Friday

August 28, 2015
Total # Posts: 30,673

**LNU**

Use Venn diagrams and this becomes quite easy. Start with the intersection of the three circles and place 3 in that regions. Now working from the inside out, enter the data Make sure you don't count items more than once. e.g. for the 10 taking Math and History, remember ...
*July 13, 2015*

**algebra**

if -2(x-3y)-3(x+5y)-(6x-8y) then = -2x + 6y - 3x - 15y - 6x + 8y = -11x - y if -2(x-3y)-(3x+5y)-(6x-8y) . then = -2x + 6y - 3x - 5y - 6x + 8y = -11x + 9y
*July 13, 2015*

**algebra**

I see mismatched brackets ... is it -2(x-3y)-3(x+5y)-(6x-8y) or -2(x-3y)-(3x+5y)-(6x-8y) or .... (the brackets going left must have the same count as the brackets to the right)
*July 13, 2015*

**forgot some cases - prob&stat**

ok jil, I forgot the case where only one of "swing players" is in the lineup 6. X plays guard, Y does not play GXFCF C(5,1) x 1 x C(4,2) x C(3,1) = 90 7. X plays forward, Y does not play GGXCF C(5,2) x 1 x C(4,1) x C(3,1) = 120 We have the same cases if Y plays, but ...
*July 12, 2015*

**prob&stat**

number of ways to choose any 5 of the 14 = C(14,5) = 2002 number of "legitimate" starting lineups Cases: GGFCF 1. X and Y excluded: C(5,2) x C(3,1) x C(4,2) = 180 GXFCF 2. X plays guard, Y included in the forwards C(5,1) x C(5,2) x C(3,1) = 150 GYFCF 3. Y plays guard...
*July 12, 2015*

**math**

Best done with a Venn diagram. For the intersection of all three circles which I called F, H, and B, label it x Then fill in the regions of the circle using the given data. e.g. I labeled the part which is only hockey and basketball as 50-x and the part which is only hockey as...
*July 12, 2015*

**math**

Looks like Steve answered the same question in the first of the "Related Questions" below http://www.jiskha.com/display.cgi?id=1410269873
*July 11, 2015*

**Math**

Not enough information. since volume of a rectangular prism, a plain ol' box, is (length)(width)(height) any 3 numbers that will multiply to give you 256 will work e.g. L = 16 W = 8 H = 2 or L = 32 W = 8 H = 1 or L = 10 W = 6.4 H = 4 etc
*July 11, 2015*

**math probability**

Actually looking back at my answer in the Related Question, I see that I made an error The logical connector was OR , so multiples of 3 : 3,6,9,12,15,18 or less than 7: 1,2,3,4,5,6 can't count the 3 and 6 twice, so there are 10 such numbers prob = 10/18 = 5/9
*July 11, 2015*

**Algebra 2**

I will assume An is supposed to mean term(n) ?? term(n) = a + (n-1)d 136 = a + 19(7) a = 3 so sum(n) or your Sn = (n/2)(2a + (n-1)d ) = (n/2)(6 + 7(n-1) ) = (n/2)( 7n -1 ) or = (7n^2 - n)/2 or some other variation of that
*July 11, 2015*

**math**

from the first: x = 12-3z plug that into the 2nd: -12+3z-2y+z = 10 4z - 2y = 22 2z - y = 11 , #4 plut x = 12-3z into the 3rd 36-9z +5y + 2z = -7 -7z + 5y = -43 , #5 #4 times 5 ---> 10z - 5y = 55 add this to #5 3z = 12 z = 4 in #4: 8-y = 11 y = -3 back in x = 12-3z x = 12-12...
*July 10, 2015*

**changing**

s(1) = t(1) = 2+5 = 7 s(2) = 2(2^2) + 5(2) = 18 s(3) = 2(9) + 5(3) = 33 s(4) = 2(16) + 5(4) = 52 .. t(2) = s(2) - s(1) = 18-7 = 11 t(3) = s(3) - s(2) = 33-18 = 15 t(4) = s(4) - s(3) = 52-33 = 19 so we have: 7,11,15,19,... looks like an AP with a = 7 , d = 4 term(n) = a + (n-1)...
*July 10, 2015*

**math-percentage**

If that answer is supposed to be correct, then males = 352 , females = 440 percentage of males = 352/792 = appr 44.4% percentage of females = 440/792 = appr 55.6% which is NOT 20% difference. So the choice are clearly all wrong. Since I showed that my answer is correct, what ...
*July 10, 2015*

**math-percentage**

let the number of males be x then the number of females = 792-x percentage of males = x/792 percentage of females = (792-x)/792 (792-x)/792 - x/792 = .20 times 792 792-x - x = 158.4 -2x = -663.6 x = 316.8 , can't have partial people So there are 317 males and 475 females ...
*July 10, 2015*

**Math**

the primes in that range are: 2,3,5, and 7 Assuming it is a true random generator, the prob would be 4/10 or 2/5
*July 10, 2015*

**Algebra 2**

When simplifying, each new line should have an equal sign at the front You are saying: "my next line is equal to the previous line" Don't just make piece-meal statements Here is what I would have expected from my students when I was still teaching: 6x^5/(2x^3...
*July 9, 2015*

**math**

geeehhh, math is getting harder all the time.
*July 9, 2015*

**math**

I assume your are looking for (√25)x = 12 5x = 12 x = 12/5 Repeat the above for each of the others
*July 9, 2015*

**math**

Steve, I was thinking along these lines, can you find a flaw in this? number of 3-person committees that can be formed from the 15 without any restrictions = C(15,3) = 455 number of 3-person committees WITH BOTH John and Mary = C(13,1) = 13 so the number without both John and ...
*July 9, 2015*

**Algebra**

I don't think Steve is on line right now, so I will try. Did you notice the the right side of both of Steve's equations are the opposite of yours? Steve's solution would result in s = 4 c = 2 Yours give inadmissible results of s = appr -14 and c = 16.7 Your ...
*July 9, 2015*

**math (algebra)**

The x^32 can only come from multiplying the first tems of all those binomials The -1 can only come from multiplying the constants notice that if we multiply the first terms , the x's, in the right side we get (x^16)(x^8)(x^4)(x^2)(x) = x^31 so the missing bracket must be (...
*July 8, 2015*

**Evaluate the difference, and write the result in t**

(6- 1/2 I)-(3+ 9/2 I) = 6- 1/2 I - 3- 9/2 I = 3 - 5 l don't know there the t is supposed to come from.
*July 8, 2015*

**math (algebra)**

oops, forgot the link to the graph http://www.wolframalpha.com/input/?i=%28x-2%29%5E2%28x-1%29%5E3%28x%2B1%29%5E4%28x%2B2%29%5E5+%3D+0
*July 8, 2015*

**math (algebra)**

each factor could be zero, thus x-2 = 0 ---> x = 2 x-1 = 0 ---> x = 1 x+1 = 0 ---> x = -1 x+2 = 0 ---> x = -2 Look how Wolfram graphed it. How many times and where does the graph intersect with the x-axis ?
*July 8, 2015*

**Math**

A: true B: true C: false e.g. 0.5 = .499999.... D: true
*July 8, 2015*

**Math**

so we are looking at area of base of cylinder + area of sleeve of cylinder + area of cone without its base = π(.29)^2 + 2π(.29)(5) + π(.29)(1) = .... you do the button pushing (surface area of cone = πr^2 + πrs, where s is the slant height of the cone...
*July 8, 2015*

**Calculus**

very detailed solution: let 2log4 9 = x log481 = x 4^x = 81 2^(2x) = 81 let log2 3 = y 2^y = 3 2^4y = 3^4 = 81 then 2^(2x) = 2^(4y) ---> 2x = 4y x = 2y So 2log4 9 - log2 3 = x - y = 2y-y = y = log2 3
*July 8, 2015*

**Math**

let present amount be x x(1.05)^5 = 50000 x = 50000/1.05^5 = 39176.31
*July 8, 2015*

**Algebra (Normal Distribution)**

Here is the perfect website for your problem http://davidmlane.com/hyperstat/z_table.html
*July 8, 2015*

**maths**

Did you mean: (√(196/x) )*(√(90/x) ) = 4 or (√196)/x * (√(90)/x = 4 It makes a big difference
*July 8, 2015*

**mathematics**

I don't understand your question. You said that the five numbers given were picked, so the probability that five numbers should be selected would be 1 Not sure what you are asking.
*July 8, 2015*

**math**

the other is (-28/81) ÷ (14/27) = (-28/81)(27/14) = -2/3
*July 8, 2015*

**Math**

"...either a multiple of 3 or a number less than 7" only 2 elements satisfy that condition, namely the 3 and 6 so prob(of your event) = 2/18 = 1/9
*July 8, 2015*

**Maths**

If you are studying this, you must know (1+x)^n = 1 + nx + n(n-1)(x^2)/2! + ... valid only for |x| < 1 now let's apply it to your problem of 31^(1/5) = (32 - 1)^(1/5) = 32^(1/5)(1 - 1/32)^(1/5) = 2 (1 - 1/32)^(1/5)) = 2( 1 + (1/5)(-1/32) + (1/5)(-4/5)/2 (-1/32)^2 + (1/5...
*July 8, 2015*

**Algebra**

amount of the 20% stuff --- x L amount of the 50% stuff --- 200-x L .2x + .5(200-x) = .3(200) times 10 2x + 5(200-x) = 3(200) 2x + 1000 - 5x = 600 -3x = -400 x = 400/3 The chemist needs 400/3 L of the 20% solution and 200/3 L of the 50% solution
*July 7, 2015*

**Calculus**

dy/dx = x(-sinx) + cosx = 0 for a max/min xsinx = cosx sinx/cosx = 1/x tanx = 1/x No direct algebraic method to solve this, so we have to resort to other means let's look at the graph by Wolfram A preliminary look at y = xcosx shows that there would be an infinite number ...
*July 7, 2015*

**Calculus**

since v'(t) = a(t), which is the acceleration a(t) = -32 since a(t) is a constant, we get the acceleration due to gravity at -32 ft/s^2 and v'(1) = a(1) = -32 ft/s^2
*July 6, 2015*

**math**

Can we expect a question? btw, use 1/2 and 1/8 to show your fractions
*July 6, 2015*

**Algebra**

a + s = 598 s = a - 52 sub s = a-52 into the first equation a + a-52 = 598 2a = 650 a = 325 s = 325-52 = 273
*July 6, 2015*

**Math**

Let one be x metres long then the other is 150 - x x+40 = 2(150-x) x+40 = 300 - 2x 3x = 260 x = 260/3 m one is 260/3 m, the other is 150-260/3 or 190/3 m or in decimals, appr 86.67 m and 63.33 m. check: one is 86.67 twice the other is 126.67 which is 40 m more
*July 6, 2015*

**mathematics : intergration**

S = 4t - (1/2)t^2 + c "given that S=S when t=0" ????? I will assume you meant: given that S=0 when t=0 0 = 0 - 0 + c ---> c = 0 S = 4t - (1/2)t^2
*July 6, 2015*

**maths**

original --- x after first increase --- x + 1200 now decrease of 11% -- 89% are left .89(x+1200) = x-32 .89x + 1068 = x - 32 1100 = .11x x = 10,000
*July 6, 2015*

**Algebra**

The equation would be: n(t) = 5 (2^(t/20) , where t is in minutes (note that t/20 = (1/20)t = .05t) So they want the count after 4 hrs or 240 minutes n(240) = 5 (2^(240/20)) = 5 (2^12) = 5(4096) = 20480 you could do this the long way: now --- 5 after 20 min -- 10 after 40 min...
*July 5, 2015*

**maths**

start with a sketch of the finished product Let the triangle be ABC, so that angle B = 120°, angle BCA = 40° and angle CAB = 180-40-120 = 20° the centre of the triangle, O, lies on the right-bisectors of BC and AB, so that CO = AO = BO = 3 cm remember that the ...
*July 4, 2015*

**St jonhs high school/mathamatics**

√5 is obviously greater than √3 And you have 4 of the √5's vs 3 of the smaller value ! I really can't believe you asked this question.
*July 4, 2015*

**MATH**

" ..... find the polynomial whose zeroes are root 3 and -root 3" y = (x-√3)(x+√3) = x^2 - 3 What does the fact that alpha and beta are zeros of the the polynomial x^2 - 5x + 6 have to do with it? other than alpha = 2 and beta = 3
*July 4, 2015*

**Algebra**

(fog)(-2) = f(g(-2)) g(-2) = (-(-2))^3 + 1 = 10 f(10) = 3(10)+7 = 37 so (fog)(-2) = 37
*July 4, 2015*

**trigonometry**

did you make a sketch? If so you will see that sinØ = 30/40 = .75 Ø = appr 48.6° also: x^2 + 30^2 = 40^2 x^2 = 700 x = 7√10 or appr 22.1 ft
*July 4, 2015*

**Math**

children --- x grandkids --- 7-x children got (1/3)(6,000,000) = 2,000,000 so grandkids got 4,000,000 each grandkid got 4000000/(7-x) kids got 2000000/x each "200,000 more a piece than what each of the grandchildren" ---> 2000000/x - 200000 = 4000000/(7-x) times x...
*July 4, 2015*

**math**

thousandth digit --- t tens digit --------- 2t hundredth digit ---- t + 2t = 3t well, digits can only range from 0 to 9 let's rule out t = 0 , since that would not be a sensible number then tenth digit is obviously an even number so it could be 2,4,6,8 which means that t ...
*July 4, 2015*

**Applied Mathematics ( Mechanices**

your distance equation: height = -4.9t^2 + 14t + 29.4 at ground, height = 0 -4.9t^2 + 14t + 29.4 = 0 divide by -7 .7t^2 - 2t - 4.2=0 times 10 7t^2 - 20t - 42 = 0 t = (20 ± √1576)/14 = appr 4.26 seconds (or a negative)
*July 2, 2015*

**linear equations in two variable**

let the speed of the current be x km/h time against the current = 40/(5-x) time with the current = 40/(5+x) 40/(5-x) = 3(40)/(5+x) 1/(5-x) = 3(5+x) 15-3x = 5+x -4x=-10 x=2.5 the speed of the stream is 2.5 km/h check: time against the current = 40/2.5 = 16 hrs time withe the ...
*July 2, 2015*

**trigonometry26**

1 + sin^2 Ø = 3sinØcosØ divide by cosØ 1/cosØ + tanØsinØ = 3sinØ secØ + tanØsinØ = 3sinØ tanØ = (3sinØ - secØ)/sinØ = 3 - secØ/sinØ let's stop here...
*July 2, 2015*

**trigonometry 28**

This basic proof should be found in your textbook or in your notes. If not, just Google it, you will found many proofs.
*July 2, 2015*

**calculus**

the largest area of course is contained within a circle. So if the perimeter is 15 m then 2πr = 15 r = 15/(2π) area = π(15/(2π))^2 = 225/(4π) m^2 or appr 17.9 m^2
*July 2, 2015*

**calculus**

Ok, I will go with that assumption. As I made my diagram, I also noticed that you did not state the speed of the car B. I will also assume that the speeds are the same. At a time of t hrs, let the distance between them be x miles so by the cosine law: x^2 = (30+30t)^2 + (30t)^...
*July 2, 2015*

**calculus**

How are the two cars positioned relative to each other ? e.g. is car A directly west of car B ? is car A north of car B ?
*July 2, 2015*

**trigonometry**

use the fact that cos Ø = sin (90° - Ø) cos(3x - 10) = sin(90 - (3x-10) ) cos(3x - 10) = sin(100 - 3x) so sin(x-20) = sin(100 - 3x) then: x-20 = 100-3x 4x = 120 x = 30 check with your calculator
*July 2, 2015*

**trigonometry**

given: sinØ = a/b so y = a , x = ? r = b r^2 = x^2 + y^2 b^2 = x^2 + a^2 since we are in quad I, x = +√(b^2 - a^2) now use your definitions to state the trig ratios
*July 2, 2015*

**Math**

#1 is the interesting question Since the annuity payments become your "salary", I will assume they are made at the beginning of the year. IF x is the first payment made now , the Present Value is: PV = 8,503.05 + (1.03)(1.075)^-1 (8,503.05) + (1.03)^2 (1.075)^-2 (8,...
*July 2, 2015*

**Math**

I did this one yesterday http://www.jiskha.com/display.cgi?id=1435760969
*July 2, 2015*

**Math**

done yesterday http://www.jiskha.com/display.cgi?id=1435761181 why did you repeat the question?
*July 2, 2015*

**Math**

did you mean a = (√5 + 1)/(√5 - 1) and b = (√5-1)/(√5 + 1) ?? or the way you typed it
*July 1, 2015*

**Math**

27x^3+8y^3 --- the difference of cubes = (3x + 2y)(9x^2 - 6xy + 4y^2) = 12(9x^2 - 6xy + 4y^2) but 9x^2 - 6xy + 4y^2 = (9x^2 + 12xy + 4y^2) - 18xy = (3x+2y)^2 - 18xy = 144 - 108 = 36 so 27x^3 + 8y^3 = 12(36) = 4320 or: y = 6/x back in the first: 3x + 2(6/x) = 12 times x 3x^2 + ...
*July 1, 2015*

**Maths**

You will have 2 congruent triangles, so we need to find only the area of one of them Heron's formula: Area = √(s(s-a)(s-b)(s-c)) , were a, b, and c are the sides and s= half the perimeter s = (26+28+30)/2 = 42 s-a = 16 s-b = 14 s-c = 12 area = √(42x16x14x12...
*July 1, 2015*

**math in distress**

the second oldest could be either 9, 10, 11, or 12 All of the following satisfy the given conditons: 5 5 9 9 12 5 5 9 10 12 5 5 9 11 12 5 5 9 12 12
*July 1, 2015*

**math in distress**

one book weighs 2.5 lbs so 5 books weigh 5(2.5) or 12.5 lbs one notebook weighs 4 ounces 5 notebooks weigh 20 ounces = 1 lbs and 4 ounces , (if I recall the non-metric stuff) total = 12.5 lbs + 1 lb + 4 ounces, you were correct here = 13.5 lbs + .25 lbs = 13.75 lbs or 13 lbs ...
*July 1, 2015*

**math**

set up a simple ratio ... 1/x = (3/4) / 4 (3/4)x = 4 3x = 16 x = 16/3 I will take 5 1/3 quarts You will need to buy 6 quarts, (best bought as 1 gallon and 2 quarts) or, (by the 3 step process) 3/4 wall takes 1 quart one wall takes 1 / (3/4) quarts or 4/3 quarts 4 walls take 4(...
*July 1, 2015*

**correction - maths**

logx (1/8) = -3/2 means: x^(-3/2) = 1/8 x^(3/2) = 8 (√x)^3 = 8 √x = 2 x = 4 check: log4 (1/8) = log41 - log48 = 0 - 3/2 , (since 4^(3/2) = 8) = -3/2
*July 1, 2015*

**mathematics :geometric progression**

If geometric, then (2k-4)/(k-3) = (4k-3)/(2k-4) (2k-4)^2 = (k-3)(4k-3) 4k^2 - 16k + 16 = 4k^2 -15k + 9 -k = -7 k = 7 so the first 3 terms are: 4, 10, 25 a = 4, r = 2.5 sum(8) = a(r^8 - 1)/(r-1) = 4(2.5^8 - 1)/(2.5-1) = 4(390625/256 - 1)/(3/2) = 4(390369/256)(2/3) =4(130123/128...
*June 30, 2015*

**Tupper**

Never heard of a subject called Tupper. anyhow.... let the number of Katies truffles be x after first gifting: Katie had (3/4)x left she gave 1/2 of those away leaving her with (1/2)(3/4)x or (3/8)x truffles (3/8)x = 18 3x = 144 x = 48 So she started with 48 check: she gave 1/...
*June 30, 2015*

**math**

actually it is 1/18 since we are counting all 36 possible outcomes, our desired event could be 1,2 or 2,1 so 2/36 = 1/18
*June 30, 2015*

**math**

we have 1 - 7/9 + (7/9)^2 - (7/9)^3 + ... a = 1 , r = -7/9 sum∞ = a/(1-r) = 1/(1 - (-7/9) ) = 9/16
*June 30, 2015*

**MRGS SCHOOL.**

It says that any whole number greater than 1 is either prime itself or can be expressed as a product of two or more primes. e.g. 600 = 2x2x3x5 247 = 13x19 the factors in both examples are all made up of primes
*June 30, 2015*

**Math**

I know, I know, 6+2+5 ≠ 15, but maybe in the far distant past it was. That's what happens when you have to switch to the second hand to count, I always get confused if I have to count a finger as a carry.
*June 29, 2015*

**Math**

prob = (2/15)(5/12) = ...
*June 29, 2015*

**Mah**

prob of 2 nickels = (4/12)(4/12) = 1/9 so prob of not picking 2 nickels = 8/9 odds in favour of 2 nickels = (1/9) / (8/9) = 1 : 8 none of the choices are correct for the ODDS if you wanted the probability of getting 2 nickels it would be 1/9 the odds of an event is NOT the ...
*June 29, 2015*

**calc**

Maybe I should become a politician. Never actually answer the question, rather give an answer to some other question. Thanks for the catch Steve, that is two for one evening, I should get more sleep.
*June 29, 2015*

**calc**

slope = x/y = 3/1 = 3 so the equation of the tangent at the point (3,1) is y-1 = 3(x-3) y = 3x -8 or 3x - y - 8 = 0
*June 29, 2015*

**Calculus**

let the piece of paper be x inches wide and y inches long area of printed part = (x-4)(y-8) = xy - 8x - 4y + 32 but that equals 72 xy - 8x - 4y + 32 = 72 y(x-4) = 8x + 40 y = (8x+40)/(x-4) , clearly x > 4 amount of paper used = A A = xy = x(8x+40)/x-4) = (8x^2 + 40x)/(x-4) ...
*June 29, 2015*

**Cycle geometry**

So the exterior angle = 180-162 = 18° sum of exterior angles = 360° so 18n = 360 n = 20 It is a 20-gon
*June 29, 2015*

**Physics**

let's assume that for the first 1.95 seconds, the given acceleration of 44.3 m/s^2 includes the effect of gravity, and for any time thereafter the effects of gravity of -4.9 m/s^2 takes over for the first part: a = 44.3 v = 44.3t + c but when t = 0 (at the start) v = 0...
*June 29, 2015*

**Algebra**

amount of 15% juice --- x amount of 5% juice ---- 10-x .15x + .05(10-x) = .12(10) solve for x
*June 29, 2015*

**algebra**

Steve answered a similar question: http://www.jiskha.com/display.cgi?id=1435406901
*June 28, 2015*

**math**

the way you typed it, it is not a quadratic but a cubic e.g. 10x^2 - 1/x = 3 times x, 10x^3 - 1 = 3x 10x^3 - 3x - 1 = 0 , which is a cubic equation appr x = .67023 if you meant: (10x^2 - 1)/x = 3 then 10x^2 - 1 = 3x 10x^2 - 3x - 1 = 0 (2x - 1)(5x + 1) = 0 x = 1/2 or x = -1/5 ...
*June 28, 2015*

**Math**

I assume you are rounding to the nearest thousand since it rounds to 4000, the hundreds digit could only be 0,1,2,3, or 4 if the number starts with a 4 or only 5,6,7,8,9 if it starts with a 3 but the hundreds digit is twice the tens, so the hundreds digit must be even so cases...
*June 28, 2015*

**MATH**

number of 5RS coins --- x number of 2RS coins = .15x 5x + 2(.15x) = 1272 5.3x = 1272 x = 240 so 240 of the 5 RS coins, and 36 of the 2 RS coins
*June 28, 2015*

**Maths**

let the number of cookies be x let the number of friends by y x - 5y = 0 x - 3y = 36 subtract them: -2y = -36 y = 18 x - 5(18) = 0 x = 90 John has 90 cookies.
*June 28, 2015*

**Math**

starts with x spends half, so amount left = (1/2)x Spends 1/3 of that, so left with (2/3)of (1/2)x thus amount left = (2/6)x or (1/3)x but (1/3)x = 20 x = 60
*June 28, 2015*

**Geometry**

no, one other piece of information , such as one of the angles or one of the diagonals must be given. Many years back on Sesame Street, Oscar the Grouch took a rectangle and squished it, so its angles were no longer 90°. He then called it a wrecked-angle. Notice that if ...
*June 27, 2015*

**ahhh #2 - Math**

looks like our replies crossed. So there was an actual direction to your problem. Now you state: "Write each expression as a single logarithm" Why didn't you say that at the beginning and avoid all this confusion.?
*June 27, 2015*

**ahhh - Math**

Just thought I would play some "Jeopardy" with your post Alex Trebek : log3 (3x^2) me: What is 1 + log3 (x^2) simplified expanation: log3 (3x^2) = log3 3 + log3 (x^2) = 1 + log3 (x^2) so the two expressions are the same.
*June 27, 2015*

**Math**

1 + log3(x^2) is not a question 1 + log3(x^2) is an algebraic expression What do you want to do with it ? Do you want to solve something like 1 + log3(x^2) = 0 ? Do you want to colour it blue? Do you want to sent it to Donald Trump as a campaign slogan? etc The way it stands, ...
*June 27, 2015*

**Math**

just replace y with x, since it says y = x 2x^2 - x^2 = 1 x^2 = 1 x = ±1 if x = 1, then y = 1 if x = -1, then y = -1
*June 27, 2015*

**Maths**

arrangements in a line = 5! = 120 around a circle, with no specified position around the table = 5! / 5 = 4! = 24 e.g. for any arrangement of the 5 people around the table, everybody could get up, move once to the left, and the arrangement would not change, etc . We could do ...
*June 27, 2015*

**Math**

A: x > 14 , so NO B: x > 77/2 , so NO C: x = -8 , so NO D: x ≤ 26/3 or x ≤ 8 2/3 , YEAH, since 8 ≤ 8 2/3
*June 26, 2015*

**Geometry**

Just use ordinary keyboard keys According to the properties of tangents to circles, AO is perpendicular to PA making angle PAO = 90°, thus angle angle POA = 90-32 = 58° The same property is true for angle POB since PA = PB , angle POB = 58° Then angle AOB = 116°...
*June 26, 2015*

**math**

possible numbers: 111111 222222 .... 999999 largest such number: 999999 number from above with a sum of 6 : 111111 999999 - x = 111111 x = 888888
*June 26, 2015*

**Probability**

sounds like conditional probabilty Prog(A|B) , (read as the prob of A, given B) = prob(A AND B)/prob(B) prob(A and B) = 1/15 prob(B) = 7/15 prob( as stated) = (1/15) / (7/15) = 1/7 (of course, since the 4 is one of the 7 even numbers from 1 - 15)
*June 25, 2015*

**Algebra**

I agree with Ms Sue To show us that you are not merely sponging off us, for the question above, I would be interested in your thinking to solve the problem So you want whole numbers m and n so that 3^m + 2^n ≤ 999
*June 25, 2015*