Saturday
May 18, 2013

# Posts by Prakash

Total # Posts: 16

statistics
A 90% confidence interval for a population mean based on 144 observations is computed to be (2.7,3.4). How many observations must be made so that 90% confidence interval will specify the mean to within ± 0.2

stats 4
4. RBI is analyzing the total credit flow in the economy and the circulation of money in the economy. In order to formulate its annual Monetary & Credit policy, RBI is assessing the credit off take in the banking sector and has classified as low, moderate and high, according t...

stats 3
2. Collect the data pertaining to the number of customers serviced (by you or by one of the branch employees) and the number of leads generated through them during any 10 consecutive working days in February 2010. The data has to be tabulated as under. The following table pres...

stats 2
3. Piyush, who had joined the infrastructure department of the bank, was asked to estimate the rental value of commercial property at Ranchi, for the purpose of identifying suitable premises for locating a new branch. Piyush assessed the standard deviation of the value of the ...

statistics
1. Observe the number of customers visiting a particular ATM Centre during any day from March 21 to 26, 2011 between 10 a.m. – 12 noon with a time interval of 5 minutes (number of customers using the ATM every 5 minutes). Calculate the average number of customers arrived ...

sanskrit
guru shabd rop

Calculus
Hi Carol, No one will be able to solve this one. haha.

Algebra
By taking the natural logarithm of both sides: 2^(2x + 11) = 3^(x - 2) ==> ln[2^(2x + 11)] = ln[3^(x - 2)] ==> (2x + 11)ln(2) = (x - 2)ln(3), since ln(a^b) = b*ln(a) ==> 2x*ln(2) + 11ln(2) = x*ln(3) - 2ln(3), by distributing ==> 2x*ln(2) - x*ln(3) = -2ln(3) - 11ln(...

College Algebra
Use simultaneous equation method: x=-y-z-1...(1) Now, the equation 2 become: 2(-y-z-1)+2y+5z=1 -2y-2z-2+2y+5z=1 3z=1+2; z=3 Now equation 1 becomes x=-y-3-1=-y-4; i.e, x=-y-4....(a) equation 3 becomes: 5(-y-4)+2y+3(3)=8 -5y-20+2y+9=8 -3y=19; y=-19/3 Now the very first equation ...

calculus
y=f(x)= x^2-19x+x-19+7= x^2-18x-12 Find the critical value: f'(x)= 2x-18, set it equal to zero 0= 2x-18 hence, x=9 is the critical value Find the second derivative: f"(x)= 2 & f"(9)= 2, since the second derivative is positive, the function has a minimum at x=2. x...

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