component of weight down ramp = mg sin(theta) friction up ramp = u mg cos(theta) where u is the coeff of friction therefore, we have mg sin(theta)- umg cos (theta) = ma or a = g(sin(theta) - u cos(theta)) so, sub 25 deg for theta, 0.7m/s/s for a and 9.8m/s/s for g and get u = ...
LOL, I got the wrong picture out the solutions manual. That's how you solve it though, just substitute the values.
msFn = Fw; Fn = 5mg; Fw = 2.25mg FwL sin 60 o = (mgL/2 + 4mgx)cos 60 o = 2.25mgL sin 60 o x = 0.85L; you can go 85% of the way to the top
The content is good but the wording is awkward.
1inches:10feet 2inches:20feet STOP
Hint, your order of steps should look like this: Synthetic division Quotient Quotient Solve All Real Zeros.
Post what you have so far (:
Equation for exponential growth/decay: y = Ce^(kt) Where y is the amount leftover and t is the time elapsed. Notice if you plug in time (4000 years) right away, you get y = Ce^(4000k), and you can't solve for y (the amount)--there's too many unknowns (C and k). So firs...
Refer to the answer I just gave you and how I solved that problem.
Anything to the zero power is one. So: 9(x)^0 9((2)^0) 9(1) =9 Try it with the next one. And your third problem isn't written correctly. x^??
List the formulas your teacher has you use, so I can solve it using methods that you are familiar with.
All I did was rearrange the fractions so that the +8 would be on the other side. To get your answer you need put the fractions over each other and start eliminating like terms. Post as far as you can and I'll assist you.
7r^3+8/3t^4r Need an explanation let me know (:
At the local min/max points, the derivative is zero. f' = 3ax^2 + 2bx + c = 0 Plug in x = -3 and x = 2, and that gives you two equations. Also, use f = ax^3 + bx^2 + cx + d Plug in the values (x = -3, f = 3) and (x = 2, f = 0). That gives you two more equations. Now solve ...
Draw your triangle Decide whether to use sin or cos find value dh=vht Solve for dh.
Not if everyone is included.(: Why? Try it yourself.
Post your work and I'll check it/guide you. If you're having trouble getting started try drawing a picture. Nice and BIG.
Anything moving in a circle is accelerating so you can eliminate answer one. And since it's accelerating (a vector) it has a changing direction and magnitude. Hope that helps, if you want you can tell me what you got and I'll check it.