math
a^3=1/cos-cos = (1-cos^2)/cos=sin^2/cos b^3=1/sin-sin = (1-sin^2)/sin=cos^2/sin a^3/b^3=sin^2/cos * cos^2/sin=sin^3/cos^3 => a/b=sin/cos = tan (Hope you understand your own notations.)
statistics
μ=98.2 σ=0.62 Z(100)=(100-98.2)/0.62=2.903 Look up (normal) probabilities for Z=2.903 from tables (for people with temperatures below 100). Subtract from 1 to get probabilities of healthy person considered having a fever.
Mathematics
Assuming radiator reaches 120° between 0 and 4 minutes. Trying to solve: 120 = 6.2t² + 12t +32 or 6.2t² + 12t - 88 = 0 Use quadratic formula to get t=-4.8 or t=2.92 sec. Reject t=-4.8 because it is not within interval [0,4].
Algebra
1. The transformations are: e(O,2) : dilation about origin of 2 units t(0,5) : translation 5 units up r(y,-x) : rotation counter-clockwise 90° So (x,y)-> (2x,2y) -> (2x, 2y+5) -> (2y+5, -2x) So combining it all: (x,y) -> (2y+5, -2x) 2. Using Cramer's rule: ...
Physics
We are unable to help you solve the problem without guessing how the objects are configured. You can describe in detail how the objects are arranged, or post the diagram at an external site and post the link.
Math 4 questions
"at most" means ≤ "minimuum of" means ≥ "less than" means < "low of" means ≥ "high of" means ≤ You will be more likely to get an answer quickly if you show your attempts.
Algebra II Part 2
Thanks Steve, good thought!
Algebra II Part 2
use the identities: tan(x)=sin(x)/cos(x) cot(x)=cos(x)/sin(x) and sin(π/2)=1, cos(π/2)=0 sin(0)=0, cos(0)=1
ALGEBRA
Use compound interest formula: Amount = Principal * (rate)^n rate=interest rate per period n=number of periods compounded. Here rate = 1+ 0.07/2=1.035 number of periods = 3 years * 2 periods/yr principal=$7300 The question didn't say what's required.
Exponential modelling
Let the mathematical model be f(x)=ax^b where x=years past 1970. f(x)=population in millions Note: much better accuracy is obtained by shifting the origin to 1970, the closest possible. Substituting given data for 1970: 5.1=ax^0=a so f(x)=5.1x^b For 2004, 14.3=5.1(34^(b)) or ...
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