Friday

August 22, 2014

August 22, 2014

Total # Posts: 26,966

**Math**

first tell me what you got for your inverse matrix
*March 25, 2014*

**Geometry B**

x^2 + y^2 − 2x + 2y − 1 = 0 , notice how we indicate exponents complete the square x^2 + y^2 − 2x + 2y = 1 x^2 - 2x + 1 + y^2 + 2y + 1 = 1+1+1 (x-1)^2 + (y+1)^2 = 3
*March 25, 2014*

**math**

http://www.wolframalpha.com/input/?i=y+%3D+1%2F%283-x%29 asymptote at x = 3
*March 25, 2014*

**discrete mths**

(white, red) ----> 12 13 14 15 16 (5 of them ----> 23 24 25 26 (4 of them) ----> 34 35 36 (3 of them) ----> 45 46 (2 of them) ----> 56 just one so 5+4+3+2+1 = 15 prob(your event) = 15/36
*March 25, 2014*

**algebra 2**

complete the square ... y = -4(x^2 - (3/4)x .....) - 6 , (we usually don't say +-6 to adding a negative 6 ) = -4(x^2 - (3/4)x + 9/64 - 9/64) - 6 , ( take 1/2 of 3/4 to get 3/8, now square that ----> 9/64 = -4( (x - 3/8)^2 - 9/64) - 6 = -4(x-3/8)^ + 9/16 - 6 = -4(x - 3/8...
*March 25, 2014*

**Trigonometry**

http://www.wolframalpha.com/input/?i=y%3D2sin%28x-2pi%2F3%29 for x-intercepts, y = 0 2sin(x-2pi/3) = 0 sin(x-2pi/3)=0 but sin 0 = 0 and sin π =0 and sin 2π = 0 so x - 2π/3 = 0 and x -2π/3 = π and x - 2π/3 = 2π x = 2π/3 or x = π + 2...
*March 24, 2014*

**math**

amount in B ---- x amount in A -----x - 8000 .04x + .08(x-8000) = 1040 times 100 4x + 8(x-8000) = 104000 I am sure you can finish it
*March 24, 2014*

**Algebra**

-5 + 2x^2 = -6x 2x^2 + 6x - 5 = 0 x = (-6 ± √(36 - 4(2)(-5))/4 = (-6 ± √76)/4 = (-6 ± 2√19)/4 = (-3 ± √19)/2
*March 24, 2014*

**Implicity**

1 + 4x dy/dx + 4y (1) = 2y dy/dx 1 + 4y = 2y dy/dx - 4x dy/dx dy/dx(2y - 4x) = 1 + 4y dy/dx = (1+4y)/(2y-4x)
*March 24, 2014*

**Calculus A**

I will assume you meant: h(x) = x^2 + 5x + 4/(x-1) h ' (x) = 2x + 5 - 4/(x-1)^2 = 0 for max/min 2x + 5 = 4/(x-1)^2 (2x+5)(x^2 - 2x + 1) = 4 2x^3 - 4x^2 + 2x + 5x^2 - 10x + 5 = 4 2x^3 + x^2 - 8x + 1 = 0 hard to solve, Wolfram has this http://www.wolframalpha.com/input/?i=2x...
*March 24, 2014*

**math**

after 1st round 7 people receive email after 2nd round 7^2 or 49 receive email after 3rd round 6^3 or 343 receive email after 4th round 7^4 or 2401 receive email after 5th round ...........16807 receive email number receiving email in 5th round = 7^5
*March 24, 2014*

**math**

correct, so .....
*March 24, 2014*

**math**

what is √(300^2 + 50^2 ) ?
*March 24, 2014*

**Maths**

in groups of 4 with 2 left over: 6 10 14 .... 94 98 102 106 110 114 in groups of 5 with 1 left over : 6 11 16 21 .....96 101 106 111 116 .... looks like 106 or 4a + 2 = 5b + 1 4a = 5b - 1 a = (5b-1)/4 but 5b+1 > 100 5b > 99 b > 99/5 or 20, 21, ... let b = 21, then a= ...
*March 24, 2014*

**Algebra 1 Answer Evaluation**

check by expanding your answer, you will see that the first one is wrong you probably meant a^3 - 5a^2 + 2a -10 , says by grouping, so do that ... = a^2(a-5) + 2(a-5) = (a-5)(a^2 + 2)
*March 24, 2014*

**Algebra**

17*w*(2w+4) = 2720 2w^2 + 4w = 160 w^2 + 2w + 1 = 80+1 , I completed the square (w+1)^2 = 81 w+1 = ± √81 w = -1 ± 9 = 8 or some negatiave, which I will reject the width = 8 inches
*March 24, 2014*

**Math**

general equation of a conic: Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 we can eliminate the xy term by finding the angle of rotation Ø , so that tan (2Ø) = B/(A-C) and replacing the x and y with a new X and Y, so that x = XcosØ - YsinØ and y = XsinØ...
*March 24, 2014*

**Algebra**

If x=-4 and x = -1 are zeros to one or more of the given functions, then dividing them by both x+1 and x+4 should yield a remainder of zero. I divided x+1 into each of the given functions (I used synthetic division), each yielded a remainder. So x+1 did not divide into any of ...
*March 24, 2014*

**good catch , Calcules**

yup, looked over my work and found an error in my SA substitution. SA = 2(4xy) +2(x)(4x) + 2(xy) .... = 10x(231/x^2) + 8x^2 ---->10x(231/(4x^2)) + 8x^2 to produce your answers
*March 23, 2014*

**Calcules**

let the height be x then the width is 4x , (the height is 1/4 of the width, this way I have no fractions ) let the length be y volume = (x)(4x)(y) = 4x^2 y 4x^2 y = 231 y = 231/(4x^2) SA = 2(4xy) +2(x)(4x) + 2(xy) = 8xy + 8x^2 + 2xy = 10xy+8x^2 = 10x(231/x^2) + 8x^2 = 2310/x...
*March 23, 2014*

**MATH HELP!!**

from the 2nd: 2c + 6d = -34 c + 3d = -17 c = -3d-17 plug into the 1st: 3(-3d-17) - 7d = -3 -9d - 51 - 7d = -3 -16d = 48 d = -3 then c = -3(-3) - 17 = -8 c = -8 , d = -3
*March 23, 2014*

**Algebra II**

double the 2nd c - 6d = 16 add to the first 3c = 30 c = 10 back into the 1st 20 + 6d = 14 6d = -6 d = -1 c = 10 , d = -1
*March 23, 2014*

**algebra 2**

what is 3500(1.025) ?
*March 23, 2014*

**trig**

sin(anything) lies between -1 and +1 so -18sin(71π t) lies between -18 and +18 then p lies between 83-18 and 83+18 or between 65 and 101 period of your function = 2π/(71π) = 2/71 min or appr 1.69 seconds 1.69 seconds = 1 beat 1 second = 1/1.69 beats 60 seconds...
*March 23, 2014*

**maths**

distance along flight path = (3/4)(220) = 165 km measured horizontally: cos 25° = x/16 x = 165cos28 = 49.54 km
*March 23, 2014*

**Math**

Just noticed that Steve answered the same question when you reposted it just a few entries above this Please avoid reposting the same question, especially when it still shows near the top of the list of questions like it did here. It avoids unnecessary duplication of solutions.
*March 23, 2014*

**Math**

vector ab = (-3,4,1) vector dc = (3, -4, -1) = vector cd since their magnitude is the same, and they simply have opposite direction they must be equal and parallel So the figure is a parallogram vector cb = (0,-2,6) area = cross product of ab and cb = (-3,4,1) x (0,-2,6) = (26...
*March 23, 2014*

**Math**

loan at 2.8% --- $ x loan at 4.5 % ---- $ 31000-x solve for x .... .028x + .045(31000-x = 1024.40 times 1000 28x + 45(31000-x) = 1024400 etc
*March 22, 2014*

**Algebra**

Just noticed a typo (sticking 3 key) <taking the first 3 I got: a = 5.5 , b=-12.5 , c = 12> should say: taking the first 3 I got: a = 53.5 , b=-12.5 , c = 12 btw , I did not show how I solved those 3 equations in 3 unknowns, I used a webpage for that http://www.1728.org/...
*March 22, 2014*

**Algebra**

I did the usual analysis and found the first differences to be 145, 250, 358, and 465 and the second differences to be 105, 108, and 107 which appear to be relatively constant at appr 106, so I suspect a quadratic. let N = ad^2 + bd + c, where d is the number of days, and N is...
*March 22, 2014*

**Math (help)**

So the punch contained 1 gal of fruit juice and 1 gal of ginger ale, for a total of 2 gallons percentage of fruitjuice = 1/2 * 100% = 50% I have no clue how they get 25%, did you check the wording of the problem?
*March 22, 2014*

**Math**

66 2/3 of 39 = (200/3)(39) = 7800/3 = 2600
*March 22, 2014*

**Math**

If you have consecutive values of x, like in both your cases, in general if the first differences in the y's are constant, you have a linear function if the 2nd differences in the y's are constant, you have a quadratic function, (as your case above) if the 3rd ...
*March 22, 2014*

**Math**

I took first differences and got 2.8 , 8.4 , 14, and 19.6 second differences yielded: 5.6 , 5.6 , 5.6 which tells me that the relationship is a quadratic function. so let y = ax^2 + bx + c, giving us 0 = c 2.8 = a + b + c 11.2 = 4a + 2b + c we know c = 0 so if we double the ...
*March 22, 2014*

**math**

sinhx = (e^x - e^-x)/2 and coshx = (e^x + e^-x)/ , by definition. then: 5coshx + 3sinhx = 4 5(e^x + e^-x)/2 + 3(e^x - e^-x)/2 = 4 5e^x + 5e^-x + 3e^x - 3e^-x = 8 8e^x + 2e^-x = 8 times e^x 8 (e^x)^2 + 2 = 8e^x a quadratic, let a = e^x 8a^2 - 8a + 2 = 0 4a^2 - 4a + 1 = 0 (2a - ...
*March 22, 2014*

**maths**

The correct answer to your question is: It is a quadratic equation. If you want the solution ... it factors: (3x-1)(3x + 2) = 0 x = 1/3 or x = -2/3
*March 22, 2014*

**precal**

from sin 2x = 1/2 2x = π/6 or 2x = π-π/6 = 5π/6 x = π/12 or 5π/12 but the period of sin 2x is π so we get 2 more solutions: x = π/12 + π = 13π/12 or x = 5π/12 + π = 17π/12 in [ 0 , 2π] x = π/12 , 5π...
*March 21, 2014*

**Math - PreCalc (12th Grade)**

First of all , I am sure you meant: s(t) = 2t^2 + 3t s(2) = 2(4) + 3(2) = 14 s(4) = 2(16) + 3(4) = 44 total distance = 44-14 = 30 m total time = 4-2 seconds = 2 seconds average velocity = total distance / total time = 30 m/2 seconds = 15 m/s
*March 21, 2014*

**Math - PreCalc (12th Grade)**

very similar to http://www.jiskha.com/display.cgi?id=1395410253
*March 21, 2014*

**Math - PreCalc (12th Grade)**

Use you "sense" of numbers to see what happens to the fractions as n gets larger. (I think your last term should read 15/(3n^2) or else it becomes large as n gets large) e.g. look at 5/n suppose n = 100,000, then 5/n = .00005 , which is close to zero suppose n = 1,...
*March 21, 2014*

**Math and Music**

Perhaps you will find it fascinating to see the relationshipe between music and the Fibonacci Numbers and the Golden Ratio ( google Fibonacci numbers to see thousands of webpages, here is probably one of the best: http://www.maths.surrey.ac.uk/hosted-sites/R.Knott/Fibonacci/...
*March 21, 2014*

**arithmetic**

interest = 2000(1.0155)^20 - 2000 = 720.37 or "appr" $ 720
*March 21, 2014*

**Math - PreCalc (12th Grade)**

spread = 5-2 = 3 if cut into n pieces, each base = 3/n endpoint of 1st rectangle = 2 + 3/n endpoint of 2nd rectangle = 2 + 2(3/n) ... endpoint of kth rectangle = 2 + k(3/n) = 2 + 3k/n f(2+3k/n) = 2(2 + 3k/n) + 1 = 5 +6k/2 I see you have two other questions above that follow ...
*March 21, 2014*

**MATHS**

Steve's answer and mine seem to contradict each other, but we defined x differently. Steve defined x as his usual time, so the answer of 7.5 is correct for his usual time I defined x to be the usual speed, and got x = 2/15 so to go 1 km would take 1/(2/15) = 15/2 = 7.5 , ...
*March 20, 2014*

**MATHS**

usual speed --- x km/h time at usual speed to go 1 km = 1/x hrs time at 3/4 his normal speed = 1/(3x/4) = 4/(3x) 4/(3x) - 1/x = 2.5 times 3x 4 - 3 = 7.5x 7.5x = 1 x = 1/7.5 = 2/15 km/h
*March 20, 2014*

**Trigonometry**

r^2= 7^2 + (-3)^2 = 58 r = √58 since (7,-3) is in IV, cosØ = 3/√58 secØ = √58/3 cotØ = -7/3
*March 20, 2014*

**CORE MATHS**

Unless the x term had a coeffecient of zero, then of course you wouldn't count it, so 5a + 10b = 0 ---> a = -2b and 45/2 a^2 + 45b^2 = 90 (45/2)(4b^2 + 45b^2 = 90 90b^2 + 45b^2 = 90 135b^2 = 90 b^2 = 90/135 = 2/3 b = ±V2/√3 if b = +√2/√2 then a...
*March 20, 2014*

**CORE MATHS**

(1+ax/2)^10 + (1+bx)^10 = (1 + 10(ax/2) + (10)(9)/2 (ax/2)^2 + ... ) + (1 + 10bx + (10)(9)/2 (bx)^2 + ...) = 2 + (5ax + 10bx) + (45/4) a^2 x^2 + 45b x^2 + .. = 2 + (5a+10b)x + (45/2 a^2 + 45b^2)x^2 + ... first term matches your given, but the 2nd only contains first degree x...
*March 20, 2014*

**math**

roughly plot the points to see that you have a rectangle of base = 30 height = 2 area = 2x30 = 60 square units
*March 19, 2014*

**math**

term 11 = a+10d = 8+10d term 7 = a + 6d = 8+6d (8+10d)/(8+6d) = 5/8 64 + 80d = 40 + 30d 50d = -24 d = -24/50 = -.48 check: term 11 = 8 + 10(-.48) = 3.2 term 7 = 8+6(-.48) = 5.12 5.12 : 3.2 = 512 :320 = 8 : 5
*March 19, 2014*

**Physics question - I NEED HELP PLEASE**

need rules of physics here. volume of water if trough is full = (1/2)(3)(5)(8) = 60 cubic metres from here on it is physics
*March 19, 2014*

**math**

boys --- 4x girls ---- 5x 4x+5x = 54 take over....
*March 19, 2014*

**Math**

distance at 15 km/h --- x distance at 18 km/h ---- 136-x x/15 + (136-x)/18 = 8 multimply each term by 90 6x + 5(136-x) = 720 6x + 680 - 5x = 720 x = 40 distance at 15 km/h is 40 km distance at 18 km/h is 136-40 or 96 km check: 40/15 = 2 2/3 hrs 96/18 = 5 1/3 hrs , for a total ...
*March 19, 2014*

**math**

(1/8) of what number is 3 ?
*March 18, 2014*

**derivatives**

yup! sloppiness on my part
*March 18, 2014*

**derivatives**

I assume that you want the derivative, since you titles your post that way. if y = x^2cosx-2xsinx-2cosx dy/dx = (x^2)(-sinx) + 2x cosx - 2x(-cosx) - 2sinx + 2sinx = -x^2( sinx) + 4x( cosx) etc if needed
*March 18, 2014*

**Not so fast .....**

Since each flower needs 1 square foot, the flowers planted along the circumference will not have a complete square foot. To illustrate, take a grid paper, and draw a circle with radius 7. we will need x^2 + y^2 = 49 you only have to look at 1/4 of the circle and look at the ...
*March 18, 2014*

**Calculus Help**

y = (e^-x) (cosx)^2 (x^2 + x + 1) take ln of both sides ln y = ln e^-x + ln (cosx)^2 + ln(x^2 + x + 1) = -x + 2 ln(cosx) + ln(x^2 + x + 1) now differentiate y' / y = -1 + 2(-sinx/cosx) + (2x+1)/(x^2 + x + 1) = -1 - 2tanx + (2x+1)/(x^2 + x + 1) y' = y(-1 - 2tanx + (2x+1...
*March 18, 2014*

**Math**

for any quadratic function f(x) = ax^2 + bx + c the x of the vertex is -b/(2a) sub that x value into the function to get the y of the vertex, so n(x) = -.3x^2 + 9x + 15 x of vertex is -9/(2(-.3)) = 15 n(15 = -.3(225) + 9(15) + 15 = 82.5 ticket sales will peak on day 15 and ...
*March 18, 2014*

**math**

TC = 5/9 (TF – 32) TF = 9/5 TC + 32 , converts between TF and TC TF is temperature in archaic Fahrenheit, TC is temperature in Celsius I + PRT, interest = principal x rate x time for simple interest D = R x T , distance = rate x time
*March 18, 2014*

**Math**

yes , the x-intercepts are 0 and 4, respectively confused about your second reply, the vertices are indeed (0,0) and (0,4) <<I mean 0 for -2x^2. Sorry about the 4, I didn't mean to put that. >> , don't even know what that is supposed to say. see, http://www...
*March 18, 2014*

**Math**

You talk about equations, but show no equation. You must have meant the equations to be y = -2x^2 and y = -2x^2 + 4 You are asking for the axes of symmetry but instead state the vertices. You were correct that the vertices are (0,0) and (0,4) respectively. so the axes of ...
*March 18, 2014*

**Math**

Did you not notice that for every increase of 20 in the x's there is a decrease of 20 in the y's so the slope is (45-65)/(30-10) = -1 so y = -x + b using x=10, y = 65 65 = -10 + b b = 75 y = -x + 75
*March 18, 2014*

**trigonometry**

the formula you want is cos a + cos b= 2cos((a+b)/2) * cos((a-b)/2) so cos 5w + cos 2W = 2cos(7w/2) * cos(3W/2)
*March 18, 2014*

**Algebra**

I did this one last year http://www.jiskha.com/display.cgi?id=1362104847
*March 18, 2014*

**algebra 1**

first even : x 2nd even : x+2 now do it like the others
*March 17, 2014*

**PreCalc**

Andy, I have done quite a few for you now. Give this one a try, let me know what you get.
*March 17, 2014*

**uninhibited growth**

done, look back to your earlier post of this
*March 17, 2014*

**algebra 1**

done , look back
*March 17, 2014*

**interest**

we don't really need the amount at first rate: 2 = 1 e^(.05t) ln2 = .05t t = 13.86 ---> the doubling time at 2nd rate: 2 = 1 e^(.1t) you finish it.
*March 17, 2014*

**algebra 1**

1st number ---> x 2nd number -- > x+1 3rd number --> x+2 x+x+1+x+2 = -204 3x = -207 x = -69 largest is -67 or let the 3 numbers be (x-1) , x , (x+1) x-1 + x + x+1 = -204 3x = -204 x = -68 largest number is -68+1 = -67 notice that in my second solution, the equation ...
*March 17, 2014*

**algebra 1**

what does (2/9)x = 24 sound like to you?
*March 17, 2014*

**algebra 1**

looks like (3/8)b = 14
*March 17, 2014*

**Math**

The ones digit is 5 less than 10. ---> xx5 The tens digit is 2 more than the ones digit -- x75 it must be less than 200 so it is either 175 or 75
*March 17, 2014*

**Precalculus**

I have now answered several question for you of this type. This is the easiest of the bunch Your turn ! let me know what you got
*March 17, 2014*

**PreCalculus**

amount = 100 (1/2)^(t/5730) b) 59 = 100 (.5)^(t/5730) .59 = .5^(t/5730) ln .59 = (t/5730) ln (.5) t/5730 = ln .59/ln .5 = .76121314 t = 4361.75 yrs
*March 17, 2014*

**Uninhibited Growth**

time from 1992 to 2010 = 18 years Denmark: pop = 5.2 e(18(.001)) = appr 5.29 million Chad: pop = 5.2 e(18(.025)) = 8.2 million when is 10 = 5.2 e^(.025t) 1.923077 = e^ .025t .025t = ln 1.923077 t = 26.16 years or in appr 26 years or in 2018 (in 2010 it was 12.7 million)
*March 17, 2014*

**Precalculus**

let t=0 correspond with the year 1850 then 1900 ---> t = 50 then 1950 ---> t = 100 population = a( e^(kt) ) , where a is the initial population and t is the number of years since 1850 23,191,876 = a e^0 a = 23,191,876 then: 62,947,714 = 23,181,876 e^(50k) 2.715384812 = e...
*March 17, 2014*

**math**

what is 123(81) - 492(9) + 813 ?
*March 17, 2014*

**AP Calc**

let's eliminate the parameter t from x = e^t lnx = t then y = (lnx)^2 - 3 to be concave up, the second derivative must be positive y' = 2(lnx)(1/x) y'' = 2lnx (-1/x^2) + (1/x)(1/x) = (-2lnx + 1)/x^2 x^2 is always positive so -2lnx + 1 > 0 lnx < -1/2 ----&...
*March 17, 2014*

**AP Calc**

cos y = x - y -sin y dy/dx = 1 - dy/dx dy/dx - siny dy/dx = 1 dy/dx(1 - siny) = 1 dy/dx = 1/(1 - siny) to have a vertical tangent, the slope of that tangent must be undefined, that is, 1 - siny = 0 sin y = 1 y = π/2 or y = -3π/2 or 5π/2 if y = π/2 , then ...
*March 17, 2014*

**College Algebra**

by intuition, it must be 8 oz or the amount of salt must stay the same, so .02(16) = .04(16-x) .32 = .64 - .04x .04x = -.32 x = 8
*March 17, 2014*

**Trigg**

y=1000 sin (2t) +400 sin(anything) lies between -1 and +1 so the smallest value of sin(2t) is -1 so the smallest value of y = 1000(-1) + 400 = -600 But, it would make not make any sense to have a negative population, so my answer would be zero
*March 17, 2014*

**Algerbra**

I will assume I am looking at two different ones 1. -1< 3+2x<11 2. 1 – x >-3 or 5x-1>19 #1. -1< 3+2x<11 subtract 3 -4 ≤ 2x < 8 divide by 2 -2 < x < 4 all real numbers between -2 and 4 #2 1 – x >-3 or 5x-1>19 -x > -4 or 5x >...
*March 17, 2014*

**math**

The use of this page is more efficient and more accurate than using a standard normal distribution table, http://davidmlane.com/hyperstat/z_table.html for the prob(between 170 and 180) is gives .4772 for the prob( > 178) it gives .0548 multiply each of these by the 80 ...
*March 17, 2014*

**French school**

This person has listed the number of school days of several countries http://norberthaupt.com/2012/04/20/school-days-around-the-world/ Not all countries are listed of course, e.g. he did not list my Canada, but I know that in Ontario the number of days is 195 on average.
*March 17, 2014*

**Math 134**

Don't try to "create" fractions in this format, the spacing comes out all wrong. did you mean: 2x/(x+3) + 9/(x-3) - 36/(x^2 - 9) ?? if so, notice that x^2-9 = (x+3)(x-3) , so your LCD is (x+3)(x-3) give it a try
*March 16, 2014*

**Math 134**

my goodness! I answered this same question for you earlier. All you have to do here is change the numbers. http://www.jiskha.com/display.cgi?id=1395018684
*March 16, 2014*

**Alegbra**

if those negatives are supposed to be exponents, write them this way: 6.3 x 10^-7 3.25 x 10^-12 both expressions are in scientific notation
*March 16, 2014*

**Alegbra**

I suspect a typo
*March 16, 2014*

**math**

ummh, that would be (0,0) You should know the properties of this , the simplest form of the equation of a circle.
*March 16, 2014*

**Math 117**

done, check back on your previous post of this
*March 16, 2014*

**Math 117**

I interpret (fg)(x) as (-6x-1)(4x^2) = -24x^3 - 4x^2
*March 16, 2014*

**Math 117**

I bet you mean: f(x) = (x+10)^2 new equation: g(x) = (x+10 - 12)^2 = (x-2)^2
*March 16, 2014*

**math**

radius of each bubble = .005 m or (1/2) cm volume of each bubble = (4/3)π(1/2)^3 cm^3 so 1 million of them = 1000000(4/3)π(1/2)^3 = appr 523598.78 cm^3 = appr .5236 m^3 a bit over 1/2 cubic metre
*March 16, 2014*

**trig**

2tanA+6=tanA+3 tanA = -3 so A must be in II or IV using tanx = +3 x = 71.565° so A = 180-71.564 = appr 108.4 or A = 360 - 71.565 = appr 288.4°
*March 16, 2014*

**Math 134**

rate = 4760/34000 = .14 so .14(36000) = $ 5040
*March 16, 2014*

**Math**

Make the rectangle sit on the diameter. Let its base be 2x and its height be y then x^2 + y^2 = 27^2 y = √(729 - x^2) area = 2xy area^2 = 4x^2y^2 = 4x^2(729-x^2) = 2916x^2 - 4x^4 d(area^2)/dx = 5832x - 16x^3 = 0 for a max of area (if area is the largest of all areas, ...
*March 16, 2014*

**Algebra**

A variety of 9 different questions with no apparent effort shown by you, indicates that you just want us to do this assignment for you. Tell me what answers you obtained, and where you are having difficulty. Are you telling me that you can't do #2 ?
*March 16, 2014*

**Math**

Just realized that I answered this same question back in 2011 http://www.jiskha.com/display.cgi?id=1306326095
*March 16, 2014*

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