Sunday

April 26, 2015

April 26, 2015

Total # Posts: 502

**PHYSICS**

What did you get when you converted the weight to kg?
*April 24, 2015*

**math**

Correct!
*March 30, 2015*

**Electricity and Electronics**

oops... I meant amps.
*February 24, 2015*

**Electricity and Electronics**

Your are correct! current for 40 volts across 12 ohms: 40V/12 ohms=3.33 smps
*February 24, 2015*

**Math**

2.5 times $4.00 is the cost to make 1 tent. So, what would it cost to make 4 tents?
*January 22, 2015*

**Math**

The first equation has y=10-2.2x Substituting that value for y into the second equation: 5x + (10-2.2x)=70 5x + 10-2.2x=70 combining... 2.8x=60 x=? Plug that value for x into the first equation to find y.
*January 4, 2015*

**Algebra 1**

When you multiplied the second equation by 2 your result is wrong. It should be: 6x + 12y=52 NOT: 6x-12y=52
*January 2, 2015*

**math**

30% of 200,000 is NOT 6000
*December 16, 2014*

**math**

Looks good!
*December 30, 2012*

**Math**

Try multiplying by a/a.
*July 2, 2012*

**Maths**

Don't forget to think about negative numbers here. What negative numbers would give you a correct answer?
*July 1, 2012*

**algebra**

Both answers are correct!
*January 13, 2012*

**Math**

Looks good!
*December 14, 2011*

**trig**

You have the right idea. one revolution is 2(pi) radians. Converting revolutions to radians: R=revolutions Revolutions in Radians=R*2(pi) So, to convert 2.8 revolutions/sec to radians =2.8(2)(pi)/sec
*December 14, 2011*

**precalculus**

With the values given, I did not find any of the answers on the graph. For a distance vs time graph. X axis is time and Y axis is distance. at t=6s, dist=5m at t=8s, dist=6m at t=10s, dist=7m at t=12s, dist=8m I don't see any of those as choices.
*December 3, 2011*

**precalculus**

For problem 2, I got A, x=-1.
*December 3, 2011*

**precalculus**

C is the answer I got.
*December 3, 2011*

**precalculus**

Problem 1. Look at my calculation, the average rate is +12,not a negative number.
*December 3, 2011*

**precalculus**

For a distance vs time graph. X axis is time and Y axis is distance. at t=6s, dist=5m at t=8s, dist=6m at t=10s, dist=7m at t=12s, dist=8m I don't see any of those as choices.
*December 3, 2011*

**precalculus**

Problem 1 A is not the answer. f(4)- f(1) =11 - (-1) = +12 -------------- Problem 3. C looks correct
*December 3, 2011*

**precalculus**

Problem 2. The answer is not B, (x=0).
*December 3, 2011*

**precalculus**

Problem 1. The answer is NOT D. The average rate of change is: for x=1, f(1)=-3 for x=4, f(4)=-3 Average rate of change is 0, not a negative number. One of the answers does give a negative average rate of change.
*December 3, 2011*

**PreAP Physics**

Yes, that's what I got, also.
*November 23, 2011*

**Help**

That's correct!
*October 28, 2011*

**Math**

Let B = the "break even" number of books. Production costs=$76,322 + B * $10 Total Sales = B * $25.50 Setting these equal... Total sales = Production costs or... $76,322 + B * $10 = B * $25.50 Solve for B
*October 28, 2011*

**MATH 7th GRADE**

1, 2, 3, 4, and 6 look OK I don't understand 5, 7 is wrong.
*October 26, 2011*

**MAT 7th GRADE**

number 4 should be +5 6 is wrong.
*October 26, 2011*

**algebra**

slope = rise/run. For a slop of 0.4 0.4 = rise/130 Solve for rise. It looks like you have accidentally moved the decimal in your line: .040=rise
*October 21, 2011*

**MATh please help**

Let D = the number of dimes. So, D + 9 = the number of nickels. Adding... D * 10 + (D + 9) * 5=135 combining 15 * D + 45 = 135 15 * D = 90 Divide both sides by 15 D = 6 There are six dimes. So, the number of nickels is 6 + 9 = 15
*October 18, 2011*

**physics**

The time is takes to slow down is T2 - T1. That is given as 3.0s.
*October 12, 2011*

**pre-calculus**

The best way to check is to substitute your answer back into the equation. SQRT(2x+1)-5=8 SQRT( (2*84)+1)-5=8 SQRT(168+1)-5=8 SQRT(169)-5=8 13 - 5 = 8 8 = 8 You are correct!
*September 20, 2011*

**Math**

Adding the items gives $460 The tax on that at 5.5% =0.055*$460 =? Add the tax to the cost of the items. That value is one of the choices given.
*September 18, 2011*

**College Math**

-5+2*SQR(12) =-5+2*SQR(4*3) =-5+2*SQR(4)*SQR(3) =-5+2*2*SQR(3) =-5+4*SQR(3)
*September 17, 2011*

**College Math**

My Alt+251 keyboard did not post as a square root--reposting...
*September 17, 2011*

**College Math**

You got the right answer! It just needed to be reduced. -5 + 2*ã(12) =-5+2*ã(4*3) =-5+2*ã4 * ã3 =-5+2*2*ã3 =-5+4*ã3
*September 17, 2011*

**Physics for Engineers**

Check part b comments on your previous post.
*September 14, 2011*

**Physics**

Using that... Y=14.47m/s(2.2s)-(1/2)(9.8m/s)(2.2)^2 Y=31.834m - 23.716m =8.118m So it clears the wall by 8.118m - 6.7m =1.418m
*September 14, 2011*

**Physics**

I get 14.47m/s for Vy.
*September 14, 2011*

**Physics**

I calculated the ball was thrown at a speed of 18.12m/s. Vx is 24m/2.2s=10.91m/s Vx=V(cos(53)) That gives V as 18.12m/s
*September 14, 2011*

**Physics**

Sorry, I see that was given.
*September 14, 2011*

**Physics**

On part b, You need to find how long it takes the ball to go th 24.0m in the x direction. Use that time for the y calculation.
*September 14, 2011*

**algebra 2**

I believe Capreeca is wrong on this one. 2x+1=3 2x=2 x=1
*July 13, 2011*

**maths**

Please note that "ina"'s answer is wrong.
*July 7, 2011*

**Algebra**

Change the 31% to a decimal value. Then multiply both sides of the equation by Q. Then get all the Q terms on one side and the number terms on the other side. Combine the terms and solve for Q.
*July 7, 2011*

**Geometry**

I think you made an error in adding the angles. In your problem angles are x, 3x, and 4x. Adding those gives 8x not 7x. Does that help?
*July 4, 2011*

**Algebra 1**

let J=Jim's age let D=Dave's age It is given that Dave can vote. So D>=18 Dave is 5 years older J+5=D or J=D-5 Jim can't vote. J<18 Substitute for Jim's age: D-5<18 Solve this for the upper limit for Dave's age.
*July 4, 2011*

**algebra 1 **

Sorry the next to last line should say to express LENGTH as a function of W. Then, solve for W.
*July 4, 2011*

**algebra 1 **

What does the problem say: Perimeter is less than 48ft. Let P=perimeter Let L=length Let W=width P<48ft Express perimeter in terms of length and width: P=L+W+L+W or L+W+L+W<48ft Express the width as a funtion of L. Substitute that value into the above equation and solve ...
*July 4, 2011*

**physics**

Yes, that is correct. I would really encourage you to carry the units through from start to finish. It seems like extra work, but it can help detect errors.
*July 2, 2011*

**math**

Yes, you are correct!
*July 1, 2011*

**math**

type LCM, least common multiple
*July 1, 2011*

**math**

I think 72 is the LCM, least common multile, not GCF, greatest common factor.
*July 1, 2011*

**Algebra**

Add 4 to both sides. Then, square both sides. Does that help?
*June 19, 2011*

**Pre-algebra**

To clarify: (-4)^4 is not equal to -256.
*March 25, 2011*

**Pre-algebra**

-256 is not the correct answer.
*March 25, 2011*

**math**

Yes! All answers are correct. Note that answer 4 could be reduced to 19/30 hours.
*March 6, 2011*

**math**

BUBBA's answers start with a wrong answer.
*March 6, 2011*

**Algebra 2**

Correcting typo The line 5 = H = 1 shoud read: 5 = H - 1
*February 21, 2011*

**Algebra 2**

My error I just reread that the first 1/2 hour is included. I am quite sure that the it is $30 for each additional 1/2 hour the equation is: Let H = the number of HALF HOURS $200 = $50 + (H-1))$30 similarly $150 = (H-1)*$30 5 = H=1 adding 1 to each side: H= 6 This is the ...
*February 21, 2011*

**Algebra 2**

I think there is some confusion here. Let H = the total hours $200 = $50 + (H-1)*$30 Remember that the first hour is included in the $50. subtract $50 from both sides $150 = (H-1)*$30 divide both sides by $30 5 = H -1 add 1 to both sides: H = ??
*February 21, 2011*

**Algebra B**

You are very welcome.
*February 16, 2011*

**Algebra B**

You're welcome, but I am not sure what you mean by reverse FOIL. First terms: x and x Outer terms: x and -5/4 Inner terms: -5/4 and x Last terms : -5/4 and -5/4 I just want to be sure you have a good understanding about the order.
*February 16, 2011*

**Algebra B**

OK, (x-5/4)^2 = (x-5/4)(x-5/4) multiplying (remember FOIL--first, outer, inner, last) = x^2 -(5/4)(x) - (5/4)(x) + (5/4)^2 = x^2 - (10/4)(x) + (5^2)/(4^2) = x^2 -(5/2)(x) + (25)/(16) Does that help?
*February 16, 2011*

**Algebra B**

Which side (left or right) is puzzling?
*February 16, 2011*

**Physics**

Be careful of units. You expressed the runway length in m (meters), but the takeoff speed is expressed in mi/h (miles/hour). You will need to do some units conversion.
*January 23, 2011*

**computer architecture**

Modern PCs have a word size of 32 or 64 bits. Early IBM PCs used an Intel 8088 which had an 8 bit data path.
*December 12, 2010*

**ALGEBRA/AM I CORRECT?**

my misspelling... You have AN eror.
*December 11, 2010*

**ALGEBRA/AM I CORRECT?**

You have and error. 3X + 240 + 36X = 6 39X = -234 X = ?
*December 11, 2010*

**Physics**

You are very welcome!
*December 7, 2010*

**Physics**

Since the moments were calculated from the end the fisherman is holding in his left hand, that force does not generate any moment.
*December 7, 2010*

**Physics**

Assuming the fishing pole is horizontal... Yes, the fisherman's left hand is exerting a downward force. You are correct.
*December 7, 2010*

**ALGEBRA**

You're welcome. Glad to help
*November 5, 2010*

**ALGEBRA**

6 is correct. However, your last step is not quite correct. starting with... 20x + 10 - 10 = 130 - 10 20x = 120 Now divide both sides by 20, not 20x 20x/20 = 120/20 x = 6
*November 5, 2010*

**math**

Yes, that answer is correct.
*November 5, 2010*

**Physics**

You are headed in the right direction. That is a distance formula when there is uniform acceleration which is gravity in this problem. The formula is: s2 = s1 + vt + (1/2)(a)t^2 where: s2 = final distance s1 = initial distance v = initial velocity a = acceleration t = total ...
*October 24, 2010*

**Physics**

How are you solving it? What answer are you getting?
*October 24, 2010*

**Algebra**

Your welcome! Glad to help
*October 5, 2010*

**Algebra**

Yes, you got it!
*October 5, 2010*

**Algebra**

Close... You have the inequality correct, but when you divided both sides by -4, you you have an error on the right side. 6/(-4) = ?
*October 5, 2010*

**Algebra**

-4x + 1 >= 7 Solve this as you would if there was just an "=" sign. But, anytime you multiply or divide both sides by a negative number the inequality sign will reverse. To get you started... Subtract 1 from both sides.
*October 5, 2010*

**algebra**

1. Make sure the equation is in the form: ax^2 + bx + c = 0, which your problem is. 2. Use the quadratic formula: x1 = (-b + (b^2 - 4ac)^(1/2))/(2a) x2 = (-b - (b^2 - 4ac)^(1/2))/(2a) You can check your answers by substituting into the original equation.
*September 5, 2010*

**algebra1**

The problem says the hours will always be over 20. The charge for the first 20 hours is $9.95. All the hours after 20 are $0.50 each. h = total monthly hours cost = $9.95 + (h - 20)x $0.50 Plug in 35 for h and what do you get?
*August 26, 2010*

**math**

Be cautious about units on this problem. The problem gives the distance in feet. Gravitational acceleration in English units is about 32 ft/sec^2 .
*August 26, 2010*

**calculus**

You got it! Glad to help.
*August 26, 2010*

**calculus**

Sorry, my error... I went the wrong way! Your exponent and coefficient are wrong.
*August 26, 2010*

**calculus**

The exponent is correct, but the coefficient is not 1. If you take the derivative of your answer do you get x^4?
*August 26, 2010*

**math**

Retyping last lines... What is 10% of the new larger salary? Subtract that to find what your salary is after the 10% cut.
*August 26, 2010*

**math**

What is 10% of $90,000? Add that to $90,000 to find your salary after the raise. What is %10 of the new larger salary? Substract that to find what your salary is after the %10 cut.
*August 26, 2010*

**algebra word problem**

r-5 being negative results in a negative t2 and so should be ignored.
*August 24, 2010*

**algebra word problem**

You are practically there! Combine terms and rearrange to get into the form: 4r^2 -90r + 275 = 0 Use the quadratic formula to find r. There will be two answers. One of the answers is the result if the canoeist reverses direction (r-5 is negative).
*August 24, 2010*

**math**

Put the equations into slope-intercept form: y = mx + b m = slope b = y intercept For your first problem... subtract x from both sides x + 8y = 16 8y = -x + 16 divide both sides by 8 y = -(1/8)x + 2 So, the slope is -(1/8) I am not sure why you set y to 0 in your solution. ...
*August 23, 2010*

**Math**

Put the equation into the form ax^2 + bx + c = 0 then use the quadratic formula to find the solutions.
*August 22, 2010*

**math**

You can put the equations into the form ax^2 + bx + c = 0 then use the quadratic formula to find the solutions.
*August 22, 2010*

**math**

The x intercept occurs where the line intercepts the x axis. The value of y at that point is 0. If you substitute 0 for y in your equation, what does x then equal?
*August 17, 2010*

**math**

The y intercept is where the line intercepts the y axis. So, it occurs when x = 0. Plug the value of 0 into your equation. What do you get?
*August 17, 2010*

**Math**

If you multiply the top row number by 5 and then add 1, you get the bottom row number.
*August 10, 2010*

**Math**

I am not sure why your teacher circled it. When the problem is solved, 8 fits into the sequence top and bottom.
*August 10, 2010*

**Math**

Now for the second part, how does the second row relate to the first. 2, 3, 5, 8, 12 11, 16, 26, 41, ? First I would check what would be added to the top row to get the bottom row. That would be 9, 13, 21, 33. Those don't seem very related. What would be multiply the top ...
*August 10, 2010*

**Math**

Yes! Excellent!
*August 10, 2010*

**Math**

For determining sequences a good start is to look at the difference between adjacent numbers. For the sequence: 2, 3, 5, ?, 12 write the differences. This sequence is not a hard one.
*August 10, 2010*