Wednesday
June 19, 2013

Posts by Mackenzie


Total # Posts: 188

math
Can someone please show me how to estimate mixed numbers. An exsample like 6 and two thrids times 4 and one fifth. Also estimate by rounding to 0, 1/2, or 1. Exsample...5/8x9/10. I would appreciate any help I am in the 6th grade and me and math are not doing so well.....Thanks!

art
In what ways does Albrecht Dürer’s "Four Apostles" serve as an expression of the Protestant faith?

grammer
What is the prepostional phrase and the object it modifies in the following sentence . Energy stored in carbohydrates is released quickly.

Calculus
The solution says the the boundary for phi is from 0 to pi as well as the one for theta.

Calculus
Evaluate the integral by changing to spherical coordinates. The outer boundaries are from 0 to 1. The middle one goes from -sqrt(1-x^2) to sqrt(1-x^2) The inner one goes from -sqrt(1-x^2-z^) to sqrt(1-x^2-z^) for 1/sqrt(x^2+y^2+z^2) dydzdx I don't understand how to get the...

Calculus
Evaluate the integral by changing to spherical coordinates. The outer boundaries are from 0 to 1. The middle one goes from -sqrt(1-x^2) to sqrt(1-x^2) The inner one goes from -sqrt(1-x^2-z^) to sqrt(1-x^2-z^) for 1/sqrt(x^2+y^2+z^2) dydzdx I don't understand how to get the...

Calculus
Evaluate the integral by changing to spherical coordinates. The outer boundaries are from 0 to 1. The middle one goes from -sqrt(1-x^2) to sqrt(1-x^2) The inner one goes from -sqrt(1-x^2-z^) to sqrt(1-x^2-z^) for 1/sqrt(x^2+y^2+z^2) dydzdx I don't understand how to get the...

Calculus
Evaluate the integral by changing to spherical coordinates. The outer boundaries are from 0 to 1. The middle one goes from -sqrt(1-x^2) to sqrt(1-x^2) The inner one goes from -sqrt(1-x^2-z^) to sqrt(1-x^2-z^) for 1/sqrt(x^2+y^2+z^2) dydzdx I don't understand how to get the...

Calculus
Do you know why they divided it by 2?

Calculus
Find the parametric equations for the line of intersection of the planes x+y+z=3 and x-y+2z=2 I took the cross product of the 2 equations and got 3i-j-2k I then set z=0 and got x=5/2 and y=1/2. I got: x=5/2 +3t y=1/2-t z=-2t However, the answers are supposed to be: x=5/2-(3/2)...

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