Friday

May 22, 2015

May 22, 2015

Total # Posts: 508

**math**

Yes, you got it! 49 = 49
*May 14, 2015*

**math**

No, D is not correct. (7*7*7*7)=? (7*7)=? Divide the 4 7s multiplied by the 2 7s. What do you get
*May 14, 2015*

**math**

What did you get when you calculated 7^4/7^2
*May 14, 2015*

**math**

You're welcome!
*May 14, 2015*

**math**

Yes, you got it! 5^0=1
*May 14, 2015*

**math**

You are correct on 1. The answer is c. You are not correct on 2.
*May 14, 2015*

**PHYSICS**

What did you get when you converted the weight to kg?
*April 24, 2015*

**math**

Correct!
*March 30, 2015*

**Electricity and Electronics**

oops... I meant amps.
*February 24, 2015*

**Electricity and Electronics**

Your are correct! current for 40 volts across 12 ohms: 40V/12 ohms=3.33 smps
*February 24, 2015*

**Math**

2.5 times $4.00 is the cost to make 1 tent. So, what would it cost to make 4 tents?
*January 22, 2015*

**Math**

The first equation has y=10-2.2x Substituting that value for y into the second equation: 5x + (10-2.2x)=70 5x + 10-2.2x=70 combining... 2.8x=60 x=? Plug that value for x into the first equation to find y.
*January 4, 2015*

**Algebra 1**

When you multiplied the second equation by 2 your result is wrong. It should be: 6x + 12y=52 NOT: 6x-12y=52
*January 2, 2015*

**math**

30% of 200,000 is NOT 6000
*December 16, 2014*

**math**

Looks good!
*December 30, 2012*

**Math**

Try multiplying by a/a.
*July 2, 2012*

**Maths**

Don't forget to think about negative numbers here. What negative numbers would give you a correct answer?
*July 1, 2012*

**algebra**

Both answers are correct!
*January 13, 2012*

**Math**

Looks good!
*December 14, 2011*

**trig**

You have the right idea. one revolution is 2(pi) radians. Converting revolutions to radians: R=revolutions Revolutions in Radians=R*2(pi) So, to convert 2.8 revolutions/sec to radians =2.8(2)(pi)/sec
*December 14, 2011*

**precalculus**

With the values given, I did not find any of the answers on the graph. For a distance vs time graph. X axis is time and Y axis is distance. at t=6s, dist=5m at t=8s, dist=6m at t=10s, dist=7m at t=12s, dist=8m I don't see any of those as choices.
*December 3, 2011*

**precalculus**

For problem 2, I got A, x=-1.
*December 3, 2011*

**precalculus**

C is the answer I got.
*December 3, 2011*

**precalculus**

Problem 1. Look at my calculation, the average rate is +12,not a negative number.
*December 3, 2011*

**precalculus**

For a distance vs time graph. X axis is time and Y axis is distance. at t=6s, dist=5m at t=8s, dist=6m at t=10s, dist=7m at t=12s, dist=8m I don't see any of those as choices.
*December 3, 2011*

**precalculus**

Problem 1 A is not the answer. f(4)- f(1) =11 - (-1) = +12 -------------- Problem 3. C looks correct
*December 3, 2011*

**precalculus**

Problem 2. The answer is not B, (x=0).
*December 3, 2011*

**precalculus**

Problem 1. The answer is NOT D. The average rate of change is: for x=1, f(1)=-3 for x=4, f(4)=-3 Average rate of change is 0, not a negative number. One of the answers does give a negative average rate of change.
*December 3, 2011*

**PreAP Physics**

Yes, that's what I got, also.
*November 23, 2011*

**Help**

That's correct!
*October 28, 2011*

**Math**

Let B = the "break even" number of books. Production costs=$76,322 + B * $10 Total Sales = B * $25.50 Setting these equal... Total sales = Production costs or... $76,322 + B * $10 = B * $25.50 Solve for B
*October 28, 2011*

**MATH 7th GRADE**

1, 2, 3, 4, and 6 look OK I don't understand 5, 7 is wrong.
*October 26, 2011*

**MAT 7th GRADE**

number 4 should be +5 6 is wrong.
*October 26, 2011*

**algebra**

slope = rise/run. For a slop of 0.4 0.4 = rise/130 Solve for rise. It looks like you have accidentally moved the decimal in your line: .040=rise
*October 21, 2011*

**MATh please help**

Let D = the number of dimes. So, D + 9 = the number of nickels. Adding... D * 10 + (D + 9) * 5=135 combining 15 * D + 45 = 135 15 * D = 90 Divide both sides by 15 D = 6 There are six dimes. So, the number of nickels is 6 + 9 = 15
*October 18, 2011*

**physics**

The time is takes to slow down is T2 - T1. That is given as 3.0s.
*October 12, 2011*

**pre-calculus**

The best way to check is to substitute your answer back into the equation. SQRT(2x+1)-5=8 SQRT( (2*84)+1)-5=8 SQRT(168+1)-5=8 SQRT(169)-5=8 13 - 5 = 8 8 = 8 You are correct!
*September 20, 2011*

**Math**

Adding the items gives $460 The tax on that at 5.5% =0.055*$460 =? Add the tax to the cost of the items. That value is one of the choices given.
*September 18, 2011*

**College Math**

-5+2*SQR(12) =-5+2*SQR(4*3) =-5+2*SQR(4)*SQR(3) =-5+2*2*SQR(3) =-5+4*SQR(3)
*September 17, 2011*

**College Math**

My Alt+251 keyboard did not post as a square root--reposting...
*September 17, 2011*

**College Math**

You got the right answer! It just needed to be reduced. -5 + 2*ã(12) =-5+2*ã(4*3) =-5+2*ã4 * ã3 =-5+2*2*ã3 =-5+4*ã3
*September 17, 2011*

**Physics for Engineers**

Check part b comments on your previous post.
*September 14, 2011*

**Physics**

Using that... Y=14.47m/s(2.2s)-(1/2)(9.8m/s)(2.2)^2 Y=31.834m - 23.716m =8.118m So it clears the wall by 8.118m - 6.7m =1.418m
*September 14, 2011*

**Physics**

I get 14.47m/s for Vy.
*September 14, 2011*

**Physics**

I calculated the ball was thrown at a speed of 18.12m/s. Vx is 24m/2.2s=10.91m/s Vx=V(cos(53)) That gives V as 18.12m/s
*September 14, 2011*

**Physics**

Sorry, I see that was given.
*September 14, 2011*

**Physics**

On part b, You need to find how long it takes the ball to go th 24.0m in the x direction. Use that time for the y calculation.
*September 14, 2011*

**algebra 2**

I believe Capreeca is wrong on this one. 2x+1=3 2x=2 x=1
*July 13, 2011*

**maths**

Please note that "ina"'s answer is wrong.
*July 7, 2011*

**Algebra**

Change the 31% to a decimal value. Then multiply both sides of the equation by Q. Then get all the Q terms on one side and the number terms on the other side. Combine the terms and solve for Q.
*July 7, 2011*

**Geometry**

I think you made an error in adding the angles. In your problem angles are x, 3x, and 4x. Adding those gives 8x not 7x. Does that help?
*July 4, 2011*

**Algebra 1**

let J=Jim's age let D=Dave's age It is given that Dave can vote. So D>=18 Dave is 5 years older J+5=D or J=D-5 Jim can't vote. J<18 Substitute for Jim's age: D-5<18 Solve this for the upper limit for Dave's age.
*July 4, 2011*

**algebra 1 **

Sorry the next to last line should say to express LENGTH as a function of W. Then, solve for W.
*July 4, 2011*

**algebra 1 **

What does the problem say: Perimeter is less than 48ft. Let P=perimeter Let L=length Let W=width P<48ft Express perimeter in terms of length and width: P=L+W+L+W or L+W+L+W<48ft Express the width as a funtion of L. Substitute that value into the above equation and solve ...
*July 4, 2011*

**physics**

Yes, that is correct. I would really encourage you to carry the units through from start to finish. It seems like extra work, but it can help detect errors.
*July 2, 2011*

**math**

Yes, you are correct!
*July 1, 2011*

**math**

type LCM, least common multiple
*July 1, 2011*

**math**

I think 72 is the LCM, least common multile, not GCF, greatest common factor.
*July 1, 2011*

**Algebra**

Add 4 to both sides. Then, square both sides. Does that help?
*June 19, 2011*

**Pre-algebra**

To clarify: (-4)^4 is not equal to -256.
*March 25, 2011*

**Pre-algebra**

-256 is not the correct answer.
*March 25, 2011*

**math**

Yes! All answers are correct. Note that answer 4 could be reduced to 19/30 hours.
*March 6, 2011*

**math**

BUBBA's answers start with a wrong answer.
*March 6, 2011*

**Algebra 2**

Correcting typo The line 5 = H = 1 shoud read: 5 = H - 1
*February 21, 2011*

**Algebra 2**

My error I just reread that the first 1/2 hour is included. I am quite sure that the it is $30 for each additional 1/2 hour the equation is: Let H = the number of HALF HOURS $200 = $50 + (H-1))$30 similarly $150 = (H-1)*$30 5 = H=1 adding 1 to each side: H= 6 This is the ...
*February 21, 2011*

**Algebra 2**

I think there is some confusion here. Let H = the total hours $200 = $50 + (H-1)*$30 Remember that the first hour is included in the $50. subtract $50 from both sides $150 = (H-1)*$30 divide both sides by $30 5 = H -1 add 1 to both sides: H = ??
*February 21, 2011*

**Algebra B**

You are very welcome.
*February 16, 2011*

**Algebra B**

You're welcome, but I am not sure what you mean by reverse FOIL. First terms: x and x Outer terms: x and -5/4 Inner terms: -5/4 and x Last terms : -5/4 and -5/4 I just want to be sure you have a good understanding about the order.
*February 16, 2011*

**Algebra B**

OK, (x-5/4)^2 = (x-5/4)(x-5/4) multiplying (remember FOIL--first, outer, inner, last) = x^2 -(5/4)(x) - (5/4)(x) + (5/4)^2 = x^2 - (10/4)(x) + (5^2)/(4^2) = x^2 -(5/2)(x) + (25)/(16) Does that help?
*February 16, 2011*

**Algebra B**

Which side (left or right) is puzzling?
*February 16, 2011*

**Physics**

Be careful of units. You expressed the runway length in m (meters), but the takeoff speed is expressed in mi/h (miles/hour). You will need to do some units conversion.
*January 23, 2011*

**computer architecture**

Modern PCs have a word size of 32 or 64 bits. Early IBM PCs used an Intel 8088 which had an 8 bit data path.
*December 12, 2010*

**ALGEBRA/AM I CORRECT?**

my misspelling... You have AN eror.
*December 11, 2010*

**ALGEBRA/AM I CORRECT?**

You have and error. 3X + 240 + 36X = 6 39X = -234 X = ?
*December 11, 2010*

**Physics**

You are very welcome!
*December 7, 2010*

**Physics**

Since the moments were calculated from the end the fisherman is holding in his left hand, that force does not generate any moment.
*December 7, 2010*

**Physics**

Assuming the fishing pole is horizontal... Yes, the fisherman's left hand is exerting a downward force. You are correct.
*December 7, 2010*

**ALGEBRA**

You're welcome. Glad to help
*November 5, 2010*

**ALGEBRA**

6 is correct. However, your last step is not quite correct. starting with... 20x + 10 - 10 = 130 - 10 20x = 120 Now divide both sides by 20, not 20x 20x/20 = 120/20 x = 6
*November 5, 2010*

**math**

Yes, that answer is correct.
*November 5, 2010*

**Physics**

You are headed in the right direction. That is a distance formula when there is uniform acceleration which is gravity in this problem. The formula is: s2 = s1 + vt + (1/2)(a)t^2 where: s2 = final distance s1 = initial distance v = initial velocity a = acceleration t = total ...
*October 24, 2010*

**Physics**

How are you solving it? What answer are you getting?
*October 24, 2010*

**Algebra**

Your welcome! Glad to help
*October 5, 2010*

**Algebra**

Yes, you got it!
*October 5, 2010*

**Algebra**

Close... You have the inequality correct, but when you divided both sides by -4, you you have an error on the right side. 6/(-4) = ?
*October 5, 2010*

**Algebra**

-4x + 1 >= 7 Solve this as you would if there was just an "=" sign. But, anytime you multiply or divide both sides by a negative number the inequality sign will reverse. To get you started... Subtract 1 from both sides.
*October 5, 2010*

**algebra**

1. Make sure the equation is in the form: ax^2 + bx + c = 0, which your problem is. 2. Use the quadratic formula: x1 = (-b + (b^2 - 4ac)^(1/2))/(2a) x2 = (-b - (b^2 - 4ac)^(1/2))/(2a) You can check your answers by substituting into the original equation.
*September 5, 2010*

**algebra1**

The problem says the hours will always be over 20. The charge for the first 20 hours is $9.95. All the hours after 20 are $0.50 each. h = total monthly hours cost = $9.95 + (h - 20)x $0.50 Plug in 35 for h and what do you get?
*August 26, 2010*

**math**

Be cautious about units on this problem. The problem gives the distance in feet. Gravitational acceleration in English units is about 32 ft/sec^2 .
*August 26, 2010*

**calculus**

You got it! Glad to help.
*August 26, 2010*

**calculus**

Sorry, my error... I went the wrong way! Your exponent and coefficient are wrong.
*August 26, 2010*

**calculus**

The exponent is correct, but the coefficient is not 1. If you take the derivative of your answer do you get x^4?
*August 26, 2010*

**math**

Retyping last lines... What is 10% of the new larger salary? Subtract that to find what your salary is after the 10% cut.
*August 26, 2010*

**math**

What is 10% of $90,000? Add that to $90,000 to find your salary after the raise. What is %10 of the new larger salary? Substract that to find what your salary is after the %10 cut.
*August 26, 2010*

**algebra word problem**

r-5 being negative results in a negative t2 and so should be ignored.
*August 24, 2010*

**algebra word problem**

You are practically there! Combine terms and rearrange to get into the form: 4r^2 -90r + 275 = 0 Use the quadratic formula to find r. There will be two answers. One of the answers is the result if the canoeist reverses direction (r-5 is negative).
*August 24, 2010*

**math**

Put the equations into slope-intercept form: y = mx + b m = slope b = y intercept For your first problem... subtract x from both sides x + 8y = 16 8y = -x + 16 divide both sides by 8 y = -(1/8)x + 2 So, the slope is -(1/8) I am not sure why you set y to 0 in your solution. ...
*August 23, 2010*

**Math**

Put the equation into the form ax^2 + bx + c = 0 then use the quadratic formula to find the solutions.
*August 22, 2010*

**math**

You can put the equations into the form ax^2 + bx + c = 0 then use the quadratic formula to find the solutions.
*August 22, 2010*

**math**

The x intercept occurs where the line intercepts the x axis. The value of y at that point is 0. If you substitute 0 for y in your equation, what does x then equal?
*August 17, 2010*