Monday

March 30, 2015

March 30, 2015

Total # Posts: 29,327

**Math**

counting the first bounce at up and down ... we have 144 + 144(2/3) + 144(2/3)^2 + ... which is an infinite geometric series where a = 144 , r = 2/3 sum(all terms) = a/(1-r) = 144/(1-2/3) = 144/(1/3) = 432 cm
*November 22, 2014*

**Maths**

then (3x+10)/(7x) = 6:7 42x = 21x + 70 21x=70 x = 70/21 = 10/3 so the number of reds originally was 3(10/3) = 10 the number of blues originally was 7(10/3) = 70/3 ????? how can we have partial balls ? I think there is something very wrong with your question. notice that "...
*November 22, 2014*

**Maths**

original red --- 3x original blue --- 7x number of reds added -- a number of blues added -- 10-a (3x+a)/(7x + 10-a) = 6/7 42x + 60 - 6a = 21x + 7a 21x - 13a = -60 I think you have something missing in your problem, maybe a typo We have to know how the 10 balls are distributed ...
*November 22, 2014*

**Math Check please**

your equation of c = 36/d^2 is correct so your constant of proportionality is 36 (your k value) now just plug in d = 5 c = 36/25 or 1.44
*November 21, 2014*

**Math**

the diagram looks rather routine draw the smaller building and mark is as 12 m high draw the other building a bit taller . draw a horizontal from the smaller to the taller, label the difference in height as x draw in your cable, Don't you have a right-angled triangle with ...
*November 21, 2014*

**Math**

(4^x)-(2^x)=56 (2^2)^x - 2^x - 56 = 0 (2^x)^2 - 2^x - 56 = 0 let 2^x = t , we get t^2 - t - 56 = 0 (t-8)(t+7) = 0 t = 8 or t = -7 if t = -7 2^x = -7 , no such x exists or if t = 8 2^x = 8 -----> x = 3
*November 21, 2014*

**Math**

3^(2c+1)=28*(3^c)-9 3^(2c)*3^1 = 28*3^c - 9 3(3^c)^2 - 28(3^c) + 9 = 0 let 3^c = x 3x^2 - 28x + 9 = 0 (3x - 1)(x - 9) = 0 x = 1/3 or x = 9 if x = 1/3 3^c= 1/3 = 3^-1 -----> c = -1 if x = 9 3^c = 9 = 3^2 ----> c = 2
*November 21, 2014*

**Math**

a) is correct b) since the S and L are defined variables, taken the inverse in the usual way changes their definitions. We could just follow the usual steps ... if S = 2√(5L) , the inverse is obtained by interchanging the variables, so inverse is L = 2√(5S) we ...
*November 21, 2014*

**Math Question**

-1500/360 = -4 with a remainder of -60° So we would have 4 clockwise rotations with and angle of 60 into quadrant IV
*November 21, 2014*

**Math**

f(f(x)) = f(6/(5+x) ) = 6/(5 + 6/(5+x) ) = 6/( (25+5x+6)/(5+x) ) = (30 + 6x)/(31 + 5x) = g(x) let y = (30+6x)/(31+5x) inverse is : x = (30+6y)/(31+5y) 31x + 5xy = 30 + 6y 5xy - 6y = 30 - 31x y(5x - 6) = 30-31x y = (30-31x)/(5x-6) = g^-1 (x)
*November 21, 2014*

**Math**

81^x = 64 log 81^x = log 64 x log81 = log64 x = log64/log81 27^(log64/log81 + 1) = 610.940...
*November 21, 2014*

**typo - Algebra**

forgot the zero in the first line , should read: as x is hugely negative, 2*51^x ----> 0
*November 21, 2014*

**Algebra**

as x is hugely negative, 2*51^x ----> so f(x) ----> 3 - 0 or 3 as x becomes hugely positive -2*51^x --->- ∞ do the range is y < 3 I will let you use whatever notation you have learned
*November 21, 2014*

**Math**

P(1.04)^10 = 5000 solve for P
*November 21, 2014*

**Math**

Rachel, Rachel ! Since both Damon and I went farther than the question asked for and also found the value of a .... all you needed is r = 1/2 (the value of a indeed has √2 in it, but your teacher was not referring to a but rather to r . Note we both had that √2 in ...
*November 21, 2014*

**Math**

ahh, so we have two ordered pairs (2,1) and (32, 4) that satisfy our equation ----> 1 = a(2)^r ----> 4 = a(32^r a(32)^r = a(2)5r so a(2)5r = 4 and a(2)^r = 1 divide them 2^(5r-r) = 4 2^4r = 2^2 then 4r = 2 r = 1/2 back into the first: a(2)^(1/2) = 1 a√2 = 1 a = 1...
*November 21, 2014*

**Math**

where does r come in ? did you mean , find a ?
*November 21, 2014*

**Algebra Help please!**

amount owing at 12% compounded annually in 4 years = 6000(1.12)^4 = 9441.12 amount owing at 12% per annum compounded quarterly in 4 years = 6000(1.03)^16 = 9628.24 Now subtract them as Henry told you to do.
*November 21, 2014*

**math please help!!!!!**

Since you are telling me that 4i = k then f(x)=x^3+(12-4i)x^2+(32-48i)x-128i =x^3 + (12 - k)x^2 + (32 - 12k) - 32k and since k is a zero, then (x - k) is a factor by synthetic division: f(x)=x^3+(12-4i)x^2+(32-48i)x-128i = (x-k)(x^2 + 12x + 32) = (x - 4i)(x^2 + 12x + 32)
*November 21, 2014*

**Algebra 2**

I will assume that you have (√5 + i)/(√5 - i) those brackets are absolutely essential. I will also assume that you want this rationalized. (√5 + i)/(√5 - i) = (√5 + i)/(√5 - i) * (√5+i)/(√5 + 1) , I am merely multiplying by 1, ...
*November 21, 2014*

**Math Help!!!**

If you meant √-75 , then you can't have a real number thus to ask for the nearest integer would be silly So you must have meant -√75 = -8.66025... = -9 to the nearest integer (look at the number on a number line)
*November 21, 2014*

**Math**

Brackets are essential here .... h(x) = (3x+2)/(7x-6) or y = (3x+2)/(7x-6) step 1 of finding the inverse is to interchange the x's and y's x = (3y + 2)/(7y - 6) 7xy - 6x = 3y + 2 step 2 : solve this for y 7xy - 3y = 6x + 2 y(7x - 3) = 6x + 2 y = (6x + 2)/(7x - 3) , ...
*November 21, 2014*

**Algebra 2**

from the type of problem that you posted, you surely MUST know how to solve quadratic equations. Steve took you as far as 5x^2 - 16x + 6 = 0 and made the same assumption I made. I suggest using the quadratic formula. (you will get two irrational answers)
*November 21, 2014*

**MATH**

proceed this way: f(g(x)) = f(2x^2 - 1) = 2/(2x^2 - 1) test it for some number e.g. let x = 3 g(3) = 18-1 = 17 f(g(3)) = f(17) = 2/17 in my answer: 2/(2x^2 - 1) = 2/17 This does not 'prove' that my answer is correct, but there is high probability that it is. Had my ...
*November 21, 2014*

**math**

old rate --- $x new rate --- $ x+2 wage per week at old rate = $ 32x wage per week at new rate with more hours = 40(x+2) 40(x+2) - 32x = 200 easy to solve
*November 20, 2014*

**Math Help**

Think about it .... if perimeter of little square is 16, each side is 4 for the larger, each side is multiplied by 7, or , each side is 28 so perimeter of larger is .....
*November 20, 2014*

**algebra. help!**

How can I check your work if you did not supply any of your choices
*November 20, 2014*

**math**

your solution is correct to check, you must go back to the original equation LS = log4 (19-3) = log 4 (16) = 2 -----> what must be exponent on 4 to get 16 ? = RS so x = 19
*November 20, 2014*

**Math**

Let his original number of pens be x then his original number of pencils is 30 - x So for every pen he gets 2 pencils so x pens will yield him 2x pencils but he already had 30-x pencils, so 2x + 30-x = 48 x = 18 So, originally he had 18 pens and 12 pencils check: 12+18 = 30 , ...
*November 20, 2014*

**math**

of course not distribute ... -36 - 6x - 6x - x^2 = .... add like terms
*November 19, 2014*

**math!!!!!!**

just distribute ... x(x+y+2) = x^2 + xy + 2x
*November 19, 2014*

**Algebra**

I will assume you mean (1/25)^(x+2) = 125^-x or else we got ourselves one doosey of a problem (5^-2)^(x+2) = (5^3)^-x 5^(-2x-4) = 5^(-3x) then -2x-4 = -3x x = 4
*November 19, 2014*

**Algebra**

m-7 < 6 add 7 to both sides, (just like you would for an equation) m < 13 Do the other two the same way
*November 19, 2014*

**math**

P(1 + .07/4)^28 = 30000 solve for P
*November 19, 2014*

**math!**

GCD(722,2413) = 19 then GCD(19,209) = 19 so GCD(722,2413,209) = 19
*November 19, 2014*

**Algebra Help! Please**

Did you not read the 3 conditions I outlined for you? Especially this one: "- if the variable drops out, and you get a true statement, there will be an infinite number of solutions " so you got 0=0, which is true, thus there will be an infinite number of solutions
*November 19, 2014*

**ALGEBRA Help Please**

1st: 2(x-3) = 2x 2x - 6 = 2x -6 = 0 -----> contradiction, thus no solution 4th: 4(x+3) + 2x = x - 8 4x + 12 + 2x = x - 8 5x = -20 x = -4 -----> One solution in general - if you get ?x = ? , there will be one solution - if the variable drops out, and you get a true ...
*November 19, 2014*

**Math**

#1, you can decide for yourself if (-5,-1) is correct by subbing in those values into both equations. You should be able to do this mentally. -- A quick mental calculation shows that your answer does not work in either equation from the 2nd: x = 2y + 10 plug that into the 1st...
*November 19, 2014*

**MATH HELP**

When testing if a number is prime, you would only try primes as divisors until you reach the last prime < √(the number) e.g. is 71 prime try: 2, 3, 5, 7 none divided exactly, so 71 is prime (did not have to go for 11 , since 11 > √71 so for 1881 ... √...
*November 19, 2014*

**maths**

Once around is one circumference. The circumference of a circle is 2πr or πd, d the diameter. So 5 times around would be ...... Plug in your values
*November 19, 2014*

**math**

I assume you meant to say, " ... travels 180 cm farther than ... " let the distance to the point of the minute hand be r cm In one hour the minute hand has gone around one rotation or 2πr in one hour the 'hour hand' has gone (1/12)(2π60)) or 10π...
*November 19, 2014*

**Maths**

Take a sheet of printer paper and try it. Doesn't the circumference of your tube equal the long side ? So.... 2πr = 20 r = 10/π
*November 19, 2014*

**Math- Combinations**

You are choosing 4 from 19 = C(19,4) = 19!/(15!4!) = 3876
*November 18, 2014*

**Math**

correct
*November 18, 2014*

**Math**

Retype in English please, and tell me what C is.
*November 18, 2014*

**AP CALC**

let the point of contact on the cosine curve be (x,y) So the perimeter of the rectangle = P = 2x + 2y = 2x + 2cos 2x dP/dx = 2 - 4sin 2x = 0 for a max/min of P 4sin 2x = 2 sin 2x = 1/2 I know sin π/6 = 1/2 so 2x = π/6 x = π/12 then y = cos π/6 = √3/2 ...
*November 18, 2014*

**algebra**

Let Jena time alone be x hrs let Cindy's time alone be 2x hrs let the two rates be 1/x and 1/(2x) combined rate = 1/x + 1/(2x) = 3/(2x) 1/(3/(2x)) = 10 2x/3 = 10 hrs = 2x = 30 or x = 15 Jena will take 15 hrs to do the house alone
*November 18, 2014*

**ap calc**

There are many variations of this same question,. Hint: let TP = x then OP^2 = x^2 + 64 OP = (x^2 + 64)^(1/2) I think you are missing the length of TR, we need that to find PR Just for arguments sake, lets say TR = 12 miles then PR = 12-x cost = 90000(x^2+64)^(1/2) + 54000(12-...
*November 18, 2014*

**ap calc**

Your graph looks like a W and I assume you want the rectangle placed inside the centre part. Let the two other vertices be (x,y) and (-x,y) So the length is 2x and the height is y Area = 2xy = 2x(x^4 - 2x^2 + 1) = 2x^5 - 4x^3 + 2x d(area)/dx = 10x^4 - 12x^2 + 2 = 0 5x^4 - 6x^2...
*November 18, 2014*

**sixth grade ratios and rates**

Here is another way of looking at Morgan's solution. Morgan found the percentage to be 25% or 1/4 of the marbes are blue. So 1/4 of Jasper's marbles must be blue , it said they have the same percentage of blue marbles. Let the total of Jasper's marbles be x then (1...
*November 17, 2014*

**Math**

f(x)= -x^2 + 2x = -1(x^2 - 2x +1 - 1 ) = -( (x-1)^2 - 1) = - (x-1)^2 + 1
*November 17, 2014*

**college, math**

If I were Sears I would sue the publisher of this textbook for associating their name with such a fraudulent practice . Anyway, according to this criminal plan .... cost after sales tax = 1656.9 "add-on interest" = 1656.90(.12)(3) = 596.484 amount to be "...
*November 17, 2014*

**algebra**

let's just plug in t = 10 T(10) = 65 + 115 e^-.42 = 140.56 = 141° to the nearest degree. b) we want 110 = 65 + 115 e^(-.042t) e^(-.042t) = (110-65)/115 = .391304... take ln of both sides -.042t = ln .391304.. t = 22.34 minutes or 22.3 minutes
*November 17, 2014*

**math**

x^2 = (-16 ± √196)/10 = (-16 ± 14)/10 x^2 = -1/5 or x^2 = -3 x = ± i/√5 or x = ± √3 i All four roots are imaginary
*November 17, 2014*

**Math**

only x= 0 so y= 0 x= 1 so y= -3 is correct, the others are not Perhaps, if you show how you are doing the calculations, I can see where you are going wrong. I will do one for you ... if x = -4 y = (-4)^2 - 4(-4) = 16 + 16 = 32
*November 17, 2014*

**Math**

So this question is essence establishes the quadratic equation formula hint: give yourself an equation such as 3x^2 + 12x + 2 = 0 and whichever step you perform on this equation, do the same thing for a parallel solution to ax^2 + bx + c = 0 Of course you know what you are ...
*November 17, 2014*

**Algebra Work Check**

correct or (x^2+4)(x^2-4) = 0 x^2 + 4 = 0 --> no real solution or x^2 - 4 = 0 (x+2)(x-2) = 0 x = ±2
*November 17, 2014*

**Pre-Calc/Trig**

let f(x) = 5x^3 - 119x^2 - 10x + 16 now try some f(x) , where x = ±1, ±2, ±4, ±8 ... hopefully to get a zero took some some, but f(8) = 0 so (x-8) will be a factor now by synthetic division , I got 15x^3-119x^2-10x+16 = (x-8)((15x^2 + x - 2) = 0 ...
*November 17, 2014*

**algebra**

speed of current --- x mph time to go 217 miles with the current = 217/(29+x) time to go 189 againts current = 189/(29-x) 217(29+x) = 189/(29-x) cross-multiply, solve for x
*November 17, 2014*

**Calculus**

everything happens starting at t=.5 a = -10 v = -10t + c when t = .5 , v = 20 20 = -10(.5) + c c = 25 v = -10t + 25 , for t ≥ .5 s = -5t^2 + 25t + k when t = .5 , the car goes goes another 20(.5) or 10 m so when t = .5, the remaining distance is 20 m 20 = -5(.5)^2 + 25(....
*November 17, 2014*

**maths**

original number --- x after epidemic --- .98x are left 14% of those leave, leaving (.86)(.98x) .86(.98x) = 2107 x = 2107/(.86(.98)) = 2500
*November 17, 2014*

**maths**

I am sure you meant A=p(1+r/n)^(nt) for yours r/n = .12/12 = .01 and nt = 12t (our unknown) so 500000(1.01)^(12t) = 1000000 1.01^(12t) = 2 take log of both sides log 1.01^(12t) = log 2 12t log1.01 = log2 12t = log2/log1.01 = 69.6607 t = 5.8 years
*November 17, 2014*

**math**

If I understand correctly there would have been 4 transactions. let the amount that each child has originally be x first transaction: 1st child -- x-9 each of remaining 9 children has x+1 2nd transaction: 1st child -- x-9 2nd child -- x+1 - 8 = x-7 each of remaining 8 children...
*November 17, 2014*

**proportion test**

new machine, defect rate is 85/820 = .1037 or 1037% draw you conclusion from that
*November 16, 2014*

**Math**

The question was to "find all possible roots" so you would try f(1), f(-1) , f(2) ...., f(±12) so you must try all of these unfortunately, none are equal to zero, so you have no rational roots.
*November 16, 2014*

**Math**

It is a 4th degree equation, so at most you could have 4 roots How can you possible get 6 of them ?
*November 16, 2014*

**math**

√(31-9x) = 5 - x square both sides 31 - 9x = 25 - 10x + x^2 x^2 - x - 6 = 0 (x-3)(x+2) = 0 x = 3 or x = -2 BUT, since we squared, we must verify ALL answers if x = 3 LS = 3 + √4 = 5 RS = 5, YEahh if x = -2 LS = -2 + √49 = -2 + 7 = 5 = RS, YEAHH x = -2 or x = 3
*November 16, 2014*

**MATH 101**

using the difference of cubes factoring x^2 - 8 = 0 (x-2)(x^2 + 2x + 4) = 0 x = 2 or x = (-2 ±√-12)/2 = (-1 ± 2√3 i )/2 = -1 ± √3 i for 3 solutions, one real, two complex
*November 16, 2014*

**MATH 101**

not enough information. is f(x) linear ? we must assume that, since you only have 2 points, namely, (3,0) and (-4,0) slope = 0/-7 = 0 so we have a horizontal line and f(x) = 0 f(x) is the x-axis
*November 16, 2014*

**math**

let's look at x^2 + 2x + 4 = 0 by completing the square, (in this case the easiest way to solve it) x^2 + 2x = -4 x^2 + 2x + 1 = -4+1 (x+1)^2 = -3 but anything squared cannot be negative, so there is no real solution consider y = x^2 + 2x + 4 this parabola never touches or...
*November 16, 2014*

**Math**

let f(x) = 3x^3 + 2x^2-1 f(1) = 3 + 2 - 1 ≠ 0 f(-1) = -3 + 2 - 1 ≠ 0 f(1/3) = 1/9 + 2/9 - 1 ≠ 0 f(-1/3) ≠ 0 So there are no "nice" roots looking at the graph, there appears to be a real solution at appr x = 0.5 and two complex roots (the graph...
*November 16, 2014*

**CAL**

y = x^3/x- x would reduce to y = x^2 - x and (1,-2/3) would NOT lie on this curve. So there is something wrong with the way you typed it Use brackets to establish the correct form Otherwise this question is bogus.
*November 16, 2014*

**CAL**

could be the way you typed your equation. The way you typed it, why not just simplify x^3/x to x^2 ? That is why I am suspicious about the way it was typed. Did you mean y = x^(3/x) - x ?
*November 16, 2014*

**Derivative**

But, to even attempt this question, you MUST know the derivatives of the basic trig functions. in this case, use the quotient rule dy/dx = ( (1+sinx)(-sinx) - cosx(cosx) )/(1+sinx)^2 = (-sinx - sin^2 x - cos^2 x)/(1+sinx)^2 = (-sinx -1)(1+sinx)^2 = -(1+sinx)/(1+sinx)^2 = -1/(1...
*November 16, 2014*

**calculus**

#1, your dy/dt is correct b) correct, to the right when v(t) > 0 but they probably want to know when that happens look at your derivative, the denominator will always be positive, since it is something squared. So the ± of your v(t) is only determined by the ...
*November 16, 2014*

**Calculus Help**

It is not a matter of "choosing" here, you must calculate it. f ' (x) = cos(7-5x)(-5) = -5cos(7-5x) f '(π) = -5cos(7-5π) = 5cos(-8.7078..) = 3.770 Did you set your calculator to radians in your DRG mode ?
*November 16, 2014*

**Pre Albergra**

Just put on my tin-foil hat and got a message of 3.4 cm How did I do ?
*November 16, 2014*

**Calculus**

let x = √5 then x^2 - 5 let y = x^2 - 5 y' = 2x Newton said: newx = x - y/y' = x - (x^2 - 5)/(2x) = (2x^2 - x^2 + 5)/2x = (x^2 + 5)/(2x) x newx 3 2.3333.... 2.333... 2.23809... 2.23809... 2.23606... could have stopped here 2.23606.. 2.236067878 2.236067978.. 2....
*November 16, 2014*

**Trig**

The primary function is ln(...) we can only take logs of positive numbers now look at the sine curve only, and note where it lies above the x-axis so the intervals would be 0 < x < 90° or 360° < x < 450° or 720° < x < 810° or ... how about...
*November 16, 2014*

**Math**

first , because of the negatiave outer exponent = 1/(16x^2)^3/4 since (ab)^x = a^x * a^x we get 1/( (16^(3/4 ) * x^(3/2) now 16^(3/4) = (16^(1/4) )^3 = 2^3 = 8 so finally = 1/(8 (√x)^3 )
*November 16, 2014*

**math**

Volume of cylinder = π r^2 h you are given r and h, plug in the values and evaluate
*November 16, 2014*

**Elementary Math**

Ricardo --- x years Miriana ---- x+4 Ten years ago: Ricardo --- x-10 Miriam --- x+4 - 10 = x-6 x-6 = 3(x-10) easy to solve ... let me know what you get
*November 16, 2014*

**Math**

One would think that after trying this for two days, you might realize that you don't have enough information. e.g. If your tank is a large rectangular tank of 10 ft by 10 ft the water level would rise more than if your "tank" had been a swimming pool.
*November 16, 2014*

**Math**

PV = 800( 1 - 1.09^-10)/.09 Wow, let me know which bank pays you 9% in 2014.
*November 16, 2014*

**Advanced Algebra (Infinite Geometric Series)**

8.690909.... =8.6 + .09 + .0009 + .000009+... = 86/10 + .09/(1-.01) = 86/10 + .09/.99 = 86/10 + 9/99 = 86/10 + 1/11 = 478/55
*November 15, 2014*

**Math**

2 / ((cos(r^2 - s^2) / (sin(r^2 - s^2)) = 2 * (sin(r^2 - s^2) / (cos(r^2 - s^2) = 2 tan (r^2 - s^2)
*November 14, 2014*

**Math Please Assist**

sin^3 x + sinx cos^2 x = cosx sinx(sin^2 x + cos^2 x) = cosx sinx (1) = cosx sinx/cosx = 1 tanx = 1 x = 45° or x = 225° but you wanted to be between 0 and 180 so x = 45°
*November 14, 2014*

**math**

since you want cos 2Ø in terms of x from x+5 = 9sinØ bringing the 5 over would make things worse ... and no, you would not distribute the 9 over the 9sinØ - 5 I would proceed this way: sinØ = ( x+5)/9 now you will have to use one of the half-angle ...
*November 14, 2014*

**Pre-Calc/Trig**

quadratic --- x^2 term makes it that linear ----- x term makes it that cubic ------ from the x^3 term the highest exponent term establishes what kind it is
*November 14, 2014*

**Algebra**

slope = (-3-1)/(1-3) = 2 so it has to be one of the last two of your choices sub in (1,3) into y = 2x+5 ---> doesn't work sub in (1,3) into y = 2x - 5 ----> Yeahhh! so y = 2x-5 that is what bob had suggested to you, that is, try the points in the equations.
*November 14, 2014*

**math**

so in effect the ship went 41 + 15 or 56 north and 23 east. so d^2 = 56^2 + 23^2 = 3665 d =√3665 = 60.5 km
*November 14, 2014*

**math probability**

since the code > 400, your choice for the first digit is 6, you can put 10 different digits in the 2nd spot, and 10 different digits in the 3rd spot number of possible codes = 6x10x10 = 600 this would include 400, which cannot be used, since it must be greater than 400 so ...
*November 14, 2014*

**Math**

to the nearest 10 13---> 10 46 ---> 50 87 ---> 90 sum = 150 if you added them up like you did to get 146 , you have the actual answer, why bother estimating ? Besides, 146 rounded to the nearest tens is 150, not 160
*November 14, 2014*

**math probability**

I don't understand the question. In your first sentence, you are saying that there are only 9 dollars in the box.
*November 14, 2014*

**Intermediate Algebra**

simple interest formula: I = PRT, lets plug in our values 85 = 6000(R)(1/12) multiply both sides by 12 1020 = 6000R divide both sides by 6000 R = 1020/6000 = .17 or 17% You had the correct answer, but you should not just piece-meal bits and pieces from the equation.
*November 14, 2014*

**Intermediate Algebra**

sloppy use of the decimal place and your solution makes absolutely no sense. if x is the amount loaned at 6% ... .06x + .14(15000-x) = 1500 .06x + 2100 - .14x = 1500 -.08x = -600 x = 600/.08 = 7500 So $ 7500 was loaned at 6% and $7500 at 14% check: .06(7500) + .14(7500) = 1500
*November 14, 2014*

**MATH**

true if both are positve, or if both are negative. depends if one is + , the other - e.g 8/5 - 9/7 = 11/35 but 15/4 - 3/2 = 9/4 , still a mixed number
*November 13, 2014*

**Geometry**

let the size of the cut-out be x by x inches length of base = 24-2x width of base = 24-2x height = x V = x(24-x)^2 = x(576 - 48x + x^2) =576x - 48x^2 + x^2 dV/dx = 576 - 96x + 3x^2 = 0 for a max of V x^2 - 32x + 192 = 0 (x - 24)(x - 8) = 0 x - 8 or x = 24, but if x = 24, we ...
*November 13, 2014*

**Probability.. HELP!**

what is 36x35x34 ? Do you know why ?
*November 13, 2014*

**Math, Please Help!**

I will assume we are not distinguishing between small and capital letters. I will do one: TENNESSEE - 9 total, 2 N's , 4 E's, 2 S's total number of ways = 9!/(2!4!2!) = 3780 Can you see what I did ? OHIO ----> 4!/(2!) = 12 try the others.
*November 13, 2014*

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