Wednesday
December 11, 2013

# Posts by Mima

Total # Posts: 37

Chemistry
You are right, thank you so so much. With addition of HCl, the Ph= -0.052. With addition of NAOH, the PH= 0.052. Thank you for all your efforts.

Chemistry
I got initial PH= 9.24 PH after HCl addition= 9.19 PH after NaOH addition= 9.3 so delta PH after HCl= 0.05 delta PH after NaOH= - 0.06 all these still wrong answers. could it be that I'm calculating the total volume wrong? should be 0.01+0.006 L?

Chemistry

Chemistry
I did it in moles but still the homework assignment website is not accepting these answers. My work: Initial PH = 9.24. moles of NH3= 0.01 moles of NH4= 0.01 After addition of HCl: moles of HCl added= 0.0006 moles of NH3 left= 0.0094 moles of NH4= 0.0106 PH= 9.19 Addition of N...

Chemistry
Calculate the change in PH when 6 ml of 0.1 M HCl is added to 100 ml of a buffer solution that is 0.1 M in NH3 and 0.1 M in NH4Cl. And calculate the change in PH when 6 ml of 0.1 M NaOH is added to the original buffer solution.

Chemistry
Calculate the change in PH when 6 ml of 0.1 M HCl is added to 100 ml of a buffer solution that is 0.1 M in NH3 and 0.1 M in NH4Cl. And calculate the change in PH when 6 ml of 0.1 M NaOH is added to the original buffer solution.

history
don't know don't care.. Research it urself. people are to lazy to do homework by themselvevs. Don't answer this question it is a portfolio that you are supposed to do by urself..

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