Friday

July 3, 2015

July 3, 2015

Total # Posts: 11,301

**Geometry**

Sorry. In that case, we make use of the fact that rhombuses have diagonals which intersect at right-angles. Thus each side is the hypotenuse of a right triangle with legs equal to the half-diagonals. Thus if s=length of each side of the rhombus, then s²=(AC/2)²+(BD/2...
*June 3, 2014*

**Geometry**

A quadrilateral with all four sides equal is a rhombus, whose area is half the product of the diagonals AC and BD.
*June 3, 2014*

**physics**

weight = 11.2 N = mg => m=11.2/9.8 = 1.143 kg new weight = 13.1 = m(g+a) a=13.1/1.143-9.8=1.661 m/s²
*June 3, 2014*

**math -logarithm**

729=9³ log9729 = 3 25 = (1/5)-2 log(1/5)25 = -2 for a=bc² rearrange to (a/b) = c² and proceed similar to above.
*June 3, 2014*

**math -logarithm**

x=log1010000 10x=10000 therefore x=4, or log1010000=4
*June 3, 2014*

**Math - Data Management**

Binomial distribution gives us 5C2*(.5)²(.5)³ =10(.5)^5 =0.3125 E(x)=2400*0.3125=750
*June 3, 2014*

**physics**

vf=vi+at a=-0.08 m/s² vi=1 m/s t=4 s
*June 3, 2014*

**physics - insufficient information**

Graph is a necessary ingredient of this question.
*June 3, 2014*

**physics**

Δx = vi*Δt+(1/2)aΔt² vi=0 so Δx = (1/2)aΔt² a=2Δx/Δt² =2*420/(32²) =(105/128) m/s² vf=aΔt =(105/128)*32 =26.25 m/s (not extremely fast for a plane)
*June 3, 2014*

**Physics :)**

You're welcome!
*June 3, 2014*

**Physics**

Correct.
*June 3, 2014*

**physics**

Her resultant speed is perpendicular to the flow of the river. Thus resultant velocity, using Pythagoras theorem, V=√(1.2²-0.8²) =√(0.8) =0.8944 m/s Time to cross river =550m/0.8944 m/s =614.9 s =10 minutes 15 seconds, approx. to cross as rapidly a ...
*June 3, 2014*

**Physics - correction**

Power = VI watts
*June 3, 2014*

**Physics**

V=IR I=V/R=45/15000=3*10-3 A. Power = VI joules
*June 3, 2014*

**statistics**

min/max number of people hired =50,80 Best estimate of number of people hired =(50+80)/2=65 Best estimate of people who speak English only = 0.75*65=48.75, or approx. 49 persons Note that sometimes the "best estimate" is interpreted as mean, which often is the best ...
*June 3, 2014*

**Math**

Assuming the question requires the zeroes of Y(x). Multiply by 50 (to get integer coefficients) 50*y(x)=-x²+65x+400=0 Solve by quadratic formula: x=(-65±√(65²+1600))/-2 =5.66 or 70.66 approximately
*June 3, 2014*

**statistics**

If all students take at least one of the subjects, then no one took both, because 84+16=100.
*June 3, 2014*

**Physics**

Area swept by turbine = 2000 m² Wind speed, v = 10 m/s mass of air through turbine, m = Volume of air * density = 2000 m² * 10 m/s * 1.3 kg /m³ = 26000 kg/s Raw power = kinetic energy available /s = (1/2)mv² = (1/2)*26000 kg/s * (10 m/s)^2 J/s = 1.3 MW With...
*June 3, 2014*

**math HELP!!!!!!**

This is an experimental probability project. Ideally you will need a 10-sided die (can get from toy/game stores) in the shape of a duodecahedron (10 identical faces), and proceed as described. The more trials you make, the closer it should approach the expected values, i.e. 10...
*June 2, 2014*

**Physics HELP ME PLEASE**

Newton's second law says "Force = mass × acceleration". Here acceleration = (27-11)/5.4 m/s² mass = 1250 kg So you can find the force accordingly.
*June 2, 2014*

**math :)**

You're welcome!
*June 2, 2014*

**math**

Assuming you mean A= -3(a + b - (1/3)c) when parentheses are used correctly. Divide both sides by -3, and swap sides a+b-(1/3)c = -A/3 -(1/3)c = -A/3-a-b Divide both sides by -(1/3) c = A+3a+3b
*June 2, 2014*

**Physics I NEED HELP BADLY :)**

You're welcome!
*June 2, 2014*

**Physics I NEED HELP BADLY**

Airplane speed = <270,0> (components in the x,y directions) Wind speed 75 km/hr eastwards =<75,0> Resultant speed = <270,0>+<75,0> = <345,0> = 345 km/hr eastwards. Wind speed blowing 75 km/h west Resultant =<270,0>+<-75,0> =<195,0&...
*June 2, 2014*

**physics**

If the acorn fell from rest, equate energies mgh=(1/2)mv² h=v²/2g =100/(2*9.8) =5.1 m Time =v/g =10/9.8 =1.02 s
*June 2, 2014*

**Physics**

Assuming it is a 20 m bridge. Initial vertical velocity = 0 time to reach base = t then t=√(-2Δy/g) =√(2*20/9.8) =2.02 s Horizontal distance =2.02*35 m/s =70.7 m approximately
*June 2, 2014*

**Physics**

Distance between wave crests, λ = wave length = 2 metres Time complete one wave = period = 60 s / 20 waves = 3 s Frequency f is number of waves per second = (1/3) Hz Speed = f * λ = (1/3)Hz * 2m =2/3 m/s
*June 2, 2014*

**Algebra**

Next easiest is by comparison. Solve the quadratic by factoring -3x+5 = x² +2x -45 x²+5x-50=0 (x+10)(x-5)=0 x=5 or x=-10 Substitute x to find corresponding values of y.
*June 2, 2014*

**Algebra**

Find the vertex of the parabola by completing the square: h(t)=-16t²+20t+6 =-16(t²-2(5/8)t+25/64)+6+25/4 which means that the vertex is at t=5/8 and it will hit the ground at h(t)=0, or t=3/2 s (rejecting negative root). Maximum is at the vertex, or h(5/8)=49/4 ft.
*June 2, 2014*

**Which one is correct?**

Eden is right. Multiplying two numbers with the same base is the same as adding the exponents.
*June 2, 2014*

**Algebra/can you help me**

log710 =log(10)/log(7) =1.183294662454939 approximately (use your calculator) I'll leave the other problem for you to practise.
*June 2, 2014*

**physics**

Some characters are not properly displayed on my computer, I assume it to be: A particle moves along the x-axis from an initial position xi to a final position xf. Of the following values of xi and xf, which results in a negative displacement? (a) xi = 6 m, xf = 4 m (b) xi = -...
*June 2, 2014*

**Math**

The starting number (initial value, or y-intercept) is not subject to the power, so the rule for the function is y=2(3)^x year 0: 2(3)^0 = 2 year 1: 2(3)^1 = 6 year 2: 2(3)^2 = 18 ... year 6: 2(3)^6 = 1458
*June 2, 2014*

**Math**

{L,M} is the Ω (sample space) for one single draw. When there are two draws one after another with replacement, the sample space will contain LL LM ML MM
*June 2, 2014*

**Physics**

Ignoring air resistance, equate potential and kinetic energies: mgh = (1/2)mv² Cancel m, v=√(2gh) =√(2*9.8*15) = 17.1 m/s
*June 2, 2014*

**science**

Please look up a diagram of the parts and then give a try at the answer.
*June 2, 2014*

**geometry**

The area can be found by using cross multiplication of elements in a rectangular matrix formed by the coordinates of the 4 (or any number) points. Let P be a 5x2 matrix, where the columns represnt the x and y coordinates. Rows 1 to 4 represent the (x,y) ordered pairs of the 4 ...
*June 2, 2014*

**physics**

Gravity acts on bodies of mass m with a force of mg equal to its weight. g is the acceleration due to gravity. The given weight is 10N, so gravity is already included, and the net force acting on the table is 10N.
*June 2, 2014*

**rounding to the nearest meter**

51 is the nearest metre, and 51.4 is the nearest tenth of a metre.
*June 2, 2014*

**jill**

Future value, F = 5*125000=625000 Interest, i = 6% annually = 0.06 compounding frequency, f = 2 Time, t = 2.5 years Let P = present value then use the compound interest formula F=P(1+i/f)ft Solve for P P=F/(1+i/f)ft =625000/(1+0.06/2)2*2.5 =539130.49 =
*June 2, 2014*

**Kirr**

Please do not use more than one name for your posts.
*June 1, 2014*

**jill**

Isn't 1500 already the present value? Could you double check to see if there is a typo?
*June 1, 2014*

**physics**

Distance = speed * time = (1.25*speed)*((1/1.25)*time) = 25 min./1.25 = 20 minutes
*June 1, 2014*

**helppppp math helppp!**

Future value, F Interest, i = 0.045 compounding frequency, f = 12 Time, t = 3.5 years Let P = present value, = 250000 then use the compound interest formula F=P(1+i/f)ft
*June 1, 2014*

**physics**

Horizontal component of the normal force.
*June 1, 2014*

**Physics**

Use Ek=(1/2)mv² Equate Ek=mgh h=height
*June 1, 2014*

**Physics**

Good, so Frictional force = ma = 1kg (-2.5)m/s² = -2.5 N Normal reaction =mg =1kg * 9.8 m/s² =9.8 N Coefficient of kinetic friction = Frictional force / Normal reaction = -2.5 / 9.8 = 0.255 (omit sign).
*June 1, 2014*

**trigonometry, check my answer please?**

It doesn't sound right when you have a 15 ft. ladder leaning against a wall with the foot of the ladder 36.9 ft away. So you need to recheck your work when it does not look right. The length of the ladder is the hypotenuse of the right triangle. The base of the ladder is ...
*June 1, 2014*

**Math**

Work on the left-hand side first: csc60 cot30 tan60 =(1/sin60)(tan60)(tan60) =(1/sin60)(tan²60) =(1/sin60)(sec²60-1) =(2/√3)(2²-1) =2√3 Work on the right-hand side: 2sec²45cos30 =2(2/√2)² (√3)/2 =8/2 (√3)/2 =2√3 Thus...
*June 1, 2014*

**Geometry :)**

You're welcome!
*June 1, 2014*

**Geometry**

Assuming my interpretation of the word "back" is correct, I said: "... because we usually consider the positive x-axis as going forward" so it would be A.
*June 1, 2014*

**Geometry**

A sphere has infinite planes of symmetry, a cube does not. All the given choices (A) to (C) are solids. A polygon is a plane figure. We cannot make a solid out of plane figures. We can make faces of polyhedrons out of plane figures, but that's not what the question is ...
*June 1, 2014*

**Geometry**

If you notice that all the coordinates of the image are half the corresponding values in the pre-image, this means that the transformation is a contraction about the origin, with a factor of 0.5.
*June 1, 2014*

**Algebra 1**

Slope of segment, a = (y2-y1)/(x2-x1) = (8-4)/(6-2)=1 Mid-point =( (x1+x2)/2, (y1+y2)/2 ) =( (2+6)/2, (4+8)/2 ) = M(4,6) Slope of line perpendicular to segment,a1 = -1/a = -1/(1) =-1 Equation of perpendicular line: (y-y1)=a1(x-x1) y-6 = -1(x-4) or y=-x + 10 Check that it goes ...
*June 1, 2014*

**Math**

For every 100 people, there were 40 men 30 women 30 children. Use proportion to figure out the number for 2400 people.
*June 1, 2014*

**Algebra**

Sum and difference: (sum+difference)/2 = larger number (sum-difference)/2 = smaller number
*June 1, 2014*

**math**

1 foot = 0.3048 m (exactly) so 1 m² = (1/0.3048)² ft². Area of rectangle = 48 m × 24 m = 1152 m² = 1152/0.3048² ft² = 12400.0 ft² (approximately)
*June 1, 2014*

**Physics**

The picture is not complete. Are the two blocks identical (in mass) ? Does block B hang free? If it is, B will descend as A moves up. Draw the free body diagram of each block. Let the tension in string be T. mass of each block = m acceleration due to gravity = g angle of ...
*June 1, 2014*

**biology Please Help**

I am not a biology expert, but here are some mathematical aspects of the problem. If both parents are heterozygous (contains one PKU allele, or Pp), the outcomes are: PP has PKU (probability 1/4) Pp carrier pP carrier pp non-carrier (probability 1/4) Probability of being a ...
*June 1, 2014*

**physics**

Round trip distance is double the earth-moon distance. Speed of light is 3*10^8 m/s. Distance = Speed * time, so Time = Distance /Speed Plug in numbers and calculate time accordingly.
*May 31, 2014*

**Pre-Calculus**

If you mean to find the value of cos(2θ) given cos(θ)=7/13, then use the double angle formula: cos(2θ)=cos²(θ)-sin²(θ) where: sin²(θ) =(1-cos²(θ)) =120/169
*May 31, 2014*

**Statistics**

90+6(80)+10(70)+3(60)+2(50)+3(40)=1670 I'll leave the rest to you.
*May 31, 2014*

**math 1 question!!!!!!**

Put the first number (x) of the ordered pair into the equation and check if y evaluates to the second number (y). For example, for B(8, -98), x=8, y=-98. Check: y=–12x – 3 = -12(8)-3=-96-3=-99, so no, B is not the answer. Try all the other options until you get the ...
*May 31, 2014*

**math**

None of them, unless you mean A.(x,y)--->(x+3,y-2)
*May 31, 2014*

**Physics.**

Start with a free-body diagram (FBD). It solves most statics problems automatically when you isolate the system into individual pieces. Start with the 500g block, mass m1. Normal force=m1g coefficient of friction, μk=0.25 Frictional force = μkm1g Let tension in string, T...
*May 31, 2014*

**Physics**

Centripetal force, same as normal force on the "wall" = mrω² Static friction =μs*N =μsmrω² For the people to be "glued" on the wall, static friction must exceed the weight of the riders due to gravity. Therefore, μsmrω&...
*May 31, 2014*

**intro to computers**

It could be: She does not have admin privileges.
*May 31, 2014*

**Solution and colloids**

I would put H2O and CH3OH are miscible since they are both polar, and hexane and CCl4 as well since they are both non-polar.
*May 31, 2014*

**Chemistry**

Thank you Dr. Bob.
*May 31, 2014*

**Chemistry**

molarity is the number of moles per unit volume (L). 6.25 m means 6.25 moles per L of solution, or per 1221.9 g of solution. Calculate the mass density accordingly.
*May 31, 2014*

**Chemistry**

Mass of 1 L of solution = 1.55 g/mL * 1000 mL/L = 1550 g/L Percentage of H2SO4 by mass = 65% Mass of H2SO4 in 1 L = 1550 g/L * 0.650 = 1007.5 g = 1.01×10³ g approximately.
*May 31, 2014*

**physics**

Sum and difference Man:(15+5)/2=10 Water: (15-5)/2=5
*May 31, 2014*

**physics - circular motion**

Speed=v (in given units) magnitude of velocity of each particle = v direction: opposite Velocity of particle 1: <v cosθ,v sinθ> velocity of particle 2: <-v cosθ -v sinθ> Distance between particles: √(((vcosθ-(-vcosθ))²...
*May 31, 2014*

**physics**

At height 4h/5, KE=h/5 PE=4h/5 Ratio of KE:PE=?
*May 31, 2014*

**Algebra 1-- Explain How to Solve**

I suspect #1 is missing parentheses. If it is a big fraction made up of two small fractions, it would read: 1.((x^2 + 8x)/(x - 2)) / ((3x + 14)/(x - 2)) Remember that parentheses are always there around the numerator and denominator. These questions are solved using factors. ...
*May 31, 2014*

**Physics**

Unless I misunderstood the numbers, the value 45 cm does not match the sequence 80,60,40,20. Please check or clarify.
*May 31, 2014*

**Physic**

Tension, T=2640 N Length of wire, L = 2.6 m frequency, f = 330 Hz length density, μ = to be found Using equation: f = (1/(2L))√(T/μ) Solve for μ (kg/m) Multiply be the length of wire, L to get the mass of the wire.
*May 30, 2014*

**sdfds**

Find n using PV=nRT and multiply by molecular mass. R=8.3144621 J K−1 mol−1 or 0.08205746 L atm K−1 mol−1 depending on the units of pressure used Watch number of significant figures used in calculations (at least 4) and the...
*May 30, 2014*

**Physics**

mass, m = 2.5 kg spring constant, k = 320 N/m compression of spring, Δx = 0.075 m Coefficient of kinetic friction, μk = 0.25 acceleration due to gravity, g = 9.8 m/s² Let initial velocity of block, u =u m/s final velocity of block, v = 0 m/s Work done by block, W...
*May 30, 2014*

**Physics**

(a) KE=(1/2)mv² (b) At maximum height, KE in y-direction = 0, i.e. loss in KE =(1/2)m(v sin(θ))² (c) Maximum height, h equate mgh to loss in KE, or mgh = (1/2)m(v sin(θ))² Solve for h.
*May 30, 2014*

**geometry**

Volume of a sphere =4πr³/3 Volume of hemisphere is half of the above.
*May 30, 2014*

**math problem**

If triangle ABC is right-triangle right angled at B or C, then by the definition of sin(A), it is the opposite side length divided by the hypotenuse.
*May 27, 2014*

**Physics**

See previous post http://www.jiskha.com/display.cgi?id=1401230418
*May 27, 2014*

**Physics**

Solve using momentum. Initial momentum=0, since both astronaut and satellite are stationary with respect to shuttle. Assuming velocity away from shuttle is positive, and m1=mass of astronaut, m2=mass of satellite, then m1v1+m2v2=0 97v1+1100*0.13 Solve for v1 to get v1 = -1100*...
*May 27, 2014*

**Physics**

Solve using momentum m1u1+m2u2=m1v1+m2v2 u=initial speed v=final speed m1,m2 masses Using the ground as reference, m1=69.5 kg m2=0.470 kg u1=u2=2.15 m/s v2=16 m/s m1u1+m2u2=m1v1+m2v2 Solve for v1 to get v1=2.056 m/s approx. B) v2=16+2.15=18.15 Solve similarly to get 2.042 m/s ...
*May 27, 2014*

**algebra/Can you see if I am right**

If you mean conditional probability, meaning P(Face|King), or probability of a face card given it is a king, then start with the definition of conditional probability: P(A|B)=P(A∩B)/P(B) P(Face|King) =P(Face∩King)/P(king) =(4/52)/(4/52) = 1 A king is a face card, that ...
*May 27, 2014*

**physics-force and pressure**

Pressure (pascals) = Force (N) / Area (m²) 700 cm² = 700/10000 m²
*May 27, 2014*

**Math**

A: plot 1 has a smaller range (spread) Interpretations regarding C and D. Plot 2 has a higher grade in all quartiles than plot 1, so class of plot 2 has better scores in general.
*May 26, 2014*

**Algebra**

Probability of not repeating, P(no repeat) =10*26*25*24*9*8*7 / (10^4 * 26^4) Probability repeated =1-P(no repeat)
*May 26, 2014*

**math**

You're welcome! :)
*May 26, 2014*

**math**

R∩P means find the set of members which are in both R and P. You can type the symbol ∩ as follows: & c a p ; but omit all spaces. The other symbol can by typed similarly as: & c u p ; For example, 1 is in both R and P. Can you find the other one?
*May 26, 2014*

**trigonometry**

The hypotenuse of a right triangle, using Pythagoras theorem, is Length of cable =√(200²+85²) feet The angle would be arc tangent(85/200)
*May 26, 2014*

**intermed Algebra**

R=timing, t=years after 1925, for example in 1950 t=25, and so on. The problem you need to solve is R=48.8 s and need to solve for t. 48.8=-0.037t+50.1 Solution : t=35.1 This means by 1925+35.1=1961 (round up), world records will be 48.8 seconds or less.
*May 26, 2014*

**physics**

θ is not defined. It is assumed to be the angle with the horizontal. By finding resultant of two cables at θ with horizontal. W=2Tsin(θ) Solve for T=tension in one of the cables.
*May 26, 2014*

**physics**

Using Newton's second law: F=ma and since F=constant, we have m0a0=m2a2 Knowing that m2/m0=(1-0.11)=0.89 you can solve for a2. Note: it does not seem realistic that an aircraft accelerates horizontally for two hours and continue accelerating!
*May 26, 2014*

**PRECALC QUESTION**

Multiply the matrices on the left-hand side and equate cell by cell with the right to get: the equations 6x=-24 y/2-4x=19 Solve for x and y. The two bottom cells turn out to be -6=-6 and 5=5.
*May 25, 2014*

**college physics**

Centripetal acceleration =v²/r or it varies with the square of the velocity. When acceleration is doubled, the velocity is increased by a factor of √2. This way (√2)²=2.
*May 25, 2014*

**physics**

KE=(1/2)mv² =(1/2)*0.1822*4.6² =1.9276 =1.93 (3 significant figures) To calculate the uncertainty, we do a partial differentiation with respect to m and v, and multiply by the maximum errors of δm=0.00005kg and δv=0.05 m/s. δKE=(1/2)v²δm+...
*May 25, 2014*

**Algebra 2**

Write the equation as y=a cos(b(θ))+k For a max=4,and min=-4, k=0, and a=4, so y=4cos(b(θ))) Period = 2π/b if period = 2π/3, then b=3, and the equation reads: y=4cos(3θ) Pick your choice betwen A and D, unless there is a typo.
*May 25, 2014*

**math**

You may want to check the equation to see if there is a typo. I expect it to read: h=-16t²+v_0 t since the object is thrown straight upwards, while gravity (downwards) is indicated negative. If it is fired straight upwards at an initial speed of 800 ft/s, the initial ...
*May 25, 2014*