Thursday

September 3, 2015
Total # Posts: 30,714

**Calculus**

yes, you can split it into x/(x^2 + 9) + 3/(x^2+9) the first part becomes (1/2) ln(x^2 + 9) and the second part becomes sin^-1 (3/x) .... (had to look that one up in my old-fashioned table of integrals) don't forget to add the constant
*March 29, 2015*

**calculus**

Just noticed that all of the 10 "Related Questions" below are your problem. Steve assumed P(V^(1/4) = C http://www.jiskha.com/display.cgi?id=1414421171
*March 29, 2015*

**calculus**

not sure of your equation, is it (PV)^1.4 = C or P(V^(1.4)) = C or 1.4PV = C , (usually we don't write a multiplier after the variable like in yours)
*March 29, 2015*

**Math**

no, it would be correct if you included a sketch. I would give you full marks.
*March 29, 2015*

**Math**

Depends where you place the arch on your graph. I centered mine so the top is (0,88) and its x-intercepts are (42, 0) and (-42,0) so using the vertex form of the parabola equation, I get y = ax^2 + 88 but (42,0) lies on it 0 = 1764a + 88 a = -88/1764 = -22/441 which yields the...
*March 29, 2015*

**exponential equations**

2500(1.0275)^t = 3500 1.0275^t = 7/5 = 1.4 take log of both sides and use rules of logs t log 1.0275 = log 1.4 t = log 1.4/log 1.0275 = 12.4 It will take 12 years and appr 5 months
*March 29, 2015*

**Math**

you would get (1-2)^1 + (1-1)^2 + (1 - 2/3)^3 + (1-2/4)^4 + (1-2/5)^5 + .... (1 - 2/100)^100 + ... = -1 + 0 + 1/27 + 1/16 + 243/3125 + ... (49/50)^100 + ... notice that the terms are actually increasing and as k becomes larger, the terms approach 1 so the sum becomes ...
*March 29, 2015*

**Calculus**

tan (3x) = sin(3x)/cos(3x) so ∫tan(3x) dx = ∫sin(3x)/cos(3x) dx = -(1/3) ln(cos(3x)) + c
*March 29, 2015*

**Calculus 1**

R^-1 = R1^-1 + R2^-1 -R^-2 dR/dt = -R1^-2 dR1/dt - R2^-2 dR2/dt ** 1/R^2 dR/dt = 1/R1^2 dR1/dt + 1/R2^2 dR2/dt ** when R1 = 80, R2 = 110 1/R = 1/80+1/110 = 19/880 R = 880/19 now you have the values in ** , and you can solve for dR/dt
*March 29, 2015*

**Geometry check**

No, I got the side to be 18/√3 check how I did your other question dealing with the equilateral triangle.
*March 29, 2015*

**math**

let Maya's original number of beads be 12x and Kayla's be 7x Maya bought another 28 , now has 12x+28 Kayla gave away 32, now has 7x-32 but 7x-32 = 57 x = 89/7 , which is not a whole number. Something is not right with your question, check your numbers or your typing
*March 29, 2015*

**Geometry help**

Did you make a sketch of an equilateral triangle? draw in the "centre", and the "radius", and the height (the apothem) I see a right-angled triangle with a hypotenuse of 6√3, and angles 30° , 60° and 90° label the base as x and the height ...
*March 29, 2015*

**math**

Molly's original amount ---- x Will's original amount ------y after give-away: Molly has x+9 Will has y-9 but then x+9 = y-9 y = x+18 after hypothetical other case: Molly has x-9 Will has y+9 (x-9)/(x+9) = 1/2 2x - 18 = y+9 y = 2x - 27 so 2x - 27 = x + 18 x = 45 , then...
*March 29, 2015*

**Math**

let the side parallel to the open side by y m let each of the other two sides be x m 2x + y = 52 y = 52-2x area = xy x(52 - 2x) = 240 -2x^2 + 52x - 240 = 0 x^2 - 26x + 120 = 0 (x-20)(x-6) = 0 x = 20 or x = 6 if x = 20, then y = 52-40 = 12 if x = 6, then y = 52-12 = 40 make a ...
*March 29, 2015*

**Calculus**

y = x^(1-x) take ln of both sides ln y = ln (x^(1-x) = (1-x)(ln x) ln y = (1-x)(ln x) don't really see what can be gained by that, unless you were asked to find the derivative of the original. Now it can be done.
*March 29, 2015*

**Calculus**

Can't be taken any further, unless you want to use logs Don't know what you mean by "basic simplification".
*March 29, 2015*

**Calculus**

f(x) = ln(x^2 + 1)^(1/2) - (ln x + ln(2x^3 - 1)^2 = (1/2) ln(x^2 + 1) - ln x - 2ln (2x^3 - 1)
*March 29, 2015*

**Differential Calculus**

let the radius of circle be r let the side of the square be x 4x + 2πr = 10 2x + πr = 5 x = (5 - πr)/2 total area = πr^2 + x^2 replace the x with (5 - πr)/2 careful with the squaring. a) Differentiate, set that equal to zero and solve for r sub back ...
*March 29, 2015*

**Algebra**

first of all let's simplify the example -3 < x+5 < 8 subtract 5 from each part -8 < x < 3 In this notation, a < x < b, a is usually less than b and x is any value "between" them. As a matter of fact, I recall one text actually calling this the &...
*March 29, 2015*

**Math**

d^2 = t^2 + (5t)^2 = 26t^2 d = t√26 is correct
*March 28, 2015*

**Math**

I am almost sure you meant: 6/(√3 + 2) then ... = 6/(√3 + 2) * (√3-2)/(√3-2) = (6√3 - 12)/(3-4) = 12 - 6√3 , you are correct btw, those brackets I put in are essential, or else you would have two terms
*March 28, 2015*

**math**

If g(x) = √x then (f/g) (x) = (x^2 + 3)/√x domain: all real values of x, x ≠ 0
*March 28, 2015*

**Math**

the answer I should get is 18.2955 let x = 3^√7 then x^(1/√7) = 3 x^(1/√7) - 3 = 0 let y = x^(1/√7) - 3 = x^.3779645 - 3 dy/dx = (1/√7)^(1/√7 - 1) = .3779645 x^-.62204 iteration expression: x - (x^.3779645 - 3)/(.3779645x^-.62204) x = 2...
*March 28, 2015*

**geometry**

Triangle PQS has all 3 sides given, so using the cosine law, we can find angle P The use the cosine law again in triangle PRT to find RT
*March 28, 2015*

**Math questions**

#1, does he pay off the remaining 110320 with a single payment after 30 years, or does he make monthly payments? the fact you are using the word "mortgage" appears to suggest there are monthly payments involved. Confirm before I answer #1 #5. I confirm the $144 ...
*March 28, 2015*

**math**

total time from 1:00 to 6:00 is 5 hours or 300 minutes each half hour is 30 minutes, so number of students needed = 300/30 = 10
*March 28, 2015*

**math**

You have listed playing football and basketball playing twice, with different numbers. I will conclude that the second football and basketball should be football and volleyball. Made a Venn diagram filled in the data as given, and got this equation. 2x + 2x + 2x + x + 20+15+26...
*March 28, 2015*

**Math**

a = 124 a/(1-r) = 64 124/(1-r) = 64 124 = 64 - 64r r = -60/64 = -15/16
*March 28, 2015*

**Math**

c must be 225/4 or 56.25 take 1/2 of 15, then square it check: (x + 15/2)^ = x^2 + 15x + 225/4
*March 27, 2015*

**Algebra**

(x^15 y^18)/a^15
*March 27, 2015*

**dps**

log 10^25 + 10log 10^4 = 25log10 + 10(4)log10 , recall log10 = 1 = 25 + 40 = 65
*March 27, 2015*

**Pre-Calculus**

You are correct, but write it as x = (-5 ± √37)/6 I use a Mac and to get √7 I press "option v"
*March 26, 2015*

**math**

done, check to earlier post of this
*March 26, 2015*

**Math Check**

#1 should be A, look at your last sum (1/2)[ ..0 + 9 ] = [ ....9/2] #2 you have a 1 by 3 matrix multiply by a 3 by 1 which will give you [(6+6+0)] = [12]
*March 26, 2015*

**Math**

your discriminant is correct so for 2 points: 100-4k^2 > 0 -4k^2 > -100 k^2 < 25 -5 ≤ k ≤ +5 for 1 point k = ± 5 for 0 points, 100 - 4k^2 < 0 k < -5 OR k > 5
*March 26, 2015*

**math**

At the ends it could be Jeff, Dariya or Dariya, Jeff So for the first row: 2x3x2x1 or 12 ways, leaving 15! for the other positions. but there are 4 rows, prob(of your event) = 4x12(15!)/20! = .000025799
*March 26, 2015*

**Math**

clearly false All you need is one exception to the rule and the rule becomes bogus since 6+7 = 13 and 13 is NOT a composite number the statement is false.
*March 26, 2015*

**math**

It would work if you had used the correct number 1 1/6 weeks is NOT 1.16 it is 7/6 , so secondly, this is not a direct proportion, but rather an inverse proportion. That is, the more workers you have, the less time it takes. the correct proportion is 5/x = (7/6) / 3.5 then (7/...
*March 26, 2015*

**math**

think of it in terms of "workweeks" Number of total workweeks needed is 5(3.5) or 17.5 that is workweeks = number of workers x number of weeks so number of workers = workweeks/number of weeks = 17.5/(7/6) = 17.5(6/7) = 15
*March 26, 2015*

**Algebra**

in your first equation the coefficient of y is 1, so that becomes your obvious choice. y = 5x - 3 sub that into the 2nd 3x - 8(5x-3) = 24 3x - 40x + 24 = 24 -37x = 0 x = 0 back into y = 5x-3 y = 0 - 3 = -3 x = 0 , y = -3
*March 26, 2015*

**Math**

Wolfram shows 2 solutions, which verify when substituted. http://www.wolframalpha.com/input/?i=+solve++ln%28x%2B3%29+%3D+-3%2Be%5Ex+ btw, I assume that your f ' (x) is not the derivative of the given f(x) .
*March 26, 2015*

**Calculus**

This is the same type of question as your previous one dealing with rent increases. Follow my steps, by defining the number of $16 rebates as n for c) recall that profit = revenue - cost so just subtract the cost expression from your expression from a) and repeat the steps.
*March 25, 2015*

**Calculus**

let the number of $10 increases be n new rent = 460+10n number rented= 80-n Revenue = (80-n)(460+10n) = 36800 + 340n - 10n^2 d(Rev)/dn = 340 - 20n = 0 for a max/min 20n=340 n = 17 So there should be an increase of 17(10) or 170 and the new rent should be 630 and 63 units would...
*March 25, 2015*

**math**

cannot be determined as the data is written. e.g. are the data values exlusive, that is, how do we know that some students like the program but still think it is unnecessary. How are the 220 who are running for government distributed among the 190 who like the program, and ...
*March 25, 2015*

**Math**

sigh !
*March 25, 2015*

**calculus**

f ' (x) = (x^2+1) -(x)(2x) all over (x^2+1)^2 = (x^2 + 1 - 2x^2)/(x^2+1)^2 = (1 - x^2)/(x^2 + 1)^2 You can be sure that the denominator will always be positive, so let' just look at the top. recall that a function is increasing when its derivative is positive, and it ...
*March 25, 2015*

**algebra**

I looked at how Steve answered your question and he did it correctly. (Trust Steve's answers !!) The way you just typed it now, it would be √18/√18 - 3 which would simply be 1 - 3 or -2
*March 25, 2015*

**Payment calculation**

i = .045/12 = .00375 n = 10(12) = 120 paym( 1 - 1.00375^-120)/.00375 = 100000 you do the button pushing, you should get $1036.38
*March 25, 2015*

**math**

If I read this correctly as an = (1/5) an-1 , where 1 = 20 then 1 = 20 2 = 4 3 = 4/5 etc then this not an arithmetic but rather a geometric sequence with a = 20 , r = 1/5 t6 = ar^5 = 20(1/5)^5 = 20/3125 = 4/625
*March 25, 2015*

**Math payment calculation**

i= .12/12 = .01 n = 12(30) = 360 Paym( 1 - 1.01^-360)/.01 = 100000 paym(97.218331..) = 100000 payment = $1028.61
*March 25, 2015*

**geometry**

r = 17/2 = 8.5 V = (4/3)π r^3 = (4/3)π(8.5)^3 = appr 2575.44 inches^3 mass = 2575.44(.033) = 84.89 pounds seems very unreasonable. A hailstone with a diameter of 17 inches ? ABsurd
*March 24, 2015*

**Business mathematics**

What is 650(1.04)^5 - 650 ?
*March 24, 2015*

**algebra--1 question**

SA = 4πr^2 = 4π(4x+1)^2 = 4π(16x^2 + 8x + 1) = 64πr^2 + 32πx + 4π None of the choices match this
*March 24, 2015*

**mathhhhhhhhhhhhhhhhhhh**

All I did was to sub in your choice into each of the equations. #7 is correct, the other two are not #5 since both say y = ... we can substitute: x-2 = 6-x 2x = 8 x = 4 back in the first: y = 6-4 = 2 , so (4,2) #6 , same way ... 2x-1 = x+3 x = 4 then y = 8-1 = 7 solution: (4,7)
*March 24, 2015*

**Probablity**

sum of six: 1,5 2,4 3,3 4,2 5,1 ---> 5 ways top faces the same: 1,1 2,2 3,3 4,4 5,5 6,6 ---> 6 ways number of ways of our event = 5+6-1 (can't count the 3,3 twice) = 10 prob(of our event) = 10/36 = 5/18
*March 24, 2015*

**Needs help in math**

x/4 + (3/5)(3x/4) + 3600 = x x/4 + 9x/20 + 3600 = x times 20 5x + 9x + 72000 = 20x 72000 = 6x x = 12000 metres -- the total distance check: swims 1/4 of 12000 or 3000 , leaving 9000 paint left over = 5 quarts 1 square foot takes 1/8 of quart, so number of square ft = 5/(1/8...
*March 24, 2015*

**maths**

at least 2 the same ---> 1 - prob(all different) = 1 - 6*5*4/216 = 1 - 120/216 = 96/216 = 4/9
*March 24, 2015*

**math**

prob(score) = 6/8 = 3/4 prob(not score) = 1/4 odds in favour of scoring = (3/4) : 1/4) = 3 : 1 you are right.
*March 24, 2015*

**geometry**

V= (1/3)π r^2 h 600π = (1/3)πr^2h 1800 = r^2 h h = 1800/r^2 pick any r value you feel like, then evaluate h e.g. r = 9 h = 1800/81 = 200/9 or 22.22.. find as many as you want
*March 23, 2015*

**math**

new square: (x+2)(x+2) (x+2)^2 - 4 = 21 x^2 + 4x +4 - 4 - 21 = 0 x^2 + 4x - 21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3, x = -7 making no sense new square = 2+3 or 5 units long check: old square = 2x2 = 4 new square = 5x5 = 25 increase is 25-4 = 21 , as given All is good
*March 23, 2015*

**Algebra 1**

1. Rule: a^x * a^y = a^(x+y) b^(1/6)^3 * b^(1/6) = b^(1/2) * b^(1/6) = b^(1/2 + 1/6) = b^(2/3) 2. (2x^-3)^2 (0.2x)^2 = 4x^-6 * .04x^2 = .01 x^-4 3. (3^7)^2 (3^-4)^3 = 3^14 * 3^-12 = 3^2 = 9
*March 23, 2015*

**Math**

looks like we are increasing the previous number by 4, so ..... let me know what you think.
*March 23, 2015*

**Calculus**

Did you make a sketch? I called her distance from the pole x ft, and the length of her shadow y ft So by similar triangles, 6/y = 15/(x+y) 15y = 6x + 6y 9y = 6x 3y = 2x 3dy/dt = 2dx/dt we know that dx/dt = 5 3dy/dt = 10 dy/dt = 10/3 ft/sec So her shadow is increasing at 10/3 ...
*March 23, 2015*

**math**

amount = 2500(1.06)^15 = 5991.40 so the interest for that time is $3491.40
*March 23, 2015*

**Calculus**

let the height of the water level be h m let the radius of the water level be r m we are told r/h = 1.75/13 = 7/52 52r = 7h r = 7h/52 let the rate at which water is pumped be x m^3/min V = (1/3)π r^2 h = (1/3)π(49h^2/2704)h = (49π/8112) h^3 dV/dt = (49π/...
*March 23, 2015*

**Absolute value inequalities**

1 - 3|7-x| ≤ -11 -3|7-x| ≤ -12 |7-x| ≥ 4 7-x ≥ 4 or -7+x ≥ 4 -x ≥ -3 or x ≥ 11 x ≤ 3 OR x ≥ 11 I think that matches your answer.
*March 23, 2015*

**Calculus**

V = (4/3)π r^3 dV/dt = 4π r^2 dr/dt when r = .6 , dV/dt = 3.2 3.2 = 4π(.6)^2 dr/dt dr/dt = 3.2/(1.44π) = appr .707 so d(diameter)/dt = 1.415 ft/min
*March 23, 2015*

**Math help check**

8t^5 x 8t^5 = (8)(8)(t^5)(t^5) = 64t^10
*March 23, 2015*

**Algebra**

.76 = 1 (1/2)^(t/5730) log both sides: log .76 = (t/5730) log .5 t/5730 = log .76/log .5 = .39592... t = 2268.67 years or t = appr 2300 years, correct to the nearest 100 yrs.
*March 23, 2015*

**algebra 2**

1. I will assume you mean 4(fifthroot(3x+1) - 8 = 0 4(3x+1)^(1/5) = 8 (3x+1)^(1/5) = 2 raise both sides to the 5th power 3x+1 = 2^5 3x+1 = 32 3x = 31 x = 31/3 #2, same way (5m+6)^(1/3) = -13 cube both sides 5m+6 = -2197 5m= -2203 m = -2203/5 or -440.6
*March 23, 2015*

**Math**

#1 For which choice has the y value been increased by 3 ? #2. mmmh, which choice has the 3 subtracted from the x, and 2 added to the y ? #3, wow, let's see now, starting with (4,3) we added 2 to the x and subtracted 5 from the y to get ..... ?
*March 23, 2015*

**math**

50% larger than a right angle would be (90+45)° or 135° That leaves 45° for the two equal angles, making each one 22.5°
*March 23, 2015*

**math**

8/7 = 56/x 8x = 392 x = 49 You are correct
*March 23, 2015*

**calc**

I assume you made a diagram. I let the angle of elevation be Ø, and the horizontal distance of the plane as x km In mine, tanØ = x/5 xtanØ = 5 dx/dt tanØ + x sec^2 Ø dØ/dt = 0 when Ø = π/3 , (I recognize the 30-60-90° ...
*March 23, 2015*

**Trig**

let the base be 2x Construct an altiude to the base, resulting in a right-angled triangle with hypotenuse 4, angle 15° and opposite side x sin15 = x/4 x = 4sin15 so the base is 2x, or 8sin15° you do the button pushing.
*March 23, 2015*

**math**

looks like Damon is still cleaning seagull poop .... prob(busy) = 1/10 prob(not busy) = 9/10 prob(at least 3 of 6 are busy) = C(6,3)(1/10)^3 (9/10^3) + C(6,4) (1/10)^4 (9/10)^2 + ... + C(6,6) (1/10)^6 I will let you do the button-pushing
*March 23, 2015*

**arithmetic**

a+d = 8 a+3d = 14 subtract them: 2d = 6 d = 3 I will let you finish it
*March 23, 2015*

**Calculus**

since you are dealing with "half-life" , we can use the formula amount = c (1/2)^(t/40) amount = 700 (1/2)^(t/40) when t = 40, amount = 350 so when t = 30 amount = 700 (1/2)^(30/40) = 700 (1/2)^.75 = 416.22.. mg reading your question again, I gather you want to use ...
*March 23, 2015*

**Algebra**

I am not happy to learn that I went through the effort of solving the question to relieve your boredom.
*March 23, 2015*

**Algebra**

carefully expand to get x^4+12x^3+47x^2+72x+36 - 3x^2 = x^4 + 12x^3 + 44x^2 + 72x + 36 I assume it will factor, (or else why have the question?) I tried all possible factors of 36, and none made the expression zero, so there are no binary factors with rational numbers. I then ...
*March 23, 2015*

**Calculus**

I strongly suggest you listen to the two videos by Khan In the first he establishes the formula: T(t) = c e^(-kt) + Ta , where Ta is the ambiant temperature. your given data will be: Ta = 34 T(0) = 70 T(30) = 52 your t will be in minutes The first video results in the basic ...
*March 23, 2015*

**Urgent geometry help**

Still makes no sense. If the bottom angle is 45° and it is isosceles, then you have a right-angled triangle.
*March 22, 2015*

**Urgent geometry help**

You seem to have conflicting data. Where is the 45° angle ? if the base is 12 and the two equal sides are 32 each, then there can't be a 45° angle. If the base is 32 and the two equal sides are 12, you will not be able to draw the triangle, since that is not possible.
*March 22, 2015*

**Math**

with semi-annual compounding: amount = 4000(1.07)^16 = ...... with quarterly compounding: amount = 4000(1.035)^32 = ....
*March 22, 2015*

**Math**

What was your quadratic equation ? Make sure that all your points satisfy it, if even one of them does not work, your equation is wrong. If they do, and a is negative, then it opens downwards. If your a is positive then it opens up
*March 22, 2015*

**trig**

Several ways to do this. This might be the easiest to understand ... Make a sketch of a right-angled triangle in quad II since cosA = x/r = -6/7 x = -6 and r = 7 (remember r is always positive) by Pythagoras: x^2 + y^2 = r^2 36 + y^2 = 49 y^2 = 13 y = ±√13 , but ...
*March 22, 2015*

**Pre algebra**

1. amount of 5.0% stuff --- x ml amount of 50% stuff ---- 20-x .05x + .5(20-x) = .075(20) .05x + 10 - .5x = 1.5 -.45x = -8.5 x = -8.5/-.45 = 18.888... or appr 18.9 ml 2. don't understand the problem, no idea what AWP is
*March 22, 2015*

**Math**

When the 2nd overtakes the first, they will have travelled the same distance: let the time of the first plane since 1:00 pm be t hrs distance covered by first plane = 400t miles let the time of the 2nd plane be t-2 hrs distance covered by 2nd plane = 600(t-2) 400t = 600(t-2) ...
*March 22, 2015*

**Math**

according to the order of operations, 5 squared + 8 divided by 2 =25 + 8/2 =25+4 = 29
*March 22, 2015*

**math**

of the 26 letters, how many are vowels ? so prob = ?/26
*March 22, 2015*

**math**

since they are parallel, k/6 = 3/2 2k = 18 k = 9
*March 22, 2015*

**Math**

1. I will assume you want simple interest rather than compound interest, judging by the level of the other questions. amount paid = 6(516.5) = 3099 interest paid = 99 I = PRT R = I/(PT) = 99/((3000)(.5)) = .066 or 6.6% How did you get .33% ???? 2. This question makes little ...
*March 22, 2015*

**maths**

since A+B = 90 B = 90-A and sinB = sin(90-A) = cosA similarly cosB = sinA sinAsinB = sinAcosA = (1/2)sin 2A thus y = (1/2)sin 2A has an amplitude of 1/2 so the range is -1/2 ≤ y ≤ 1/2
*March 22, 2015*

**related rates calculus 1**

from 15 = π/9 (100)dh/dt I multiplied both sides by 9/(100π) which left me with dh/dt on the one side and 15(9/(100π) ) or 135/(100π) on the other side
*March 22, 2015*

**related rates calculus 1**

height ------- h base radius --- h/3 V = (1/3)π r^2 h = (1/3)π (h^2/9)(h) = (π/27) h^3 dV/dt = (π/9) h^2 dh/dt for the given data: 15 = π/9 (100)dh/dt dh/dt = 135/(100π) ft/hr
*March 22, 2015*

**Algebra**

let the border be x cm wide picture is (30-2x) by (36-2x) (30-2x)(36-2x) = 480 1080 - 132x + 4x^2 - 480 = 0 4x^2 - 132x + 600 = 0 x^2 - 33x + 150 = 0 solve using the quadratic equation,
*March 22, 2015*

**Advanced Algebra**

It would simply be 10 x 9 x 8 x 7 or 5040 ways This is the same as P(10,4) = 10!/(10-4)! = 10!/8! = 5040
*March 22, 2015*

**Math**

Set them equal or R(x) - C(x) = 0 2x + 10 = -5x^2 + 21x 5x^2 - 19x + 10 = 0 x = .6311 thousand or appr 631 or x = 3.169 thousand or appr 3169 check: if x = .6311 , R(.6311) - C(.6311) = .00053.. , not bad if x = 3.169 , ...... = .001805 both answers are valid
*March 21, 2015*

**Pre-Calculus**

It is considered "better form" to have your quadratics start with a positive x^2 term So for #2, I would write: 6x^2 - 25x + 24 = 0 , (just switch all the signs, like multiplying by -1) Each of your roots satisfy your equations, but each of your quads should have a ...
*March 21, 2015*

**algebra**

Is y = -3x^2 - 4x + 3 supposed to be your answer ? Can't be right, since (0,-4) clearly does not satisfy your equation. Method1: let the equation be ax^2 + bx+c = y for (0,-4), 0+0+c=-4 , c = -4 for (-2,-20), 4a-2b - 4 = -20 4a - 2b = -16 2a - b = -8 for (4,-20), 16a + 4b...
*March 21, 2015*