Saturday

December 3, 2016
Total # Posts: 36,897

**maths**

OK, even though have always been told that we can't add apples and oranges, ..... let the amount of apples be x lbs amount of oranges ----- (52 - x) lbs 5.25x + 3.8(52-x) = 4.25(52) 5.25x + 197.6 - 3.8x = 221 1.45x = 23.4 x = 16.1 lbs of apples and 35.9 lbs of oranges appr...

*November 22, 2016*

**math**

cost = 7.2(12) = 86.4 18 eggs = 1.5 dozen so you sold 10.5 dozen at 7.5 return = 10.5(7.5) = 78.75 loss = 86.4 - 78.75 = 7.65

*November 22, 2016*

**Maths**

Four times as much, or 32 kg Can you show me why that is so?

*November 22, 2016*

**maths**

volume of ball = (4/3)?(4.5)^3 So that is the change in volume in the cylinder once removed ?(6^2) h = (4/3)?(9/2)^3 36h = (4/3)(729/8) = 243/2 h = 243/72 = 27/8 the water will fall 27/8 cm or 3.375 cm check my arithmetic.

*November 22, 2016*

**Algebra 1**

The boat will be .15 miles from Ellen coming and going away. So 1 - 70t = .15 OR -1 + 70t = .15 t = .01214... hrs or t = .01642.. hrs t = .01214(3600) sec or t = .01642(3600) sec t = 43.7 sec OR t = 59.1 sec

*November 22, 2016*

**check - Math**

ok, the cat's were adopted, that means the count was reduced by 120, not increased. I read the question incorrectly number of cats after adoption = 2x - 120 make the simple change in the equation and solve

*November 22, 2016*

**Math**

number of cats ---- 2x number of dogs ----3x after adoption: number of cats = 2x + 120 (2x+120) : 3x = 3 : 7 (2x+120)/(3x) = 3/7 14x + 840 = 9x 5x = -840 x is a negative, which is not possible. notice 2:3 = .66.. and 3:7 = .42 , which is < 2/3 How can the ratio of cats : ...

*November 22, 2016*

**maths**

Area of a triangle = (1/2)(ab)sinØ where a and b are sides with Ø as the angle between them. Your data is perfectly suited for that formula

*November 22, 2016*

**found my error - Go with Steve - maths need help**

The second equation had addition, I read it as another subtraction.

*November 22, 2016*

**maths need help**

Log (a+3) (base 9) - log b(base 9)= c + (1/2) log9 (a+3) - log9 b = c+1/2 log9 ((a+3)/b) = c+1/2 ---> 9^(c+1/2) = (a+3)/b 3^(2c+1) = (a+3)/b ** log (a-3) (base 3) + log b (base 3)=c - 1 log3 (a-3)+ log3 b = c-1 log3 ( (a-3)/b )= c-1 --> 3^(c-1) = (a-3)/b *** divide ** by...

*November 22, 2016*

**Math**

let the roots of ax^2+bx+c=0 be m and n then m:n = r:1 m/n =r/1 m = rn sum of roots = m+n = rn + n = n(r+1) = -b/a ** product of roots = mn = n^2 r = c/a *** divide ** by *** (r+1)/nr = (-b/a) / (c/a) = -b/c rc + c = -bnr rc + bnr = -c r(c + bn) = -c r = -c/(c+bn) For acr^2+(...

*November 21, 2016*

**math**

A standard rotation is 2?. So whatever angle you have either adding or subracting multiples of 2? will yield a coterminal angle. e.g 8?/3 -----> think 480° 8?/2 - 2? = 2?/3 -----> think 120° 8?/3 + 2? = 14?/3 -----> think 840° 8?/3 - 4? = -4?/3 -----> ...

*November 21, 2016*

**calculus**

c(x)=3x^3 - 12x^2 +9000x c ' (x) = 9x^2 - 24x + 9000 = 0 for a max/min of c(x) 9x^2 - 24x + 9000 = 0 This equation has no real solution. c(0) = 0, for all values of x > 0, c(x) increases so our minimum cost is when we don't produce anything, (that actually makes ...

*November 21, 2016*

**Math**

If you are referring to your previous post, look at my reply to it.

*November 21, 2016*

**Math**

For any number to be divisible by 6, it must be divisible by both 2 and 3 To be divisible by 2, the unit digit must be even or zero, so that eliminates A - 5. To be divisible by 3, the sum of the digits must be a multiple of 3 (divisible by 3) Since we have a sum of 8 for the ...

*November 21, 2016*

**Algegra**

So let's just change Ax + By = C to the form y = mx + b Ax + By = C By = -Ax + C divide each term by B y = (-A/B)x + C/B So compare that to y = mx + b m = -A/B so I have just developed a quick way to find the slope of any equation in general form e.g. 7x + 9y = 17 has slpe...

*November 21, 2016*

**Math**

so with her new test, there will be 6 tests (sum of what you have so far + x)/6 = 69 solve for x

*November 21, 2016*

**maths**

original fraction --- x/y first new fraction: (x+1)/(y+1) = 2/3 3x + 3 = 2y + 2 3x - 2y = -1 ** second new fraction: (x-2)/(y-2) = 3/5 5x - 10 = 3y - 6 5x - 3y = 4 *** solve the two equations ** and ***

*November 21, 2016*

**mathematical methods for economics**

Did you try Venn diagrams? Start filling in from the intersection of all three circles. Put 50 in that intersection, then work your way outwards from there.

*November 21, 2016*

**Math, Surds**

let the length of each side be s s^2 = 60 s = ?60 = ?4*?15 = 2?15 each side is 2?15 m perimeter = 8?15 m

*November 21, 2016*

**Mathss**

If you have a right-angled triangle, the area is (1/2) base x height You have the base and height, clearly 65 will not be used since it is the hypotenuse. So go for it. For the second, if you have two sides and the contained angle, then the area is (1/2)(a)(b)sinØ, ...

*November 21, 2016*

**maths**

The first two triangles are clearly right-angled. Is the third one ? is 65^2 = 33^2 + 56^2 ??, YES So make sketches of each one. for a) I labeled by triangle ABC, where a = 30 angle A = 90, and angle B = 30° sin35° = 30/b bsin35 = 30 b = 30/sin35 = appr 52.30 tan35 = ...

*November 21, 2016*

**MATHS**

All of the trig ratios shown are based on "standard" angles. We used to have math kits that contained a compass, a protractor and two triangles. One had angles 45-45-90°, the other had 30-60-90° The ratio of sides of the 30-60-90 were 1 : ?3 : 2 and for the ...

*November 21, 2016*

**Math probability**

prob(big winner) = 1/C(68,5) = 1 / 10,424,128 = appr .000,000,1

*November 20, 2016*

**algebra**

first number ---- x second number --- x+9 third number ----- 82 - x - x - 9 = 72 -2x all three numbers are expressed in terms of one variable: x , x+9, and 72-2x

*November 20, 2016*

**algebra 1**

just subtract them: 10y = -10 y = -1 plug that into the first: -4x + 7(-1) = -3 -4x = -3+7 = 4 x = -1 x = -1, and y = -1

*November 20, 2016*

**Math**

There are no "points in the table below"

*November 20, 2016*

**Math**

y+x =10 y - x = 20 add them: 2y = 30 y = 15 15+x = 10 x = -5 x = -5, y = 15

*November 20, 2016*

**Life Science Math**

acceleration --- a then v = at + c at the start, t = 0, and v=0 0 = 0 + c ---> c = 0 so v = at when t = 3 sec = 3/3600 hrs or 1/1200, v = 60 60 = a(1/1200) a = 72000 ------> v = 72000t if s is the distance travelled , s = 36000t^2 + k when t = 0 , s = 0, so k = 0 s = ...

*November 20, 2016*

**f math**

I will assume that by t ta you mean Ø so sin(90 - 5Ø) = cos(180 - Ø) but sin(90 - 5Ø) = cos Ø just like sin(90 - 30) = cos30 so we have cos(5Ø) = cos(180-Ø) take arccos of both sides 5Ø = 180-Ø 6Ø = 180 &...

*November 20, 2016*

**f math**

What is "t ta" ?? Where does "d" enter the picture?

*November 20, 2016*

**Math**

agree with C I did not answer the question that was asked My 4 slices would represent 1/2 of an 8 slice pizza.

*November 20, 2016*

**Math**

If each pizza is cut into 8 slices, then in the 7 pizzas there are 56 slices So each of the 14 student would get 56/14 or 4 slices. You did not post any "answer choices", so I hope 4 is in there.

*November 20, 2016*

**Math**

let one number be x let the other be x+7 x + x+7 = 63 solve for x, and all that is unknown shall be revealed.

*November 20, 2016*

**Math**

Done the way you typed it: |1-15x/5| < 3 1 - 15x/5 < 3 AND -1 + 15x/5 < 3 -3x < 2 AND 3x < 4 x > -2/3 AND x < 4/3 What you probably meant: | (1-15x)/5 | < 3 (1 - 15x)/5 < 3 AND (-1 + 15x)/5 < 3 1 - 15x < 15 AND -1 + 15x < 15 -15x < 14 AND...

*November 20, 2016*

**Math Quadratic Equations . URGENT!!!!**

look back when you posted this earlier

*November 20, 2016*

**Trig**

Did you make a sketch? I followed your labels and let the base of the building be B in triangle DAB, tan30 = DB/30 DB = 30tan30° = ... in triangle CAB, tan 60 = CB/30 CB = 30tan60 = ... CD = CB - DB = ....

*November 20, 2016*

**Math**

correct, ***80 is the only one divisible by 4

*November 20, 2016*

**Math**

A number is divisible by 4 if its last two digits are divisible by 4, or the last two digits are zeros. I see only one such case

*November 20, 2016*

**Math, Quadratic equations**

this was answered when you were Rachel.

*November 20, 2016*

**Math, Quadratic equaitons**

your data does not match the equation , so I don't know which is the correct one I will go with the equation: h = -4t^2 + 8.1t + 3 , (according to your data it would be 8.2t) when h = 6 6 = -4t^2 + 8.1t + 3 4t^2 - 8.1t + 3 = 0 using the formula: t = (8.1 ± ?17.61)/8...

*November 20, 2016*

**College Math**

You are partly on the right track. The C(13,7) is the number of to choose 7 of the 13 marbles. you want the case of 3 reds plus 4 non-reds prob(your stated event) = C(3,3)*C(10,4)/C(13,7) = 1*210/1716 = 35/286

*November 20, 2016*

**f math**

1 - cos^2 x = 0 , for 0 ? x ? 270° cos^2 x = 1 cos x = ± 1 now look at the cosine curve. Where is the y equal to either +1 or -1 within your domain ?

*November 20, 2016*

**Calculus**

y = ln(sint) dy/dt = (1/sint)(cost) = cost/sint for x= cos^2 t = (cost)^2 dx/dt = 2cost(-sint) (dy/dt) / (dx/dt) = (cost/sint) / (-2sintcost) dy/dx = -1/(2 sin^2 t) = (-1/2)(sint)^-2 d(dy/dx) / dx = (-2)(-1/2)(sint)^-3 (cost) = cost / sin^3 t sub in t = ?/4 d(dy/dx) / dx = (?2...

*November 20, 2016*

**Maths**

remember that sinx = cos(90-x) - property of complementary angles, "co-sine" vs sine Your statement is only true if (cos40-sin30)/(sin60-cos50) =tan50 , but not the way you typed it. cos40 = sin50 and sin60 = cos30 so LS = (sin50 - sin30)/(cos30 - cos50) remember ...

*November 20, 2016*

**Math**

let the obtuse angle be A and its opposite diagonal be x. By the cosine law: x^2 = 45^2+28^2-2(48)(28)cosA similarly... y^2 = 45^2+28^2-2(48)(28)cosB but A+B = 180 B=180-A and cosØ = -cos(180-Ø) by the CAST rule e.g. cos 60 = - cos120 then cos B = -cosA x^2+y^2...

*November 19, 2016*

**math**

original fraction: x/y case1 (x+5)/(y+5) = 1/2 2x + 10 = y+5 2x - y = -5 ** case2 (x-1)/(y-1) = 1/5 5x - 5 = y - 1 5x - y = 4 *** subtract ** from *** 3x = 9 x = 3, then from ** 6 - y = -5 , y = 11 the original fraction was 3/11 check: (3+5)/(11+5) = 8/16 = 1/2, check! (3-1)/(...

*November 19, 2016*

**Math Quadratic Functions**

A squaring of the input value is involved. A rather vague question.

*November 19, 2016*

**math**

just like in 5/6 - 3/7 you will need a common denominator. In my example, it would be 42? How did I get 42 ? Next step 35/42 - 18/42 ---> how did I get those fractions = 17/42 Now to your problem 5/(x-2) - 4(x-3) LCD = (x-2)(x-3) ---> same step as above e.g = 5(x-3)/((x-...

*November 19, 2016*

**Calculus**

I will assume you are saying $1 per square foot let the base be x ft by x ft, let the height be y area of top and 4 sides = x^2 + 4xy cost of top and 4 sides = 1(x^2 + 4x) = x^2 + 4xy area of base = x^2 cost for the base = 2x^2 total cost = 3x^2 + 4xy = 114 y = (114 - 3x^2)/4x...

*November 19, 2016*

**Math (Calculus) (mean value theorem emergency)**

your secant equation is correct checking the other parts: f '(x) = 2x - 1 ---> you had that setting that equal to 1, since the slope of our secant is 1 2x-1 = 1 2x = 2 x = 1 so all you have to do is sub that back into the original f(1) = 1 - 1 - 12 = -12 So the point ...

*November 19, 2016*

**algebra**

no Why do you think it is C or are you just guessing?

*November 19, 2016*

**algebra**

no , B does not have the necessary brackets

*November 19, 2016*

**algebra**

if the point is (a,b) and the slope is m then the equation is y - b = m(x - a) now which one of the given answers follows that pattern?

*November 19, 2016*

**Math help pls. !!**

(2x-3)(5x+2)=0 This is only possible if one or more of the given factors equal zero. But we don't know which one, so 2x-3 = 0 OR 5x+2=0 2x = 3 OR 5x = -2 x = 3/2 or x = -2/5

*November 19, 2016*

**Math**

(1/2)x^2 - 2x = 6 times 2 x^2 - 4x = 12 x^2 - 4x - 12 = 0 it factors: (x - 6)(x + 2) = 0 now follow the steps I showed you here http://www.jiskha.com/display.cgi?id=1479598571

*November 19, 2016*

**math**

number of digits = 3x2x1 = 6 , we could actually list them 137 173 317 371 713 731 Here is a list of primes: http://primos.mat.br/indexen.html you will find that all are prime except 371, 713 and 731 731 =17 x 43 713 = 23 x 31 371 = 7 x 53

*November 19, 2016*

**math algebra**

I did this when you were rita http://www.jiskha.com/display.cgi?id=1479589996

*November 19, 2016*

**FUNCTIONS HELPPPPP????**

After seeing how you responded to Steve when he helped you with this question .... http://www.jiskha.com/display.cgi?id=1479505703

*November 19, 2016*

**Math**

Volume of cylinder = ?(r^2)(h) plug in your values.

*November 19, 2016*

**math algebra**

rate of gandola in still water --- x mph speed of current ---- y mph time to go 2.8 miles with the current = 2.8/(x+y) time to go 2 miles against the current = 2/(x-y) they are the same! 2.8/(x+y) = 2/(x-y) 2.8x - 2.8y = 2x+2y .8x = 4.8y 8x = 48y x = 6y or y = (1/6)x All we ...

*November 19, 2016*

**math algebra**

Gray's rate = 1/15 Anna' rate = 1/20 Job done by Gray = 6(1/15) = 2/5 leaving 3/5 of the job left to be done by Anna time for Anna to complete = (3/5) / (1/20) = 12 It will take her 12 days to finish the roof

*November 19, 2016*

**Math**

6 1/7 - 1 5/21 = 43/7 - 26/21 = 129/7 - 26/21 = 103/21

*November 19, 2016*

**math algebra**

assuming that you meant: f(x) = (x+1)/(x^2-9) and g(x) = x/(x-3) The domain for both f(x) and g(x) are all values of x except those that make the denominator zero domain of f(x): all x's except x = ±3 domain of g(x): all x/s except x = 3 (f+g)(x) = (x+1)/(x^2 - 9...

*November 19, 2016*

**math - business**

Steve is probably off line now, so I will answer. For any quadratic function of the form y = ax^2 + bx + c the x of the vertex is -b/(2a), once you have the x you just sub that back into the equation to get the y of the vertex. In your case: P = -.005x^2 + 4x - 200 a = -.005 b...

*November 19, 2016*

**GEOMETRY**

You have similar triangles. Since XA = AY AY : XY = 1 : 2 triangle XYZ is similar to triangle AYB XZ/XY = AB/AY 8.4/2 = AB/1 AB = 8.4/2 = 4.2

*November 19, 2016*

**Algebra**

3n^2+5n-100=? If this is a quadratic equation, the your ? is 0 If you are dealing with the corresponding quadratic function you would normally find it as y = 3n^2 + 5n - 100 , where y is the dependent variable, and n is the independent variable What about it ?

*November 19, 2016*

**Pre-calculus**

Watch those brackets, you must have meant: (sin(x+y)+sin(x-y))/(cos(x+y)+cos(x-y))=tanx LS = (sinxcosy + cosxsiny + sinxcosy - sinxcosy)/(cosxcosy - sinxsiny + cosxcosy + sinxsiny) = 2sinxcosy/(2cosxcosy) = (sinx/cosx)(cosy/cosy) = tanx = RS

*November 19, 2016*

**Pre-calculus**

I checked with my calculator and actually found the angles. It works !!!

*November 19, 2016*

**Pre-calculus**

If siny = -2/?13 , and coty ?0, then y is in quad III so cosy = -3/?13 then sin 2y = 2sinycosy = 2(-2/?13)(-3/?13) = 12/13 cos 2y = cos^2 y - sin^2 y = 9/13 - 4/13 = 5/13 so sin 2y = 12/13 and cos 2y = 5/13 if sin 2x = 7/25 remember cos^2 (2x) = 1 - sin^2 (2x) = 1 - 49/625 = ...

*November 19, 2016*

**Probability Help**

at least one boy ----> exclude the case of all 5 girls, which is (1/2)^5 = 1/32 prob(at least one boy in 5) = 1 - 1/32 = 31/32

*November 19, 2016*

**Math**

A:B:C = 5:5:7 or 5x : 5x : 7x Cindy ate 30 Skittles less than Ann and Ben together -----> 7x = 5x + 5x - 30 -3x = -30 x = 10 5x = 50 7x = 70 They ate 50+50+70 = 170 of them

*November 18, 2016*

**Calculus**

g(x) = sinxcosx g ' (x) = sinx(-sinx) + cosxcosx = cos^2 x - sin^2 x = cos 2x at x = ?/3 g '(x) = cos (2?/3) = -.5 equation: y - ?3/4 = (-1/2)(x - ?/3) So I agree with your answer. for a max/min of g(x) , g '(x) = 0 cos 2x = 0 2x = ?/2 or 2x = 3?/2 x = ?/4 or x = 3...

*November 18, 2016*

**Calculus**

with the information given, you should be able to form the equation h = -16t^2 + 68t + 6 dh/dt = -32t + 68 = 0 for a max of h 32t = 68 t = 2.125 evaluate h when t = 2.125

*November 18, 2016*

**argghh - Calc**

forgot to change the units from km/h to m/s go with Damon's answers

*November 18, 2016*

**Calc**

if we have acceleration of a, then v = at + c case1: when t=0, v=25 25 = 0+c ---> v = at + 25 so when t = 13, v = 90 90 = 13a + 25 a = 65/13 = 5 m/s^2 -----> v = 5t + 25 distance = (5/2)t^2 + 25t + k when t=0 , distance = 0 , so k = 0 distance = (5/2)t^2 + 25t when t = ...

*November 18, 2016*

**Math**

I agree with all of them

*November 18, 2016*

**Math**

amount taken out as loan = 25 - .2(25) = 20 or just take .8(25) = 20 amount owing after 8 years = 20(1.025)^8 = 24.368 gh cedis

*November 18, 2016*

**Math**

1 7/10 = 17/10 "as many" suggests multiplication e.g. bill eats 3 times as many donuts as Bob if Bob eats 4 donuts, then Bill would eat 3*4 or 12 donuts so Elizabeth has (17/10) as many as Rosalie. let Rosalie's number of plants be x then: (17/10)x = 51 ----> ...

*November 18, 2016*

**Math**

time for first trip = d/x time for return = d/y total time = (d/x + d/y) = (dy + dx)/(xy) = d(x+y)/(xy) total distance = 2d average speed = 2d/( d(x+y)/(xy) ) = 2xy/(x+y) = 50 xy/(x+y) = 25 xy = 25x + 25y 25y - xy = 25x y(25 - x) = -25x y = 25x/(x-25) e.g. let x = 50, then y...

*November 18, 2016*

**math**

horizontal path = 15(2.5) = 37.5 units^2 vertical path = 9(2.5) = 22.5 units^2 total = 60 units^2 BUT, we counted the intersection of the paths twice, so we have to subtract 2.5(2.5) or 6.25 units^2 leaving us with 63.75 units^2

*November 18, 2016*

**Geometry**

So what is (3/2)(4.8) ? Just add up your 4 sides, remember they come in equal pairs.

*November 18, 2016*

**Order MATH!**

I suggest you change them all to decimals, and then it is easy to see.

*November 18, 2016*

**Pre-calculus**

correction for #1, should say: (1+cosx)/(1-cosx) = (secx + 1)/(secx - 1) RS = (1/cosx + 1)/(1/cosx - 1) = (1/cosx + 1)/(1/cosx - 1) * cosx/cox = (1+ cosx)/(1 - cosx) = LS Well, that was easy. #2, hint: change everything to sines and cosines expand and simplify the LS #3, use ...

*November 18, 2016*

**Maths**

So in 60 minutes he can type 3200 words. How many words can he type in 1 minute? Then how many in 15 minutes ?

*November 18, 2016*

**additional maths (maths)**

so you just want the max of d(t) find the derivative, set it equal to zero, and solve that for t Once you have the value of t which gives you the maximum, plug it back into d(t) to actually find that distance. Very straight-forward.

*November 18, 2016*

**Maths**

The missing angle ? = 45° by the sine law: a/sin35 = 40/sin100 a = 40sin35/sin100 = appr 23.3 c/sin45 = 40/sin100 c = 40sin45/sin100 = appr 28.7 area = (1/2)(ab)sin45 = appr 329.5 units^2

*November 18, 2016*

**maths**

so he gave away 60%, leaving him with 40% .4x = 9600 solve for x

*November 18, 2016*

**Math (Differentials)**

our f(x) = x^(1/3) , and f ' (x) = (1/3)x^(-2/3) = 1/(3(x)^(2/3) ) I will go with your x = 27 , dx = -2 f(x + dx) is appr = f(x) + f ' (x) (dx) f(25) = f(27) + (1/3)(27)^(-2/3) = 3 + (1/27)(-2) = 3 - .0741 = 2.926 you simply added the part at the end instead of ...

*November 18, 2016*

**algebra 2**

Your calculations are correct (sum of roots = 2+3i + 2-3i = 4 product of roots = (2+3i)(2-3i) = 4-(-9) = 13 ) It said to write the quadratic equation, which is x^2 - 4x + 13 = 0 you had y = x^2 - 4x + 13 , which is the quadratic function.

*November 17, 2016*

**Math**

I will place the parabola as opening to the right, with its vertex at (0,0) so the equation is y^2 = 4px, where (p,0) is the focus but (6,16) lies on it 16^2 = 4p(6) p = 256/24 = 32/3 So it should be placed at (32/3 , 0)

*November 17, 2016*

**Geometry**

original area = base x height = bh new area = .7b x 1.2h = .84bh so there is a 16% decrease in the area

*November 17, 2016*

**Calculus: Centers of Mass**

A quick calculation shows that the line intersects the parabola at (2,2) in the first quadrant lots of work ahead of us: first you must find the area of the region, it has to be done in two parts: from x=0 to x=2 under the curve, then from x=2 to x=4 under the straight line ...

*November 17, 2016*

**correction - Difficult Math**

I misread "Thirty of the cards from his cousin are National League players" as one third of the cards from his cousin are NL players

*November 17, 2016*

**Difficult Math**

total collection ---- x from dad --- x/4 from uncle --- x/5 ---> (.2)x = (2/10)x = x/5 from brother --- x/2 leaving : x -x/4 - x/5 - x/2 = x/20 so from cousin = x/20 so (1/3)(x/20) = 30 x = 1800 Steve has 1800 cards check: from dad = 1800/4 = 450 from uncle = .2(1800) = 360...

*November 17, 2016*

**Math**

999,999,999,999 = appr 1,000,000,000,000 = 10^12 ( you would be off by $1 on 1 Trillion dollars) 100,000,000,000,000 = 10^14 so 100,000,000,000,000 times 999,999,999,999 = 10^12 * 10^14 = 10^26 that would be 100 septillion.

*November 17, 2016*

**Math**

In arithmetic "of" means multiplication, so 1/10 of 2(10)+4(1)+6(1/10)+7(1/100)+8(1/1000) = (1/10)(20) + 4 + .6 + .07 + .008 = 2+4+.6+.07+.008 = 6.678 http://www.wolframalpha.com/input/?i=evaluate+1%2F10+*+2(10)%2B4(1)%2B6(1%2F10)%2B7(1%2F100)%2B8(1%2F1000) if you ...

*November 17, 2016*

**Algebra**

Help with what? You have given us two different circles. What do you want to do? They do intersect. Here is a picture of your problem http://www.wolframalpha.com/input/?i=plot+x%5E2%2By%5E2%2B6y%2B5%3D0+,+x%5E2%2By%5E2-2x-8%3D0

*November 17, 2016*

**Maths**

no XYYYY , where X is the vowel, Y can be anything else number of ways = (2)(4!) = 48 e.g. E(BGIN) - one of the 24 ways to arrange BGIN I(GBEN) - one of the 24 ways to arrange GBEN

*November 17, 2016*