lol, both method can find the answer
At equilibrium position, K.E.=max,P.E. = 0 At the two extreme points, K.E.=0,P.E.=max Total energy is constant at ANY POINT. We find E at extreme point. E = 1/2*k*(0.8)^2 = 0.24J
lol, you are welcome
K.E. = P.E. 1/2mv^2 = mgh v^2 = 2gh v = (2gh)^(1/2) v = (2x9.81x155)^(1/2) v = 55.146m/s
I am a Hong Kong student. But i think i may help you. The only force on the ladder from the wall is the horizontal force.The system here is in static equilibrium. Net torque is zero.Let the total length of the ladder be 1m. then, (1)[(29+9.9+7.1)(g)(0.68)]sinâ...
A ball is attached by two spring as shown [vvvOvvv]. If the mass is displaced a distance â³x BELOW the equilibrium position h (see figure A). Determine whether vertical SHM is possible for the system shown.If so, find the natural frequency. [Assume that the ve...
I am a student.But i think i may help you.....the formula for the period of a simple pendulum is T = 2pi(L/g)^0.5.........as you can see..the mass do not affect the period.
what does Q=m times t times c. mean and wat are the meaning of each letter
having a little trouble following the steps to complete this problem. Rewrite each expression with a positive ration exponent. Simplify if possible: 16^-3/4