Saturday
May 18, 2013

# Posts by Reiny

Total # Posts: 22758

math
x^2 + y^2 = 100 , where x is the base, y the height 2x dx/dt + 2y dy/dt = 0 given: dx/dt = 2 , and x = 6 then 36+y^2 = 100 y^2 = 64 y = 8 in 2x dx/dt + 2y dy/dt = 0 2(6)(2) + 2(8)dy/dt = 0 dy/dt = -24/16 = -3/2 it is sliding down at 3/2 m/sec

math
let y = (14sinØ + 5cosØ)^2 dy/dx = 2(14sinØ + 5cosØ)(14cosØ - 5sinØ) = 0 for a max/min of y so 14sinØ = -5cosØ = 0 or 14cosØ = 5sinØ first case: sinØ/cosØ = -5/14 tanØ = -5/14 Ø =...

Algebra
I assume the 2 is the base of the log log2(y^5) = 5log2y

Algebra
ln x = -4/9 e^(-4/9) = x my calculator says x = appr .64

Math
draw a line, marking off the times of 8:00 am, 10:00 am, and noon (12:00) "At 12 noon, Leslie recorded the temperature as 56 degree Fahrenheit" ----> put 56 over 12:00 "The temperature had increased by 8 degree Fahrenheit from 10 a.m. " ---> what is 5...

Math
see http://www.jiskha.com/display.cgi?id=1367299682

Calculus 1
the first term is easy the derivative of 5e^x is 5e^x so the integral of 5e^x is 5e^x now look back at your derivatives of basic trig functions isn't derivative of secx = secxtanx ? We have that term so the integral of secxtanx would be secx thus the integral of -2secxtanx...

algebra
dimes -- x nickels -- x+3 quarters --- 38-x-(x+3) = 35-2x 10x + 5(x+3) + 25(35-2x) = 795 10x + 5x + 15 + 875 - 50x = 795 -35x = -80 no integer solution, so the question is flawed. check my arithmetic, and check your typing

Calculus
really no steps needed recall that derivative of ln(u) is u'/u I recognize that pattern so if y' = 3/(3x+5) then y = ln(3x+5) + c

Calculus
I used an intuitive approach. as x --> 0 , sinx ---> 0 ,but not quite anything raised to the zero is 1 (except 0^0 is undefined) try this on your calculator .... set it to radians take sin(.000001)^.000001 to get .999986184 take sin(.00000001)^.00000001 to get .999999815...

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