Wednesday

October 22, 2014

October 22, 2014

Total # Posts: 27,504

**math,algebra,fractions, decimals**

1/2 = .5 2/3 = .66666.... so terminating decimal between is .58 repeating decimal between is .567676767...
*October 21, 2014*

**math**

then I am right check: area of one triangle = (1/2)(3.5)(10.7857 = 18.875 4 such triangle = 4(18.875) = 75.5
*October 21, 2014*

**math**

define what you mean by slant height.
*October 21, 2014*

**math**

Clearly the surface area would consist only of the 4 triangles. area of one of them = 75.5/4 or 18.875 m^2 area = (1/2)base x height 18.875 = (1/2)(3.5)h h = 2(18.875)/3.5 = appr 10.7857 clean up to whatever accuracy is expected I would say 10.8 , since the original data had ...
*October 21, 2014*

**Algebra**

the original value does not matter e.g. let's start with 100,000 after 3 years: value = 100,000(.9)^3 after 3 more years: value = 100,000(.9)^3 (1.1)^3 = 97,029.9 so what do you think? Here is a new question for you. Would it matter if the value first increased by 10% for ...
*October 21, 2014*

**math**

any number that can be expressed as a simple fraction of the form a/b, where b ≠ 0 is rational rational --- from ratio --- a: b or a/b A number which cannot be expressed as a simple fraction in the above form is irrational irrational --> not rational (irresponsible...
*October 21, 2014*

**Calculus**

f ' (x) = ( (x-2)(2x) - (x^2 + 1)(1) )/(x-2)^2 = (2x^2 - 4x - x^2 - 1/(x-2)^2 = (x^2 - 4x - 1)/(x-2)^2 so f ' (a) = (a^2 - 4a - 1)/(a-2)^2
*October 21, 2014*

**math**

correct
*October 21, 2014*

**math**

simple interest = PRT = 5000(.09)(2) = $ 900 compound interest = 5000( 1.09)^2 - 5000 = $ 940.50
*October 21, 2014*

**math**

-7x^2 + 4x + 9 = 0 7x^2 - 4x - 9 = 0 using the formula ... x = (4 ± √268)/14 = appr 1.455 or x = - .884 the only one that comes close is the last choice Do the other one in the same way
*October 21, 2014*

**math**

done, look at your other post
*October 21, 2014*

**Maths**

f' (x) = x^(2/3) + (2/3)x^(-1/3) (x-1) = (1/3)x^(-1/3) [ 3x - 2(x-1) ] = (1/3)x^(-1/3) [ x + 2] = 0 for a max/min x = 0 or x = -2 checking the f(x) for those and the endvalues f(0) = 0 f(-2) = (-2)^(2/3) (-2-1) = -3(-2)^(2/3) = appr 4.76 f(4) = 4^(2/3) (4-1) = appr 7.56 so...
*October 21, 2014*

**algebra**

amount at 4% --- x amount at 3% --- 15000 - x solve for x .... .04x + .03(15000-x) = 550
*October 21, 2014*

**Algebra**

if 9>-3w-51>60 add 51 60 > -3w > 111 divide by -3 -20 < w < -37 which of course is not possible, since we can't have a number which is greater than -20 AND less than -37 (try to place such a number on a number line)
*October 21, 2014*

**Math**

at a time of t minutes, let the height of the water be h ft V = π(6^2)(h) = 36π h dV/dt = 36π dh/dt subbing in our values 3 = 36π dh/dt dh/dt = 1/(12π) ft/min Did you notice that the rate was constant (it did not depend on what h was) ?
*October 21, 2014*

**Math HELP!!!!!**

????
*October 21, 2014*

**Algebra**

I do not understand your long first sentence. I will attempt to make sense out of it let number of 5 centavo coins be x let the number of 10 centavo coins be y let the number of 25 centavo coins be z "25 centavo coin is 3 times as many 5 coinand" ---- z = 3x "...
*October 21, 2014*

**algebra**

another ---- x one integer ---- 4x-3 x(4x-3) = 27 4x^2 - 3x - 27 = 0 (x-3)(4x+9) = 0 x = 3 or x = -9/4 but x was to be an integer so x =3 3 and 9
*October 20, 2014*

**Math**

Math is a language Just translate: 25 is --- "25 =" three times a number ---- "3w" , if w is the number decreased ---- " - " 8 --------- " 8 " so what do we have ?
*October 20, 2014*

**math**

let x be the total number of beads 2x/3 + 4x/21 + whites = x times 21 14x + 4x + 21whites = 21x 21whites = 3x whites = (1/7)x or (1/7) of the total
*October 20, 2014*

**Pre-Calc**

your given point is in quad II, so the cosine of the angle will have to negative. x = -1/5 , y = 1/2 r^2 = 1/25 + 1/4 = 29/100 r = √29/10 cosØ = x/r = (-1/5)/(√29/10) = (-1/5)(10/√29) = -2/√29 they might expect it to be rationalized and want the ...
*October 20, 2014*

**calculus**

your dy/dx should be -2sint + 2cos2t = 0 recall that one of the equivalents for cos 2t is 1 - 2sin^2 t so -2sint + 2(1 - 2sin^2 t) = 0 -sint + 1 - 2sin^2 t = 0 2sin^2 t + sint - 1= 0 (2sint - 1)(sint + 1) = 0 sint = 1/2 or sint = -1 but we want quadant I ,so sint = 1/2 t = &#...
*October 20, 2014*

**geometry**

You did not state which sides are parallel, so we can't tell If QT || RS, then obviously angle T = 180-23
*October 20, 2014*

**Math**

2z dz/dt = 2x dx/dt + 2y dy/dt when x=4 and y = 3 z^2 = 4^2 + 3^2 = 25 z = 5 Now that you have 5 of the 6 terms, just sub those in and solve for dz/dt
*October 20, 2014*

**Calculus**

I will guess you meant: f(x) = x^(1/6) - x^(-5/6) then f'(x) = (1/6)x^(-5/6 + (5/6)x^(-11/6) = 0 for critical values factor it .. (1/6)x^(-11/6)[ x + 5] = 0 x = 0 or x = - 5 sub those values back into the original function if you need the y values
*October 20, 2014*

**Calculus**

I will give you the derivative, you should be able to take it from there f ' (x) = (x^6(1/x) - lnx(6x^5) )/x^12 = (x5 - 6x^5(lnx))/x^12
*October 20, 2014*

**Calculus**

f'(x) = 12x^2 - 36x - 480 =0 for max/mins divide by 12 x^2 - 3x - 40=0 (x-8)(x+5) = 0 x = 8 or x = -5 You should know the general behaviour of cubic curve with a positive x^3 term and critical values at -5 and 8 I will give you the decreasing interval, it is between -5 and...
*October 20, 2014*

**arithmetic**

(7(9) + x)/8 = 6 63 + x = 48 x = -15 So you would have to add a negative number ?
*October 20, 2014*

**Trigonometry**

So A in in quadrant III tan 2A = 2tanA/(1 - tan^2 A) = 2(1/3)/(1 - 1/9) = (2/3) / (8/9) = (2/3)(9/8) = 18/24 = 3/4
*October 20, 2014*

**Calculus**

Your dy/dx should be (2y-4x)/(3y^2 - 2x) (the way you have it, only the -4x is divided by 3y^2 ) so when y = 2 , in the original, 2x^2 - 4x + 8 = 14 2x^2 - 4x - 6 = 0 x^2 - 2x - 3 = 0 (x-3)(x+1) = 0 x = 3 or x = -1 b) you probably meant to say: Find the equation of the tangent...
*October 20, 2014*

**Math**

You are right. It is not so much of an equation, but rather a statement. I would simply say: cost per child = 192/16 as the "equation"
*October 20, 2014*

**math**

let the sides be x , 3x , 5x, and 7x x+3x+5x+7x = 64 solve for x back-substitute to find any or all sides
*October 20, 2014*

**calculus**

Question makes no sense. It appears whole words are missing.
*October 20, 2014*

**maths**

term7 = a+6d = 6d-8 term9 = a+8d = 8d-8 (6d-8)/(8d-8) = 5/8 48d - 64 = 40d - 40 8d = 24 d = 3
*October 20, 2014*

**Math**

From the identity sin^2 x + cos^2 x = 1 if we divide both sides by sin^2 x , we get 1 + cot^2 x = csc^2 x so csc^2 x - 1 = cot^2 x RS = cot^2 x LS = csc^2(x)cos^2(x) = (1/sin^2 x)(cos^2 x) = cot^2 x = RS All done
*October 20, 2014*

**Algebra**

slope = (1-0)/(3-(-3)) = 1/6 so y = (1/6)x + b plug in (-3,0) 0 = (1/6)(-3) + b b = 1/2 y = (1/6)x + 1/2
*October 20, 2014*

**math**

since a = 2m/s^2 , note you have a typo there. v = 2t + c when t = 3, v = 6 6 = 2(3) + c c = 0 v = 2t so at top of hill, t = 0 then v = 0
*October 20, 2014*

**algebra**

3/(5-i) = 3/(5-i) * (5+i)/(5+i) = (15 + 3i)/(25-i^2) = (15+3i)/26
*October 19, 2014*

**Math**

contradiction: you say the diameter of the cone is the same as the diameter of the ice crream, but then you say 4 cm scoop of ice cream vs 7 cm of diameter of cone
*October 19, 2014*

**math**

Ø = tan^-1 (4/3) so you have right-angled trianle with opposite side = 4 and adjacent side = 3 You should recognize the 3-4-5 right-angled triangle, so sinØ = 4/5
*October 19, 2014*

**algebra**

Really ???? 10-4x = 0 -4x = -10 x = -10/-4 = 2.5
*October 19, 2014*

**tech math**

let the diameter of the small pulley be d let the diameter of the larger pulley be d+7 belt distance covered by smaller pulley in one minute = 136(πd) = 136πd by the larger pulley = 80(π)(d+7) so 136πd = 80π(d+7) divide out the π 136d = 80d + 560 ...
*October 19, 2014*

**Business Math**

work on the loan option: balance owing = 7200-720 = 6480 let the monthly rate be x then 205( 1 - (1+x)^-36)/x = 6480 205(1 - (1+x)^-36) = 6480x Equations of this type are very difficult to solve, since there is no "formula" to handle it. In the "olden" days...
*October 19, 2014*

**Calculus**

I would have taken the first derivative of -1/(1-x) and simplified it to 1/(x-1) or (x-1)^-1 (If my numerator or my denominator is a constant, I seldom use the quotient rule, since one part drops out anyway) y' = (x-1)^-1 y'' = -1(x-1)^-2 = -1(x-1)^2 f '' (...
*October 19, 2014*

**Maths**

recall two properties 1. for y = abc y' = abc' + acb' + bca' etc for multiple factors **** However, if any of the a, b, or c are powers such as (c-4)^4 , then that base of x-4 will appear in each of the terms of y'' ***** very important ! 2. if y'&#...
*October 19, 2014*

**Steve or Damon or bobpursly or ... - Calculus**

not quite, your brackets are very important what you have worked out is ... ln (x^x) which is x lnx etc, and your answer would be correct for that but you typed (lnx)^x which would be (lnx)(lnx)(lnx) ... (lnx) , x times we might apply the rule: extension of the product rule if...
*October 19, 2014*

**AP Calc. AB**

1. take the derivative of each, not that bad If you have a calculator, just plug in each given value and see what happens or make a sketch of y = sin^2 (x) and y = (1/2)x^2 from appr -1.6 to +1.6 take a few points using your calculator . 2. Did you get the actual derivative? I...
*October 19, 2014*

**Maths**

let's use an intuitive approach You might recall that lim (1 + 1/n)^n = e as n ---> ∞ or lim (1 + n)^(1/n) = e , as n ---> 0 now we have (1+sinx)^(1/tanx) now as x ---> 0 , sinx --->0 and 1/tanx ----> ∞ so we have (1 + really small)^really large ...
*October 19, 2014*

**College Algebra (Word Problem)**

What's an eld ? let the side parallel to the rive by y ft let the other sides be x ft each so xy = 1200 y = 1200/x cost of fence = 16y + 8(2x) = 16(1200/x) + 16x = 19200/x + 16x d(cos)/dx = -19200/x^2 + 16 = 0 for a min cost. 16x^2 = 19200 Can you finish it?
*October 19, 2014*

**Math**

What is 5x5x4
*October 18, 2014*

**math**

Use the distance between 2 points formula ... d = √( (4 - (-2))^2 + (-6-2)^2 ) = √(36+64) = √100 = 10
*October 18, 2014*

**algebra**

I will assume you want A(w) = √(w^2+13) then A(0) = √(0+13) = √13
*October 18, 2014*

**algebra**

wherever you see an x, plug in x+5 f(x+5) = 6(c+5)^2 + 7 = 6c^2 + 60c + 157
*October 18, 2014*

**Math**

amount of 36% solution -- x cc amount of 14% solution -- (25-x) cc .36x +.14(25-x) = .25(25) times 100 , (don't like decimals like to avoid them) 36x + 14(25-x) = 25(25) 36x - 14x = 625 - 350 22x = 275 x = 12.5 cc so it looks like 12.5 cc of each
*October 18, 2014*

**math**

let the number have the form abc "the first and second digits are multiple of 3 the first digit is greater than the second digit." ---> has to be 63c or 963, would also consider 30c "the sum of the first two digits is 7 more that the third digit " -->...
*October 18, 2014*

**Algebra**

difference of squares ... ( (y+2) + 9)( (y+2) - 9) = (y+11)(y-7)
*October 18, 2014*

**Algebra**

without "calculating", I can tell that the question is bogus, since only one point is given. Can't find slope if given only one point.
*October 18, 2014*

**Intermediate Algebra**

If they have to do their OWN homework, then the question really makes no sense. If it is an assignment type homework were both can work on the project, then beth's rate = 1/6 nina's rate = 1/9 combined rate = 1/6 + 1/9 = 5/18 time at combined rate = 1/(5/18) = 18/5 or ...
*October 18, 2014*

**Algebra**

2x^2-5x^3-20x^2+115x-52=0 -5x^3 - 18x^2 + 115x - 52 = 0 5x^3 + 18x^2 - 115x + 52 = 0 no obvious NICE factors the graph suggests 3 real roots, thus no complex zeros http://www.wolframalpha.com/input/?i=5x%5E3+%2B+18x%5E2+-+115x+%2B+52+%3D+0 I suspect a typo
*October 18, 2014*

**Algebra Help**

interpretation: 4 roots: 2+2i 2-2i -5 -5 the -5 root twice yields (x+5)^2 for the two complex roots: sum of those two = 4 product of those two = (2+2i)(2-2i) = 8 which gives us the trinomial x^2 -4x + 8 so f(x) = a(x^2 - 4x + 8)(x+5)^2 , where a is any non-zero constant
*October 18, 2014*

**Scientific notation**

correct, use 10^4 to show 10 raised to the fourth
*October 17, 2014*

**Scientific notation**

the format is to always have a single non-zero digit, followed by a decimal place time a power of 10 69,000,000,000 = 6.9 x 10^10 , exponent is 10 since we moved our decimal 10 places
*October 17, 2014*

**finance**

let the quarterly rate be i then 1(1+i)^12 = 3 (1+i) = 3^(3/12) = 3^(1/4) = 1.316 i = .316 or appr 31.6 % per quarter, or appr 126.4% per annum quickly, tell me who is giving us that, I have a few dollars to invest.
*October 17, 2014*

**diff calculus**

let the length of the rectangle parallel to the 160 ft side be x let its height be y I see 3 similar triangles, the original and the 2 smaller triangles by ratios: y/(160-x) = 120/160 = 3/4 4y = 480 - 3x y = 120 - 3x/4 area of rectangle = A = xy = x(120 - 3x/4) = 120x - 3x^2/4...
*October 17, 2014*

**algebra 1**

no first of all your answer, if that number is supposed to be the answer, is incorrect secondly, I do not like the way you present your answer proper way: 4 = 18 - 3w 3w = 18-4 3w = 14 w = 14/3 or 4 2/3
*October 17, 2014*

**math**

did you make a sketch? Isn't it just 5 km due west of where it started from without doing any calculations?
*October 17, 2014*

**Algebra2**

the given line has slope -2/3 so your perpendicular line has slope 3/2 new line must be y = (3/2)x + b passing through (-4,3) 3 = (3/2)(-4) + b b = 3 + 12/2 = 9 new line: y = (3/2)x + 9
*October 16, 2014*

**Math**

You want the sum of "all " the terms an infinite GS you have a GS, where a = 4/3, r = 1/2 sum(of all the terms) = a/(1-r) = (4/3)/(1-1/2) = (4/3)/(1/2) = 8/3 or 2 2/3
*October 16, 2014*

**calculus**

I will ignore the hint and use a very straight-forward method the shortest distance will of course be the normal to the plane going through (1,0,0) plane: 6x + 9y - z + 1 = 0 a normal to the plane is (6,9,-1) and passing through (1,0,0) would be the line x = 6t + 1 y = 9t z...
*October 16, 2014*

**Math**

That will depend on what type of sequence we are looking at Is it AS ? Is it GS ? or is it ...?
*October 16, 2014*

**calculus**

forget the very last line, I had made corrections, but forgot to delete that line
*October 16, 2014*

**calculus**

Last time I did this type of question was 55 years ago, so I hope I can remember. I think we first have to find the area intercepts between y = 25x^2 and y = 4 25x^2 = 4 x = ± 2/5 by symmetry we can go from 0 to 2/5 and double area = 2(integral) (4 - 25x^2) dx from 0 to...
*October 16, 2014*

**Algebra2**

were did you get 2^7i from ??? I thought we did 2 i^7 and I thought I did that for you. i^100 = (i^4)^25 = (+1)^25 = 1 I strongly suggest your write down the first 4 or 5 terms of the pattern I gave you and I strongly suggest you read my explanation of that pattern.
*October 16, 2014*

**Algebra2**

I assume you want to simplify each one the imaginary number i has very unusual properties watch this cyclic pattern: i i^2 = -1 i^3 = i(i^2) = -i i^4 = i^2 i^2 = (-1)(-1) = +1 i^5 = i i^4 = i(1) = i , and here we go round again notice every even power of i is either +1 or -1 ...
*October 16, 2014*

**Algebra**

actually the 2nd is a strange one, as it has an infinite number of solutions 3/x = 3x/x^2 the right side simplifies to 3/x so you have 3/x = 3/x, which of course is true for all values of x except x = 0 (remember, we can't divide by zero)
*October 16, 2014*

**Math**

correct
*October 16, 2014*

**math**

There were 23 marbles, of which 5 were blue 3 were removed, one of them blue so now there are 20 marbles, of which 4 are blue prob(blue) = 4/20 = 1/5 which is C
*October 16, 2014*

**algebra**

width --- x length -- 3x+5 area = x(3x+5) or 3x^2 + 5x
*October 16, 2014*

**Math**

yes
*October 16, 2014*

**Math algebra Help please**

original: base --- b, height --- h area = (1/2)bh = 24 bh = 48 new triangle: base ---6b, height ----6h new area = (1/2)(6b)(6h) = 18 bh = 864
*October 16, 2014*

**Algebra**

Let the time for the first train be t hrs 50t + 70(t-1) = 350 120t = 420 t = 420/120 = 7/2 or 3.5 hrs
*October 16, 2014*

**Math**

break down of A = [ w | w < 1} A = ------ A is equal to | w ----- the set of all w such that w < 1 ----- w is less than 1 Now "translate" the second one for me
*October 16, 2014*

**Math**

check if (2x+2)/(x+1) = (5x+1)/(2x+2) for ALL values of x that is, the equation should reduce to 0 = 0 to be a GS (I know it works for x = 3)
*October 16, 2014*

**Calc**

sorry, I forgot the +2xy on the left side should have been dy/dx = (y^3 - 2xy - 12x^2)/(x^2 - 3xy^2) I am disappointed that you could not find that simple error.
*October 16, 2014*

**Calc**

4x^3+x^2y-xy^3 = -4 we want derivatives with respect to x, so whenever we get a dx/dx, we get 1 So I will not write the dx/dx 's 12x^2 + (x^2)dy/dx + y(2x) - x(3y^2)dy/dx - y^3 = 0 dy/dx(x^2 - 3xy^2) = y^3 - 12x^2 dy/dx = (y^3 - 12x^2)/(x^2 - 3xy^2) check my work, I tend ...
*October 16, 2014*

**math**

correct
*October 16, 2014*

**math**

difference = 1/2 - 13/32 = 16/32 - 13/32 = 3/32
*October 16, 2014*

**Calculus**

or #1, use r^2 = x^2 + y^2 x^2 + y^2 = 169 2x dx/dt + 2y dy/dt = 0 , I differentiated with respect to t (time) or dy/dt = (-x/y)dx/dt when x = 12, dx/dt = 5 ft/s find dy/dt at that moment 12^2 + y^2 = 169 y = 5 dy/dt = (-12/5)(5) ft/s = -12 ft/sec the negative shows it is ...
*October 16, 2014*

**Maths**

y1/y2 = √x1/√x2 1/4 = √x1/√x2 √x2 = 4√x1 square both sides x2 = 16x1 x2/x1 = 16/1 or 1600 % e.g. suppose x = 36 then y = 6 now we want y to be quadrupled, so y = 24 and x would be such that √x = 24 , so x = 576 percentage increase in x...
*October 16, 2014*

**Maths**

6 men --- 4 hrs --- 6m deep 1 man ---24 hrs --- 6m deep 10 men 24/10 hrs -- 6 m deep 10 men 2.4 hrs --- 6 m deep 10 men 2.4/6 hrs --1 m deep 10 men .4 hrs ===1 m deep 10 men .4(5) hrs --- 5 m deep 10 men 2 hrs ---- 5 m deep OR it takes 24 manhrs to dig a 6 m deep hole it takes...
*October 16, 2014*

**Math**

1. looks like a GS, were a = 2/3, and r = 3 sum(5) = a(r^5 - 1)/(r-1) = (2/3)(3^5 -1)/2 = ..... 2. nope, (4x-2)/(2x) ≠ (6x-4)/(4x-2) for all values of x it would be true or only x = 1 3. 0.7575757575... = .75 + .0075 + .000075 + ... a GS where a = .75, r = .01 sum(...
*October 16, 2014*

**maths**

Suppose we had 25600 kg of food or 25600/80 kg per student for 80 days, or 1 kg per student for 1 day so in 20 days, 320(20) kg or 6400 kgwere used so 19200 kg are left for 300 students time for this to last = 19200/300 = 64 days or do the same with a variable let the amount ...
*October 16, 2014*

**Map Rectangle**

area on map = 12 cm^2 actual size of rectangle = 4000 cm by 3000 cm or 40 m by 30 m real area = 1200 m^2
*October 16, 2014*

**math**

-2/5x - 9 < 9/10 times 10 -4x - 90 < 9 -4x < 99 x > -99/4
*October 16, 2014*

**Math**

4cos^2 A - 3cosA = 0 cosA(4cosA - 3) = 0 cosA=0 or cosA = 3/4 but your domain is quadrant II, where the cosine is negative except cos90° = 0 so x = 90° do the 2nd the same way by factoring out tanA
*October 15, 2014*

**Math**

first of all, notice that each equation is divisible by 4 new equations: 8x + 9y = -4 9x + 8y = -4 multiply 1st by 8 ---> 64x + 72y = -32 multiply 2nd by 9 --> 81x + 72y = -36 subtract them 17x= -4 x = -4/17 into the 1st:8(-17/4) + 9y = -4 times 4 -136 + 36y = -16 36y = ...
*October 15, 2014*

**St Grainne,s**

let the tend digit be 2x then the unit digit and the hundreds digit are each x x+2x+x = 16 4x=16 x = 4 you are 484
*October 15, 2014*

**maths**

I will assume you meant to say that the area of the ink blot is growing at the rate of 2 cm^2 /s A = πr^2 dA/dt = 2πr dr/dt 2 = 2π (28/11) dr/dt dr/dt = 11/(28π) cm/sec = appr .125 cm/s
*October 15, 2014*

**math**

dozen of pencils --- x dozen of pens ----- y dozen of erasers --- z 4x + 3y + 2z = 16 2x + 4y + 6z = 90 6x + 2y + 3z = 70 Since you want it done by matrices, which for these nice equations would be overkill, I would find the inverse of 4 3 2 2 4 6 6 2 3 , then multiply that by...
*October 15, 2014*

Pages: **1** | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | Next>>