math
x = 2 5/6 or 17/6 ((5 13/21) - (2 11/14))
Calculus (Area Between Curves)
I got the same thing. Working out the other answers, they were either negative or obviously too large of an area for the given bounds, thank you Nade!
Calculus (Area Between Curves)
Find the area of the region bounded by the curves y=x^(-1/2), y=x^(-2), y=1 and y=3. You get: a.) 1/2(sqrt(3)) + 4/3 b.) 2(sqrt(3)) - 8/3 c.) 1/2(sqrt(3) - 32/3 d.) 2(sqrt(3)) - 32/3 e.) 8/3 - 2(sqrt(3))
logic application
4, 5, and 9. This way, you have all five odd numbers and 4+5+9=18 and 4+6+8=18 are of equal sums. Is this what you were looking for?
Calculus (Area Between Curves)
Thank you Nade for making this correction! I went back and graphed the functions with pencil to see if I could figure a rough estimate for the area. I found that these function make an odd trapezoid shape. The area of the solid trapezoid portion of the graph is 15 and then the...
Calculus (Area Between Curves)
Find the area of the region bounded by the curves y^2=x, y-4=x, y=-2 and y=1 (Hint: You'll definitely have to sketch this one on paper first.) You get: a.) 27/2 b.) 22/3 c.) 33/2 d.) 34/3 e.) 14
Calculus (Antiderivatives)
Suppose f(x) is a continuous function. Then a function F(x) such that F'(x) = f(x) is called: A.) the indefinite integral of f B.) the antiderivative of f C.) an antiderivative of f D.) a definite integral of f E.) All of the above
Calculus (Integrals)
Evaluate the following expression: d/dx (integration sign: upper=1 and lower= -3) (2t^3 + 3)dt = I am given the following options: 2t^3 + 3 56 5 -28.0 None of the above
Calculus (Integrals and Derivatives)
Evaluate the following expression: d/dx (integration sign: upper=1 and lower= -3) (2t^3 + 3)dt = I am given the following options: 2t^3 + 3 56 5 -28.0 None of the above Would the result of the expression be 0 or 5???
Calculus
Evaluate the following expression: d/dx (integration sign: upper=1 and lower= -3) (2t^3 + 3)dt = I am given the following options: 2t^3 + 3 56 5 -28.0 None of the above Would the result of the expression be 0 or 5???
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