Friday

March 27, 2015

March 27, 2015

Total # Posts: 29,284

**Math**

The first thing I would do is get rid of the fractions The LCD is (x-1)(x+1) so let's multiply each term by that ... 5(x+1) + 2(x-1) = -6(x+1)(x-1) 5x + 5 + 2x - 2 = -6x^2 + 6 6x^2 + 7x - 3 = 0 (3x - 1)(2x + 3) = 0 x = 1/3 or x = -3/2 I won't even attempt to figure out...
*January 9, 2015*

**math**

You started by talking about a cylinder and suddenly you are talking about a cube. ????
*January 9, 2015*

**Math**

Oh my !!! How about factoring first and see where that gets you?
*January 9, 2015*

**math**

Bula --- x Jako --- 2x abdi --- 2x/3 Jane ---- (2/3)(2x = 4x/3 x+2x+2x/3+4x/3 = 108000 times 3 3x + 6x + 2x + 4x = 324000 15x = 324000 x = 21600
*January 9, 2015*

**Math**

7 ∑ (2i + 3) i = 1
*January 9, 2015*

**Algebra 1**

since x = 5 and y = 75, you have the point (5,75) If you are working with the above equations, then you have to be able to plot points on the x-y grid for (5,75), from the origin go 5 units to the right, then up 75 You might want to scale your graph, e.g. one space on the gird...
*January 9, 2015*

**Math**

that's what my calculator gave me
*January 9, 2015*

**math**

so you need 15(10) or 150 man-days to do the job so with 6 men you would need 150/6 or 25 days or use a ratio 15/6 = x/10 6x = 150 x = 25
*January 9, 2015*

**Math**

1 e^(3r) = 2 take ln of both sides 3r lne = ln2 , but lne = 1 3r = ln2 r = ln2/3 = .231.. So you will need a continuous rate of growth of 23.1 % good luck on that one.
*January 9, 2015*

**Math**

g(x)=(2x^2-7x+3)/(x-3) = (x-3)(2x-1)/(x-3) = 2x-1 , x ≠ 3 ≠ f(x)
*January 9, 2015*

**Marh**

just translate your English sentence into "Math" 5 + 8x = 60 + 3x easy to solve
*January 9, 2015*

**Math**

if f(x) = g(x), it must be true for all values of x (all we need is ONE exception and they would not be equal) f(1) = 6 + -11/5 = a fraction g(1) = 3-4 = -1 so f(x) is NOT the simplified form of g(x)
*January 9, 2015*

**Math**

(-9,-90°) this would point you clockwise 90° or 270° using the standard rotation. You would then go in the opposite direction for 9 units so equivalent to (9, 90°) (9,270°) would be the same as (9, -90°)
*January 9, 2015*

**Math**

I will put in the brackets for you, (you obviously ignored my comment about brackets from yesterday) (x^2-2x)/(x+1) * (x^2-1)/(x^2+x-6) = x(x-2)/(x+1) * (x-1)(x+1)/((x+3)(x-2)) you take over I see nice cancellations
*January 9, 2015*

**Math**

x/( (x-4)(x+1)) - 4/(x+1) LCD is (x-4)(x+1) = ( x - 4(x-4) )/((x-4)(x+1)) = (x - 4x + 16)/(x^2 - 3x - 4) = (16 - 3x)/(x^2 - 3x - 4) , x ≠ -1,4 btw, I recall Damon answering this same question for you yesterday
*January 9, 2015*

**Math**

7(cos 5pi/6 +isin 5pi/6) / -2(cos pi/2 +isin pi/2) = 7(-√3/2 + i/2) / (-2(0 + i)) = (7/2)( -√3 + i) / (-2i) * i/i = (7/2)(-√3i + i^2)/(-2i^2) = (7/2)(-1 - √3 i)/2 = (-7/4)(1 + √3 i) your 7 square root 3/4 i part is ambiguous, it needs brackets to ...
*January 9, 2015*

**Math**

Two concerns about your post: 1. For the first equation, did you mean 4x + 2y = 6 ? 2. This is clearly an assignment which will be marked, since you are showing how many points each answer is worth. We do not do a student's assignment for them. Show your steps and the area...
*January 9, 2015*

**Math**

I got -10i Did you get your answer by expanding -10((cos pi/3 +isin pi/3)(cos pi/6+ isin pi/6) ? my 2nd-last line was: -10( cos π/2 + i sin π/2)
*January 9, 2015*

**Math**

Steve answered this question for you yesterday. Always check back before re-posting the same problem.
*January 9, 2015*

**geometry honors**

To be a ||gm , opposite sides must be equal 7y-8 = 5y and 6x-3 = 3x+12 7y - 8 = 5y 2y = 8 y = 4 6x-3 = 3x+12 3x = 15 x = 5 Since the given information about x and y match those solutions, yes, it is a parallogram or just sub in the given values into the 4 different expressions...
*January 8, 2015*

**Math**

nothing to simplify did you mean (e^27)x or e^(27x) the first one is appr 5.32 x 10^11 x the other one stays as is
*January 8, 2015*

**Ap calc**

You will need brackets y= (e^x - e^-x) / (e^x + e^-x) wonder what would happen if we multiply top and bottom by e^x = y= (e^x - e^-x) / (e^x + e^-x) * (e^x/e^x) = (e^2x - 1)/(e^2x + 1) now dy/dx = ( (e^2x + 1)(2e^2x) - (e^2x - 1)(2e^2x) )/(e^2x + 1)^2 = (2e^4x + 2e^2x - 2e^2x...
*January 8, 2015*

**math**

wouldn't there now be 6 white balls left out of the remaining 19 ? so ....
*January 8, 2015*

**math**

make sure you type or enter (-5)^6 your expression of -5^6 = - 15625 according to the order of operations.
*January 8, 2015*

**Math**

The point (5,-2) lies in the 4th quadrant. So plot it and complete the right-angled triangle (draw a vertical to the x-axis) so x = 5, y = -2 , r = √(25 + 4) = √29 we know sinØ = -2/√29 then cscØ = -√29/2
*January 8, 2015*

**Note to Alex - Math**

Alex, yesterday I pointed out to you how important it is to include brackets in this format of typing your questions. http://www.jiskha.com/display.cgi?id=1420682753 You have ignored this and continue to type in this ambiguous way for your previous set of questions. Are you ...
*January 8, 2015*

**math**

sketch y = x^3 then reflect the part which is below the x-axis about the x-axis http://www.wolframalpha.com/input/?i=plot+y+%3D+%7Cx%7C%5E3
*January 8, 2015*

**Math**

h(t) = -16t^2 + 96t + 60 v(t) = -32t + 96 at max height , v = 0 -32t + 96=0 32t = 96 t = 96/32 = 3 h(3) = -16(9) + 96(3) + 60 = 204 or h(t) = -16(t^2 - 6t + 9-9) + 60 = -16( (t-3)^2 - 9) + 60 = -16(t-3)^2 + 144 + 60 = -16(t-3)^2 + 204 this has a vertex of (3,204) thus a max of...
*January 8, 2015*

**College Algebra**

So I will use two variables in the solution let the amount of 10% solution used be x cc let the amount of 5% solution be y cc "A pharmacist wants to mix two solutions to obtain 100 cc" ---> x + y = 100 the new solution must contain 8% , so .08(100) 2nd equation: ....
*January 7, 2015*

**math**

Thanks for the correction , Steve
*January 7, 2015*

**math**

let the smaller angle be x° then the larger is 7x + 10 but ... x + 7x + 10 = 180 take over
*January 7, 2015*

**Math 10 aw**

let that distance be h , (the hypotenuse) I see it as sin18° = 125/h h = 125/sin18 = ...
*January 7, 2015*

**Math**

You must know that for any linear equation written in the form y = mx + b the slope is m and the y-intercept is b so, what do you think?
*January 7, 2015*

**sixth grade math**

you are welcome
*January 7, 2015*

**sixth grade math**

There are 24 seats open in a theatre, shown as 3 rows. How many seats are there in each of the three rows. let the number of seats be y 24/y = 3 y = 8
*January 7, 2015*

**Math**

The largest quotient can be obtained when the numerator is largest and the denominator is smallest so since in x/y, x goes from 10 to 20 and y goes from .2 to 5 the largest quotient is 20/.2 which is 100 the farthest vertex would be (-x,y) , the others would be (-x,0) , (0,y) ...
*January 7, 2015*

**Math**

PV = 12000(1 + .09/12)^-72 = 12000(1.0075)^-72 = $7007.08
*January 7, 2015*

**Math**

Why not type x divided by x^2-3x-4 subtracted by 4 divided by x +1 as x/(x^2 -3x - 4) - 4/(x+1) then = x/( (x+1)(x-4) - 4/(x+1) now your common denominator is (x+1)(x-4) take over
*January 7, 2015*

**Math**

As you typed it ... 1 + 2x/x+4=3/x-1 1 + 2 + 4 = 3/x - 1 8 = 3/x 8x = 3 x = 3/8 I will assume you meant: 1 + 2x/(x+4) = 3/(x-1) multiply each term by (x+4)(x-1) (x+4)(x-1) + 2x(x-1) = 3(x+4) x^2 + 3x - 4 + 2x^2 - 2x = 3x + 12 3x^2 - 2x - 16 = 0 (3x - 8)(x + 2) = 0 x = 8/3 or x...
*January 7, 2015*

**Math**

for any function y = sin (kx) or cos (kx) the period is 2π/k so for yours the period = 2π/(1/7) = ...... I think you just guessed at 2π, because it makes no sense otherwise.
*January 7, 2015*

**math**

recall that when dividing by a fraction we multiply by its reciprocal y/4 ÷ 1/4 = (y/4)(4/1) = y
*January 7, 2015*

**math**

is there a question ?
*January 7, 2015*

**Algebra**

Easiest way to graph a straight line on a grid is to find their x and y intercepts. for this one: let x = 0 , then y = 2 let y = 0 , then x = 2/3 you now have two points (0,2) and (2/3 , 0) plot them , join them and you are done
*January 6, 2015*

**Math**

I will try to explain with an example Suppose you have the product (4x5x6) which would be 120 So if we double that we would get 2 x (4x5x6) or 240 Would we multiply the 2 by each of the factors of the original product ? Of course not. We would multiply by only one of the ...
*January 6, 2015*

**math**

reduce the ratio: 2.8 : 1.25 = 280 : 125 = 56 : 25 let the ratio of the ribbons be 56x : 25x "The difference in the length of the shorter pieces is 80.6 cm. " This makes no sense, I will assume you meant that the difference in the length of the two pieces is 80.6 56x...
*January 6, 2015*

**algebra**

use this probability calculator instead of tables Just enter the date, and click on the greater than option http://davidmlane.com/hyperstat/z_table.html you should get .0228
*January 6, 2015*

**Math**

wouldn't you you just set 25t - 80 = 60 and solve ? looks pretty straighforward
*January 6, 2015*

**college pre-calculus**

For any polynomial equation with rational coefficients, complex roots must occur as conjugate pairts, that is, if one root is 1+i, there has to be another one 1 - i so, including the root of -1, the equation could have been (x+1)(x - (1+i) )(x - (1-i) ) = 0 (x+1)(x-1-i)(x-1+i...
*January 6, 2015*

**math**

r^2 = 200^2 + 50^2 = 42500 r = √42500 = 50√17 tanØ = -50/200 = -1/4 Ø = 165.96° so using the (r,Ø) notation , her position is (50√17, 165.96°)
*January 5, 2015*

**Math**

e(x + 1) + e(x - 4) = ex + e + ex - 4e = 2ex - 3e or = e(2x-3)
*January 5, 2015*

**Math**

All kinds of missing information: - how much more each month does he deposit ? - are the increases each month the same amount? - does he not get any interest in his savings account? (if not, he might as well put each month's deposit in a sock under his bed, at least he won...
*January 5, 2015*

**math**

This looks like silly math pedagogy to me. For heaven's sake : just learn and memorize the 6 times table
*January 5, 2015*

**Math**

L#L-##LL ---> 25x10x25x10x10x25 =
*January 5, 2015*

**Math**

Not familiar with this notation and the ( or [ are confusing. In the "good ol' days" way: domain: any real number range : y ≤ 0 I will leave it up to you to identify the matching answer
*January 5, 2015*

**Mathematics**

There is really no need to have brackets on the RS but I would mentally look at it as (2x)(y^2) so the product rule is more obvious so ..... 3/(3x) + (dy/dx)/y = (2x)(2y dy/dx) + (y^2)(2) multiply each term by y y/x + dy/dx = 4xy^2 dy/dx + 2y^3 dy/dx - 4xy^2 dy/dx = 2y^3 - y/x...
*January 5, 2015*

**Mathematics**

I have now shown you how to do several of these kind of derivatives. It is time for you to show us some of your own efforts. What have you got so far ?
*January 5, 2015*

**Mathematics**

recall that the basic log derivatives apply to logs with base e then let y = log5 ((2x+1)/(3x-1)) = log5 (2x+1) - log5 (3x-1) dy/dx = (1/ln5)(2/(2x+1)) - (1/ln5)(3/(3x-1)) = (1/ln5) (2/(2x+1) - 3/(3x-1) )
*January 5, 2015*

**Math**

Did this one yesterday. make sure the points are the same http://www.jiskha.com/display.cgi?id=1420371208
*January 5, 2015*

**Mathematics**

y' = 2(sin 4x cos 3x)( sin4x(3)(-sin3x)) + cos3x(4)cos4x))
*January 5, 2015*

**Mathematics**

That was clearly a typo, good for you to catch it
*January 5, 2015*

**Mathematics**

or y = x^3/cosx y' = (cosx(3x^2) - x^3(-sinx))/cos^2x = (3x^2 cosx + x^3 sinx)/cos^2x now do it again
*January 5, 2015*

**Mathematics**

I assume you differentiating with respect to x ? 3x^2 = y(-sinx) + dy/dx(cosx) dy/dx = 3x^2 + ysinx d(dy/dx)/dx = 6x + dy/dx sinx + ycosx = 6x + (3x^2 + ysinx)sinx + ycosx = 6x^2 + 3x^2sinx + ysin^2 x + ycosx check my work, should have written it on paper first
*January 5, 2015*

**math**

multiply 1st by 3 9x - 3y = 0 4x + 3y = 26 add them: 13x = 26 x = 2 back into original #1 3(2) - y = 0 -y = -6 y = 6 x = 2, y = 6
*January 5, 2015*

**business math**

amount = 3000( 1 + .06/12)^12 = 3185.03 Didn't know tables were still being used in this topic.
*January 5, 2015*

**math,trigonometry**

I just did this one: http://www.jiskha.com/display.cgi?id=1420462410 for #2. using the sine law: sinB/7 = sin88/8 sinB = 7sin88/8 = .8744... angle B = 60.98° or angle B = 119.18° using the CAST rule case1: B = 60.98, A = 88 , then C = 180-88-60.98 = 31.02° or to ...
*January 5, 2015*

**math, solving Oblique triangle**

Notice one of the fractions is a constant, so use b/sin49 = 10/sin16 b = 10sin49/sin16 you should get appr 27.38 then c/sin115 = 10/sin16 c = 10sin115/sin16 = 32.88
*January 5, 2015*

**algebra**

So what is 9 x 8 ?
*January 5, 2015*

**math/ ratio**

ban : pine : pap = 21 : 15 : 9 = 7 : 5 : 3
*January 5, 2015*

**Mathematics**

use your rules of logs to simplify this messy expression I will assume you meant: y = ln [ (2x-1)/(1+x) ]^(1/2) = (1/2)( ln(2x-1) - ln(1+x) ) dy/dx = (1/2)( 2/(2x-1) - 1/(1+x) ) = 1/(2x-1) - 1/(2(1+x))
*January 5, 2015*

**Algebra I**

number of adult tickets --- x number of student tickets -- y x + y = 64 2.5x + y = 109 subtract the two equations to get x = ... then sub back into the first equation to get y
*January 4, 2015*

**Pre-Calc**

John, I don't know how you got 63 when t=5 I got 44.48 when t = 5 We could have used a sine curve height = 30sin ((πt/8)(t-4) ) +33 check: when t = 0 , height = 3 , ok when t = 8 , height = 63, ok when t = 4, height = 4.48 , the same result we get when we use Steve&#...
*January 4, 2015*

**Math**

Cherie, You are using decimals and rounding off your answer before you are substituting. look at Quidditch's last line 2.8x = 60 x = 60/2.8 = 600/28 = 150/7 or 21 3/7 now y = 10 - 2.2(150/7) = 10 - (22/10)(150/7) = 10 - 330/7 = -260/7 or -37 1/7 since "anything"/...
*January 4, 2015*

**maths**

dy/dx = 6x^2 - x - 1 = 0 at the turning points (3x + 1)(2x - 1) = 0 x = -1/3 or x = 1/2 sub those values into original equation to get the whole points y'' = 12x-1 when x = -1/3, y'' is negative, so x = -1/3 will yield a maximum point when x = 1/2 , y''...
*January 4, 2015*

**maths**

dy/dx = 8x so at (2,21) , the slope is 16 y - 21 = 16(x-2) etc
*January 4, 2015*

**math**

a + 8d = 52 (12/2)(2a + 11d) = 414 or 2a + 11d = 69 solve these two equations for a and d
*January 4, 2015*

**Analytical Geometry**

looks like plain ol' Pythagoras base^2 + 8^2 = 10^2 bse^2 = 100-64 = 36 base = √36 = 6 slope = rise/run = height/base = 8/6 = 4/3 Make a sketch of the situation Place the 6-ft man on the base 3 ft from the base. Is he below the ladder or did his head hit the ladder? ...
*January 4, 2015*

**math**

I can't see your diagram, but the diagonal of the square from (4,1) to (5,8) is also the diameter of the circle length = √(1^2 + 7^2) = √50 = 5√2 so the radius of the circle must be 2.5√2 perimeter of circle = 2πr or dπ = √50π...
*January 4, 2015*

**Math**

mmmh, diagonals in a triangle ? Label your given points A, B, and C in the corresponding order. Clearly AB is a horizontal line, thus AB = 8 AC = √(1^2 + 9^2) = √82 BC = √(7^2 + 9^2) = √130 perimeter = 8 + √82 + √130 = appr 28.5
*January 4, 2015*

**math**

the number is 10y + x 10y + x = 9(x+y) 10y + x =9x + 9y y - 8x = 0 or y = 8x since both x and y must be ≤ 9, the only choice for x = 1 so y = 8 and the number must be 81
*January 4, 2015*

**maths**

100000 = 3000( 1 - 1.0041666...^-n)/.0041666.. .3888.. = 1 - 1.0041666..^- 1.0041666..^-n = .61111.. take log of both sides and use log rules - n = log .61111../log 1.0041666.. -n = - 118.44 n = 118.44 So there are 118 full payments of 3000 plus another partial payment at ...
*January 4, 2015*

**Maths**

done, see the two previous posts of the same question.
*January 4, 2015*

**Maths**

net price = (200)(.9)(.95)(.98)(.95) = 159.20
*January 4, 2015*

**Maths**

Always check back to see if your previous post of the same question has been answered before reposting it. http://www.jiskha.com/display.cgi?id=1420301789 This will prevent unnecessary duplication.
*January 4, 2015*

**ALGEBRA**

i = .03/12 =.0025 n = 12(20) = 240 amount = 200 ( 1.0025^240 - 1)/.0025 = .....
*January 3, 2015*

**Math - Please help**

slope of given line is 4 since the new line is parallel, its slope must also be 4 let y = 4x + b using the point (1,-3) -3 = 4(1) + b -7 = b new equation in slope-intercept form is y = 4x - 7
*January 3, 2015*

**Maths**

You need one more piece of information. The way it stands ar^2 = 7 r^2 = 7/a r = ±√(7/a)
*January 3, 2015*

**ALGEBRA**

You have to know the formulas for the general term and the sum of n terms of an arithmetic sequence term6 = a + 5d = 48 sum6 = (6/2)(2a + 5d) = 300 3(2a + 5d) = 300 2a + 5d = 100 subtract the two two equations: a = 52 back in a+5d = 48 52+5d = 48 5d = -4 d = -4/5 so the first ...
*January 3, 2015*

**math**

yup, there are lots of them let Google be your friend
*January 3, 2015*

**trig**

In other words.... we have to prove that 2sinxcosx + 4cos^2 x - 1 = tan^2 x - 2tanx - 3 I had my doubts about this "identity" so I tried any arbitrary value of x (remember , all we need is ONE exception and the identity is not true) I tried x = 21° LS = 2sin21 ...
*January 3, 2015*

**calculus**

use the product rule .. dy/dx = x^3 (5/5) + 3x^2 ln(5x) = x^2 + 3x^2 ln(5x) or = x^2(1 + 3ln(5x) )
*January 3, 2015*

**^NeEd HeLp^**

What language are you using? The majority of questions posted here are in English.
*January 3, 2015*

**Algebra 1**

Since both equations were in the form y = ... he simply replaced the y value of the first equation with the y value of the second. Some texts call this the "comparison" method e.g. if a = b and c = b , then a = c yes, you could use elimination after some doctoring of...
*January 3, 2015*

**trigonometry**

I see a right-angled triangle with hypotenuse of 60 and a base angle of 52° sin52 = y/60 --> y = 60sin52 = ... cos52 = x/60 ---> x = 60cos52 = ...
*January 3, 2015*

**AP CaLC. AB**

if v(t) = t^2 - 3cos(t) then s(t) = (1/3)t^3 - 3sin(t) + c given : when t = 0 , s(0) = 0 0 = 0 - 3sin0 + c c = 0 so when v = 0 0 = t^2 - 3cos(t) using Wolfram, I got t = 1.13062 where does x enter the picture, your function was defined in terms of t http://www.wolframalpha.com...
*January 3, 2015*

**retype - calculus**

Let me type this again in proper English. (Can I blame it on my keyboard ? ) Clearly the vertex of this parabola is (-2,-4) and it opens downwards. Thus it cannot possible reach the x-axis, thus there are no x-intercepts for the y-intercept, in you let let x = 0 and evaluate ...
*January 3, 2015*

**calculus**

clearly the vertex of this parabola is (-2,-4) and it opens downwards. This is cannot possible reach the x-axis, thus no x-intercepts for the y-intercepts, in you head let x = 0 and evaluated to get y = -4-4 = -8
*January 3, 2015*

**Calculus**

h ' (x) = 3x^2 + b = 0 at a critical point if (2,-4) is a critical point, 3(4) + b = 0 b = -12 but (2,-4) also satisfies h(x) -4 = 8 - 12(2) + c c = 12 thus h(x) = x^3 - 12x + 12
*January 2, 2015*

**Statistic**

for test1 prob correct = 1/4 prob wrong = 3/4 i) could be c or wc or wcc , (c for correct, w for wrong) prof (of that) = 1/4 + (3/4)(1/4) + (3/4)^2 (1/4 = 37/64 ii) less than 4 correct ---> none correct + 1 correct + 2 correct + 3 correct = C(8,0) (1/4)^0 (3/4)^8 + C(8,1)(1...
*January 2, 2015*

**Physics 1**

v = -9.8 t so when t = 10 s v = -9.8(10) = -98 m/s The negative indicates the direction of the stone.
*January 1, 2015*

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