# Posts by RZeal

Total # Posts: 8

Chemistry
Thanks I was able to solve it!

Chemistry
Sorry about the confusion Ecell = 0.15 and Eocell = 0.31

Chemistry
3HClO2(aq) +2Cr3+(aq) + 4H2O(l) -> 3HClO(aq) + (Cr2O7)2–(aq) + 8H+(aq) At pH 0.00, with [Cr2O72–] = 0.80 M, [HClO2] = 0.15 M, and [HClO] = 0.20 M, the cell voltage is found to be 0.15 V. Calculate the concentration of [Cr3+] in the cell Ecell = 0.31 Not sure how ...

Chemistry
Calculate the Ecell for this reaction 3HClO2(aq) +2Cr3+(aq) + 4H2O(l) -> 3HClO(aq) + (Cr2O7)2–(aq) + 8H+(aq) I thought Cr + e -> Cr2O7 is the cathode and 3HClO2 -> 3HClO + e- is the anode. Using Ecell = Cathode - Anode I get -0.31, but the answer I checked is ...

Chemistry
Ka = Ch3COO- 5.6x10^-10 Ka = Ch3COOH 1.8x10^-5

PH Calculation
Consider a 0.42 M solution of NaCH3COO CH3COO–(aq) + H2O(l) -> CH3COOH(aq) + OH–(aq) Calculate the pH of the solution at equilibrium. Try the weak acid or weak base approximation (as appropriate) and check the validity of the approximation. If the approximation is...

Chemistry Acid Question Ka
Nevermind I figured it out, With the equation Ka = x^2 / 0.0165 - x x = [H+] I forgot to do the 0.0165-x in my original calculation, but after doing that I got the correct answer.

Chemistry Acid Question Ka
Enough of a monoprotic acid is dissolved in water to produce a 0.0165 M solution. The pH of the resulting solution is 2.38. Calculate the Ka for the acid.

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