Saturday
December 10, 2016

# Posts by Quidditch

Total # Posts: 512

Math
You are correct!
December 22, 2015

Where is the energy stored in a flashlight?
December 10, 2015

Computer Programming
I think that the semicolon (;) should be deleted in your line: if (a == b) System.out.println(a*b);
July 5, 2015

Intro to computers
You are correct!
June 17, 2015

math
Yes, you got it! 49 = 49
May 14, 2015

math
No, D is not correct. (7*7*7*7)=? (7*7)=? Divide the 4 7s multiplied by the 2 7s. What do you get
May 14, 2015

math
What did you get when you calculated 7^4/7^2
May 14, 2015

math
You're welcome!
May 14, 2015

math
Yes, you got it! 5^0=1
May 14, 2015

math
You are correct on 1. The answer is c. You are not correct on 2.
May 14, 2015

PHYSICS
What did you get when you converted the weight to kg?
April 24, 2015

math
Correct!
March 30, 2015

Electricity and Electronics
oops... I meant amps.
February 24, 2015

Electricity and Electronics
Your are correct! current for 40 volts across 12 ohms: 40V/12 ohms=3.33 smps
February 24, 2015

Math
2.5 times \$4.00 is the cost to make 1 tent. So, what would it cost to make 4 tents?
January 22, 2015

Math
The first equation has y=10-2.2x Substituting that value for y into the second equation: 5x + (10-2.2x)=70 5x + 10-2.2x=70 combining... 2.8x=60 x=? Plug that value for x into the first equation to find y.
January 4, 2015

Algebra 1
When you multiplied the second equation by 2 your result is wrong. It should be: 6x + 12y=52 NOT: 6x-12y=52
January 2, 2015

math
30% of 200,000 is NOT 6000
December 16, 2014

math
Looks good!
December 30, 2012

Math
Try multiplying by a/a.
July 2, 2012

Maths
Don't forget to think about negative numbers here. What negative numbers would give you a correct answer?
July 1, 2012

algebra
January 13, 2012

Math
Looks good!
December 14, 2011

trig
You have the right idea. one revolution is 2(pi) radians. Converting revolutions to radians: R=revolutions Revolutions in Radians=R*2(pi) So, to convert 2.8 revolutions/sec to radians =2.8(2)(pi)/sec
December 14, 2011

precalculus
With the values given, I did not find any of the answers on the graph. For a distance vs time graph. X axis is time and Y axis is distance. at t=6s, dist=5m at t=8s, dist=6m at t=10s, dist=7m at t=12s, dist=8m I don't see any of those as choices.
December 3, 2011

precalculus
For problem 2, I got A, x=-1.
December 3, 2011

precalculus
C is the answer I got.
December 3, 2011

precalculus
Problem 1. Look at my calculation, the average rate is +12,not a negative number.
December 3, 2011

precalculus
For a distance vs time graph. X axis is time and Y axis is distance. at t=6s, dist=5m at t=8s, dist=6m at t=10s, dist=7m at t=12s, dist=8m I don't see any of those as choices.
December 3, 2011

precalculus
Problem 1 A is not the answer. f(4)- f(1) =11 - (-1) = +12 -------------- Problem 3. C looks correct
December 3, 2011

precalculus
Problem 2. The answer is not B, (x=0).
December 3, 2011

precalculus
Problem 1. The answer is NOT D. The average rate of change is: for x=1, f(1)=-3 for x=4, f(4)=-3 Average rate of change is 0, not a negative number. One of the answers does give a negative average rate of change.
December 3, 2011

PreAP Physics
Yes, that's what I got, also.
November 23, 2011

Help
That's correct!
October 28, 2011

Math
Let B = the "break even" number of books. Production costs=\$76,322 + B * \$10 Total Sales = B * \$25.50 Setting these equal... Total sales = Production costs or... \$76,322 + B * \$10 = B * \$25.50 Solve for B
October 28, 2011

1, 2, 3, 4, and 6 look OK I don't understand 5, 7 is wrong.
October 26, 2011

number 4 should be +5 6 is wrong.
October 26, 2011

algebra
slope = rise/run. For a slop of 0.4 0.4 = rise/130 Solve for rise. It looks like you have accidentally moved the decimal in your line: .040=rise
October 21, 2011

Let D = the number of dimes. So, D + 9 = the number of nickels. Adding... D * 10 + (D + 9) * 5=135 combining 15 * D + 45 = 135 15 * D = 90 Divide both sides by 15 D = 6 There are six dimes. So, the number of nickels is 6 + 9 = 15
October 18, 2011

physics
The time is takes to slow down is T2 - T1. That is given as 3.0s.
October 12, 2011

pre-calculus
The best way to check is to substitute your answer back into the equation. SQRT(2x+1)-5=8 SQRT( (2*84)+1)-5=8 SQRT(168+1)-5=8 SQRT(169)-5=8 13 - 5 = 8 8 = 8 You are correct!
September 20, 2011

Math
Adding the items gives \$460 The tax on that at 5.5% =0.055*\$460 =? Add the tax to the cost of the items. That value is one of the choices given.
September 18, 2011

College Math
-5+2*SQR(12) =-5+2*SQR(4*3) =-5+2*SQR(4)*SQR(3) =-5+2*2*SQR(3) =-5+4*SQR(3)
September 17, 2011

College Math
My Alt+251 keyboard did not post as a square root--reposting...
September 17, 2011

College Math
You got the right answer! It just needed to be reduced. -5 + 2*ã(12) =-5+2*ã(4*3) =-5+2*ã4 * ã3 =-5+2*2*ã3 =-5+4*ã3
September 17, 2011

Physics for Engineers
September 14, 2011

Physics
Using that... Y=14.47m/s(2.2s)-(1/2)(9.8m/s)(2.2)^2 Y=31.834m - 23.716m =8.118m So it clears the wall by 8.118m - 6.7m =1.418m
September 14, 2011

Physics
I get 14.47m/s for Vy.
September 14, 2011

Physics
I calculated the ball was thrown at a speed of 18.12m/s. Vx is 24m/2.2s=10.91m/s Vx=V(cos(53)) That gives V as 18.12m/s
September 14, 2011

Physics
Sorry, I see that was given.
September 14, 2011

Physics
On part b, You need to find how long it takes the ball to go th 24.0m in the x direction. Use that time for the y calculation.
September 14, 2011

algebra 2
I believe Capreeca is wrong on this one. 2x+1=3 2x=2 x=1
July 13, 2011

maths
July 7, 2011

Algebra
Change the 31% to a decimal value. Then multiply both sides of the equation by Q. Then get all the Q terms on one side and the number terms on the other side. Combine the terms and solve for Q.
July 7, 2011

Geometry
I think you made an error in adding the angles. In your problem angles are x, 3x, and 4x. Adding those gives 8x not 7x. Does that help?
July 4, 2011

Algebra 1
let J=Jim's age let D=Dave's age It is given that Dave can vote. So D>=18 Dave is 5 years older J+5=D or J=D-5 Jim can't vote. J<18 Substitute for Jim's age: D-5<18 Solve this for the upper limit for Dave's age.
July 4, 2011

algebra 1
Sorry the next to last line should say to express LENGTH as a function of W. Then, solve for W.
July 4, 2011

algebra 1
What does the problem say: Perimeter is less than 48ft. Let P=perimeter Let L=length Let W=width P<48ft Express perimeter in terms of length and width: P=L+W+L+W or L+W+L+W<48ft Express the width as a funtion of L. Substitute that value into the above equation and solve ...
July 4, 2011

physics
Yes, that is correct. I would really encourage you to carry the units through from start to finish. It seems like extra work, but it can help detect errors.
July 2, 2011

math
Yes, you are correct!
July 1, 2011

math
type LCM, least common multiple
July 1, 2011

math
I think 72 is the LCM, least common multile, not GCF, greatest common factor.
July 1, 2011

Algebra
Add 4 to both sides. Then, square both sides. Does that help?
June 19, 2011

Pre-algebra
To clarify: (-4)^4 is not equal to -256.
March 25, 2011

Pre-algebra
-256 is not the correct answer.
March 25, 2011

math
Yes! All answers are correct. Note that answer 4 could be reduced to 19/30 hours.
March 6, 2011

math
March 6, 2011

Algebra 2
Correcting typo The line 5 = H = 1 shoud read: 5 = H - 1
February 21, 2011

Algebra 2
My error I just reread that the first 1/2 hour is included. I am quite sure that the it is \$30 for each additional 1/2 hour the equation is: Let H = the number of HALF HOURS \$200 = \$50 + (H-1))\$30 similarly \$150 = (H-1)*\$30 5 = H=1 adding 1 to each side: H= 6 This is the ...
February 21, 2011

Algebra 2
I think there is some confusion here. Let H = the total hours \$200 = \$50 + (H-1)*\$30 Remember that the first hour is included in the \$50. subtract \$50 from both sides \$150 = (H-1)*\$30 divide both sides by \$30 5 = H -1 add 1 to both sides: H = ??
February 21, 2011

Algebra B
You are very welcome.
February 16, 2011

Algebra B
You're welcome, but I am not sure what you mean by reverse FOIL. First terms: x and x Outer terms: x and -5/4 Inner terms: -5/4 and x Last terms : -5/4 and -5/4 I just want to be sure you have a good understanding about the order.
February 16, 2011

Algebra B
OK, (x-5/4)^2 = (x-5/4)(x-5/4) multiplying (remember FOIL--first, outer, inner, last) = x^2 -(5/4)(x) - (5/4)(x) + (5/4)^2 = x^2 - (10/4)(x) + (5^2)/(4^2) = x^2 -(5/2)(x) + (25)/(16) Does that help?
February 16, 2011

Algebra B
Which side (left or right) is puzzling?
February 16, 2011

Physics
Be careful of units. You expressed the runway length in m (meters), but the takeoff speed is expressed in mi/h (miles/hour). You will need to do some units conversion.
January 23, 2011

computer architecture
Modern PCs have a word size of 32 or 64 bits. Early IBM PCs used an Intel 8088 which had an 8 bit data path.
December 12, 2010

ALGEBRA/AM I CORRECT?
my misspelling... You have AN eror.
December 11, 2010

ALGEBRA/AM I CORRECT?
You have and error. 3X + 240 + 36X = 6 39X = -234 X = ?
December 11, 2010

Physics
You are very welcome!
December 7, 2010

Physics
Since the moments were calculated from the end the fisherman is holding in his left hand, that force does not generate any moment.
December 7, 2010

Physics
Assuming the fishing pole is horizontal... Yes, the fisherman's left hand is exerting a downward force. You are correct.
December 7, 2010

ALGEBRA
November 5, 2010

ALGEBRA
6 is correct. However, your last step is not quite correct. starting with... 20x + 10 - 10 = 130 - 10 20x = 120 Now divide both sides by 20, not 20x 20x/20 = 120/20 x = 6
November 5, 2010

math
November 5, 2010

Physics
You are headed in the right direction. That is a distance formula when there is uniform acceleration which is gravity in this problem. The formula is: s2 = s1 + vt + (1/2)(a)t^2 where: s2 = final distance s1 = initial distance v = initial velocity a = acceleration t = total ...
October 24, 2010

Physics
How are you solving it? What answer are you getting?
October 24, 2010

Algebra
October 5, 2010

Algebra
Yes, you got it!
October 5, 2010

Algebra
Close... You have the inequality correct, but when you divided both sides by -4, you you have an error on the right side. 6/(-4) = ?
October 5, 2010

Algebra
-4x + 1 >= 7 Solve this as you would if there was just an "=" sign. But, anytime you multiply or divide both sides by a negative number the inequality sign will reverse. To get you started... Subtract 1 from both sides.
October 5, 2010

algebra
1. Make sure the equation is in the form: ax^2 + bx + c = 0, which your problem is. 2. Use the quadratic formula: x1 = (-b + (b^2 - 4ac)^(1/2))/(2a) x2 = (-b - (b^2 - 4ac)^(1/2))/(2a) You can check your answers by substituting into the original equation.
September 5, 2010

algebra1
The problem says the hours will always be over 20. The charge for the first 20 hours is \$9.95. All the hours after 20 are \$0.50 each. h = total monthly hours cost = \$9.95 + (h - 20)x \$0.50 Plug in 35 for h and what do you get?
August 26, 2010

math
Be cautious about units on this problem. The problem gives the distance in feet. Gravitational acceleration in English units is about 32 ft/sec^2 .
August 26, 2010

calculus
You got it! Glad to help.
August 26, 2010

calculus
Sorry, my error... I went the wrong way! Your exponent and coefficient are wrong.
August 26, 2010

calculus
The exponent is correct, but the coefficient is not 1. If you take the derivative of your answer do you get x^4?
August 26, 2010

math
Retyping last lines... What is 10% of the new larger salary? Subtract that to find what your salary is after the 10% cut.
August 26, 2010

math
What is 10% of \$90,000? Add that to \$90,000 to find your salary after the raise. What is %10 of the new larger salary? Substract that to find what your salary is after the %10 cut.
August 26, 2010

algebra word problem
r-5 being negative results in a negative t2 and so should be ignored.
August 24, 2010

algebra word problem
You are practically there! Combine terms and rearrange to get into the form: 4r^2 -90r + 275 = 0 Use the quadratic formula to find r. There will be two answers. One of the answers is the result if the canoeist reverses direction (r-5 is negative).
August 24, 2010

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