Tuesday

August 4, 2015

August 4, 2015

Total # Posts: 30,540

**math**

First let's see if it is possible. Start with a base of BC, sketch an angle of 30° at B and draw a line BA = 3.5 sketch in an altitude from A to BC to meet BC at D sin30° = AD/3.5 AD = 3.5(1/2) = 1.75 Since AC > 1.75, it will be possible to draw the triangle. As...
*April 6, 2015*

**AP CALC**

then y = c e^(kt) when t = 4 4c = c e^(4k) 4 = e^ 4k 4k = ln4 k = ln4/4 y = 1500 e^((ln4/4)t) so when t = 3 y = 1500 (e^(3ln4/4) = appr 4243 check: at t=4 y = 1500 e^(4ln4/4) = 6000
*April 6, 2015*

**geometry**

let C be (a,b) by the midpoint theorem we know: (-3+a)/2 = 5 and (2 + b)/2 = -4 -3+a = 10 and 2+b = -8 a = 13 and b = -10 so A is (-3,2) , C is (13,-10), and the midpoint between them is B(5,-4) You should have seen that your answer is incorrect as soon as you graphed it. (I ...
*April 6, 2015*

**Algebra**

You probably do not recognize that as a "sum of cubles" facoring result, if you do, you can jump directly to the final line, otherwise .... So let y = 5x^(1/3) , then 25x^(2/3) can be written as (5x^(1/3))^2 = y^2 so we have (y + 1)(y^2 - y + 1) = y^3 + 1 = (5x^(1/3...
*April 6, 2015*

**Math**

the official radius of a ping pong ball is 20 mm or 2 cm so the volume of a ball is (4/3)π(2^3) = appr 33.5 cm^3. which Ms Sue has correctly as 2.045 inches^3 but the balls will not "stack" nicely. Did you ever look at a stack of cannonballs at some fort? If we ...
*April 6, 2015*

**Math**

volumes of similar solids are proportional to the cube of their sides so volume of original = 8m^3 volume of new is 72 m^3 so let's take the smallest dimension of 1 m , since it is a unit dimension. 8/72 = 1^3/x^3 8x^3 = 72 x^3 = 9^(1/3) x = 9^(1/3) = appr 2.08 So, he ...
*April 6, 2015*

**Algebra**

= t + 4t^(1/2) + 4 or = t + 4√t + 4
*April 6, 2015*

**math**

You haven't even defined any variables, so what equations did you get?
*April 6, 2015*

**Finite Math**

treat P(R and S) as a variable, suppose it is x, then your first equation becomes P(R or S) = P(R) + P(S) - x , .... you have a typo here .64 = .38 + .52 - x x = .9 - .64 x = .26 P(R and S) = .26
*April 6, 2015*

**Math Check**

Did you even look at my reply to your same question which you posted less than 1 hour ago ? http://www.jiskha.com/display.cgi?id=1428346534
*April 6, 2015*

**Math Help Please!**

Without even doing any calculation, since there is such a large difference in the interest rates, it should be obvious that the simple interest plan should be the better of the two. check: at simple interest I = 2000(.13)(4) = 1040 so amount in your account = 3040 at compound ...
*April 6, 2015*

**math**

look at my concern about this problem in your earlier post
*April 6, 2015*

**Math: Geometry**

a) the block was (15)(8)(5) cm^3 = ..... you have to know the volume of a cylinder , which is v = π r^2 h You don't say in which direction the holes are drilled, so I can't continue
*April 6, 2015*

**Math**

If this relation were to be even remotely true, we could form a ratio .... 18 months/36 inches = 60 months/x inches 18x = 2160 x = 120 inches or 10 ft tall (can you see how absurd your question is ???? ) Also in h = 2c , you don't define what h and c stand for.
*April 6, 2015*

**algebra**

first step: (a^3 - b^3)(a^3 + b^3) second step: we can factor the sum and difference of cubes, should be in your notes or text = (a-b)(a^2 + ab + b^2)(a+b)(a^2 - ab + b^2)
*April 6, 2015*

**maths**

That is, 8x - 163 = 3x -13
*April 6, 2015*

**math**

mmmmhhh , been on this earth over 75 years, and guess what, each of those years had 4 seasons (4 quarters) , so 4 years will have 16 quarters. notice that the interest rate is compounded quarterly, so we need the rate per quarter. That is i = .06/4 = .015 n = 16 I have no clue...
*April 6, 2015*

**math**

i = .06/4 = .015 n= 4(4) = 16 Present value of payment option = 2400(1 - 1.015)^-16)/.015 = 33915.03 Well, what do you think ?
*April 6, 2015*

**math**

Prob(green, then yellow) = (5/30)(8/29) = 4/87
*April 6, 2015*

**Math**

-8x^2-8x-2=0 or 4x^2 + 4x + 1 = 0 discrm = 16 - 4(4)(1) = 0 thus there is one solution. check: 4x^2 + 4x + 1 = 0 (2x + 1)^2 = 0 2x+1 = 0 x = -1/2
*April 6, 2015*

**Precal**

change 9 to base 3 as 9 = 3^2 (3^2)^x^2 = 3^(-5x - 2) so : 2x^2 = -5x-2 2x^2 + 5x + 2= 0 (2x + 1)(x + 2) = 0 x = -1/2 or x = -2
*April 5, 2015*

**calc 1**

Look at the solution I gave Ryan for an almost identical problem as yours http://www.jiskha.com/display.cgi?id=1427010949
*April 5, 2015*

**Math**

I think Steve is missing part of the formula and/or using the wrong formula. PV = paym(1 - (1+i)^-n)/i so here PV = 900(1 - 1.02^-16)/.02 = $12,219.94 So he should take the payment option.
*April 5, 2015*

**algebra**

I will read that as: (x+3)/x^3 ÷ 6/(x-3) then ... = (x+3)/x^3 * (x-3)/6 = (x^2 - 9)/(6x^3)
*April 5, 2015*

**math**

You don't tell me what your x represents, but from your equation I conclude that you defined x to be each of the 3 parallel sides and y as the length of the whole field then area = xy = x(2250 - 1.5x) = -1.5x^2 + 2250x your A(x) = 2250 - 1.5x^2 is almost correct, but it is...
*April 4, 2015*

**math**

divide your equation by 50 20x + 10y + z = 200 remember that x, y, and z must be positive whole numbers. Are we allowed to have zero of any of them ???? I will let you decide that z = 200 - 20x - 10y maximum value of x has to be 9, (if x=10, z = 0) maximum value of y has to be...
*April 4, 2015*

**algebra**

One small change from your previous problem. Instead of 46 minutes you now have 54 minutes.
*April 4, 2015*

**algebra**

distance outside city --- x distance inside city ---- 33-x time = distance/rate x/50 + (33-x)/30 = 46/60 solve for x (I suggest multiplying each of the 3 terms by 300)
*April 4, 2015*

**math**

points depend on the number of prizes
*April 4, 2015*

**Trigonometry**

first answer line should be 1. y = 2 sin 4(x - π/8) + 1 or y = 2 sin (4x - π/2) + 1
*April 4, 2015*

**disagree - rigonometry**

I disagree with your phase shift in general: y = a sin k(x - d) + c the phase shift is d. Notice that the period indicator k is factored out In your answer we have ... sin(4x - π/8) ... or ... sin 4(x - π/32)... So the phase shift of your equation would be π/32 ...
*April 4, 2015*

**maths**

circumference = 40π cm so in one minute would cover 50(40π) or 2000π cm to cover 6.28 km or 628000 cm would take 628000/(2000π) minutes , or 99.949.... minutes, which is appr 1hr and 40 minutes
*April 4, 2015*

**geometry**

let the third side be x , where x is a positive number FACT: the sum of any two sides of a triangle must be greater than the third side, so 22+34 > x AND 22+x > 34 AND 34+x > 22 clearly 34+x is always > 22, so for the other two ... 56 > x AND x > 12 or 12 <...
*April 3, 2015*

**geometry**

Don't all three angles add up to 180° ? Use this fact to form your equation, then solve it
*April 3, 2015*

**math discrete 2**

Since it is linear, we can just "reverse" our steps. e.g. for g(x) , for any x, the first thing we do is multiply it by 4 and then subtract 5 now doing this backwards, start with an x, add 5, then divide that be 4 so g^-1 (x) = (x+5)/4 standard method: step1 : ...
*April 3, 2015*

**math discrete**

h◦(g◦f) = h(g(f(x) ) ) = h(g(4x^3 - 5) ) ) = h(2(4x^3 - 5)) = ( 2(4x^3 - 5) )^2 manipulate this if needed. testing with some value, say x = 2 according to my result: (2(32-5))^2 = 2916 long way: f(2) = 27 g(27) = 54 h(54) = 2916
*April 3, 2015*

**Math**

Did you make your sketch?? According to mine it is a simple case of the cosine law HB^2 = 270^2 + 160^2 - 2(270)(160)cos 23° = .. take over
*April 3, 2015*

**Math - Help Me Please**

cost = 300 + 40(1 - 1.0325^-24)/.0325 = $ 959.53 interest paid = 300 + 24(40) - 959.53 = $300.47 Wow, that is 39% . Is that even legal? In the middle ages they would have burned you at the stake for usury.
*April 3, 2015*

**pre calculus**

cost = 2000 + 15(x-100) , x ≥ 100 b) just divide all of the above by x c) plug in your x d) set your equation in a) equal to 16
*April 3, 2015*

**present value**

PV = 20000(1.04)^-1 + 10000(1.04^-2 + 1.04^-3 + 1.04^-4 + 1.04^-5) = ... you push the buttons
*April 3, 2015*

**Geometry help**

original: length --- x width ---- y height ---z xyz = 420 new prism length --- x/2 width ---- y/3 height --- z (x/2)(y/3)z = = xyz/6 = 420/6 = 70 units3 notice it wouldn't matter which dimensions are halved and cut into thirds, I could have used other combinations. The ...
*April 3, 2015*

**math**

That would be an example. To solve it, I would change the 2nd to y = 24-4x and sub that into the 1st.
*April 3, 2015*

**Algebra**

Were the "givings" consecutive or simultaneous ?
*April 3, 2015*

**math**

Present Value = 900(1 - 1.0041666..)^-300)/.0041666... = $153,954.05
*April 3, 2015*

**M ath**

i = .09/12 = .0075 a) n = 9(12 = 108 pmt( 1 - 1.0075^-108)/.0075 = 26000 pmt = $352.12 b) I will assume you know what changes to make for b)
*April 3, 2015*

**Math/Calculus**

I agree
*April 2, 2015*

**math- please help me - Ms. Sue**

The above method results in an interest rate much higher than 18%. Explanation: The $216 of simple interest would be valid if there were no payments made and you would just pay back the $816 after 2 years. BUT, you are making payments of $34 each month so the balance keeps ...
*April 2, 2015*

**Math**

you are correct.
*April 2, 2015*

**Algebra help Will only take a minute**

Plug in n = 1 , 2, 3, 4 , .... and see what you get remember, you have to calculate the power before you multiply by 5
*April 2, 2015*

**Math please help**

I got the same results, and I stand by them
*April 2, 2015*

**Math please help**

Every angle can be found. In triangle CAT, use the sine law to find AC and in triangle BAT, use the sine law to find AB Area of triangle ABC = (1/2)(AC)(AB)sin 60° = ...
*April 2, 2015*

**math please help**

mmmh, and we are supposed to guess where ?
*April 2, 2015*

**math please help**

Where do points D and E enter the picture ?
*April 2, 2015*

**Math, Science**

h = -4.9t^2 + 15t take derivative, set equal to zero, and solve for t plug t back into h = ...
*April 2, 2015*

**calculus**

A litter is a group of kittens, a litre is a fluid measure of 1000 ml let the height be h cm let the radius be r cm πr^2 h = 200 h = 200/(πr^2) amount of material ---> surface area (SA) SA = 2πr^2 + 2πrh = 2πr^2 + 2πr(200/(πr^2)) = 2π...
*April 2, 2015*

**Algebra**

The instructions appear quite clear, where does your problem arise? I will do a) Left Side = g(x+2) = 7(x+2) - 2 = 7x + 14 - 2 = 7x + 12 Right Side = g(x) + g(2) = 7x - 2 + 12 - 2 = 7x +8 Thus g(x+2) ≠ g(x) + g(2) do the others in a similar way
*April 2, 2015*

**algebra**

The speed of the wind is indeed 200/7 or 28.57 mph check: with the help of the wind the plane is moving at 228.57 mph, for 6 hrs = 1371.43 kkm against the wind, the plane is moving at 200-28.57 or 171.43 km/h, and for 6 hours that would be 1028.57 and (3/4)(1371.43) = 1028.57 ...
*April 2, 2015*

**algebra**

let the speed of the wind be x km/h so distance with the wind = 6(200+x) km distance against the wind = 6(200-x) but 6(200-x) = (3/4)(6(200+x)) solve for x , let me know what you get.
*April 2, 2015*

**Math**

and .... ?
*April 2, 2015*

**Math - hw check**

Remember, that your x and y have to be whole numbers, since they represent number of people, (can't have partial people) What they want you to do is graph both x+y = 12 and 8x + 15y = 131. The intersection of the two lines will be your answer. What you did is simply find ...
*April 2, 2015*

**Math please help**

First of all , the length of the hypotenuse is not 10 AC^2 = 5^2 + 9^2 = 106 So AC = √106 Area of square on that side = AC*AC = AC^2 = 106 - end of problem! Since I don't see your diagram, I have no idea where your 11 and 121 comes from.
*April 1, 2015*

**Math please help**

So you have the famous 30-60-90 right-angled triangle, which has sides in the ratio 1 : √3 : 2 (memorize those values, easy to remember that the smallest side is opposite the smallest angle and the largest side is opposite the largest angle) so using simple ratios QR : ...
*April 1, 2015*

**math please help**

I suspect this is a question in the topic of circles. If I draw any triangle on the diameter of a circle, then the angle subtended by that diameter must be 90° So draw a semicircle with a diameter of 15 , (your 3+12 parts of AX and CX ) Since BX is an altitude (it says it ...
*April 1, 2015*

**Math (ASAP)**

then check back please
*April 1, 2015*

**Math (ASAP)**

Makes no sense. Did you check for my concern about this question when you posted it earlier?
*April 1, 2015*

**math please help**

Have you come across this area formula for the area of a triangle ? - if two sides are a and b, and Ø is the angle between them, then the area = (1/2)(ab)sinØ so for yours, area = (1/2)(12)(12)sin 120° = .....
*April 1, 2015*

**Algebra**

You are welcome
*April 1, 2015*

**Algebra**

write it as: x^3(x^2-1)^(-5/8) + 2x(x^2-1)^3/8 common factor is x(x^2 - 1)^(-5/8) so we get =x(x^2 - 1)^(-5/8) [ x^2 + 2(x^2 - 1)] = x(x^2 - 1)^(-5/8) (3x^2 - 2) or = x(3x^2 - 2)/(x(x^2 - 1)^(5/8) )
*April 1, 2015*

**Algebra**

Well yeahh! That would make it (3√t + 5)(3√t - 5) = 9t - 25 , and the 9t - 25 is what I had pointed out to you above. Usually, the instruction to "factor" implies that we restrict ourselves to rational numbers. If you allow irrationals, like the above, or...
*April 1, 2015*

**Algebra**

And as I said before, 1/1 is merely 1, so why even have the exponent ? If it were the way I suspect as 9t^2 - 25 you could write it as a trinomial by inserting 0t and now you have a trinomial 9t^2 + 0t - 25 = (3t+5)(3t-5) but you claim that is not right. I don't think I ...
*April 1, 2015*

**Algebra**

Must be the way you typed the original question. If the answer is (3t+5)(3t-5) then the original question must have been 9t^2 - 25 , which is not even close to what you typed.
*April 1, 2015*

**Algebra**

nope, the 1/1 part is simply 1 , so 9t^1/1 simply becomes 9t so you have just 9t - 25 , which does not factor
*April 1, 2015*

**Algebra**

I am sure it was not worded like that in your textbook.
*April 1, 2015*

**math**

The distributive property distributed multiplication over addition or subtraction. I see no addition so 4(y*y) = 4*y*y = 4y^2
*April 1, 2015*

**Calculus**

Did you check the "Related Questions" below ?
*April 1, 2015*

**calculus**

Did you check all those "Related Questions" below, which are the same as yours? Steve's answer is probably the best http://www.jiskha.com/display.cgi?id=1414421171
*April 1, 2015*

**calc**

so h = r V = (1/3)πr^2 h ---- #1 V = (1/3)π h^3 dV/dt = π h^2 dh/dt ----- #2 you have all the values of #2 except dh/dt Go for it
*April 1, 2015*

**calculus**

A = πr^2 dA/dt = 2πr dr/dt when A = 10 πr^2 = 10 r^2 = 10/π r = √(10/π) you now have r and dr/dt, so just plug in and push buttons on your calculator
*April 1, 2015*

**Calculus**

Is that supposed to say: y = x^8 / 37 ? then 37y = x^8 37dy/dx = 8x^7 dx/dx dy/dx = (8/37)x^7 usually the multiplier is written in front of the variable
*April 1, 2015*

**Math, please help**

Yes, there are 36 outcomes. Make a chart using rows and columns from 1 - 6 Fill in the sums, you will find that 18 will be even and 18 will be odd So prob(sum is odd) = 18/36 = 1/4
*April 1, 2015*

**math**

Did you not check your previous post on this same question? http://www.jiskha.com/display.cgi?id=1427909481
*April 1, 2015*

**Math**

I don't know what method you have learned to find the determinant, but I get x^2 - 4x - 22 = 10 x^2 - 4x - 32 = 0 (x-8)(x+4) = 0 x=8 or x=-4
*April 1, 2015*

**Math**

Did you mean the determinant of the matrix is 10 ?
*April 1, 2015*

**6th Grade Geometry Help Please**

done, look at your other post
*April 1, 2015*

**6th Grade Geometry Help and A.S.A.P!!**

It makes no difference which units you use, as long as you label your dimensions with those units. however, use common sense which units you pick. It would not make much sense to use either yards or metres to measure the diameter of a coffee mug, I would use either cm or ...
*April 1, 2015*

**6th Grade Geometry Help and A.S.A.P!!**

You would use whichever instrument or ruler you have. If you have a metric ruler, use centimetres, then your circumference will be in the same units, namely centimetres, and your area will be cm^2 Noah would have measured a circle in cubits and his circumference would have in ...
*April 1, 2015*

**math**

If a point is reflected in the x-axis, its x value stays the same, but its y value becomes opposite Make a sketch to see how this happens e.g. A(2,-5) ---> A' (2,5) do this with the other two points.
*April 1, 2015*

**exponential equations**

what is 85000(1.0725)^8 ??
*April 1, 2015*

**math help**

not enough information. Do these point lie in on a straight line? Do the points fall in order of A,B,C,... ?
*April 1, 2015*

**maths please help and explain**

by 21"40^1, I will assume you mean 21° 40 minutes and 1 second 1 second = 1/3600 of a degree 1 minute = 1/60 of a degree so 21"40^1 = 21 + 40/60 + 1/3600 = 21.66694444.. so sin(21.6669444..) = .3692106... do the same for the second term, then add them up On most ...
*April 1, 2015*

**math**

Which of the x values has been increased by 3 units without changing its height , that is 5+3 = ????
*April 1, 2015*

**calculus**

I made a sketch, drew lines from her eyes to the top and bottom of the picture and called this angle a I drew a horizontal from her eyes to the wall and called that angle of elevation b so we have two tangent relations. tan(a+b) = 12/x and tanb = 5/x then a+b = arctan (12/x) ...
*April 1, 2015*

**Geometry**

areas of similar figures area proportional to the square of their sides area1/area2 = side1^2/side2^1 1/4 = side1^2/side2^2 4side1^2 = side2^2 take √ of both sides 2side1 = side2 so if one side is 3, the side of the larger square must be 6 check: area of smaller is 3x3...
*April 1, 2015*

**precalculus**

u dot v = |u| |v| cosØ where Ø is the angle between them 18-1 = √10√37cosØ cosØ = 17/√370 Ø = cos^-1 (17/√370) = appr 27.9° your B and C are undecipherable
*March 31, 2015*

**precalculus**

Too bad, ok, the long way then ..... I am just going to call z1 as z let z^(1/3) = a + bi then z = (a+bi)^3 = a^3 + 3a^2 bi + 3a b^2 i^2 + b^3 i^3 = a^3 + 3a^2 b i - 3ab^2 -b^3 i = (a^3 - 3ab^2) + i (3a^2b - b^3) but z = 2(cos 2π/3 + i sin 2π/3) = -1 + √3i so ...
*March 31, 2015*

**precalculus**

Are you familiar with DeMoivre's Theorem?
*March 31, 2015*

**precalculus**

let u = [a,b] then a^2 + b^2 = 20 and tan60° = b/a = √3 b = √3 a back in a^2 + b^2 = 20 a^2 + (√3a)^2 = 20 a^2 + 3a^2 = 20 a^2 = 5 a = ±√5 b = ±√15 u = [√5,√15] or [-√5,-√15] or in your notation u = &...
*March 31, 2015*

**Finance - Loans problem**

done, see your previous post
*March 31, 2015*

**algebra**

Woahhh, let's back up here, how did you get that inverse? How do you find the inverse of a function? - you interchange the x and y variables. so the inverse of y = x^2 + 4 is x = y^2 + 4 - now solve this for y y^2 = x - 4 y = ±√(x-4) now let x = 8 , (or some ...
*March 31, 2015*

**Finance - Loans problem**

the monthly interest charge on the $17,000 loan is (.07/12)(17000) = 99.17 Since the interest is paid every month , the outstanding balance will remain at $17,000. So we need to set up a monthly payment which will accumulate to 17,000 at the end of 5 years, using the 12% of ...
*March 31, 2015*