Tuesday
September 23, 2014

Posts by RZeal


Total # Posts: 8

Chemistry
Thanks I was able to solve it!
June 10, 2012

Chemistry
Sorry about the confusion Ecell = 0.15 and Eocell = 0.31
June 10, 2012

Chemistry
3HClO2(aq) +2Cr3+(aq) + 4H2O(l) -> 3HClO(aq) + (Cr2O7)2–(aq) + 8H+(aq) At pH 0.00, with [Cr2O72–] = 0.80 M, [HClO2] = 0.15 M, and [HClO] = 0.20 M, the cell voltage is found to be 0.15 V. Calculate the concentration of [Cr3+] in the cell Ecell = 0.31 Not sure how ...
June 10, 2012

Chemistry
Calculate the Ecell for this reaction 3HClO2(aq) +2Cr3+(aq) + 4H2O(l) -> 3HClO(aq) + (Cr2O7)2–(aq) + 8H+(aq) I thought Cr + e -> Cr2O7 is the cathode and 3HClO2 -> 3HClO + e- is the anode. Using Ecell = Cathode - Anode I get -0.31, but the answer I checked is ...
June 10, 2012

Chemistry
Ka = Ch3COO- 5.6x10^-10 Ka = Ch3COOH 1.8x10^-5
April 26, 2012

PH Calculation
Consider a 0.42 M solution of NaCH3COO CH3COO–(aq) + H2O(l) -> CH3COOH(aq) + OH–(aq) Calculate the pH of the solution at equilibrium. Try the weak acid or weak base approximation (as appropriate) and check the validity of the approximation. If the approximation is...
April 26, 2012

Chemistry Acid Question Ka
Nevermind I figured it out, With the equation Ka = x^2 / 0.0165 - x x = [H+] I forgot to do the 0.0165-x in my original calculation, but after doing that I got the correct answer.
April 22, 2012

Chemistry Acid Question Ka
Enough of a monoprotic acid is dissolved in water to produce a 0.0165 M solution. The pH of the resulting solution is 2.38. Calculate the Ka for the acid.
April 22, 2012

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