Tuesday

May 26, 2015

May 26, 2015

Total # Posts: 34

**Algebra**

How do you graph the equation of -1.2x + 2y= -4 and y = 0.6x + 8
*April 28, 2013*

**algebra**

how do you do the linear equation y + 9 =1/5x and 45 - 3y = 15x
*April 28, 2013*

**algebra**

the line "l" passes through the point P=(1,-1,1) and has a direction vector d=[2,3,-1], for the following plane Pl, determine whether l and P is parallel, perpendicular, or neither. a) 2x + 3y - z = 1 could you tell me also how it would differ if it was parallel or ...
*January 12, 2011*

**chemistry**

I'm assuming mass? I'm not sure.
*September 25, 2010*

**chemistry**

Pure acetylsalicylic acid has a melting point of 135.0 - 135.5 (degrees Celsius). What would you expect for the melting point is this was mixed as a 50:50 mixture with pure benzoic acid (melting point 121 - 122)? Explain.
*September 25, 2010*

**chemistry - buffers**

what mass of sodium acetate should be dissolved in 1.00L of acetic acid, 0.150M concentration, in order to produce a buffer with pH = 4.5?. Ka of CH3COOH = 1.8x10^-5
*April 12, 2010*

**buffers**

thanks a lot :D
*March 3, 2010*

**buffers**

thanks. so for this question is the pH 3.70?
*March 3, 2010*

**buffers**

we havn't learnt that equation.
*March 3, 2010*

**buffers**

9.00mL of 1.10M CH3COOH and 1.00mL of 0.900M CH3COO- what is the pH?
*March 3, 2010*

**chemistry**

determine the pH of 10.00mL or 0.100M HCl after adding 10.00mL of indicator solution. (i think this is supposed to be a buffer problem)
*March 2, 2010*

**Chemistry**

a few drops of NaOH are added to a sample of the unknown. A blue precipitate appears. Next, approximately 1mL of ammonia, NH3, is added. The precipitate dissolves, but the solution remains blue. Which ion is present. Explain
*January 24, 2010*

**percipitate and colour**

a few drops of NaOH are added to a sample of the unknown. A blue precipitate appears. Next, approximately 1mL of ammonia, NH3, is added. The precipitate dissolves, but the solution remains blue. Which ion is present. Explain
*January 24, 2010*

**sigma sums**

evaluate: n sigma i=1 3/2^(i-1)
*November 12, 2009*

**sigma notation**

find the value of the sum n sigma i=1 (2-5i)
*November 12, 2009*

**calculus**

sorry, i meant what is the antiderivative of f'(x) = (x^2-1)/x
*November 8, 2009*

**calculus**

f'(x) = (x^2-1)/x
*November 8, 2009*

**calculus**

im sorry. i think it was because i wrote it wrong. i meant f'(x) = (x^2-1)/x
*November 8, 2009*

**calculus**

i just didn't understand how you got to that point. And i havn't learned integrals yet. I was hoping someone else could give me a different perspective as to how to answer it.
*November 8, 2009*

**calculus**

find f(x) f'(x) = (x^2-1)/x^(-1)
*November 8, 2009*

**antiderivates**

find f(x) f'(x) = (x^2-1)/x^(-1)
*November 8, 2009*

**antiderivatives**

find the equation of f(x) f''(x)= 2 + x^3 + x^6
*November 8, 2009*

**calculus**

P /|\ / | \ / | \ on this side there is an / | \ arc with A(θ) in the / | \ middle. the B(θ) /θ | B(θ)\ triangle is not equal O -------------- R to the θ triangle. Q the figure shows a setor of a circle with central angle theta. Let A(θ) be the ...
*November 8, 2009*

**limits**

lim as x-> infinity sec^2(1/x)
*November 7, 2009*

**implicit differentiation**

what is the derivative of ln(y) = x
*November 1, 2009*

**calculus**

what is the derivative of y = (1/2)xln(x)
*November 1, 2009*

**chemistry**

A sample of the primary standard, Potassium hydrogen phthalate, weighing 0.3589g requires 14.96mL of NaOH solution for neutralization. calculate the molarity of the NaOH solution.
*October 21, 2009*

**calculus - limits**

limit as x approaches infinity; tan^(-1) (x^2 - x^4) any help is appreciated =D
*October 18, 2009*

**calculus - please help**

Simplify the expression: cos(2tan^(-1)x) any help is appreciated =D
*September 22, 2009*

**10th grade algebra**

try isolating for y
*September 22, 2009*

**calculus**

solve for x: a)e^x=5 b) lnx=2
*September 13, 2009*

**math**

isolate t: 300(1.o5)^t = 1000(0.92)^t
*May 24, 2009*

**word unscramble**

its two words the letters are hemctbenwee the second word is four letters
*September 28, 2006*

**word unscramble**

its two words the letters are hemctbenwee
*September 28, 2006*

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