Tuesday

July 26, 2016
Total # Posts: 35,348

**math**

Your Taylor expansion of f(x) is correct I disagree with your derivative, it should be (-1/4)((1/16 + x)^(-5/4) why not just integrate ʃ(1/16 +x)^(-1/4) dx to get (4/3)(1/16 + x)^(3/4) + C
*April 24, 2016*

**maths**

let z^5 = rcosθ + rsinθ i = -1 + 0 we have r = 1 θ = 180° so z^5 = 1(cos180° + isin180°) by de Moivre's theorme z = 1^(1/5)(cos 180/5 + i sin180/5) = 1(cos 36° + isin36°) or cis36° repeating at 360/5 or 72° z = cis 36° z = ...
*April 24, 2016*

**math**

(3.3x10^3)(1.8x10^4) = 5.94 x 10^7
*April 23, 2016*

**Math**

the prob that the biased coin is tails = .4 so prob(3tails) = .4^3 = .064 So what do you think?
*April 23, 2016*

**Pre-Calc**

we can only take logs of positive numbers so 3x-8 > 0 3x > 8 x > 8/3 I will let you write it in the new-fangled notation. In my time we used the above simple way of stating it.
*April 23, 2016*

**maths**

x^3 + y^3 = 72 x^2 - y^2 = 12 We could just do this by listing the cubes less than 72 : 1, 8, 27, 64 the only combination for a sum of 72 is 8 + 64 so x=2, y=4 so the numbers are 2 and 4 is the difference property ok? is 16-4 = 12 ?? YES
*April 23, 2016*

**math**

the largest prime < 50 is 47 the smallest composite > 10 is 12 so what is the difference between those ?
*April 23, 2016*

**Math**

s = t(t^2 - 8t + 16) = t^3 - 8t^2 + 16t v = 3t^2 - 16t + 16 a = 6t - 16 for zero of a, 6t-16=0 t = 16/6 = 8/3 seconds when t = 8/3 v = 3(64/9) - 16(8/3) + 16 = -16/3 s = (8/3)(8/3 - 4)^2 = 128/27 work these answers in with your concluding statements
*April 23, 2016*

**maths**

When it falls down, the distance is zero so 0 = 30t - 4.9t^2 t(30 - 4.9t) = 0 t = 0 , that would be at the beginning or t = 30/4.9 or appr. 6.12 seconds 2nd part: 20 = 30t - 4.9t^2 4.9t^2 - 30t + 20 = 0 t = (30 ± √508)/9.8 = .761 seconds, on its way up or = 5.36 ...
*April 23, 2016*

**algebra**

did you mean an = (3)^(n−1) ? if so, follow the same steps I showed you in your previous post.
*April 23, 2016*

**sequence**

If n = 1, term(1) = 4 if n = 2, term(2) = 8 if n = 3, term(3) = 12 etc
*April 23, 2016*

**Math**

Unless I see an obvious identity I can replace, I usually change everything to sines and cosines. LS = (1/cosx - cosx)/(sinx/cosx - sinx) = ( 1 - cos^2 x)/cosx )/( (sinx - sinxcosx)/cosx ) = ( 1 - cos^2 x)/cosx )* cosx/( (sinx - sinxcosx) = (1 - cos^2 x)/(sinx(1 - cosx)) = (1...
*April 23, 2016*

**math**

shares bought at RS140 --- x shares bought at RS125 --- y amount invested at 6% --- 140x amount invested at 5% --- 125y 140x + 125y = 6750 ** .06(140x) + .05(125y) = 280 8.4x + 6.25y = 280 times 20 168x + 125y = 5600 *** subtract ** from *** 28x = -1150 not possible. Unless ...
*April 23, 2016*

**geomentry**

I drew a line AB, with A to the left of B I marked P and Q on the left side of the midpoint. "Point P divides AB in the ratio 2:3" ---> let AP = 2x and PB = 3x then AB = 5x "Q divides AB in the ratio 3:4" --> let AQ = 3y and QB = 4y then AB = 7y ...
*April 23, 2016*

**Maths**

The altitude in an isosceles triangle right-bisects the base, so BD = DC let BD = x then BC = 2x AB = 4x in the right-triangle ABD AD^2 + x^2 = (4x)^2 = 16x^2 AD^2 = 15x^2 AD^2 = 15BD^2 , not 15 BC^2 as you stated.
*April 23, 2016*

**Finance**

amount at 4% compounded quarterly = 1500(1.01)^20 = .. amount at 4% compounded semi-annually = 1500(1.02)^10 = .. amount at 4% per annum = 1500(1.04)^5 = ...
*April 23, 2016*

**Math**

let the number be x x/2 + 4 = 10 carry on
*April 22, 2016*

**Math, NEEDS HELP EMEDIETLY!**

To me the method of your solution is much more important than the answer. Since your method makes no sense, it would benefit you to actually care more about how the answer is obtained. 7/12 of the students take martial arts, and (7/12)(144) = 84 sample size?? well, how many ...
*April 22, 2016*

**Science/Math**

a = -4 m/s^2 v = -4t + k when t = 0, v = 3- thus k = 30 v = -4t + 30 when the vehicle stops, v = 0 0 = -4t + 30 4t = 30 t = 30/4 or 7.5 seconds
*April 22, 2016*

**Calculus Help**

lim (5 - √x)/(x-25) as x ---> 25 = lim (5-√x)/((√x-5)(√x+5)) = lim -1/(√x+5) as x ---> 25 = -1/(5+5) = -1/10
*April 22, 2016*

**math**

√-1 , also called i , is a complex or imaginary number. Every other complex number can be expressed in terms of i
*April 22, 2016*

**math**

Your start would be to make a diagram of the right-angled triangle. Then you should see that if L is the length of the ladder, sin76° = 10/L L = 10/sin76° = 10.306 m
*April 22, 2016*

**Mathematics**

let u = e^x then u^2 = e^(2x) and du/dx = e^x dx = du/e^x = du/u ʃ e^x /sqrt[e^(2x) -1] dx = ʃ u/√(u^2 - 1) du/u = ʃ 1/√(u^2 - 1) du = ln (√(u^2 - 1) + u) , from my old integration formulas = ln((√(e^(2x) - 1) + e^x) + C
*April 22, 2016*

**Geometry**

circumference of whole circle = 2pi r = 6pi so : arc/6pi = 20/360 arc = 120pi/360 = pi/3 = appr 1.047 units or arc = rθ , where θ is the angle in radians so 20 degrees = 20pi/180 radians = pi/9 arc = 3(pi/9) = pi/3 , same as above
*April 22, 2016*

**Math (Calculus)**

Yes, it does work, let's set -6x^2+20.4x+202.275 = 0 6x^2 - 20.4x - 202.275 = 0 I used the formula and got x = 7.75 or x = -4.35 remember that the function is increasing when the derivative is postive, and decreasing when .... so the function is increasing for -4.35 < x...
*April 21, 2016*

**Math Pythagorean**

northern direction = 3 - 1 + 2 = 4 eastern direction = 2 + 4 = 6 h^2 = 4^2 + 6^2 = 52 the hypotenuse is √52 = appr. 7.2 miles
*April 21, 2016*

**Math**

older sister --- x younger sister --- 19-x in 5 years: (x+5)(24-x) = 208 -x^2 + 19x + 120 - 208 = 0 x^2 - 19x + 88 = 0 (x-11)(x-8) = 0 x = 11 or x = 8 older sis is 11, younger is 8 check: in 5 years: 16(13) = 208 , all is good
*April 21, 2016*

**Math**

expand: (x-5) log19= (x+2) log3 xlog19 - 5log19 = xlog3 + 2log3 xlog19 - xlog3 = 2log3 + 5log19 x(log19 - log3) = 2log3 + 5log10 x = (2log3 + 5log19)/(log19 - log3) = appr 9.1663
*April 21, 2016*

**algebra 2**

(21 − 4i) − (16 + 7i) + 28i just like basic algebra ... = 21 - 4i - 16 - 7i + 28i = 5 + 17i
*April 21, 2016*

**math 1**

8p^2 + 56p + 98 = 2(4p^2 + 28p + 49) = 2(2p + 7)^2 ----> notice the perfect square in the 2nd last line
*April 21, 2016*

**Math**

–1, 9, 19, 29, . . . looks like you are adding 10 each time, so the next 3 terms would be 39, 49, 59 None of your choices match that, unless C contains a typo Your choice of D is definitely wrong
*April 21, 2016*

**Math- Check my answers please!**

#3 4^4/4^6 = 1/4^2 = 1/16 #5 7^4/7^2 = 7^2 = 49 #6 –2r(8r + 5) = -16r^2 - 10r #7 4a(a^2 + 7a + 4) = 4a^3 + 28a^2 + 16a #8 (2y-3)(3y-2) = 6y^2 - 4y - 9y + 6 = 6y^2 - 13y + 6 Looks like somebody has some major review ahead of them.
*April 21, 2016*

**maths-I only need the solution**

To me, the actual solution is less important than the method of getting that solution. We should assume that all values would be whole numbers. More than that, all numbers would have to be perfect squares or else we would have decimals suppose we subtract the second from the ...
*April 21, 2016*

**Math**

What part of yesterdays solution did you not like? http://www.jiskha.com/display.cgi?id=1461201861
*April 21, 2016*

**math0**

We have to know how many gumballs there are and how many of each colour.
*April 21, 2016*

**maths**

P = k/Q + C given: P=3, Q=9 3 = k/9 + C 27 = K + 9C *** P=9, Q = 18 9 = k/18 + C 162 = k + 18C ** subtract *** from ** 135 = 9C C = 15 in *** k+135 = 27 k = -108 P = -108/Q + 15 so when Q = 12 P = -108/12 + 15 = 6
*April 21, 2016*

**sequences and Series**

I have now answered 6 of your questions without any effort on your part showing me that you have attempted these. What do you think about this one? Why not just follow the rules of the sequence as you stated them?
*April 21, 2016*

**Maths**

Ok so far simplify your expression a bit and use proper brackets = 11Ck (1/4)^(11-k) (-16)^k x^(11-k) y^k so y^k <----> y^4 thus k = 4 the coefficient comes from 11Ck (1/4)^(11-k) (-16)^k = 11C4 (1/4)^7 (-16)^4 = 330(1/16384)(65536) = 1320 confirmation: https://www....
*April 21, 2016*

**sequences and Series**

geeesh, why not just list the berries handed out for each house? There are only 5 identical steps
*April 21, 2016*

**Sequences and Series**

appears to go 6,5,1,2 ..... a cycle of 4 terms. the 21st term must be 6
*April 21, 2016*

**Sequences and Series**

add 1 to each even numbered term add 5 to each odd numbered term 25,5,30,6,35,7,40,8,45,...
*April 21, 2016*

**Series and Sequences**

Not enough data to tell for the first 3, there is an increase of 20 from one to the other for the last three, there is the same increase but we can't tell what happened from term3 to term4
*April 21, 2016*

**please math help**

T/F ---- x multiple choice --- y x+y = 20 ----> y = 20-x 3x + 11y = 100 3x + 11(20-x) = 100 3x + 220 - 11x = 100 -8x = -120 x = 15 and then y = 5 There are 5 multiple choice questions
*April 21, 2016*

**Math linear equations**

large pitcher --- x small pitcher --- y x + 2y = 8 x - y = 2 subtract them: 3y = 6 y = 2 then x = 4 large holds 4 cups, the smaller holds 2 cups
*April 21, 2016*

**Math**

radius of circle = 1450 ft circumference of whole track = 2π(1450) = 2900π ft angle of sector between them = 90 + arctan(1440/170) = 173.267° Distance Robin has to make up is 173.267/360 = x/2900π x = 4384.9155 ft He is gaining on him at a rate of 1.3 ft/sec...
*April 20, 2016*

**Math**

prob(grow) = .65 prob(not grow) = .35 prob(1 of 11 will not grow) = C(11,1)(.35)(.65)^10 = .05183
*April 20, 2016*

**NEED HELP MATH QUESTION ASAP**

Prob(rolling a two) = 1/6 number of expected times of getting a 2 in 6 rolls = 6(1/6) = 1
*April 20, 2016*

**Math**

I assume you meant:Volume = 4(c)^3(b)^8 Base area = 16(ab)^3 let the height be h h(16(ab)^3) = 64(c)^3(b)^8 h = 4 c^3 b^5 /a^3 No choice is correct
*April 19, 2016*

**math**

age of son ---- x age of woman --- 4x 5 years from now: son : x+5 woman : 4x+5 4x+5 = 3(x+5) solve for x
*April 18, 2016*

**Trig**

This same post has been declared as muddled and garbled several times. It has been answered by both Steve and I and you should not expect any more replies until you fix the wording so that the question makes sense http://www.jiskha.com/display.cgi?id=1460596777
*April 18, 2016*

**Math/algebra**

Cutting through the chase: 60 + -25x = 35x + 20 -25x - 35x = 20 - 60 -60x = -40 x = 40/60 = 2/3
*April 18, 2016*

**Trigonometry**

draw your triangles in the correct quadrantIs. Use Pythagoras in each case. if cosu = 3/5, in IV, then sinu = -4/5 if cosv = 12/13, then sinv = -5/13 sin(u-v) = sinu cosv - cosu sinv = (-4/5)(12/13) -(3/5)(-5/13) = (-48 + 15)/65 = -33/65
*April 17, 2016*

**Ms Sue please helpp**

4356/9999 = 484/1111
*April 17, 2016*

**Algebra**

x y 1stdiff -- 2nddiff 0 4 1 5 -- 1 ----- 2 8 -- 3 ----- 2 3 13 --5 ----- 2 4 20 --7 ----- 2 since the 2nd difference is a constant, it must be a quadratic, or 2nd degree function
*April 15, 2016*

**Algebra**

take 1/2 of the coefficient of the middle term, then square it, so c = 169/4
*April 15, 2016*

**Algebra**

rate of smaller pipe --- 1/x rate of larger pipe ---- 1/(x-18) , where x > 18 combined rate = (x-18 + x)/(x(x-18) = (2x-18)/(x^2 - 18x) 1/[(2x-18)/(x^2 - 18x)] = 12 x^2 - 18x = 24x - 216 x^2 - 42x + 216 = 0 (x - 36)(x - 6)= 0 x = 36 or x = 6 but x = 6 does not fall into my ...
*April 15, 2016*

**Algebra**

http://www.jiskha.com/display.cgi?id=1460741071
*April 15, 2016*

**Algebra**

look below at Related Questions for variations of your question. Simply change the numbers in the solution by Henry
*April 15, 2016*

**Algebra**

your equation should be s = -4t^2 - 6t + 100 you want to know when s = 0 4t^2 + 6t - 100 = 0 2t^2 + 3t - 50 = 0 t = (-3 ±√409)/4 = appr 4.3 seconds or a negative, which we will reject
*April 15, 2016*

**Algebra**

speed of slower plane --- x km/h speed of faster plane --- x+50 km/h 1400/x - 1000/(x+50) = 3 times x(x+50) 1400(x+50) - 1000x = 3x(x+50) 1400x + 70000 - 1000x = 3x^2+ 150x 3x^2 - 250x - 70000 = 0 (x - 200)(3x + 350) = 0 x = 200 or a negative, which is rejected The slower ...
*April 15, 2016*

**math**

In the first case I would be dividing both sides by -4 In the second equation I would be multiplying both sides by -4 the two answers differ by a factor of 16
*April 15, 2016*

**math**

you are welcome
*April 15, 2016*

**math**

From some starting point, draw 5 lines downwards. From the end of each of those lines, branch off 3 more lines each There should now be 15 endpoints.
*April 15, 2016*

**maths**

Confirming Steve's conclusion: https://www.wolframalpha.com/input/?i=Plot+y+%3D+e%5Ex,+y+%3D+x
*April 15, 2016*

**engineering mathematics**

let f(x) = x^3 - 6x^2 + 13x - 9 f'(x) = 3x^2 - 12x + 13 xnew = x - f(x)/f'(x) = x - (x^3 - 6x^2 + 13x - 9)/(3x^2 - 12x + 13) = (3x^3 - 12x^2 + 13x - x^3 + 6x^2 - 13x + 9)/(3x^2 - 12x + 13) = (2x^3 - 6x + 9)/(3x^2 - 12x + 13) using my calculator, with an initial guess ...
*April 15, 2016*

**math**

for a fun topic along these lines, Google and look into the "chinese remainder theorem"
*April 14, 2016*

**math**

So the number must be such that when divided by 3 , leaves a remainder of 1 when divided by 4 , leaves a remainder of 1 when divided by 5 , leaves a remainder of 1 Find the lowest common number is these sets: 4 7 10 13 16 19 22 25 28 31 34 37 40 43 46 49 52 55 58 61 64..... 5 ...
*April 14, 2016*

**algeabra**

x+7 divided by x-4 = 1 + 11/(x-4) test by adding 1 + 11(x-4)
*April 14, 2016*

**maths**

Jake --- x Ken ---- 4x giveaway: Jake --- x+360 Ken ---- 4x-360 4x-360 >= x+360 3x >= 720 x >= 240 Ken >= 600 The least Ken will have is 600
*April 14, 2016*

**mathematics-combination vs A.P**

then n!/(5!(n-5)!) - n!/(4!(n-4)!) = n!/(6!(n-6)! - n!/(5!(n-5)!) divide each term by n! and re-arrange 2/(5!(n-5)!) - 1/(4!(n-4)!) = 1/(6!(n-6)!) realize that 6!=6x5x4! and (n-4)! = (n-4)(n-5)(n-6)! 5!=5x4! and (n-5)! = (n-5)(n-6)! multiply each term by 6!(n-4)! 2(6)(n-4) - (...
*April 14, 2016*

**Statisitcs**

Use the same formula you have to find the z-score I don't know if you use tables from the back of a textbook, or some webpage like David Lane's fabulous page http://davidmlane.com/hyperstat/z_table.html suppose that the percentage of Alice getting a mark of 75 or less ...
*April 14, 2016*

**Math**

John's rate = room/3 Apprent's rate = room/6 combined rate = room/2 + room/6 = 3room/6 = room/2 time at combined rate = room/(room/2)) = 1/(1/2) = 2 hours
*April 14, 2016*

**Disagree - MATH I DONT UNDERSTAND PLZ HELP ASAP THX= }**

At 6:00 am, the temperature was -20° C after having risen 8° since midnight So at midnight it was -28° (years ago that would have been just a nippy night. These last few years it never got that cold in my part of Canada)
*April 13, 2016*

**calculus 1**

let the radius be r and let the height be h πr^2 h = 2000π h = 2000/r^2 we want to minimize the surface area A A = 2πr^2 + 2πrh = 2πr^2 + 2πr(2000/r^2) = 2πr^2 + 4000π/r dA/dr = 4πr - 4000π/r^2 = 0 for a minimum of A 4πr...
*April 13, 2016*

**Precalculus(another)**

The wording is quite muddled in the middle of your post. However, I think we have a cosine law problem here, with sides 12 and 5 and the contained angle as 37 degrees d = 12^2 + 5^2 - 2(12)(5)cos37 = ....
*April 13, 2016*

**Precalculus**

I assume you only want the length of the cable going down the hill. Make a sketch. On mine I have a triangle with sides 100 and 95 with an angle of 102 degrees between them. The cosine law is just screaming at you here. x^2 = 100^2 + 95^2 - 2(100)(95)cos102 = .... you do the ...
*April 13, 2016*

**CONSUMER MATH**

I assume the $12,000 is the present value i = .039/12 = .00325 n = 6(12) = 72 Payment = p p( 1 - 1.00325^-72)/.00325 = 12000 solve for p
*April 13, 2016*

**Math**

If 1/4 inches ---> 1 ft then 1 inch -----> 4 ft and 3 inches ---> 12 ft
*April 13, 2016*

**Math**

Make a sketch, extend the line from the top of the tower to the man until it hits the base line You now have a small isosceles right-angled triange within a larger one. so the smaller one has legs 1.4 m and 1.4 m. So the base of the larger is 1.4+10 or 11.4 m, which means that...
*April 13, 2016*

**Damon,steve,reiny,bobpursley....Any 1 just help me plz**

That's just plain silly.
*April 13, 2016*

**Geometry**

You want the lateral surface area of a cone = π r s, where r is the radius, and s is the "slant" height = π(25)(32) = cm^2
*April 13, 2016*

**Algebra**

This is a GP where a = 26000 and r = 1.03 sum(5) = 26000(1.03^5 - 1)/(1/03-1 = $138,037.53
*April 13, 2016*

**Algebra 2**

if you want your index to be n = 0 , then 9 Σ 2(n+1) n=0
*April 13, 2016*

**Algebra 2**

10 Σ 2n n = 1
*April 13, 2016*

**Probability**

I did the first two for the last two , you are dealing with conditional probability Prob( B given A) = prob(B|A) = prob(A and A)/prob(A)
*April 13, 2016*

**oops - Math**

ignore my previous answers, I totally forgot about the actual probabilities. so for prob(makes first misses seconds and third shots) = (7/10)(3/10)(3/10) = 63/1000 or .063 prob(missing all 3) = (3/10)^3 = 27/1000 so prob(of making at least one shot) = 1 - 27/1000 = 973/1000...
*April 13, 2016*

**Math**

h -- hit m -- miss she has the following cases: hhh hhm hmh mhh hmm * mhm mmh mmm "makes first misses seconds and third shots " --- I see one case, marked with * so prob(hmm) = 1/8 "Makes at least 1 shot" all except mmm so prob(of that event) = 1 - 1/8 = 7/8
*April 13, 2016*

**Math**

No common ratio, thus no geometric sequence however the 2nd, 3rd and 4th form the pattern: -(consecutive even)^2 but then the first term does not follow this pattern. I don't see anything else
*April 13, 2016*

**Trig**

You should memorize the trig ratios is terms of x, y and r so for the point (-1,3) x = -1, y = 3 and by Pythagoras, r = √10 cosθ = x/r = -1/√10 and since secθ = 1/cosθ secθ = -√10
*April 13, 2016*

**math**

There are 3 such multiples, 6,12, and 18 prob(of your event) = 3/18 = 1/6
*April 13, 2016*

**Math**

Are we answering only c) ? c) since there are only reds and whites, and you want prob(red OR white) the prob(red OR white) = 1 that is, 2/10 + 8/10 = 10/10 = 1
*April 13, 2016*

**Calculus Answer Confirming Not Sure Im Right Help?**

For the given substitution , the two statements: lim (∛x-4)/(x-64) , as x --->64 and lim (u - 4)/(u^3 - 64) , as u ---> 4 are equivalent, so lim (∛x-4)/(x-64) , as x --->64 = 1/48 and lim (u - 4)/(u^3 - 64) , as u ---> 4 = 48 They are equivalent ...
*April 12, 2016*

**Calculus Answer Confirming Not Sure Im Right Help?**

let ∛x = u then x = u^3 and as x---> 64, u ---> 4 lim (∛x-4)/(x-64) , as x --->64 = lim (u - 4)/(u^3 - 64) , as u ---> 4 = lim (u-4)((u-4)(u^2 + 4u + 16) , u -->4 = lim 1/(u^2 + 4u + 16), as u --> 4 = 1/(16 + 16 + 16) = 1/48 When you make your ...
*April 12, 2016*

**IMPORTIANT MATH**

let the width be x let the length be y, along the wall so 2x + y = 75 y = 75-2x area = xy = 600 x(75 - 2x) = 600 -2x^2 + 75x = 600 x^2 - 37.5x = -300 x^2 - 37.5x + 351.5625 = -300 + 351.5625 (x - 18.75)^2 = 51.5625 x - 18.75 = appr 7.18 x = appr 25.93 y = 23.139
*April 12, 2016*

**Math**

I ask myself, "how far from the x-axis is my given angle" After I decide which quadrants the given angle is in, I go in II: 180 - angle in III: angle - 180 in IV: 360 - angle e.g. for 330° , which is in IV reference angle = 360-330 = 30° ... for 203, which is...
*April 12, 2016*

**Math**

area of yard = (14x)(19x) = 266x^2 area of circle = π(36x^2) area of remaining yard = 266x^2 - 36πx^2 = (266-36π)x^2
*April 12, 2016*

**Math**

let the monthly rate be i 614( 1 - (1+i)^-48)/i = 24905 (1 - (1+i)^-48)/i = 40.56189 that's toughie to solve, I will use Wolfram https://www.wolframalpha.com/input/?i=solve+614(+1+-+(1%2Bx)%5E-48)%2Fx+%3D+24905 i = .00709 so the annual rate compounded monthly = 12(.00709...
*April 12, 2016*

**finance math**

not that simple let the monthly rate be i 614 (1 - (1+i)^-48)/i = 24905 very tough to solve I will let Wolfram do it https://www.wolframalpha.com/input/?i=sove+614+(1+-+(1%2Bx)%5E-48)%2Fx+%3D+24905 i= .00709283 12i = .08511... or 8.511% per annum compounded monthly
*April 12, 2016*

**algebra**

amt = 800(1.02^22 - 1)/.02 = ....
*April 12, 2016*

**Math question help!!**

Two interpretations are possible for this question. 1. There are 24 students in the class like you said. So if 1/3 are missing, then there are 8 missing, just like Ms Sue had in her previous post. 2. With 1/3 missing, there are 24 students in the class, so the 24 students ...
*April 12, 2016*