Tuesday

January 24, 2017
Total # Posts: 37,376

**calculus**

I don't see the problem with this limit question other than your notation. I will assume you meant: lim 4^(2x -1) , as x ---> 0 Since you don't want to use substitution, which is always my first step, you could look at the graph of y = 4^(2x-1) and observe what it ...

*January 5, 2017*

**value**

Make your vector diagram. You should have a triangle with sides 200 and 100 and the contained angle of 135°. The third side is your resultant velocity, call it x by the cosine law: x^2 = 200^2 + 100^2 - 2(200)(100)cos 135° continue let me know what you get

*January 5, 2017*

**math**

I will assume that in each case, the first ball drawn is not returned. prob(2 blue) = (12/35)(11/34) = .. prob(2 yellow) = you do it prob(red, then yellow) = (14/35)(9/34) = ... prob(red, then yellow) = your turn again

*January 5, 2017*

**Pre calc**

the slope-yintercept form is y = mx +b so why not plug in your given data ?

*January 4, 2017*

**Math**

Since the new line is parallel to x+3y=5 it differs only in the constant: x+3y=c plug in (-1,4) to find c and you are done

*January 4, 2017*

**Maths**

let the amount he spent on food, utilities, socializing and savings be 2x , 7x, 3x, and 4x respectively 2x = 2500 solve for x, then sub back into my definitions add them all up to get the total expenses. divide this by .8 to get his total earnings.

*January 4, 2017*

**am I right ? or no?**

You did not show your answers, how can we check ?

*January 4, 2017*

**Trig**

make sketches of each triangle for sinx = 4/5 sin^2 + cos^2 x = 1 16/25 + cos^2 x = 1 cos^2 x = 9/25 cos x = 3/5, in quadrant I siny = 5/13 using your triangle and Pythagoras cosy = -12/13 , since we are in quadrant II sin(x+y) = sinxcosy + cosxsiny = (4/5)(-12/13) + (3/5)(5/...

*January 4, 2017*

**Algebra 2**

T)r) = 100 (1.1)^r plug in r = 8 and calculate

*January 4, 2017*

**algebra**

but the integers are consecutive, so smaller number --- x next integer ---- x+1 x + x+1 ? 9x - 5(x+1) 2x + 1 ? 4x - 5 2x ? -6 x ? -3 Also consider Steve's other possibility .

*January 4, 2017*

**Maths**

but Mike, you said that the two sides are equal, so the triangle is isosceles, and the angles would be (180 - 1/60)/2 ° = 89.99166.. ° each or your top angle is 1 minute of angle the base angles would be (10800 - 1)/2 minutes of angle = 5399.5 minutes = 89.99166.. °...

*January 4, 2017*

**Maths**

compare your answer of 14,730,933,173.9 with mine: 1.4725 x 10^10 they are the same answer correct to 4 significant digits.

*January 4, 2017*

**Maths**

Looks like you are doing some astronomical type of calculation. Make an exaggerated diagram of an isosceles triangle with a vertex angle of 1/60° or 1 minute of angle and mark each of the equal sides as 50,620,..... I am tempted to state your side as 5.0621 x 10^13 , or ...

*January 4, 2017*

**math**

number of metres of fencing = 3200/1.6 = 2000 m so each side of the square is 2000/4 or 500 m and its area is 500^2 m^2 cost of "reaping" = 500^2 /100 * 1.2 = 3000 rupees

*January 4, 2017*

**math**

a = 16 ar^4 = 9 sub in a = 16 16r^4 = 9 4r = ± 3 r = ± 3/4 7th term = ar^6 = 16(±3/4) = 16(729/4096) = 729/256

*January 4, 2017*

**Math**

length of BC = ?( (5-1)^2 + (1-3)^2) = ?(16+4) = ?20 = 2?5 since BM = (1/2)BC BM = ?5

*January 4, 2017*

**Statistics**

number of two-digit numbers: 10, 11, ... , 99, ----> 90 of them (1 - 9 are missing) smaller than 20: 10,11, ... , 19 ----> 10 of them prob( < 20) = 10/90 = 1/9 use the same type of analysis for the two other parts, let me know what you get.

*January 4, 2017*

**Maths**

solve: 4x - 23 = (1/3)(54)

*January 4, 2017*

**Maths**

looks like your standard: x = my + b case1: y = 2 when x = 15 15 = 2m + b ** case2: y = 4 when x = 27 27 = 4m + b *** subtract ** from *** 12 = 2m m=6 from ** 15 = 12+b ---> b=3 x = 6y + 3 when y = 7 x = 42+3 = 45

*January 4, 2017*

**Math**

new length = 1.15(8) = ... new width = ....

*January 4, 2017*

**maths**

original dimensions ---- w by l original area = wl new width = 9w/10 new length = L L(9w/10) = lw L = lw/(9w/10) = (10/9)l = 1.111.. so the length would have to increase, not be reduced, as your question stated. The increase is 10/9 of the original or appr 11.1% check: if wl ...

*January 4, 2017*

**Maths**

(4/3) ? r^3 = 250?/3 4?r^3 = 250? r^3 = 250/4 or 500/8 r = 500^(1/3) / 2 SA = 4? r^2 = 4? (500)^(2/3) / 8 = (1/2)(500)^(2/3) ?

*January 3, 2017*

**Algerbra**

The two areas of similar objects are proportional to the square of their corresponding sides. The two volumes of similar objects are proportional to the cubes of their corresponding sides. sides of model^2 : sides of statue^2 = 6 : 253.5 side of model : side of statue = ?6 : ?...

*January 3, 2017*

**Maths**

looks like your base is x-2 and the height is x, so (1/2)(x)(x-2) = 2.5 x(x-2) = 5 x^2 - 2x - 5 = 0 solve for x and take it from there

*January 3, 2017*

**Mathmatics**

Just re-arrange it .... 3x^2 - x^3 + 3 = 0 -x^3 = -3x^2 - 3 x^3 = 3x^2 + 3 divide both sides by x^2 x = 3 + 3/x^2 let x = 3.2 RS = 3+ 3/10.24 = 3.29296875 sub that into the RS RS = 3 + 3/(3.2929...)^2 = 3.276659... new RS = 3.279420685 new RS = 3.278950402 new RS = 3.279030424...

*January 3, 2017*

**Maths**

your sequence has a = 7, d = 6 term(n) = a+(n-1)d = 7 + 6(n-1) = 7 + 6n - 6 = 6n + 1 term(n+1) = a + (n-2)d = 7 + 6(n-2) = 7 + 6n - 12 = 6n - 5 (6n+1)^2 - (6n-5)^2 = 36n^2 + 12n + 1 - (36n^2 - 60n + 25) = 72n - 24 = 24(3n - 1) which is clearly a multiple of 24 (anything ...

*January 3, 2017*

**Math**

make a sketch and use a simple ratio: h/55 = 8/11 solve for h

*January 3, 2017*

**Math**

f (g(x) ) = (1 + g(x) )/(1 - g(x) ) = (1 + x/(1-x) / (1 - x/(1-x) ) multiply top and bottom by (1-x) = (1 - x + x) / (1 - x - x) = 1/(1 - 2x) check: let x = 2 g(2) = 2/(1-2) = -2 f(g(2)) = f(-2) = (1-2)/(1+2) = -1/3 in mine f(g(2)) = 1/(1-4) = -1/3 it is "highly likely&...

*January 3, 2017*

**geometry**

Follow similar steps I used in your previous post. Make sure you use the definition of supplement of an angle.

*January 3, 2017*

**geometry**

let the angle be x then its complement is 90-x 90-x = x + 18 -2x = -72 x = 36 check: the angle is 36° and its complement is 54° which is 18° more than 36°

*January 3, 2017*

**Geometry**

first transformation: (x,y) ---> (x+5,y) (-3,-3) ----> (2,-3) second transformation: reflection in y = 1 (x,y) ---> (x, 2-y) (2,-3) ----> (2, 5) A' is (2,5)

*January 2, 2017*

**Kudos for Steve**

What a splendid observation ! Ignore my gibberish, it must contain an error somewhere anyhow.

*January 2, 2017*

**maths**

tanx - ?3 + tan2x + ?3tanx tan2x = 0 tanx - ?3 + tan 2x(1 + ?3tanx) = 0 recall tan 2x = 2tanx/(1 - tan^2 x) tanx - ?3 + 2tanx/(1 - tan^2 x)(1 + ?3tanx) = 0 times (1 - tan^2 x) tanx - tan^3 x - ?3 + ?3tan^2 x + 2tanx(1 + ?3tanx) = 0 let tanx = y for easier typing y - y^3 - ?3...

*January 2, 2017*

**algebra**

Can you think of 2 numbers which have a sum of 11 and when multiplied give a product of -42 ? how about -3 and +14 ? Now form the factors

*January 2, 2017*

**algebra**

Steve answered this same question for you over a week ago http://www.jiskha.com/display.cgi?id=1482520904

*January 2, 2017*

**math**

looks like you defined the larger as x and the smaller as y so x - y = 26 is correct then.... "one number is three times the other " ---> x = 3y now sub that into the first equation: x - y = 26 3y - y = 26 2y = 26 y = 13 then x = 3y = 3(13) = 39

*January 2, 2017*

**Algebra**

Why not follow the same steps I showed you for the questions similar to this one. Let me know how you make out.

*January 2, 2017*

**Math :)**

It helps to make a sketch in this case, I assume you did that (-2,-1) ---reflect in y=-5 ---> (-2,-9) notice the midpoint of these points lies on y = -5 (-2,-9) ---reflect in x = 1)---> (4,-9) again, notice the midpoint of these two points lies on the line x = 1

*January 2, 2017*

**trigonomentry**

looks like your equation to solve is incomplete.

*January 2, 2017*

**Math**

Just like in trigonometry, a counterclockwise rotation is considered positive.

*January 2, 2017*

**Algebra**

Start with what I gave you here: http://www.jiskha.com/display.cgi?id=1483383485 Pick any two points on y = ?x e.g. (9,3) and some other point find the equation of the straight line passing through two points, and you are done

*January 2, 2017*

**math**

"the fifth term of an arithmetic progression is 19" ----> a+4d = 19 " the fourteenth term is 55" ----> a+13d=55 subtract the two equations: 9d = 36 d = 4 in a+13d = 55 a + 13(4) = 55 a = 3

*January 2, 2017*

**Algebra**

try y = ?x and y = (1/4)x + 1 see: http://www.wolframalpha.com/input/?i=y+%3D+%E2%88%9Ax+,+y+%3D+(1%2F4)x+%2B+1

*January 2, 2017*

**Math**

15 metres is 1500 cm. So what is 1500/75 ? This is a silly question. The snowball would have hit the ground long before it traveled 15 m due to gravity. The speed of 75 cm/s is way too slow.

*January 2, 2017*

**Math**

What a sucker you would be to play this game! the expected winnings on one play is 15 cents. You are playing this 30 times, so your can expect to win $4.50 , but you spent $30 to play those games.

*January 2, 2017*

**@ R**

Why did you repost this question ?? Just noticed that Steve answered it for you several days ago http://www.jiskha.com/display.cgi?id=1483135842

*January 2, 2017*

**Math**

Assuming you meant: f(x)=?x^3 ?x^2 +16x+16 f ' (x) = -3x^2 - 2x + 16 f ''(x) = -6x - 2 If you are studying Calculus or Pre-Calculus, you MUST know how to do this. if f(x) = 0 ?x^3 ?x^2 +16x+16 = 0 x^3 + x^2 - 16x - 16 = 0 by grouping, x^2(x+1) - 16(x+1) = 0 (x+1)(x...

*January 2, 2017*

**Math**

No idea what a "tape diagram" is, but the question is easy to solve in the traditional way: number of adults ---- 45 number of students ---- 90 Just noticed that there is NO question in your post. If you want the return for the museum Return = 25(45) + 12(90) = $2205

*January 2, 2017*

**math C2 sequences and series**

8th term of AS = a+7d 4th term of AS = a+3d 2nd term of AS = a+d then, if they form the first three terms of a GS (a+3d)/(a+7d) = (a+d)/(a+3d) (a+3d)^2 = (a+7d)(a+d) a^2 + 6ad + 9d^2 = a^2 + 8ad + 7d^2 2d^2 - 2ad = 0 d(d-a) = 0 d = 0 or d = a but we are told that d ? 0 , so d...

*January 2, 2017*

**Math**

what is 100000(.95)^2 ?

*January 1, 2017*

**Math**

let the number be x 1/(x-4) = 2(1/x) solve for x

*January 1, 2017*

**Geometry**

Did you know that the slope of a line equals the tangent of the angle that the line makes with the x-axis ? so tan45° = 1 so we know the slope of the line is 1 (-5-5)/(a-4) = 1 a - 4 = -10 a = -6 Check with a quick sketch of the situation.

*January 1, 2017*

**math**

Even though with only 3 terms, 20 + 12 + 36/5 + .... seems to be the sum of an infinite series with a = 20 and r = .6 Sum(all terms) = a/(1-r) = 20/(1-.6) = 20/.4 = 50 btw, " ---tend as n" makes no sense.

*January 1, 2017*

**Math**

4d^2= (d+4)(-d+12) 4d^2 = -d^2 + 12d - 4d + 48 5d^2 - 8dd = 48 d^2 - (8/5)d = 48/5 d^2 - (8/5)d + 16/25 = 48/5 + 16/25 (d - 4/5)^2 = 256/25 d - 4/5 = ± 16/5 d = 4/5 + 16/5 OR d = 4/5 - 16/5 d = 4 or d = -12/5

*January 1, 2017*

**math**

Well, did you use your graph as instructed? What did you get?

*January 1, 2017*

**Math**

let the tens digit be x, and the unit digit be y So the number is 10x + y, the number reversed is 10y + x 10x+y - (10y+x) = 9 9x - 9y = 9 x - y = 1 or x = y+1 ** 2x = 7y-8 sub in ** 2(y+1) = 7y - 8 2y + 2 = 7y - 8 -5y = -10 y = 2 The number is 32 check: the number reversed is ...

*January 1, 2017*

**math(geometric series)**

2nd term is 3/2 --- ar = 3/2 sum of all terms is 8 a/(1-r) = 8 divide the first equation by the 2nd equation: (ar) / (a/(1-r)) = (3/2) / 8 r(1-r) = 3/16 r - r^2 = 3/16 3 = 16r - 16r^2 16r^2 - 16r + 3 = 0 (4r - 1)(4r - 3) = 0 r = 1/4 or r = 3/4 check for r = 1/4 a(1/4) = 3/2 a...

*December 31, 2016*

**math(A.P/G.P)**

Shall I assume that 2% p.a C.I means 2% per annum compounded instantaneously ? the amount = 55 e^.02t if 2005 ---> t = 0 then 2015 --- t = 10 amount = 55 e^(.02(10)) = 67.177 crores (is 1 crore equal to 10 million? I see one answer as 6700, but that would not match your ...

*December 31, 2016*

**Algebra**

for 1st series: first term is a, common difference is d sum(n) = (n/2)(2a + d(n-1)) for 2nd series: first term is b, common difference is e sum(n) = (n/2)(2b + e(n-1)) (n/2)(2a + d(n-1)) / (n/2)(2b + e(n-1)) = (7n+1)/(4n+27) (2a + dn - d)/ (2b + en- e) = (7n+1)/(4n+27) 8an + ...

*December 31, 2016*

**Math**

The way you typed it, and following the order of operation ... 100-100/100-100 = 100 - 1 - 100 = -1

*December 29, 2016*

**mathematics**

look at the second part of this post http://www.jiskha.com/display.cgi?id=1482579345

*December 24, 2016*

**maths**

No zero in single digit numbers For double digit numbers: 10, 20 .. , 90 ---> 9 of them triple digits: using 2 zeroes: 100, 200, 300, 400, 500 --- 10 of them using 1 zero: case 1: the zero in 2nd place = 5 x 1 x 9 = 45 case 2: the zero in 3rd place = 5 x 9 x 1 = 45 total = ...

*December 24, 2016*

**MATH**

The change is caused by the term -3x Since you are "decreasing" x by 2 we sub in x = -2 so y = 42 - 3(-2) = 42 + 6 thus the change is 6

*December 24, 2016*

**ellipse**

alternate solution for B: let's "move" everything to standard position using (x,y) ---> (x+1, y-2) centre (-1,2) ---> centre (0,0) F(-1,5) ----> focus( 0, 3) , so c = 3 P(5,6) -----> P' (6, 4) b^2 = a^2 + c^2 = a^2 + 9 starting equation: x^2 /a^2...

*December 24, 2016*

**ellipse**

A) centre at (-2,3) --> (x+2)^2 /a^2 + (y-3)^2 / b^2 = 1 focus at (-2,7) implies the ellipse is vertical and c = 7-3 = 4 vertex is (-2,10) , so a = 10=3 = 7 and a^2 + c^2 = b^2 7^2 + 4^2 = b^2 = 65 (x+2)^2 /49 + (y-3)^2 / 65 = 1 B) centre (-1,2) ---> (x+1)^2/a^2 + (y-2)^...

*December 24, 2016*

**algebra**

I see 2c^3 as a common factor = 2c^3(a^2 - 7b + 16d^2)

*December 22, 2016*

**math**

a1 = 13 a2 = 15 = a1 + 2 a3 = 17 = a2 + 2 ... an = an-1 + 2 , n > 1

*December 22, 2016*

**small correction - QUADRILATERAL MATHS**

For the last method, I meant to say : " list the coordinates of the quadrilateral counter-clockwise starting with any point in a column. "

*December 22, 2016*

**QUADRILATERAL MATHS**

There are several ways to do this: 1. If you join AC, you have a right-angled triangle ABC. Find the length of AB and BC and use area = (1/2)base x height for its area. Find angle D by using the slopes of AD and CD, find the lengths of CD and AD , then area of triangle ACD = (...

*December 22, 2016*

**math**

look at the last 4 answers below under Related Questions.

*December 22, 2016*

**math**

Sketch your three intersecting circles, V, B, and T place 20, 10 and 6 in the "only" part of the circles. Place 4 in the intersection of all circles. Place x in the remaining parts of the circle. Add up all the parts: x + x + x + 4 + 20 + 10 + 6 = 70 3x + 40 = 70 3x...

*December 22, 2016*

**calculus**

looks like a homework dump. Five questions without showing us any of your starting steps or any indication where your problems lie with these questions.

*December 21, 2016*

**calculus**

find the derivative, set that equal to zero and solve for x sub back into original f(x) to find the matching y values. also find the end values of f(-2) and f(4) , then decide which are your max/mins.

*December 21, 2016*

**calculus**

let the two numbers be x and y xy = 16 y = 16/x Let S be the sum of their squares S = x^2 + y^2 = x^2 + 256/x^2 = x^2 + 256x^-2 dS/dx = 2x - 512x^-3 = 2x - 512/x^3 = 0 for a min of S 2x = 512/x^3 2x^4 = 512 x^4 = 256 x = ±4 then 16/±4 = ±4 the two numbers ...

*December 21, 2016*

**math**

Or did you notice that each of the given numbers is one more than the perfect square, that is 2 = 1^2 + 1 5 = 2^2 +1 10 = 3^2 + 1 17 = 4^2 + 1 thus: term(n) = n^2 + 1

*December 21, 2016*

**math connections**

solve -4n + 7 + 2n=1 ---> -2n = -6 n = 3 solve 4(y-4)=8 divide by 4 y-4 = 2 y = 6

*December 21, 2016*

**Math**

let the distance traveled by car X be x km let the distance traveled by car Y by y km their paths form a right-angled triangle. Let the distance between them be D km D^2 = x^2 + y^2 2D dD/dt = 2x dx/dt + 2y dy/dt dD/dt = (x dx/dt + y dy/dt)/D at the given case: x = 60, y = 80...

*December 20, 2016*

**math**

effectively he gains 10 m every 2 minutes but for the last 10 m he does not have to rest 1 minute to reach his goal. That is, at the end of 2 minutes, he has gone 10 m 4 minutes, he has gone 20 m ... 36 minutes, he has gone 180 m Since he can swim 20 m per minute, he will ...

*December 20, 2016*

**pre calculus**

Ok, Meredith, after doing this one for you http://www.jiskha.com/display.cgi?id=1482199382 surely you can follow the same steps for this one.

*December 19, 2016*

**Business Finance**

ummmhhh, for 5 years, for 2 years, for 20 years ??? The question is incomplete.

*December 19, 2016*

**Business Finance**

You did not state the time period

*December 19, 2016*

**math**

Prob(sum of 2) = 1/36 prob(sum of 3 ) = 2/36 prob(sum of 4) = 3/36 prob(sum of 5) = 4/36 prob(sum of 6) = 5/36 prob(sum of 7) = 6/36 ... sum of 8 = 5/36 ... sum of 9 = 4/36 ... sum of 10 = 3/26 ... sum of 11 = 2/36 ... sum of 12 = 1/36 notice the sum of these prob's is 1 ...

*December 19, 2016*

**Maths**

I will do the first one, you do the other two in the same way. let the width be x let the length be 2x, notice x : 2x = 1 : 2 2(x) + 2(2x) = 30 5x = 30 x = 6 sides are 6 cm and 12 cm, with an area of 72 cm^2

*December 19, 2016*

**business math**

i = .055/365 = .000150684 amount after 21 days = 6000(1.000150684)^21= 6019.01 So what interest did she earn ?

*December 19, 2016*

**Write the system of equations as an augmented matr**

-4 -1 | -6 -8 -5 | -6

*December 19, 2016*

**Pre calculus**

recall: sinØ = y/r and cosØ = x/r so: r= 5/(sin theta +2cos theta) r = 5/(y/r + 2x/r) r = 5/((2x+ y)/r) r = 5r/(2x + y) 1 = 5/(2x+y) 2x + y = 5 <----- a straight line proof: http://www.wolframalpha.com/input/?i=polar+plot+r%3D+5%2F(sin+theta+%2B2cos+theta)

*December 19, 2016*

**data management gr.12**

Your question is perfectly suited for this applet http://davidmlane.com/normal.html Just enter your data

*December 19, 2016*

**pre calculus**

Steve has the correct equation. I don't know why my 8 was dropped in my 3rd last line, just careless.

*December 19, 2016*

**pre calculus**

from your previous question, recall sinØ = y/r --> y = rsinØ cosØ = x/r --> x = rcosØ (x-4)^2+y^2=16 (rcosØ -4)^2 + r^2sinØ = 16 r^2 cos^2 - 8rcosØ + 16 + r^2sin^2 Ø = 16 r^2 (cos^2 Ø + sin^2 Ø) - rcos...

*December 19, 2016*

**data management gr.12**

See the webpage I gave you in your other post

*December 19, 2016*

**Trigonometry**

tan(Ø - 30) = -5 we know tan 78.69° = +5 and since the tangent of our given angle of Ø-30 is negative it must be quadrants II or IV Ø-30 = 180-78.69 = 101.31 Ø = 101.31+30 = 131.3° ir Ø-30 = 360 - 78.69 = 281.3 Ø = 311.3°

*December 19, 2016*

**Engineering Mathematics-I**

First you need the intersection (2x^2)^2 = 4x 4x^4 - 4x = 0 x(x^3 - 1) = 0 x=0 or x = 1 see: http://www.wolframalpha.com/input/?i=y%3D2x%5E2+,+y%5E2%3D4x effective height = ?(4x) - 2x^2 = 2 x^(1/2) - 2x^2 area = ?(2 x^(1/2) - 2x^2) dx from x = 0 to 1 = [ (4/3)x^(3/2) - (2/3)x^...

*December 17, 2016*

**Maths**

original fraction ----- 5x/2x new fraction: (5x+5)/(2x-2) I can't make out what 15 4 is supposed to be. Once you have decided, set that equal to (5x+5)/(2x-2) , looks like you would just cross-multiply to solve

*December 17, 2016*

**Math**

width --- 5x length ---8x (5x)(8x) = 169 40x^2 = 169 x^2 = 169/40 x = 13/?40 width is 65/?40 = appr 10.28 length is 104?40 = appr 16.44 check: area = (65/?40)(104/?40) = 6760/40 = 169 ratio = (65/?40) : 104/?40) = 65 : 104 = 5 : 8

*December 16, 2016*

**math-circles**

The areas of two circles are proportional to the square of their raddi so r1^2 / r2^2 = 9/4 r1/r2 = 3/2 r1 = 3r2/2 also r1 = r2 + 2 Thus: 3r2/2 = r2 + 2 3r2 = 2r2 + 4 r2 = 4 then r1 = 6 the larger radius is 6 units check: area of larger = 36? area of smaller is 16? ratio of ...

*December 16, 2016*

**Math**

sequence is : 3/4 , 1/4, 1/12, 1/36 = 27/36 , 9/36, 3/36, 1/36, ... = (1/36){ 27, 9, 3, 1, ......} can you see the pattern in 27, 9, 3, 1, .... ??

*December 16, 2016*

**maths**

volume of original sphere = (4/3)? R^3 volume of each of the 1000 smaller ones = (4/3000)? R^3 = (1/750) ? R^3 let the radius of the smaller be r 4/3 ? r^3 = (1/750) ? R^3 r^3 = (1/1000) R^3 r = R/10 surface area of smaller = 4? r^2 = 4? R^2/100 = ? R^2/25

*December 16, 2016*

**Math**

first number ---- x 2nd number ----- x+5 x + x+5 = 57 carry on

*December 16, 2016*

**Math algebra**

A quick check with your notes or textbook would have shown this to be a clear case of the distributive property.

*December 16, 2016*

**precalculus**

#1 term(5) = C(8,4) (2x)^4 (-4)^4 = 70(16x^4)(256) = 286720 x^4 <-------- B general term of (a+b)^n: term (k+1) = C(n,k) * (a)^(k-1) * b^k #2, correct

*December 16, 2016*