Chemistry
Ok,then how do I find the dH of NaOH? Do I need to use the total heat of the system and divide it by the mass of NaOH to get its dH ? I'm still confused Thank you
Chemistry
500.0mL of 0.220 mol/L HCl(aq) was added to a high quality insulated calorimeter containing 500.0mL of 0.200mol/L NaOH(aq).Both solutions had a density of 1.000g/mL & a specific heat of 4.184 J/g.K. The calorimeter had a heat capacity of 850.0 J/degree C. The temperature of th...
Chemistry
When solving Hess law problems,do we need to use all the equations given to get the Htotal or just choose the relevant equations that are related to the final equation required? Let's say there r 5 equations given,but the relevant equations are 3 only ,so we can neglect th...
Chemistry
Given acidity constant,Ka of benzoic acid is 6.28 X 10^-5. pH of 0.15 molar solution of this acid is ? Here is my method: Benzoic acid is a weak acid,hence it dissociates very little. So: C6H5COOH---> C6H5COO- + H+ [H+] and [C6H5COO-] are yet to be calculated,so let them be...
Chemistry
So,my second method is correct isn't it? The answer is -78.4kJ?
Chemistry
But in the answer options: a) -27.4 kJ b) -72.8 kJ c) -78.4 kJ d) -84.6kJ I attempted this problem in the other way.When using the q =mcdT,I added the mass of both water and sulfuric acid. q = (300g +10.65g)(4.184J/g.K)(6.55C) = 8513.43 J Then, I calculated the mole of sulfuri...
Chemistry
But in the answer options: a) -27.4 kJ b) -72.8 kJ c) -78.4 kJ d) -84.6kJ I attempted this problem in the other way.When using the q =mcdT,I added the mass of both water and sulfuric acid. q = (300g +10.65g)(4.184J/g.K)(6.55C) = 8513.43 J Then, I calculated the mole of sulfuri...
Chemistry
When pure sulfuric acid is dissolved in water,heat is evolved.To a calorimeter containing 300g of water at 20degree C,10.65g of sulfuric acid also added at the same temperature.The change in temperature,which was monitored by a digital probe with negligible heat capacity cease...
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