Math2[Please Check Again]
Problem: a^2-9 a^2-3a ----- * -------- a^2 a^2+a-12 What I Got: 3-3a ---- a-4 *Please Check My Work.* Nope. factor the denominator to a^2(a+4)(a-3) The last factor divides out in the numerattor (second term factors to a(a-3). The a in the numerator reduces the denominaor a^2 t...
Math[PLease Check]
Problem: 25-x^2 6 ------ * --- 12 5-x What I got: 5-x --- 2 *PLease Check My Work. No. Factor the 25-x^2 into two factors. Then the 5-x in the denominator divides out. So then is it: 5+x --- 2 yes. 12x12
PLease Check My Work
3. T^2-25/t^2+t-20= (t-5) (t+5)/ (t-10) (t+2) 4. 2x^2+6x+4/4x^2-12x-16= 2(x+2) (x+1)/4 (x-4) (x+1) 5. 6-y/y^2-2y-24= 1/(y+4) *Please check them.- 3. (t-5)(t+5) / (t+4)(t-5) 4. 2((x-1)(x+2)) / 4((x+4)(x-1)) 5. (6-y) / (y+6)(y-4) i dont really understand what this is... but lol ...
Please Help (Math)
You have to simplify each expression: 1/R+1/T multiply the first term by t/t, and the second R/R You should then get... (T+R)/RT
Please Check (Math2)
a^2-9 a^2-3a ----- * ------- a^2 a^2+a-12 *I got: 3-3a/4 I dont think so. factor the a^2-9, and the second numerator to a(a-3) Then the denominator factored is a^2*(a+4)(a-3) So wait... don't I have to first have to take out the repeated thingys.? I dont know what repeated...
Math(Please Check Again)
25-x^2 6x^2 ------ * ------ 12 2x *I got: 5-x/2 No. Try again. Can you tell me what I did wrong please.? You have to factor the numerator, you should have two factors for the first, and one for the second. In the denominator, you will have 24 x. I think the x divides out, and ...
Math(Please Help)
* I don't get this problem at all... 4(x+2) 6x^2 ------ * ---- 5x 2x what are the directions? in the denominator, you have 10x^2 in the numerator, you have 24x^2(x+2) the x^2 divides out, and the numbers can be reduced. that would be (12(x+2))/(5) the directions say: Multi...
Math(PLease Check)
m-2 m+5 --- * ---- m-5 m-2 *I got : m+5 ---- m-5 you're absolutely correct. the m-2's cancel out and you're left with m+5/m-5 thank you hopefully you can help me with the others...
MATH PLEASE CHECK IT!!2
m-2/m-5*m+5/m-2=-1 If your problem is this: (m - 2)/(m - 5) * (m + 5)/(m - 2) = -1 (m - 2) cancels out in both the numerator and denominator on the left-hand side since you are multiplying. That leaves us with this: (m + 5)/(m - 5) = -1 To solve for m: Multiply both sides by (...
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