Saturday

April 25, 2015

April 25, 2015

Total # Posts: 29,683

**trigonometry pls help**

According to my sketch, sinØ = 28/32 Ø = ... I assume you have a calculator
*April 25, 2015*

**trigonometry pls help**

You don't state where Ø is, I will assume it is one of the two equal angles at the base. a) tan 45 = height/18 height = 18tan45 = 18 b) repeat with tan 55 = height/18 c) since area = (1/2)(36)(height) the larger the height, the larger the area. you do the calculations.
*April 25, 2015*

**math**

2cos^2 Ø - sinØ -1=0 2(1-sin^2 Ø) - sinØ - 1 = 0 -2sin^2 Ø - sinØ +1 = 0 2sin^2 Ø + sinØ - 1 = 0 (2sinØ + 1)(sinØ - 1) = 0 sinØ = -1/2 or sinØ = 1 case1: sinØ = -1/2 Ø must be in ...
*April 25, 2015*

**math**

At the start: number of fives ---- 4x number of tens ----- 3x $140 in fives = 28 notes so he has 4x-28 of the fives left over he also spent 2/5 of his tens, so he has 3/5 of the tens left or he has 3/5(3x) or 9x/5 tens left over (4x-28)/( (9x/5)) = 2/3 12x - 84 = 18x/5 60x - ...
*April 25, 2015*

**math**

There are actually 4 solutions, from Jai's: tanØ = 1/2 so by the CAST rule, Ø is in either the first or the third quadrant Ø = 26.6° ---- Jai's answer Ø = 180+26.6= 206.6° if tanØ = 1 Ø = 45° , ----- again, Jai'...
*April 25, 2015*

**Math**

1. 78.5° would be the answer if the angle had been acute, but you wanted the angle in the 4th quadrant so Ø = 360 - 78.463 = 281.5° check by taking cos 281.5° 2. Again you want -90 ≤ Ø ≤ 90, which would be quadrant I or quadrant IV but for...
*April 25, 2015*

**Math**

From the equation I can tell that Diane started with $450 , (x=0) and her account increased by $30 per week
*April 24, 2015*

**6th Grade Math Help Please**

A rational number is a number which can be expressed exactly as a fraction or a ratio. so your coordinates would NOT contain any square roots.
*April 24, 2015*

**algebra 2**

yup, correct again (instead of 30x2power we can type 30x^2 on here)
*April 24, 2015*

**algebra 2**

I agree, good job
*April 24, 2015*

**Interest**

what is 10000(1.015)^4 ??
*April 24, 2015*

**maths**

In effect for each jump , he gains 1 foot. after 1 jump, he is 39 feet from the top after 2 jumps he is 38 feet from the top ... after 10 jumps he is 30 feet from the top .... after 37 jumps he is 3 feet from the top So on the 38th jump he is at the top, and we will assume he ...
*April 24, 2015*

**math**

9th term = a+8d = 12 17th term= a+16d = 28 subtract them 8d = 16 d = 2 sub into a+8d = 12 a = -4 4th term = a+3d = -4 + 6 = 2
*April 24, 2015*

**Algebra**

let the time passed since Chelsea left be t hrs So Chelsea went for t hrs Sarah went for t+1 hrs When they meet, they both have covered the same distance, so 75t = 55(t+1) 75t = 55t + 55 20t = 55 t = 55/20 or 2.75 hrs Chelsea went for 2.75 hrs of 2 hrs and 45 minutes Sarah ...
*April 24, 2015*

**Math**

4 S's 2 P's 4 I's number of permutations = 11!/(4!4!2!) = 34650
*April 24, 2015*

**Algebra**

I really don't know where Steve got his numbers from. Making a sketch I have a triangle with sides 165 and 80 and an angle of 65° between them, so by the cosine law x^2 = 80^2 + 165^2 - 2(80)(165)cos 65° = 22467.87789 x = appr 149.9 miles Using vectors we have (...
*April 24, 2015*

**math**

no After taking out any two, you could have the following cases: R W B 4 4 2 4 2 4 2 4 4 3 3 4 3 4 3 4 3 3 let's take the 3 3 4 situation prob of that having happened = C(4,1)xC(4,1)xC(4,0)/C(12,2) = 16/66 = 8/33 The other two cases of choosing 2 different colours = 8/33 ...
*April 24, 2015*

**7th grade math**

It says to find the equivalent equation containing no fractions. It did not ask to find the solution, so (2/3)x - 1 = 1/2 multiply each term by 6 , the LCD 6(2/3)x - 6(1) = 6(1/2) 4x - 6 = 3 which is choice A
*April 23, 2015*

**Analytic Geometry**

make a sketch label the intersection withe the y-axis as (0,y) I have two similar triangles and by ratios (6-y)/3 = (6+y)/6 18+3y = 36-6y 9y=18 y=2 so the sides of the smaller right-angled triangle are 3 and 4, and I recognize the 3, 4, 5 triangle the other triangle is 6 , 8, ...
*April 23, 2015*

**Math**

slope = (4-(-3))/(4-2) = 7/2
*April 22, 2015*

**math**

The wording is too nebulous. Are the balls numbered from 1 to 75 ? Are you just asking , "What is the probability of picking a 7, then a 14 , and then a 21 ? That is very straight-forward? Once you have that probability, multiply it by 500.00
*April 22, 2015*

**math**

ok, how about you trying some of these. They are rather simple probability question and you should be able to do them. Where are you having your difficulty?
*April 22, 2015*

**math**

prob(2reds) = (8/14)(7/13) = ..
*April 22, 2015*

**math**

prob(red, then yellow) = (8/14)(6/13_ = ...
*April 22, 2015*

**Algebra IMPORTANT**

I see 5 terms, not 3. You will need brackets to identify the terms
*April 21, 2015*

**Math**

2 errors error #1 : -1 - (-4) = -1 + 4 = 3 So review your subtraction of integers 2nd error: you can't switch direction in your subtraction your points where (-1,-4) and (0,-1) You started by subtracting the first y from the second y, and then you subracted the second x ...
*April 21, 2015*

**Math**

Did you not follow the method I showed you for the same kind of question in your previous post?? Are you just guessing at an answer, hoping some somebody will do it for you correctly? How did you arrive at the answer A ?
*April 21, 2015*

**Math**

let's take the first pair: (0,-4) and (1,-3) : slope = (-3-(-4))/(1-0) = 1/1 = 1 (I guess C is wrong) second pair: (1,-3) and (2, -2): slope = (-2+3)/2-1) = 1 mmmhhh? third pair: (2,-2) and (3,-1) = (-1+2)/(3-2) = 1 well, now, what do you think??
*April 21, 2015*

**Algebra-VERY IMPORTANT**

we need 2 values which have a sum of 10 how about 6 and 4 x^2 + 10x + 24 = (x+6)(x+4) , k = 24 how about 2 and 8 x^2 + 10x + 16 = (x+2)(x+8) , k = 16 how about -12 and 22 x^2 + 10x - 264 = (x+22)(x-12) , k = -264 etc. an infinite number of different values of k are possible
*April 21, 2015*

**math**

Assuming the same rate and the same time: amount/5800 = 720/4500 amount = 5800(720/4500) = 928
*April 21, 2015*

**Math**

To be a GS , any number divided by its previous one must produce the same result first pair: -6/9 = -2/3 2nd pair: 4/-6 = -2/3 3rd pair: -8/3 /4 = -2/3 yes!, common ratio is -2/3 you do the 2nd problem.
*April 21, 2015*

**Math**

The scale factor is 1 : 64 , not 1 : 64 inches, ratios don't have units It means that 1 inch in the model is 64 inches in reality 1 foot in the model is 64 feet in reality 1 metre in the mode is 64 metres in reality etc x feet in the mode is 20 feet in reality x/1 = 20/64 ...
*April 21, 2015*

**geometry**

-2 √15 / (6- √13) = -2 √15 / (6- √13) * (6+√13)/(6+√13) = (-12√15 - 2√195)/(36-13) = -(12√15 + 2√195)/23
*April 21, 2015*

**Math**

"the rule is add 4, subtract 1" ---> in effect is adding 3 term(n) = 5 + 3n so term(10) = 5 + 3(10) = 35 Emma is correct
*April 21, 2015*

**calc**

in general the inverse of a b c d is 1/(ad - bc) times d -b -c a e.g. 5 4 2 2 inverse is 1/(10-8) times 2 -4 -2 5 = 1 -2 -1 2.5 Apply this rule to your matrix
*April 21, 2015*

**calc**

We can only take inverses of square matrices. I see 2 numbers in the first row, but 3 in the second row. Are there supposed to be brackets? Is it i 3 (1+i) - i ??
*April 21, 2015*

**math**

let the height be h cm so 2(7h) + 2(5h) + 2(5)(7) = 4.65 cm^2 14h + 10h + 70 = 4.65 24h = negative this question is bogus, once you realize that the area of the base alone would be 35 cm^2, without even considering the other surfaces. How can the total be only 4.65 cm^2
*April 21, 2015*

**MATH**

total cost = 1.05(875) = 918.75 so you made 7 payments of 100, leaving you with a balance of 218.75 when the 8th payment is due Penalty is 39 + .1425(218.75) = 70.17 Your wording does not make it clear, on what amount the 14.25% interest is charged. I assumed it would ...
*April 21, 2015*

**Math**

Since the time is less than one year, I will use simple interest. R = I/(PT) = 685.13/(6300(270/365)) = appr .147 or appr 14.7% None of your answers match this, but my calculations are correct
*April 21, 2015*

**Math**

i = .16/4 = .04 n = 4(2) = 8 amount = 2500(1.04)^8 =3421.42 your textbook still has tables??? how old is this?
*April 21, 2015*

**math**

"without the use of tables" ?? - then how about just using a calculator ? ( I am being facetious) Here is the method I actually taught in medieval times, and remember we had no calculators either. http://www.johnkerl.org/doc/square-root.html
*April 21, 2015*

**Math Help**

r = (1/16)/(1/32) = 2 term(12) = a r^11 = (1/32) (2)^11 = (1/32)(2048 = 64
*April 21, 2015*

**Math**

a+3d = 27 a+6d = 64 subtract them 3d = 37 d = 37/3 a + 3(37/3) = 27 a = -10 term(9) = a+8d = -10 + 8(37/3) = 266/3 check: term(4) = a+3d = -10 + 3(37/3) = 27 term(7) = a+6d = -10 + 6(37/3) = 64
*April 21, 2015*

**Maths, functions**

At ground level, h = 0 1+15t-4.9t^2 = 0 4.9t^2 - 15t - 1 = 0 Solve using the quadratic equation, using only the positive solution.
*April 21, 2015*

**algebra**

width ---- x length ----y 2x + 2y = 124 x+y=62 y = 62-x xy = 912 x(62-x) = 912 62x - x^2 - 912 = 0 x^2 - 62x + 912 = 0 (x-24)(x-38) = 0 x = 24 or x = 38, then y = 38 or y = 24 the doormat is 24 by 38
*April 20, 2015*

**Maths**

Samuel K. Simultaneous ?
*April 20, 2015*

**college algebra**

amount of 14% solution --- x amount of 6% solution ----- 28-x solve for x: .14x + .07(28-x) = .08(28) I suggest multiplying each term by 100 to get rid of those pesky decimals
*April 20, 2015*

**Calculus**

Let's see what this looks like https://www.wolframalpha.com/input/?i=plot+y+%3D++%28e%5E-x%29%28sin%28x%29%29 f ' (x) = e^-x(cosx) - sinx (e^-x) = 0 for max/min e^-x(cosx - sinx)=0 e^-x = 0 ---> not possible or cosx = sinx tanx = 1 x = pi/4 or -3pi/4 sub that back ...
*April 20, 2015*

**Math**

we were given that t = 4 so we had to "freeze" the situation at t = 4 That gave us tan O = 4/25 so we have a right-angled triangle with opposite 4 and adjacent 25. Since we need the secant of that angle and secant = 1/cosine , and cosine = adjacent/hypotenuse, so...
*April 20, 2015*

**Math**

let the angle be Ø, so we have tanØ = h/400 h = 400 tanØ dh/dt = 400 sec^2 Ø dØ/dt but dh/dt = 8t 400 sec^2 Ø dØ/dt = 8t dØ/dt = t/(50sec^2 Ø) so for the given case of t = 4 h = 4(4^2) = 64 tanØ = 64/400 = 4...
*April 20, 2015*

**Math**

y = (e^x + x)^x I would take ln of both sides ln y = x ln(e^x + x) now use the product rule (dy/dx)/x = x(e^x + 1) + ln(e^x + 1) dy/dx = y(x(e^x + 1) + ln(e^x + 1)) I don't know what kind of simplification you need , but you could sub back the original y value dy/dx = ( (e...
*April 20, 2015*

**Trig**

According to my sketch , we have a cosine law problem x^2 = 140^2 +60^2 - 2(60)(140)cos 110° = ...
*April 20, 2015*

**Calculus**

Here was my first answer http://www.jiskha.com/display.cgi?id=1429478661 In a subsequent reply you said you were confused. Now you simply repost the same question for a third time. Exactly what did you not understand in my answer?
*April 19, 2015*

**Math**

let original piece of material be x by x inches after cut-out, the base will be x-4 by x-4 and the height will be 2 so 2(x-4)^2 = 72 (x-4)^2 = 36 take √ of both sides x - 4 = 6 x = 10 the original piece was 10 by 10 inches
*April 19, 2015*

**Math 10**

I see a common factor of 12xy so ....
*April 19, 2015*

**Calculus**

look back before reposting
*April 19, 2015*

**Pre-Calculus**

Hasn't the boat effectively traveled 9 km north and 8 km west? Don't you have a right-angled triangle with sides 8 and 9 and we have to find the hypotenuse ? Go for it, don't go to decimals btw, I get √145, which cannot be written as a mixed radical
*April 19, 2015*

**7th grade math**

I did not answer your question the first time you posted it, since it looks like an obvious "homework dump" The first 4 questions simply require that you sub in the values and test. #5, what happened to the x and to the y value of the original point? -looks like 4 ...
*April 19, 2015*

**Math**

Easiest way is to use 2 variables let x be the speed of the boat in still water let y be the speed of the current so going downstream the boat is going x+y mph going against the current it is x-y mph now use your formula, we need t = d/r time upstream = 40/(x-y) time ...
*April 19, 2015*

**Vectors**

A point on the line is (-3,-1,-2) and the direction of the line is [-2,5,4] To find the equation of a plane I need another direction vector, using the point (-3,-1,-2) and the other point P(1,3,0) , I get [-4, -4, -2] or we could simply use [2,2,1] since you want the vector ...
*April 19, 2015*

**math**

did you make your sketch?? If you follow the standard definition of "bearing", I see it as a cosine law problem solve: x^2 = 5^2 + 10^2 - 2(5)(10)cos 150° ....
*April 19, 2015*

**geometry**

I can't follow your description
*April 19, 2015*

**Calculus**

I would start by sketching it http://www.wolframalpha.com/input/?i=plot+y+%3D+1+%2B+sin%282x%29%2C+y+%3D+e%5E%28x%2F2%29 So now for the hard part of finding their intersection. The left one is obviously (0,1) How do they expect you to solve 1 + sin(2x) = e^(x/2) ??, Have you ...
*April 19, 2015*

**Trig**

I will do it in parts for easier typing sinØ + cscØ = sinØ + 1/cosØ = (sinØcosØ + 1)/cosØ tanØ + cotØ = sinØ/cosØ + cosØ/sinØ = (sin^2 Ø + cos^ Ø)/sinØcosØ = ...
*April 19, 2015*

**Precalculus Trig (Geometry)**

So if you place the ellipse with centre at (0,0), we have a=19 and b = 13 , and the equation would be x^2/19^2 + y^2/13^2 = 1 or x^2/361 + Y62/169 = 1 Now if x = 5 25/361 + y^2/169 = 1 y^2/169 = 336/361 y^2 = 157.296... y = 12.54 adding on the 60 m it would be 72.54 m high. ...
*April 19, 2015*

**Precalculus Trig (Geometry)**

I would sketch a parabola with vertex at (0,20) opening downwards, and crossing the x-axis at (10,0) and (-10,0) then in vertex form the equation would be y = a(x-0)^2 + 20 = ax^2 + 20 but (10,0) lies on it, so 0 = a(100) + 20 x = -20/100 = -1/5 so we have y = (-1/5)x^2 + 20 ...
*April 19, 2015*

**calc**

wow http://www.wolframalpha.com/input/?i=integrate+5%2F%28t%5E3+%2B3%29 What methods have you been taught?
*April 19, 2015*

**Finance**

solve for n 3500(1.038)^n = 7000 1.035^n = 2 log both sides, and use log rules n log 1.035 = log 2 n = log 2/log 1.035 = appr 20.15 years
*April 19, 2015*

**algebra**

40000(.9)^n < 25000 .9^n < .625 take log of both sides and use log rules n log .9 < log .625 n < 4.46 yrs testing: 40000(.8)^4.5 = 24,897.24 40000(.9)^4 = 26244 4000(.9)^5 = 23619.60 So, I would say in 4 1/2 years
*April 19, 2015*

**math**

Now: son's age --- x Norman's age --- 4x Three years ago: son ---- x-3 Norman --- 4x-3 so x-3 + 4x-3 = 49 5x = 55 x = 11 the son is now 11 and Norman is 44 check: 3 years ago, son was 8 and Norman was 41 what is 41 + 8 ??
*April 19, 2015*

**calculate the area of plane figures**

I assume you want the area between. you need their intersection: x^2 = 8-x^2 ... x = ± 2 we can use symmetry and just go from 0 to 2 effective height = top curve - bottom curve = 8-x^2 - x^2 = 8 - 2x^2 integrate, and evaluate from 0 to 2
*April 19, 2015*

**math**

a) how many red or white balls are there ? b) how many yellow or reds are there ? c) how many non-reds are there ? How many balls are there in the bag in total? Well ??
*April 19, 2015*

**Maths- Please help**

Switch to the same units, metres. - good thing we are in metric diameter = 500 mm = 50 cm = .5 m so radius = .25 m height = 10 cm = .1 m volume of flywheel = π r^2 h = π(.25)^2 (.1) = .00625π m^3 mass = 750(.00625π) kg = appr 147.26 kg
*April 19, 2015*

**Math**

x/15 + x/10 = 1 multiply by 150 10x + 15x = 150 etc
*April 19, 2015*

**Math**

prob(Saturday) = 1/7 prob(not Saturday) = 6/7 a) prob(as stated) = C(15,4) (1/7)^4 (6/7)^11 = appr .1043 b) prob(at least 2 Saturdays) ---> 1 - (no Saturday + 1 Saturday) = 1 - ( C(15,0) (1/6)^0 (6/7)^15 + .....) I will let you finish that one
*April 19, 2015*

**maths**

interest after 2 years = 1200(1.06)^2 - 1200 = ... assuming compound interest
*April 19, 2015*

**Sequences**

done when you posted it as Chris, please don't switch names.
*April 18, 2015*

**geometry**

Statement: -5x=10 Reason: subtract 8 from both sides, whatever you do to one side you must do to the other Statement: x=-2 Reason: divide both sides by -5 , whatever you do to one side you must do to the other
*April 18, 2015*

**Maths**

4 = 2^2 36 = 6^2 100 = 10^2 196 = 14^2 324 = 18^2 ahhh, so the base is a multiple of 4 but starts with 2 so how about a base of 4n-2 all we have to do is square it, so ... term(n) = (4n-2)^2 check: let n = 5 term(5) = (2-2)^2 = 18^2 = 324 looks like we got it.
*April 18, 2015*

**ALGEBRA II**

Had they all been positive, then it would be ∑ (2n) from n=1 to 6 but they alternate + - , so you need a multiplier that flip-flops between ± how about (-1)^n, if n is odd you get a negative, if n = even you get a positive, so .... ∑ (2n)(-1)^n from n=1 to 6
*April 18, 2015*

**math**

(94+67+83+93+x)/5 = 90 x + 337 = 450 x = 113 mmmmh, looks like this question is bogus. She cannot get a 90 average.
*April 18, 2015*

**algebra**

-3 < x+5 < 8 subtract 5, (subtraction does not affect the direction of the inequality) -8 < x < 3 This pattern implies the word "and" - it can also be read: x is between -8 and 3 - to have "between -8 and 3" mean: greater than -8 OR less than 3...
*April 18, 2015*

**math help**

rate of slower --- x units/min rate of faster ---- y units/min combined rate = x+y units/min let the volume of the whole thing have 1 unit 1/(x+y) = 40 x+y = 1/40 1/x - 1/y = 60 (y - x)/xy = 60 60xy = y - x 60xy + x = y x(60y+1) = y x = y/(60y+1) then in x+y = 1/40 y/(60y+1...
*April 18, 2015*

**Math**

leg #1 --- x leg #2 --- 8-x x^2 + (8-x)^2 = 6^2 x^2 + 64 - 16x + x^2 = 36 2x^2 - 16x + 28= 0 x^2 - 8x + 14 = 0 x^2 - 8x + 16 = -14 + 16 --- I am completing the square (x-4)^2 = 2 x-4 = ± √2 x = 4+√2 or x=4-√2 x = appr 5.41 or x = appr 2.59 sides are 5....
*April 18, 2015*

**Math**

so you have: y = (x+1)/(x-1) , ..... those brackets are absolutely essential multiply both sides by x-1 y(x-1) = x+1 xy - y = x+1 re-arrange: xy - x = y + 1 factor: x(y-1) = y+1 x = (y+1)/(y-1) , again, those brackets are needed test by picking any x, except x=1 let x = 5, ...
*April 18, 2015*

**math**

"any additional" to what ? Confusing wording.
*April 18, 2015*

**math**

Repeat of your previous problem
*April 18, 2015*

**math**

Same type of problem as your previous one. Let me know what you got
*April 18, 2015*

**Math**

Assuming the 3 miles is the horizontal distance to the "inside" of the mountain, this is a basic tangent ratio tan15 = height/3 height = 3tan15° = ... miles
*April 18, 2015*

**math**

I see no equation If you mean y^3 - 1.5y^2 + .3275 = 0 would rather work with integers, so multiply each term by 400 400y^3 - 600y^2 + 131 = 0 I don't know where you are at in your math studies. Have you learned a way to solve cubics? One way is to use Newton's Method...
*April 18, 2015*

**maths**

make a list of the possible outcomes of your event under the headings a a b TTH --- (1/3)(1/3)(1/4) = 1/36 THT --- (1/3)(2/3)(3/4) = 6/36 HTT --- (2/3)(1/3)(3/4) = 6/36 total = 1/36 + 6/36 + 6/36) = 13/36 mmmhhh, did I miss something ?
*April 18, 2015*

**Math**

In my sketch the position of A and B are as follows: B is to the "left" of A and "up" from A the rise is 1° and the run is 1.25° So the line AB makes an angle of 38.66° with the horizontal. I then sketched in the position of the fire F and got ...
*April 17, 2015*

**Math**

Interpretation: √20/10 - √10/√32 - √.3125 + √(3+1/5) = 2√5/10 - √10/√32 * √32/√32 - √(5/16) + √(16/5) = 2√5/10 - 8√5/32 - √5/4 + 4/√5 *√5/√5 = √5/5 - √5/4...
*April 17, 2015*

**Math**

smaller -- x larger --- 9x x + 9x = 70.4 etc
*April 17, 2015*

**Analytic and Solid Geometry**

any point equidistant from the two given points must lie on the right bisector of the line joining the two points, so ... midpoint of given points is (1,0) slope of line joining the given points = (-1-1)/(-3-5) = 1/4 so the slope of the right-bisector must be -4 equation of ...
*April 17, 2015*

**Math**

Did you check for conditions of either an arithmetic or geometric condition? What are they?
*April 17, 2015*

**math trigonometry**

just good-old Pythagoras here. y^2 + 4^2 = 8.5^2 ... y = √56.25 sinØ = √56.25/8.5 = .. tanØ = √56.25/4 = ...
*April 17, 2015*

**Math.**

slope = rise/run so which fraction is bigger, 12/7 or 8/4 of course you know that 8/4 = 2, so is 12/7 greater or less than 2 ?
*April 16, 2015*

**Algebra 1**

If 363 metres, solve 4.9t^2 = 363 if 363 ft, solve 16t^2 = 363
*April 16, 2015*

**Algebra**

so you want √(x+4) ≥ 4 square both sides x+4 ≥16 x ≥ 12 check: if x = 5 , y = √9 = 3 , which does not exceed 4 if x = 21, y = √25 = 4 which is > 4 if x = 12 , y = √16 = 4, which is ≥ 4 My answer is correct
*April 16, 2015*