Friday
May 24, 2013

# Posts by Quidditch

Total # Posts: 494

Math
You are doing it correctly. 5(59.4) = 4(61) + x multiply it out... 297 = 244 + x subtract 244 from each side 53 = x

math
First write the problem. 4 < x^(1/2) < 9 Square each term. There are no negative signs, so the inequality signs will not change. Squaring... 16 < x < 81

algebra

algebra
Well, let's try your answer: (x-5)(x+5) = x^2 - 25. So, that doesn't work. Doing the factoring I mentioned previously gives: 7x^2(x - 5) - 6(x - 5) Now there are two terms. The terms have a common factor of (x-5). Using our friendly distributive law we can write: (7x^2...

algebra
7x^3 - 35x^2 - 6x + 30 Factor 7x^2 from the first two terms and -6 from the last two terms.

math
For this type of problem, try to get just the variable on one side and just the numbers on the other side. (1/2)a - 5 = (1/3)a - 1 Add 5 to both sides to get rid of the number on the left. (1/2)a - 5 + 5 = (1/3)a - 1 + 5 combining... (1/2)a = (1/3)a + 4 Now subtract (1/3)a fro...

math
The numerator can be factored: (x^4 - 8x^2 + 15) = (x^2 - 3)(x^2 - 5) Use that and cancel the common (x^2 - 3) in the numerator and denominator.

math
1. The solution is an inequality. Also when you multiply or divide by a negative number, the inequality is reversed. from you step: -3x/-3 < 6/-3 Since you are dividing both sides by a negative number the inequality is flipped: x > -2 2. OK

math
4x3x2 are common in both the numerator and denominator. Canceling those leaves just 5 in the numerator.

math
Turn the factorial expressions into product series, cross out common factors in the numerator and denominator.

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