Monday

December 22, 2014

December 22, 2014

Total # Posts: 10,866

**compound interest math**

calculate the compound interest on an investment of $45,000 at 6% interest compounded quarterly fro 3 years Formula for compound interest: A=P(1+i)^n A=amount at the end of n periods (future value) P=amount invested (present value) i=interest per compounding period. 6% per ...
*July 1, 2013*

**Math**

Check for type, I believe the question should read: (8/(sqrt(x)-3)) - (48)/x-9) =(8(sqrt(x)+3)/(x-9)- 48/(x-9) ... multiply top & bottom by sqrt(x)+3 =(8sqrt(x)-24)/(x-9) =(8(1/2)/sqrt(x)) / 1 ... diff. top and bottom, de l'hôpital's rule =4/3
*June 25, 2013*

**math**

4x4x4x4 =4^4 =(2^2)^4 =2^(2*4) =2^8
*June 25, 2013*

**Discreet math**

If you need a proof of the proposition/identity, please first double check the expressions. [(pvq)^(p=>)^(q=>)]=>r[(pvq)^(p=>)^(q=>)]=>r Not sure if something is missing where expression is indicated in bold. Perhaps there are other problems.
*June 25, 2013*

**Math :)**

You're welcome!
*June 25, 2013*

**Math**

Typo corrections: Area of square PRSQ - Area of ΔPDQ - area of sector RPD - Area of sector SQD. Note that sectors RPD and SQD have central angles of (90-60)=30°.
*June 25, 2013*

**Math**

We will describe the problem as follows. Two circles A,B of equal radii (r=30') are centred at P, Q, distance r apart. Points R and S on circles A, B are such that RS form a common tangent to both circles. Hence PRSQ form a square of side r. Arcs are drawn with centre P ...
*June 25, 2013*

**devry**

Divide total cost by the number of miles driven to get the average cost per mile, $773.02 / 180 miles = ? $/mile
*June 24, 2013*

**Physics (Stress & Strain)**

Area = lw (correct) =1cm x 2.5 cm =0.0100 cm x 0.025 cm =0.00025 m² (remember, length 8.1 does not come into the calculation of cross section area) Stress =force (in N)/area (in m²) =150000/0.00025 Pa =6×10^8 Pa =6×10^5 mPa =600,000 mPa Strain =...
*June 24, 2013*

**Algebraic Fractions**

6x/(12x) would be simplified just like an ordinary (numeric fraction). Look for common factors in the numerator and denominator to cancel out, separately for numeric values and variables. For the numeric part, the HCF is 6 and for variables, it is x. So divide both numerator ...
*June 24, 2013*

**Physics (Stress & Strain)**

Correct!
*June 24, 2013*

**Physics (Stress & Strain)**

Stress = force / area Load is 87500N which is just a force. You need to divide the force by the area resisting the tensile stress. Factor of safety is then ultimate stress / stress under load
*June 24, 2013*

**Physics (Stress & Strain)**

Do not forget to multiply by 10^-4 when converting cm² to m² Here we are talking about shear stress, which is dependent on the thickness and the circumference of the hole, not the area. Surface area which resists shear force is similar to the lateral surface area of ...
*June 24, 2013*

**math - please check question**

There must be a typo, because the cheapest ticket is $7, which when multiplied by 1275 gives 8925, much higher than the revenue of $2490. Assuming total of 275 tickets sold. x=number of adult tickets 275-x=number of children's tickets Then 12x+7(275-x)=2490 Solve for x to ...
*June 24, 2013*

**Physics**

So is it 30 m/s or 35 m/s? Let the initial velocity be u m/s, which remains constant while it is airborne. Time to drop down 1.5 m vertically with g=9.81 m/s^2 is given by S=(1/2)gt^2 or t=√(2S/g)=√(2*1.5/9.81)=0.553 s Horizontal distance covered before touching ...
*June 24, 2013*

**Math 61 part 2**

To solve this category of problems where you need the area/centroid of a region bounded by two curves, you need to first find TWO intersection points of the two curves by equating y1(x)=x^2 and y2(x)=2*x+3. The intersection points are at x=-1 and x=3, with y2(x) above y1(x). ...
*June 24, 2013*

**How do I solve for this??**

H (joules) =ΔT*m*Q where H=energy required (joules) ΔT=change in temperature (°C) m=mass (g) Q=specific heat in j/°C/g So heat gain =12.67 °C * 100 g * 4.180 j/°C/g =5296 j
*June 24, 2013*

**physics**

non-zero and constant.
*June 24, 2013*

**math**

Find the slope of the line that joins (0,-1) and the centroid of the parallelogram which is (8.5,4), or the mean of all the coordinates.
*June 24, 2013*

**Physics**

See: http://www.jiskha.com/display.cgi?id=1372082354
*June 24, 2013*

**Physics**

See: http://www.jiskha.com/display.cgi?id=1372082354
*June 24, 2013*

**Math**

Since 31^2=961<1000, and 32^2=1024>1000 we can have a maximum of 31 pairs of numbers whose product would be less than 1000. So the maximum number of runners would be 62.
*June 23, 2013*

**Physics (Stress & Strain)**

When you see a factor of safety over 10, it would be a good idea to check your calculations. Watch out for units conversions for areas and volumes. In converting 6.5 cm² to m², you must multiply by the (linear factor)², namely 0.01². The area is therefore 6...
*June 23, 2013*

**Physic (Stress & Strain)**

Both are numerically correct. In #2, you divide m by m, hence no units.
*June 23, 2013*

**math**

This is similar to a previous question. I believe it would do you good to plot the scatter diagram and calculate the regression line according to the formula. Post again if you have difficulties. For your information, the regression coefficient a is between 0 and 0.2, the ...
*June 23, 2013*

**statistics check :)**

You're welcome!
*June 23, 2013*

**statistics check**

I got it from summing (y-yBar)^2, and I had yBar=24.3.
*June 23, 2013*

**statistics check**

SE² is given by: [ Σ(y-yBar)^2 - [Σ(x-xBar)(y-yBar)]²/Σ(x-xBar)² ] /(n-2) I get: Σ(y-yBar)²=258.1 Σ(x-xBar)(y-yBar) = -168.7 Σ(x-xBar)²=296.9 n=10 to get se²=20.28
*June 23, 2013*

**math**

A=P[(1+i)^n -1]/i => P=Ai/[(1+i)^n -1] =1000000*(0.08/12)/((1+0.08/12)^480-1) =286.45023 per month.
*June 23, 2013*

**Please help me solve**

See http://www.jiskha.com/display.cgi?id=1372073330
*June 23, 2013*

**Please help me solve**

Multiply the temperature difference by the calorimeter constant to get the energy in joules.
*June 23, 2013*

**Phil103 Informal Logic**

I think you would be more productive if you read Chapter six before you attempt these exercises. For example: ~p∨q reads as not p or q, with the "not" applying to p only.
*June 23, 2013*

**Strength of materials**

You have posted a number of questions without your input, and most of all, without the accompanying diagrams, nor the descriptions to replace the diagrams. If you believe that we can imagine what the loading is like, you are mistaken. I suggest you concentrate on one ...
*June 23, 2013*

**Physics (Stress & Strain)**

Area 10.5cm²=10.5*10^(-4) m² Load = 5550 N Stress =load/area =5550/(10.5*10^-4) Pa =5285.714 kPa Strain: 1.1mm/1.9 m =1.1*10-3 m / 1.9m =0.000 579 (no units)
*June 23, 2013*

**math**

This is an exponential function of the form y=ae^x Substituting x,y values (20,45)into the equation, 20=160*e^(45k) take logs on both sides and solve for k k=-(1/45)ln(8) =-0.04621 So the mathematical model becomes: y(t)=y0*e^(-0.04621t) t=time in hours y0=initial mass y(t)=...
*June 23, 2013*

**Physics**

2 grams of hydrogen occupies 22.4 litres, so 18000kg=18000*1000 g will occupy 18000000/2*22.4 L =9000 m³ (at STP)
*June 23, 2013*

**maths**

See: http://www.jiskha.com/display.cgi?id=1371992237 If you do not agree with the response, please post and explain.
*June 23, 2013*

**maths**

The problem we have on hand is: Maximize |xy| subject to: f(x,y)=0 where f(x,y)=2y^2+43x^2y-6xy+5y+2x^2+48x-174.3 To solve the problem, we will solve for the extreme values of xy, and choose from the extreme values the largest value of |xy|. To do this, we would use Lagrange ...
*June 23, 2013*

**physics**

Use kinematic equation v^2-u^2=2as v=0 (at 0.8m above floor) u=unknown a=-9.81 s=0.8 u^2=√(2*9.81*0.8)=15.696 u=4 m/s approx.
*June 23, 2013*

**business math**

We do not know if it is simple or compound interest. Since compounding frequency is not mentioned, we assume it is simple interest. The simple interest formula: Future value = present value(1+ni) n=number of years, i=annual interest So 4,370.91 =PV(1+3*0.03) => PV=4,370.91...
*June 23, 2013*

**statistics**

This is a binomial distribution of n=240 trials with probability of success p=0.17 and of failure q=1-0.17=0.83. Mean=np=40.8 variance = npq=33.864 Std dev = √(33.864)=5.82
*June 23, 2013*

**math**

Divide by two until the remainder is 0 or 1. The corresponding quotients will give the powers of 2 to make up 2000. 2000/2=1000 R0 1000/2=500 R0 500/2=250 R0 250/2=125 R0 125/2=62 R1 62/2=31 R0 31/2=15 R1 15/2=7 R1 7/2=3 R1 3/2=1 R1 So 2000 in binary notation is 11111010000 or...
*June 23, 2013*

**maths**

Assuming 74.2 cm of pressure refers to the mercury column. Under standard temperature and pressure (273.15°K, 100 kPa=760.06 mmHg), the gas constant is: 62.364 L mmHg K−1 mol−1 molecular mass of N2=2*14.0067=28.0134 So volume occupied ...
*June 23, 2013*

**maths**

The solution is given for AD. Are you able to calculate AD²?
*June 23, 2013*

**maths**

I assume the last sentence is "What is AD?" since AD2 does not mean much. Hints: Use cosine rule to find ∠A, in triangle ABC. A=arccos((20²+24²-22²)/(2*20*24)) =arccos(41/80) = 59° (approx.) Then Area of triangle ABC =(1/2)AB.AC.sin(A) =(1/2)*...
*June 23, 2013*

**phy**

Do check your previous post for answers before reposting! See: http://www.jiskha.com/display.cgi?id=1371911866
*June 23, 2013*

**Physics :)**

you're welcome!
*June 23, 2013*

**Physics**

A=[5,-6.5] B=[-3.5,7] If A is perpendicular to C, then A.C=0, or C=[6.5k, 5k] (verify that A.C=0) If in addition, C.B=15, we have C.B=[6.5k,5k].[-3.5,7] =35k-22.75k =12.25k But C.B=15, therefore 12.25k=15, => k=15/12.25=60/49 Therefore C=[6.5k,5k] =[390/49, 300/49] Check my...
*June 23, 2013*

**Physics**

Ignore mass of balloon and basket. Consider 1 m^3 of hot air: mass, m = 0.93 kg net upward force, F =(1.29-0.93)=0.36 kg = 9.81*0.36 N =3.53 N acceleration = F/m = 3.53/0.93 m/s² = 3.8 m/s² Note: At this acceleration, air resistance is significant.
*June 23, 2013*

**Maths**

In the given case, since the given polynomial is of the fifth degree, you only have to try S=1,2,3,4 and up to 5. In fact: Let's factor the polynomial f(x)=n^5-17*n^3+16*n =(n-4)*(n-1)*n*(n+1)*(n+4) From this you will find the factors have the following properties: if n=0...
*June 23, 2013*

**maths**

Assume the equation has three roots a,b and c: then (x-a)(x-b)(x-c)=0 x³-(a+b+c)x²+(ab+bc+ca)x-abc=0 which means (a+b+c)=-3 (negative of coeff.of x²) (ab+bc+ca)=-7 (coeff. of x) Hence a²+b²+c² =(a+b+c)²-2(ab+bc+ca) =3²-2(-7) =9-(-14) =23
*June 23, 2013*

**maths - incomplete**

I'm afraid I do not make a lot of sense out of the the following definition: f(x2+1)1x√=x6x Kindly verify before and after posting your question.
*June 23, 2013*

**Precal**

5^(-t/2)=0.20 take log on both sides, (-t/2)log(5)=log(0.20) solve for t -t/2 = log(0.20)/log(5) t=-2log(0.20)/log(5)...isolate t =log(1/0.04)/log(5)...absorb -2 into log(0.2) =log(25)/log(5)... evaluate reciprocal =2... laws of logarithm, 25=5²
*June 23, 2013*

**Math**

The ordinary interest method is to calculate simple interest based on 360 days in a year. So interest=principal*(days/360)*rate 68.50=principal*(274/360)*6% therefore principal=68.50*(360/274)/0.06 =$1500
*June 23, 2013*

**statistics**

The answer should be a negative number as the numbers increase as x becomes smaller. The correlation coefficient lies between -0.2 and -0.3. Please post your equation for r again to see if it is interpreted correctly. Most of the time mistakes come from incorrect ...
*June 23, 2013*

**statistics**

What did you get using the given formulas 13.2 and 13.3?
*June 23, 2013*

**math**

Exact interest is based on a 365-day year. From June 30 to September 17, three months have passed. Both July and August have 31 days, while June has 30 days. So the duration of the loan is 30+31+31-3=89 days. Interest =Principal*(days/365)*0.10 =19000*(89/365)*0.10 =$463... ...
*June 23, 2013*

**Algebra 2**

Let y=kxz 98/3=k(2*7) k=98/3/14=7/3 Therefore y=(7/3)xz when x=7, z=3 then y=(7/3)*7*3=49
*June 22, 2013*

**algebra - incomplete**

I suspect you have missed out part of the question, such as: a) A∪B b) A∩B ... etc. Which is/are the "given set"?
*June 22, 2013*

**Math Algebra 1A**

I am not too sure what exactly your question is asking. If the time is elapsed since 1995, then you would subtract 1995 from the year in question. For example, 2004 is 9 years since 1995.
*June 22, 2013*

**Physics**

Assume a distance of d from the fulcrum. Take moments about the fulcrum: 350*2-540d=0 d=1.296 m
*June 22, 2013*

**Physics**

If I were to do the calculations, I would always work with stress, because ultimate stress is constant from problem to problem if the same material is used. It helps to spot errors, if any. Ultimate strength = 550 mPa. Stress under load = 64000/(7.6*10^-4) =84.2 mPa Now find ...
*June 22, 2013*

**Physics**

Required capacity of bar (in tension) =225kN*7 =1.575 MN Tensile strength = 231 MPa Area required =1.575 MN / 231 MPa =0.006818 m² =6818 mm² From πr²=6818 radius=√(6818/π) = 46.6 mm (or more)
*June 22, 2013*

**Math**

P²-0.037 = 0 P²=0.037 P=√0.037 Your calculator will give you the numerical value.
*June 22, 2013*

**maths**

A stimulating problem, combining probabilities with discrete mathematics. The question requires the probability of successively picking two balls of same colour be the same before and after adding 14 balls of a new colour. Initial situation: Assume there are n balls with k of ...
*June 22, 2013*

**math - Tom Beth & Brad**

Please do not use aliases, and do not repost within a short interval.
*June 22, 2013*

**math**

Let A = borrowed amount then A*(0.132)*2.5 years = 1320 A=1320/(0.132*2.5) =4000
*June 22, 2013*

**Math (Trigonometry)**

tan(θ)=1/4 => cos(θ)=4/√17, and sin(θ)=1/√17 Guess you can take it from here.
*June 22, 2013*

**Calculus 2**

Assume all measurements are in metres (since g is given as 9.8 m/s^2) The centre of gravity of the full tank is at 1.5/2=0.75 from the bottom. Work done is equal to the potential energy of the water at the spout (top) minus the potential of the full tank. Volume of tank, V=(&...
*June 22, 2013*

**math help**

The probability is all the question wanted. If you have a more detailed question, kindly post. We do not generally follow all your previous posts.
*June 22, 2013*

**math help**

The probability of committing a type I error is the level of significance, α. See: http://www.cs.uni.edu/~campbell/stat/inf5.html
*June 22, 2013*

**Algebra**

Polynomials with all terms in even degree are even functions, and those with all odd degree terms are odd functions. For this purpose, a constant k can be considered as k*x^0, so it is even. A mix of even and odd degree terms is neithter odd nor even. Example: f(x)=x^6+x^2+4 ...
*June 21, 2013*

**Physics**

See your other post. Try to work with stress for comparison.
*June 21, 2013*

**math**

This has been posted many times, and answered more than once by different teachers. The solution to the system of algebraic equations are: (3,1),(1,3),(-2,4),(4,-2). The maximum value of |xy| is therefore 8.
*June 21, 2013*

**math**

The solution to the system of algebraic equations are: (3,1),(1,3),(-2,4),(4,-2). The maximum value of |xy| is therefore 8.
*June 20, 2013*

**computer**

It would be more helpful if you can indicate: 1. blank means black, white or blue screen? 2. What happened during the "booting" process, i.e. since the computer is turned on. Did you see any messages (whether you are able to decipher them or not). 3. Have you tried ...
*June 20, 2013*

**math**

This seems to be a programming challenge. While this can probably be worked out in mathematical terms, it is easily shown by exhaustive search that the 3-digit number is 199, where the minimum quotient is 199/19 =10.47 approximately.
*June 20, 2013*

**diffirential calculus**

Let the height be h (constant). First find radius in terms of V, volume. Volume, V = πr²h radius, r = √(V/(πh)) So the total surface area is obtained by substituting r in the following expression: A(total) =2πrh+2πr^2 =2π√(V/(πh))(√(V...
*June 20, 2013*

**maths**

obtained by adding the two vectors: (18,0)+(3cos(40),3sin(40)) =(18+3cos(40), 3sin(40)) =(x,y) The resultant speed R is obtained by |R|=sqrt(x²+y²)
*June 20, 2013*

**Math**

Let distance be D km, and the current be C km/h His speed is 8 km/h in still water. So his speed upstream is D/3.25=8-C and downstream, D/1.5=8+C Cross multiply each to get D = 3.25(8-C) D=1.5(8+C) Solve by comparison 1.5(8+C)=3.25(8-C) Isolate C 4.75C = 8(3.25-1.5) C=8*1.75/4...
*June 19, 2013*

**maths - question incomplete**

So far, ABC is just any triangle. The addition of the altitudes do not help. If it is further specified that BD intersects the segment AC at D, and CE intersects segment AB at E, and that BD and CE are equal, then it is possible to prove that triangles EBC and DCB are ...
*June 19, 2013*

**statistics**

A two-tailed test of a=0.05 is equivalent to two tests of a=0.05/2=0.025 for each for the upper and lower tails. So for |z|>1.96 has a=0.025 (two tailed) is equivalent to z>1.96 and z<-1.96. Ref: http://www.math.unb.ca/~knight/utility/NormTble.htm
*June 18, 2013*

**math**

Here m=7.50 / shirt b=set-up fee Since we know that 2450=7.5(300)+b => b=2450-7.50*300 =2450-2250 =200 So y=7.50x+200
*June 18, 2013*

**Math**

All good to me. For number 3, I am not sure if I understand the context of the question. I interpret it to mean what variable can adversely affect the accuracy of extrapolated data, in which case I choose independent variable. If an independent variable is chosen out of the ...
*June 18, 2013*

**maths**

Distance travelled in one revolution = 2 × π × r where r is 3 cm. Distance travelled in 15 revolutions will be 15 time the above amount.
*June 18, 2013*

**computer science**

Read some of the articles on the subject, post a rough draft of your description, and we will be glad to critique your work. Some possible articles could be: http://en.wikipedia.org/wiki/Programming_language http://en.wikipedia.org/wiki/Category:Computer_languages
*June 18, 2013*

**Math**

FV=PV*(1+i)^n i=interest per period (year) expressed in fraction, =0.05 in this case. n=number of periods (year), = 12 in this case Your calculator can now be put to good use. Post for an answer check if necessary.
*June 17, 2013*

**Math**

We need to know how often interest is accrued. It is not always equal to the payment frequency. Some banks compound every 3 months, some six months, and some a year. For lack of information, we will assume that interest is compounded monthly, which simplifies the calculations...
*June 17, 2013*

**algebra**

Distance driven = 50 mph * (1/2) hour = 25 miles Distance to go = 100-25=75 miles.
*June 17, 2013*

**Physics**

acceleration =(v1-v0)/t =(34-10)/5.35 m/s² =4.486 m/s²
*June 17, 2013*

**math**

See http://www.jiskha.com/display.cgi?id=1371989906
*June 17, 2013*

**maths**

y2:x2=y1:x1 so y2=(y1/x1)*x2 =(15/9)*33
*June 17, 2013*

**math**

Height=Horiz. distance * tan(∠elev) =42*tan(36°)
*June 17, 2013*

**mathematics**

The way to proceed is: 1. plot the two points (3,-7) and (-9,21) on graph paper 2. join the two points with a straight line (using a straight-edge) 3. If the line passes through the origin, then the two ratios are in proportion.
*June 17, 2013*

**Algebra 2 ..**

(-16)^(1/4) =((-16)^(1/2))^(1/2) using rules of exponents =√√(-16) =√(4i) =√(2²i) =2√(i)
*June 16, 2013*

**algebra**

If you compare two graphs, which we don't see, you will need to describe or define the axes of the graphs. Does the x-axis represent the amount of gas consumed in gallons, and the y-axis represent the distance travelled? If that is the case, the rate of change represents ...
*June 16, 2013*

**Programming**

If you need debug help, please 1. specify the compiler/language 2. supply error messages you got when the programme was executed or compiled. 3. indicate if it is a compilation, execution or logical error. This one looks fishy: output "Enter student name or ", QUIT...
*June 16, 2013*

**math**

Choosing 3 out of 11 is given by: 11C3 =11!/[(11-3)!3!] =11*10*9/(1*2*3) =165
*June 15, 2013*

**math trigonometry**

See: http://www.jiskha.com/display.cgi?id=1371300101
*June 15, 2013*

**st.paul**

112,000,000,000
*June 15, 2013*

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