Saturday

November 29, 2014

November 29, 2014

Total # Posts: 27,979

**math**

Here is the "magic" square, where not only are your diagonals equal to a sum of 15, but so are each row and column 8 1 6 3 5 7 4 9 2
*June 13, 2014*

**UGRENT HELP, math**

They used the < sign should have used the ≤ for the ones that are equal
*June 13, 2014*

**UGRENT HELP, math**

number = 80(3)^(8/2) = 6480 C is obviously the biggest, followed by A B and D are the same none of the answers match, after you find the typo, I will let you figure it out
*June 13, 2014*

**finance**

first let the 50,000 and the 100,000 ride for the 12 years. Amount = 50000(1.05)^12 + 100000(1.10)^12 = 403,635.65 PLus our annuity of 30,000 for 12 years at 10% = 30000(1.1^12 - 1)/.1 =641,528.51 for a total of $1,045,164.17 Last part: let the rate be i 1,045,164.17 = 102,000...
*June 13, 2014*

**maths**

All four sides are equal, so each side of the rhombus is 8 cm get angle Ø , opposite the 10 cm diagonal 10^2 = 8^2 + 8^2 - 2(8)(8)cosØ cosØ = 7/32, then sinØ = 5√39/32 area = 8(8)sinØ = ... you take over
*June 13, 2014*

**MAth**

4+√(4+x^2) = x √(4+x^2) = x-4 square both sides 4+x^2 = x^2 - 8x + 16 8x = 12 x = 12/8 = 3/2 since we squared the equation, we MUST verify the answer LS = 4 + √(4 + 9/4) = 4 + √(25/4) = 4 + 5/2 = 13/2 RS = 2/3 LS ≠ RS so actually there is no ...
*June 12, 2014*

**Math**

prob(blue, then red) = (10/24)(1/23) = 5/276
*June 12, 2014*

**College Algebra**

from vertex, y = a(x+9)^2 + 8 but (9,4) lies on it, so 4 = a(18^2) + 8 324a = -4 a = -4/324 = -1/81 etc you messed up here: 4=a(18)^2+8 4=a(332) , you added 8 to 324a , you can't add unlike terms
*June 12, 2014*

**College Algebra**

from the given vertex, the equation must be y = a(x+2)^2 + 4 but (0,2) lies on it, so 2 = a(0+2)^2 + 4 2 = 4a + 4 4a=-2 a = -1/2 y = (-1/2)(x+2)^2 + 4
*June 12, 2014*

**Math please help**

let y = 3/x + 4(1-x) = 3/x + 4(1-x)^-1 dy/dx = -3/x^2 -4(1-x)^-2 (-1) = -3/x^2 + 4/(1-x)^2 = 0 for a max/min of y 4/(1-x)^2 = 3/x^2 4x^2 = 3(1-x)^2 2x = ± √3(1-x) 2x = √3 - √3x 2x + √3x = √3 x = √3/(2 + √3) = appr .4641 or 2x...
*June 12, 2014*

**algebra**

D : B = 27 : 16 = D : 64 D/64 = 27/16 D = 64(27/16) = 108
*June 12, 2014*

**Math**

$1 = 82.8/12 francs so he has 12 + 25 or $37 $37 = 37(82.8/12) francs = appr 255.3 francs Time to update that ancient texbook your school is using. France has been using the Euro since 1999
*June 12, 2014*

**Math**

2nd angle --- x 1st angle ---- 4x 3rd angle ---- x+84 x + 4x + x+84 = 180 6x=96 x = 16 1st angle = 4x = 4(16) = 64°
*June 12, 2014*

**ALgebra**

adults --- x children -- 3x solve: 975x + 525(3x) = 30600
*June 12, 2014*

**math**

In terms of cosx cos 3x = 4 cos^3 x - 3cosx , and cos 2x = 2 cos^2 x - 1 so cos 3x = cos 2x 4 cos^3 x - 3cosx - 2cos^2 x + 1 = 0 let cosx = y so we need 4y^3 - 2y^2 - 3y + 1 = 0 I tried y = 1 and sure enough that was a solution. then by synthetic division ... 4y^3 - 2y^2 - 3y...
*June 12, 2014*

**math**

i = .08 n = 40 years a) amount = 3000 ( 1.08^40 - 1)/.08 = appr $777,170.00 b) change the exponent from 40 to 30
*June 12, 2014*

**geometry**

second angle --- x first angle ------ 4x third angle ----- x+84 x + 4x + x+84 = 180 you finish it
*June 11, 2014*

**Math**

dimes--- x quarters -- x+2 nickels --- 3(x+2) = 3x + 6 10x + 25(x+2) + 5(3x+6) = 180 10x + 25x + 50 + 15x + 30 = 180 50x =100 x = 2 so 2 dimes and 4 quarters and 12 nickels check: 10(2) + 4(25) + 5(12) = 180 all is good
*June 11, 2014*

**Introductory Algebra**

Ummmh, isn't it about your school updated those old textbooks? France hasn't used the franc for years, they use the Euro.
*June 11, 2014*

**algebra**

cost of pound of copper ---- x cost of pound of tin -------- x+2 3(x + 2) + 7x = 10(3.85) 3x + 6 + 7x = 38.5 10x = 32.5 x = 3.25 copper sells for $3.25 per pound, and tin sells for $5.25 per pound
*June 11, 2014*

**Math**

I would write it as y = (8x^3)(3x-2)^(-1/2) and use the product rule dy/dx = (8x^3)(-1/2)(3x-2)^(-3/2) (3) + 24x^2 (3x-2)^(1/2) I will let you clean it up a bit
*June 11, 2014*

**Math**

yes, f(-6) = -18-5 = -23 f(4) = 12 - 5 = ........ f(8) = ........ range = { -23, ..... , .... }
*June 11, 2014*

**trig**

3secØ = 5 secØ = 5/3 then cosØ = 3/5 , since secA = 1/cosA Ø = arccos 3/5 = appr53.13° but you wanted the obtuse angle, so Ø = 360-53.13 = 306.87° , because the cosine is positive in quadrant I and IV to the nearest degree it would be...
*June 11, 2014*

**Algebra**

to get the y-intercept, let x = 0, that would leave you with y = 3 for the x-intercept, let y = 0 , that would leave you with x = 3 if the equation is of the form Ax + By = C do the same thing, usually you can do it your head e.g. 5x + 3y = 20 x-intercept is 4 y-intercept is 20/3
*June 11, 2014*

**Algebra**

of course
*June 11, 2014*

**Algebra**

treat it like two ordered pairs (1,295) and (2,272) slope = (272 - 295)/(2-1) = - 23 so equation in the form y = mx + b would be count = -23x + b , were x is the day number so using (1,295) 295 = -23(1) + b b = 318 count = -23x + 318 so on day 3 , x =3 count = -23(3) + 318 = ...
*June 11, 2014*

**data management**

a) z-score for 6 days = (6-7)/2 = -1/2 = -.5 b) go to your table at z = -.5 and find the corresponding probability , multiply by 8000 ( I got 2468 c) repeat the above for 4 days I found this website a great replacement for tables http://davidmlane.com/hyperstat/z_table.html
*June 11, 2014*

**math (please check answer)**

prob = (6/20)(2/19) = 3/95 you were right
*June 11, 2014*

**algebra/what am I doing wrong Please help**

You should have definitions for dependent, independent, and incosistent. if there is a unique solution , the system would be independent. since the two lines have different slopes, they MUST intersect in a point, thus independent Wolfram is great ... http://www.wolframalpha....
*June 11, 2014*

**Please help me with this question.!!!!!!**

I must admit that I had no idea what a "box and whisker" plot is, even though I taught math for 35 years, so I looked it up and found this video of the very useful Khan Academy by Sal Khan https://www.khanacademy.org/math/probability/descriptive-statistics/Box-and-...
*June 10, 2014*

**Algebra**

prob on base = .45 prob not on base = .55 prob (on base 5 of 7 times) =C(7,5) (.45^5)(.55^2) = appr .117
*June 10, 2014*

**Math**

-4x-8>4 -4x > 12 divide both sides by -4 x < -3 You add and subtract jus like you would for an equation, but when you divide by a negative, like I did in the last step, you MUST reverse the inequality sign.
*June 10, 2014*

**math (cant figure it out)**

Prob(vowed, then Q) = (3/6)(1/6) = 3/36 = 1/12 How did you possible get 1/10 ?
*June 10, 2014*

**math *check***

Strike 2 prob (red from 1st then red from 2nd) = (12/20)(8/13) = 24/65
*June 10, 2014*

**algebra**

what is 4^3 - 5(4^2) + 4 ?
*June 10, 2014*

**math**

1/8 = .125 or 12.5% so to double we would solve 1(1.125)^n = 2 log both sides log (1.125^n = log2 n log 1.125 = log2 n = log2/log 1.125 = appr 5.885 years for tripling, solve 1.125^n = 3 ------> you should get appr 9.33
*June 10, 2014*

**math *check***

prob(green) = 9/20 prob(not green) = 11/20 odds in favour of green = (9/20) : (11/20) = 9: 11 you are correct.
*June 10, 2014*

**math (cant figure it out)**

Valid point by Writeacher, if they they are numbered from 0-10 , there would be 11 sections. Clarify before I answer it.
*June 10, 2014*

**math**

strange wording .... " Finding three geometrically numbers" I assume you have 3 numbers in a geometric sequence. "30 units exceeds the sum of the other two" ...... which "other two" , the first two, the last two , or the middle two ? the three ...
*June 10, 2014*

**Math**

Use Cartesian geometry let the first be at (1,120) and the last one at (7,12) slope = (120-12)/(1-7) = -18 so for each increase in x, the height drops 18 cm so you want two decreases, height of third = 120-2(18) = 84 or find the equation: y = -18x + b at (7,12) 12 = -18(7) + b...
*June 10, 2014*

**math -interest**

i = .14/12 = .0116666... n = 12 400 = payment (1 - 1.011666...^-12)/.01166.. I get payment = 35.91
*June 10, 2014*

**Algebra 1**

y = x^2 - 4x+ 4 = (x - 2)^2 for x-intercept, let y = 0 (x-2)^2 = 0 x-2 = 0 x = 2 we have a double root at x = 2 , ( x=2 or x=2) see Wolfram: http://www.wolframalpha.com/input/?i=plot+y+%3D+x%5E2+-+4x+%2B+4 Usually , I would put my money on Wolfram.
*June 10, 2014*

**math**

If f(x) will "vanish" when x = 1 and x = -2 (x-1) and (x+2) must be factors assume we have f(x) = a(x+b)(x-1)(x+2) given: f(-1) = 4 ---> 4 = a(-1+b)(-2)(1) -2a(-1+b) = 4 2a - 2ab = 4 a - ab = 2 f(2) = 28 ---> 28 = a(2+b)(1)(4) 4a(2+b) = 28 8a + 4ab = 28 2a + ab...
*June 10, 2014*

**math**

I see about 9 questions that you posted all dealing with the factor and remainder theorems. You have shown no effort on your part or let us know where you difficulties are. They all basically follow these two concepts : if for some f(x) , x-a is a factor, then f(a) = 0 if for ...
*June 10, 2014*

**math**

p(4) = 64k + 48 - 3 = 64k + 45 Q(4) = 128 - 20 + k = k + 108 by the remainder theorem , each of these are the remainders when divided by x-4 But they are equal ... 64k + 45 = k + 108 63k = 63 k = 1
*June 10, 2014*

**math**

x^3-a^2x+x+2 is divisible by x-a so x=a has to give a result of 0 when subbed in a^3 - a^2 (a) + a + 2 = 0 a^3 - a^3 + a + 2 = 0 a = -2
*June 10, 2014*

**maths**

area = (4)(6)sin52° = ....
*June 10, 2014*

**check answer**

good, carry on
*June 9, 2014*

**algebra**

g^-1 = { (5,-4), (2,3), (0,4)} h^-1(x) = (x-9)/2 g^-1 (2) = 3 h^-1 (x) = (x-9)/2 (h*h^1) (-7) .... is there a typo? did you mean (h*h^-1) (-7) ?? if so, then (h*h^-1) (x) = (2x+9)(x-9)/2 = (2x^2 + 9x - 81)/2 (h*h^-1) (-7) = (98 - 63 - 81)/2 = -23
*June 9, 2014*

**Math**

Basic property of triangles: the largest side is opposite the largest angle the smallest side is opposite the smallest angle etc since angle A is 125° , the sum of the other two angles must be 55° that is, "a" must be the largest side, but b > a which ...
*June 9, 2014*

**Precalculus**

Expected pay-out = .04(300) + .03(400) + (.03)(.04)(6000) = 12 + 12 + 7.20 = $31.20 how did you get 31.40 ? to make a $10 profit, they should charge 41.20 per policy
*June 9, 2014*

**Algebra 1--Please, help me!**

1. for the x-intercept let y = 0 ---> x = 2/3 for the y-intercept , let x = 0 ---> y = -2 2. (3m^2 n)/(5m)(20mn/n^6) = (3mn/5)(20m/n^5) = 12m^2/n^4 ------> a) 3. 3/x + 3/(5x) LCD = 5x = 15/(5x( + 3/(5x) = 18/(5x)-----> c)
*June 9, 2014*

**Algebra**

domain: { -7,9,0} range : { 5,-4,3,-7}
*June 9, 2014*

**Algebra 1--Please, check my answer!**

1. the slope of x+2y = -6 is -1/2 so we are looking for a line with slope +2 so anything starting with 2x-y = .... or -2x + y = ... will do. looks like b) to me 2. They all factor and simplify a) 3(x+2)/((x+2)(x-1)) = 3/(x-1) , x ≠ -2 b) 3(x-1)/((x-1)(x-1)) = 3/(x-1) , x...
*June 9, 2014*

**algebra/can you show me how to solve problem**

f(x) = x^2 + 2 f(-3) = (-3)^2 + 2 = 9+2 = 11 notice that I substituted x with the given value of x wherever I saw an x do the others the same way
*June 9, 2014*

**Algebra 1--Please, help me!**

see later post
*June 9, 2014*

**Algebracan you answer my question**

http://www.wolframalpha.com/input/?i=plot+x-y%3D4+%2C+2x%2B3y%3D13+
*June 9, 2014*

**Math**

let y = -x^2 + 5x + 5 dy/dx = -2x + 5 = 0 for a max of y 2x = 5 x = 5/2 when x = 5/2 y = -25/4 + 5(5/2) + 5 = 45/4 you should recognize y = -x^2 + 5x + 5 as a downward opening parabola , the max is 45/4 when x = 5/2
*June 9, 2014*

**Calculus**

if f ' (x) = 2x- 3x^2 f(x) = x^2 - x^3 + c f(0) = 0-0+c f(3) = 9 + 27 + c = 36+c change from f(0) to f(3) = 36+c - c = 36
*June 9, 2014*

**algebra**

Your expansion is incorrect 3(x-5)(x+5) = 3(x^2 - 25) = 3x^2 - 75 Since you wanted a quadratic equation, it should be 3x^2 - 75 = 0
*June 9, 2014*

**algebra**

What did you get ?
*June 9, 2014*

**Algebra**

follow the same steps that I showed you in your previous post of the identical type of question. It appears you never even looked at it.
*June 9, 2014*

**Algebra**

that would simply be f(x) = 2(x+3)(x+4) = 2x^2 + 14x + 24
*June 9, 2014*

**Math**

1by1 --- 64 of them 2by2 --- 49 3by3 --- 36 4by4 --- 25 5by5 --- 16 6by ----- 9 7by7 ---- 4 8by8 ---- 1 total = 204 There can only be an equal number of reds and blacks in the even-numbered squares, so 64 + 36 + 16 + 4 + 1 = 121 121 blocks have the same number of reds and ...
*June 9, 2014*

**Probability!**

since you are replacing the marble, the second draw is not affected by anything you did before. so Prob(red, then blue) = (8/43)(12/43) = 96/1849
*June 9, 2014*

**MATH**

correct
*June 9, 2014*

**MATH**

For the first, the following are divisible by 3: 3 6 9 so what do you think?
*June 9, 2014*

**math.**

0 < (x+3)/2 < 5 multiply by 2 0 < x + 3 < 10 subtract 3 -3 < x < 7
*June 9, 2014*

**Algebra**

I think the main purpose of the question, even though they did not say that, was to show that the midpoint of the hypotenuse is equidistant from the 3 vertices. All I did with the slope calculation was to show that the triangle is indeed right-angled. Other than that, finding ...
*June 9, 2014*

**Algebra**

I don't understand your question. I DID use the distance between two points formula, I just did not show the subtraction since that is easily done in your head. here is one of them with all steps : AM = √( 2.5 - 1)^2 + (3.5-1)^2 ) = √( 1.5^2 + 2.5^2) = √2...
*June 9, 2014*

**Algebra**

Your diagram should show that you have a right angle at B , but let's prove it anyway. slope AB = (2-1)/(5-1) = 1/4 slope of BC = (6-2)/(4-5) = -4 YES, AB is perpendicular to BC, thus AC is a hypotenuse midpoint of AC = M( (1+4)/2 , (1+6)/2) = M(5/2 , 7/2) = M(2.5 , 3/5) ...
*June 9, 2014*

**Algebra**

(f*g)(x) = (2x+5)(x^2 - 3) = 2x^3 + 5x^2 - 6x - 15 do the other one in the same way
*June 9, 2014*

**trig**

let's fit the data to a curve of the type f(t) = a cos k(t +d) + c from highest to lowest = 65-25= 40 cm so a = 20 from highest to lowest = .3 s to 1.8 s so period = 3 seconds 2π/k = 3 k = 2π/3 so far we have f(t) = 20 cos (2π/3) (t +d) + c let's raise ...
*June 9, 2014*

**Maths, Divine International Public School**

cotA = 8/15 tanA = 15/8 so y=15, x=8 r^2 = 15^2 + 8^2 r = √289 = 17 sinA = 15/17 cosA = 8/17 then (1+SinA)(1-SinA)/(1+CosA)(1-CosA) = (1 - sin^2 A)/(1 - cos^2 A) = (1 - 225/289)/(1 - 64/289) = (64/289) / (225/289) = 64/225
*June 8, 2014*

**Math**

upwards: f(x) = (x+2)(2x+5) downwards f(x) = -(x+2)(2x+5) expand if needed
*June 8, 2014*

**Math 11**

I hope you made a diagram. label the window position P label the top of the statue T label the bottom of the statue B So we want TB I can find BP sin34° = 20/BP BP = 20/sin34 let's use the sine law in triangle TBP TB/sin4 = BP/sin120 TB = BPsin4/sin120 = (20/sin34)(...
*June 8, 2014*

**Math helpppp!**

You gave the equation in vertex form so the vertex is easily read to be (6,3) for standard form, just expand your function h(x) = x^2 -12x + 36 + 3 = x^2 - 12x + 39
*June 8, 2014*

**math**

Euler said: V + F - E = 2 so if 4 + 6 - E = 2 -E = -8 E = 8 It has 8 edges
*June 8, 2014*

**math**

This is the same as finding a Lowest Common Denominator 20 = 2*2*5 24 = 2*2*2*3 30 = 2*3*5 so we need: 2*2*2*3*5 or 120
*June 8, 2014*

**math**

let a^(2/3) = y for easier typing then x = y - 1/y = (y^2 - 1)/y x^3 = (y^6 -3y^4 + 3y^2 - 1) / y^3 = (a^4 - 3a^(8/3) + 3a^(4/3) - 1)/a^2 or a^2 - 3a^(2/3) + 3a^(-2/3) - a^-2 3x = 3a^(2/3) - 3a^(-2/3)
*June 8, 2014*

**math**

present age: michael ---- x max ------- x-5 4 years ago: michael ---- x-4 max ------- x - 9 x-4 + x-9 = 25 2x = 38 x = 19 Michael is now 19 , and Max is now 14 check: 4 years ago , Michael was 15 and Max was 10 was the sum of their ages at that time 25? YES
*June 8, 2014*

**Math**

The equation for your cost: cost = .1(m-500) + 25 , where m is in minutes so : .1(m-500) + 25 > 30 For the second part, m = 525 cost = .1(525-500) + 25 = $27.50
*June 8, 2014*

**Pre-Calc**

For any (r,Ø) x = rcosØ, y = rsinØ so x = 5cos(π/4) , y = 5sin(π/4) x = 5√2/2 , y = 5√2/2 so you have the point (5√2/2 , 5√2/2) (I don't see why you would want to write that in decimals, since you have to round it) ...
*June 7, 2014*

**Algebra confused/Thank you**

You should be able to read the solution. http://www.wolframalpha.com/input/?i=plot+3x+%2B+2y+%3D+5+%2C+4x+−+3y+%3D+1
*June 7, 2014*

**maths**

a+bi = √(1+i)/√(1-i) = √(1+i)/√(1-i) * √(1-i)/√(1-i) = √(1 - i^2) / (1-i) = √(1 - i^2) / (1-i) * (1+i)/(1+i) = √2(1+i)/2 = √2/2 + √2/2 i so a = √2/2 and b=√2/2 and a^2 + b^2 = 2/4 + 2/4 = 1
*June 6, 2014*

**Algebra**

Put Hobbinton at the origin (0,0) on the x-y grid then Tom's house would be (12,-16) distance from (0,0) to (12,-16) = √(12^2 + (-16)^2) = √400 = 20
*June 6, 2014*

**math**

prob(c) = 1/4 prob(not c) = 3/4 so you are looking for c c notc = (1/4)(1/4)(3/4) = 3/64 c notc c = (1/4)(3/4)(1/4) = 3/64 notc c c = (3/4)(1/4)(1/4) = 3/64 prob of your event = 3(3/64) = 9/64
*June 6, 2014*

**Algebra**

the way you typed it, there is very little simplification I multiplied top and bottom by x^2 to get (x^3 + 3 - 36x + 3x^2)/(x^3 + 3x^2) , and that's about it. If you meant: ( (x+3/x^2 -36/(x+3)) /( (x+3)/x ) it would be something totally different. I can't guess what ...
*June 5, 2014*

**MATH**

Pick any x say, x = 0 y = 2(0)-5 = -5 ----> the point (0,-5) how about x = 4 , (or any x you feel like) then y = 2(4) - 5 = 3 --- the point (4,3) plot (0,-5) and (4,3) , join the with a straight line, extend the line to any length you feel like
*June 5, 2014*

**math**

that would be 8 - choose - 4 = C(8,4) = 8!/(4!4!) = 70
*June 5, 2014*

**trig**

For your first one, You should recognize those numbers as belonging to the 30-60-90° right-angled triangle which would make c = 1 If you didn't notice that, you could use the cosine law c^2 = 2^2 + √3^2 - 2(2)(√)cos30° = 4 + 3 - 4(√3)(√3/2...
*June 5, 2014*

**math word problems**

original: x by x area = x^2 new dimensions: (x+3) and (x+2) new area = (x+3)(x+2) = x^2 + 5x + 6 x^2 + 5x + 6 - x^2 = 46 5x = 40 x = 8 original was 8 by 8 check: old area = 64 new is 11 by 10 new area = 110 change in area = 110-64 = 46 , yeahh!
*June 4, 2014*

**Precalculus**

#3 Those are permutations since the order matters a) start with a vowel: 2*5*4 = 40 , you were right b) all consonants, means we only pick from 4 4*3*2 = 24 , you were right c) all vowels, you are right with 0 since we only have 2 vowels and we need 3 d) all consonants , ...
*June 4, 2014*

**Math - Business Calc.**

I noticed an error in Damon's solution 4th line : V = (17-2h)(5-2h)h = (17-h)(5h-2h^2) should be : V = (17-2h)(5-2h)h = (17-2h)(5h-2h^2) I had h = 1.1445
*June 4, 2014*

**Algebra - Help!!**

I did a synthetic division of x^3 - 7x + 6 by x+3 to get the other dimension of x^2 - 3x + 2 , looks like a)
*June 4, 2014*

**Math**

Where is the second equation ?
*June 3, 2014*

**algebra math**

so she need one of 10, 11, or 12 prob of that = 3/12 = 1/4
*June 3, 2014*

**Algebra**

LCD is 24x -9y/(12x) + 28y/(12x) - 2y/(12x) = 17y/(12x)
*June 3, 2014*

**Math**

x^3 - x^2 - x + 8 = 0 tough one - it does not factor tried x = ±1, ±2, ±4 , none worked so no rational root what about real roots? let f(x) = x^3 - x^2 - x + 8 for f(-1) = -1 -1 +1 +8 = 7 for f(-2) = -8 - 4 + 2 + 8 = -2 so there is a real root between -2 ...
*June 3, 2014*

**math**

Did you make a sketch? I have a right-angled triangle with a base of 15 and a height of 4, (10 ft - his 6 ft) so in relation to your angle of elevation Ø, we have the opposite and the adjacent, suggesting tanØ = 4/15 arctan = 14.93° So to the nearest degree: ...
*June 3, 2014*

Pages: <<Prev | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | **15** | 16 | 17 | 18 | 19 | 20 | 21 | Next>>