measured along the diagonals, so diagonal is twice as big
I will do the 1st one you do the 2nd method 1. check to see if it is right -angled, then it would be real easy is 3.5^ + 4.8^2 = 6.1^2 ? , NO --- so forget that method method 2: find the angle opposite the smallest side using the cosine law 3.5^2 = 4.8^2 + 6.1^2 - 2(4.8)(6.1)c...
You must have a typo If you want me to use the stated property, then you must have meant 9^(-x+15) = 27^x if as assumed, then (3^2)^(-x+15) = (3^3)^x 3^(-2x + 30) = 3^3x -2x + 30 = 3x , using your stated property -5x = -30 x = 6
You will also have to insert brackets to clarify the order of operation here e.g. I will do the 2nd one assuming you meant: 7√(2x) + 2√(72x^3( - √(162x^5) = 7√(2x) + 2√(2x) √(36x^2) - √(2x) √(81x^4) = 7√(2x) - 12x√(2x...
area of circle = π(7^2) = 49π prob of landing in circle = 49π/420 = 7π/60 = appr .3665 ignoring any leaves that fall partially either on the circle or the edge of the yard
GEOMETRY CIRCLES PLEASE
This is just too easy. Remember that both tangents to the same circle from an exterior point are equal. so AB = AC but AC is also tangent to the small circle so AC = AD but AD is also a tangent to the circle at the right so AD = AE Since the are all equal , and AB = 15 each on...
make a diagram showing a sideview. remember the angle of depression from the helicopter view is equal to the angle of elevation from groundview. So I have a right-angled triangle, with a height of 105 (opposite side), the adjacent side of x and an angle of 30.5 take it from there
first of all use the rules of logs y = ln (1 - x^2)^(1/2 = (1/2) ln (1 - x^2) now ... dy/dx = (1/2) (-2x)/(1-x^2) = -x/(1-x^2)
My interpretation of the wording first year = 47500 2nd year = 47500(1.23) third year = 47500(1.23)^2 fourth year = 47500(1.23)^2 (1.12) = .....
You have the same base, so (8^6/8^4)(8/2) = 8^(6-4+2) = 8^4