A car covers a distance of x,while moving at 54km/1 in 15sec.Find the value of x
oin AC and DE. Triangles AFE and DFC are similar. so AF/FC = AE/CD = AE/EB also AE + EB = AB ie AE +234AE =AB so AE/AB =1/235 so AF/FC = 1/235 FC = 235 AF now, AC = AF +FC = 236AF ie AC/AF = 236/1 ie AC : AF = 236 : 1
There exists only one solution and the whole challenge is in proving the fact that there does not exist any other solution. So here we go... Let's add both these expressions. Then as per the problem, 7(a^2+b^2)=c^2+d^2 Clearly LHS is a multiple of 7 and so RHS must be a mu...
0.935 divided by 0.5
A sphere of radius 4 cm iss carved from a homogenous sphere of radius 8cm and mass 160g. the mass of the smaller sphere is
mgh=1/2mv^2 To find h sin 20= h/3 Put h and g in above equation and you are happpy :)