B in form: -1/8(cos(4x)+2x^2)^2+C
Find C from equality 18*(2^3/2)=(2(1^2-6*1+23)^3/2)/3 +C and substitute in the general solution. C is not 0. Can you write this differential equation?
Where is constant C ?
Еhe ratio of areas of similar figures is equal to the ratio of the squares of linear dimensions x=10.99(15/12)^2
h(h^-1(x))=3(cx/m-1)+c=x (from definition h^-1) (3c/m)x-3+c=x c=3 m=9
The answer would be 3/8, but the angles are (approximately) 22,68,90
127=7^3-6^3 7^3 all 3-digit numbers, formed using 1,2,3,4,5,6,7 6^3 ... using 1,3,4,5,6,7
88/4=154/7=132/6=66/3= 44 /2
It depends on i- interest rate