Friday

April 17, 2015

April 17, 2015

Total # Posts: 29,591

**ALGEBRA Help Please**

1st: 2(x-3) = 2x 2x - 6 = 2x -6 = 0 -----> contradiction, thus no solution 4th: 4(x+3) + 2x = x - 8 4x + 12 + 2x = x - 8 5x = -20 x = -4 -----> One solution in general - if you get ?x = ? , there will be one solution - if the variable drops out, and you get a true ...
*November 19, 2014*

**Math**

#1, you can decide for yourself if (-5,-1) is correct by subbing in those values into both equations. You should be able to do this mentally. -- A quick mental calculation shows that your answer does not work in either equation from the 2nd: x = 2y + 10 plug that into the 1st...
*November 19, 2014*

**MATH HELP**

When testing if a number is prime, you would only try primes as divisors until you reach the last prime < √(the number) e.g. is 71 prime try: 2, 3, 5, 7 none divided exactly, so 71 is prime (did not have to go for 11 , since 11 > √71 so for 1881 ... √...
*November 19, 2014*

**maths**

Once around is one circumference. The circumference of a circle is 2πr or πd, d the diameter. So 5 times around would be ...... Plug in your values
*November 19, 2014*

**math**

I assume you meant to say, " ... travels 180 cm farther than ... " let the distance to the point of the minute hand be r cm In one hour the minute hand has gone around one rotation or 2πr in one hour the 'hour hand' has gone (1/12)(2π60)) or 10π...
*November 19, 2014*

**Maths**

Take a sheet of printer paper and try it. Doesn't the circumference of your tube equal the long side ? So.... 2πr = 20 r = 10/π
*November 19, 2014*

**Math- Combinations**

You are choosing 4 from 19 = C(19,4) = 19!/(15!4!) = 3876
*November 18, 2014*

**Math**

correct
*November 18, 2014*

**Math**

Retype in English please, and tell me what C is.
*November 18, 2014*

**AP CALC**

let the point of contact on the cosine curve be (x,y) So the perimeter of the rectangle = P = 2x + 2y = 2x + 2cos 2x dP/dx = 2 - 4sin 2x = 0 for a max/min of P 4sin 2x = 2 sin 2x = 1/2 I know sin π/6 = 1/2 so 2x = π/6 x = π/12 then y = cos π/6 = √3/2 ...
*November 18, 2014*

**algebra**

Let Jena time alone be x hrs let Cindy's time alone be 2x hrs let the two rates be 1/x and 1/(2x) combined rate = 1/x + 1/(2x) = 3/(2x) 1/(3/(2x)) = 10 2x/3 = 10 hrs = 2x = 30 or x = 15 Jena will take 15 hrs to do the house alone
*November 18, 2014*

**ap calc**

There are many variations of this same question,. Hint: let TP = x then OP^2 = x^2 + 64 OP = (x^2 + 64)^(1/2) I think you are missing the length of TR, we need that to find PR Just for arguments sake, lets say TR = 12 miles then PR = 12-x cost = 90000(x^2+64)^(1/2) + 54000(12-...
*November 18, 2014*

**ap calc**

Your graph looks like a W and I assume you want the rectangle placed inside the centre part. Let the two other vertices be (x,y) and (-x,y) So the length is 2x and the height is y Area = 2xy = 2x(x^4 - 2x^2 + 1) = 2x^5 - 4x^3 + 2x d(area)/dx = 10x^4 - 12x^2 + 2 = 0 5x^4 - 6x^2...
*November 18, 2014*

**sixth grade ratios and rates**

Here is another way of looking at Morgan's solution. Morgan found the percentage to be 25% or 1/4 of the marbes are blue. So 1/4 of Jasper's marbles must be blue , it said they have the same percentage of blue marbles. Let the total of Jasper's marbles be x then (1...
*November 17, 2014*

**Math**

f(x)= -x^2 + 2x = -1(x^2 - 2x +1 - 1 ) = -( (x-1)^2 - 1) = - (x-1)^2 + 1
*November 17, 2014*

**college, math**

If I were Sears I would sue the publisher of this textbook for associating their name with such a fraudulent practice . Anyway, according to this criminal plan .... cost after sales tax = 1656.9 "add-on interest" = 1656.90(.12)(3) = 596.484 amount to be "...
*November 17, 2014*

**algebra**

let's just plug in t = 10 T(10) = 65 + 115 e^-.42 = 140.56 = 141° to the nearest degree. b) we want 110 = 65 + 115 e^(-.042t) e^(-.042t) = (110-65)/115 = .391304... take ln of both sides -.042t = ln .391304.. t = 22.34 minutes or 22.3 minutes
*November 17, 2014*

**math**

x^2 = (-16 ± √196)/10 = (-16 ± 14)/10 x^2 = -1/5 or x^2 = -3 x = ± i/√5 or x = ± √3 i All four roots are imaginary
*November 17, 2014*

**Math**

only x= 0 so y= 0 x= 1 so y= -3 is correct, the others are not Perhaps, if you show how you are doing the calculations, I can see where you are going wrong. I will do one for you ... if x = -4 y = (-4)^2 - 4(-4) = 16 + 16 = 32
*November 17, 2014*

**Math**

So this question is essence establishes the quadratic equation formula hint: give yourself an equation such as 3x^2 + 12x + 2 = 0 and whichever step you perform on this equation, do the same thing for a parallel solution to ax^2 + bx + c = 0 Of course you know what you are ...
*November 17, 2014*

**Algebra Work Check**

correct or (x^2+4)(x^2-4) = 0 x^2 + 4 = 0 --> no real solution or x^2 - 4 = 0 (x+2)(x-2) = 0 x = ±2
*November 17, 2014*

**Pre-Calc/Trig**

let f(x) = 5x^3 - 119x^2 - 10x + 16 now try some f(x) , where x = ±1, ±2, ±4, ±8 ... hopefully to get a zero took some some, but f(8) = 0 so (x-8) will be a factor now by synthetic division , I got 15x^3-119x^2-10x+16 = (x-8)((15x^2 + x - 2) = 0 ...
*November 17, 2014*

**algebra**

speed of current --- x mph time to go 217 miles with the current = 217/(29+x) time to go 189 againts current = 189/(29-x) 217(29+x) = 189/(29-x) cross-multiply, solve for x
*November 17, 2014*

**Calculus**

everything happens starting at t=.5 a = -10 v = -10t + c when t = .5 , v = 20 20 = -10(.5) + c c = 25 v = -10t + 25 , for t ≥ .5 s = -5t^2 + 25t + k when t = .5 , the car goes goes another 20(.5) or 10 m so when t = .5, the remaining distance is 20 m 20 = -5(.5)^2 + 25(....
*November 17, 2014*

**maths**

original number --- x after epidemic --- .98x are left 14% of those leave, leaving (.86)(.98x) .86(.98x) = 2107 x = 2107/(.86(.98)) = 2500
*November 17, 2014*

**maths**

I am sure you meant A=p(1+r/n)^(nt) for yours r/n = .12/12 = .01 and nt = 12t (our unknown) so 500000(1.01)^(12t) = 1000000 1.01^(12t) = 2 take log of both sides log 1.01^(12t) = log 2 12t log1.01 = log2 12t = log2/log1.01 = 69.6607 t = 5.8 years
*November 17, 2014*

**math**

If I understand correctly there would have been 4 transactions. let the amount that each child has originally be x first transaction: 1st child -- x-9 each of remaining 9 children has x+1 2nd transaction: 1st child -- x-9 2nd child -- x+1 - 8 = x-7 each of remaining 8 children...
*November 17, 2014*

**proportion test**

new machine, defect rate is 85/820 = .1037 or 1037% draw you conclusion from that
*November 16, 2014*

**Math**

The question was to "find all possible roots" so you would try f(1), f(-1) , f(2) ...., f(±12) so you must try all of these unfortunately, none are equal to zero, so you have no rational roots.
*November 16, 2014*

**Math**

It is a 4th degree equation, so at most you could have 4 roots How can you possible get 6 of them ?
*November 16, 2014*

**math**

√(31-9x) = 5 - x square both sides 31 - 9x = 25 - 10x + x^2 x^2 - x - 6 = 0 (x-3)(x+2) = 0 x = 3 or x = -2 BUT, since we squared, we must verify ALL answers if x = 3 LS = 3 + √4 = 5 RS = 5, YEahh if x = -2 LS = -2 + √49 = -2 + 7 = 5 = RS, YEAHH x = -2 or x = 3
*November 16, 2014*

**MATH 101**

using the difference of cubes factoring x^2 - 8 = 0 (x-2)(x^2 + 2x + 4) = 0 x = 2 or x = (-2 ±√-12)/2 = (-1 ± 2√3 i )/2 = -1 ± √3 i for 3 solutions, one real, two complex
*November 16, 2014*

**MATH 101**

not enough information. is f(x) linear ? we must assume that, since you only have 2 points, namely, (3,0) and (-4,0) slope = 0/-7 = 0 so we have a horizontal line and f(x) = 0 f(x) is the x-axis
*November 16, 2014*

**math**

let's look at x^2 + 2x + 4 = 0 by completing the square, (in this case the easiest way to solve it) x^2 + 2x = -4 x^2 + 2x + 1 = -4+1 (x+1)^2 = -3 but anything squared cannot be negative, so there is no real solution consider y = x^2 + 2x + 4 this parabola never touches or...
*November 16, 2014*

**Math**

let f(x) = 3x^3 + 2x^2-1 f(1) = 3 + 2 - 1 ≠ 0 f(-1) = -3 + 2 - 1 ≠ 0 f(1/3) = 1/9 + 2/9 - 1 ≠ 0 f(-1/3) ≠ 0 So there are no "nice" roots looking at the graph, there appears to be a real solution at appr x = 0.5 and two complex roots (the graph...
*November 16, 2014*

**CAL**

y = x^3/x- x would reduce to y = x^2 - x and (1,-2/3) would NOT lie on this curve. So there is something wrong with the way you typed it Use brackets to establish the correct form Otherwise this question is bogus.
*November 16, 2014*

**CAL**

could be the way you typed your equation. The way you typed it, why not just simplify x^3/x to x^2 ? That is why I am suspicious about the way it was typed. Did you mean y = x^(3/x) - x ?
*November 16, 2014*

**Derivative**

But, to even attempt this question, you MUST know the derivatives of the basic trig functions. in this case, use the quotient rule dy/dx = ( (1+sinx)(-sinx) - cosx(cosx) )/(1+sinx)^2 = (-sinx - sin^2 x - cos^2 x)/(1+sinx)^2 = (-sinx -1)(1+sinx)^2 = -(1+sinx)/(1+sinx)^2 = -1/(1...
*November 16, 2014*

**calculus**

#1, your dy/dt is correct b) correct, to the right when v(t) > 0 but they probably want to know when that happens look at your derivative, the denominator will always be positive, since it is something squared. So the ± of your v(t) is only determined by the ...
*November 16, 2014*

**Calculus Help**

It is not a matter of "choosing" here, you must calculate it. f ' (x) = cos(7-5x)(-5) = -5cos(7-5x) f '(π) = -5cos(7-5π) = 5cos(-8.7078..) = 3.770 Did you set your calculator to radians in your DRG mode ?
*November 16, 2014*

**Pre Albergra**

Just put on my tin-foil hat and got a message of 3.4 cm How did I do ?
*November 16, 2014*

**Calculus**

let x = √5 then x^2 - 5 let y = x^2 - 5 y' = 2x Newton said: newx = x - y/y' = x - (x^2 - 5)/(2x) = (2x^2 - x^2 + 5)/2x = (x^2 + 5)/(2x) x newx 3 2.3333.... 2.333... 2.23809... 2.23809... 2.23606... could have stopped here 2.23606.. 2.236067878 2.236067978.. 2....
*November 16, 2014*

**Trig**

The primary function is ln(...) we can only take logs of positive numbers now look at the sine curve only, and note where it lies above the x-axis so the intervals would be 0 < x < 90° or 360° < x < 450° or 720° < x < 810° or ... how about...
*November 16, 2014*

**Math**

first , because of the negatiave outer exponent = 1/(16x^2)^3/4 since (ab)^x = a^x * a^x we get 1/( (16^(3/4 ) * x^(3/2) now 16^(3/4) = (16^(1/4) )^3 = 2^3 = 8 so finally = 1/(8 (√x)^3 )
*November 16, 2014*

**math**

Volume of cylinder = π r^2 h you are given r and h, plug in the values and evaluate
*November 16, 2014*

**Elementary Math**

Ricardo --- x years Miriana ---- x+4 Ten years ago: Ricardo --- x-10 Miriam --- x+4 - 10 = x-6 x-6 = 3(x-10) easy to solve ... let me know what you get
*November 16, 2014*

**Math**

One would think that after trying this for two days, you might realize that you don't have enough information. e.g. If your tank is a large rectangular tank of 10 ft by 10 ft the water level would rise more than if your "tank" had been a swimming pool.
*November 16, 2014*

**Math**

PV = 800( 1 - 1.09^-10)/.09 Wow, let me know which bank pays you 9% in 2014.
*November 16, 2014*

**Advanced Algebra (Infinite Geometric Series)**

8.690909.... =8.6 + .09 + .0009 + .000009+... = 86/10 + .09/(1-.01) = 86/10 + .09/.99 = 86/10 + 9/99 = 86/10 + 1/11 = 478/55
*November 15, 2014*

**Math**

2 / ((cos(r^2 - s^2) / (sin(r^2 - s^2)) = 2 * (sin(r^2 - s^2) / (cos(r^2 - s^2) = 2 tan (r^2 - s^2)
*November 14, 2014*

**Math Please Assist**

sin^3 x + sinx cos^2 x = cosx sinx(sin^2 x + cos^2 x) = cosx sinx (1) = cosx sinx/cosx = 1 tanx = 1 x = 45° or x = 225° but you wanted to be between 0 and 180 so x = 45°
*November 14, 2014*

**math**

since you want cos 2Ø in terms of x from x+5 = 9sinØ bringing the 5 over would make things worse ... and no, you would not distribute the 9 over the 9sinØ - 5 I would proceed this way: sinØ = ( x+5)/9 now you will have to use one of the half-angle ...
*November 14, 2014*

**Pre-Calc/Trig**

quadratic --- x^2 term makes it that linear ----- x term makes it that cubic ------ from the x^3 term the highest exponent term establishes what kind it is
*November 14, 2014*

**Algebra**

slope = (-3-1)/(1-3) = 2 so it has to be one of the last two of your choices sub in (1,3) into y = 2x+5 ---> doesn't work sub in (1,3) into y = 2x - 5 ----> Yeahhh! so y = 2x-5 that is what bob had suggested to you, that is, try the points in the equations.
*November 14, 2014*

**math**

so in effect the ship went 41 + 15 or 56 north and 23 east. so d^2 = 56^2 + 23^2 = 3665 d =√3665 = 60.5 km
*November 14, 2014*

**math probability**

since the code > 400, your choice for the first digit is 6, you can put 10 different digits in the 2nd spot, and 10 different digits in the 3rd spot number of possible codes = 6x10x10 = 600 this would include 400, which cannot be used, since it must be greater than 400 so ...
*November 14, 2014*

**Math**

to the nearest 10 13---> 10 46 ---> 50 87 ---> 90 sum = 150 if you added them up like you did to get 146 , you have the actual answer, why bother estimating ? Besides, 146 rounded to the nearest tens is 150, not 160
*November 14, 2014*

**math probability**

I don't understand the question. In your first sentence, you are saying that there are only 9 dollars in the box.
*November 14, 2014*

**Intermediate Algebra**

simple interest formula: I = PRT, lets plug in our values 85 = 6000(R)(1/12) multiply both sides by 12 1020 = 6000R divide both sides by 6000 R = 1020/6000 = .17 or 17% You had the correct answer, but you should not just piece-meal bits and pieces from the equation.
*November 14, 2014*

**Intermediate Algebra**

sloppy use of the decimal place and your solution makes absolutely no sense. if x is the amount loaned at 6% ... .06x + .14(15000-x) = 1500 .06x + 2100 - .14x = 1500 -.08x = -600 x = 600/.08 = 7500 So $ 7500 was loaned at 6% and $7500 at 14% check: .06(7500) + .14(7500) = 1500
*November 14, 2014*

**MATH**

true if both are positve, or if both are negative. depends if one is + , the other - e.g 8/5 - 9/7 = 11/35 but 15/4 - 3/2 = 9/4 , still a mixed number
*November 13, 2014*

**Geometry**

let the size of the cut-out be x by x inches length of base = 24-2x width of base = 24-2x height = x V = x(24-x)^2 = x(576 - 48x + x^2) =576x - 48x^2 + x^2 dV/dx = 576 - 96x + 3x^2 = 0 for a max of V x^2 - 32x + 192 = 0 (x - 24)(x - 8) = 0 x - 8 or x = 24, but if x = 24, we ...
*November 13, 2014*

**Probability.. HELP!**

what is 36x35x34 ? Do you know why ?
*November 13, 2014*

**Math, Please Help!**

I will assume we are not distinguishing between small and capital letters. I will do one: TENNESSEE - 9 total, 2 N's , 4 E's, 2 S's total number of ways = 9!/(2!4!2!) = 3780 Can you see what I did ? OHIO ----> 4!/(2!) = 12 try the others.
*November 13, 2014*

**College Algebra**

If you mean (-10-6i) /( -9+9i) , then the brackets are essential (-10-6i) /( -9+9i) = (-10-6i) /( -9+9i) * (-9-9i)/(-9-9i) = (90 + 90i + 54i + 36i^2)/(81 -81i^2) = (54 + 144i)/162 = 1/3 + (8/9)i
*November 13, 2014*

**College Algebra**

type it this way: (-6 - √10)/(3 + 8√10) I will assume you are rationalizing (-6 - √10)/(3 + 8√10) = (-6 - √10)/(3 + 8√10) * (3 - 8√10)/(3 - 8√10) = (-18 + 48√10 - 3√10 + 80)/(9 - 640) = ( 62 + 45√10)/-631 = (-62...
*November 13, 2014*

**Calculus**

are you using the usual notation so that a(t) is acceleration, v(t) is velocity and s(t) is distance ?? I will assume you are a(t) = t^2 - 8t + 5 v(t) = (1/3)t^3 - 4t^2 + 5t + c s(t) = (1/12)t^4 - (4/3)t^3 + (5/2)t^2 + ct + k s(0) = 0 0-0+0+0+k=0 k=0 s(1) = 20 1/12 - 4/3 + 5/2...
*November 13, 2014*

**algebra**

looks like we are dividing by -2 each time, so ....
*November 13, 2014*

**algebra**

So a is always positive and b is always negative. What is a positive divided by a negative ?
*November 13, 2014*

**Algebra**

if f(x) = 4x^7+x^5+3x^2-2x+c f(-1) = -4 -1 + 3 +2 +c = 0 c = 0
*November 13, 2014*

**math**

Since the area of each time is 16 in^2, each side of the tile must be 4 inches the table is 6 ft by 6ft or 72 inches by 72 inches so we need 72/4 or 18 tiles along a side. since the table is square, the number of tiles needed = 18(18) 324 tiles
*November 13, 2014*

**Math**

I usually get rid of nasty decimals ... .1g+3.75m=7.36 --> 10g + 375m = 736 --> g = (736-375m)/10 8.2g+21m=73 ----> 82g + 210m = 730 10g +375m = 736 -times 410 --> 4100g + 153750m = 301760 82g + 210m = 730 -times 50 --> 4100g + 10500m = 36500 subtract them: ...
*November 13, 2014*

**math**

I think Bob has a typo in dividing x+y+z by 2 instead of 3 x+y+z+ (x+y+z)/3=360 3x+3y+3z + x+y+z = 1080 4x+4y+4z = 1080 x+y+z = 270
*November 13, 2014*

**Algebra 2**

3x^2 - 24x + 45 = 0 remember Steve told you about all that "zero stuff" ? divide each term by 3 x^2 - 8x + 15 = 0 can you think of 2 numbers that add up to -8 and multiply to get 15 ? I am thinking -3 and -5 so (x-3)(x-5) = 0 x-3=0 ----> x = 3 or x-5 = 0 ----> ...
*November 13, 2014*

**math**

Proof for all values: let a+b+c+d+e = S let M be the average M = S/5 5M = S then S/M = 5/1 or S : M = 5 : 1
*November 13, 2014*

**Math**

correct
*November 13, 2014*

**algebra. help!**

first one: y = 2^x why did you possible pick c) not a single one of the pairs given satisfies that equation. It is clearly y = (x+3)^2 , that is, d)
*November 13, 2014*

**Algebra**

number of $1 --- n number of $2 --- n+11 number of $3 --- n-18 now for the "value" : 1n + 2(n+11) + 3(n-18) = 100 n+2n+22 + 3n-54 = 100 6n = 132 n = 22 then n+11 = 33 n-18 = 4 so 22 $1 bills , 33 $2 bills and 4 $3 bills check: 22 + 66 + 12 = 100 Yeahh
*November 13, 2014*

**Algebra**

surely you can replace x with 2 and add 2+6
*November 13, 2014*

**Algebra**

in h(x) = −9x^3+3x^2−2x+2 they are in order of decreasing degree
*November 13, 2014*

**Algebra**

h(x) = −9x^3+3x^2−2x+2 why did you put commas between terms in your answer ?
*November 13, 2014*

**math**

cost = 16m + 1895 , where m is the number of miles and cost is in cents 16m + 1895 = 5000 16m = 3105 m = appr 194 miles check: 194(.16) + 18.95 = 49.99
*November 13, 2014*

**Algebra 2**

As Morgan pointed out, your left side is a perfect square (x+4)^2 = 16/9 x+4 = ± 4/3 x = 4/3 - 4 = -8/3 or x = -4/3 - 4 = -16/3 your signs were wrong
*November 13, 2014*

**algebra**

tom has x stickers Matt has 6x stickers there must have been a total of 140 stickers x + 6x = 140 7x = 140 x = 20 Tom has 20 and Matt has 120 So Matt has to give 50 of them to Tom check: Tom: 20+50 = 70 Matt: 120-50 = 70 Yeahhh
*November 13, 2014*

**Trig/Pre-Calc**

try x = ±1 , ±2, ±4, ±8 I got x = 8 to work for me so after a sythetic division, I got (x-8)(15x^2 + x - 2) = 0 (x-8)(3x-1)(5x + 2) = 0 x = 8 , 1/3 , -2/5
*November 13, 2014*

**math**

same type of problem as your previous one
*November 13, 2014*

**math**

What is 9 ÷ (3/8) ?
*November 13, 2014*

**chin**

That is a "serious" problem I will use A for ace F for facecard and L for non-ace, non-face (L for loser) I will also assume that none of the 4 cards drawn in a game are returned to the deck, but they would be returned after a game is played. so the possible ...
*November 13, 2014*

**maths algebra**

I think you are referring to this earlier post by you http://www.jiskha.com/display.cgi?id=1415787409 I agree with Steve's answer, I subbed his answer back in the original equation, and it worked. Steve's solution was correct, perhaps you typed it incorrectly. As to ...
*November 13, 2014*

**math**

Just translate the English into Math "Half the total number of balls are pink. " ----> p = (1/2)(r+b+g+p) 2p = r+b+g+p p = r+b+g , #1 "One-fourth of the number of green balls equals one-third of the numher of blue balls. " ----> (1/4)g = (1/3)b 3g = ...
*November 13, 2014*

**Algebra**

amount = 19 (1/2)^(150/97) = appr 6.5 g
*November 13, 2014*

**math**

look at Steve's solution here http://www.jiskha.com/display.cgi?id=1382123644 then change the numbers to fit your problem
*November 12, 2014*

**math**

at a time of t minutes, let the radius of the water level be r cm let the height of the water level be h cm by ratios: r/h = 1.75/6 1.75h = 6r r = 1.75h/6 = 7h/24 V = (1/3)π r^2 h = (1/3)π(49h^2/576)h = (49π/1728) h^3 dV/dt = (49π/576) h^2 dh/dt without ...
*November 12, 2014*

**calculus**

total distance = 24 + 24(.95) + 24(.95)^2 + .... an infinite GS, where a = 24 and r = .95 sum(all terms) = a/(1-r) = 24/(1-.95) = 24/.05 = 480 metres
*November 12, 2014*

**Calculus**

nope, I have no idea how you got that. use the product rule, y = x secx y' = x(secx)(tanx) + secx or = x(1/cosx)(sinx/cosx) + 1/cosx = xsinx/cos^2 x) + 1/cosx or = (xsinx + cosx)/cos^2 x so slope = (π/4)(√2/2) + √2/2)/(1/2) = .....
*November 12, 2014*

**finance math**

Assumption: the rate stays at 7% throughout her 31 years of deposits and the 15 years of withdrawals. (What happens after the 15 years of retirement and her money is used up ? ) let her payment + employers share be $x per year x( 1.07^31 - 1)/.07 = 30000(1 - 1.07^-15)/.07 you ...
*November 12, 2014*

**Math**

so in your equation, y is the number of words and x is the number of minutes so set y = 2500 50x - 25 = 2500 50x = 2525 x = 50.5 so it will take 50.5 minutes or 50 minutes and 30 seconds.
*November 12, 2014*

**Algebra**

Trish, since subtraction only involves "like" terms, and g(x) does not contain any x^4 term, nothing can happen to the x^4 term of f(x) so your result still contains the x^4 term , and thus is a polynomial of degree 4
*November 12, 2014*

**Math**

Well, I would suggest you do each division and see.
*November 12, 2014*

**Math**

Your question asked for the slope, you gave the equation as an answer. I can tell that you found the slope to be 35, which is correct. Also the equation is correct
*November 12, 2014*