Thursday

November 26, 2015
Total # Posts: 31,844

**Calculus**

very detailed solution: let 2log4 9 = x log481 = x 4^x = 81 2^(2x) = 81 let log2 3 = y 2^y = 3 2^4y = 3^4 = 81 then 2^(2x) = 2^(4y) ---> 2x = 4y x = 2y So 2log4 9 - log2 3 = x - y = 2y-y = y = log2 3
*July 8, 2015*

**Math**

let present amount be x x(1.05)^5 = 50000 x = 50000/1.05^5 = 39176.31
*July 8, 2015*

**Algebra (Normal Distribution)**

Here is the perfect website for your problem http://davidmlane.com/hyperstat/z_table.html
*July 8, 2015*

**maths**

Did you mean: (√(196/x) )*(√(90/x) ) = 4 or (√196)/x * (√(90)/x = 4 It makes a big difference
*July 8, 2015*

**mathematics**

I don't understand your question. You said that the five numbers given were picked, so the probability that five numbers should be selected would be 1 Not sure what you are asking.
*July 8, 2015*

**math**

the other is (-28/81) ÷ (14/27) = (-28/81)(27/14) = -2/3
*July 8, 2015*

**Math**

"...either a multiple of 3 or a number less than 7" only 2 elements satisfy that condition, namely the 3 and 6 so prob(of your event) = 2/18 = 1/9
*July 8, 2015*

**Maths**

If you are studying this, you must know (1+x)^n = 1 + nx + n(n-1)(x^2)/2! + ... valid only for |x| < 1 now let's apply it to your problem of 31^(1/5) = (32 - 1)^(1/5) = 32^(1/5)(1 - 1/32)^(1/5) = 2 (1 - 1/32)^(1/5)) = 2( 1 + (1/5)(-1/32) + (1/5)(-4/5)/2 (-1/32)^2 + (1/5...
*July 8, 2015*

**Algebra**

amount of the 20% stuff --- x L amount of the 50% stuff --- 200-x L .2x + .5(200-x) = .3(200) times 10 2x + 5(200-x) = 3(200) 2x + 1000 - 5x = 600 -3x = -400 x = 400/3 The chemist needs 400/3 L of the 20% solution and 200/3 L of the 50% solution
*July 7, 2015*

**Calculus**

dy/dx = x(-sinx) + cosx = 0 for a max/min xsinx = cosx sinx/cosx = 1/x tanx = 1/x No direct algebraic method to solve this, so we have to resort to other means let's look at the graph by Wolfram A preliminary look at y = xcosx shows that there would be an infinite number ...
*July 7, 2015*

**Calculus**

since v'(t) = a(t), which is the acceleration a(t) = -32 since a(t) is a constant, we get the acceleration due to gravity at -32 ft/s^2 and v'(1) = a(1) = -32 ft/s^2
*July 6, 2015*

**math**

Can we expect a question? btw, use 1/2 and 1/8 to show your fractions
*July 6, 2015*

**Algebra**

a + s = 598 s = a - 52 sub s = a-52 into the first equation a + a-52 = 598 2a = 650 a = 325 s = 325-52 = 273
*July 6, 2015*

**Math**

Let one be x metres long then the other is 150 - x x+40 = 2(150-x) x+40 = 300 - 2x 3x = 260 x = 260/3 m one is 260/3 m, the other is 150-260/3 or 190/3 m or in decimals, appr 86.67 m and 63.33 m. check: one is 86.67 twice the other is 126.67 which is 40 m more
*July 6, 2015*

**mathematics : intergration**

S = 4t - (1/2)t^2 + c "given that S=S when t=0" ????? I will assume you meant: given that S=0 when t=0 0 = 0 - 0 + c ---> c = 0 S = 4t - (1/2)t^2
*July 6, 2015*

**maths**

original --- x after first increase --- x + 1200 now decrease of 11% -- 89% are left .89(x+1200) = x-32 .89x + 1068 = x - 32 1100 = .11x x = 10,000
*July 6, 2015*

**Algebra**

The equation would be: n(t) = 5 (2^(t/20) , where t is in minutes (note that t/20 = (1/20)t = .05t) So they want the count after 4 hrs or 240 minutes n(240) = 5 (2^(240/20)) = 5 (2^12) = 5(4096) = 20480 you could do this the long way: now --- 5 after 20 min -- 10 after 40 min...
*July 5, 2015*

**maths**

start with a sketch of the finished product Let the triangle be ABC, so that angle B = 120°, angle BCA = 40° and angle CAB = 180-40-120 = 20° the centre of the triangle, O, lies on the right-bisectors of BC and AB, so that CO = AO = BO = 3 cm remember that the ...
*July 4, 2015*

**St jonhs high school/mathamatics**

√5 is obviously greater than √3 And you have 4 of the √5's vs 3 of the smaller value ! I really can't believe you asked this question.
*July 4, 2015*

**MATH**

" ..... find the polynomial whose zeroes are root 3 and -root 3" y = (x-√3)(x+√3) = x^2 - 3 What does the fact that alpha and beta are zeros of the the polynomial x^2 - 5x + 6 have to do with it? other than alpha = 2 and beta = 3
*July 4, 2015*

**Algebra**

(fog)(-2) = f(g(-2)) g(-2) = (-(-2))^3 + 1 = 10 f(10) = 3(10)+7 = 37 so (fog)(-2) = 37
*July 4, 2015*

**trigonometry**

did you make a sketch? If so you will see that sinØ = 30/40 = .75 Ø = appr 48.6° also: x^2 + 30^2 = 40^2 x^2 = 700 x = 7√10 or appr 22.1 ft
*July 4, 2015*

**Math**

children --- x grandkids --- 7-x children got (1/3)(6,000,000) = 2,000,000 so grandkids got 4,000,000 each grandkid got 4000000/(7-x) kids got 2000000/x each "200,000 more a piece than what each of the grandchildren" ---> 2000000/x - 200000 = 4000000/(7-x) times x...
*July 4, 2015*

**math**

thousandth digit --- t tens digit --------- 2t hundredth digit ---- t + 2t = 3t well, digits can only range from 0 to 9 let's rule out t = 0 , since that would not be a sensible number then tenth digit is obviously an even number so it could be 2,4,6,8 which means that t ...
*July 4, 2015*

**Applied Mathematics ( Mechanices**

your distance equation: height = -4.9t^2 + 14t + 29.4 at ground, height = 0 -4.9t^2 + 14t + 29.4 = 0 divide by -7 .7t^2 - 2t - 4.2=0 times 10 7t^2 - 20t - 42 = 0 t = (20 ± √1576)/14 = appr 4.26 seconds (or a negative)
*July 2, 2015*

**linear equations in two variable**

let the speed of the current be x km/h time against the current = 40/(5-x) time with the current = 40/(5+x) 40/(5-x) = 3(40)/(5+x) 1/(5-x) = 3(5+x) 15-3x = 5+x -4x=-10 x=2.5 the speed of the stream is 2.5 km/h check: time against the current = 40/2.5 = 16 hrs time withe the ...
*July 2, 2015*

**trigonometry26**

1 + sin^2 Ø = 3sinØcosØ divide by cosØ 1/cosØ + tanØsinØ = 3sinØ secØ + tanØsinØ = 3sinØ tanØ = (3sinØ - secØ)/sinØ = 3 - secØ/sinØ let's stop here...
*July 2, 2015*

**trigonometry 28**

This basic proof should be found in your textbook or in your notes. If not, just Google it, you will found many proofs.
*July 2, 2015*

**calculus**

the largest area of course is contained within a circle. So if the perimeter is 15 m then 2πr = 15 r = 15/(2π) area = π(15/(2π))^2 = 225/(4π) m^2 or appr 17.9 m^2
*July 2, 2015*

**calculus**

Ok, I will go with that assumption. As I made my diagram, I also noticed that you did not state the speed of the car B. I will also assume that the speeds are the same. At a time of t hrs, let the distance between them be x miles so by the cosine law: x^2 = (30+30t)^2 + (30t)^...
*July 2, 2015*

**calculus**

How are the two cars positioned relative to each other ? e.g. is car A directly west of car B ? is car A north of car B ?
*July 2, 2015*

**trigonometry**

use the fact that cos Ø = sin (90° - Ø) cos(3x - 10) = sin(90 - (3x-10) ) cos(3x - 10) = sin(100 - 3x) so sin(x-20) = sin(100 - 3x) then: x-20 = 100-3x 4x = 120 x = 30 check with your calculator
*July 2, 2015*

**trigonometry**

given: sinØ = a/b so y = a , x = ? r = b r^2 = x^2 + y^2 b^2 = x^2 + a^2 since we are in quad I, x = +√(b^2 - a^2) now use your definitions to state the trig ratios
*July 2, 2015*

**Math**

#1 is the interesting question Since the annuity payments become your "salary", I will assume they are made at the beginning of the year. IF x is the first payment made now , the Present Value is: PV = 8,503.05 + (1.03)(1.075)^-1 (8,503.05) + (1.03)^2 (1.075)^-2 (8,...
*July 2, 2015*

**Math**

I did this one yesterday http://www.jiskha.com/display.cgi?id=1435760969
*July 2, 2015*

**Math**

done yesterday http://www.jiskha.com/display.cgi?id=1435761181 why did you repeat the question?
*July 2, 2015*

**Math**

did you mean a = (√5 + 1)/(√5 - 1) and b = (√5-1)/(√5 + 1) ?? or the way you typed it
*July 1, 2015*

**Math**

27x^3+8y^3 --- the difference of cubes = (3x + 2y)(9x^2 - 6xy + 4y^2) = 12(9x^2 - 6xy + 4y^2) but 9x^2 - 6xy + 4y^2 = (9x^2 + 12xy + 4y^2) - 18xy = (3x+2y)^2 - 18xy = 144 - 108 = 36 so 27x^3 + 8y^3 = 12(36) = 4320 or: y = 6/x back in the first: 3x + 2(6/x) = 12 times x 3x^2 + ...
*July 1, 2015*

**Maths**

You will have 2 congruent triangles, so we need to find only the area of one of them Heron's formula: Area = √(s(s-a)(s-b)(s-c)) , were a, b, and c are the sides and s= half the perimeter s = (26+28+30)/2 = 42 s-a = 16 s-b = 14 s-c = 12 area = √(42x16x14x12...
*July 1, 2015*

**math in distress**

the second oldest could be either 9, 10, 11, or 12 All of the following satisfy the given conditons: 5 5 9 9 12 5 5 9 10 12 5 5 9 11 12 5 5 9 12 12
*July 1, 2015*

**math in distress**

one book weighs 2.5 lbs so 5 books weigh 5(2.5) or 12.5 lbs one notebook weighs 4 ounces 5 notebooks weigh 20 ounces = 1 lbs and 4 ounces , (if I recall the non-metric stuff) total = 12.5 lbs + 1 lb + 4 ounces, you were correct here = 13.5 lbs + .25 lbs = 13.75 lbs or 13 lbs ...
*July 1, 2015*

**math**

set up a simple ratio ... 1/x = (3/4) / 4 (3/4)x = 4 3x = 16 x = 16/3 I will take 5 1/3 quarts You will need to buy 6 quarts, (best bought as 1 gallon and 2 quarts) or, (by the 3 step process) 3/4 wall takes 1 quart one wall takes 1 / (3/4) quarts or 4/3 quarts 4 walls take 4(...
*July 1, 2015*

**correction - maths**

logx (1/8) = -3/2 means: x^(-3/2) = 1/8 x^(3/2) = 8 (√x)^3 = 8 √x = 2 x = 4 check: log4 (1/8) = log41 - log48 = 0 - 3/2 , (since 4^(3/2) = 8) = -3/2
*July 1, 2015*

**mathematics :geometric progression**

If geometric, then (2k-4)/(k-3) = (4k-3)/(2k-4) (2k-4)^2 = (k-3)(4k-3) 4k^2 - 16k + 16 = 4k^2 -15k + 9 -k = -7 k = 7 so the first 3 terms are: 4, 10, 25 a = 4, r = 2.5 sum(8) = a(r^8 - 1)/(r-1) = 4(2.5^8 - 1)/(2.5-1) = 4(390625/256 - 1)/(3/2) = 4(390369/256)(2/3) =4(130123/128...
*June 30, 2015*

**Tupper**

Never heard of a subject called Tupper. anyhow.... let the number of Katies truffles be x after first gifting: Katie had (3/4)x left she gave 1/2 of those away leaving her with (1/2)(3/4)x or (3/8)x truffles (3/8)x = 18 3x = 144 x = 48 So she started with 48 check: she gave 1/...
*June 30, 2015*

**math**

actually it is 1/18 since we are counting all 36 possible outcomes, our desired event could be 1,2 or 2,1 so 2/36 = 1/18
*June 30, 2015*

**math**

we have 1 - 7/9 + (7/9)^2 - (7/9)^3 + ... a = 1 , r = -7/9 sum∞ = a/(1-r) = 1/(1 - (-7/9) ) = 9/16
*June 30, 2015*

**MRGS SCHOOL.**

It says that any whole number greater than 1 is either prime itself or can be expressed as a product of two or more primes. e.g. 600 = 2x2x3x5 247 = 13x19 the factors in both examples are all made up of primes
*June 30, 2015*

**Math**

I know, I know, 6+2+5 ≠ 15, but maybe in the far distant past it was. That's what happens when you have to switch to the second hand to count, I always get confused if I have to count a finger as a carry.
*June 29, 2015*

**Math**

prob = (2/15)(5/12) = ...
*June 29, 2015*

**Mah**

prob of 2 nickels = (4/12)(4/12) = 1/9 so prob of not picking 2 nickels = 8/9 odds in favour of 2 nickels = (1/9) / (8/9) = 1 : 8 none of the choices are correct for the ODDS if you wanted the probability of getting 2 nickels it would be 1/9 the odds of an event is NOT the ...
*June 29, 2015*

**calc**

Maybe I should become a politician. Never actually answer the question, rather give an answer to some other question. Thanks for the catch Steve, that is two for one evening, I should get more sleep.
*June 29, 2015*

**calc**

slope = x/y = 3/1 = 3 so the equation of the tangent at the point (3,1) is y-1 = 3(x-3) y = 3x -8 or 3x - y - 8 = 0
*June 29, 2015*

**Calculus**

let the piece of paper be x inches wide and y inches long area of printed part = (x-4)(y-8) = xy - 8x - 4y + 32 but that equals 72 xy - 8x - 4y + 32 = 72 y(x-4) = 8x + 40 y = (8x+40)/(x-4) , clearly x > 4 amount of paper used = A A = xy = x(8x+40)/x-4) = (8x^2 + 40x)/(x-4) ...
*June 29, 2015*

**Cycle geometry**

So the exterior angle = 180-162 = 18° sum of exterior angles = 360° so 18n = 360 n = 20 It is a 20-gon
*June 29, 2015*

**Physics**

let's assume that for the first 1.95 seconds, the given acceleration of 44.3 m/s^2 includes the effect of gravity, and for any time thereafter the effects of gravity of -4.9 m/s^2 takes over for the first part: a = 44.3 v = 44.3t + c but when t = 0 (at the start) v = 0...
*June 29, 2015*

**Algebra**

amount of 15% juice --- x amount of 5% juice ---- 10-x .15x + .05(10-x) = .12(10) solve for x
*June 29, 2015*

**algebra**

Steve answered a similar question: http://www.jiskha.com/display.cgi?id=1435406901
*June 28, 2015*

**math**

the way you typed it, it is not a quadratic but a cubic e.g. 10x^2 - 1/x = 3 times x, 10x^3 - 1 = 3x 10x^3 - 3x - 1 = 0 , which is a cubic equation appr x = .67023 if you meant: (10x^2 - 1)/x = 3 then 10x^2 - 1 = 3x 10x^2 - 3x - 1 = 0 (2x - 1)(5x + 1) = 0 x = 1/2 or x = -1/5 ...
*June 28, 2015*

**Math**

I assume you are rounding to the nearest thousand since it rounds to 4000, the hundreds digit could only be 0,1,2,3, or 4 if the number starts with a 4 or only 5,6,7,8,9 if it starts with a 3 but the hundreds digit is twice the tens, so the hundreds digit must be even so cases...
*June 28, 2015*

**MATH**

number of 5RS coins --- x number of 2RS coins = .15x 5x + 2(.15x) = 1272 5.3x = 1272 x = 240 so 240 of the 5 RS coins, and 36 of the 2 RS coins
*June 28, 2015*

**Maths**

let the number of cookies be x let the number of friends by y x - 5y = 0 x - 3y = 36 subtract them: -2y = -36 y = 18 x - 5(18) = 0 x = 90 John has 90 cookies.
*June 28, 2015*

**Math**

starts with x spends half, so amount left = (1/2)x Spends 1/3 of that, so left with (2/3)of (1/2)x thus amount left = (2/6)x or (1/3)x but (1/3)x = 20 x = 60
*June 28, 2015*

**Geometry**

no, one other piece of information , such as one of the angles or one of the diagonals must be given. Many years back on Sesame Street, Oscar the Grouch took a rectangle and squished it, so its angles were no longer 90°. He then called it a wrecked-angle. Notice that if ...
*June 27, 2015*

**ahhh #2 - Math**

looks like our replies crossed. So there was an actual direction to your problem. Now you state: "Write each expression as a single logarithm" Why didn't you say that at the beginning and avoid all this confusion.?
*June 27, 2015*

**ahhh - Math**

Just thought I would play some "Jeopardy" with your post Alex Trebek : log3 (3x^2) me: What is 1 + log3 (x^2) simplified expanation: log3 (3x^2) = log3 3 + log3 (x^2) = 1 + log3 (x^2) so the two expressions are the same.
*June 27, 2015*

**Math**

1 + log3(x^2) is not a question 1 + log3(x^2) is an algebraic expression What do you want to do with it ? Do you want to solve something like 1 + log3(x^2) = 0 ? Do you want to colour it blue? Do you want to sent it to Donald Trump as a campaign slogan? etc The way it stands, ...
*June 27, 2015*

**Math**

just replace y with x, since it says y = x 2x^2 - x^2 = 1 x^2 = 1 x = ±1 if x = 1, then y = 1 if x = -1, then y = -1
*June 27, 2015*

**Maths**

arrangements in a line = 5! = 120 around a circle, with no specified position around the table = 5! / 5 = 4! = 24 e.g. for any arrangement of the 5 people around the table, everybody could get up, move once to the left, and the arrangement would not change, etc . We could do ...
*June 27, 2015*

**Math**

A: x > 14 , so NO B: x > 77/2 , so NO C: x = -8 , so NO D: x ≤ 26/3 or x ≤ 8 2/3 , YEAH, since 8 ≤ 8 2/3
*June 26, 2015*

**Geometry**

Just use ordinary keyboard keys According to the properties of tangents to circles, AO is perpendicular to PA making angle PAO = 90°, thus angle angle POA = 90-32 = 58° The same property is true for angle POB since PA = PB , angle POB = 58° Then angle AOB = 116°...
*June 26, 2015*

**math**

possible numbers: 111111 222222 .... 999999 largest such number: 999999 number from above with a sum of 6 : 111111 999999 - x = 111111 x = 888888
*June 26, 2015*

**Probability**

sounds like conditional probabilty Prog(A|B) , (read as the prob of A, given B) = prob(A AND B)/prob(B) prob(A and B) = 1/15 prob(B) = 7/15 prob( as stated) = (1/15) / (7/15) = 1/7 (of course, since the 4 is one of the 7 even numbers from 1 - 15)
*June 25, 2015*

**Algebra**

I agree with Ms Sue To show us that you are not merely sponging off us, for the question above, I would be interested in your thinking to solve the problem So you want whole numbers m and n so that 3^m + 2^n ≤ 999
*June 25, 2015*

**Algebra**

make a list of possible coins to give you 38 cents e.g. Q D N P 1 1 0 3 1 0 2 3 ... 0 0 7 3 ... then pick the one where the sum of coins is 8
*June 25, 2015*

**Advanced Algebra**

Use your definition of an arithmetic sequence. The difference between any pair of consecutive terms must be the same, if subtracted in the same direction, that is .... (4m-8) - (m) = (m^2 - 6) - (4m-8) 4m - 8 - m = m^2 - 6 - 4m + 8 0 = m^2 - 7m + 10 (m - 2)(m - 5) = 0 m = 2 or...
*June 25, 2015*

**Math: Compounded Interest**

for semi-annually .... amount = 200( 1.025)^(1/2) = 202.48 , not 201.20
*June 25, 2015*

**Math**

Steve, your graph does not agree with your solution, so looking at it carefully, I had the same up to 3(√(x^2 + y^2) = 1 + 4y square both sides 9(x^2 + y^2) = 1 + 8y + 16y^2 9x^2 + 9y^2 - 16y^2 - 8y = 1 9x^2 - 7y^2 - 8y = 1 you forgot to square the 3 I am sure Justine ...
*June 25, 2015*

**math**

1 km = 1,000 metres = 100,000 cm = 1,000,000 mm so 18 mm = 18/1000000 km = .000018 km nobody using the metric system would measure mm in km !
*June 25, 2015*

**Math (arithmetic)**

In your arithmetic series: a = 21 d = 1 n = ?? sum(n) = 1065 1065 = (n/2)(2(21) + (n-1)(1) ) 2130 = n(42 + n - 1) 2130 = n^2 + 41n n^2 + 41n - 2130 = 0 (n-30)(n + 71) = 0 n = 30 or n = -71 , but n > 0 there are 30 rows
*June 25, 2015*

**math 2**

prob = (8/18)(6/18) = .....
*June 25, 2015*

**mathematics**

"product" is the result of multiplication, so ... just multiply them.
*June 25, 2015*

**Math**

Just translate .... "My hundreds digit means nothing." ----> XX0XX "Six more than my hundreds digit is my thousand’s" --->X60XX "ones less than my thousands’ is my ten thousands" ---> 560XX "My tens digit is four more than ...
*June 25, 2015*

**Math**

Review the laws of exponents First of all √2 = 2^(1/2) then √(1/2) = √1/√2 = 1/√2 = 1/2^(1/2) = 2^(-1/2) based on 1/a^n = a^-n
*June 24, 2015*

**Math**

It would be so much easier if we could identify you by some name other than Anonymous.
*June 24, 2015*

**Algebra**

Damon did a whole bunch of those for you yesterday. The idea is to use a previous solution and apply it to a new question. x^2 + ax + 25 = (x + ???)^2 Gee what do you think we need so when squared we will get 25? And what will be the middle term if we expand that?
*June 24, 2015*

**Math**

You will have to know the 3 prime properties of logs 1. logk (AB) = logk A + logk B 2. logk(A/B) = logk A - logk B 3. logk (A^n) = n logk A where k is any positive number , k ≠ 1 so log2√36 - log2 log2</sub√72 = log2 (√36/√72) = log2 √(36...
*June 24, 2015*

**math**

You posted the same question yesterday, and Steve pointed out to you that you are missing some important data http://www.jiskha.com/display.cgi?id=1435116033 and yet you posted it again exactly the same way.
*June 24, 2015*

**Geometry**

The diagonals of the prism are formed by the height of the prism, which is 12 cm, and the diagonals of the base rhombus. I will do one of the diagonals , you do the other. for acute angle of the rhomus: sinØ = 9.6/10 Ø = 73.7° the the obtuse angle is 106.3&...
*June 24, 2015*

**dav public**

Not enough information, you need either another angle or another side
*June 24, 2015*

**Algebra**

R(P) = .37 ln P + .05 when P = 532 walking speed = .37ln 532 + .05 = 2.372 ft/s ?????
*June 23, 2015*

**math**

when is 5,592,000(1.038)^n = 14,000,000,000 5.592 x 10^6 (1.038)^n = 1.4 x 10^10 1.038^n = 2503.576... n log 1.038 = log 2503.576.. n = 209.8 years What a silly question.
*June 23, 2015*

**math**

Are you sure these logs weren't added ? then we could do something, but the way it sits, I see no simplification
*June 23, 2015*

**math**

correct
*June 23, 2015*

**math**

What is 5000(1.035)^16 ?
*June 23, 2015*

**math**

log2 8 = 3 <-----> 2^3 = 8 I actually had my students write this down in their notebooks, highlight it, and memorize it It clearly shows where the numbers go in the conversion of one format to the other.
*June 23, 2015*

**Math**

3/5 < n/7 < 4/5 multiply by 35 , the LCD 21 < n < 28
*June 23, 2015*

**Math**

The question only makes sense if we know the definition of x. Is x the number of years since 2000?
*June 23, 2015*

**Math**

A = 2 , term(10= ar^9 = 1024 then 2 r^9 = 1024 r^9 = 512 take 9th root r = 2
*June 23, 2015*

**math**

Possible cases: 3A0AA0 5A2AA1 7A4AA2 9A6AA3 , where A can be any number from 0-9 since those positions have not been defined If we make the unit digit 4, then the thousand digit is 8 and the hundred thousand digit would be 11 ???? Now fill in any digits for A that you like.
*June 23, 2015*