Monday

December 22, 2014

December 22, 2014

Total # Posts: 495

**visual basic**

gradeCounter is defined as Integer. Try: If(gradeCounter = 0)...
*May 7, 2009*

**Algebra**

For the first problem: Let x = lesser number let y = greater number (x) (y) = 273 The problem states that y = x + 8. substituting for y: (x) (x+8)=273 x^2 + 8x=273 so x^2 + 8x - 273 = 0 Solve for x. Then, y = x + 8
*April 30, 2009*

**Algebra**

Uh-oh, You need to reverse the inequality sign when you multiply or divide both sides by a negative number! should be: y < (1/3)x + 5
*April 29, 2009*

**Math**

Take your step: x^2 + 5x + 6 = 90 Now: x^2 + 5x - 84 = 0 Factor by inspection or use the quadratic formula to solve for x. A hint is what two factors of 84 differ by 5?
*April 29, 2009*

**Algebra, PLEASE help!**

One approach is to just use the quadratic formula to solve it. But, you could probably do it by inspection if you write the equation as: 0.25x^2 + 0.3x + 0.09 =(10^(-2))(25x^2 + 30x + 9)
*April 29, 2009*

**Algebra**

What do you think the answer is?
*February 24, 2009*

**math**

One method: Use substitution to express an equation in one unknown. Choose a. From the first equation... a + b = 6 So, b = 6 - a From the third equation... c + a = 7.5 So, c = 7.5 - a Now write the second equation substituting the values for b and c in terms of a: b + c = 20 ...
*February 22, 2009*

**Calc help**

Just to be clear, it is a vertical line at x=1.
*February 19, 2009*

**Calc help**

Below assumes: y = e^2x means e^(2x) and y = e^5x means e^(5x) The two curves (equations) intersect at x=0, y=1. Then, going in the positive x direction, they diverge. But, the right side of the region is bounded by a line at x=1. So, find the area from x = 0 to x = 1 under ...
*February 19, 2009*

**Math 116**

1. m/n = 8 is correct. 2. x=2178 is not correct 11x=198 divide both sides by 11 x=198/11 x=?
*February 17, 2009*

**Algebra**

Area = length * width length = (2x-1)m width = (x+2)m Area = (2x-1)(x+2) m^2 Multiply the two factors (use FOIL).
*February 17, 2009*

**Algebra**

Let A=Total amount of the stronger (75%) DeMuggle juice potion added in ml. The percent of DeMuggle juice is: (total DeMuggle juice)/(total volume of potion) The final total DeMuggle juice is: 2000ml(30%) + A(%75) =600ml + 0.75A The final total volume of potion is: 2000ml + A ...
*February 6, 2009*

**Pre Calc**

Absolute values are always positive. For any t, |3t| will be larger than |2t| . So, the right side is always negative. The absolute value of the left side is always positive.
*February 5, 2009*

**math**

I think Chopsticks misread the problem. let P=price 20 years ago 49 cents = 4P-(3 cents) 52 cents = 4P P=13 cents
*February 5, 2009*

**math**

let R = rainfall last year in cm. 18.6cm = (R/2) -3.2cm 21.8cm = R/2 R= ?
*February 5, 2009*

**math**

Chopsticks is wrong. let W = Juan's weight in kg 6W - 12kg = 486kg 6W = 498kg W = ?
*February 5, 2009*

**Math 012**

Your are on the right track. You want to get just the variable on one side of the equation. You have done that. Your last step above: 4 - 10 = 10n + 10 - 10 The +10 and - 10 on the right cancel 4 - 10 = 10n Subtract 10 from 4 on the left. Then you something on the left = 10n. ...
*January 31, 2009*

**Factor Completely**

Sorry, I am not sure what they are asking. Someone else here might understand it.
*January 23, 2009*

**Factor Completely**

Is the problem c^2 - 8c + 16 - y^2 = 0?
*January 23, 2009*

**Factor Completely**

OK, (3x^3 - 1) (2x^3 + 5) First Multiply the first terms of the two factors: (3x^3)(2x^3) = 6x^6 Outer Multiply the outer terms of the factors: (3x^3)(5) = 15x^3 Inner Multiply the inner terms of the factors: (-1)(2x^3) = -2x^3 Last Multiply the last terms of the factors: (-1...
*January 23, 2009*

**Factor Completely**

Yes. Also, lyne mentioned checking using FOIL (First Outer Inner Last). That is a good acronym for multiplying binomials.
*January 23, 2009*

**Factor Completely**

Your step 3: 6u^2 + 13u - 5 What number multiplied give -5? One possibility... (?u - 1) ( ?u + 5) What numbers multiplied give 6? One possibility... (3u - 1)(2u + 5) Now substitute back for u.
*January 23, 2009*

**calculus**

Hint: get rid of the denominator (4x^2 + 10)/(x^(1/2)) =4x^(3/2) + 10x^(-1/2)
*January 21, 2009*

**math- logarithms**

Check your previous post for the solution to problem 2.
*January 8, 2009*

**math**

The first line above (where the problems was restated) should have been: 3^(x^3)=9^x The rest of the lines are correct.
*January 8, 2009*

**math**

For problem 2: 3^(x^3)=9^3 take log of both sides (x^3)log(3)=(x)log(9) divide both sides by x (x^2)log(3)=log(9) 9=3^2 so (x^2)log(3)=2log(3) divide both sides by log(3) x^2=2 x=sqrt(2)
*January 8, 2009*

**MATH**

[SQRT(2x^2 + 5x +6) = x square both sides 2x^2 + 5x + 6 = x^2 subtracting x^2 from both sides... x^2 + 5x + 6 = 0 Factor by inspection or use the binomial theorem to solve for x. The second problem is similar.
*January 4, 2009*

**math**

7x + 13x = 140 Combine all the x terms: 20x = 140 Solve for x.
*December 18, 2008*

**6th grade Math**

night 1=1 night 2=5 night 3=14 night 4=30 difference from 1 and 2 = 4 difference from 2 and 3 = 9 difference from 3 and 4 = 16 Do you see anything special in the differences?
*December 18, 2008*

**math**

First convert the number to a decimal number. Remember that percent is expressed in "hundredths". So multiply the decimal number by 100 to get the percent value. Example: 3 1/16 = 3.0625 = 306.25 percent = 306.25%
*December 16, 2008*

**Math**

Yes, it is correct.
*November 6, 2008*

**Physics 12**

Disregard my answer. I assumed that the stationary block was fixed. I don't think that is the case. DRWLS has the correct approach. He is very good.
*October 29, 2008*

**Physics 12**

K1=initial kinetic energy K2=kinetic energy after collision K1 = (1/2)(5.2kg)(9.4m/s)^2 K2 = (1/2)(5.2kg)(1.80m/s)^2 kinetic energy lost is: K1 - K2
*October 29, 2008*

**Math**

If you can't quickly factor the equation, it is generally easier to just use the quadratic equation. As you do more and more, you will probably remember how you factored them previously.
*October 29, 2008*

**math [ i need help with these.]**

The line -0(3) should have been =0(3) See below: For x=0 2x(x+3) =2(0)(0+3) =0(3) =0
*October 24, 2008*

**math [ i need help with these.]**

2x(x+3)=0 I am assuming that you need to find the values of x that will be true for the above. When you multiply several items (each of these is called a factor) together the answer (called the product) is 0 if ANY of them are 0. Example: multiply (a)(b)(c) If any of them, a ...
*October 24, 2008*

**math [ i need help with these.]**

Sorry, I meant to say factor not term. If any "factor" in a product is 0 the whole product is 0. There are 2 "factors".
*October 24, 2008*

**math [ i need help with these.]**

2. 2x(x+3)=0 There are 2 terms: 2x and (x+3). If any term in a product is 0 the whole product is 0. So, what value of x would make 2x=0 and what value of x would make x+3 = 0?
*October 24, 2008*

**math**

x * y = 7 x - y = 5 One method: express one variable in terms of the other variable and then solve the single variable expression. If x - y = 5 then y = x - 5 substituting back into the first equation: x * (x - 5)=7 Solve for x, then substitue the x value into either equation ...
*October 2, 2008*

**statistics**

Answered in your 5:50pm post.
*October 2, 2008*

**math**

Jessica's answer is not correct. x intercept point = -4,0 y intercept point = 0,2 y = mx + b is the standard line equation where: m = the slope of the line b = the y intercept The problems gives the y intercept as 2. slope = (delta y)/(delta x) = (0 - 2)/(-4 - 0) = -2/(-4...
*October 1, 2008*

**Calculus**

sorry for the mistake (d g(x)/dx = -6(x^5) SIN (x^6)
*September 27, 2008*

**Calculus**

(d(cos(u))dx = -sin(u)(du/dx) for g(x)=cos(x^6) (d g(x))/dx = -6(x^5)cos(x^6)
*September 27, 2008*

**Calculus**

Close, but I believe is should be: 309(t^2)((t^3)+8)^102
*September 27, 2008*

**pre calc**

N = number of nickles D = number of dimes = N+4 Q = number of quarters = 25-N-D = 25-N-(N+4) = 21-(2N) Add the coins to get $3.20 (N*$0.05) + (D*$0.10) + (Q*$0.25) = $3.20 Expressing D and Q in terms of N: (N*$0.05) + ((N+4)*$0.10) + (21-2N)*$0.25=$3.20 Solve for N. Then plug ...
*September 26, 2008*

**algebra/math**

Check the reply to your 1:15am post.
*September 26, 2008*

**algebra/math**

FOIL is an acronym for First Outer Inner Last used when multiplying binomials. 1. Multiply the FIRST terms in each binomail. In this problem that would be x^(1/2) * x^(1/2) 2. Multiply the OUTER terms: x^(1/2) * 4 3. Multiply the INNER terms: -2 * x^(1/2) 4. Multiply the LAST ...
*September 26, 2008*

**7th grade**

Multiplication is distributive over addition. Division can be performed by multiplying by the inverse of the divisor. So, yes, division is distributive over addition.
*September 24, 2008*

**physics**

Here the vector angles are relative to the X axis. So, east would be 0 degrees, north is 90 degrees, west is 180 degree, and south is 270 degrees. So, SE is 270 + 45 = 315. -45 degrees could also be used.
*September 23, 2008*

**physics**

Break the 3 vectors into components and solve for the unknown vector. For this choose North is positive y East is positive x First vector, 2.00km east represented by (2.00km)x + 0(km)y Second vector, 3.50km SE represented by (3.50)(cos(315))(km)x + (3.50)(sin(315))(km)y Third ...
*September 23, 2008*

**Help!**

Let x = first number Let y = second number x +(2x-1) = y 3x-1=y so x = (y+1)/3
*September 19, 2008*

**Help!**

3 - 8 difference = 5 4 - 11 difference = 7 5 - 14 difference = 9 etc. In each case the difference is: 2 x (first number) - 1
*September 19, 2008*

**math**

Let x be the number. (1/3)(x) + 5 = -2 multiply both sides by 3: x + 15 = -6 subtract 15 from both sides to solve for x.
*September 19, 2008*

**Math**

You are CORRECT on #2. Also There is no parenthesis in the problem. I copied it down and added it.
*September 17, 2008*

**Math**

I got the same for #1. For #2 (-6)^-2 =1/((-6)^2) =1/(36
*September 17, 2008*

**physics please help!**

A handy equation for an object with 0 initial velocity and constant acceleration is: v^2 = (2*a*s) where v = final velocity a = acceleration (in this problem it is gravity) s = distance
*September 16, 2008*

**Physics**

Passenger height = 2.5m + vt = 2.5m + (2.2m/s)t Camera height = (11.6m/s)t + (1/2)(-g)t^2 The camera reaches the passenger when Passenger height = Camera height solve t for equal height, then plug t into either equation for the height. You will find 2 answers for equal height...
*September 16, 2008*

**Math**

For the problem (4m-7)/2 = 18 To solve for m: The object is to get a single m on one side of the equation. 1. get rid of the denominator (2) on the left side by multiplying both sides of the equation by 2. That gives: 4m-7 = 36 Now add 7 to both sides to get just a term with n...
*September 15, 2008*

**physics**

Paint thickness multiplied by area covered should equal the volume of paint. Let T = thickness of paint. T = (volume of paint) / (area covered) T = (231 in^3) / (450 ft^2) Convert 450 ft^2 to its equivalent in in^2, divide, and you have the answer in inches.
*September 15, 2008*

**math**

Check the answer for the similar problem you posted. It is solved the same way.
*September 15, 2008*

**math**

For the problem, a value of x which makes a factor 0 is a solution. (x^2-9)(2x-1) = 0 factoring (x^2-9) further (x+3)(x-3)(2x-1) = 0 For each factor, what value of x will make the term 0? The first term, (x+3), will be 0 for x=-3. The second term is 0 for x=? The third term is...
*September 15, 2008*

**Math - Imaginary Numbers**

Remember that i^2 = -1 3(-2i)^2 =3(-2)^2(i^2) =? -i(isqrt(5))^2 =-i(i^2)(sqrt(5))^2 =?
*September 11, 2008*

**Math - Imaginary Numbers**

Remember that i represents the square root of (-1). So, i^2 = -1 i^5 = (i^2)(i^2)(i) =(-1)(-1)(i) =?
*September 11, 2008*

**discrete math**

Multiply out all the terms -4(k-2) + 3(k+1)=7 -4k + 8 + 3k + 3 = 7 Now combine like terms (all k's and all numbers) -1k + 11 = 7 11 - 7 = k So, k = ?
*September 11, 2008*

**6th grade**

The volume of the hole will be the length X width X depth. It's always good to be sure that units for each dimension are the same. In this problem, they are all in meters. Volume = length X width X depth Volume = 6m X 2m X 1m Multiply the right side to get the volume. ...
*September 10, 2008*

**math**

Let B = the number of balloons in each bag. The problem says that each bag has the same number of balloons. Also, after all the bags are used, 18 more balloons are still needed to get to 138. The equation would be: 5B + 18 = 138 To solve for B first subtract 18 from each side...
*September 10, 2008*

**math**

To clarify the previous posting Number, Square Root: 9, 3 16, 4 23, 4.796 (approximately)
*July 31, 2008*

**math**

The square root of a number is the number which multiplied by itself results in the original number. Number Square Root 9 3 16 4 23 4.796 (approximately) There are methods to calculate the square root without a calculator, but they are a bit involved. google: calculating ...
*July 31, 2008*

**Check Work (Math)**

That is correct!
*July 29, 2008*

**MAth**

Your answer for the first question (b) is correct. I don't think you copied the second question correctly.
*July 28, 2008*

**Algebra1**

Let's look at this: The original value is 18/7. You want to find an equivalent value that has a denominator of 28. To get that value, you need to multiply the denominator by 4. To "multiply by 1" to not change the value, you need to also multiply the numerator by...
*July 25, 2008*

**Math**

(x+4)log3 = (x+2)log5 (x+4)(0.47712) = (x+2)(0.69897) 0.47712x + 1.90848 = 0.69897x + 1.39794 0.22185x = 0.51054 x=2.301 Checking you will probably find a small rounding error. If you carry the calculations to a lot of decimal places it will be more exact.
*July 23, 2008*

**PRECALC**

See reply to your 6:51pm posting below.
*July 22, 2008*

**Precalc**

Oops! An error on my part! The last line should be: =((2y+7)^5)x((y-2)^4)x[5x(2y+7)+6x(y-2)x2]
*July 22, 2008*

**Precalc**

I changed the variable to y to avoid confusion with the x used for multiplication. [(2y+7)^6 x 5(y-2)^4] + [(y-2)^5 x 6(2y+7)^5 x 2] (2y+7)^5 and (y-2)^4 are common to both terms. bring the common factors outside: =((2y+7)^5)x((y-2)^4)x[(2y+7)+(y-2)x2] There are 2 terms in the...
*July 22, 2008*

**Algebra**

There is an error in the second line. Should be: 10x - 35 < -8
*July 16, 2008*

**Math Urgent**

square both sides, collect like terms and solve. Here's the first step: (k+3)^2 = (2k-1)^2 k^2 + 6k + 9 = 4k^2 - 4k + 1 Combine all the like terms. You might factor it out, but I would suggest using the quadratic equation.
*July 13, 2008*

**Math Urgent**

I don't think you copied the first question correctly. Did you intend 2 equal signs?
*July 13, 2008*

**Math Urgent**

Also, because of the (p+1) term remember that p=-1 will be a solution.
*July 13, 2008*

**Math Urgent**

Hint. Each term on both sides has a factor (p+1). Divide all terms on both sides by (p+1). This will simplify it for you.
*July 13, 2008*

**Algebra**

(x + a ) (x + b) = x^2 + 7x + 10 Think what two number multiplied give 10, and when added give 7?
*July 10, 2008*

**algebra**

let x = speed of first part of trip in mph let x-5 = speed of second part of trip in mph 5 hours = 63 miles/x + 6/(x-5) Solve for x. If you solve a quadratic, ignore the answer which would cause the slower speed to be negative (non-real case).
*July 10, 2008*

**Calculus**

point A f(x) = 1/(x^2) point B f(x+deltaX) = 1/((x+deltaX)^2) The slope of the line between these points is: [f(x+deltaX) - f(x)]/[(x+deltaX - x] The slope of the tangent is given when deltaX->0. to get you started... [(1/(x+deltaX)^2) - 1/x^2]/[x+deltaX - x] Get rid of the...
*July 10, 2008*

**C++**

First problem I see is in your first case 'Yes'. You output "Does the hard drive spin?", then you have a "break;". The break takes you out of the first enclosing switch. So, the cin does not get executed. This same error is in the first case 'No...
*July 10, 2008*

**Algebra**

when you write: (sqrt5/15) Which do you mean: sqrt(5/15) or (sqrt(5))/15
*July 5, 2008*

**Algebra**

If you let y=x^2 then: 25*y^2 - 20*y +3 = 0 You can use the quadratic formula to solve. Your solution for y will really be for x^2. Take the square root of y values to get the x values. I did not get any imaginary values. One answer (that I got) IS sqrt(3/5), but as a real ...
*July 5, 2008*

**Algebra**

That's the answer I got.
*July 4, 2008*

**math**

Calculate the total cost of each game including tax--remember that 8.125% = 0.08125 total cost = game + tax = $3.95 + 0.08125($3.95) Now divide the money he has ($20.92) by the total cost per game. Disregard any remainder/fraction/decimal of a game since you cannot normally ...
*June 25, 2008*

**Algebra**

For the equation of a line in the form: y = m*x + b m=slope b=y intercept The lines will be parallel if the slopes (m value) are the same. Rearrange the equations to the above form and check for m being the same value for each.
*June 18, 2008*

**Algebra 1**

Correct!
*June 17, 2008*

**Algebra**

Generally, the rational expression will be undefined when the denominator is 0. Find all values for z which would result in the denominator being 0.
*June 16, 2008*

**College Algebra**

For: Assume all values are in inches. L=length of rectangle W=width of rectangle P=perimeter of rectangle P=L + W + L + W The problem states: P=78 L=W + 3 Substitute the above values into the perimeter equation.
*June 16, 2008*

**math**

Generally, a fraction would be considered undefined if the denominator is 0. For the problem, what values of x would make the denominator 0?
*June 16, 2008*

**algebra**

p1 = -2,0 p2 = 0,1 slope = (1 - 0)/(0 - (-2) ) = 1/2 =0.5
*June 4, 2008*

**math final tmrw!!!!!!!**

(x + a)(x + a) =x^2 + 2ax + a^2 In the problem, 2ax=22x 2a=22 a=11 substituting back (x + 11)(x + 11) x^2 + 22x + 121
*June 3, 2008*

**Math**

The exponent is evaluated first. So, you would evaluate 4^x first, then multiply that by 3. If the expression had been written as: (3*4)^x, then you would multiply 3*4 first and raise that product to the x power.
*May 28, 2008*

**Math question - plz correct**

Glad to help!
*May 27, 2008*

**Math question - plz correct**

Actually, you would have to multiply them by 4 because they are squared. You have the right idea. For the legs use: b=2*450km=900km c=2*355km=710km This would then give you 800^2=900^2 + 710^2 - 2(900)(710)cos(A) Solve for A using the same method you did before.
*May 27, 2008*

**Math question - plz correct**

A quick look finds that you missed the fact that the time the airplanes are 800km apart is 2 hours not 1 hour. The legs should be 2*355km and 2*450km.
*May 27, 2008*

**Algebra**

A good way to be sure is to put the lines into the familiear y=mx+b form. The second equation is already there. If the value of m is the same, the lines are parallel.
*May 27, 2008*

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