It depends. Are the dimensions increased by 136% or is the area increased by 136% ?
-5x^2 + 400x - 2550 > 4000 5x^2 - 400x + 6550 < 0 x^2 - 80x + 1310 < 0 what are the x-intercepts? x^2 - 80x + 1310 = 0 x^2 - 80x + 1600 = -1310 + 1600 (x-40)^2 = 290 x-40 = ± √290 x = 40±√290 = appr 57.029 or 22.97 They must spend between $22...
I thought this looked familiar Here is an extended version of your question http://www.jiskha.com/display.cgi?id=1384866716
"simplest " form would be 82944 , namely the answer if you want to write it as a power? (2^6)(6^4) or (2^4)(4)(6^4) = 4(12^4) or 4^5(3^4) or (3^4)(2^10) or ....
ok, then take log of both sides log (4^(x+2) ) = log (9^x) (x+2)log4 = xlog9 xlog4 + 2log4= xlog9 2log4 = xlog9 - xlog4 x(log9-log4) = 2log4 x = 2log4/(log9-log4) button-pushing time .... x = appr 3.419
A rough sketch of y = 4^(x+2) and y = 9x shows that the two can never meet. So, there is no solution Did you mean: 4^(x+2) = 9^x ?
In any reciprocal function or rational function, the possibility exists that the denominator could be zero. This would make the expression undefined, since we cannot divide by zero. So set the denominator equal to zero, solve for the variable, and the solution becomes the rest...
reciprocal of a linear function? I suppose we could say: f(x) = 1/(mx + b) e.g. y = 1/(3x -5) reciprocal of a quadratic function? How about f(x) = 1/(ax^2 + bx+ c) rational functions could have many different forms (there has to be an independent variable in the denominator) e...
first one: a = 1.25 period = 6 2π/k = 6 6k = 2π k= π/3 so we have y = 1.25 cos ((π/3)(t + d) + 0.75 we have to know the height at the beginning (t=0) it was not given. That is, where is the swing at the "start" ? 2. circumference = 2π(3) = 6&...
No, there is no solution, since log(any negative) is undefined. For the equation to be true, you correctly stated that 3^x = -27 I suggest you look at the graph of y = 3^x and see where the y value is -27. http://www.wolframalpha.com/input/?i=plot+y+%3D+3%5Ex