Calculus
a)f(x)=(x+2)(x-1)(x-2) c)From the graph a>=2, b>=0. The equation of the tangent y=b+(3a^2-2a-4)(x-a) and if x=0 y=b-(3a^3-2a^2-4a) or y=a^3-a^2-4a+4-(3a^3-2a^2-4a) y=-2a^3+a^2+4=(2-a)(6+3a+2a^2)-8 If a>2 then y<-8 (a,b)=(2,0)
Calc
The equation of a circle with the center at origin and passing through (1,sqrt3)is x^2+y^2=2^2 The distance between the point and semicircle is the difference R1-R2=4-2=2
CALCULUS
4sin^2(x)cos^2(x)=(sin2x)^2 (sin2x/cos2x)dx=(-1/2)d(cos2x)/cos2x
calculus
B)CLOCKWISE In 1st quadrant (for ex.)dx/dt>0, so x increases; C)dx/dt=d(cos(theta))/dt= d(cos(theta))/d(theta)*d(theta)/dt= -sin(theta)*d(theta)/dx, so dx/dt=-y*d(theta)/dt =>d(theta)/dt=-1
calculus
F(x) = f(xf(xf(x))) F'(x) = f'(xf(xf(x))) d/dx xf(xf(x)) F'(x) = f'(xf(xf(x))) [ f(xf(x)) + xf'(xf(x)) d/dx xf(x) ] F'(x) = f'(xf(xf(x))) [ f(xf(x)) + xf'(xf(x)) [f(x) + xf'(x)] ] F'(1) = f'(1*f(1*f(1))) [ f(1*f(1)) + 1*f'(1*f(1)...
Math
-52 mod 13 = 0 -45-(-52)=7
calculus
3,4,5,6 2,3,6,7 2,4,5,7 1,4,5,8 1,2,7,8 1,3,6,8 1,4,5,8 (4,4,5,5)?
Calculus
We integrate by parts twice: 1)u=x^2, du=2xdx, dv=cos(x/4)dx, v=4sin(x/4) 2)u=8x, du=8dx, dv=sin(x/4)dx, v=-4cos(x/4) The answer I have already sent.
Math: Factoring
sqrt-2/3 ?
Math: Factoring
sqrt=square root?
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