Wednesday

March 4, 2015

March 4, 2015

Total # Posts: 29,207

**math101**

I will assume compound interest: 6900(1.12)^n = 9384 (1.12)^n = .1.36 take log of both sides, and use log rules nlog1.12 = log1.36 n = log1.36/log1.12 = 2.7 it would take 2 years and appr. 8.5 months check: balance after 1 year = 6900(1.12) = 7740.32 balance after 2 years = ...
*February 11, 2015*

**Math**

Did you make your sketch? area of larger square = (2s)^2 = 4s^2 For the side of the smaller square: x^2 = s^2 + s^2 x = √2s area of smaller is (√2s)^2 = 2s^2 so the ratio of their areas = 4s^2 : 2s^2 = 2 : 1
*February 10, 2015*

**algebra**

number of quarters --- x number of dimes ---- 2x number of nickels ---- 2x+47 25x + (10)(2x) + 5(2x+47) = 400 solve for x, then sub into my definitions
*February 10, 2015*

**algebra**

let the amount of pure acid added be x ml x + .45(600) = .5(x+600 x + 270 = .5x + 300 .5x = 30 x = 60
*February 10, 2015*

**Math**

no, it said that she flew at 800 mph for one hour, so she used up 1 hour of flying time To average 1000 mph in flying 1000 miles would take exactly one hour, which she has already spent flying. So she must do the remaining 200 miles in zero time. That is why it is not possible.
*February 10, 2015*

**Math**

She must fly faster than the speed of light, that is, it can't be done. I want your explanation of why I said that.
*February 10, 2015*

**math - exponent laws**

You must be referring to the post from yesterday where you had -( -11/-17)^-10 ÷ (9/5)^(1/10) http://www.jiskha.com/display.cgi?id=1423540960yes , you could have done that. I treated the (-11/-17)^-10 as 1/(11/17)^10 which was 77.725... You want to do (17/11)^10 which ...
*February 10, 2015*

**Algebra 1**

outer area = (10x+89)(7x+7)= 70x^2 + 693x + 623 skylight area = (x+5)(3x+3)= 3x^2 + 18x + 15 remaining area = 70x^2+693x+623 - (3x^2+18x+15) = 67x^2 + 675x + 608
*February 10, 2015*

**Algebra 2**

first of all notice that each term divides by 2, so (6x^2+4x-16)/(2x-2) = (3x^2 + 2x-8)/(x-1) hard to show the actual long division on here but you should get 3x+5 with a remainder of -3
*February 10, 2015*

**Algebra 2**

factor it, you are looking at the difference of squares x^4 - 81 = 0 (x^2 + 9)(x^ - 9) = 0 , and again (x^2 + 9)(x+3)(x-3)= 0 x= -3 or x = +3 or x^2 = -9 ---> x = ± 3i If you have not studied complex numbers, then just go with the x = ± 3
*February 10, 2015*

**math**

if that is supposed to say u^2 - 14u + 49 , then can you think of two numbers which multiply to get 49 and have a sum of -14 ? -7 and -7 come to mind = (u - 7)(u - 7) or (u-7)^2
*February 10, 2015*

**Math**

volume is proportional to the cube of their corresponding sides V/280 = 2.5^3/1^3 V = 280(15.625) = 4375 cm^3
*February 10, 2015*

**Algebra**

area of first = x^2 area of 2nd = (x+5)^2 x^2 + x^2 + 10x + 25 = 193 2x^2 + 10x - 168 = 0 x^2 + 5x - 84 = 0 (x - 7)(x + 12) = 0 x = 7 or x = -12 , which would be a silly square the first square is 7 by 7 the second is 12 by 12 check: 49 + 144 = 193 , yeahhh!
*February 10, 2015*

**math**

The following OA , OB etc are vectors OA + AB = OB AB = OB - OA AB = OB + AO = (4,1,-3) + (-3,2,-1) = (1,3,-4) |AB| = √(1^2 + 3^2 + (-4)^2) = √26 = appr 5.10
*February 10, 2015*

**Math**

the the two integers be x and y x+y = 100 y = 100-x product = xy = x(100-x) 100x - x^2 ≥ 2000 x^2 - 100x + 2000≤0 so we are looking for all those integer values of x where the parabola y = x^2 - 100x + 2000 lie below the x-axis, so we have to find the x-intercepts ...
*February 10, 2015*

**Math**

For some unit of time: number of words for kala --- 4x number of words for rose ---- x but x = 48, so kala typed 192 words Since Lita typed twice as fast as kala, lita typed 384 words
*February 10, 2015*

**Maths**

Rather tedious to find the inverse of a 4by4 matrix, and out of the question to type it all out. Surely you can find an inverse calculator on the web. Just google and pick one then multiply that inverse by 5 8 12 7
*February 10, 2015*

**Math**

I just did this before you decided to repost under a different name
*February 10, 2015*

**maths**

sin30° = height/10 height = 10sin30 = ...
*February 10, 2015*

**Trigonometry**

I made a sketch and marked all the angles Let r be the distance between start and ending point. the angle between the two trips is 90+28°20'+28°20' = 146° 40' by the cosine law: r^2 = 86^2 + 124^2 - 2(86)(124)cos146°40' = 40591.28405 r = √...
*February 10, 2015*

**math**

if the base is a proper fraction (less than one) and you are raising it to positive exponents > 1, the answer is less than the base if the base is a improper fraction (greater than one) and you are raising it to positive exponents > 1, the answer is greater than the base...
*February 10, 2015*

**Calculus**

I will answer no more of these types until you show me some of your efforts and work
*February 9, 2015*

**Calculus**

these questions you are posting all basically all the same. a = 72 v = 72t+c when t = 0 , v = 17 17 = 0 + c, v = 72t + 17 s = 36t^2 + 17t + k when t = 0 , s = 10 so k = 10 s = 36t^2 + 17t + 10
*February 9, 2015*

**Calculus**

see http://www.jiskha.com/display.cgi?id=1423541938 and make the necessary adjustments
*February 9, 2015*

**Calculus**

height = -16t^2 + 96t v = -32t + 96 = 0 at the top 32t=96 t = 3 it will take 3 seconds to reach the max, and that max is -16(9) + 96(3) = 144 ft
*February 9, 2015*

**MATH - exponent laws**

-(11/17^-10/(9/5)^(1/10) use the y^x key, the most powerful key on your calculator (-11/-17)^-10 = 1/(11/17)^10 = 77.725... (I stored that in A on my calculator) (9/5)^(1/10) = 1.0605.. so -(11/17^-10/(9/5)^(1/10) = -77.725... /1.0605... = -73.28837824 I use the memories on my...
*February 9, 2015*

**Math**

What is 360 ÷ 18 what is 5 times that ?
*February 9, 2015*

**Math**

Not necessarily. The angles could be different, thus not similar Imagine the second figure having hinges at the vertices and you "squish" the figure.
*February 9, 2015*

**Math**

I am guilty of that more often than you are
*February 9, 2015*

**Math**

prob of making the free throw = 32/60 = 8/15 so the prob of NOT making it = 1 - 8/15 = 7/15
*February 9, 2015*

**Math 110**

can't make out a) if x5/3 is supposed to mean x^(5/3) use the notation I just used.
*February 9, 2015*

**Math**

a peek at the graph might guide you along http://www.wolframalpha.com/input/?i=plot+y+%3D++2x+%2B+1+%E2%88%92+sin%28x%29
*February 9, 2015*

**Mat104**

i = .055/3 = .018333... what is 955(1.018333..)^12 ?
*February 9, 2015*

**Calculus**

sketching should have been no problem both have axes on the x-axis, one has vertex (-49,0) and opens to the right the other has vertex (49,0) and opens to the left There is perfect symmetry and they meet at (0,7) and (0,-7) I would take horizontal slices, thus integrate with ...
*February 9, 2015*

**math**

gradient = slope = dy/dx dy/dx = 3ax^2 - 6x - 2 using the given: 7 = 3a(1) -6(1) - 2 7 = 3a - 8 3a = 15 a = 5
*February 9, 2015*

**Calculus**

well, finding y' and y'' is really the main part of the meal, the rest is just cleaning the dishes. you should know the derivatives of the 6 basic trig functions by heart. y' = secx(sec^2 x) + tanx(secxtanx) , by the product rule = sec^3 x + tan^2 x secx y'...
*February 9, 2015*

**Math**

a = -32 v = -32t + c since it was 'dropped' , when t=0 , v =0 so c = 0 v = -32t 120 = -32t t= 120/-32 = -15/4 s = -16t^2 + k when it hit the ground, t = 15/4 , s = 0 0 = -16(225/16) = k k = 225 s = -16t^2 + 225 So the height of the cliff is 225 ft
*February 9, 2015*

**Differentiation**

y' = (e^tanx )(sec^2 x)
*February 9, 2015*

**Vector Cross & Dot Product**

1. I got (-1,2,6) Your error is in the last calculation, I had 4(1) - (2(-1) = 6 and then (-1,2,6)dot((-1,0,3) = 1 + 0 + 18 = 19 2. since this problem depends on your answer from #1, check your calculations with the correct answer from #1, I did get (6,-3,2)
*February 9, 2015*

**Cross Product of Vectors**

your initial vector is correct magnitude of (0,6,18) = √(0+36+324) = √360 = 6√10 so I see that your unit vector is also correct Perhaps you are looking at some answer key and the answer there looks different. They might have rationalized the denominator 1/&#...
*February 9, 2015*

**math**

Ms Sue correctly assumed that the largest rectangle one can have for a given perimeter is a square, and gave you a correct solution based on that assumption. Were you supposed to find the answer without making that assumption? Let me know and I will show you how.
*February 9, 2015*

**math**

What is the USE format ?
*February 9, 2015*

**Math**

yes, but that would give you how many brought skates, which is not the question. First, how many came ? (3/4) of 400 = 300 of those 1/5 brought skates number who brought skates = (1/5)(300) = 60 Assuming the rest rented skates, so 300-60 or 240 rented skates or if 1/5 brought ...
*February 9, 2015*

**Trigonometry**

since 1+cot^2theta=csc^2theta cot^2 Ø = csc^2 - 1 = (-3.589142)^2 - 1 = 11.8819403 cotØ = ± √11.8819403 = ± 3.447... but since Ø in in III, cotØ must be positive, so cotØ = 3.447.. Why were you doing 1/sin(-3.58914...
*February 9, 2015*

**Algebra 2**

(1 - √(3x)/√(6x) = (1 - √(3x)/√(6x) * √(6x)/√(6x) = (√(6x) - (√18)x)/(6x) = ( √(6x) - 3√2 x)/(6x)
*February 9, 2015*

**Algebra 2**

Follow the same steps suggested by Steve in your previous post or take the negative term to the right side, then square collect all like terms, isolate the square root term and square again.
*February 9, 2015*

**Math - not PSC**

y1/x1 = y2/x2 65/33 = y2/44 y2 = 44(65/33) = 260/3 or 86 2/3 = appr 86.67 or "If y is directly proportional to x" means y = kx if y = 65, x = 33 65 = 33k k = 65/33 y = (65/33)x when x = 44 y = (65/33)(44) = appr 86.67
*February 9, 2015*

**math**

If the base is a square of area 49, then each side is 7 cm so look at the block, you have 2 squares + 4 equal surfaces on the sides Surface area = 2(49) + 4(7)(10) = 378 cm^2 btw, I don't understand your previous post, it looks incomplete
*February 9, 2015*

**linear algebra**

I will give you 2 nice youtubes to show how this is done https://www.youtube.com/watch?v=taBHTo8sviM She sets it up nicely, but does not actually show how to find the determinant of a 3by3. This one shows a nice short-cut method to find the determinant, but I must point out ...
*February 9, 2015*

**Math- Calculus**

1. done by just getting a "feel" for the numbers e^(-2x) = 1/e^(2x) so as x ---> infinitity, the denominator gets huge and the result approaches zero as for the sinx it simply runs up and down between -1 and 1 no matter what x is or how large x is So the lim(e^(-...
*February 9, 2015*

**Calc**

1. lim tanx/x , as x ---> 0 (after each line below) = lim (sinx/cosx)/x = lim (sinx/x)(1/cox = lim sinx/x * lim 1/cosx , you should know these = (1)(1) = 1 2. y = x^2 dy/dx = 2x Let the point of contact be (a,b) we know b = a^2 and the slope of the tangent is 2a but using ...
*February 9, 2015*

**math**

Same as the standard "hand-shake" problem number of games = 10 choose 2 = C(10,2) = 45 In the hand-shake problem, we have 10 people and they all shake hands on meeting. so each of the 10 people can shake hands with 9 others for 90 shakes but that would include A ...
*February 9, 2015*

**Algebra 1**

#1, your middle term is -x , thus A #2 D #3 B How are you doing these, so far they are all wrong (4p-2)(p-4) = 4p^2 - 16p - 2p + 8 = 4p^2 - 18p + 8 #4 A = 2πr^2 + 2πrh = 2π(3x-2)^2 + 2π(3x-2)(x+3) = 2π[ 9x^2 - 6x - 6x + 4 + 3x^2 + 9x - 2x - 6] = 2π...
*February 9, 2015*

**math algebra**

In the golden rectangle the ratio of length : width = (1+√5) : 2 or appr 1.618 5/w = (1+√5)/2 w = 10/(1+√5) = appr 3.09 check: 5/3.09 = appr 1.6181.. good enough
*February 9, 2015*

**Maths**

8m, 9 cm = 809 cm number of pieces which are 9 cm long = 809/9 = 89.88.. or appr 90 cm each btw, in the true usage of the metric system, one would not say 8m, 9cm it would be either 809 cm or 8.09 m the beauty of the metric system is that you don't have to mix units like ...
*February 9, 2015*

**math**

number without a 1 = 9^7 = 4,782,969 so number where no 1 occurs = 4,782,969 number where a 1 does occur = 10,000,000-4,782,969 = 5,217,031 Your conclusion ?
*February 9, 2015*

**Geometry**

Use the information from my previous post to answer this one. Let me know what your answer is
*February 9, 2015*

**Geometry**

Since perimeter is a linear relationship, the ratio of perimeters of two similar figures is proportional to the ratio of their sides, thus 48 : 54 or 8 : 9 Since area is a quadratic relationship , ..... the square of their sides, thus 48^2 : 54^2 = 2304 : 2916 = 64 : 81
*February 9, 2015*

**math**

I assume you want this in simple interest. let the amount needed now be A A + A(.0547)(8/12) = 1762 A + A(.0364666..) = 1762 A(1.0364666..) = 1762 A = 1762/1.0364666.. = $1700.00
*February 8, 2015*

**Calculus**

just tedious work .... I suggest you make a sketch, and plot the points (0,20) , (2,22), .... you will get trapezoids by joining all the y-values and drawing in all the verticals look at the first trapezoid, its base = 2 the left vertical is 20 and the right vertical is 22 ...
*February 8, 2015*

**math1979**

Wow, let me know what stock that is. profit = 96-17 + 3.57 = 82.57 I = PRT 82.57 = 17(R)(1) R = 82.57/17 = 4.857 = appr 486 %
*February 8, 2015*

**math**

In your last line you have a = 30, d = -2 but you had found d = -10, which is correct so a = 30, d = -10 sum(n) = (n/2)(2a + (n-1)d ) , you should know that formula sum(15) = (15/2)(60 + 14(-10)) = -600
*February 8, 2015*

**Math**

One of the basic identities you should have at your disposal is sec^2 x = 1 + tan^2 x so sec^2 x + tanx = 1 1 + tan^2 x + tanx = 1 tanx(tanx + 1) = 0 tanx = 0 or tanx = -1 if tanx = 0 then x = 0 or x = 180° if tanx = -1, then x = 135° or x = 315° x = 0 , π , 3...
*February 8, 2015*

**Math**

f ' (x) = ax^(a-1)(1-x)^b + b(1-x)^(b-1) x^a = 0 for a max of f(x) x^(a-1) (1-x)^(b-1)[a(1-x) + b(x)] = 0 then x^(a-1) = 0 , which is not possible or (1-x)^(b-1) = 0 , which is also not possible or a-ax+bx=0 a = ax+bx a = x(a+b) x = a/(a+b) f(a/(a+b))) = [a/(a+b)]^a [(1-a...
*February 8, 2015*

**Vectors/Scalars?**

The dot product is an operation between any two vectors and is always a scalar, your (u dot v)dot (a dot c) = (a scalar) dot (a scalar) which would be undefined, since there is no such thing as a dot product between two scalars.
*February 8, 2015*

**Math 1105**

18x^2+36x+18 = 18(x^2 + 2x + 1) = 18(x+1)^2 so one square is x+1 by x+1, the other is 3√2 by 3√2
*February 8, 2015*

**Math**

what I stated is true for any positive base > 1 thus it is true for 9^x
*February 8, 2015*

**Math**

consider y = 9^x and look at its graph http://www.wolframalpha.com/input/?i=plot+y+%3D+9%5Ex You might want to change the equation to y = 2^x in the input window of Wolfram to show the shape is basically the same for any positive base > 1. if x = 0 , 9^x = 1 if x is ...
*February 8, 2015*

**finite math**

I don't know what example 1 is, thus I don't know how you are taught to do these. Here is how I would do it Number of ways to choose 8 from 15 = C(15,8) = 6435 at least one green ---> exclude the case of no green number with no green = (10,8) = 45 so the number with...
*February 8, 2015*

**geometry**

x/55 = tan49° x = 55tan49° get out your calculator
*February 8, 2015*

**Math (Pre-Calc)**

5√3 tanx + 3 = 8√3 tanx 3√3tanx = 3 √3 tanx = 1 tanx = 1/√3 x = π/6 in quadrant I or x = π + π/6 or 7π/6 in quadrant III x = π/6 , 6π/6
*February 8, 2015*

**Math**

A little "trick" needed here cosx/(1+sinx) , (those brackets are essential) = cosx/(1+sinx) * (1-sinx)/(1-sinx) ---> I multiplied by a version of 1, thus changing the appearance but not the value of the expression = cosx(1-sinx)/(1 - sin^2 x) = cosx(1-sinx)/cos^2 ...
*February 8, 2015*

**math**

price of cup ---- x price of spoon --- y Samuel: 3x+4y=324 Daniel paid 5x for his cups Mary paid 2y for her spoons 5x - 2y = 228 double this last equation 10x-4y=456 , add to the first 3x+4y=324 13x = 780 x = 60 back in 1st: 3(60) +4y = 324 I will let you finish it , and state...
*February 8, 2015*

**math algebra 8**

amount of 12% powder --- x amount of 20% powder --- 30-x .12x + .20(30-x) = .18(30) times 100 12x + 20(30-x) = 18(30) solve for x
*February 8, 2015*

**Math**

Assuming you made a sketch, and the 34° angle is at the end of the shadow, then h/11 = tan34 h = 11tan34 = ...
*February 8, 2015*

**math**

A lot of wording just to confuse you. The fact that 2 people draw the apples has nothing to do with it, might just as well have Michael draw 2 apples, assuming the first apple is not returned to the bag. What is the prob they are both red or green ? prob(both red) = (5/9)(4/8...
*February 8, 2015*

**maths**

set up the 4by4 matrix of the coefficients. find the inverse of that matrix multiply that inverse matrix by 5 8 12 7 This will take several sheets of paper and lots of patience - not really suitable to write up in this format, matrices are horrible to type in jiskha. There are...
*February 8, 2015*

**math**

8 is not evenly divisible by 3 , so I guess we might have to cut some of those tiles.
*February 8, 2015*

**maths**

one rotation = 1π = π m 78.5 km = 78500 m number of revs = 78500/π = appr 24987
*February 8, 2015*

**math**

let the smaller of the unknown angles be 5x and the larger of the two be 16x so 130+20+5x+16x = 360 21x = 210 x = 10 so the two missing angles are 50° and 160° check: 50+160+130+20 = 360 50:160 = 5 : 16
*February 8, 2015*

**math**

number without a 1 = 9^7 = 4,782,969 so number where no 1 occurs = 4,782,969 number where a 1 does occur = 10,000,000-4,782,969 = 5,217,031
*February 8, 2015*

**precalculus**

let a = -33 , (the last one) let d = -33 , going backwards a+(n-1)d = appr -500 -33 + (n-1)(-33) = -500 -33 -33n + 33 = -500 -33n = -500 n = 15.15.. So there are 15 terms, and term(15) = -33 + 14(-33) = -495 so we have -495 , -462, -429, ... -66, -33 sum(15) = (15/2)(first + ...
*February 8, 2015*

**problem**

number of miles ---- m .5m + 42.15 ≤ 130 .5m ≤ 87.85 m ≤ 175.7 He can go 175 miles
*February 8, 2015*

**math**

I am not even going to guess what that means.
*February 8, 2015*

**maths please help and explain**

Did you not look at my reply to this from yesterday morning ? http://www.jiskha.com/display.cgi?id=1423307265 You have typed it exactly the same way, the same lack of brackets in the numerators, and the same ambiguity in B.
*February 8, 2015*

**trigo**

your equations all fit the pattern y = a (sin or cos)(kx) where |a| is the amplitude and the period is 2π/k I will do one of them , you do the others in the same way. 2. y = 4sin(5x) amplitude is 4 period = 2π/5 radians dy/dx = 4cos(5x) (5) = 20 cos(5x) = 0 for any ...
*February 8, 2015*

**math**

calls received after one session of calls = 4 calls received after two sessions of calls = 4^2 = 16 calls received after three sessions of calls = 4^3 = 64 ....... calls received after n sessions of calls = 4^n Please finish the question
*February 8, 2015*

**math:order of operation**

Pattern: at start: 3 butterflies after one minute: 3(2) = 6 butterflies after two minutes: 3(2)(2) = 3(2^2) butterflies after three minutes : 3(2^3) butterflies after four minutes : 3(2^4) butterflies but at that point she captured 7 of them after 4 min, number on screen = 3(2...
*February 8, 2015*

**PreCalculus**

I will assume the chips are not returned after being selected. a) You want the situation GGGGN and its other 4 variations, where N stands for non-green Prob(GGGGN) = (30/60)(29/59)(28/58)(27/57)(30/56) = 135/4484 But there are C(5,4) of these Prob(exactly 4 green) = 5(135/4484...
*February 7, 2015*

**dot product of vecotrs**

Sure looks like you corrected the typo, but made no effort to adjust the corresponding arithmetic. http://www.jiskha.com/display.cgi?id=1423332996 The unnecessary duplication of work could have been avoided.
*February 7, 2015*

**Math Help**

You need brackets: (1+ sec u)/tan u - tan u/(1+sec u) I am going to guess that you have just learned: sin^2 x + cos^2 x = 1 and its variations ... tan^2 x + 1 = sec^2 x cot^2 x + 1 = csc^2 x So (1+ sec u)/tan u - tan u/(1+sec u) = ( (1+secu)^2 - tan^2 u)/(tanu(1+secu)) = (1 + ...
*February 7, 2015*

**Math**

since sinx = -12/13, and tanx is positive, x must be in quad III in your triangle: sinx = -12/13 ----> the given cosx = -5/13 tanx = -12/-5 = 2.4
*February 7, 2015*

**geometry**

one circumference = 8π ft 3 miles = 3(5280) ft or 15840 ft number of rotations = 15840/8π) = appr 630 times
*February 7, 2015*

**Math**

NOT to be a trig identity requires a single exception so take an angle for which you know the trig rations and test the equations e.g. let x = 45° you know sin^2 45 = cos^2 45 = 1/2 tan^2 45 = 1 and cot^2 45= 1 also sec^2 45 = 2, and csc^2 45 = 2 What do you think?
*February 7, 2015*

**^Math.^ Pls,I need help**

LS = (a-b)^2 = a^2 - 2ab + b^2 RS = (a+b)^2 - 4ab = a^2 + 2ab + b^2 - 4ab = a^2 - 2ab + b^2 = LS Q.E.D. or (quid est demonstrata) (Thus it has been proven)
*February 7, 2015*

**Vectors and Math**

I will use the notation: a = -i-3j+k = <-1,-3,1> b = 2i+4j-5k = <2,4,-5> and (3a+4b)(2b+4a) is the dot product = ( <-3,-9,3> + <8,16,-20>) dot (<4,8,-10> + <-4,-12,4>) = <5,7,-17> dot <0,-4,-6> = 0 -28 + 102 = 74 check my ...
*February 7, 2015*

**maths please help**

You will need brackets in the numerator as well in A B appears to have a typo C) notice the middle term denominator factors and it becomes the LCD 3/(x-3) - x^2/((3-x)(2+x)) - 2/(x+2) Do the others in the same way hint for D after you insert the brackets in the top you get (x+...
*February 7, 2015*

**Math**

I will assume you meant the numerator to be ( √(x^2+25) - 13 ) , so lim ( √(x^2+25) - 13 )/(x+12) , as x-->-12 = lim ( √(x^2+25) - 13 )/(x+12) * ( √(x^2+25) + 13 )/( √(x^2+25) + 13 ) = lim( x^2 + 25 - 169)/( ( √(x^2+25) + 13 )(x-12) ) = ...
*February 7, 2015*

**math**

volume of cone= (1/3)π(49)(18) = 294π cm^3 Height needed in the cylinder to hold that volume π(14^2)(h) = 294π h = 276/196 = 3/2 or 1.5 cm
*February 7, 2015*

**math**

ignore my reply above,
*February 7, 2015*

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