Friday

July 1, 2016
Total # Posts: 21

**Physics**

component of weight down ramp = mg sin(theta) friction up ramp = u mg cos(theta) where u is the coeff of friction therefore, we have mg sin(theta)- umg cos (theta) = ma or a = g(sin(theta) - u cos(theta)) so, sub 25 deg for theta, 0.7m/s/s for a and 9.8m/s/s for g and get u = ...
*November 19, 2012*

**Physics**

LOL, I got the wrong picture out the solutions manual. That's how you solve it though, just substitute the values.
*November 19, 2012*

**Physics**

msFn = Fw; Fn = 5mg; Fw = 2.25mg FwL sin 60 o = (mgL/2 + 4mgx)cos 60 o = 2.25mgL sin 60 o x = 0.85L; you can go 85% of the way to the top
*November 19, 2012*

**English**

The content is good but the wording is awkward.
*November 19, 2012*

**algebra**

1inches:10feet 2inches:20feet STOP
*November 19, 2012*

**college algebra**

Hint, your order of steps should look like this: Synthetic division Quotient Quotient Solve All Real Zeros.
*November 19, 2012*

**Math**

Post what you have so far (:
*November 19, 2012*

**Calculus**

Equation for exponential growth/decay: y = Ce^(kt) Where y is the amount leftover and t is the time elapsed. Notice if you plug in time (4000 years) right away, you get y = Ce^(4000k), and you can't solve for y (the amount)--there's too many unknowns (C and k). So ...
*November 16, 2012*

**math**

Correct! (:
*November 16, 2012*

**math**

Refer to the answer I just gave you and how I solved that problem.
*November 16, 2012*

**mah**

Anything to the zero power is one. So: 9(x)^0 9((2)^0) 9(1) =9 Try it with the next one. And your third problem isn't written correctly. x^??
*November 16, 2012*

**physics**

List the formulas your teacher has you use, so I can solve it using methods that you are familiar with.
*November 16, 2012*

**math**

All I did was rearrange the fractions so that the +8 would be on the other side. To get your answer you need put the fractions over each other and start eliminating like terms. Post as far as you can and I'll assist you.
*November 16, 2012*

**math**

7r^3+8/3t^4r Need an explanation let me know (:
*November 16, 2012*

**Calculus**

At the local min/max points, the derivative is zero. f' = 3ax^2 + 2bx + c = 0 Plug in x = -3 and x = 2, and that gives you two equations. Also, use f = ax^3 + bx^2 + cx + d Plug in the values (x = -3, f = 3) and (x = 2, f = 0). That gives you two more equations. Now solve ...
*November 12, 2012*

**Physics**

Draw your triangle Decide whether to use sin or cos find value dh=vht Solve for dh.
*November 12, 2012*

**math**

Not if everyone is included.(: Why? Try it yourself.
*November 8, 2012*

**algebra 2**

$1175
*November 8, 2012*

**Math**

288
*November 8, 2012*

**PHYSICS**

Post your work and I'll check it/guide you. If you're having trouble getting started try drawing a picture. Nice and BIG.
*November 8, 2012*

**physics**

Anything moving in a circle is accelerating so you can eliminate answer one. And since it's accelerating (a vector) it has a changing direction and magnitude. Hope that helps, if you want you can tell me what you got and I'll check it.
*November 8, 2012*

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