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Since the moments were calculated from the end the fisherman is holding in his left hand, that force does not generate any moment.
Assuming the fishing pole is horizontal... Yes, the fisherman's left hand is exerting a downward force. You are correct.
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6 is correct. However, your last step is not quite correct. starting with... 20x + 10 - 10 = 130 - 10 20x = 120 Now divide both sides by 20, not 20x 20x/20 = 120/20 x = 6
Yes, that answer is correct.
You are headed in the right direction. That is a distance formula when there is uniform acceleration which is gravity in this problem. The formula is: s2 = s1 + vt + (1/2)(a)t^2 where: s2 = final distance s1 = initial distance v = initial velocity a = acceleration t = total ti...
How are you solving it? What answer are you getting?
Your welcome! Glad to help
Yes, you got it!