I've already helped you twice. Please try some on your own, you obviously need the practice.
parallel plane: mgsin(39.5) - .330N = ma perpendicular plane: N - mgcos(39.5) = 0 <== because it is not accelerating perpendicular the plane so N = mgcos(39.5) therefore, parallel plane: mgsin(39.5) - .330(mgcos(39.5)) = ma m's cancel: gsin(39.5) - .33gcos(39.5) = a a =...
Find the real height, rather than the slant height. Use Sin Cos or Tan. Plug that value into PE=mgh solve for PE. PE=KE KE=1/2mv^2 Solve for v
Don't get caught up in the words. ([ii-x^3y^2]-(r^3)(.5d)) Plug in your values, tell me what you get.
The area A = x*y We already know that y = 2x, so we can substitute that in: A = x*2x = 2x^2 We were given that x(t) = 2t+5 A = 2x^2 = 2(2t +5)^2 A = 2(4t^2 + 10t + 25) A(t) = 8t^2 + 20t + 25 The rate of change of the area with respect to time is dA/dt dA/dt = 16t + 20 When t=2...
Your F stage vector should be 784.3m/s in a spiral is correct. My guess is you didn't take [4(pi)SA^3] when finding F (:
Third year? Try drawing all the vectors and their rates for EACH stage and see if that helps. Your final answer should be: 24.2m If you still can't get it don't be afraid to ask for an explanation.
Basic college Math
What are you supposed to be solving for? (:
Grade 12 AP calculus
your equation would be xnew = x - (x^3 - 5x - 2)/(3x^2 - 5) so for x=2 xnew = 2 - (8-10-2)/(12-5) = 2.5714 Incidentally, my next 4 answers were 2.4268029 2.4143045 2.4142136 and 2.4142136 which would be one of the answers correct up to 7 decimal places.