Friday

December 19, 2014

December 19, 2014

Total # Posts: 28,255

**geometry**

Go with MathMate, I misread the question
*November 26, 2014*

**geometry**

All angles in the equilateral triangle are 60° In the isosceles triangle the two base angles are 73 ° each ......... ( (180-34)/2 ) so angle ABD = 60+73 or 133°
*November 26, 2014*

**Trig**

1. can't see your diagram but will assume that the angle of 35° is between the two given sides, so ... R^2 = 98^2 + 55^2 - 2(55)(98)cos 145° 2. "each" vector ? , what vector 3. a = <9,8> b = <-8,7) a dot b = |a| |b| cosØ -72 + 56 = √...
*November 26, 2014*

**analytic**

duplicate post, see your other post
*November 26, 2014*

**analytic**

slope of first line = m1 = (6-9)/(2-1) = -3 slope m2 = (5-3)/(3+1) = 1/2 if Ø is the angle between them: tanØ = (m2-m1)/(1 + m2m1) = (1/2 - 3)/(1 + (1/2)(-3)) = (-5/2) / (-1/2) = 5 Ø = 78.7° to the nearest tenth
*November 26, 2014*

**Statistics**

z score = (your data value - mean)/sd I will do the first and fourth, follow the same procedure for the others 68, ? z = (68-70)/8 = -2/8 = -.25 ? 1.8 1.8 = (x - 70)/8 multiply by 8 14.4 = x-70 add 70 84.4 = x notice the z value may be ± but your data value must be ...
*November 26, 2014*

**Math**

10/12 = 50/60 = 25/30 = ... just multiply the numerator and denominator by the same non-zero constant e.g (5/6)*(2/2) = 10/12 etc
*November 26, 2014*

**Trig**

2csc^2x-8=0 csc^2 x = 4/2 = 4 then sin^2 x = 1/4 sinx = ±1/2 ---> so x can be in any of the 4 quads we know sinπ/6 = 1/2 so x = π/6 x = π - π/6 = 5π/6 x = π + π/6 = 7π/6 x = 2π - π/6 = 11π/6
*November 25, 2014*

**Trigonometry**

sin^2 x = 3/4 sinx = ±√3/2 I know sin 60° = √3/2 or sin π/3 = √3/2 so x = π/3, 2π/3 , 4π/4 , 5π/3 2 tan^2 x = √12 = 2√3 tan^2 x = √3 now you should know the trig ratios of the 30-60-90 triangle. once you ...
*November 25, 2014*

**Brief Calculus**

look at the graph first. http://www.wolframalpha.com/input/?i=plot+y+%3D+e%5Ex%2C+y+%3D+2x%2B1%2C+-2+to+1 I is obvious that y = e^x and y = 2x+1 intersect at the y-axis at (0,1). there is another intersection but it beyond x = 1, so of no concern to us So area = ∫ (e^x...
*November 25, 2014*

**Geometry**

In the actual case they had 18° So in the general case they now have x° So let's do exactly the same thing So if we have n sides and the exterior angle is x° then the interior angle is 180-x So (180-x)n = (180)(n-2) 180x - nx = 180n + 360 solving for n: 180x - ...
*November 25, 2014*

**math show work please**

Did you notice that x^2 + 8x + 15 = (x+3)(x+5) which happen to be the denominators on the left side So let's multiply everybody by (x+3)(x+5) (x+5) + 4(x+3) = 2 Now how easy is that from there ?
*November 25, 2014*

**math show work please**

1 - 11/x + 30/x^2 = 0 times x^2 x^2 - 11x + 30 = 0 (x-5)(x-6) = 0 x = 5 or x = 6
*November 25, 2014*

**calculus**

s = (3+6t)^(1/2) v = (1/2)(3+6t)^(-1/2) (6) = 3(3+6t)^(-1/2) a = (-3/2)(3+6t)^(-3/2) (6) = -9(3+6t)^(-3/2) when t = 1 a =-9(9)^(-3/2) = -9(1/27) = -1/3 you are correct!
*November 24, 2014*

**trig**

Oh my! I know that cos π/3 = 1/2 and cos π/6 = √3/2 (What is the matter with me ? )
*November 24, 2014*

**trig**

1. 4cosx = 2 cosx = 2/4 = 1/2 I know cos π/6 = 1/2 , so x = π/6 but the cosine is positive in quadrants I or IV so x is also 2π- π/6 = 11π/6 #2 sec^2 = 4/3 1/cos^2 x = 4/3 cos^2 x = 3/4 cos x = ± √3/2 so x could in any of the 4 quadrants ...
*November 24, 2014*

**MATH**

I got 12 Make a Venn diagram consisting of two intersecting circles, one called M, the other called L Put a rectangle around the circles. place 5 in the intersection of M and L since M contains 18 , but 5 are already written down, place 13 in the M only part of the circle. ...
*November 24, 2014*

**Math**

What is 10000(1.01)^72 ?
*November 24, 2014*

**calculus**

dy/dx = 2x - 6 = 0 for horizontal tangent 2x-6 = 0 2x=6 x = 3 , which is choice a)
*November 24, 2014*

**algebra**

ratio of x and y coefficient of first = 2 : 5 ratio of x and y coefficients of 2nd = 4 : 10 = 2:5 but the constants are not in that ratio, so you have two parallel lines
*November 24, 2014*

**Math**

This is my interpretation of the question: R-- right W -- wrong there are 8 ways for the selection to take place (or there are 2 ways to pick the first cheese, right or wrong, 2 ways to pick the 2nd, and 2 ways to pick the third: 2x2x2=8 ) WWW WWR ** WRW ** WRR RWW ** RWR RRW ...
*November 24, 2014*

**math**

let the acceleration be a , (I expect a to be negative) v = at + c when t = 0 , v = 8 8 = 0+c ---> c = 0 so v = at + 8 when t = .36, v = 0 0 = a(.36) + 8 a = -8/.36 = appr -22.2 m/s^2
*November 24, 2014*

**Precalc 2**

Can't see your diagram, but it looks like a straightforward cosine law R^2 = 1600^2 + 3200^2 - 2(1600)(3200)cos 135° R = ....
*November 23, 2014*

**Math (trigonometry)**

1. angle A = 180-17.9-108.1 = 54° now by the sine law: AB/sin17.9 = 472/sin54 AB = 472sin17.9/sin 54 = .... 2. (9,2)dot((-3,3) = √85√18cosØ , where Ø is the angle between them (-27 + 6)/(√85√18) = cosØ I got Ø = 122.5°...
*November 23, 2014*

**Calculus**

Of course ! For some reason I was thinking x = 0. Ignore my silly comment , ( I will blame it on "old-timers syndrome" )
*November 23, 2014*

**Calculus**

What about the constraint of y = 0 wouldn't that restrict the volume to the part on the left of the y-axis ? and using washers, we would get only v = π∫[-2,0]((2-x)-(-2x)) dx = 2π
*November 23, 2014*

**mathematics of investment**

I = PRT 8000(.09)T = 180 T = .25 years or 91 days I will leave it up to you to calculate what date that is
*November 22, 2014*

**Math**

counting the first bounce at up and down ... we have 144 + 144(2/3) + 144(2/3)^2 + ... which is an infinite geometric series where a = 144 , r = 2/3 sum(all terms) = a/(1-r) = 144/(1-2/3) = 144/(1/3) = 432 cm
*November 22, 2014*

**Maths**

then (3x+10)/(7x) = 6:7 42x = 21x + 70 21x=70 x = 70/21 = 10/3 so the number of reds originally was 3(10/3) = 10 the number of blues originally was 7(10/3) = 70/3 ????? how can we have partial balls ? I think there is something very wrong with your question. notice that "...
*November 22, 2014*

**Maths**

original red --- 3x original blue --- 7x number of reds added -- a number of blues added -- 10-a (3x+a)/(7x + 10-a) = 6/7 42x + 60 - 6a = 21x + 7a 21x - 13a = -60 I think you have something missing in your problem, maybe a typo We have to know how the 10 balls are distributed ...
*November 22, 2014*

**Math Check please**

your equation of c = 36/d^2 is correct so your constant of proportionality is 36 (your k value) now just plug in d = 5 c = 36/25 or 1.44
*November 21, 2014*

**Math**

the diagram looks rather routine draw the smaller building and mark is as 12 m high draw the other building a bit taller . draw a horizontal from the smaller to the taller, label the difference in height as x draw in your cable, Don't you have a right-angled triangle with ...
*November 21, 2014*

**Math**

(4^x)-(2^x)=56 (2^2)^x - 2^x - 56 = 0 (2^x)^2 - 2^x - 56 = 0 let 2^x = t , we get t^2 - t - 56 = 0 (t-8)(t+7) = 0 t = 8 or t = -7 if t = -7 2^x = -7 , no such x exists or if t = 8 2^x = 8 -----> x = 3
*November 21, 2014*

**Math**

3^(2c+1)=28*(3^c)-9 3^(2c)*3^1 = 28*3^c - 9 3(3^c)^2 - 28(3^c) + 9 = 0 let 3^c = x 3x^2 - 28x + 9 = 0 (3x - 1)(x - 9) = 0 x = 1/3 or x = 9 if x = 1/3 3^c= 1/3 = 3^-1 -----> c = -1 if x = 9 3^c = 9 = 3^2 ----> c = 2
*November 21, 2014*

**Math**

a) is correct b) since the S and L are defined variables, taken the inverse in the usual way changes their definitions. We could just follow the usual steps ... if S = 2√(5L) , the inverse is obtained by interchanging the variables, so inverse is L = 2√(5S) we ...
*November 21, 2014*

**Math Question**

-1500/360 = -4 with a remainder of -60° So we would have 4 clockwise rotations with and angle of 60 into quadrant IV
*November 21, 2014*

**Math**

f(f(x)) = f(6/(5+x) ) = 6/(5 + 6/(5+x) ) = 6/( (25+5x+6)/(5+x) ) = (30 + 6x)/(31 + 5x) = g(x) let y = (30+6x)/(31+5x) inverse is : x = (30+6y)/(31+5y) 31x + 5xy = 30 + 6y 5xy - 6y = 30 - 31x y(5x - 6) = 30-31x y = (30-31x)/(5x-6) = g^-1 (x)
*November 21, 2014*

**Math**

81^x = 64 log 81^x = log 64 x log81 = log64 x = log64/log81 27^(log64/log81 + 1) = 610.940...
*November 21, 2014*

**typo - Algebra**

forgot the zero in the first line , should read: as x is hugely negative, 2*51^x ----> 0
*November 21, 2014*

**Algebra**

as x is hugely negative, 2*51^x ----> so f(x) ----> 3 - 0 or 3 as x becomes hugely positive -2*51^x --->- ∞ do the range is y < 3 I will let you use whatever notation you have learned
*November 21, 2014*

**Math**

P(1.04)^10 = 5000 solve for P
*November 21, 2014*

**Math**

Rachel, Rachel ! Since both Damon and I went farther than the question asked for and also found the value of a .... all you needed is r = 1/2 (the value of a indeed has √2 in it, but your teacher was not referring to a but rather to r . Note we both had that √2 in ...
*November 21, 2014*

**Math**

ahh, so we have two ordered pairs (2,1) and (32, 4) that satisfy our equation ----> 1 = a(2)^r ----> 4 = a(32^r a(32)^r = a(2)5r so a(2)5r = 4 and a(2)^r = 1 divide them 2^(5r-r) = 4 2^4r = 2^2 then 4r = 2 r = 1/2 back into the first: a(2)^(1/2) = 1 a√2 = 1 a = 1...
*November 21, 2014*

**Math**

where does r come in ? did you mean , find a ?
*November 21, 2014*

**Algebra Help please!**

amount owing at 12% compounded annually in 4 years = 6000(1.12)^4 = 9441.12 amount owing at 12% per annum compounded quarterly in 4 years = 6000(1.03)^16 = 9628.24 Now subtract them as Henry told you to do.
*November 21, 2014*

**math please help!!!!!**

Since you are telling me that 4i = k then f(x)=x^3+(12-4i)x^2+(32-48i)x-128i =x^3 + (12 - k)x^2 + (32 - 12k) - 32k and since k is a zero, then (x - k) is a factor by synthetic division: f(x)=x^3+(12-4i)x^2+(32-48i)x-128i = (x-k)(x^2 + 12x + 32) = (x - 4i)(x^2 + 12x + 32)
*November 21, 2014*

**Algebra 2**

I will assume that you have (√5 + i)/(√5 - i) those brackets are absolutely essential. I will also assume that you want this rationalized. (√5 + i)/(√5 - i) = (√5 + i)/(√5 - i) * (√5+i)/(√5 + 1) , I am merely multiplying by 1, ...
*November 21, 2014*

**Math Help!!!**

If you meant √-75 , then you can't have a real number thus to ask for the nearest integer would be silly So you must have meant -√75 = -8.66025... = -9 to the nearest integer (look at the number on a number line)
*November 21, 2014*

**Math**

Brackets are essential here .... h(x) = (3x+2)/(7x-6) or y = (3x+2)/(7x-6) step 1 of finding the inverse is to interchange the x's and y's x = (3y + 2)/(7y - 6) 7xy - 6x = 3y + 2 step 2 : solve this for y 7xy - 3y = 6x + 2 y(7x - 3) = 6x + 2 y = (6x + 2)/(7x - 3) , ...
*November 21, 2014*

**Algebra 2**

from the type of problem that you posted, you surely MUST know how to solve quadratic equations. Steve took you as far as 5x^2 - 16x + 6 = 0 and made the same assumption I made. I suggest using the quadratic formula. (you will get two irrational answers)
*November 21, 2014*

**MATH**

proceed this way: f(g(x)) = f(2x^2 - 1) = 2/(2x^2 - 1) test it for some number e.g. let x = 3 g(3) = 18-1 = 17 f(g(3)) = f(17) = 2/17 in my answer: 2/(2x^2 - 1) = 2/17 This does not 'prove' that my answer is correct, but there is high probability that it is. Had my ...
*November 21, 2014*

**math**

old rate --- $x new rate --- $ x+2 wage per week at old rate = $ 32x wage per week at new rate with more hours = 40(x+2) 40(x+2) - 32x = 200 easy to solve
*November 20, 2014*

**Math Help**

Think about it .... if perimeter of little square is 16, each side is 4 for the larger, each side is multiplied by 7, or , each side is 28 so perimeter of larger is .....
*November 20, 2014*

**algebra. help!**

How can I check your work if you did not supply any of your choices
*November 20, 2014*

**math**

your solution is correct to check, you must go back to the original equation LS = log4 (19-3) = log 4 (16) = 2 -----> what must be exponent on 4 to get 16 ? = RS so x = 19
*November 20, 2014*

**Math**

Let his original number of pens be x then his original number of pencils is 30 - x So for every pen he gets 2 pencils so x pens will yield him 2x pencils but he already had 30-x pencils, so 2x + 30-x = 48 x = 18 So, originally he had 18 pens and 12 pencils check: 12+18 = 30 , ...
*November 20, 2014*

**math**

of course not distribute ... -36 - 6x - 6x - x^2 = .... add like terms
*November 19, 2014*

**math!!!!!!**

just distribute ... x(x+y+2) = x^2 + xy + 2x
*November 19, 2014*

**Algebra**

I will assume you mean (1/25)^(x+2) = 125^-x or else we got ourselves one doosey of a problem (5^-2)^(x+2) = (5^3)^-x 5^(-2x-4) = 5^(-3x) then -2x-4 = -3x x = 4
*November 19, 2014*

**Algebra**

m-7 < 6 add 7 to both sides, (just like you would for an equation) m < 13 Do the other two the same way
*November 19, 2014*

**math**

P(1 + .07/4)^28 = 30000 solve for P
*November 19, 2014*

**math!**

GCD(722,2413) = 19 then GCD(19,209) = 19 so GCD(722,2413,209) = 19
*November 19, 2014*

**Algebra Help! Please**

Did you not read the 3 conditions I outlined for you? Especially this one: "- if the variable drops out, and you get a true statement, there will be an infinite number of solutions " so you got 0=0, which is true, thus there will be an infinite number of solutions
*November 19, 2014*

**ALGEBRA Help Please**

1st: 2(x-3) = 2x 2x - 6 = 2x -6 = 0 -----> contradiction, thus no solution 4th: 4(x+3) + 2x = x - 8 4x + 12 + 2x = x - 8 5x = -20 x = -4 -----> One solution in general - if you get ?x = ? , there will be one solution - if the variable drops out, and you get a true ...
*November 19, 2014*

**Math**

#1, you can decide for yourself if (-5,-1) is correct by subbing in those values into both equations. You should be able to do this mentally. -- A quick mental calculation shows that your answer does not work in either equation from the 2nd: x = 2y + 10 plug that into the 1st...
*November 19, 2014*

**MATH HELP**

When testing if a number is prime, you would only try primes as divisors until you reach the last prime < √(the number) e.g. is 71 prime try: 2, 3, 5, 7 none divided exactly, so 71 is prime (did not have to go for 11 , since 11 > √71 so for 1881 ... √...
*November 19, 2014*

**maths**

Once around is one circumference. The circumference of a circle is 2πr or πd, d the diameter. So 5 times around would be ...... Plug in your values
*November 19, 2014*

**math**

I assume you meant to say, " ... travels 180 cm farther than ... " let the distance to the point of the minute hand be r cm In one hour the minute hand has gone around one rotation or 2πr in one hour the 'hour hand' has gone (1/12)(2π60)) or 10π...
*November 19, 2014*

**Maths**

Take a sheet of printer paper and try it. Doesn't the circumference of your tube equal the long side ? So.... 2πr = 20 r = 10/π
*November 19, 2014*

**Math- Combinations**

You are choosing 4 from 19 = C(19,4) = 19!/(15!4!) = 3876
*November 18, 2014*

**Math**

correct
*November 18, 2014*

**Math**

Retype in English please, and tell me what C is.
*November 18, 2014*

**AP CALC**

let the point of contact on the cosine curve be (x,y) So the perimeter of the rectangle = P = 2x + 2y = 2x + 2cos 2x dP/dx = 2 - 4sin 2x = 0 for a max/min of P 4sin 2x = 2 sin 2x = 1/2 I know sin π/6 = 1/2 so 2x = π/6 x = π/12 then y = cos π/6 = √3/2 ...
*November 18, 2014*

**algebra**

Let Jena time alone be x hrs let Cindy's time alone be 2x hrs let the two rates be 1/x and 1/(2x) combined rate = 1/x + 1/(2x) = 3/(2x) 1/(3/(2x)) = 10 2x/3 = 10 hrs = 2x = 30 or x = 15 Jena will take 15 hrs to do the house alone
*November 18, 2014*

**ap calc**

There are many variations of this same question,. Hint: let TP = x then OP^2 = x^2 + 64 OP = (x^2 + 64)^(1/2) I think you are missing the length of TR, we need that to find PR Just for arguments sake, lets say TR = 12 miles then PR = 12-x cost = 90000(x^2+64)^(1/2) + 54000(12-...
*November 18, 2014*

**ap calc**

Your graph looks like a W and I assume you want the rectangle placed inside the centre part. Let the two other vertices be (x,y) and (-x,y) So the length is 2x and the height is y Area = 2xy = 2x(x^4 - 2x^2 + 1) = 2x^5 - 4x^3 + 2x d(area)/dx = 10x^4 - 12x^2 + 2 = 0 5x^4 - 6x^2...
*November 18, 2014*

**sixth grade ratios and rates**

Here is another way of looking at Morgan's solution. Morgan found the percentage to be 25% or 1/4 of the marbes are blue. So 1/4 of Jasper's marbles must be blue , it said they have the same percentage of blue marbles. Let the total of Jasper's marbles be x then (1...
*November 17, 2014*

**Math**

f(x)= -x^2 + 2x = -1(x^2 - 2x +1 - 1 ) = -( (x-1)^2 - 1) = - (x-1)^2 + 1
*November 17, 2014*

**college, math**

If I were Sears I would sue the publisher of this textbook for associating their name with such a fraudulent practice . Anyway, according to this criminal plan .... cost after sales tax = 1656.9 "add-on interest" = 1656.90(.12)(3) = 596.484 amount to be "...
*November 17, 2014*

**algebra**

let's just plug in t = 10 T(10) = 65 + 115 e^-.42 = 140.56 = 141° to the nearest degree. b) we want 110 = 65 + 115 e^(-.042t) e^(-.042t) = (110-65)/115 = .391304... take ln of both sides -.042t = ln .391304.. t = 22.34 minutes or 22.3 minutes
*November 17, 2014*

**math**

x^2 = (-16 ± √196)/10 = (-16 ± 14)/10 x^2 = -1/5 or x^2 = -3 x = ± i/√5 or x = ± √3 i All four roots are imaginary
*November 17, 2014*

**Math**

only x= 0 so y= 0 x= 1 so y= -3 is correct, the others are not Perhaps, if you show how you are doing the calculations, I can see where you are going wrong. I will do one for you ... if x = -4 y = (-4)^2 - 4(-4) = 16 + 16 = 32
*November 17, 2014*

**Math**

So this question is essence establishes the quadratic equation formula hint: give yourself an equation such as 3x^2 + 12x + 2 = 0 and whichever step you perform on this equation, do the same thing for a parallel solution to ax^2 + bx + c = 0 Of course you know what you are ...
*November 17, 2014*

**Algebra Work Check**

correct or (x^2+4)(x^2-4) = 0 x^2 + 4 = 0 --> no real solution or x^2 - 4 = 0 (x+2)(x-2) = 0 x = ±2
*November 17, 2014*

**Pre-Calc/Trig**

let f(x) = 5x^3 - 119x^2 - 10x + 16 now try some f(x) , where x = ±1, ±2, ±4, ±8 ... hopefully to get a zero took some some, but f(8) = 0 so (x-8) will be a factor now by synthetic division , I got 15x^3-119x^2-10x+16 = (x-8)((15x^2 + x - 2) = 0 ...
*November 17, 2014*

**algebra**

speed of current --- x mph time to go 217 miles with the current = 217/(29+x) time to go 189 againts current = 189/(29-x) 217(29+x) = 189/(29-x) cross-multiply, solve for x
*November 17, 2014*

**Calculus**

everything happens starting at t=.5 a = -10 v = -10t + c when t = .5 , v = 20 20 = -10(.5) + c c = 25 v = -10t + 25 , for t ≥ .5 s = -5t^2 + 25t + k when t = .5 , the car goes goes another 20(.5) or 10 m so when t = .5, the remaining distance is 20 m 20 = -5(.5)^2 + 25(....
*November 17, 2014*

**maths**

original number --- x after epidemic --- .98x are left 14% of those leave, leaving (.86)(.98x) .86(.98x) = 2107 x = 2107/(.86(.98)) = 2500
*November 17, 2014*

**maths**

I am sure you meant A=p(1+r/n)^(nt) for yours r/n = .12/12 = .01 and nt = 12t (our unknown) so 500000(1.01)^(12t) = 1000000 1.01^(12t) = 2 take log of both sides log 1.01^(12t) = log 2 12t log1.01 = log2 12t = log2/log1.01 = 69.6607 t = 5.8 years
*November 17, 2014*

**math**

If I understand correctly there would have been 4 transactions. let the amount that each child has originally be x first transaction: 1st child -- x-9 each of remaining 9 children has x+1 2nd transaction: 1st child -- x-9 2nd child -- x+1 - 8 = x-7 each of remaining 8 children...
*November 17, 2014*

**proportion test**

new machine, defect rate is 85/820 = .1037 or 1037% draw you conclusion from that
*November 16, 2014*

**Math**

The question was to "find all possible roots" so you would try f(1), f(-1) , f(2) ...., f(±12) so you must try all of these unfortunately, none are equal to zero, so you have no rational roots.
*November 16, 2014*

**Math**

It is a 4th degree equation, so at most you could have 4 roots How can you possible get 6 of them ?
*November 16, 2014*

**math**

√(31-9x) = 5 - x square both sides 31 - 9x = 25 - 10x + x^2 x^2 - x - 6 = 0 (x-3)(x+2) = 0 x = 3 or x = -2 BUT, since we squared, we must verify ALL answers if x = 3 LS = 3 + √4 = 5 RS = 5, YEahh if x = -2 LS = -2 + √49 = -2 + 7 = 5 = RS, YEAHH x = -2 or x = 3
*November 16, 2014*

**MATH 101**

using the difference of cubes factoring x^2 - 8 = 0 (x-2)(x^2 + 2x + 4) = 0 x = 2 or x = (-2 ±√-12)/2 = (-1 ± 2√3 i )/2 = -1 ± √3 i for 3 solutions, one real, two complex
*November 16, 2014*

**MATH 101**

not enough information. is f(x) linear ? we must assume that, since you only have 2 points, namely, (3,0) and (-4,0) slope = 0/-7 = 0 so we have a horizontal line and f(x) = 0 f(x) is the x-axis
*November 16, 2014*

**math**

let's look at x^2 + 2x + 4 = 0 by completing the square, (in this case the easiest way to solve it) x^2 + 2x = -4 x^2 + 2x + 1 = -4+1 (x+1)^2 = -3 but anything squared cannot be negative, so there is no real solution consider y = x^2 + 2x + 4 this parabola never touches or...
*November 16, 2014*

**Math**

let f(x) = 3x^3 + 2x^2-1 f(1) = 3 + 2 - 1 ≠ 0 f(-1) = -3 + 2 - 1 ≠ 0 f(1/3) = 1/9 + 2/9 - 1 ≠ 0 f(-1/3) ≠ 0 So there are no "nice" roots looking at the graph, there appears to be a real solution at appr x = 0.5 and two complex roots (the graph...
*November 16, 2014*

**CAL**

y = x^3/x- x would reduce to y = x^2 - x and (1,-2/3) would NOT lie on this curve. So there is something wrong with the way you typed it Use brackets to establish the correct form Otherwise this question is bogus.
*November 16, 2014*

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