don't know what your b and c refers to , but I am sure you can match ...
Your first answer is correct. the second: prob(nickel, then penny) = (4/10)(1/9) = 4/90 = 2/45
I read that as 4x + 16 = x^2 - 2x x^2 - 6x - 16 = 0 (x-8)(x+2) = 0 x = 8 or x = -2
9 times "What" = 27 What = 27/9 = 3
let the number of prints be n so cost of prints = .19n cost of subscription = 5.95 so .19n + 5.95 = 15.83 .19n = 9.88 n = 9.88/.19 = 52 So .....
How about this? let a = 2, and b = 2 then a^2 - b^2 = a-b (a+b)(a-b) = a-b divide both sides by a-b a+b = 1 then 2+2 = 1 and 4 = 1 nice , eh?
2+2 = 5 for relatively large values of 2.
If the 9th term of an AP is 0 , then a+8d = 0 a = -8d 29th term = a + 28d = -8d + 28d = 20d 19th term = a +18d = -8d + 18d = 10d since 20d = 2(10d) the 29th term is twice the 19th term
Math - Check my answer?
Again, I am not crazy about your second line, since you are solving equations, I don't see one. I suggest this if you have to show your steps -6q + 5.8 = 23.8 -6q + 5.8 - 5.8 = 23.8 - 5.8 -6q = 18 -6q-6 = 18/-6 q = -3
Math - Help!!
I don't like the presentation of your second line, but you last two lines are good If you want to show all your steps, I prefer this: 7x/8 = 21 (7x/8)(8) = 21(8) 7x = 168 7x/7 = 168/7 x = 24
Math - Help!!
multiply each side by 8 7x = 168 divide both sides by 7 x = 168/7 = 24
Check my answer?
I would give it as 88.89% to the nearest hundredth of a percent
1260 = 2x2x3x3x5x7 so their sum is .... ?
looks like an arithmetic sequence with a = 3 d = 4 term(n) = 439 a + (n-1)d = 439 3 + (n-1)(4) = 439 4n - 4 = 436 4n = 440 n = 110 there are 110 terms
just use a simple ratio .... 5/2 = h/8 h = 8(5/2) = 20
math(please check answers)
I disagree with #7 (5/20) ÷ (1/7) = (1/4)(7/1) = 7/4 or 1 3/4 none of your choices match this. #9, how did you get 6 rooms ? If he takes 1 hour to clean one room, wouldn't it take him 6 hrs to clean the house?
You have a couple of typos. I will assume you meant f(x) = √(x^2-1) and g(x) = √(x-1) then f(x)/g(x) = √( (x^1-1)/(x-1) ) = √( (x+1)(x-1)/(x-1) ) = √(x+1) , for all x > -1 Since you didn't supply the choices they gave you ..... btw, the way...
so we are doing: (x,y) --->(x-1, y+3) ----> (x+4, y-1) so for R(-2,-2) (-2,-2) --->(-3, 1) ----> (1, 0) do the same for the other points (I am not sure why you have quotations around S and T in the final result. Are you saying that only S and T are transformed? If ...
No, both direct, the variable is in the numerator. I wrote it the way I did, to point that out to you. Notice that to be an inverse variation, the variable must be in the denominator.
suppose I write c = e/-4 as c = (-1/4) e and u = l/18 as us = (1/8)l now what do you think?
(same as diameter halved, anyway ....) original: radius r, height h surface area = 2πrh + 2πr^2 = 956 πrh + πr^2 = 478 h = (478-πr^2)/(πr) for new cylinder, height = h, radius = r/2 volume = π(r^2/4)(478-πr^2)/(πr) = (478r - πr...