Saturday

June 25, 2016
Total # Posts: 35,063

**Probability**

What is the definition of probability? So in your experiment in how many of the 500 cases did you get the required event ?
*March 6, 2016*

**trig**

recall that 1 + cot^2 x = csc^2 x as a variation of the Pythagorean identity so LS = (csc^2x+1)(csc^2 x-1)/cot^2x = (1 + cot^2 x + 1)(1 + cot^2 x -1)/cot^2 x) = 2 + cot^2 x = RS
*March 6, 2016*

**algebra 2**

What is wrong with my "final" equation. Why mess up a nice looking equation in factored form ?? your answer is correct, if you fix that typo in "-x.5x^2"
*March 6, 2016*

**algebra 2**

I will do mine using just a good ol' fashioned pencil and paper ... intercepts are -4, 2, and 5 so y = a(x+4)(x-2)(x-5) The a will stretch it and force it to go through (6,20) 20 = a(10)(4)(1) 20 = 40a a = 1/2 y = (1/2)(x+4)(x-2)(x-5) Well, what do you know, I didn't ...
*March 6, 2016*

**calc 1**

You haven't defined your x and y, so I can't answer the last part of your question. On my diagram, I have a right-angled triangle with a height of 1 m, a horizontal of x m and a hypotenuse of y m given: dy/dt = -1 m/s ( I made it negative, because the value of y will ...
*March 6, 2016*

**Math**

number of chain saws --- x number of chippers ----- y 7x + 3y ≤ 63 ---> time inequation profit = 190x + 220y we need integer values of x and y only possible cases from 7x + 3y = 63 : (0,21) , (3,14), (6,7), (9,0) for (0,21) profit = 0 + 4620 = 4620 for (3,14) profit...
*March 6, 2016*

**Calculus / Rates of Change**

ok, let's go with your definitions: height: --- h base --- 1.5h area ---- a given: d(a)/dt = 9 cm/s find dh/dt, when h = 12 (I see variables a for area and h for height. So I will need an equation that contains a and h) a = (1/2)base x height a = (1/2)(h)(1.5h) = .75h^2 d(...
*March 6, 2016*

**trig plz help**

tan (3x) = -1 I know that 3x must be in quadrants II or IV and I know that tan 45° = +1 or tan π/4 = 1 so 3x = π - π/4 OR 3x = 2π - π/4 3x = 3π/4 or 3x = 7π/4 x = π/4 or x = 7π/12 now the period of tan 3x is π/3 so adding ...
*March 6, 2016*

**trigonometric**

let the height of the mountain be h ft let the distance from the base of the mountain to its vertical line h be x ft (inside the mountain) You have two right-angled triangles. From the first: tan25 = h/(x+600) h = (x+600)tan25 From the 2nd: tan 20 = h/(x+1400) h = (x+1400)...
*March 6, 2016*

**trig gauss jordan**

lots of writing... Here is a neat page http://www.gregthatcher.com/Mathematics/GaussJordan.aspx tell it you have 3 rows and 4 columns, then enter the values Notice it takes it all the way to the matrix 1 0 0 ? 0 1 0 ? 0 0 1 ? you only have to go as far as 1 x x x 0 1 x x 0 0 1...
*March 6, 2016*

**trig help**

centre is the midpoint of the vertices: C(-1,1) our a value is 6, and we don't know b but we know b/a = 1/3 b/6 = 1/3 3b = 6 b = 2 (x+1)^2 / 36 - (y-1)^2/4 = 1 or (x+1)^2 - 9(y-1)^2 = 36 verification: http://www.wolframalpha.com/input/?i=plot+(x%2B1)%5E2+-+9(y-1)%5E2+%3D+36
*March 6, 2016*

**mat**

nice graph, what about it ? http://www.wolframalpha.com/input/?i=f(x)%3D5sin%5E2x-8cos%5E5x
*March 6, 2016*

**Math**

Perfect for this page ... http://davidmlane.com/hyperstat/z_table.html click on above prob = .1587 multiply that by 8000
*March 6, 2016*

**algebra**

rate of sailing in still water , assuming the lake has no current ---- x km/h rate of sailing in river against current -- x-2 km/h time in river = 6/(x-2) time in lake = 15/x the difference in those times is = 1 form the equation and solve for x hint: I would multiply each ...
*March 6, 2016*

**Math (Help Please)**

#2 7(2p − 1) just expand, takes 1 step = 14p - 7 ----> C #3, 1.8c + 5.4cd, common factor is 1.8c, one step = 1.8c( 1 + 3d)
*March 6, 2016*

**Math (Help Please)**

1.C -- correct 2.D -- wrong 3 Idk. - wrong 4.C -- wrong 5.A -- wrong 6.D -- wrong I think you were just guessing, hoping that now I would do them for you. Why not show your steps to get these answers, that way I can help you.
*March 6, 2016*

**Math (Help Please)**

Your choices of answers to these questions did not show up.
*March 6, 2016*

**Math**

What is your choice and why ?
*March 6, 2016*

**trig/ellipse equation**

the major axis is vertical, and a = 5, b = 6 , and centre is (-1,-2) equation: (x+1)^2/25 + (y+2)^2/36 = 1
*March 6, 2016*

**math**

but it said the tens digit is less than 9, your is 9 how about 78?
*March 6, 2016*

**Math**

I made a sketch, and let RS = PS = x then QP = 3x Draw RC || SP to meet QP at C Then CP = x and QC = 2x PCRS is now a ||gram, making angle QCR = 60° In triangle RCQ, by the cosine law: QR^2 = (2x)^2 + x^2 - 2(x)(2x)cos60° = 5x^2 - 4x^2 (1/2) = 3x^2 QR = √3 x In ...
*March 6, 2016*

**math**

I will assume you meant: "largest volume" Obviously the "bose" must be a cube. Sketch a cross-section I see a square in a circle, with a diameter of 2. let each side of the cube be x then x^2 + x^2 = 2^2 2x^2 = 4 x^2 = 2 x = √2 The "bose" is...
*March 6, 2016*

**Physics ?? - Maths**

sounds like Physics to me
*March 6, 2016*

**algebra**

a=3/8, r = 2 term8 = ar^7 = (3/8)(2^7) = ....
*March 6, 2016*

**Calculus**

area = πr^2 d(area)/dt = 2πr dr/dt given: dr/dt = -4 inches/hr find d(area)/dt when r = 108 inches d(area)/dt = 2π(108)(-4) inches^2/hr = appr 2714.3 inches^2/h if you had said 3:00 am, the time would have been 3 hrs, and the radius would have shrunk by 12 ...
*March 6, 2016*

**trigonometry**

See my previous comment http://www.jiskha.com/display.cgi?id=1457256421
*March 6, 2016*

**Maths**

let height of tower be h m let height of "flay" pole be f m two right-angled triangles: tan40 = h/10 h = 10tan40 tan 50 = (h+f)/10 h+ f = 10tan50 continue
*March 6, 2016*

**Pre calc quadratic stuff**

I will let the y-axis be the axis of symmetry So the vertex is (0,24) so the equation must be y = a(x-0)^2 + 24 y = ax^2 + 24 but we have two points at the top of the tower, (84,??) and (-84,??) Unless I am misreading the question, we are missing information. How high are the ...
*March 6, 2016*

**trigonometry**

This and your previous questions have all been the same type. You have shown no effort on your part or indicated where your difficulties lie. Did you just want us to simply do them for you ?
*March 6, 2016*

**trigonometry**

You have a triangle with sides 8(24) km and 8(28) km, and the contained angle of (180 - 38°15; - 51°45') between them Just use the cosine law
*March 6, 2016*

**Math**

Euler's formula: V-E+F=2 14-E + 21 = 2 -E = -33 E = 33
*March 6, 2016*

**trigonometry**

I see a right-angled triangle with a horizontal side of 10 km and its opposite angle 40°20' for original position SL tan 40°20' = 10/SL SL = 10/tan40°20' = 11.7776.. km for final position LS' sin40°20' = 10/LS' you finish it, and state ...
*March 6, 2016*

**linear equations**

√(5-x) = x+1 To be defined, 5-x ≥ 0 -x ≥ -5 x ≤ 5 also since √anything yields a positive result, x+1≥0 x≥-1 so -1 ≤ x ≤ 5 To solve, square both sides 5-x = x^2 + 2x + 1 x^2 + 3x - 4 = 0 (x+4)(x-1) = 0 x = -4 or x = 1 ...
*March 6, 2016*

**quadratic equations**

x = ±√( (4-8p)/4) square it x^2 = (4-8p)/4 x^2 = 1 - 2p x^2 + 2p = 1 x^2 + 2p + p^2 = 1+p^2 , I completed the square (x+p)^2 = 1+p^2 x+p = ±√(1+p^2) x = -p ± √(1+p^2) since 1+p^2 is always positive , x will always be real to have equal ...
*March 6, 2016*

**Calculus Derivatives**

y' = x(1/x) + lnx = 1 + lnx y'' = 1/x ---> yup, you had that concave up when 1/x > 0 or x> 0 concave down when 1/x < 0, or x < 0 yes, you got it!
*March 5, 2016*

**math**

the sheet of paper is 324 cm by 172 cm The tempation is to say: area of whole paper = 55728 cm^2 area of 1 envelope = 216 so we have 55728/216 or 258 envelopes. BUT, not so fast ..... If we lay the length of the envelope along the long side of the large sheet, we can get 324/...
*March 5, 2016*

**Calculus**

Found this youtube for you He is doing dx/√(x^2+a^2) so for yours a^2 = 16, a = 4 https://www.youtube.com/watch?v=MWfA85-Mb50 Have fun
*March 5, 2016*

**Math**

prob(good) = .9 prob(bad) = .1 you want prob(6 of 7 to be good) = C(7,6)(.9)^6 (.1) = .. you push the buttons
*March 5, 2016*

**Math**

value of $1.00 at end of 1 year: Bank A : amount = (1 +.0479/12)^12 = ... Bank B : amount = (1 + .048/4)^4 = .. compare the results
*March 5, 2016*

**Algebra**

are we solving √(8-3x) + √(6x-1) = 7 - 2√(9x-24) ???? I tested it in Wolfram, and there is no "real" solution, so I won't even try. http://www.wolframalpha.com/input/?i=%E2%88%9A(8-3x)+%2B+%E2%88%9A(6x-1)+%3D+7+-+2%E2%88%9A(9x-24) notice that ...
*March 5, 2016*

**math**

factors of 1440 2x720 3x480 4x360 5x288 6x240 8x180 9x160 10x144 12x120 15x96 16x90 18x80 20x72 24x60 30x48 32x45 36x40 ---> that's all of them values of n^2-1 1,3,8,15,24,35,48,63,80,99,120,143,168,195,288,325,360,399,440,483,529,575,624,675,728 the largest of these ...
*March 5, 2016*

**math**

values of n+1 2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,.... multiples of 4n+1 5,9,13,17,21,25,29,33,37,41,45,49,53,57,61,65,69,73,77,81,85,89,93,97,101,... let 4n+1) = k(n+1) k = (4n+1)/(n+1) , so k has to be whole number if n=2 , 9/3 = 3 --> k = 3 if n=3, 13/4 ≠ ...
*March 5, 2016*

**Algebra**

speed of slower --- x km/h speed of faster ---- x+2 km/h 20/x - 20/(x+2) = 20/60 = 1/3 times 3x(x+2) , the LCD 60(x+2) - 60x = x(x+2) x^2 + 2x - 120 = 0 (x+12)(x-10) = 0 x = 10 or x = -12, the ladder is silly The slower one went 10 km/h, and the faster went 12 km/h check: 20/...
*March 5, 2016*

**Math**

width --- x length --- (6/5)x (6/5)x^2 = 480 x^2 = 400 x = √400 = 20 picture is 20 inches by 24 inches
*March 5, 2016*

**business math**

Did you mean simple interest? if so, PRT = I 52600(.05)T = 1261 T = 1261/(.05(52600)) = .4795 years or 175 days check: 52600(.05)(175/365) = 1260.96 or $1261
*March 5, 2016*

**Calc Derivatives**

you should say y = (4x-3)/(3x^(1/2)) or f(x) = (4x-3)/(3x^(1/2)) dy/dx =[ 3x^(1/2) (4) - (4x-3)(3/2)x^(-1/2) ]/(9x) = 0 for a max/min 12x^(1/2) = (3/2)(4x-3)/x^(1/2) 12x = (3/2)(4x - 3) 24x = 12x - 9 12x=-9 x = -3/4 , but x ≥0 or else x^(1/2) is undefined. There are no ...
*March 5, 2016*

**math ples help**

using these log rules: log(ab) = loga + logb log(a/b) = loga - logb log( a^n) = nloga Rewrite 2log8/6 + 2^2log3 - 2log12 as log(64/36) + 4log3 - log144 = log(64/36) + log81 - log144 = log ( (64/36)(81)/144) = log 1 = 0
*March 5, 2016*

**Math**

The simple proportion for your similar triangles: h/48 = 5/12 12h = 240 h = 20 or by straight logic: The mirror is 4 times the distance away from the pole as she is from the mirror. So the flage pole is 4 times her height, or 20 ft " Find the geometric mean of the pair of...
*March 5, 2016*

**math**

Ok ... RS = sinx/√(1+cosx) * √(1-cosx)/√(1-cosx) , you did that = sinx √(1-cosx) /(√( (1+cox)(1-cosx) ) = sinx √(1-cosx)/√(1 - cos^2 x) = sinx √(1-cosx)/√sin^2 x = sinx √(1-cosx)/sinx = √(1-cosx) = LS
*March 5, 2016*

**math**

solve for m, the number of miles .09m + 57.98 = .14m + 49.98 9m + 5798 = 14m + 4998 ...
*March 5, 2016*

**Math**

Make a Venn diagram Label it P and B, for pepperoni and banana put 5 in the intersection of both circles - of the 25 who like pepperoni, 5 are already counted, so put 20 in the P circle apart from the intersection. - of the 31 who like banana peppers, 5 are already counted, so...
*March 5, 2016*

**Maxima, Stationary Points**

If (9*x^6+28*x^4+51*x^2-88*x-10)/(3*x^2+2)^2 is the derivative of some function and you want to find max/min, you would set the above equal to zero that would leave you with 9x^6 + 28x^4 + 51x^2 - 88x - 10 = 0 I am not at all familiar with your software, but my favourite math ...
*March 5, 2016*

**math**

How good are you at sketching 3-D diagrams? I let P be the point directly below plane A, and I now have 4 triangles, each in their own plane. Redraw each with a side view: right-triangle ABP , right angle at P right-triangle ACP, right angle at P triangle BCP , (on ocean floor...
*March 5, 2016*

**trigonometry**

sinx/secx = 1/tanx+cotx , is not true but sinx/secx = 1/(tanx+cotx) is true LS = sinx(1/cosx) =sinxcosx RS = 1/(sinx/cosx + cosx/sinx) = 1/( (sin^2 x + cos^2 x)/(sinxcosx) ) = 1/(1/sinxcosx)) = sinxcosx = LS
*March 5, 2016*

**college algebra**

let the three numbers be x x+2 x+4 2x - (x+2) = 20 x = 22 largest is x+4 = 26
*March 5, 2016*

**MATH**

Make a sketch, (it won't be to scale!) You will have an isosceles triangle with an angle at the earth of 31 minutes of angle. Draw in a perpendicular which would be 360,000 km If the radius of the moon is r, I see it as tan (0°15'30") = r/360000 r = 360000(tan...
*March 5, 2016*

**Math**

let the two numbers be 3x and 4x 3x+10 = 4x - 10 solve for x
*March 5, 2016*

**Allgebra**

let the two numbers be x and y (x+y)/2 = 17 x+y = 34 --> y = 34-x √(xy) = 8 xy=64 x(34-x) = 64 x^2 - 34x = -64 x^2 - 34x + 289 = 289-64 ---> I completed the square (x-17)^2 = 225 x-17 = ±15 x = 32 or x = 2 if x = 32, y = 2 if x = 2, y = 32 , (called ...
*March 5, 2016*

**Algebra**

in a harmonic progression, the reciprocals of its terms form an arithmetic progression. so if the third term of the HP is x then 1/a , 1/b, and 1/x form an AP that is, 1/b - 1/a = 1/x - 1/b 2/b - 1/a = 1/x (2a - b)/(ab) = 1/x x = ab/(2a - b)
*March 5, 2016*

**Algebra**

"one third of a one third of a point is deducted" - why not just say say: " 1/9 of a point is deducted for an incorrecte answer" ?? number correct --- x number incorrect --- 72-x x - (1/9)(72-x) ≥ 60 x - 8 + (1/9)x ≥ 60 (10/9)x ≥ 68 x &#...
*March 4, 2016*

**maths**

1/x + 1/(x+6) = 1/(40/3) = 3/40 times 40x(x+6) 40(x+6) + 40x = 3x(x+6) 3x^2 - 62x - 240 = 0 t = (62 ± √6724)/6 = 24 or -3/1/3 , but x > 0 so x = 24 tom alone can do it in 24 hrs, John alone can do it in 30 hours check: at combined time, time of job = 1/(1/24+1/...
*March 4, 2016*

**probability**

prob(zero people leave tip) = C(6,0)(.7)^0 (.3)^6 = .000729 prob(1 person leaves tip) = C(6,1)(.7)(.3)^5 = .010206 prob(2 persons leave tip) = C(6,2)(.7)^2 (.3)^4 = .059535 prob(3 persons leave tip) = C(6,3)(.7)^3 (.3)^3 = .18522 prob(4 people leave tip) = C(6,4)(.7)^4 (.3)^2...
*March 4, 2016*

**Calculus with Analytical Geometry**

you are looking for the vertex of h = -16t^2 + 1000t + 20 the t of the vertex is -1000/-32 = 31.25 seconds for that value of t, h = 15645 ft
*March 4, 2016*

**Math Algebra Intermediate**

ay - a^6 y^6 = ay(1 - a^5 y^5) Much Ado About Nothing, as Shakespeare would say.
*March 4, 2016*

**Math**

i = .042/12 = .0035 n = 30(12) = 360 PV =.8(260000) = 208,000 let the payment be P P( 1 - 1.0035^-360)/.0035 = 208000 P = $1017.16
*March 4, 2016*

**Math**

S(1) = 2 by the formula: S(1) = 1(1 + 3)/2 = 2 S(2) = 2+5 = 7 by the formula: S(2) = 2(1+6)/2 = 7 S(3) = 2+5+8 = 15 by formula: S(3) = 3(1+9)/2 = 15 seems to work.
*March 4, 2016*

**math**

let the two numbers be x and x+1 4x + x(x+1) = 36 x^2 + 5x - 36 = 0 (x+9)(x-4) = 0 x = 4 or x = -9, but x>0 x = 4 the two numbers are 4 and 5
*March 4, 2016*

**Algebra 2**

(log5 16^3 )(log11 6^2 = log x 3(log16/log5)(2)(log6/log11) = logx 6(log16/log5)(log6/log11) 6(1.28724...) = logx 7.72346... x = 10^7.72346.. x = appr 52,900,679 I was using the log properties: log a^n = n loga , and log a b = logb/loga
*March 4, 2016*

**algebra 1b**

typo: don't know where my 20 came from. should have been: quarters ---- x nickels ----- 16-x solve for x: 25x + 5(16-x) = 220
*March 4, 2016*

**algebra 1b**

quarters ---- x nickels ----- 20-x solve for x: 25x + 5(20-x) = 220
*March 4, 2016*

**math**

let the total be x make a Venn diagram of two intersecting circles, and place 27 in the intersection. In the exclusive parts of the two circles place (3/4)x - 27 and (4/7)x - 27 then: (3/4)x-27 + 27 + (4/7)x-27 = x (3/4)x + (4/7)x-27 = x multiply each term by 28, the LCD 21x...
*March 4, 2016*

**Math**

Was that supposed to say KL = 14 ? I will assume that, since N does not enter the picture elsewhere. Let's find angle K, the largest angle. 18^2 = 14^2 + 16^2 - 2(14)(16)cosK 448cosK = 128 cosK = 2/7 K = appr 73.4° area = (1/2)(14)(16)sinK = 112(.9583..) = appr 107.33 ...
*March 3, 2016*

**Geometry**

in any rhombus, the diagonals right-bisect each other. illustration: midpoint of PR = (0,0) midpoint of QS = (0,1/2) oops, something is not right the figure is not a rhombus, I think S should be (1,-2) then midpoint of QS is also (0,0) and the two diagonals would bisect each ...
*March 3, 2016*

**typo at end - statistics**

Last line of previous post should have been: number of ways = 4x36 = 144
*March 3, 2016*

**statistics**

a) consider each couple as one unit, so you are just arranging 3 units. Number of ways = 3! = 6 b) I don't understand the question c) for the men to sit together, we could have MMMWWW **** WMMMWW WWMMMW WWWMMM Number of ways to do *** = 3x2x1x3x2x1=36 but each of the other...
*March 3, 2016*

**Calculus Related Rates**

let the distance between them be x ft after a time of t seconds, distance of the northbound person = 4t ft distance of the other person = 5t ft They walk at an angle of 45° to each other. By the cosine law: x^2 = (4t)^2 + (5t)^2 - 2(4t)(5t)cos45 = 41t^2 - 40t^2 (√2/2...
*March 3, 2016*

**Algebra**

so you have an arithmetic series with a = 30,000 , d = 2300 sum(10) = (10/2)(60000 + 9(2300) ) = 403,500
*March 3, 2016*

**mathematics**

The way you typed it, all is good, the expression would be real and defined for all values of x but... if you meant: 5x+4÷√(8-4x) , then we have two concerns 1. to be real, 8-4x ≥ 0 -4x ≥ -8 x ≤ 2 2. to be defined: 8-4x ≠ 0 -4 ≠ -8 x...
*March 3, 2016*

**Math**

speed on first part ---- x km/h speed on return trip -- x+2 km/h time on first trip = 42/x time on 2nd trip = 42/(x+2) 42/x - 42/(x+2) =1/2 multiply each term by 2x(x+2) 84(x+2) - 84x = x(x+2) 84x + 168 - 84x = x^2 + 2x x^2 + 2x - 168 = 0 (x-12)(x+14)=0 x = 12 or x =-14, let&#...
*March 3, 2016*

**Mathematics**

Please don't post the same problem again under a different name. Once will do. I just did this for you
*March 3, 2016*

**Maths**

In my diagram, I have the perpendicular from T go PC meeting PC at S, giving me 2 right angled triangles. In triangle CST: tan30° = 6/CS CS = 6/tan30 in triangle PST: tan40° = 6/SP SP = 6/tan40 PC = CS+SP = .... you do the button-pushing
*March 3, 2016*

**Finance**

I am not familiar with US mortgage laws. What is this "3.5% closing cost" ? so is the original mortgage: add 3.5% to 225,000, then take 90% of that? That would be 225,000(1.035)(.9) = $209,587.50 confirm that before I proceed
*March 3, 2016*

**Math**

(-1,14), (0,10), (1,8), (2,?), (3,10), (4,?) and (5,20) the missing values should be like: (-1,14), (0,10), (1,8), (2,8), (3,10), (4,14?) and (5,20) Now if you put those same x value into the straight line you get: (-1,6), (0,7), (1,8), (2,9), (3,10), (4,11), and (5,12) Notice...
*March 3, 2016*

**math**

Join A and B to O, the centre of the circle So we have triangle ABO with all 3 sides known. We can use the cosine law to find angle Ø 6^2 = 9^2+9^2-2(9)(9)cosO 162cosØ = 126 cosØ = 126/162 = 7/9 Ø = 38.94...° (I stored it in calculator's ...
*March 3, 2016*

**Algebra**

amount = 6300(1.06)^3 = 7503.40 how did you get your answer ??
*March 2, 2016*

**trigonometry (Course and Bearing)**

According to my sketch: tan46°10' = 7/AP AP = 7/ tan46°10' = .... sin46°10' = 7/BP BP = 7/sin46°10' = ....
*March 2, 2016*

**Trig**

Of course I can't see where your Ø is let's assume it is opposite the smallest side. 10^2 = 17^2 + 20^2 - 2(17)(20)cosØ 680cosØ = 589 cosØ = 589/680 Ø = appr 29.98° If otherwise, make the necessary changes
*March 2, 2016*

**Math**

1/2 ÷ 1/8 =
*March 2, 2016*

**Math**

be more specific please
*March 2, 2016*

**Algebra**

ummh, notice that two of the terms has a single decimal place with that decimal being an even number What happens when you multiply any even number by 5 ?
*March 2, 2016*

**finance**

PV = 3000(.96) + 3000(.96)^2 or PV = 3000(1/04)^-1 + 3000(1.04)^-2 depending on how "annual discount rate" is defined in your course. btw, they yield different results.
*March 2, 2016*

**Algebra**

pop(chessville) = 50,000(1.07)^n pop(checkerville) = 70,000(.96)^n we want to know when 50,000(1.07)^n ≥ 70,000(.96)^n divide by 10,000 5(1.07)^n = 7(.96)^n take logs of both sides and use rules of logs log5 + nlog1.07 = log7 + nlog.96 nlog1.07 - nlog.96 = log7 - log5 n(...
*March 2, 2016*

**precalculus**

Make a reasonable sketch. Using vectors and using R to be the resultant vector: R = (180cos300,180sin300) + (50cos245,50sin245) = (90,-90√3) + (-21.1309.. , -45.31538..) = (68.869.., -201.1996...) Magnitude = √(68.869^2 + (-201.1996..)^2) = appr 212.66 km direction...
*March 2, 2016*

**MATH.**

done yesterday http://www.jiskha.com/display.cgi?id=1456884647
*March 2, 2016*

**math**

6x^3 + 3x^2 - 9x what about it ?
*March 1, 2016*

**Math**

so number = a e^(kt) 10,000 = a e^(3k) 40,000 = a e^(5k) divide the 2nd by the 1st: 4 = e^(2k) 2k = ln4 k = (ln4)/2 so N = a e^( (ln4)/2 t) so we need a a e^(3ln4/2) = 10,000 a = 10,000/8 = 1250 initial count is 1250 bacteria
*March 1, 2016*

**math**

what is 6000(1.02)^28 ?
*March 1, 2016*

**Math**

time the dog wants to go outside in that time frame = (7/12)(60) = 35 minutes so not wanting to outside = 25 minutes percentage of time not going out = 25/60 = appr 42%
*March 1, 2016*

**Math**

prob = 6/10 = 3/5 a cube has 6 sides, so division by 6 would be the model for probs, we need a division by 5 or 10 or 15 ,etc
*March 1, 2016*

**Pre-Calc**

did you test the answer in the first equation? It clearly works in the last two equations.
*March 1, 2016*