Saturday
December 7, 2013

Posts by Margie

Total # Posts: 200

Find the sum and express in simplest form. Show all work: x^2 2x-15 ----- *------ x^2-9 x^2-9 *I don't get this at alll.Plz help me. I assume you are trying to add, since the problem says "find the sum" and express in simplest form. x^2/(x^2-9) + (2x-15)/(x^2-9) ...

Solve the inequality x > 6x - 10 and write a description of the graph. Show all work Subtracting x from both sides does not change the inequality sign direction. 0 > 5x - 10 Add 10 to both sides 5x < 10 Divide both sides by 5. x < 2.

Problem: a^2-9 a^2-3a ----- * -------- a^2 a^2+a-12 What I Got: 3-3a ---- a-4 *Please Check My Work.* Nope. factor the denominator to a^2(a+4)(a-3) The last factor divides out in the numerattor (second term factors to a(a-3). The a in the numerator reduces the denominaor a^2 t...

Problem: 25-x^2 6 ------ * --- 12 5-x What I got: 5-x --- 2 *PLease Check My Work. No. Factor the 25-x^2 into two factors. Then the 5-x in the denominator divides out. So then is it: 5+x --- 2 yes. 12x12

3. T^2-25/t^2+t-20= (t-5) (t+5)/ (t-10) (t+2) 4. 2x^2+6x+4/4x^2-12x-16= 2(x+2) (x+1)/4 (x-4) (x+1) 5. 6-y/y^2-2y-24= 1/(y+4) *Please check them.- 3. (t-5)(t+5) / (t+4)(t-5) 4. 2((x-1)(x+2)) / 4((x+4)(x-1)) 5. (6-y) / (y+6)(y-4) i dont really understand what this is... but lol ...

You have to simplify each expression: 1/R+1/T multiply the first term by t/t, and the second R/R You should then get... (T+R)/RT

a^2-9 a^2-3a ----- * ------- a^2 a^2+a-12 *I got: 3-3a/4 I dont think so. factor the a^2-9, and the second numerator to a(a-3) Then the denominator factored is a^2*(a+4)(a-3) So wait... don't I have to first have to take out the repeated thingys.? I dont know what repeated...