Friday

August 22, 2014

August 22, 2014

Total # Posts: 10,652

**math**

These two lines are parallel and distinct, hence there are no solutions. Show that this is the case by dividing the first one by two to get 5x+5y=515 Since both equations have 5x+5y on the left, and different values on the right, it shows that the two lines are parallel and ...
*June 11, 2013*

**math**

What do you think, and why?
*June 11, 2013*

**math**

P=principal = $3000 i=interest=0.06 n=number of 6-month periods FV=future value =P(1+i/2)^(n)
*June 11, 2013*

**ssm**

acceleration = v²/r
*June 11, 2013*

**math**

The probability of a red pen on the first draw is 4/18. For the second draw, there are 3 red pens left out of 17 pens total. The probability of both happening is obtained by multiplying the two probabilities: P(RR)=(4/18)*(3/17)=2/51
*June 11, 2013*

**math**

There are 2^10 possible subsets, including Φ, the null set. Not sure what you mean by sum of the elements, do you mean the sum of the cardinalities of the 1024 subsets, or do you mean the sum of the numbers of each subset? In the case of the latter, the distinct sums would...
*June 11, 2013*

**math problem**

Assume that the "grid" means "grid of squares" is the collection of all the squares, then we consider one square: The "safe" area for the centre of the coin is a square of 1/2"x1/2" out of a total of 1.5"x1.5". Probability is ...
*June 11, 2013*

**math**

Rewrite the word as: "ceeeffitv" we see that it is a 9 letter word in which the letters e and f repeat 3 and 2 times respectively. The number of permutations is therefore 9!/(3!2!1!1!1!1!) =30240
*June 11, 2013*

**math**

Since "education" can be written as "acdeinotu" a nine letter word without repetition, the number of permutations is 9! = 362880
*June 11, 2013*

**computer**

There are many free C/C++ compilers available. Notable ones could be Microsoft's Visual Express C++, Dev-C, Borland C/C++ compilers. Cnet has a whole section for that purpose. Note that some of the compilers listed at the Cnet site are try and buy. Here are some links: ...
*June 11, 2013*

**Probability**

P(odd)=0.75 P(even)=0.25 P(3)=0.75/3=1/4 P(6)=0.25/3=1/12 Since 3 and 6 are mutually exclusive, P(3∪6)=P(3)+P(6)=1/4 + 1/12 = 1/3
*June 10, 2013*

**Geometry**

The radius is the distance between the centre and the given point, which is r=sqrt(15^2+4^2)=sqrt(241) The circle with centre (2,-5) is (x-2)^2+(y-(-5))^2=r^2 There is only one choice that fits these criteria.
*June 10, 2013*

**Number Theory**

Yes, it works! If we solve a,b,c in terms of d, we get, a=-(d+36)/6, b=d+11, c=-(11d-24)/6 from which we can define f(x)=x^4 -(d+36)x^3/6 +(d+11)x^2 -(11d-24)x/6 +d and based on this, f(1)=10 f(2)=20 f(3)=30 f(12)+f(-8)-19000 =-608(d+36)/3 +208(d+11)+2d+2(24-11*d)/3 +5832 =840
*June 10, 2013*

**Geometry**

It is a conditional probability problem where the distribution is binomial. The general expression for conditional probability for probability of event A given event B is P(A|B)=P(A∩B)/P(B) where A = P(exactly 2 heads) B=P(at least one head) P(A∩B)=P(A) since A is a ...
*June 10, 2013*

**Algebra**

If the length and width of the pool are L and W, and the width of the path is w, then perimeter of the pool = 2(W+L) perimeter of the outside = 2(W+2w + L+2w) Difference between outside perimeter and the pool =2(W+2w + L+2w) - 2(W+L) =8w So w=(74-50)/8=24/8=3 m
*June 10, 2013*

**maths**

Use FOIL to expand (x+1)(x+2) =x²+2x+x+2 =x²+3x+2
*June 10, 2013*

**maths**

Does (x+1)3 stand for (x+1)³ or 3(x+1) ?
*June 10, 2013*

**maths**

(x+1)3=2f(x+1) Transpose the two, and switch sides f(x+1)=(x+1)³/2 Since x+1 is the argument of the function, we replace y=x+1 and express the right-hand side in terms of y: f(y)=y³/2 Therefore: f(10)=10³/2
*June 10, 2013*

**Hello? My math question was ignored?**

See http://www.jiskha.com/display.cgi?id=1370816233
*June 9, 2013*

**Math**

(x+2)(x+1)=x²+3x+2 Multiply by 9: 9x²+27x+18 Now put it all together: 9x²+27x+18 -2x-2 -4x-4 = 0 group like terms: 9x²+21x+10=0 The next step is to factorize the expression by grouping: Find m, n such that m+n=21, m*n=90 so m=6, n=15 9x²+6x +15x+10 = 0 ...
*June 9, 2013*

**Algebra II**

There are infinitely many of them. Are you given a list of choices?
*June 9, 2013*

**Math**

Let ω=angular velocity (rad/s) To offset gravity, the centripetal force must offset gravity, g, or rω²=g Solve for ω.
*June 9, 2013*

**French**

The difference between the two sentences is the adjective "vert", which varies according to gender and number vert (masc. sing.) verte (fem. sing.) verts (masc. plur.) vertes (fem. plur.) Since herbe is a feminine noun in singular, you will choose the adjective , and...
*June 7, 2013*

**Math check and question**

What did you do for #a? P(n=1, x=0, p=0.15) =nPx 0.15^0((1-0.15)^(1-0) =1!/(0!1!)(0.15^0)(0.85)^1 =1*1*0.85 =0.85 For #b, P(n=3,x=3,p=0.15) =3P3 (0.15^3)(1-0.15)^(3-3) =1*(0.003375)(0.85^0) =0.003375 Check out the other numbers using P(n,x,p) =nPx (p^x)(q^(n-x)) where q=(1-p)
*June 6, 2013*

**Algebra**

Solve the equation -16t^2+20t+6 = 0 will give you the times that the ball is on the ground. The negative root accounts for the fact that the ball is 6 feet above ground at t=0. I get t=3/2 and t=-1/4
*June 6, 2013*

**C++**

C++ is just another programming language. If you have already programmmed in other languages, switching to C++ will not be difficult. On the other hand, if you are programming for the first time, you will be learning two things at the same time: programming concepts, and the C...
*June 6, 2013*

**Calculus**

Volume of pyramid =area of base * height /3 For a square base of side s, Volume =(s²h)/3
*June 5, 2013*

**Calculus**

e^x is non-negative, so the volume is the definite integral from 0 to 10 of I=∫A(x)dx =0.01*10e^0.01x =0.1*e^0.01x evaluated from 0 to 10
*June 5, 2013*

**maths**

f(208)=208/207+208/207×206/205+208/207×206/205×204/203+… =208 This can be obtained by induction: Let f(n) be the function such that: f(n)=n/(n-1) + n/(n-1)*(n-2)/(n-3) + … n/(n-1)*(n-2)/(n-3)…(2/1) where n is even. Then f(2)=2/1=2 f(4)=4/3+(4/3...
*June 5, 2013*

**maths**

Do you agree with the following response? http://www.jiskha.com/display.cgi?id=1370323034
*June 5, 2013*

**probability statistics**

Assume population height follows a normal distribution N(μ,σ), then the top 4% falls above μ+1.75σ (approximately) as read from the normal distribution table.
*June 4, 2013*

**Math**

3/5-2/5=1/5 So proportion is 1/5 of the class equals 12 students So the whole class is 5*12=60 students. # of Girls = 60*2/5=24
*June 4, 2013*

**math**

Volume = 256 m³ Let base = x by x m height = 256/x² Surface area = x²+4(x)(256/x²) =x²+1024/x differentiate with respect to x and equate to zero for extremum: 2x-1024/x²=0 x=8 So the box size is 8x8x4 high Note: I have assumed that the base area ...
*June 4, 2013*

**algebra1**

Remove the first set of parentheses with no change of the contents. Remove the second set of parentheses but change the sign of each term in the parentheses, since the parentheses are preceded by a negative sign. (3x^2-2x-1)-(5x^2-4x-2) =3x^2-2x-1-5x^2+4x+2 Now group like ...
*June 4, 2013*

**math 7**

experimental probability = (no. of successes) / (total number of trials) =8/20 =2/5
*June 4, 2013*

**comptuer programming**

There are quite a few things to note. I believe your hour rate is multiplied by 1.5 only for those hours exceeding 40 hours. The way you're doing it, it will never get changed because the hour rate is changed AFTER you calculated the total. Don't know what you want to ...
*June 4, 2013*

**maths - typo**

Please check you post. I think 4.2 m is not the right length because if you add any two sides of a triangle, it should be greater than the third side. Here 4.2+(hypotenuse-14)=hypotenuse-9.8 which is shorter than the hypotenuse. It probably reads 42. Let x=length of the other ...
*June 4, 2013*

**Maths**

I have a winning strategy, but perhaps there are others. Draw a line of symmetry to split the game into two identical games. Whatever the next player does, you would do the mirror image. Therefore you will end-up splitting the last rectangle. Based on this, there are only two ...
*June 4, 2013*

**Math**

Let O = centre of circle Γ, then ∠PAO=90° Consider ΔPAC, use sine rule to find ∠PAC, which equals 13° (approx.). ∠CAO is therefore 90-∠PAC and equals 77° approx. Since Δ CAO is isosceles, with congruent legs equal to the radius r ...
*June 4, 2013*

**Math**

Let O = centre of circle Γ, then ∠PAO=90°
*June 4, 2013*

**Math**

I have one feasible solution, not sure if it is optimal. You can find others for a check along the same lines. C=4, 3 factors: 1,2,4 B=6, 4 factors: 1,2,3,6 A=12,6 factors: 1,2,3,4,6,12 N=72,12 factors: 1,2,3,4,6,8,9,12,18,24,36,72
*June 4, 2013*

**Math**

brake. Use the kinematics equation v2²-v1²=2aS v2=final velocity v1=initial velocity S=distance travelled a=uniform acceleration. I get approximately 20 m/s if I assume you mean deceleration of 4.5m/s or acceleration of -4.5 m/s. Deceleration of -4.5 m/s will ...
*June 3, 2013*

**Velocity**

v^2 = 11m/s + 2 * 9.81m/s^2 * 60 should read: v =sqrt( 11m/s ² + 2 * 9.81m/s^2 * 60 ) I get about 36 m/s
*June 3, 2013*

**math**

x=Bessy y=Bob x=6y (Bessy has 6 times as much as Bob) x+6=3(y+6) (when each earns $6, Bessy will have 3 times as much money as Bob) Solve for x and y
*June 3, 2013*

**math**

The only right triangle that I know of which has the side lengths form an arithmetic sequence is (3,4,5) or multiples thereof. If the 8 cm leg is the shortest side, then we can find the remaining sides by proportions, namely 8 cm, 8*4/3=32/3, 8*5/3 = 40/3 If the 8 cm side is ...
*June 3, 2013*

**Math**

A=cost of adult ticket C=cost of child ticket 9A+2C = 252 A=C+6 Use substitution 9(C+6)+2C = 252 9C+2C = 252-54 11C = 198 C=18 A=C+6=24 Check: 9A+2C=9*24+2*18=216+36=252 OK
*June 3, 2013*

**pcm**

I assume you mean what is the minimum possible value of f(75p²). Is it known if p is greater than 5? If it is, would it be the number of distinct factors of 75 multiplied by 3 (6*3)=18, namely 1,3,5,15,25,75, then multiply each one by p, and then multiply each one by p&...
*June 3, 2013*

**tech III math ( ACT Prep)**

You need the LCM (lowest common multiple) of the two numbers. Here's a systematic way to find the LCM between two numbers. In the following calculation, the number on the right is a common factor. Extract a common factor on each line (write on the right). Then divide each ...
*June 3, 2013*

**Statistics**

Binomial distribution, n=10 p=0.28 q=1-0.28=0.72 mean=np variance=npq std dev=sqrt(npq) Exactly r successes =P(r) =nCr p^r q^(n-r) Work out each of the above problems and you will find a match. For example, the first one: P(no more than 3 tails) =P(0)+P(1)+P(2)+P(3) =0.037+0....
*June 2, 2013*

**To Sarah: please do not multiple post the same question **

Sorry for having misspelled your name.
*June 2, 2013*

**To Sara: please do not multiple post the same question**

There are people on earth who work with 56kb Internet connections, which means that the 3 seconds that you take to make each of the quintuple posts, it could take up to 3-4 minutes for others to just to display it. The Air America problem is a multi-step experiment, where ...
*June 2, 2013*

**algebra**

xy=36 x+y=26/2=13 Since 4*9=36 and 4+9=13 we have the sides of the rectangle as 4 and 9 yards.
*June 2, 2013*

**algebra 2**

Use the given formula i=500 mg r=(1-0.25)=0.75 (fraction of what remains) t=6 hours e=base of natural log a(t)=amount left after t hours in mg. a(t)=i e^(rt)
*June 2, 2013*

**algebra**

By proportion, you get 2.5%-1%=1.5 1%-0.25%=0.75 Ratio=1.5:0.75=2:1 To make the mixture, we use the inverse of the ratio, therefore Mixture=1:2, or 120g of 2.5% and 240g of 0.25% make 360g of 1% (assuming both have same density). Check: (120*.025+240*.0025)/360=1% You can also...
*June 2, 2013*

**physics**

Hint: Calculate the time it takes to reach the lower roof, say t (in seconds), by solving for t in: (100-25)=(1/2)gt² The minimum horizontal velocity will be 20/t m/s
*June 2, 2013*

**Math check**

Check your calculations! Did you get standard deviation or σ² as 2.88? Don't understand how you got 2.88 and 10.58. Can you post what you did? For the variance, I have 1.49+0.09+0.00+0.14+1.39=3.1
*June 2, 2013*

**Math check**

First step: Check to see if it is a discrete probability distribution by summing all probabilities. If it does not equal one, either the given distribution is incomplete, or it is not a discrete distribution. Second step: Mean (expected value of X, E(X), μ) =ΣX*P(X) =...
*June 2, 2013*

**statistics**

Let D=event that a television selected is defective and ~D=event that a television selected is NOT defective Then probability that both are not defective: P(~D~D)=(5/9)(4/8)=5/18 Therefore at least one defective is its complement P( (~D~D)') = 1-5/18 = 13/18
*June 2, 2013*

**Math**

Follow the same strategy as the previous problem, we make use of given information and deduce values by expansion. Let f(x)=x^2+(a+6i)x+b+12i=0 and given that f(x) has a repeated root, we deduce that the discriminant is zero, i.e. (a+6i)²-48i=0 which expands to a²-4b...
*June 2, 2013*

**Math**

Let z=a+bi where i²=-1 then z²-26z =-b²-26a + (2a-26)bi Since is real, and z is non-real, therefore b≠0, and consequently (2a-26)bi = 0 => 2a-26=0, => a=13 Thus z=13+bi, z(conjugate) = 13-bi so z+z(conjugate)=13+bi+13-bi=26
*June 2, 2013*

**Math**

Overall loss, neglecting benefit from use of the car, is loss = $20,000 - $18,200 = $1800 It is a loss because he ended up with less money than the start.
*June 2, 2013*

**Calculus**

Define the surface as: f(x,y,z)=xy^2+zy^2+4y-xz^2-18=0 Then check that P0(-2,0,3) is on the surface by evaluating f(-2,0,3) and confirm that it is zero. Let fx,fy,fz be the partial derivatives of f(x,y,z) with respect to x,y and z respectively, and evaluated at P0(-2,0,3). The...
*June 2, 2013*

**math check**

Your answer corresponds to P(-0.25<z<0). Look up a probability table (or use your calculator) for +1.32. Many normal probability tables are one-tail from -∞ so you need to subtract 0.5 from the result, taking advantage of symmetry of the normal distribution.
*June 2, 2013*

**check math**

Correct!
*June 2, 2013*

**check math**

Your answer corresponds to at least one boy in a family of 6. Retrace what you did and work it out for a family of 8. "At least one boy" corresponds to "NOT all girls". So calculate the probability of having all girls in the family, and subtract from 1.0 to...
*June 1, 2013*

**math**

Sale price = normal price *(1-markdown) =$2.77(1-0.22)=$2.16 It must have been a while back since Macy's sold a designer jacket for $2.77.
*June 1, 2013*

**Math check my answer**

Since we are talking about costs, a better deal is a lower cost, so the inequality should read: .80x + 29 < 1.19x + 17 The answer is almost perfect... 30.769 rounds to 30.8, although in this case, it does not count because we are talking about integers.
*June 1, 2013*

**math**

Work with the "weighted mean". For each pound, cost of meat powder = 0.4*1.20 = 0.48 cost of grain = 0.6*0.80 = 0.48 Total cost per pound = 0.48+0.48 = $0.96
*June 1, 2013*

**programming**

What have you done so far, and how would you like us to help? Can you show us your pseudocode?
*June 1, 2013*

**arithmetic**

Set up a table of outcomes and the corresponding probabilities to create the probability distribution. For example, the lowest outcome is X=2 (=1+1) with probability 1/36. then X=3 (1+2 or 2+1) with probability 2/36 ... X=12 (=6+6) with probability 1/36. Find the mean using E(...
*June 1, 2013*

**arithmetic**

Did you read your other post? http://www.jiskha.com/display.cgi?id=1370132243 Set up a table of outcomes and the corresponding probabilities to create the probability distribution. For example, the lowest outcome is X=2 (=1+1) with probability 1/36. then X=3 (1+2 or 2+1) with ...
*June 1, 2013*

**probability**

Create the probability distribution for the random variable X (see other post), and sum probabilities of all outcomes greater than 7.
*June 1, 2013*

**Math**

For 23)(ii) I have σ=√(npq)=√(379*0.15*0.85)=6.95 For 24(ii) p=0.89, q=1-0.89=0.11 σ=√(npq)
*June 1, 2013*

**Math**

17% are left-handed means P(left-handed)=0.17 (remember 17%=17/100=0.17) so N=59, p=0.17, q=1-0.17=0.83 you can take it from here!
*June 1, 2013*

**Math**

For a binomial distribution with N bernoulli trials with probability of success p (i.e. failure q = 1-p), the following properties can be proved: mean = Np variance = Npq Take the square-root of variance to get standard deviation. In 15 tosses of a fair dime, N=15, p=0.5, q=1-...
*June 1, 2013*

**math answer check**

I don't know to which question 0.0675 referred. Note that: nCr = n!/[(n-r)!(r!)] For (e), we have P(n=3,x=1,p=0.45) =3C1*0.45^1*(1-0.45)^(3-1) =3*0.45*0.55^2 =0.408375 (f) probabilities never exceed 1! P(n=6,x=6,p=0.25) =6C6*0.25^6*(1-0.25)^(6-6) =1*0.25^6 =0.000244
*June 1, 2013*

**math answer check**

For a binomial distribution, the outcomes are either 1 (success) or zero (failure). The probability of success (outcome =1)of EACH step (out of n steps) is p and remains unchanged over the duration of the experiment. The probability of failure (outcome =0) of EACH step (out of...
*June 1, 2013*

**Math**

Hint: cot^2(x)=cos^2(x)/sin^2(x) =(1-sin^2(x))/sin^2(x) =1/sin^2(x) - 1 cos(x)dx = d(sin(x)) so use the substitution u=sin(x), then du=cos(x)dx cot^2(x) cos(x)dx =(1/u^2 -1)du =(-1/u - u) + C backsubstitute u=sin(x) I=-1/sin(x)-sin(x)+C
*June 1, 2013*

**math-probaility**

Use complementarity. Calculate the probability of getting no lemon, and subtract from 1. Two-step experiment, second step dependent on the first: Total number of candies at start=5 Step 1: Number of grapes=2 Probability(No lemon)= 2/5 Step 2: Number of candies left=4 Number of...
*June 1, 2013*

**Probability**

Expectation = ΣxP(x) where x represents the gain from each of the outcomes in the sample space. Here the gains and probabilities are: outcome=oil gain=375000-25000=350000 P(oil)=1/40 xP(oil)=8750 outcome:gas gain=130000-25000=105000 P(gas)=1/20 xP(gas)=5250 outcome:...
*June 1, 2013*

**Algebra**

Hint:Use the compound interest formula Future=present*(1+i)^n Here Future=40000 n=30 i=0.06 (6%) Solve for Present.
*June 1, 2013*

**heeeeeeeeeeeeelp math**

You were quite right, Andrew. The answer should have been (4!)^4/(4!)² 4! is the number of ways to assemble a single body part. Since there are 4 body parts to assemble, we have (4!)^4 ways to assemble the 4 people where order counts. Since there are 4! permutations of ...
*June 1, 2013*

**Algebra**

There is a rule for this class of problems of finding proportions of mixtures. Most of the time this can be done mentally, for example by chemists or nurses. We have one ingredient A at 20%, and B at 60%. The required mixture is 30% (must be between those of A & B). Take the ...
*June 1, 2013*

**math**

There has been quite a few problems solved on markup based on selling price. This should give you (or others) another example to work on your other problems. retail price = selling price. If there is a 55% markup based on selling price, then the cost price is 100-55=45% So the...
*May 31, 2013*

**Algebra 1**

1. Use the distance formula: distance = (4-1)²+(a-1)²=5² Solve for a (a quadratic equation) 2. Use Pythagorean formula: 8²+b²=14² Solve for b. 3(a) 7²+9²=49+81 = 130 ≠ 12² Therefore the three sides do not form a right triangle. ...
*May 31, 2013*

**Math :)**

You're welcome!
*May 31, 2013*

**Math**

This is a discrete probability function which has the following characteristics: 1. The function is non-negative throughout its domain. 2. ΣR(i)=1 for i∈ domain From the given data, R(0)=0.2 R(1)=0.2 ... R(4)=0.2 for a sum of 1.0.
*May 31, 2013*

**Geometry**

The largest area a given perimeter can enclose is a circle. The largest area of a rectangle for a given perimeter is a square. The question did not specify that the area be a polygon, so the circle gives the largest area. 2πr=18 r=18/2π=9/π Therefore largest area =&pi...
*May 31, 2013*

**math**

Selling price = cost + markup = 47.5 + 34 = $81.50 Mark-up base on cost = mark-up/cost = 34 / 47.5 = 71.6%
*May 31, 2013*

**Math :)**

You're welcome!
*May 31, 2013*

**Math**

Therefore 120 more workers are needed.
*May 31, 2013*

**Math**

Each person accomplishes 1/3÷(60*18) of the project, 1/3240 per person per day. To finish 2/3 of the project in 12 days, Total number of workers need =2/3 ÷ (12*(1/54) =(2/3)*(3240/12) =180 Therefore 120 more workers are needed.
*May 31, 2013*

**maths**

If the original question has a unit of 8m/min., I prefer to give the answer in minutes. The question did not say to answer in hours, and did not say you have to round to the nearest hour. But it is up to you.
*May 31, 2013*

**maths**

Distance travelled =8-(-475) =483 m Speed = 8 m / min. Time = Distance ÷ speed =483÷8 =60.375 minutes
*May 31, 2013*

**Aviation**

See if this link helps answer your question: http://en.wikipedia.org/wiki/Cessna_162_Skycatcher#Specifications
*May 31, 2013*

**Math**

Hints: P(A∪B)=P(A)+P(B)-P(A∩B) If A and B are mutually exclusive (ME), then P(A∩B)=0. This should take care of (d)
*May 30, 2013*

**math**

Nora 4: Hint for you. If you provide attempted answers to the question, do add "(answer check)" to the end of "school subject", especially if you have a whole series of questions which makes it look it homework dumping.
*May 30, 2013*

**math**

Hints: Work out the following: - equal numbers of red marbles and yellow marbles (call x=number of red x=number of yellow - twice as many green marbles as red marbles 2x=number of green Now work out the sample space and the corresponding probabilities.
*May 30, 2013*

**Math**

142=58-7x Add 7x to each side 7x+142=58-7x+7x 7x+142=58 Now subtract 142 from each side to isolate x 7x+142-142=58-142 7x=-84 Divide by 7 to find x 7x/7 = -84/7 x = -12 Now you should be able to try the remaining problems the same way as above and post your answers for checking.
*May 30, 2013*

**Math**

1711 sales out of 1950 calls. The success rate is quite impressive: 1711/1950=87.7%
*May 30, 2013*

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