component of weight down ramp = mg sin(theta) friction up ramp = u mg cos(theta) where u is the coeff of friction therefore, we have mg sin(theta)- umg cos (theta) = ma or a = g(sin(theta) - u cos(theta)) so, sub 25 deg for theta, 0.7m/s/s for a and 9.8m/s/s for g and get u = ...
LOL, I got the wrong picture out the solutions manual. That's how you solve it though, just substitute the values.
msFn = Fw; Fn = 5mg; Fw = 2.25mg FwL sin 60 o = (mgL/2 + 4mgx)cos 60 o = 2.25mgL sin 60 o x = 0.85L; you can go 85% of the way to the top
The content is good but the wording is awkward.
1inches:10feet 2inches:20feet STOP
Hint, your order of steps should look like this: Synthetic division Quotient Quotient Solve All Real Zeros.
Post what you have so far (:
Equation for exponential growth/decay: y = Ce^(kt) Where y is the amount leftover and t is the time elapsed. Notice if you plug in time (4000 years) right away, you get y = Ce^(4000k), and you can't solve for y (the amount)--there's too many unknowns (C and k). So firs...
Refer to the answer I just gave you and how I solved that problem.
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