Find the values of b and c for which x^2+bx+c is a factor of 2x^3-3x^2-3x-5 Ok, i've tried to find a factor of the quadratic function using trial and error. Let f(x) = 2x^3-3x^2-3x-5 f(1) is not equals to 0 f(-1) is not equals to 0 ... and i cant find a number that would e...
You factorize the quadratic funtion on the left. x²-7x+10>0 (x-2)(x-5)>0 So the answer should be: x<2 OR x>5
Sorry i know how to do this already.
How should i integrate (4cos^2 - 1)? Do I use a certain formula??
Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx. I don't know what i'm supposed to do, and i dont come to an answer! Help, thanks! my workings: tan(45+x)= (1+tanx)/(1-tanx) a/b = (1+tanx)/(1-tanx) a(1-tanx)=b(1+tanx) i square...
Dont use a calculator. Just multiply the numerators together and the denominators together. You should get -234/64800
You mean factorize? bring out 5 from both sides. It's the highest common factor of both sides: 5(9c+5d)
1) (x+5)(3x-3) 2) 3x(x-1)
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